Hunter has a rectangular prism with a volume of 1,155 cubic cm. He measures the length of the prism as 5 1/2 cm and the width of the prism as 10 1/2 cm.
The height of Hunter’s rectangular prism must be

Answer:

D divide both the numerator and denominator by cos(x)cos(y)

Step-by-step explanation:

just took the test

Answer:

About 495 people

Step-by-step explanation:

Divide 7428 by 15 years.

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(1-\alpha\), we have the following confidence interval of proportions.

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which

z is the zscore that has a pvalue of \(1 - \frac{\alpha}{2}\).

The margin of error is of:

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

37% of freshmen do not visit their counselors regularly.

This means that \(\pi = 0.37\)

98% confidence level

So \(\alpha = 0.02\), z is the value of Z that has a pvalue of \(1 - \frac{0.02}{2} = 0.99\), so \(Z = 2.327\).

You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.035. So

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

\(0.035 = 2.327\sqrt{\frac{0.37*0.63}{n}}\)

\(0.035\sqrt{n} = 2.327\sqrt{0.37*0.63}\)

\(\sqrt{n} = \frac{2.327\sqrt{0.37*0.63}}{0.035}\)

\((\sqrt{n})^2 = (\frac{2.327\sqrt{0.37*0.63}}{0.035})^2\)

\(n = 1030.4\)

Rounding up:

A sample size of 1031 is required.

The solution of the exponential equation 3^(3x-2) = 9^(4x-1) is x = 0.

We can solve this exponential equation for x by using logarithms. We can take the logarithm of both sides of the equation, using any base that we prefer. For instance, we can use the natural logarithm, ln:

ln(3^(3x - 2)) = ln(9^(4x - 1))

Now, we can use the properties of logarithms to simplify both sides of the equation. First, recall that ln(a^b) = b ln(a), for any positive value of a and any real value of b. Therefore, we have:

(3x - 2) ln(3) = (4x - 1) ln(9)

Next, we can use another property of logarithms, namely ln(a^b) = b ln(a) = ln(c) → a^b = c, to eliminate the natural logarithms from both sides of the equation. Specifically, we can rewrite ln(9) as ln(3^2), and then use the power rule for logarithms, ln(a^b) = b ln(a), to get:

(3x - 2) ln(3) = (4x - 1) ln(3^2) = 2 (4x - 1) ln(3)

Now, we can simplify the equation by multiplying out the coefficients of ln(3) on the left-hand side:

3x ln(3) - 2 ln(3) = 8x ln(3) - 2 ln(3)

Then, we can collect like terms:

3x ln(3) - 8x ln(3) = -2 ln(3) + 2 ln(3)

Finally, we can solve for x by factoring out ln(3) and dividing both sides by the resulting factor:

(3 ln(3) - 8 ln(3)) x = 0

-5 ln(3) x = 0

x = 0

Therefore, the solution of the exponential equation 3^(3x-2) = 9^(4x-1) is x = 0.

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The ladder will reach a Height of approximately 43.46 meters on the building.

To find out how high on the building the ladder will reach, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the ladder forms a right triangle with the ground and the building. The base of the ladder is 7 meters, the height of the building is what we need to find, and the length of the ladder is given as 44 meters.

Using the Pythagorean theorem, we can set up the equation:

(Height of the building)^2 + 7^2 = 44^2

Simplifying the equation, we have:

(Height of the building)^2 + 49 = 1936

Subtracting 49 from both sides, we get:

(Height of the building)^2 = 1887

To find the height of the building, we take the square root of both sides:

Height of the building = √1887

Calculating the square root of 1887, we find that the height of the building is approximately 43.46 meters.

Therefore, the ladder will reach a height of approximately 43.46 meters on the building.

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The graph of the y+2x=6 is given in the attachment.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The standard equation of a line is expressed as y = mx + b, m is the slope

and b is the y-intercept.

Given the equation y = 2x - 2

If x = -2

y = 2(-2) - 2

y = -4-2

y = -6

If x  = 4

y = 2(4) - 2

y = 8-2

y = 6

The point (-2, -6) and (4, 6 )must be on the line graph.

