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Answer:

Y=36

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

y/3 - 2 = 10

y/3=10+2

y/3=12

y=12×3

y=36

Answer:

27x-24

Step-by-step explanation:

Using distributive property, we can simplify 8(2x-3) to 16x-24. That becomes 16x-24+11x.

Then, we can add 16x and 11x to get 27x.

The answer will be 27x-24.

I hope you found this helpful, and if it was, please mark this answer as brainliest! Thank you! :)

Complete question is;

Tiothy evaluated the expression using x = 3 and y = –4. The expression is (xy^(-2))/(3x²y^(−4))

1. (1/3)x^(−1)(y²) 2. ((1/3)^(3−1))(−4²) 3. (1/3)(1/3)(−4)² 4. (1/3)(1/3)(−16) 5. −16/9 Analyze Timothy's steps. Is he correct? If not, why not?

A) Yes, he is correct.

B) No, he needed to add the exponents when he simplified the powers of the same base.

C) No, he needed to multiply 3 and –1 instead of creating a positive exponent in a fraction.

D) No, his value of (negative 4) squared should be positive because an even exponent indicates a positive value.

Answer:

D) No, his value of (negative 4) squared should be positive because an even exponent indicates a positive value.

Step-by-step explanation:

The expression is;

(xy^(-2))/(3x²y^(−4))

Simplifying this using law of indices gives;

⅓(x^(1 - 2)) × (y^(-2 -(-4))

This gives;

= (⅓x^(-1)) × y²

= ⅓ × (1/x) × y²

We are told that x = 3 and y = –4, thus;

= ⅓ × ⅓ × (-4)²

Square of a negative number is positive, thus (-4)² = 16

Thus;

⅓ × ⅓ × (-4)² = 16/9

Looking at the answer Timothy got, it's clear he made a mistake of not getting a positive number when he squared -4.

Thus,option D is the correct answer.

Answer:

D

Step-by-step explanation:

i got it correct

The median and quartiles fall in the middle age classes.

The median is the middle value in a set of data, meaning that half of the data falls below the median and half falls above it. The quartiles divide the data into four equal parts, with the first quartile (Q1) being the 25th percentile, the second quartile (Q2) being the median or 50th percentile, and the third quartile (Q3) being the 75th percentile.

In terms of age classes, the median and quartiles would fall in the middle age classes. For example, if the age classes were 0-10, 11-20, 21-30, 31-40, 41-50, 51-60, 61-70, 71-80, and 81-90, the median and quartiles would fall in the 21-30, 31-40, and 41-50 age classes.

It is important to note that the specific age classes that the median and quartiles fall in will depend on the distribution of the data. However, they will always fall in the middle age classes, as they represent the middle values of the data set.

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Answer:

6 hours

Step-by-step explanation:

lmk if you want an explanation

Answer:

1, 3, 5, 7, 10 those are the answers to Y

Answer:

7: 1

21: 3

35: 5

49: 7

77: 11

well, let's notice the denominators, hmmm so we can use as the LCD say the expression of "rpq", so, let's multiply both sides by the LCD of "rpq" to do away with the denominators.

\(\cfrac{2}{r}+\cfrac{1}{p}=\cfrac{1}{q}\implies \stackrel{\textit{multiplying both sides by } ~~ \stackrel{LCD}{rpq}}{rpq\left( \cfrac{2}{r}+\cfrac{1}{p} \right)=rpq\left( \cfrac{1}{q} \right)}\implies 2pq+1rq=1rp \\\\\\ 2pq+rq=rp\implies rq=rp-2pq\implies rq=\stackrel{\textit{common factoring}}{p(r-2q)}\implies \cfrac{rq}{r-2q}=p\)

For this problem, I will be using the equal sign instead of the congruent sign for segments.

1) AC = AB, CD = DE, m∠ABC = 70°, m∠ECB = 35° (given)

2) ∠ACB is congruent to ∠ABC (base angles theorem)

3) m∠ACB = 70° (congruent angles have equal measure)

4) m∠DCE = 35° (angle subtraction postulate)

5) ∠DCE and ∠DEC are congruent (base angles theorem)

6) m∠DEC = 35° (congruent angles have equal measure)

7) ∠DEC is congruent to ∠ECB (angles with the same measure are congruent)

8) DE is parallel to BC (if two lines are cut by a transversal and the alternate interior angles are congruent, then the lines are parallel)

An equation that represents a function that relates the value of Ethan’s car in dollars, g(t), and the time in years since he bought the car.

\(g(t) = P * e^{(-rt)\)

Assuming that Ethan's car depreciates in value over time, a commonly used function to model such depreciation is an exponential decay function of the form:

\(g(t) = P * e^{(-rt)\)

where:

\(g(t) = P * e^{(-rt)\)

where P, r, and t are specific values based on the purchase price and depreciation rate of Ethan's car, as well as the time that has passed since he bought it.

