how many stereoisomers will be formed from the addition of phenyllithium to this molecule

Answer:

attached here is the diagram of the solution

Explanation:

A calcium hydroxide aqueous solution is used in the carbon dioxide test (lime water). Limewater turns milky whenever carbon dioxide is bubbling within it or agitated with that as well (cloudy).

Drinking lime water improves digestion. The acidity of lime juice helps saliva break down meals for easier digestion. Lime juice is good astringency can ease constipation by encouraging digestion and cleansing the digestive tract.

What results in milky lime water?

Limewater appears milky because the sodium bicarbonate that is created is white and insoluble in water. Lime water is known chemically as calcium carbonate, but also its concentration is Ca(OH)2. Pure limewater usually translucent, colorless, with a slightly bitter taste. Also, it smells little earthy.

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The results illustrate the law of multiple proportions since the oxygen atoms in A and B are in simple multiple ratios.

The formula of the oxides is SO₃ and SO₂ respectively.

Mass of sulfur in A = 3.50 g

Moles of sulfur in A = 3.50/32

Moles of sulfur in A = 0.11 moles

Mass of oxygen in A = 6.05 g

Moles of oxygen in A = 6.05/16

Moles of oxygen in A = 0.38

The mole ratio of sulfur to oxygen = 0.11 : 0.38

The mole ratio of sulfur to oxygen = 1 : 3

The formula of oxide = SO₃

Mass of sulfur in B = 2.80 g

Moles of sulfur in B = 2.80/32

Moles of sulfur in B = 0.088 moles

Mass of oxygen in B = 2.80 g

Moles of oxygen in B = 2.80/16

Moles of oxygen in B = 0.175

The mole ratio of sulfur to oxygen = 0.088 : 0.175

The mole ratio of sulfur to oxygen = 1 : 2

The formula of oxide = SO₂

The oxygen atoms in A and B are in simple multiple ratio.

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The lattice energy for the magnesium fluoride can be calculated as -3314 kJ/mol

Lattice energy is the energy released when gaseous ions come together to form a solid ionic compound. It is a measure of the strength of the electrostatic forces of attraction between the ions in an ionic crystal lattice.

Lattice energy depends on several factors, including the charges of the ions involved and the distances between them. The magnitude of the lattice energy increases with higher charges on the ions and decreases with larger ionic radii or greater separation between ions.

We have that Using the Hess law;

Lattice energy =  -1124  - 15 - 2(157) - (738 + 1451) -  (-328)

= -3314 kJ/mol

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The total pressure at equilibrium is 2.43 atm when 4.96 g of CO₂ is introduced into a 10.0 L container and heated to 1200 K in the presence of 3.71 g of graphite. The total pressure at equilibrium is 10.7 atm when 0.45 g of graphite.

Equilibrium concentrations can be determined using the equation: KP = (PCO² / PCO₂ × PC) for the reaction CO₂(g) + C(s) ↔ 2CO(g).

The total pressure can be calculated using the equation: Ptotal = PCO₂ + PCO.

KP = 5.78 (given)

Moles of CO₂ introduced = 4.96 g / 44.01 g/mol = 0.1128 mol

Moles of graphite introduced = 3.71 g / 12.01 g/mol = 0.3081 mol

Initial pressure of CO₂ = (0.1128 mol / 10.0 L) × 0.0821 atm·L/(mol·K) × 1200 K = 1.1264 atm

Initial pressure of C = (0.3081 mol / 10.0 L) × 0.0821 atm·L/(mol·K) × 1200 K = 3.0865 atm

KP = (PCO)² / PCO₂ × PC ⇒ PCO = sqrt(KP × PCO₂ / PC)

PCO = sqrt(5.78 × (1.1264 atm)² / (3.0865 atm)) = 1.3057 atm

Ptotal = PCO₂ + PCO = 1.1264 atm + 1.3057 atm = 2.4321 atm

Moles of graphite introduced = 0.45 g / 12.01 g/mol = 0.0375 mol

Initial pressure of CO₂ = (0.1128 mol / 10.0 L) × 0.0821 atm·L/(mol·K) × 1200 K = 1.1264 atm

Initial pressure of C = (0.0375 mol / 10.0 L) × 0.0821 atm·L/(mol·K) × 1200 K = 0.3045 atm

KP = (PCO)² / PCO₂ × PC ⇒ PCO = sqrt(KP × PCO₂ / PC)

PCO = sqrt(5.78 × (1.1264 atm)² / (0.3045 atm)) = 9.561 atm

Ptotal = PCO₂ + PCO = 1.1264 atm + 9.561 atm = 10.6874 atm

Therefore, the total pressure at equilibrium is 2.43 atm when 4.96 g of CO₂ is introduced into a 10.0 L container and heated to 1200 K in the presence of 3.71 g of graphite. The total pressure at equilibrium is 10.7 atm when 0.45 g of graphite is introduced into the same system.