Hence, the graph of the y+2x=6 is given in the attachment.

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A) The variable is n, which represents the number of the figure in the pattern.

B) Here is a table for up to 8-figure patterns:

Figure Number of Cheerios

1                      1

2                      3

3                      6

4                     10

5                     15

6                     21

7                    28

8                    36

C) The equation to represent the nth term of the sequence is n(n+1)/2.

D) If the pattern continues, the figure number that will have 20 whole Cheerios in it is 12.

E) It is not reasonable to think this pattern would continue forever. The number of Cheerios in each figure is increasing by 2 each time. This means that the number of Cheerios in the figure will eventually exceed the number of Cheerios in a box.

F) Based on the information provided, the largest figure number we can have using a full box of Cheerios is 107. This is because there are 108 Cheerios in a box, and the number of Cheerios in each figure is increasing by 2 each time.

Here is a more detailed explanation of how to answer each question:

A) Identify and label the variable

The variable is n, which represents the number of the figure in the pattern. For example, the first figure is figure 1, the second figure is figure 2, and so on.

B) Make a table for up to 8-figure patterns

Here is a table for up to 8-figure patterns:

Figure Number of Cheerios

1                        1

2                        3

3                        6

4                        10

5                        15

6                        21

7                        28

8                        36

C) Write an equation to represent the nth term of the sequence

The equation to represent the nth term of the sequence is n(n+1)/2. This equation can be derived by looking at the table of values. For example, the number of Cheerios in the first figure is 1, which is equal to 1(1+1)/2. The number of Cheerios in the second figure is 3, which is equal to 2(2+1)/2. And so on.

D) If the pattern continues, what figure number will have 20 whole Cheerios in it?

If the pattern continues, the figure number that will have 20 whole Cheerios in it is 12. This can be found by solving the equation n(n+1)/2 = 20. The solution is n = 12.

E) Is it reasonable to think this pattern would continue forever? If not, explain.

It is not reasonable to think this pattern would continue forever. The number of Cheerios in each figure is increasing by 2 each time. This means that the number of Cheerios in the figure will eventually exceed the number of Cheerios in a box.

F) Based on the information provided, what is the largest figure number we can have using a full box of Cheerios?

Based on the information provided, the largest figure number we can have using a full box of Cheerios is 107. This is because there are 108 Cheerios in a box, and the number of Cheerios in each figure is increasing by 2 each time.

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Step-by-step explanation:

40 :100        yellow to purple,  divide both sides by 20

2:5

Answer:

the ratio of yellow to purple is 40:100 that is 2:5 in the simplest form.

Step-by-step explanation:

Hope it helps.

Answer:

\( \frac{10}{12} \)

Step-by-step explanation:

given,

tanX = 5/12

sinX/cosX + tanX

= tanX + tanX ( sinX/cosX = tanX)

= 5/12 + 5/12

=

\( \frac{10}{12} \)

Step-by-step explanation:

\( \tan(x) = \frac{5}{12} \\ \hookrightarrow \: \frac{p}{b} = \frac{5}{12} \)

As,

\( \hookrightarrow \: \frac{ \sin(x) }{ \cos(x) } = \tan(x) \)

Now,

\( \hookrightarrow \: \frac{ \sin(x) }{ \cos(x) } + \tan(x) \\ \hookrightarrow \: \tan(x) + \tan(x) \\ \hookrightarrow \: \frac{5}{12} + \frac{5}{12} \\ \hookrightarrow \frac{5 + 5}{12} \\ \hookrightarrow \frac{10}{12} \)

Answer:hi

Step-by-step explanation:

Answer:

4:10 hope this helps

Step-by-step explanation:

Answer:

Hi

Please mark brainliest ❣️

Thanks

Step-by-step explanation:

The answer is NO

Reason

x= 2 y= 1

Now input in the first inequality

y≤ -x + 4

1 ≤ -2 +4

1≤ 2 i.e 1 is less than two

Next inequality

y≤ x +1

1 ≤ 2 + 1

1≤ 3 i.e 1 is less than 3

But 1 is not equal to 3 and also not equal to 2

Hence our answer is NO

Answer:

\( {(x + 5)}^{2} - {x}^{2} \\ {x }^{2} + 10x + 25 - {x}^{2} \\ 10x + 25 \\ 5(2x + 5)\)

An expression that can be used to find the cost of an n-minute long distance call, where n is at least 5 minutes is (0.55 + (n - 5) x 0.07) dollars.

