How often does always never sometimes
1. a parallelogram is equilateral.
2. two pairs of consecutive sides of a rhombus are congruent
3. kies have at least one pair of congruent : opposite angles.

Answer:

0.48

Explanation:

4.8 is greater than 0.48.

Step-by-step explanation:

-16(2)<4x(2)-x/2(2)

-32<8x-x

-32<7x

-32/7<7x/7

-32/7<x

-4.5714285714285714<x

~-4.56<x

So after drawing the number line, indicate it starting from negative 4.6 and pointing the arrow towards the right. Do not shade

To visualize this transformation, imagine a rectangle with vertices at and (0,2). Applying the transformation (x,y) →  \((3x,3y)\) to each vertex, we get a new rectangle with vertices at   \((0,0), (3,0), (3,6),\) and \((0,6)\), which is three times the size of the original rectangle.

Algebraic representations can take many forms, including equations, inequalities, functions, and matrices. These representations provide a powerful tool for analysing complex systems and deriving meaningful insights from them.

The algebraic representation \((x,y) (3x,3y)\) describes a dilation transformation, specifically an enlargement or stretch by a scale factor of 3 in both the x and y directions.

This means that every point in the original figure is multiplied by 3 in both the x and y directions, resulting in a larger, similar figure.

To visualize this transformation, imagine a rectangle with vertices at  \((0,0), (1,0), (1,2),\)  and   \((0,2).\) Applying the transformation (x,y) → (3x,3y) to each vertex, we get a new rectangle with vertices at \((0,0), (3,0), (3,6),\)  and (0,6), which is three times the size of the original rectangle.

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This relationship is not transitive, symmetrical, or reflexive.

It is not reflexive because, for any x ∈ R, xd x = xx ≥ 0 is not always true.

It is not symmetric because, for any x,y ∈ R, if xd y = xy ≥ 0, then the reverse is not necessarily true (i.e. yd x = yx ≥ 0).

It is not transitive because, for any x,y,z ∈ R, if xd y = xy ≥ 0 and yd z = yz ≥ 0, then the reverse is not necessarily true (i.e. xd z = xz ≥ 0).

The relation d is defined as xd y ⇔ xy ≥ 0 for all x,y ∈ R. This relation is not reflexive because for any x ∈ R, xd x = xx ≥ 0 is not always true. It is not symmetric because for any x,y ∈ R, if xd y = xy ≥ 0, then the reverse is not necessarily true (i.e. yd x = yx ≥ 0). Lastly, it is not transitive because for any x,y,z ∈ R, if xd y = xy ≥ 0 and yd z = yz ≥ 0, then the reverse is not necessarily true (i.e. xd z = xz ≥ 0). Therefore, the relation d is none of these.

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Answer:14 meters

Step-by-step explanation:

Answer:

The numbers i and V3 are elements of the set.

Step-by-step explanation:

The rational numbers are those which can be written as fractions. These are the numbers which can be repeating elements and terminating decimals. All integers can be set of rational numbers. The statements which is not true is statement  which states that numbers i and V3 are elements of the set.

On solving the provided question, we can say that the permutation will bw  , N = (4!)(5!)(3!)(3!)= 103,680

The permutation of a set in mathematics is essentially the rearranging of its elements if the set is already ordered, or the arrangement of its members in a linear or sequential order. The act of altering the linear order of an ordered set is referred to as a "permutation" in this context. The mathematical calculation of the number of possible arrangements for a given set is known as permutation. Permutation, in its simplest form, refers to the variety of possible arrangements or orders. The placement of the elements matters with permutations. The placement of items in a specific order is known as a permutation. Here, the set's components are sorted in either chronological order or linear order. like in the case of.

we can put 3 math books and 5 English books on a shelf if all the math books must stay together and all the English books must also stay together will be , N = (4!)(5!)(3!)(3!)= 103,680

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The solution of the given equation is 2x² - 13x +13.

What is the solution of the equation?

The collection of all values that, when substituted for unknowns, cause an equation to hold true is known as the solution. Two fundamental algebraic rules using the additive property and the multiplicative property are utilized to determine the solutions for equations needing a single unknown raised to a power of one.

What is the simplification rule?

For those sorts of reasoning that deal with conjunctions, the rule of simplification provides a strong argument. This covers natural deduction, predicate logic, and propositional logic.

