how to find the missing value with (1, 3) and (4, 7) x=-2

the answer

155

324

5/9 (87/3(1/12)= 155/324

We can use Coulomb's law to calculate the magnitude of the electric field at a distance r away from a point charge Q:

E = k * Q / r^2

where k is Coulomb's constant, Q is the charge of the point charge, and r is the distance from the point charge.

In this problem, we have a point charge Q of -10 nC located at (1.2 cm, 0 cm), and we want to find the x-component of the electric field at a distance r = 5.3 cm away at position (-4.1 cm, 0 cm).

To find the x-component of the electric field, we need to use the cosine of the angle between the electric field vector and the x-axis, which is cos(180°) = -1.

So, the x-component of the electric field at position (-4.1 cm, 0 cm) is:

E_x = - E * cos(180°) = - (k * Q / r^2) * (-1)

where k = 9 x 10^9 N*m^2/C^2 is Coulomb's constant.

Substituting the given values, we get:

E_x = - (9 x 10^9 N*m^2/C^2) * (-10 x 10^-9 C) / (0.053 m)^2

E_x ≈ -30,566.04 N/C

Rounding this to two significant figures and including the appropriate units, we get:

The x-component of the electric field is about -3.1 x 10^4 N/C (to the left).

Answer:

1,2, and 4 are the correct answers

Step-by-step explanation:

Answer:

1. The sides that were parallel in the pre-image are parallel in the image.

2. The angle measures of ABCD are equal to the corresponding angle measures of A’B’C’D’.

4. The segments connecting the center of rotation to the corresponding vertices create a 270° angle.

Step-by-step explanation:

Edge 2021

Answer:

Step-by-step explanation:

tan28=h/150

h=150tan28

h=79.8ft

x/(12+8)=5/8

x/20=5/8

x=100/8

x=12.5

You can use the well-known binomial series,

\(\displaystyle (1+x)^\alpha = \sum_{k=0}^\infty \binom \alpha k x^k\)

where

\(\dbinom \alpha k = \dfrac{\alpha(\alpha-1)(\alpha-2)\cdots(\alpha-(k-1))}{k!} \text{ and } \dbinom \alpha0 = 1\)

Let \(\alpha=\frac12\) and replace \(x\) with \(3x\); then the series expansion is

\(\displaystyle (1+3x)^{1/2} = \sum_{k=0}^\infty \binom{\frac12}k (3x)^k\)

and the first 4 terms in the expansion are

\(\sqrt{1+3x} \approx 1 + \dfrac{\frac12}{1!}(3x) + \dfrac{\frac12\cdot\left(-\frac12\right)}{2!}(3x)^2 + \dfrac{\frac12\cdot\left(-\frac12\right)\cdot\left(-\frac32\right)}{3!}(3x)^3\)

which simplify to

\(\sqrt{1+3x} \approx \boxed{1 + \dfrac32 x - \dfrac98 x^2 + \dfrac{27}{16} x^3}\)

You can also use the standard Maclaurin coefficient derivation by differentiating \(f\) a few times.

\(f(x) = (1+3x)^{1/2} \implies f(0) = 1\)

\(f'(x) = \dfrac32 (1+3x)^{-1/2} \implies f'(0) = \dfrac32\)

\(f''(x) = -\dfrac94 (1+3x)^{-3/2} \implies f''(0) = -\dfrac94\)

\(f'''(x) = \dfrac{81}8 (1+3x)^{-5/2} \implies f'''(0) = \dfrac{81}8\)

Then the 3rd order Maclaurin polynomial is the same as before,

\(\sqrt{1+3x} \approx f(0) + \dfrac{f'(0)}{1!} x + \dfrac{f''(0)}{2!} x^2 + \dfrac{f'''(0)}{3!} x^3 = 1 + \dfrac32 x - \dfrac98 x^2 + \dfrac{27}{16} x^3\)

Now,

\(\sqrt{1.3} = \sqrt{1+3x} \bigg|_{x=\frac1{10}} \\\\ ~~~~~~~~ \approx 1 + \dfrac32 \left(\dfrac1{10}\right) - \dfrac98 \left(\dfrac1{10}\right)^2 + \dfrac{27}{16} \left(\dfrac1{10}\right)^3 \\\\ ~~~~~~~~ = \dfrac{18,247}{16,000} \approx \boxed{1.14044}\)

Compare to the actual value which is closer to 1.14018.

\(\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}\) is the maclaurin polynomial and estimate value of \(\sqrt{1.3}\) is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.

Given the polynomial,

\(f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }\)

The formula to find the maclaurin polynomial,

\(f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}\)

Next we have to find f'(x), f''(x) and f'''(x),

By putting x = 0 , we get,

Therefore the maclaurin polynomial by using the formula will be,

\(\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}\)

\(\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}\)

To find the value of \(\sqrt{1.3}\)  we can use the maclaurin polynomial,

\(\sqrt{1.3}\) is  \(\sqrt{1+3x}\) with x = 1/10,

\(\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}\)

\(\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14\)

Hence \(\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}\) is the maclaurin polynomial and estimate value of \(\sqrt{1.3}\) is 1.14.

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Answer:

13.38

Step-by-step explanation:

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Answer:13.3829787234

Dividing decimals are the same as dividing whole numbers.

for this one I divided it and got 13.3829787234.

Answer:

1/2⁴ = 1/16

Step-by-step explanation:

2³/2⁷

3 - 7 = -4

2^-4 = 1/2⁴ = 1/16

Answer:

\(\frac{1}{16}\)

Step-by-step explanation:

\(\frac{2^{3} }{2^{7} } =2^{3-7} =2^{-4}\)

\(2^{-4} =\frac{1}{2^{4} } =\frac{1}{16}\)
Hope this helps.

a) 80 hours after 11:00 on a 12-hour clock would be 7:00.

b) 40 hours before 12:00 on a 12-hour clock would be 4:00.

c) 100 hours after 6:00 on a 12-hour clock would be 10:00.

a, To find this, we need to divide 80 by 12 (the number of hours on the clock), which gives us a quotient of 6 and a remainder of 8. We then add the remainder to the starting time of 11:00, giving us 7:00.

b, To find this, we need to subtract 40 from 12 (the number of hours on the clock), which gives us 8. We then subtract 8 from the starting time of 12:00, giving us 4:00.

c, To find this, we need to divide 100 by 12 (the number of hours on the clock), which gives us a quotient of 8 and a remainder of 4. We then add the quotient (which represents a full cycle of 12 hours) to the starting time of 6:00, giving us 6+8=14:00, which is equivalent to 2:00 on a 12-hour clock. Finally, we add the remainder of 4 to 2:00, giving us 10:00.

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Answer: Right

Step-by-step explanation:

Answer:

Your answers for #2 and #4 are incorrect.

Step-by-step explanation:

For #2:

For #4:

Answer:3and 4

Step-by-step explanation:

Answer:

um 3 and 4

Step-by-step explanation:

is this a trick question

Answer:

the answer for this one is B

Answer:

The answer would be B.

Step-by-step explanation:

Just substitute x for 5.

For example, A is 2+x=3.

Just put 5 instead of x.

It would be 2+5=3.

But that isn't the answer because 2+5 is 7, not 3.

For B, sub the x for 5 just like we did for A.

It would usually be 3x=15

But sub the x with 5.

It would turn into 3x5=15

And that is right, because if you multiple 5 three times, it would be 15.

I hope this helps, I did my best. Have a great day!

Answer:

A

Step-by-step explanation:

That's the only one that makes sense

Answer:

It's either A or C

Step-by-step explanation:

Answer:

i- um chile anywaysssss

The given equation 6x+2y=13 is a linear equation in two variables. In this equation, x and y are variables while 6 and 2 are their respective coefficients, and 13 is a constant term. The equation can be represented as a straight line on a graph. The slope of this line is -3, and it intersects the y-axis at the point (0, 13/2).

In this equation, if we substitute x=0, then y=13/2, and if we substitute y=0, then x=13/6. These are the two points that the line passes through the x and y-axis.

A linear equation is a polynomial equation that is of the first degree, meaning the variables in the equation are not raised to any powers other than one. This equation is in the standard form where the variables are in the first degree. 6x + 2y = 13 is the form of the given linear equation. x and y are the two variables, and 6 and 2 are their respective coefficients. The equation can be represented as a straight line on a graph. The slope-intercept form of this equation is y = -3x + 13/2. The equation is also in standard form.

When x = 0, the equation becomes 2y = 13. This means that the point of intersection is (0, 13/2) when y = 0, the equation becomes 6x = 13, and the point of intersection is (13/6, 0). The slope of the line is -3. When x increases by 1, y decreases by 3.

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Answer:

3 must be added to the numbers; 5, 9, 7, 12 to get the numbers which are in proportion

Step-by-step explanation:

Answer:

The Answer is 3

7-5=3

9-7=3

12-9=3

A plot that will present the information that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc. : histogram

In this question, we have been given the tree heights recorded on a school campus.

A science teacher wants to choose a data display that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc.

We need to find a correct plot that will present the information in this way.

We know that in bar charts, each bar represents one value(category). And  in a histogram, each bar will represent a continuous data

Therefore, a plot that will present the information that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc. : histogram

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Answer:

Step-by-step explanation:

A plot that will display information highlighting the number of trees in a range of heights, such as 60-64, 65-69, and so on: histogram

We were provided the tree heights reported on a school grounds in this question. A science instructor needs to select a data presentation that will show how many trees are in a given height range, such as 60-64, 65-69, and so on. We must find a suitable plot to portray the data in this manner. We know that each bar on a bar chart represents one value (category). And each bar in a histogram represents continuous data.

Answer:

Step-by-step explanation:

Image result for Guadalupe went shopping for a new pair of pants. Sales tax where she lives is 7%. The price of the pair of pants is $33. Find the total price including tax. Round to the nearest cent.

Step 1: take the total price and divide it by one plus the tax rate.

Step 2: multiply the result from step one by the tax rate to get the dollars of tax.

Step 3: subtract the dollars of tax from step 2 from the total price.

Pre-Tax Price = TP – [(TP / (1 + r) x r]

TP = Total Price.

The price of the pants after tax is $35.31

A percentage is a number or ratio that can be expressed as a fraction of 100. If we have to calculate the percent of a number, divide the number by the whole and multiply by 100. Hence, the percentage means, a part per hundred. The word percent means per 100. It is represented by the symbol “%”

Given here: Price of the pants before tax= $33 and tax rate as 7%

Thus 7% of 33=2.31

Thus price after tax is equal to $33+$2.31=$35.31

Hence, The price of the pants after tax is $35.31

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Answer:

60 inches

Step-by-step explanation:

There are 12 inches in a foot.

There are 3 feet in a yard.

With this information, Joe is 5 feet away from finishing the race, but we need that answer in inches.

So if one foot equals 12 inches, we will simply multiply:

5ft × 12 in = 60 inches

(Hope this helps :) )

Answer:

y = 3

Step-by-step explanation:

The matrix B that organizes the data is given as follows:

B = [13, 36, 27,

      10, 15, 0,

       23, 51, 27].

The matrix that shows the total value of each cap size in each location is given as follows:

C = [247, 684, 513,

      190, 285, 0,

      437, 969, 513].

The matrix B is defined considering that it will have three rows and three columns, as follows:

Then the matrix B is defined as follows:

B = [13, 36, 27,

      10, 15, 0,

       23, 51, 27].

The cost of each baseball cap is of $19, thus the cost matrix is obtained multiplying the matrix B by the constant of 19.

When a matrix is multiplied by a constant, all the elements of the matrix are multiplied by the constant, hence the cost matrix is given as follows:

C = [247, 684, 513,

      190, 285, 0,

      437, 969, 513].

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The factored expression of the expression 4x³ - 6x² + 8x is 2x(2x² - 3x + 2)

From the question, we have the following parameters that can be used in our computation:

4x³ - 6x² + 8x

The above expression is a polynomial expression

So, we have the following

4x³ - 6x² + 8x

Factor out x in 4x³ - 6x² + 8x

This gives

4x³ - 6x² + 8x = x(4x² - 6x + 8)

Factor out 2 in 4x² - 6x + 8

This gives

4x³ - 6x² + 8x = 2x(2x² - 3x + 2)

Hence, the factored expression is 2x(2x² - 3x + 2)

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The solution is Option B.

Noise is easily filtered out without damage to the original signal because a narrow range of values is expected

A digital signal encodes data as a sequence of discrete values. A digital signal can only have one value from a finite set of possible values at any given time. A signal which is a discrete function of time, i.e. non-continuous signal, is known as digital signal. Digital computers and digital phones are some of the examples of digital signals

The three types of digital signals are

Continuous-Time/Analog Signal

Discrete-Time Signal

Digital Signal

Given data ,

The digital signals are a more reliable way to encode and transmit information than analog signals

Because , while transmitting information through digital signals , they have less interference over long distances and digital signals offer better clarity

The digital devices only record pieces of sound waves, not full waves.

Now , Analog technology stores information as sound waves; digital technology stores it as strings of ones and zeroes.

Hence , noise is easily filtered out without damage to the original signal because a narrow range of values is expected

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INFORMATION:

We know that the function that describes Katie's parabolic trajectory is

And we must graph it, identifying Katie's start and end points

STEP BY STEP EXPLANATION:

Since we have a parabola, we can calculate the vertex to graph it

The formula for the vertex is

In this case, a = -16 and b = 16

Now, replacing in the formula

Now, we must replace t = 1/2, to find the coordinate of the vertex

Then, the coordinate of the vertex is (1/2, 676)

Now, we can find the x intercepts if we equal the function to 0 and solve for t

Now, knowing the vertex and the x-intercepts we can graph the function

In the graph we take the positive part of the parabola because t (x-axis) represents time and the time must be positive

The end point would be when h(t) = 0

ANSWER:

The missing words to complete the proof are respectively; Vertical Angles; Corresponding angles; Transitive Property

The image of the transversal line is attached.

1) We know that lines a and b are parallel and that line c is a transversal because that is given.

2) We can tell that angles 2 and 5 are congruent because vertical angles are congruent.

3) Angles 5 and 7 are congruent because corresponding angles by parallel lines cut by a transversal are congruent.

4) Therefore, angles 2 and 7 are congruent based on the transitive property.

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Answer: vertical, corresponding, and transitive property

Step-by-step explanation: I got the correct answer on Edge 2022. The answer is correct trust me! Proof is shown down below.

Answer:

NaNx10^-15

Step-by-step explanation:

sorry did not know you wanted it in standard form before

Answer:

35 eighth graders

Step-by-step explanation:

.125 x 280

Answer: 35 students

Step-by-step explanation:

288/36 = 8

256/32 = 8

280/35 = 8

All should have the same factor