Given:

Long Distance Rates Time (minutes) Cost5 $0.556 $0.627 $0.698 $0.769 $0.8310 $0.90We need to find an expression that can be used to find the cost of an n-minute long-distance call, where n is at least 5 minutes.

The cost of making a long-distance call is given for 5 minutes, 6 minutes, 7 minutes, 8 minutes, 9 minutes, and 10 minutes.

We can observe from the above table that for every increase of 1 minute, the cost increases by $0.07.

We can conclude that the cost of n minutes long-distance call is given by: (0.55 + (n - 5) x 0.07) dollars when n is at least 5 minutes.

Therefore, the required expression is: (0.55 + (n - 5) x 0.07) dollars when n is at least 5 minutes. The above expression is based on the pattern in the table provided for long-distance call rates. We can use this expression for values of n greater than or equal to 5.

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Answer:

3381 is the answer

Answer:

3,381

Step-by-step explanation:

hope this helps

Answer:

585m

Step-by-step explanation:

using SOHCAHTOA to solve the question

the angle of elevation is 45° so therefore the answer is 585 m

The value of ∠A for given problem will be 38.68°.

If 2 sides of right angled triangle are given, trignometric ratios can be used to find the value of missing angles as:

\(sin\theta= opposite\;side\;/\;hypotenuse\)

\(cos\theta= adjacent\;side\;/\;hypotenuse\)

\(tan\theta= opposite\;side\;/\;adjacent\;side\)

where, perpendicular of triangle( side opposite to the angle θ) is called opposite side. and base( side adjacent to angle θ) is called adjacent side.

For given problem, given, (for ∠A)

opposite side(BC): 5

hypotenuse(AB): 8

\(sin\theta= 5\;/\;8\)

\(\theta=sin^{-1} \;(5\;/\;8)\)

\(\theta=38.68\textdegree\)

Therefore, angle A= 38.68°

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Answer:

The correct answer is:

P(nuts)=7/9

Step-by-step explanation:

The experimental probability that the next sundae sold will have nuts is

7/9

Experimental probability calculates the probability of some event from the results of experiments.

For an event E, we get the experimental probability of that event

\(P_e(E) = \dfrac{\text{Number of times E occurred}}{\text{Number of times experiments was done}}\)

where, \(P_e(E)\)  is denoting the experimental probability of occurrence of E.

We are given that At Frosty Freeze, 14 of the last 18 sundaes sold had nuts.

Therefore,

Probability that the next sundae has nuts is 14/18 = 7/9.

Thus, Probability that the next sundae does not have nuts = 2/9

P(nuts)=7/9

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Answer:

7. \(x \leq 5\)

8. \(x\geq 4\)

9. x < 5

10. x < -7

11.  x < 45

12. \(x\geq -10\)

13. x < -7

14. x < 45

15. \(x\leq 50\)

16. \(w\geq 16\)

18. q > 4

Step-by-step explanation:

0.5236 meters is the length of the given arc.

The formula for the length of an arc is given by:

Arc Length = (θ/360) * 2πr

Where:

In this case, the central angle is 60 degrees and the radius is 1/2 meters.

Plugging the values into the formula, we have:

Arc Length = (60/360) * 2π(1/2)

Arc Length = (1/6) * π

Arc Length = π/6

Therefore, the length of the arc that subtends an angle of 60 degrees at the center of a circle with a radius of 1/2 meters is π/6 meters or approximately 0.5236 meters.

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Answer:

b

Step-by-step explanation:

10x6=60

<3

Answer:

The answer is B.

Answer:

x = 4

Step-by-step explanation:

if a line is parallel to a side of a triangle and it intersects the other two sides then id divides those sides proportionally.

