How much warmer is 52 than 40

|| ▼ Answer ▼ ||

8 is correct!

|| ✪ Solution ✪ ||

\(g(x)=2x^{2}-8x+1\)

Vertex of f(x) is:

\((x,y)=(2,1)\)

Graph of g(x) is attached :

Vertex of g(x) is:

\((x,y)=(2,-7)\)

Y- value of vertex f(x) subtract from Y-value of g(x)

\(=1-(-7)\)

\(=1+7\)

\(1+7=8\)

Hope this Helps!

If you have any queries please ask.

Answer: I think it's B

Step-by-step explanation: You can use the answer if you want.

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Explanation:

The surface area of a cylinder is

SA = 2*pi*r^2 + 2pi*r*h

The 2*pi*r^2 portion handles the 2 identical flat circular faces on top and bottom (each being area of pi*r^2). The 2*pi*r*h portion handles the curved side.

We'll plug in the radius of r = 6 and height of h = 5

SA = 2*pi*r^2 + 2pi*r*h

SA = 2*pi*6^2 + 2pi*6*5

SA = 2*pi*36 + 2*pi*30

SA = 2*36pi + 2*30pi

SA = 72pi + 60pi

SA = 132pi

That's the exact surface area in terms of pi.

Your teacher wants you to replace pi with the approximation 3.14

SA = 132pi

SA = 132*3.14

SA = 414.48

Then as a final step, we round to the nearest tenth (aka 1 decimal place) to get 414.5 square inches

Answer: $13,000

Step-by-step explanation:

Answer: f(6)=4

f(x)=1/3x+2

f(6)=1/3(6)+2

f(6)=6/3+2

f(6)=2+2

f(6)=4

Answer:

87 or 75 dollars

Step-by-step explanation:

So first we have to 29 by 5 wich gives us 5.8 so he raked 5.8 packs of 5 bags then you multiply 15 by 5.8 so he made 87 dollars

Unless:

Your not counting the point 8 leaves in that case the answer would be 75

the general solution to Laplace's equation in cylindrical coordinates for axially symmetric solutions is: u(r,z) = (c1J0(λr))(c3e^λz + c4e^(-λz))   where c1, c3, and c4 are constants and λ is a parameter that can be determined from the boundary conditions.

b) Assuming that u(r,z) = R(r)Z(z), we can use the method of separation of variables to obtain the equations for R and Z. Substituting u(r,z) = R(r)Z(z) into Laplace's equation in cylindrical coordinates, we have:

u_rr + (1/r)u_r + u_zz = 0

(RZ)'' + (1/r)(RZ)' + RZ'' = 0

Dividing by RZ and multiplying by r^2, we get:

r^2(R''/R + (1/r)R'/R) + Z'' = 0

Since the left-hand side of this equation is a function of r only and the right-hand side is a function of z only, they must be equal to a constant, say -λ^2:

r^2(R''/R + (1/r)R'/R) = -λ^2

Z'' = λ^2

Simplifying the first equation and multiplying by R, we get:

r^2R'' + rR' - λ^2R = 0

This is a Bessel's equation with order 0. Its solutions are of the form:

R(r) = c1J0(λr) + c2Y0(λr)

where J0 and Y0 are the Bessel functions of the first and second kind, respectively. However, since we want R to be finite as r → 0, we must set c2 = 0. Therefore, R(r) = c1J0(λr).

Similarly, the equation for Z(z) becomes:

Z'' - λ^2Z = 0

This is a second-order ordinary differential equation with constant coefficients. Its solutions are of the form:

Z(z) = c3e^λz + c4e^(-λz)

where c3 and c4 are constants.

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The minimal point does not have x = 0.

