How many total moles of ions are released when each of the following dissolves in water?
(b) 3.85×10⁻³ g of Ca(NO₃)₂

Answer:

68 degrees fahrenheit

Explanation:

A mixture of gases contains 0.31 mol CH₄, 0.25 mol C₂H₆, and 0.29 mol C₃H₈ the total pressure is 1.50 atm the partial pressures of the gases is  0.547 atm , 0.441 atm , 0.511 atm

A mixture is a compound made up of two or more chemical components that are not chemically linked

Here given data is

CH₄ = 0.31 mol

C₂H₆ = 0.25 mol

C₃H₈ = 0.29 mol

Total pressure = 1.50 atm

We have to calculate partial pressures of the gases = ?

First total number of gaseous mole

n = n(CH₄) + n(C₂H₆) + n(C₃H₈)

n = 0.31 mol + 0.25 mol + 0.29 mol

n = 0.85 mol

Then calculate the partial pressure

Pi = P×Xi

pi: partial pressure pressure of the gas "i"

P: total pressure

Χi: mole fraction of the gas "i"

pCH₄ = 1.50 atm×0.31 mol/0.85 mol = 0.547 atm

pC₂H₆ = 1.50 atm×0.25 mol/ 0.85 mol = 0.441 atm

pC₃H₈ =  1.50 atm× 0.29 mol/0.85 mol = 0.511 atm

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The maximum mass of zinc sulfate crystals that could obtain is about 6 g from the zinc of 1.36 g.

The theoretical yield of the reaction can be defined as the amount of product determined from stoichiometric calculations.

The given chemical formula of the zinc sulfate crystals ZnSO₄.7H₂O. the molecular mass of the zinc sulfate crystals is 287 g/mol.

The atomic mass of the zinc = 65.3 g/mol

The 65.3 g of Zn present in zinc sulfate crystals = 287 g

Then 1.36 g of zinc was used to prepare zinc sulfate crystals = (287/65.3) × 1.36 = 6g.

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We are told that starch consists of glucose polymer, so we can assume that the caloric value of starch will be equal to the caloric value of glucose, that is, 3.9kcal/g.

Now to determine the kcal and kJ there were in the potato we must calculate the mass of starch present in that potato. We are told that it is 92% starch, therefore the mass of starch in the potato will be:

We have that in the potato there are 160.08 grams of starch. By multiplying it by the caloric value we will have the kcal that were in the potato, assuming that the rest of the ingredients do not contribute caloric value, or it is insignificant.

To calculate the kJ we must make the conversion using the relationship that 1 cal is equal to 4.184 joules:

In the potato, there were 624 kcal of energy or 2612kJ of energy.

Answer: 10y/s

Explanation:

The concentration of OH- in the aqueous solution is approximately 1.3 × 10-6 M, which corresponds to option D.

To find the concentration of OH- in an aqueous solution when the concentration of H3O+ is 7.6 × 10-9 M, we can use the ion product constant for water (Kw):

Kw = [H3O+][OH-]

Kw is a constant value at 25°C, equal to 1.0 × 10-14.

Given [H3O+] = 7.6 × 10-9 M, we can solve for [OH-]:

1.0 × 10-14 = (7.6 × 10-9)[OH-]

To find [OH-], divide both sides of the equation by the [H3O+] value:

[OH-] = (1.0 × 10-14) / (7.6 × 10-9)

[OH-] ≈ 1.3 × 10-6 M

So, the concentration of OH- in the aqueous solution is approximately 1.3 × 10-6 M, which corresponds to option D.

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The weight of the 3 lb roast purchased by the housewife is 1,360.78 grams.

The weight of an object is the force acting on the object due to gravity.

The weight of an object varies from place to place across the globe due to difference in acceleration due to gravity.

1 lb ------------> 453.592 grams

3 lb ------------> ?

= (3 x 453.592)

= 1,360.78 grams

Thus, the weight of the 3 lb roast purchased by the housewife is 1,360.78 grams.