DE is such a line , then

\(\frac{BD}{AD}\) = \(\frac{BE}{EC}\)  ( substitute values )

\(\frac{x+2}{x}\) = \(\frac{3}{2}\) ( cross- multiply )

3x = 2(x + 2)

3x = 2x + 4 ( subtract 2x from both sides )

x = 4

a) The contents of register x31 after the following instruction is executed? addi x31, x5, 32 is 277968880 decimal.

b) The contents of register x28 after the following instruction is executed is 278427652 decimal.

c)The contents of register x29 after the following instruction is executed is 1056 decimal

d) The contents of register x29 after the following instruction is executed is 278427652 decimal

In computer architecture, registers are special storage locations within the CPU that hold data temporarily. These registers can hold values in binary, decimal, or hexadecimal formats. In this scenario, we have two registers x5 and x6, holding hexadecimal values. We will use these values to answer the given questions about register manipulation.

a) To determine the contents of register x31 after the instruction "addi x31, x5, 32", we need to add 32 to the value in x5 and store the result in x31. The value in x5 is 01a74cd0hex, which is equivalent to 277968848 in decimal. Adding 32 to this value, we get 277968880 decimal. Therefore, the contents of register x31 after the instruction is executed would be 277968880 decimal.

b) To determine the contents of register x28 after the instruction "add x28, x5, x6", we need to add the values in x5 and x6 and store the result in x28. The value in x5 is 01a74cd0hex, which is equivalent to 277968848 decimal. The value in x6 is 00467b44hex, which is equivalent to 458804 decimal. Adding these two values, we get 278427652 decimal. Therefore, the contents of register x28 after the instruction is executed would be 278427652 decimal.

c) To determine the contents of register x29 after the instruction "ld x29, 1056decimal (x30)", we need to load the value at memory location 1056decimal + the value in register x30 into register x29. The value in register x30 is not given in this scenario, so we cannot determine the contents of register x29.

d) To determine the contents of register x29 after the instruction "sd x28, 16 decimal (x29)", we need to store the value in register x28 at memory location 16 decimal + the value in register x29. The contents of register x28 is 278427652 decimal

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The probability of drawing a king from a standard deck of 52 cards is 1/13.

In a standard deck of 52 playing cards, there are four kings: the king of hearts, the king of diamonds, the king of clubs, and the king of spades.

To find the probability of drawing a king, we need to determine the ratio of favorable outcomes (drawing a king) to the total number of possible outcomes (drawing any card from the deck).

The total number of possible outcomes is 52 because there are 52 cards in the deck.

The favorable outcomes, in this case, are the four kings.

Therefore, the probability of drawing a king is given by:

Probability = (Number of favorable outcomes) / (Number of possible outcomes)

= 4 / 52

= 1 / 13

Thus, the probability of drawing a king from a standard deck of 52 cards is 1/13.

This means that out of every 13 cards drawn, on average, one of them will be a king.

It is important to note that the probability of drawing a king remains the same regardless of any previous cards that have been drawn or any other factors.

Each draw is independent, and the probability of drawing a king is constant.

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Answer:

0

Step-by-step explanation:

The * means multiplication where the ^ means exponents, so you multiply in this case.

-6 * -6 = 36

Two negatives equals a positive.

PEMDAS shows that multiplication and division occurs first so...

7 * -6 = -42

36 + -42 + 8

-8 + 8

= 0

You can search it up to see what PEMDAS is.

Answer:

The \(66\)th term is \(363\).

Step-by-step explanation:

To find the \(n\)th term, the formula is \(7n - 99\). Since we want to find the \(66\)th term, we can plug \(n\) for \(66\). So our expression is now \(7 \cdot 66 - 99 =\) \(66\)th term. Solving this we have

\(462 - 99 = 66\text{th term}\\363 = 66\text{th term}\\\). Therefore, the \(66\)th term is \(\boxed{363}\).

Answer:

a₆₆ = 363

Step-by-step explanation:

the nth term of an arithmetic sequence is

\(a_{n}\) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = - 92 and d = a₂ - a₁ = - 85 - (- 92) = - 85 + 92 = 7 , then

a₆₆ = - 92 + (65 × 7)

      = - 92 + 455

     = 363