(a) Kuhn-Tucker conditions for the minimal value of fThe Kuhn-Tucker conditions are a set of necessary conditions for a point x* to be a minimum of a constrained optimization problem subject to inequality constraints. These conditions provide a way to find the optimal values of x1, x2, ..., xn that maximize or minimize a function f subject to a set of constraints. Let's first write down the Lagrangian: L(x, y, λ1, λ2, λ3) = f(x, y) - λ1(x+y-1) - λ2(xy-3) - λ3x - λ4y Where λ1, λ2, λ3, and λ4 are the Kuhn-Tucker multipliers associated with the constraints. Taking partial derivatives of L with respect to x, y, λ1, λ2, λ3, and λ4 and setting them equal to 0, we get the following set of equations: 4x - 2y - λ1 - λ2y - λ3 = 0 2y - 2x - λ1 - λ2x - λ4 = 0 x + y - 1 ≤ 0 xy - 3 ≤ 0 λ1 ≥ 0 λ2 ≥ 0 λ3 ≥ 0 λ4 ≥ 0 λ1(x + y - 1) = 0 λ2(xy - 3) = 0 From the complementary slackness condition, λ1(x + y - 1) = 0 and λ2(xy - 3) = 0. This implies that either λ1 = 0 or x + y - 1 = 0, and either λ2 = 0 or xy - 3 = 0. If λ1 > 0 and λ2 > 0, then x + y - 1 = 0 and xy - 3 = 0. If λ1 > 0 and λ2 = 0, then x + y - 1 = 0. If λ1 = 0 and λ2 > 0, then xy - 3 = 0. We now consider each case separately. Case 1: λ1 > 0 and λ2 > 0From λ1(x + y - 1) = 0 and λ2(xy - 3) = 0, we have the following possibilities: x + y - 1 = 0, xy - 3 ≤ 0 (i.e., xy = 3), λ1 > 0, λ2 > 0 x + y - 1 ≤ 0, xy - 3 = 0 (i.e., x = 3/y), λ1 > 0, λ2 > 0 x + y - 1 = 0, xy - 3 = 0 (i.e., x = y = √3), λ1 > 0, λ2 > 0 We can exclude the second case because it violates the constraint x, y ≥ 0. The first and third cases satisfy all the Kuhn-Tucker conditions, and we can check that they correspond to local minima of f subject to the constraints. For the first case, we have x = y = √3/2 and f(x, y) = -1/2. For the third case, we have x = y = √3 and f(x, y) = -2. Case 2: λ1 > 0 and λ2 = 0From λ1(x + y - 1) = 0, we have x + y - 1 = 0 (because λ1 > 0). From the first Kuhn-Tucker condition, we have 4x - 2y - λ1 = λ1y. Since λ1 > 0, we can solve for y to get y = (4x - λ1)/(2 + λ1). Substituting this into the constraint x + y - 1 = 0, we get x + (4x - λ1)/(2 + λ1) - 1 = 0. Solving for x, we get x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4. We can check that this satisfies all the Kuhn-Tucker conditions for λ1 > 0, and we can also check that it corresponds to a local minimum of f subject to the constraints. For this value of x, we have y = (4x - λ1)/(2 + λ1), and we can compute f(x, y) = -3/4 + (5λ1^2 + 4λ1 + 1)/(2(2 + λ1)^2). Case 3: λ1 = 0 and λ2 > 0From λ2(xy - 3) = 0, we have xy - 3 = 0 (because λ2 > 0). Substituting this into the constraint x + y - 1 ≥ 0, we get x + (3/x) - 1 ≥ 0. This implies that x^2 + (3 - x) - x ≥ 0, or equivalently, x^2 - x + 3 ≥ 0. The discriminant of this quadratic is negative, so it has no real roots. Therefore, there are no feasible solutions in this case. Case 4: λ1 = 0 and λ2 = 0From λ1(x + y - 1) = 0 and λ2(xy - 3) = 0, we have x + y - 1 ≤ 0 and xy - 3 ≤ 0. This implies that x, y > 0, and we can use the first and second Kuhn-Tucker conditions to get 4x - 2y = 0 2y - 2x = 0 x + y - 1 = 0 xy - 3 = 0 Solving these equations, we get x = y = √3 and f(x, y) = -2. (b) Show that the minimal point does not have x=0.To show that the minimal point does not have x=0, we need to find the optimal value of x that minimizes f subject to the constraints and show that x > 0. From the Kuhn-Tucker conditions, we know that the optimal value of x satisfies one of the following conditions: x = y = √3/2 (λ1 > 0, λ2 > 0) x = √3 (λ1 > 0, λ2 > 0) x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4 (λ1 > 0, λ2 = 0) If x = y = √3/2, then x > 0. If x = √3, then x > 0. If x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4, then x > 0 because λ1 ≥ 0.