Here, we have

Given equation 2(x - 2)² - 5(x - 2) - 5

By applying the simplification rule, we get

= 2(x - 2)² - 5(x - 2) - 5

= 2( x² + 4 - 4x ) - 5x +10 - 5

= 2x² + 8 - 8x - 5x + 5

= 2x² - 13x +13

Hence, the solution of the given equation is 2x² - 13x +13.

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(a) The utility function U(x, y) = x²y is homogeneous of degree 3 because if we multiply both x and y by a positive constant λ, the utility function becomes U(λx, λy) = (λx)²(λy) = λ³x²y. The function exhibits a degree of homogeneity equal to the exponent of λ, which in this case is 3.

(b) The budget constraint can be derived by equating the total expenditure to the agent's income. The price of good 1 is 4, so the expenditure on good 1 is 4x, and the price of good 2 is 2, so the expenditure on good 2 is 2y. Therefore, the budget constraint is given by 4x + 2y = 12. To graph this constraint, we plot x on the horizontal axis and y on the vertical axis. The resulting line has a slope of -2 and intersects the x-axis at x = 3 and the y-axis at y = 6.

(c) To compute the marginal utility of good 1, we take the derivative of the utility function with respect to x, which gives us MU₁(x, y) = 2xy. Similarly, the marginal utility of good 2 is given by MU₂(x, y) = x².

(d) The agent's marginal rate of substitution (MRS) represents the rate at which the agent is willing to trade one good for another while maintaining the same level of utility. It is given by MRS = MU₁/MU₂ = 2xy/(x²) = 2y/x. The slope of the budget constraint is equal to the negative ratio of the prices of the two goods, which is -4/2 = -2.

(e) To derive the agent's optimal consumption bundle, we need to find the combination of x and y that maximizes the agent's utility while satisfying the budget constraint. This occurs at the point where the indifference curve (representing constant utility) is tangent to the budget constraint. In this case, the indifference curve is U(x, y) = x²y, and the optimal consumption bundle can be found by solving the system of equations formed by the utility function and the budget constraint. The resulting bundle will depend on the specific values of x and y obtained. By plotting the bundle on the (x, y) plane along with the budget constraint and an indifference curve, we can visually represent the optimal consumption bundle. The slope of the budget constraint represents the rate at which the agent can trade one good for another while staying within the budget constraint.

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Answer:

\(= 2x^{-6}y ^{21}\\\\\)

Step-by-step explanation:

Given the indicinal expression  (2x^2 y^-2 / y^5)^-3

In indices

\((x^m)^n = x^{mn\)

Applying to solve the question

\((2x^2 y^{-2} / y^5)^{-3}\\\\= \frac{2x^{-6}y^6}{y^{-15}}\\= 2x^{-6} * \frac{y^6}{y^{-15}} \\= 2x^{-6} * y ^{6-(-15)}\\= 2x^{-6} * y ^{6+15}\\= 2x^{-6} * y ^{21}\\= 2x^{-6}y ^{21}\\\\\)

Answer:

the answer would be -4 because that's the simplified version of -8+(4)

Answer:

-sin(x)

Step-by-step explanation:

im not sure what the 'difference quotient' means, but the derivative of cos(x) is just -sin(x).

Answer:

The slope is -5/2 as a fraction

or -2.5 as a decimal.

Step-by-step explanation:

First we have to get it into this format y = mx + b

5x + 2y = 6 (subtract 5x on both sides)

2y = -5x + 6 (divide by 2 on both sides)

y = -5/2x + 3

The slope is -5/2 or -2.5

Hope this helps ya!!

The given set S is linearly independent.

To test for linear independence in P3 for Exercise 21, we can use Exercise 14 and property 2 of Theorem 5.

First, we need to suppose that a linear combination of the given set equals zero. Let c1(x+1) + c2(x^2+1) + c3(x+1) + c4(1) = 0, where c1, c2, c3, and c4 are constants. Then, we can simplify this equation to (c1+c3)x^2 + (c1+c2)x + (c1+c3+c4) = 0. This means that the coefficients of the polynomial are all zero, so we can set up a system of equations to solve for the constants:

c1 + c3 = 0

c1 + c2 = 0

c1 + c3 + c4 = 0

Solving this system of equations, we get c1 = c2 = c3 = c4 = 0. Therefore, the set {x+1, x^2+1, x+1, 1} is linearly independent in P3.