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the radioactive decay of a sample containing an unknown radioactive isotope produced 9062 disintegrations per minute. 15.06 days later, the rate of decay was found to be 2421 disintegrations per minute. Half life is 7.91 days

The half-life of an amount is the time it requires to reduce to half of its original value. In nuclear physics, the term is frequently used to define how quickly atoms undergo radioactivity or how long stable atoms stay alive. The term is also used to describe any type of exponentially decaying in general. In radioactive material, the time needed for one-half of an irradiated sample's atomic nuclei to decompose (change instantaneously into the other nuclear species by emitting particles and energy), or, equally, the time needed for the number of deformation and fracture per second of a radioactive.

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To confirm Newton’s Second Law using a laboratory report, you will need to conduct an experiment using a simulation and gather data. Newton’s Second Law states that force equals mass times acceleration.

Here's how you can write a laboratory report to confirm Newton’s Second Law using the simulation and gathered data. Introduction: This section should include a brief explanation of the theory behind Newton’s Second Law and what you will be testing in your experiment. It should also include your hypothesis.

Procedure: This section should explain the steps you took to conduct your experiment. In this case, it would involve using the simulation to apply different forces to objects with different masses and measuring their acceleration.

Data: This section should present the data you collected during your experiment. It can be presented in tables or graphs, and should include measurements of force, mass, and acceleration for each trial.

Analysis: This section should analyze the data you collected to determine if it supports your hypothesis and confirms Newton’s Second Law.

Conclusion: This section should summarize your findings and draw conclusions based on the data you collected. It should also discuss any errors or limitations of the experiment and suggest areas for further research.

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Answer:

At 30 degrees C, Bromine is a liquid.

Explanation:

Explanation:      Heat capacity is the amount of heat required to change the temperature of a ... Therefore, specific heat is measured in Joules per g times degree Celsius

The value of ΔG at 298 K for a reaction mixture containing 1.9 atm N2, 1.6 atm H2, and 0.65 atm, the answer is (a) -3.86 × 10^3.

NH3 can be calculated using the equation:

ΔG = ΔG° + RT ln(Q)

where ΔG is the standard Gibbs free energy change, ΔG° is the standard Gibbs free energy change at standard conditions, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

In this case, we are given ΔG° as -33.3 kJ/mol. To calculate Q, we need to use the partial pressures of the gases in the reaction mixture. The reaction stoichiometry tells us that the ratio of the partial pressures of N2, H2, and NH3 is 1:3:2. Therefore, we can write:

Q = (P(NH3))^2 / (P(N2) * P(H2)^3)

Plugging in the given values of P(N2) = 1.9 atm, P(H2) = 1.6 atm, and P(NH3) = 0.65 atm, we can calculate Q. Then, using the value of R = 8.314 J/(mol·K) and the temperature T = 298 K, we can substitute these values into the equation and solve for ΔG.

The calculated value of ΔG at 298 K for the given reaction mixture is approximately -3.86 × 10^3 J/mol. This value is equivalent to -3.86 kJ/mol. Therefore, the answer is (a) -3.86 × 10^3.

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The Solar weather affects the Earth's magnetosphere which is a threat to our magnetic protection and can cause turbulence.

The effect is like widening a hole—suddenly more energy and particles enter the magnetosphere. Auroras intensify, and geomagnetic storms become likely. For this reason, scientists pay careful attention to not only the strength but also the orientation of incoming magnetic fields from the sun. As the wind blows from the galaxy towards the earth it carries with it the Sun's magnetic field. It moves very fast, then smacks right into the Earth's magnetic field. The blow causes a shock to our magnetic protection, which can result in turbulence.

So we can conclude that: The Solar weather affects the Earth's magnetosphere which is a threat to our magnetic protection and can cause turbulence.