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The function has a minimum of -4.35125

From the question, the equation of tis given as

f(x)=2x^2-9.1x+6

Rewrite the function as follows

f(x) = 2x² -9.1x + 6

Next, we differentiate the function

This is represented as

f'(x) = 2 * 2x - 1 * 9.1 + 0 * 6

Evaluate

f'(x) = 4x - 9.1

Set the differentiated function to 0

This is represented as

f'(x) = 0

So, we have

4x - 9.1 = 0

This gives

4x = 9.1

Divide by 4

x = 2.275

Substitute x = 2.275  in f(x) = 2x² -9.1x + 6

f(2.275) = 2(2.275)² - 9.1(2.275) + 6

Evaluate

f(2.275) = -4.35125

Hence, the minimum is -4.35125

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Answer:

-4=x

Step-by-step explanation:

1) 1-2x=-x-3 (letter's to the left)

2) then you get 1-x=-3

3) then you subtract 1 on both sides

4) then you dived the -1

5)answer -4=x

Therefore, The p-value is the probability of obtaining a test statistic as extreme or more extreme than the observed value, assuming the null hypothesis is true. If the p-value is less than the significance level, reject the null hypothesis; otherwise, fail to reject it.

To find the p-value from the t statistic on TI-84, you will need to perform a hypothesis test. Here are the steps:1. Enter your data into the calculator and choose the appropriate test.2. Calculate the t statistic by dividing the sample mean by the standard error.3. Determine the degrees of freedom. This is n-1 for a one-sample t-test or n1+n2-2 for a two-sample t-test. 4. Use the t-distribution table to find the critical value for your test.5. Calculate the p-value using the t-distribution function on the calculator.6. Compare the p-value to the significance level (usually 0.05) to determine whether to reject or fail to reject the null hypothesis.7.

Therefore, The p-value is the probability of obtaining a test statistic as extreme or more extreme than the observed value, assuming the null hypothesis is true. If the p-value is less than the significance level, reject the null hypothesis; otherwise, fail to reject it.

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The Option C is correct that Negative 3 less-than x less-than-or-equal-to 2 by solving inequality using an algebraic expression.

The equation-like form of the formula 5x 4 > 2x + 3 has an arrowhead in place of the equals sign. It is an illustration of inequity. The left half, 5x 4, is larger than the right half, 2x + 3, as evidenced by this.

To solve the inequality, we need to isolate the variable, x, in the middle of the inequality.

Starting with:

-4 < 3x + 5 ≤ 11

Taking out 5 from each component of the inequality:

-4 - 5 < 3x + 5 - 5 ≤ 11 - 5

Simplifying:

-9 < 3x ≤ 6

Dividing by 3 (and remembering to reverse the direction of the inequality if we divide by a negative number):

-3 < x ≤ 2

Therefore, the solution to the inequality is:

-3 < x ≤ 2

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The Option C is correct that Negative 3 less-than x less-than-or-equal-to 2 by solving inequality using an algebraic expression.

The equation-like form of the formula 5x 4 > 2x + 3 has an arrowhead in place of the equals sign. It is an illustration of inequity. The left half, 5x 4, is larger than the right half, 2x + 3, as evidenced by this.

To solve the inequality, we need to isolate the variable, x, in the middle of the inequality.

Starting with:

-4 < 3x + 5 ≤ 11

Taking out 5 from each component of the inequality:

-4 - 5 < 3x + 5 - 5 ≤ 11 - 5

Simplifying:

-9 < 3x ≤ 6

Dividing by 3 (and remembering to reverse the direction of the inequality if we divide by a negative number):

-3 < x ≤ 2

Therefore, the solution to the inequality is:

-3 < x ≤ 2

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Answer:

Step-by-step explanation:

Hope this helps u !!