For Exercise 14, we need to prove that (1, x, x^2, ..., x^n) is a linearly independent set in Pn. We can do this by supposing that p(x) = a0 + a1x + a2x^2 + ... + anx^n, where a0, a1, a2, ..., an are constants. Then, we can take the successive derivatives of p(x) as follows:

p(x) = a0 + a1x + a2x^2 + ... + anx^n

p'(x) = a1 + 2a2x + ... + nanx^(n-1)

p''(x) = 2a2 + 6a3x + ... + n(n-1)anx^(n-2)

...

p^(n)(x) = n!an

If we suppose that p(x) = (x), then p^(n)(x) = n!. But we know that (1, x, x^2, ..., x^n) is a basis for Pn, so any polynomial in Pn can be written as a linear combination of this basis. Therefore, we can write p(x) as a linear combination of (1, x, x^2, ..., x^n):

p(x) = c0(1) + c1(x) + c2(x^2) + ... + cn(x^n)

Substituting this into p^(n)(x) = n!, we get:

n! = n!cn

cn = 1

Substituting this back into p(x), we get:

p(x) = c0(1) + c1(x) + c2(x^2) + ... + cn(x^n) = c0(1) + c1(x) + c2(x^2) + ... + 1(x^n)

Since we know that (1, x, x^2, ..., x^n) is a basis for Pn, this linear combination can only equal zero if all the constants c0, c1, c2, ..., cn are zero. Therefore, (1, x, x^2, ..., x^n) is a linearly independent set in Pn.

Property 2 of Theorem 5 states that if the set S is linearly independent in V, then the set T obtained by adding a vector not in S to S is also linearly independent in V. In this case, V is RP (the set of real-valued polynomials) and S is the set (1, x, x^2, ..., x^n). So, if we add a vector not in S (for example, x^(n+1)), the resulting set T is also linearly independent in RP.

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1. The equation to slope-intercept form is y = -2/3(x) + 490. The slope is -2/3 and the y-intercept is 490.

2. You should start at the y-intercept (0, 490) and move right by 3 units and downward by 2 units, and then connect the points.

3. The equation in function notation is f(x) = -2/3(x) + 490. The graph of the function is the rate of change with respect to the number of sandwich lunch sold.

4. A graph of the function with intercepts is shown below.

5. The graphs of the functions for the two months both have the same slope but different y-intercept and x-intercept.

In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical equation;

y = mx + b

Where:

Based on the information provided above, a linear equation that models Sal's Sandwich Shop's profit is given by;

2x + 3y = 1,470

By subtracting 2x from both sides of the equation and dividing by 3, we have:

2x + 3y - 2x = 1,470 - 2x

y = -2/3(x) + 490

Therefore, the slope is -2/3 and the y-intercept is 490.

Part 2.

In order to graph the equation by using the slope-intercept method, you would start at the y-intercept (0, 490) and move right by 3 units and down by 2 units, and then connect the points.

Part 3.

Next, we would write the equation in function notation as follows;

f(x) = -2/3(x) + 490

where:

The graph represents the rate of change of the function with respect to the number of sandwich lunch sold.

Part 4.

In this context, we would use an online graphing calculator to plot the linear function as shown in the image attached below.

Part 5.

Assuming Sal's total profit on lunch specials for the next month is $1,593 and the profit amounts remain the same, a system of equations to model this situation is given by:

2x + 3y = 1593; y = -2/3(x) + 531.

2x + 3y = 1,470; y = -2/3(x) + 490.

In conclusion, we can logically deduce that the graphs of the functions for the two months both have the same slope but different y-intercept and x-intercept.

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Complete Question:

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2, and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.

Answer:

If n > 0, then n= 1

If n < 0, then n=n

If you could word this a bit differently, I might be able to help more, but this is what I'm getting from it. The way you worded it is a bit confusing.

The equation \(x^2 + y^2 + 10y + 20 = 0\) represents a circle with center (0, -5) and radius 5.

To determine if the equation represents a circle, we need to rewrite it in standard form. The standard form of a circle equation is \((x - h)^2 + (y - k)^2 = r^2\), where (h, k) represents the center of the circle and r represents the radius.

Completing the square for the y terms:

\(x^2 + y^2 + 10y + 20 = 0\\ x^2 + y^2 + 10y = -20\\ x^2 + y^2 + 10y + 25 = -20 + 25\\ x^2 + (y + 5)^2 = 5\)

Now the equation is in standard form, \((x - 0)^2 + (y + 5)^2 = 5^2\), which represents a circle.