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Answer:

No.

Step-by-step explanation:

It is given that Darius is putting tiles on the roof of his house.

Darius had completed = \($\frac{4}{5}$\) th of the work

He takes time = \($3 \frac{1}{3}$\) hours to complete \($\frac{4}{5}$\) th of the work

The remaining work = \($1 -\frac{4}{5}$\)

                                 \($=\frac{5-4}{5}$\)

                                 \($=\frac{1}{5}$\)

∴  Darius completes \($\frac{4}{5}$\) th of the work in = \($\frac{10}{3}$\) hours

                           So, \($\frac{1}{5}$\) th of the work in = \($\frac{10}{3} \times \frac{5}{4} \times \frac{1}{5}$\) hours

                                                                 \($=\frac{10}{12}$\) hours

Therefore total time taken to complete the work \($=\frac{10}{3}+\frac{10}{12}$\) hours

                                                                                  \($=\frac{40+10}{12}$\) hours

                                                                                  \($=\frac{50}{12}$\) hours

                                                                                  \($=4\frac{2}{12}$\) hours

                                                                                  \($=4\frac{1}{6}$\) hours

Thus, Darius continues to work at the same rate will not be able to complete the work in 4 hours.  

Answer: Non proportional

Step-by-step explanation:

To know if the values given are proportional or not, we will use the formula:

y = kx

where

y = number of organisms

x = number of minutes

k = constant of proportionality

After 5 minutes, a bacteria colony has 1.3 million organisms. Using the formula, y = kx

1,300,000 = 5k

k = 1,300,000 / 5

k = 260,000

After 12 minutes, the same colony has 41.5 million organisms. Using y= kx

41,500,000 = 12x

x = 41500000 / 12

x = 3458333.8

After 15 minutes, the colony has grown to 101.3 million organisms.

y = kx

101,300,000 = 15k

k = 101,300,000 / 15

k = 6753333.8

It is a non-proportional relationship as the constant of proportionality is different for each.

To calculate the integral over the given region using polar coordinates, we need to express the function and the region boundaries in terms of polar coordinates.

For the function f(x, y) = y, we can rewrite it in polar coordinates as f(r, θ) = r*sin(θ), where r represents the radius and θ represents the angle.

Now, let's consider the region boundaries:

1. The condition x^2 + y^2 ≤ 1 represents the unit circle centered at the origin (0, 0) in Cartesian coordinates. In polar coordinates, this condition becomes r ≤ 1.

2. The condition (x - 1)^2 + y^2 ≤ 1 represents a circle centered at (1, 0) with radius 1 in Cartesian coordinates. In polar coordinates, we can shift the center by 1 unit to the right, so the condition becomes (r*cos(θ) - 1)^2 + (r*sin(θ))^2 ≤ 1.

To find the limits of integration, we need to determine the values of θ and r that define the region of interest.

1. For the radius r, it ranges from 0 to 1, as it represents the region within the unit circle.

2. For the angle θ, we need to find the intersection points between the two circles defined by the conditions. Setting the equations equal to each other, we have:

  r^2*sin^2(θ) = 1 - (r*cos(θ) - 1)^2 - (r*sin(θ))^2

  r^2*sin^2(θ) = 1 - r^2*cos^2(θ) + 2*r*cos(θ) - 1 - r^2*sin^2(θ)

  2*r^2*sin^2(θ) = - r^2*cos^2(θ) + 2*r*cos(θ)

  2*r*sin^2(θ) = - r*cos^2(θ) + 2*cos(θ)

  2*r*sin^2(θ) + r*cos^2(θ) - 2*cos(θ) = 0

  Solving this equation is a bit complex, but we can approximate the values of θ that satisfy the equation using numerical methods or a graphing calculator. Let's assume the approximate values are θ1 and θ2.

Therefore, the integral over the given region can be expressed as:

∫∫[R] f(r, θ) * r dr dθ

Where R represents the region defined by the To calculate the integral over the given region using polar coordinates, we need to express the function and the region boundaries in terms of polar coordinates.

For the function f(x, y) = y, we can rewrite it in polar coordinates as f(r, θ) = r*sin(θ), where r represents the radius and θ represents the angle.

Now, let's consider the region boundaries:

1. The condition x^2 + y^2 ≤ 1 represents the unit circle centered at the origin (0, 0) in Cartesian coordinates. In polar coordinates, this condition becomes r ≤ 1.

2. The condition (x - 1)^2 + y^2 ≤ 1 represents a circle centered at (1, 0) with radius 1 in Cartesian coordinates. In polar coordinates, we can shift the center by 1 unit to the right, so the condition becomes (r*cos(θ) - 1)^2 + (r*sin(θ))^2 ≤ 1.