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The correct ranking of compounds in order of increasing keq for this equilibrium is Acetone < Propanone < Benzaldehyde.

The correct ranking of compounds in order of increasing keq for the equilibrium of each of the carbonyl compounds with HCN to produce cyanohydrins is

Acetone < Propanone < Benzaldehyde.

In the above reaction, the cyanide ion acts as a nucleophile and attacks the carbonyl carbon atom in the carbonyl compound to form an intermediate compound. Then the intermediate compound formed by the reaction between HCN and the carbonyl compound undergoes an intramolecular rearrangement to form cyanohydrin.Based on the stability of intermediate compound formed, the order of increasing stability is as follows:

Acetone < Propanone < Benzaldehyde.

Since the keq is directly proportional to the stability of the intermediate, the order of increasing keq for the equilibrium of each of the carbonyl compounds with HCN to produce cyanohydrins is

Acetone < Propanone < Benzaldehyde.

The correct ranking of compounds in order of increasing keq for this equilibrium is

Acetone < Propanone < Benzaldehyde.

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Answer: Two pina coloda's FR FR no cap Explanation:

Answer:

satisfaction

Explanation:

2

An equation which follow the law of conservation of mass is called the balanced equation. The coefficient of copper (II) nitrate is 1 .The correct option is C.

A chemical equation in which the number of atoms of reactants and products on both sides of the equation are equal is defined as the balanced chemical equation.

The coefficients are the numbers which are used to balance the chemical equation. They are added in front of the formulas. According to law of conservation of matter, mass can neither be formed nor be destroyed.

The balanced equation for the given reaction is:

Cu (s) + 2AgNO₃ (aq) → Cu (NO₃)₂ (aq) + 2Ag (s)

Here the coefficient of Cu (NO₃)₂ is 1. The number of 'Cu', 'Ag', 'N' and 'O' atoms are equal. So the given equation is balanced. The coefficient of AgNO₃ is 2, and 'Ag' is 2.

Thus the correct option is C.

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62.3 mol Ca

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

3.75 × 10²⁵ atoms Ca

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

62.2717 mol Ca ≈ 62.3 mol Ca

Answer:

Flatworms (Platyhelminthes) are acoelomates i.e. they lack a coelom. Molluscs and insects (Arthropoda) are coelomates as they have a true coelom derived from the germ layer mesoderm. Roundworms (Aschelminthes) are pseudocoelomates as the coelom is not derived from the mesoderm.

Earthworm is an invertebrate belongs to phylum Annelid. so it does not belongs to phylum aschelminthes​.

Phylum Aschelminthes is called as roundworms, their bodies appear circular,  approximately 15000 different types of roundworms are present.

These are pseudocoelomate, bilaterally symmetrical, triploblastic,  vermiform organisms having complete digestive system, commonly seen in soil, feed on bacteria.

These are also found in the human intestine, cause a disease called ascariasis, do not have a respiratory or circulatory system.

Some of the unique features are presence of Syncytial epidermis, Muscle layer of body wall, Pseudonym, complete digestive tract, unisexual in nature.

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There are 1.08 x 10^23 molecules of H2 in a 5.0 L sample at the same temperature and pressure as the 5.0 L sample of O2.

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. At the same temperature and pressure, two different gases will have the same value of n/V. This quantity is also known as the molar concentration or simply concentration.

Therefore, we can use the concentration of O2 to determine the number of molecules in 5.0 L of H2:

n/V = (1.08 x 10^23 molecules) / (5.0 L) = 2.16 x 10^22 molecules/L

Since the volume of H2 is also 5.0 L and the concentration is the same, the number of molecules of H2 can be found by:

n = (2.16 x 10^22 molecules/L) x (5.0 L) = 1.08 x 10^23 molecules

Therefore, there are 1.08 x 10^23 molecules of H2 in a 5.0 L sample at the same temperature and pressure as the 5.0 L sample of O2.

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The energy in the ground state of the electron confined in a 10 nm box is approximately 10.89 eV, and the energy in the first excited state is approximately 43.56 eV.

To calculate the energy of an electron confined in a 10 nm box, we can use the formula for the energy levels of a particle in a one-dimensional infinite potential well:

E_n = (n^2 * h^2) / (8 * m * L^2)

where:

E_n is the energy of the nth energy level,

n is the quantum number of the energy level (n = 1 for the ground state),

h is the Planck's constant (6.626 x 10^-34 J·s),

m is the mass of the electron (9.10938356 x 10^-31 kg),

L is the length of the box (10 nm = 10 x 10^-9 m).