Step-by-step explanation:

\( \frac{ {x}^{a + b} \times {x}^{b + c} \times {x}^{c + a} }{ {x}^{2a} \times {x}^{2b} \times {x}^{2c} } \\ \\ = \frac{ {x}^{a + b + b + c + c + a} }{ {x}^{2a + 2b + 2c} } \\ \\ (∵ {x}^{m} \times {x}^{n} = {x}^{m + n} ) \\ \\ = \frac{ {x}^{2a + 2b + 2c} }{ {x}^{2a + 2 b+ 2c} } \\ \\ = 1\)

\(\large\mathfrak{{\pmb{\underline{\orange{Mystique }}{\orange{♡}}}}}\)

As per the double integral, the flux of the vector is 2√11(6z + 1) + 176

What is double integral small definition?

In math, Double integrals are used to find the flux of a vector field through a given surface S and find the normal to the given surface and equations of the surface to find the limits of integration.

And it is calculate by the formula as Flux= ∫∫F⋅ndS

Here we have given that S be the part of the plane 2x + 1y + z = 2 which lies in the first octant, oriented upward.

And we need to find the the flux of the vector field F = 1i + 1j + 3k across the surface S.

As per the formula of flux of vector, it can be written as,

=>Flux =  ∫∫(1i + 1j + 3k) . 2 dS

When we integrate this one the we get,

=> Flux = 2√11(6z + 1) + 176

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Answer:

3

Step-by-step explanation:

I believe it is 3 because you are multiplying each number by 3 to get your bigger shape

Kate's mistake was in Step 2: "Divide the volume of Wesley's tank by 2." Since she wants a tank with half the volume of Wesley's tank, she should have divided the volume of Wesley's tank by 2, not the radius.

The correct approach would be to use the formula for the volume of a sphere:

V = (4/3)πr^3

Since Wesley's tank has a diameter of 30 cm, its radius is 15 cm. Substituting this value into the formula gives:

V = (4/3)π(15)^3

V ≈ 14,137 cm^3

To find the radius of the smaller tank with half the volume, Kate should have solved for the radius using the formula for the volume of a sphere:

(4/3)πr^3 = (1/2)(4/3)π(15)^3

Simplifying this equation gives:

r^3 = (1/2)(15)^3

r ≈ 10.8 cm

Therefore, the approximate diameter of the smaller tank should be 21.6 cm (twice the radius), not 10.8 cm.

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If the margin of error is 4.6, the interval estimate would be the point estimate plus or minus 4.6.

In statistical estimation, the margin of error represents the maximum amount by which the point estimate may deviate from the true population parameter. It provides a measure of the precision or uncertainty associated with the estimate. When constructing a confidence interval, the margin of error is used to determine the range within which the true parameter is likely to fall.

To obtain the interval estimate, we add and subtract the margin of error from the point estimate. Let's denote the point estimate as x bar. Therefore, the interval estimate can be expressed as X bar ± 4.6, where ± denotes the range above and below the point estimate.

In summary, if the margin of error in an interval estimate of μ is 4.6, the interval estimate is given by the point estimate plus or minus 4.6. This range captures the likely range of values for the true population parameter μ.

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Answer:

Put it in math-way and please write the expression so I can solve it

Step-by-step explanation:

The appropriate response will be (A). The first equation of motion gives the link between "velocity and time."

Equation: A statement that two variable or integer expressions are equal. In essence, equations are questions, and the motivation for the development of mathematics has been the systematic search for the answers to these questions.

An equation is a mathematical representation of two equal objects, one on each side of a "equals" sign. We can solve challenges in our daily lives with the aid of equations. Most of the time, we look for help with pre algebra to resolve problems in real life. Pre-algebra concepts contain the fundamentals of mathematics.

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Answer:

i believe the answer is 80

Step-by-step explanation:

We can't have a fraction of a pancake, we round down the result to the nearest whole number. Therefore, Jerry can make a maximum of 0 pancakes.

To determine the number of pancakes Jerry can make using the remaining strawberries, we need to calculate the quantity of strawberries left after making the breakfast smoothie.

Jemy initially has 4(1)/(2) cups of strawberries. He uses (3)/(4) cup to make the smoothie, so the amount of strawberries used is:

(3)/(4) * 4(1)/(2) = (3)/(4) * (9)/(2) = (27)/(8) cups of strawberries

To find the remaining strawberries, we subtract the amount used from the initial quantity:

4(1)/(2) - (27)/(8) = (33)/(8) - (27)/(8) = (6)/(8) = (3)/(4) cups

Now, we can determine how many pancakes Jerry can make using the remaining (3)/(4) cups of strawberries. It takes 1(1)/(4) cups of strawberries to make one pancake.