By comparing the equation to the standard form, we can determine the center and radius of the circle. The center is given by the values (h, k), which in this case is (0, -5). Therefore, the center of the circle is (0, -5).

The radius is determined by the term \(r^2\), which in this case is \(5^2 = 25\). Therefore, the radius of the circle is 5.

In summary, the equation x^2 + y^2 + 10y + 20 = 0 represents a circle with center (0, -5) and radius 5. The completion of the square allowed us to rewrite the equation in standard form, making it evident that it represents a circle. The center of the circle is determined by the values of x and y, and the radius is determined by the value of r.

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To solve this problem, we will use the following formula for the area of a trapezoid:

where B and b are the lengths of the bases and h is the height.

Substituting B=10 ft, b=2 ft, and h=4 ft in the above formula, we get:

Simplifying we get:

Answer:

Answer:

Answer is A

- 117

_______________________________________

Answer:

ay wee tologo bo sharmaine?

The range of the given graph is [5, ∞).

Range.

Range refers the set of possible output values, and if we have the graph, then the set of all possible y values on the graph is defined as the range.

Given,

Here we have the graph.

Through the given graph we have to find the range of the line.

As per the definition of range, we have identified that the range take the value of y axis.

While we lookin into the given graph, we have identified that the starting point of the line is

=> (0, 5)

In this point 0 refers the x coordinate and 5 refers the y coordinate. So, the starting range is 5.

And the end of the line is not pointed.

So, we can consider that this line goes infinitely.

So, the range of the graph is  [5, ∞).

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Answer:

0.29 = 29% = \(\frac{29}{100}\)

35% = 0.35 = \(\frac{7}{20}\)

\(\frac{2}{5}\)= 0.40 = 40%

Step-by-step explanation:

The probability that the mean lifetime of 25 randomly selected tires of this type will exceed than 42,000 miles is 25.14.

To break this problem, we need to use the standard normal distribution, assuming that the distribution of tire continuances is roughly normal. We can regularize the value of 42,000 using the formula

z = ( x- μ)/ σ

where x is the value of interest( 42,000 long hauls), μ is the mean tire continuance( 40,000 long hauls), and σ is the standard deviation( 3,000 miles). Plugging in the values, we get

z = ( 42,000- 40,000)/ 3,000 = 0.67

Using a standard normal distribution table or calculator, we can find the probability that an aimlessly named tire will last further than 42,000 long miles by looking up the area to the right of z = 0.67 under the standard average wind. This probability is roughly 25.14.

thus, the probability that a tire named arbitrarily from this brand will last more than 42,000 miles is roughly 25.14.

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The correct question is given below-

A particular brand of tires lasts an average of 40,000 miles with a standard deviation of 3,000 miles. What is the probability a tire selected at random lasts more than 42,000 miles?

Answer: both of you have a lead yet but you can get it right away if I can see you guys again in a developer way but I have a game pass

Step-by-step explanation: yes

Answer:

Step-by-step explanation:

Given:

A. The variables are:

B. The equations are based on given parameters

Use perimeter formula

C. Solve the system above by substitution:

Find the value of l:

The length is 16 feet, the width is 5 feet

Answer:

The length of the garden is 16 ft while the width of the garden is 5 ft.

Explanation:

a)we want to start with defining the variables.

Let the length of the garden be w.

b) here, we want to create equation

From the question, the length is 6 feet more than twice the width of one garden

Mathematically, we have this as;

\(l = 2w + 6\)

Furthermore, the perimeter is 42 feet

The formula of the perimeter is;

\(2(l + w) = 42\)

Dividing both sides by 2

\(l + w = 21\)

c)Now, we want to solve both equations simultaneously

We can substitute the first equation into the second;

\(2w + 6 + w = 21 \\ 3w + 6 = 21 \\ 3w = 21 - 6 \\ 3w = 15 \\ w = \frac{15}{3} = 5\)

\(l + w = 21 \\ l = 21 - w = 21 - 5 = 16\)

Answer:

B

Step-by-step explanation:

Answer:

thx for 5 points

Step-by-step explanation:

Answer:

=2.26

Step-by-step explanation:

0.5+1.1x1.6

multiply first (pemdas)

0.5+1.76

add

=2.26

i hope this helps :)

Answer:

0.5 + 1.1 x 1.6 = 2.26

Step-by-step explanation:

check it in a calculator so it's correct

Answer:

1/64

Step-by-step explanation: