how will an electromagnet’s strength change if the amount of current traveling through it increases?

Answer:

   \(4 m/s^{2}\)

Explanation:

You can use the formula a = (v2 - v1)/t, where a is the acceleration, v1 is the initial velocity, v2 is the final velocity, and t is the time interval.

In this case, v1 is 0 m/s (since the car starts at rest) and v2 is the final velocity of the car after it travels 100 m in 5 seconds. You can use the formula v = d/t to find the final velocity, where v is the velocity, d is the distance traveled, and t is the time taken. Plugging in the given values, you get:

v = d/t

= 100 m / 5 s

= 20 m/s

Now you can plug in the values for a, v1, v2, and t into the formula to find the acceleration:

a = (v2 - v1)/t

= (20 m/s - 0 m/s)/5 s

= \(4 m/s^{2}\)

Answer:

A

Explanation:

if he goes to the west, the east is opposite so 100-30

The jogger's displacement was 70 meters. Hence, option (a) is correct answer.

The term "displacement" refers to a shift in an object's position. The symbol for it is an arrow pointing from the initial location to the ending place.

Displacement is a vector quantity as both magnitude and direction are required for defining displacement. SI unit of Displacement is meter.

Given parameter:

The first displacement of the jogger is = 100 meters along west  direction.

The second displacement of the jogger is = 30 meters along east direction.

Hence, resultant displacement of the jogger along west  direction = 100 meters - 30 meters

= 70 meters.

Hence,  the magnitude of jogger's displacement was 70 meters. Hence, option (a) is correct answer.

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9514 1404 393

Answer:

  27.85 m/s

Explanation:

If we take the direction of motion of the aircraft carrier as positive, The speed of the deck is 31.0 m/s. Bond is running in the opposite direction, so his speed relative to the deck is -3.15 m/s.

Bond's speed relative to the stationary reference (the sub or the water), is ...

  31.0 m/s - 3.15 m/s = 27.85 m/s

Answer:

b) downward. Correct choice

Explanation:

Projectile Motion

It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

The gravity manifests through the acceleration of gravity g whose value is \(9.8 m/s^2\) and points downward. The object will eventually fall to the ground at a time and speed which depends on the initial speed and launch angle.

When the bullet is fired regardless of the initial speed and angle, the only acceleration of the system is g, thus:

b) downward. Correct choice

The acceleration acts on the bullet will be the acceleration due to gravity that is g and has a downward direction.

Since the bullet is fired at an angle of 45 so the bullet will travel in a projectile. So every point in time the acceleration due to gravity will act on the bullet.

After some point in time, the bullet will come to the surface of the earth as the energy in the bullet will reduce.

As we know that anything present on the earth is under the influence of the earth's gravity.

So the fired bullet will experience acceleration due to the gravity of the earth and the direction of the acceleration will always be downwards.

So the bullet will eventually fall to the ground at a time and speed which depends on the initial speed and launch angle.

Thus the acceleration acts on the bullet will be the acceleration due to gravity that is g and has a downward direction.

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The magnitude of the vertical force C = 624/2= 312 kips or 24.9 kips.

The given data is as follows: Length of the left side of the beam, L1 = 8 ft, Length of the right side of the beam, L2 = 5 ft

Concentrated load acting at the mid-span, W = 8 kips/ft

From the principle of superposition, we can find the vertical reaction at support C as follows;

As there is no lateral force acting on the beam, the vertical reaction force acting on the support C will be equal to the vertical load on the left half of the beam and the right half of the beam respectively.

The load on the left half of the beam is given by wl1/2, and the load on the right half of the beam is given by wl2/2.

Thus, the total vertical load on the beam is given by (wl1 + wl2)/2. Therefore, the vertical reaction force acting on the support C is given the same value.

The total weight of the beam is given by the total load multiplied by the length of the beam. The total weight of the beam can be calculated as follows;

Total load on the beam = (Wl1 + Wl2)/2= 8 x (8+5)/2= 52 kips

Total weight of the beam = 52 kips x 12 ft = 624 kips

Now, the total vertical reaction force acting on the beam will be equal to the total weight of the beam.

Therefore, the Total vertical reaction force acting on the beam = 624 kips

The magnitude of the vertical force C is equal to the total vertical load on the left half and right half of the beam, which is equal to half of the total weight of the beam.

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Answer:

217 N

Explanation:

Answer:217N

Explanation:

The maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 v is 75 A.

To calculate the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V, we need to use the equation: `V = E - Ir`, where `V` is the terminal voltage, `E` is the electromotive force, `I` is the current, and `r` is the internal resistance of the battery.Rearranging the equation, we get: `I = (E - V)/r`Substituting the given values, we get: `I = (9.00 V - 8.90 V)/0.012 Ω`I = 8.33 ΩΩ, or 75 A (rounded to the nearest whole number).Therefore, the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is 75 A.

We know that the internal resistance of the battery is 0.012 Ω and the electromotive force is 9.00 V. The formula used to calculate the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is I = (E - V)/r.Here, E = 9.00 V, V = 8.90 V, and r = 0.012 Ω.I = (9.00 V - 8.90 V)/0.012 ΩI = 83.3 ΩΩRounding off to the nearest whole number gives the answer of 75 A. Therefore, the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is 75 A.

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There is no row where all the premises (N ↔ ¬S, ¬N, S → F, F) are true and the conclusion (¬N) is false. Therefore, the argument is valid based on the given premises and their corresponding truth values.

The arguments in the symbolic form:

The truth table is there to determine the validity of the arguments,

There is no row where all the premises (N ↔ ¬S, ¬N, S → F, F) are true and the conclusion (¬N) is false. Therefore, the argument is valid based on the given premises and their corresponding truth values.

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Answer:

Drawing the triangle:

H / x = tan 52.2 = 1.29

H / (4.6 - x) = tan 28.8 = .550

H = 1.29 x

H = .55 * 4.6 - .55 x

1.84 x = 2.53        combining equations

x = 1.38

4.6 - 1.38 = 3.22

Total base of triangle = 1.38 + 3.22 = 4.6

H / x = tan 52,2 = 1.29

H = 1.29 * 1.38 = 1.78 height of triangle

Check:

1.78 / 3.22 = tan 28.9    

This agrees with the given value of 28.8

We will determine the current as follows:

First, we remember that:

So:

So, the current is 3 Amps.

The linear velocity of the solid sphere at the bottom of the incline is approximately 6.69 m/s.

To solve this problem, we can analyze the forces acting on the solid sphere as it rolls down the incline.

Diameter of the sphere (d) = 7.80 cm = 0.078 m

Mass of the sphere (m) = 320 g = 0.320 kg

Length of the incline (h) = 1.70 m

Incline angle (θ) = 20°

First, let's calculate the gravitational potential energy (PE) of the sphere at the top of the incline:

PE = m * g * h

where g is the acceleration due to gravity.

PE = 0.320 kg * 9.8 m/s² * 1.70 m

Next, let's determine the rotational kinetic energy (KE_rot) of the rolling sphere at the bottom of the incline:

KE_rot = (1/2) * I * ω²

where I is the moment of inertia and ω is the angular velocity.

For a solid sphere rolling without slipping, the moment of inertia is given by I = (2/5) * m * r², where r is the radius of the sphere.

r = d/2 = 0.078 m / 2 = 0.039 m

I = (2/5) * 0.320 kg * (0.039 m)²

Next, we need to find the linear velocity (v) of the sphere at the bottom of the incline. Since the sphere rolls without slipping, the linear velocity is related to the angular velocity by v = ω * r.

v = ω * r

To find ω, we can relate it to the linear velocity using the equation ω = v / r.

Finally, we can equate the gravitational potential energy at the top to the rotational kinetic energy at the bottom:

PE = KE_rot

m * g * h = (1/2) * I * (v/r)²

Substituting the expressions for I and v, we can solve for v:

m * g * h = (1/2) * (2/5) * m * r² * (v/r)²

Simplifying and canceling out the mass and r terms:

g * h = (1/5) * r * (v/r)²

g * h = (1/5) * v²

Now, we can solve for v:

v = √(5 * g * h)

Substituting the known values:

v = √(5 * 9.8 m/s² * 1.70 m)

v ≈ 6.69 m/s

Therefore, the linear velocity of the solid sphere at the bottom of the incline is approximately 6.69 m/s.

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Answer:

The heat doesn't come from any of those the heat comes from the Sun

Explanation:

But the thing that holds the heat from the Sun is the Earth's atmosphere.

When he gets hot the carbon dioxide holds in the heat but when the when oxygen it meets the heat in the air it makes it become cooler

Answer:

Very hot during the day and very cold at night.

Explanation:

Due to the thin atmosphere, they have very hot climate during the day time and very cold climate at night. This happens because they contain very low amounts of greenhouse gases. These gases retain the heat at night. The atmosphere also prevents excessive light and UV rays from entering. The thin  atmosphere leads to many asteroids and comets hitting the surface of the planet. On earth, these asteroids usually, burn up in the mesosphere layer of the atmosphere. These asteroid collisions cause massive fires. This in turn,  causes the temperature to increase during the day. During the night time, massive fires cannot burn due to the low temperature because of the lack of greenhouse gases.

The surface temperatures of Mercury and Mars are significantly impacted by their planets' thin atmospheres. Both planets have trouble effectively retaining heat because their atmospheres are so thin.

On Mercury, the thin atmosphere doesn't effectively block incoming solar radiation, leading to dramatic temperature swings. Due to the quick heat dissipation, daytime temperatures soar to sweltering heights while nighttime temperatures plunge to freezing lows. The thin atmosphere of Mars similarly prevents heat from being retained, resulting in frigid average temperatures. The insufficient greenhouse effect prohibits Mars from maintaining habitable conditions even though it receives less solar energy than Earth. Because of the huge temperature fluctuations on both worlds, atmospheres are crucial for controlling surface temperatures and sustaining life as we know it on Earth.

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The acceleration of a satellite orbiting Earth at an altitude of 500 km is approximately 8.985 m/s².  

The formula for gravitational acceleration is given by:
a = GM / r²
where:
a is the acceleration,
G is the gravitational constant (approximately 6.67430 × 10⁻¹¹ N(m/kg)²),
M is the mass of the Earth,
r is the distance between the center of the Earth and the satellite.

To calculate the acceleration of the satellite, we need to determine the distance from the center of the Earth to the satellite. This can be done by adding the radius of the Earth to the altitude of the satellite:

r = 6380 km + 500 km

= 6880 km

Now we can substitute the values into the formula:

a = (6.67430 × 10⁻¹¹ N(m/kg)² * M) / (6880 km)²

The mass of the Earth, M, is approximately 5.972 × 10²⁴ kg.

a = (6.67430 × 10⁻¹¹ N(m/kg)² * 5.972 × 10²⁴ kg) / (6880 km)²

To simplify the calculation, we need to convert the radius of the Earth and the altitude of the satellite to meters:

r = (6380 km + 500 km) * 1000

= 6880000 m

Now we can substitute the values into the formula and calculate the acceleration:

a = (6.67430 × 10⁻¹¹ N(m/kg)² * 5.972 × 10²⁴ kg) / (6880000 m)²

a = 8.985 m/s²

Therefore, the acceleration of a satellite orbiting Earth at an altitude of 500 km is approximately 8.985 m/s².

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The earliest known observations of the night sky date back to ancient civilizations such as the Babylonians, Egyptians, and Chinese, who recorded the positions of stars, planets, and other celestial bodies.

a = F / m

where F is the force (thrust) acting on the rocket and m is the mass of the rocket.

In this case, F = 20,000 N and m = 3,000 kg

So, a = 20,000 N / 3,000 kg = 6.67 m/s²

b) To calculate the final speed of the rocket after 5 minutes, you can use the formula:

v = a * t

where v is the final speed, a is the acceleration and t is the time.

In this case, a = 6.67 m/s² and t = 5 minutes = 300 seconds.

So, v = 6.67 m/s² * 300 seconds = 2,001 m/s

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First, we have to find the number of volts requires using Ohm's Law.

Where I = 0.30 A and R = 30 ohms. Let's replace these values and solve for V

Once we have the amount of voltage, we can divide it by 1.5V to get the number of batteries

Answer:

Also, water also makes its way into the atmosphere via a process called transpiration in which plants release water into the air from their leaves that was pulled up from the soil through roots. Collectively, the water evaporated from the land and from plants is called evapotranspiration.

Explanation:

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The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:

F = ΔP / ΔT

where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.

Now, let's apply the given values to the above equation.

Final momentum (p2) = mass × final velocity (v2)

p2 = 0.15 kg × (-50 m/s)

p2 = -7.5 kg.m/s

Initial momentum (p1) = mass × initial velocity (v1)

p1 = 0.15 kg × (40 m/s)

p1 = 6 kg.m/s

Change in momentum (ΔP) = p2 - p1

ΔP = -7.5 kg.m/s - 6 kg.m/s

ΔP = -13.5 kg.m/s

Time of collision (ΔT) = 8.0 × 10³ s

Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:

F = ΔP / ΔT

F = -13.5 kg.m/s ÷ 8.0 × 10³ s

F = -1.7 × 10⁻³ N

Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

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The magnitude of the linear impulse experienced by the passenger during this time is 421.2 kg·m/s and the average force experienced by the passenger is approximately 5.44 × 10^2 N.

(a) To calculate the magnitude of the linear impulse experienced by the passenger, we can use the equation:

Impulse = mass × change in velocity

Given:
Mass of the passenger (m) = 70.2 kg
Change in velocity (Δv) = 6.00 m/s - 0 m/s = 6.00 m/s

Substituting the values into the equation, we get:

Impulse = 70.2 kg × 6.00 m/s = 421.2 kg·m/s

Therefore, the magnitude of the linear impulse experienced by the passenger during this time is 421.2 kg·m/s.

(b) To find the average force experienced by the passenger, we can use the equation:

Average force = Impulse ÷ time

Given:
Impulse (I) = 421.2 kg·m/s
Time (t) = 0.774 s

Substituting the values into the equation, we get:

Average force = 421.2 kg·m/s ÷ 0.774 s = 544.0 N (rounded to three significant figures)

Therefore, the average force experienced by the passenger is approximately 5.44 × 10^2 N.

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The amount of distance that was covered by this person is equal to 4 kilometers.

The displacement from the starting point is equal to 2 kilometers to the right.

In Science, distance can be defined as the amount of ground that is covered (travelled) by a physical body or object over a particular period of time and speed, irrespective of its direction, starting point or ending point.

In this scenario, the total distance covered in a straight line by this person can be calculated by adding the distance he ran towards the right direction to the distance he ran towards the left direction as follows:

Distance = xf + x₀

Distance = 3 + 1

Distance = 4 kilometers.

On the other hand (conversely), the displacement of this person would be calculated by subtracting the distance he covered when running back from the distance he covered when running towards the right direction as follows:

Displacement = xf - x₀

Displacement = 3 - 1

Displacement = 2 kilometers to the right.

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Zero permeability denotes a totally reflecting barrier, whereas infinite permeability denotes the lack of a barrier.

Air is used to determine a core plug's permeability. The mean pressure is 2.152 psi, and only one measurement is taken. 46.6 md is the air permeability.

Both windings have an infinite resistance. The core has unlimited permeability and zero resistance.

In granular materials like sedimentary rocks, permeability is mostly determined by the size, shape, and packing arrangement of the grains as well as the size, shape, and size distribution of the pores in the substance.

A molecule can travel through the membrane quickly and easily when the  permeability is high.

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A particle with charge +e, baryon number 0, and strangeness +1 may content three quarks according to charge conservation along with other fundamental particles.

Particle physicists started to understand in the 1960s that quarks, not hadrons, are what make up hadrons, which are not truly elementary particles. (The word "quark" was first used by physicist Murray Gell-Mann in the James Joyce novel Finnegans Wake.) At first, it was thought there were just three sorts of quarks: up (u), down (d), and strange (s). However, this number quickly increased to six, which is interestingly the same as the number of leptons, to include charmed (c), bottom (b), and top (t).

Quarks may have charge of either +2/3e or -1/3e, baryon number 1/3 and strangeness  number either 0 or -1.

So, a particle with charge +e, baryon number 0, and strangeness +1 may content three quarks according to charge conservation along with other fundamental particles.

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Answer:

45

Explanation:

45

Increasing or decreasing the initial temperature of copper will have an impact on the final temperature based on the laws of thermodynamics. The specific effect will depend on the context and the surrounding conditions.

If we consider a scenario where a piece of copper is brought into contact with a cooler object or environment, increasing the initial temperature of the copper will result in a larger temperature difference between the copper and its surroundings. As a consequence, the copper will lose more heat energy to the surroundings, leading to a higher rate of heat transfer. This will cause the final temperature of the copper to decrease more rapidly, approaching the temperature of the surroundings.

Conversely, if the initial temperature of the copper is decreased, the temperature difference between the copper and its surroundings will be smaller. As a result, the rate of heat transfer from the copper to the surroundings will be lower. This will slow down the cooling process, and the final temperature of the copper will be higher than it would be with a higher initial temperature.

It's important to note that these observations assume that the copper is in thermal equilibrium with its surroundings and that no other factors significantly affect the heat transfer process, such as insulation or additional heat sources. The specific conditions and variables involved will ultimately determine the exact impact of changing the initial temperature of the copper on the final temperature.

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Answer: It could be many things. For example liquid, gaseous or solid objects.

Explanation: For conduction to take place between two objects, they must be touching each other. For conduction to occur between atoms within the same object, they must also be touching (or nearly touching).

The magnitude of a vector is a scalar representation of the length of the vector. To find the magnitude of a 2-dimensional vector (x, y), you can use the Pythagorean theorem:

magnitude = \(√(x^2 + y^2)\)

In this case, for the vector (3.00, 2.00), the magnitude is:    

magnitude = \(√(3^2 + 2^2) = √(9 + 4) = √13 = 3.6\)

The direction of a vector is a measure of the angle it makes with the positive x-axis. The direction is often expressed in radians, with zero radians being the positive x-axis, and positive angles rotating counter clock wise. To find the direction, you can use the arctangent function (atan2):

direction = atan2(y, x)

In this case, for the vector (3.00, 2.00), the direction is:

direction = atan2(2, 3) = 0.93 radians (or\(53.13°\))

So, the magnitude of the vector (3.00, 2.00) is 3.6 and its direction is 0.93 radians (or\(53.13°\)).

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Answer:

Revolving

Explanation:

Answer:

A.) 42.7 m/s

B.) 0.33 m/s^2

C.) 90 kg

Explanation:

A.) If Justin races his Chevy S-10 down highway 37 north for 2,560 meters in 60 seconds, what is his velocity? 

Velocity = displacement/time

Velocity = 2560/60

Velocity = 42.67 m/s

B.) The Chevy S-10 started rounding at 10 meters per hour. What is the acceleration at 30 seconds on the highway?

Acceleration = velocity/time

Acceleration = 10/30

Acceleration = 0.33 m/s^2

C.) The S-10 has a force of 30 N. What is the mass of the car?

Force = mass × acceleration

30 = mass × 0.33

Mass = 30/ 0.33

Mass = 90 kg

Answer:

B

Explanation:

The impulse experienced by an object is the force•time.

The jovian planets in our solar system include Jupiter, Saturn, Uranus, and Neptune. These gas giants are distinct from the terrestrial planets like Mercury, Venus, Earth, and Mars.

Jovian planets, namely Jupiter, Saturn, Uranus, and Neptune, are characterized by their composition and physical properties. They are primarily composed of gases and lack a solid surface. Jovian planets are much larger in size compared to the terrestrial planets.

They possess thick atmospheres with swirling cloud formations and dynamic weather systems. These gas giants also have a significant number of moons and are accompanied by planetary rings made up of dust and ice particles.

Jovian planets are located farther away from the Sun and have lower densities compared to the terrestrial planets. Their unique characteristics distinguish them from the rocky, inner planets like Mercury, Venus, Earth, and Mars.

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