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Answer:

b is right answer because xylem provide nutrition and water to the plant

Further explanation

Given

25 moles of Oxygen(02)

Required The number of molecules

Solution Reaction

2NO+02 → 2NO2

From the equation,

mol NO2: = 2/1 x mol O2 = 2/1 x 25moles = 50 moles

The number of molecules :

\( = 50 \times 6.022 \times 10^{23}\)

\( = 3.011 \times 10{²5}\)

Ernest Rutherford's experiments in which alpha rays pass through a thin piece of metal foil demonstrated that atom contains a tiny nucleus containing most of the atom's mass. The correct answer choice is "the atom contains a tiny nucleus containing most of the atom's mass."

The alpha-particle scattering experiment was performed by Ernest Rutherford in 1911. It was conducted to discover the nature of atomic structure. The experiment demonstrated that most of the mass of an atom and all of its positive charge are contained in a small nucleus at the center of the atom.

The electrons were found to occupy almost all of the remaining space. Therefore, the correct answer is the atom contains a tiny nucleus containing most of the atom's mass.

Therefore "the atom contains a tiny nucleus containing most of the atom's mass." is the correct answer.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\ \)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{3.612 \times {10}^{24} }{6.02 \times {10}^{23} } \\ \)

We have the final answer as

Hope this helps you

The cultures of prehistoric humans are primarily known through the excavation of stone tools and other durable artifacts, such as the Oldowan and Acheulian tool traditions.

Stone tools and imperishable artifacts serve as key archaeological evidence for understanding prehistoric cultures. Through meticulous excavation and analysis, archaeologists have been able to piece together the lifestyles, technological advancements, and social behaviors of early human societies. The term "paleolithic" refers to the Old Stone Age, a time when humans relied on stone tools as their primary implements.

The Oldowan tool tradition is considered the earliest stone tool industry, dating back around 2.6 million years ago. It is characterized by simple tools, such as choppers and scrapers, which were crafted by flaking off pieces from larger stones. These tools were primarily used for basic activities like butchering and processing animal carcasses.

Later, the Acheulian tool tradition emerged around 1.76 million years ago, representing an advancement in stone tool technology. Acheulian tools, such as handaxes and cleavers, were more refined and standardized, showcasing an increased level of sophistication in tool-making techniques. These tools served a wide range of purposes, including hunting, woodworking, and shaping raw materials.

By studying the Oldowan and Acheulian tool traditions, researchers gain valuable insights into the cognitive abilities, cultural development, and technological progress of early humans. The examination of these artifacts provides evidence of their adaptability, problem-solving skills, and the gradual refinement of their tool-making techniques over time.

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Transition is associated with the greatest energy change is n=1 to n=3  As you get to higher energy shells, the difference between becomes smaller.

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(a) Draw resonating structure of PhenolPhenol is a common organic molecule. It consists of a phenyl group (C6H5) attached to a hydroxyl group (OH). The hydroxyl group is connected to the benzene ring at the para position, denoted as p-phenol.

The two main resonating structures of Phenol are shown in the figure below: This reaction takes place by cleaving the double bond of Cyclohexene using ozone, followed by a reductive workup step.

(b) Phenol is heated with CH3COCl:When Phenol is heated with Acetyl Chloride, it forms Acetophenone. The reaction is as follows:Phenol reacts with Acetyl Chloride to form Acetophenone, with the elimination of HCl as a by-product.(c) Propyne reacts with hydrogeniodide in the presence of benzene peroxide:Propyne reacts with hydrogen iodide in the presence of benzene peroxide to form 2-Iodopropane.

The reaction proceeds via a radical mechanism, as shown below:The chain initiation step:This step involves the homolytic cleavage of the benzene peroxide bond to generate benzene and two free radicals. These free radicals then interact with hydrogen iodide to form iodine radicals.The chain propagation step:The chain propagation steps involve the following sequence of reactions:The chain termination step:

This reaction involves the formation of 2-Iodopropane.(d) Propoxypropane is reacted with access of NH3:Propoxypropane is reacted with excess of NH3 to form Propylamine. The reaction is as follows:Propoxypropane undergoes nucleophilic substitution with ammonia, followed by deprotonation, to form the corresponding amine. Excess ammonia is required to drive the reaction to completion.

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Answer:

...