To find the limits of integration, we need to determine the values of θ and r that define the region of interest.

1. For the radius r, it ranges from 0 to 1, as it represents the region within the unit circle.

2. For the angle θ, we need to find the intersection points between the two circles defined by the conditions. Setting the equations equal to each other, we have:

  r^2*sin^2(θ) = 1 - (r*cos(θ) - 1)^2 - (r*sin(θ))^2

  r^2*sin^2(θ) = 1 - r^2*cos^2(θ) + 2*r*cos(θ) - 1 - r^2*sin^2(θ)

  2*r^2*sin^2(θ) = - r^2*cos^2(θ) + 2*r*cos(θ)

  2*r*sin^2(θ) = - r*cos^2(θ) + 2*cos(θ)

  2*r*sin^2(θ) + r*cos^2(θ) - 2*cos(θ) = 0

  Solving this equation is a bit complex, but we can approximate the values of θ that satisfy the equation using numerical methods or a graphing calculator. Let's assume the approximate values are θ1 and θ2.

Therefore, the integral over the given region can be expressed as:

∫∫[R] f(r, θ) * r dr dθ

Where R represents the region defined by the limits of integration: 0 ≤ r ≤ 1 and θ1 ≤ θ ≤ θ2.

Please note that finding the exact values of θ1 and θ2 requires solving the equation more precisely, and it may not have simple closed-form solutions. of integration: 0 ≤ r ≤ 1 and θ1 ≤ θ ≤ θ2.

Please note that finding the exact values of θ1 and θ2 requires solving the equation more precisely, and it may not have simple closed-form solutions.

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The Translation to  algebraic expression is shown below.

A mathematical operation such as subtraction, addition, multiplication, or division is used to combine terms into an expression. In a mathematical expression, the following terms are used:

Given:

To create a variable expression for a circumstance in the actual world:

For example, the sum of a and b can be written as

= a+ b

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Answer:14/5

Step-by-step explanation:28/10

Divide through by 2

Answer:

28

Step-by-step explanation:

Given the base and height, we can split the triangle into 2.

So now the height for our right triangle with still be 25 but the base will become half of what it used to be which is 12.

Using the Pythagorean Theorem:

A^2+B^2=H^2                

a = side of right triangle

b = side of right triangle

c = hypotenuse

Plugin the values

25^2+12^2=H^2

625+144=H^2

769=H^2

27.73=H

Rounded to 28

Hope this helps :)

Answer:

x²

Step-by-step explanation:

I'm just guessing divide it and multiply it by 2 and 3

A solution in mathematics is any value of a variable that makes the specified equation true.

On, the other hand, a solution set is the set of all variables that makes the equation true.

For example;

the solution set of 2y + 6 = 14 is 4 because 2(4) + 6 = 14.

In summary, 4 is the solution set in the above example because it makes the equation true.

Also, when an equation has two variables, the set of ordered pairs that are the solution to the equation are called the solution set to the equation.

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The difference between the volumes is 79.55 cubic inches.

The volume of a sphere of radius R is:

\(V = (4/3)*3.14*R^3\)

Here we have two spheres, the larger has a diameter of 6 inches, so its radius is:

R = 6in/2 = 3in

The smaller ball has a radius of 2 in.

Then the difference between the volumes is:

\(V = (4/3)*3.14*( (3in)^3 - (2in)^3) = 79.55 in^3\)

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Answer:

I think the answers are 1 to 1 ,9 to 8 , 10 to7

Answer:

(0,-3)

Step-by-step explanation:

You can plug in x and y into the equations to see if it works.

(-1,5)

2(-1)-(-5)=-2+5=3 Yes

(-1)+2(-5)=-1-10=-11 No

So (-1,5) Does NOT work.

(0,3)

2(0)-(-3)=0+3=3 Yes

(0)+2(-3)=0-6=-6 Yes

So (0,-3) DOES work.

Answer:

(x - 1)² + y² = 81/4

Explanation:

First, we need to calculate the distance from (1, 0) to (1, 9/2). This distance is equal to

9/2 - 0 = 9/2

Because they both have the same x-coordinate. It means that the radius of the circle is 9/2.

Then, an equation of a circle with radius r and center (h, k) is

(x - h)² + (y - k)² = r²

Replacing (h, k) = (1, 0) and r = 9/2, we get

(x - 1)² + (y - 0)² = (9/2)²

(x - 1)² + y² = 81/4

Therefore, the answer is

(x - 1)² + y² = 81/4

Hello!