To find the number of pancakes, we divide the remaining strawberries by the amount required for one pancake:

(3)/(4) / 1(1)/(4) = (3)/(4) * (4)/(5) = (3)/(5) = 0.6

Hence, Jerry can make 0 pancakes using the remaining strawberries.

It's worth noting that the result indicates that the remaining quantity of strawberries is not sufficient to make a complete pancake. If Jerry wants to make at least one pancake, he would need to have at least 1(1)/(4) cups of strawberries remaining.

Keep in mind that the calculations are based on the given quantities and assumptions. If the available quantities change or there are additional factors to consider, such as the availability of other ingredients or recipe variations, the number of pancakes that can be made may differ.

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The outward flux of the vector field F across the boundary of the region D, which is the cube bounded by the planes x = ±1, y = ±1, and ±1, can be found using the divergence theorem.

The outward flux is the integral of the divergence of F over the volume enclosed by the boundary surface.The first step is to calculate the divergence of F. The divergence of a vector field F = P i + Q j + R k is given by div(F) = ∂P/∂x + ∂Q/∂y + ∂R/∂z. In this case, div(F) = ∂/∂x(5y - 4x) + ∂/∂y(-4z - 5y) + ∂/∂z(-3y - 2x). Simplifying these partial derivatives, we have div(F) = -4 - 2 - 3 = -9.

Applying the divergence theorem, we can relate the flux of F across the boundary surface to the triple integral of the divergence of F over the volume enclosed by the surface. Since D is a cube with sides of length 2, the volume enclosed by the surface is 2^3 = 8.

Therefore, the outward flux of F across the boundary of D is given by ∬S F · dS = ∭V div(F) dV = -9 * 8 = -72. The negative sign indicates that the flux is inward.

In summary, the outward flux of the vector field F across the boundary of the cube D, as described by the given vector components, is -72. This means that the vector field is predominantly flowing inward through the boundary of the cube.

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Answer:

this is just a hint

Step-by-step explanation:

the question measures 6.EE.7 because it asks the student to solve a real-world problem by writing an equation of the form px=qpx=qpx=q for a case in which p,qp,qp,q and x are all non-negative rational numbers. In this case the equation includes a division expression and shows the total cost of $13.50\$ 13.50$13.50 divided by 666, the number of spiral notebooks.

Answer:

3 cm

Step-by-step explanation:

To match decimal values with their corresponding hexadecimal values, we need to convert the decimal numbers into their hexadecimal equivalents using division and remainders.

To match each decimal value on the left with the corresponding hexadecimal value, we need to convert the decimal numbers into their hexadecimal equivalents.

Here are a few examples:

1. Decimal 10 = Hexadecimal A

To convert 10 to hexadecimal, we divide it by 16. The remainder is A, which represents 10 in hexadecimal.

2. Decimal 25 = Hexadecimal 19

To convert 25 to hexadecimal, we divide it by 16. The remainder is 9, which represents 9 in hexadecimal. The quotient is 1, which represents 1 in hexadecimal. Therefore, 25 in decimal is 19 in hexadecimal.

3. Decimal 128 = Hexadecimal 80

To convert 128 to hexadecimal, we divide it by 16. The remainder is 0, which represents 0 in hexadecimal. The quotient is 8, which represents 8 in hexadecimal. Therefore, 128 in decimal is 80 in hexadecimal.

Remember, the hexadecimal system uses base 16, so the digits range from 0 to 9, and then from A to F. When the decimal value is larger than 9, we use letters to represent the values from 10 to 15.In conclusion, to match decimal values with their corresponding hexadecimal values, we need to convert the decimal numbers into their hexadecimal equivalents using division and remainders.

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A. the elevation of the fly

A is correct because it says that the prey is above the chameleon and below that grasshopper. The above the chameleon is represented by the positive number and the below the grasshopper is represented by the negative, which means zero must be the elevation of the fly because thats the only way both numbers would fit

Answer:

-12

Step-by-step explanation:

10-22=-12

enteric shop is 92.28 before