Explanation:

Answer:

A. It makes the edges of the rock more jagged over time.

Explanation:

Abrasion makes rocks with sharp or jagged edges smooth and round. If you have ever collected beach glass or cobbles from a stream, you have witnessed the work of abrasion.

A 20.0 g sample of calcium contains approximately 3.01 x 10^23 calcium atoms.

To determine the number of calcium atoms in a 20.0 g sample of calcium (Ca), we need to use the concept of Avogadro's number and molar mass.

The molar mass of calcium (Ca) is approximately 40.08 g/mol. This value represents the mass of one mole of calcium atoms.

To calculate the number of calcium atoms in the given sample, we can use the following steps:

   Determine the number of moles of calcium in the sample:

   Number of moles = Mass / Molar mass

   Number of moles = 20.0 g / 40.08 g/mol

   Use Avogadro's number to convert moles to atoms:

   Number of atoms = Number of moles * Avogadro's number

   Number of atoms = Number of moles * 6.022 x 10^23 atoms/mol

Substituting the calculated number of moles into the equation:

Number of atoms = (20.0 g / 40.08 g/mol) * (6.022 x 10^23 atoms/mol)

Performing the calculation:

Number of atoms ≈ 3.01 x 10^23 atoms

Therefore, a 20.0 g sample of calcium contains approximately 3.01 x 10^23 calcium atoms.

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During the melting of ice, the ice absorbs heat energy and the molecules move further away; option A.

Melting refers to the process by which a solid substance changes to liquid when heat is added to it.

The melting of pure substances occur at a definite temperature called the melting point of that substance.

The molecules of a substance move further apart when they melt as the attractive forces between them are weakened.

The melting of ice is an example of the process of melting.

During the melting of ice, the ice absorbs heat energy and the molecules move further away.

In conclusion, melting of solids occur when heat is added to the solid.

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Answer:

Explanation:

one is True,   an electro magnet is only magnetic because of current producing the magnetic field.  

The 3 general ways by which a system in equilibrium can be reversed are by changing the concentration of the reactants of products, changing the pressure of the system, and changing the temperature of the system.

Le Chatelier's principle state that when a reaction is in equilibrium and one of the constraints that affect the rate of reactions is applied to the system, the equilibrium shifts so as to cancel out the effects of the constraints.

The constraints being referred to by Le Chatelier are concentration, pressure, and temperature. Increasing or decreasing the pressure of a system in equilibrium will shift the equilibrium to the sides with the lower moles or higher moles respectively.

Increasing the concentration of the reactants will shift the equilibrium toward the product side while increasing the concentration of the products will shift the equilibrium toward the reactant side.

In the same vein, increasing the temperature of a system will sift the equilibrium towards the product if the system itself is endothermic. If the system is exothermic, a reversal will occur.

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The sample of solid water would undergo several phase changes as it is heated, transitioning from a solid to a liquid, then to a gas, and possibly to a supercritical fluid.

A sample of solid water, also known as ice, would undergo several changes when heated from -10 degrees Celsius to its critical temperature at a pressure of 1.00 atm. These changes include:

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Answer:

B

Explanation:

The percent abundance of the isotope with an atomic mass of 120.905 is approximately XX%.

To calculate the percent abundance, we need to compare the relative abundance of the two isotopes. Given that there are two isotopes with atomic masses of 120.905 and 122.921, we can assume that the sum of their percent abundances is 100%.

Let's denote the percent abundance of the isotope with an atomic mass of 120.905 as "x". The percent abundance of the other isotope (with atomic mass 122.921) can then be expressed as (100 - x).

Since the atomic mass is directly proportional to the percent abundance, we can set up the following equation:

(120.905 * x) + (122.921 * (100 - x)) = 121.764

Solving this equation will give us the value of x, which represents the percent abundance of the isotope with an atomic mass of 120.905. Once we find this value, we can express it as a percentage to determine the answer.

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Answer:

Explanation: possible oxidation numbers of Au are +I and +III

Au2O3 ⇒ 2 Au + 3 O2