Let's calculate the energy in the ground state (n = 1) and the first excited state (n = 2):

For the ground state (n = 1):

E_1 = (1^2 * h^2) / (8 * m * L^2)

Substituting the values:

E_1 = (1^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2)

Calculating this expression will give us the energy in the ground state.

For the first excited state (n = 2):

E_2 = (2^2 * h^2) / (8 * m * L^2)

Substituting the values:

E_2 = (2^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2)

Calculating this expression will give us the energy in the first excited state.

Please note that the energies calculated will be in joules (J). If you prefer electron volts (eV), you can convert the results by dividing by the electron volt value (1 eV = 1.602 x 10^-19 J).

Performing the calculations:

For the ground state:

E_1 = (1^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2) ≈ 1.747 x 10^-18 J

For the first excited state:

E_2 = (2^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2) ≈ 6.987 x 10^-18 J

Converting the energies to electron volts (eV):

E_1 ≈ 10.89 eV (rounded to two decimal places)

E_2 ≈ 43.56 eV (rounded to two decimal places)

Therefore, the energy in the ground state of the electron confined in a 10 nm box is approximately 10.89 eV, and the energy in the first excited state is approximately 43.56 eV.

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number of grams of oxygen are produced from the complete reaction of 1.32 moles of KClO3 are 63.36 grams

To find the grams of oxygen produced from the complete reaction of 1.32 moles of KClO3, we need to use stoichiometry. Here are the steps to solve the problem:

Start with the given amount of KClO3: 1.32 moles KClO3

Use the balanced chemical equation to find the moles of O2 produced:

1.32 moles KClO3 x (3 moles O2 / 2 moles KClO3)

=> 1.98 moles O2

Convert the moles of O2 to grams using the molar mass of O2 (32.00 g/mol):

1.98 moles O2 x (32.00 g/mol)

=> 63.36 grams O2

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The reaction between zinc and acetic acid is classified as a single displacement reaction. This type of reaction is characterized by the replacement of an atom or a group of atoms of a compound by another atom or group of atoms.

The balanced chemical equation for the reaction between zinc and acetic acid is as follows:
Zn + 2CH₃COOH → Zn(CH₃COO)₂ + H₂

In general terms, during a single displacement reaction, an element replaces another element in a compound. This type of reaction occurs when an element that is more reactive than the one already present in a compound is introduced. For example, in the reaction between zinc and acetic acid, zinc is more reactive than hydrogen and, therefore, replaces hydrogen in acetic acid.

An example of a type of element and a type of compound that are likely to participate in a single displacement reaction is sodium and hydrochloric acid. Sodium is more reactive than hydrogen and can replace hydrogen in hydrochloric acid. The balanced chemical equation for the reaction between sodium and hydrochloric acid is as follows:
2Na + 2HCl → 2NaCl + H₂

In conclusion, the balanced equation for the reaction between zinc and acetic acid is Zn + 2CH₃COOH → Zn(CH₃COO)₂ + H₂, and this reaction is classified as a single displacement reaction. During this type of reaction, an element replaces another element in a compound. An example of a type of element and a type of compound that are likely to participate in this type of reaction is sodium and hydrochloric acid.

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Explanation:

I answered your question in the submitted photo

Answer:

The mechanical advantage (M.A) of a real machine is always less than its velocity ratio(V.R) because mechanical advantage decreases due to the friction and weight of moving parts of the machine whereas the velocity ratio remains constant

Answer:

C

Equilibrium shifts to the right, as more SO₃ are formed, the products are being used up. Hence, the concentration of SO₂ decreases!

I hope this helps!

Answer:

False.

Explanation:

Carbon = 12

Beryllium = 9

good luck, i hope this helps :)

Increasing the crosslinking or degree of crystallinity of a polymer will enhance its resistance to swelling and dissolution due to the increased strength and stability of the polymer network.

Increasing crosslinking or degree of crystallinity in a polymer affects its resistance to swelling and dissolution in the following ways:

1. Crosslinking refers to the formation of chemical bonds between polymer chains ,resulting in a more rigid and compact structure. When crosslinking increases, the polymer chains become more interconnected and form a stronger network structure. This enhanced network structure results in a higher resistance to swelling and dissolution, as it is more difficult for solvents to penetrate and interact with the polymer chains.

2. Degree of crystallinity refers to the proportion of ordered, crystalline regions in a polymer material. As the degree of crystallinity increases, the polymer becomes more rigid, tighter packing of polymer chains and less permeable to solvents. This is because the crystalline regions are more tightly packed and have stronger intermolecular forces, making it more difficult for solvents to penetrate and cause swelling or dissolution.  As a result, a polymer with a high degree of crystallinity is less likely to absorb moisture or other solvents, making it more resistant to swelling and dissolution.

In summary, increasing the crosslinking or degree of crystallinity of a polymer enhances its resistance to swelling and dissolution by creating a stronger network structure and reducing the permeability of solvents. The stronger and more compact the polymer network, the better it can withstand exposure to solvents or other environmental factors.