45% of x = 7.2

45x/100 = 7.2

45x = 7.2 * 100

45x = 720

x = 720/45

x = 16

the number = 16

Answer:

slope = 1/2

Step-by-step explanation:

-8y = -4x

y = 1/2x

y = mx

m = 1/2

slope = 1/2

Answer:

D

Step-by-step explanation:

We would expect the central 95% of autos to be found in the interval from 20 to 40 mpg.

The 68-95-99.7 rule, also known as the empirical rule, states that for a normal distribution, approximately 68% of the observations fall within one standard deviation of the mean, approximately 95% of the observations fall within two standard deviations of the mean, and approximately 99.7% of the observations fall within three standard deviations of the mean.

Assuming that the distribution of autos' miles per gallon (mpg) is approximately normal, we can use the empirical rule to estimate the interval in which we would expect the central 95% of autos to be found.

Then, according to the empirical rule, approximately 95% of autos should be found within 2 standard deviations of the mean. We can write:

μ - 2σ ≤ x ≤ μ + 2σ

where x represents the mpg of an individual auto.

For example, if we take a random sample of 100 autos and find that the mean mpg is 30 and the standard deviation is 5, then we can estimate the interval in which we would expect the central 95% of autos to be found as:

30 - 2(5) ≤ x ≤ 30 + 2(5)

20 ≤ x ≤ 40

Therefore, we would expect the central 95% of autos to be found in the interval from 20 to 40 mpg.

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No Inequality has a specific solution

What is Linear Inequality?

A linear inequality is a mathematical inequality that incorporates a linear function. A linear inequality contains one of the inequality symbols. It displays data that is not equal in graph form.

Solution:

Please refer to the graph

We can clearly see that there are no corner points within the viable region of the graph of the Linear Inequality therefore, there exists no specific solution.

And also, the inequality 3 and inequality 4 are nothing but are the same as inequality 1 and inequality 2

Any inequality does not have any specific solution

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The probability for the dots 10 and fewer shots to get a successful shot is 0.85.

Probability refers to a possibility that deals with the occurrence of random events. The probability of all the events occurring need to be 1.

The formula of probability is defined as the ratio of a number of favorable outcomes to the total number of outcomes.

P(E) = Number of favorable outcomes / total number of outcomes

The probability that Gerald makes a three-point shot in basketball is 20%.

He simulated 40 trials of three-point shots where each shot had a 0.2 probability of being successful, and in each trial, he counted how many shots it took to get the first successful shot.

All the dots that are greater than 10 = 6 dots.

we need to find for the dots 10 and fewer there are 40 dots in total

So,

40-6= 34

Then,

P(E) = \(\frac{34}{40}\)

P(E) = 0.85

Hence, The probability for the dots 10 and fewer shots to get a successful shot is 0.85.

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According to the question A line has a slope of -3 and includes the points (9, 4) and (8, t) then the value of t is 7

Typically, a line's slope provides information about the steepness and direction of the line. Finding the difference between the coordinates of the locations will allow you to quickly compute the slope of a straight line connecting two points, (x1,y1) and (x2,y2). The letter "m" is typically used to signify slope.

tan θ = Δy/Δx

the solution is -

Considering a line with a slope of -3 and also the point (9, 4), we could use the point-slope form of either a line to find the equation of a line:

y - 4 = -3(x - 9)

y = -3x + 27 + 4

y = -3x + 31

We are given some other point on the line (8, t) we can try substituting it in the equation above:

t = -3(8) + 31

t = -24 + 31

t = 7

And hence, the value of the t is 7.

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I hope this helps you .

The next three letters in the sequence J F M A M J J A are S, O, N.

To find the next three letters in the sequence J F M A M J J A, we need to identify the pattern or rule that governs the sequence. In this case, the sequence follows the pattern of the first letter of each month in the year.

The sequence starts with 'J' for January, followed by 'F' for February, 'M' for March, 'A' for April, 'M' for May, 'J' for June, 'J' for July, and 'A' for August. The pattern repeats itself every 12 months.

Therefore, the next three letters in the sequence would be 'S' for September, 'O' for October, and 'N' for November.

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The next three letters in the sequence "J F M A M J J A" are "S O N", indicating the months of September, October, and November.

The given sequence "J F M A M J J A" represents the first letters of the months in a year, starting from January (J) and ending with August (A). To find the next three letters in the sequence, we need to continue the pattern by considering the remaining months.

The next month after August is September, so the next letter in the sequence is "S". After September comes October, represented by the letter "O". Finally, the month following October is November, which can be represented by the letter "N".

Therefore, the next three letters in the sequence "J F M A M J J A" are "S O N", indicating the months of September, October, and November.

It is important to note that the given sequence follows the pattern of the months in the Gregorian calendar. However, different cultures and calendars may have different sequences or names for the months.

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