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The energy required to separate the two ions to an infinite distance apart is -1.64 * 10⁻¹⁸ J.

The potential energy required to separate two ions to an infinite distance apart is called lattice energy. The equation for lattice energy is given as follows:

U = -N (A * Z⁺ * Z⁻ / r)

where,U represents lattice energy

N represents Avogadro's constant

A represents the Madelung constant

Z+ represents cation's charge

Z- represents anion's charger represents the distance between the ion centers

As given in the question, the distance between the potassium and chloride ions in potassium chloride is 2.8e⁻¹⁰m.

Thus, putting all the values in the formula of lattice energy, we get;

U = -6.022 * 10²³* (2.31 * 10⁻¹⁰ * 1 * 1 / 2.8 * 10⁻¹⁰)U = -1.64 * 10⁻¹⁸J

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Answer:

True.

Explanation:

Yes, all systems disperse their energy spontaneously because all types of  energy spontaneously flows from concentrated to dispersed if it is not hindered by any material in their way. Energy can be prevented from spreading by materials such as containers. If there is no substance in the path of energy so it can disperse automatically from a concentrated region to a lower region.

The blending of one s atomic orbital and two p atomic orbitals produces three sp hybrid orbitals.

When an s orbital and two p orbitals combine, they undergo hybridization to form three sp hybrid orbitals. This hybridization occurs when an atom is bonded to three other atoms in a trigonal planar arrangement. The process involves mixing one s orbital and two p orbitals to form three equivalent hybrid orbitals.

These sp hybrid orbitals have a linear shape with an angle of 180 degrees between them. The term "sp" indicates that the hybrid orbitals are a combination of one s orbital and one p orbital. This type of hybridization is commonly observed in molecules with triple bonds or in the central atom of trigonal planar molecules.

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The preferred method for determining or validating the structure of organic molecules or those containing protons is ¹₁H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure.

The study of matter's physical, chemical, and biological properties is done using NMR spectroscopy. It is used by chemists to ascertain the identity and structure of molecules.

By capturing the interaction of radiofrequency (Rf) electromagnetic radiations with the nuclei of molecules put in a high magnetic field, nuclear magnetic resonance (NMR) spectroscopy allows scientists to analyze molecules.

The structure of C₆H₁₂O₂ is:

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Answer:

female reproductive structures

If one were to construct a galvanic cell consisting of two Zn2 /Zn electrodes at two different concentrations, the more concentrated cell will be the anode

In a galvanic cell, the more concentrated solution is typically associated with the anode, while the less concentrated solution is associated with the cathode. This is because, in the anode compartment, the metal electrode undergoes oxidation and releases metal ions into solution, resulting in an increase in the concentration of metal ions.

In contrast, in the cathode compartment, metal ions from the solution are reduced onto the metal electrode, resulting in a decrease in the concentration of metal ions.

Therefore, in the case of a galvanic cell consisting of two Zn2+/Zn electrodes at two different concentrations, the more concentrated cell would be associated with the anode.

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Full Question: If one were to construct a galvanic cell consisting of two Zn2 /Zn electrodes at two different concentrations, the more concentrated cell will be the _____. Multiple choice questions.

The pH of a solution is a measure of the acidity or basicity of the solution. It is defined as the negative logarithm of the hydrogen ion (H+) concentration in the solution. Therefore, the pH of the solution is 3.91.  

To determine the pH of a solution containing potassium acetate and acetic acid, we need to know the concentrations of the two solutes and the ratio of acetic acid to potassium acetate in the solution.

We are given the concentration of the potassium acetate and the ratio of acetic acid to potassium acetate in the solution. To calculate the pH of the solution, we can use the following equation:

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in the solution.

To find the concentration of hydrogen ions in the solution, we can use the following equation:

[H+] = [acetic acid] + [potassium acetate] * ([acetic acid]/[potassium acetate])

Substituting the values we have, we get:

[H+] = (6.84 x \(10^{-2\)) + (0.434 x 6.84 x  \(10^{-2\)) * (0.00072)

[H+] = 6.84 x  \(10^{-2\) + 2.69 x  \(10^{-2\)

[H+] = 9.53 x  \(10^{-2\) mol/L

The pH of the solution can be calculated using the equation:

pH = -log[H+]

Substituting the value of [H+] in the equation, we get:

pH = -log[9.53 x \(10^{-2\)]

pH = 3.91

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Answer: it's D

Explanation:

Same reason as the dude above me

Food engineering is a rapidly evolving field. Traditionally, the primary emphasis has been on food preservation and stabilization, whereas current trends emphasize diversity, health, taste, and sustainable production.

Best Example is "  Freeze-drying blueberries to extend their shelf life "

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