HURRY PLEASE!!

{9, 7, 11, 7, 4, 10, 6, 2, 0, 7}

Minum: ?
Lower Quartile: ?
Median: ?
Upper Quartile: ?
Maximum: ?

Step-by-step explanation:

15 / (1/3)  is equal to  15 x 3/1  = 15 x 3 = 45

The correct answer is 48 pieces.

To determine the number of pieces that can be cut from the steel sheet, we need to divide the dimensions of the steel sheet by the dimensions of each piece to see how many can fit.

Calculate the number of pieces along the length:

The length of the steel sheet is given as 2400 mm, and each piece has a length of 300 mm. By dividing the total length by the length of each piece, we get 2400 mm ÷ 300 mm = 8. This means we can cut 8 pieces along the length of the steel sheet.

Calculate the number of pieces along the width:

The width of the steel sheet is given as 1200 mm, and each piece has a width of 200 mm. By dividing the total width by the width of each piece, we get 1200 mm ÷ 200 mm = 6. This means we can cut 6 pieces along the width of the steel sheet.

Calculate the total number of pieces:

To find the total number of pieces, we multiply the number of pieces along the length by the number of pieces along the width: 8 pieces × 6 pieces = 48 pieces.

Therefore, the correct answer is 48 pieces.

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The following are crucial factors in hypothesis testing:

In statistics, the process of hypothesis testing involves putting an analyst's presumption about a population parameter to the test.

Thus, before conducting the hypothesis testing, a null hypothesis as well as an alternative hypothesis are established.

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Answer:

The first answer choice is correct

Step-by-step explanation:

Answer:

volume =183.26 cm³

Step-by-step explanation:

volume of a cone = 1/3πrl

l is the slant height

using; l²=h²+r²

r²= l²-h²

r²= 25²-24²= 625-576 =49

r=√49=7cm

volume = 1/3πrl = 1/3 (π×7×25)= 1/3 ×549.78

=183.26 cm³

\(P(x < x_0) = ∫_0^x_0 f(x) dx\) ,\(P(x < 2) = ∫_0^2 (1/3) 4 e^-x/3 dx = -4e^-2/3 + 4\) ,  \(P(x > 3) = 1 - P(x < 3) = 1 - ∫_0^3 (1/3) 4 e^-x/3 dx = e^-1\) , \(P(x < 5) = ∫_0^5 (1/3) 4 e^-x/3 dx = -4e^-5/3 + 4\) , \(P(2 < x < 5) = P(x < 5) - P(x < 2) = (-4e^-5/3 + 4) - (-4e^-2/3 + 4) = 4e^-2/3 - 4e^-5/3\)

are the required solutions probability density function.

a. The formula for P(x < x_0) can be obtained by integrating the probability density function f(x) from 0 to x_0:  

\(P(x < x_0) = ∫_0^x_0 f(x) dx\)

b. To find P(x < 2), we can substitute x_0 = 2 into the formula above and evaluate the integral:

\(P(x < 2) = ∫_0^2 (1/3) 4 e^-x/3 dx = -4e^-2/3 + 4\)

c. To find P(x > 3), we can use the complementary probability:

\(P(x > 3) = 1 - P(x < 3) = 1 - ∫_0^3 (1/3) 4 e^-x/3 dx = e^-1\)

d. To find P(x < 5), we can again use the formula for P(x < x_0) and substitute x_0 = 5:

\(P(x < 5) = ∫_0^5 (1/3) 4 e^-x/3 dx = -4e^-5/3 + 4\)

e. To find P(2 < x < 5), we can use the cumulative distribution function:

\(P(2 < x < 5) = P(x < 5) - P(x < 2) = (-4e^-5/3 + 4) - (-4e^-2/3 + 4) = 4e^-2/3 - 4e^-5/3\)

In general, the exponential distribution is commonly used to model the time until an event occurs, such as the time between radioactive decays or the time until a customer arrives at a service station. The parameter 1/λ, where λ is the rate parameter, represents the average time until the event occurs. The exponential distribution has a memoryless property, which means that the probability of the event occurring in the next unit of time is independent of the time elapsed so far. This property makes the exponential distribution useful in many applications, such as queuing theory and reliability analysis.

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Answer:

What is the question?

Step-by-step explanation:

Answer: 240 mins

Step-by-step explanation:

Answer:

n=75/11

Step-by-step explanation:

good luck

Answer:

adjacent = 8.66 2dp

hypotenuse = 10

Step-by-step explanation:

to find the adjacent side

tan(60) = x/5

tan(60) × 5 = x

adjacent side length = 8.66 2dp

to find the hypotenuse

8.66^2 + 5 ^2 = sqrt(ans)

hypotenuse = 10

Answer:

Second choice: i

Square root of -1 is an imaginary number, represented as i.

Please mark as BRAINLIEST! Thanks!

Answer:

523.3 cm^3

Step-by-step explanation:

You have a formula for the volume of a sphere:  \(V=\frac{4}{3}\pi r^3\) but to use it, you need the radius, r .

The panel on the left shows  c = 31.4 cm (I am assuming  c  is the circumference, like the distance around the "equator" of the sphere).

What's the relationship of circumference of a circle (equator) to the radius?

\(c=2\pi r\)

So put 31.4 in for  c  in that last formula.

\(31.4 =2\pi r\)

If you use the approximate value of pi  \(\pi \approx 3.14\) that becomes

\(31.4 = 2(3.14)r\\\frac{31.4}{6.28} = r\\\\5=r\)

Aha!  The radius r  is 5 cm.  Now go back to the formula for volume:

\(V=\frac{4}{3} (3.14)(5^3)\\V=\frac{4}{3}(3.14)(125)\\V \approx 523.3 \text{ cm^3}\)

the point (1, 7) is the only solution to the inequality y > |x| + 5.

To determine which of the given points is a solution of the inequality y > |x| + 5, we need to substitute the x and y coordinates of each point into the inequality and check if the inequality holds true.

a. (7, 1)

Substituting x = 7 and y = 1 into the inequality:

1 > |7| + 5

1 > 7 + 5

1 > 12

This inequality is not true, so (7, 1) is not a solution.

b. (0, 5)

Substituting x = 0 and y = 5 into the inequality:

5 > |0| + 5

5 > 0 + 5

5 > 5

This inequality is not true, so (0, 5) is not a solution.

c. (1, 7)

Substituting x = 1 and y = 7 into the inequality:

7 > |1| + 5

7 > 1 + 5

7 > 6

This inequality is true, so (1, 7) is a solution.

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The second pump working by itself can fill the pool in 3.5 hours.

One pump can fill a pool in 14 hours. When working together, the pumps can fill the pool in 10 hours. We are required to determine the speed of the second pump working by itself.

Let's consider the speed of the first pump working by itself to be S1. Let's consider the speed of the second pump working by itself to be S2 We can now use the formula, Work = Speed × Time.

We know that both pumps working together can fill the pool in 10 hours. Therefore, using this formula:

1 = (S1 + S2) × 10/Pool Similarly

, we know that the first pump can fill the pool in 14 hours.

Therefore

1 = S1 × 14/Pool

We can use the above two equations to solve for S2

.S1 = 1/14

Pool (equation 1)

\(1 = (S1 + S2) × 10/Pool (equation 2)\)

Substituting the value of S1 from equation 1 into equation 2, we get:

\(1 = ((1/14Pool) + S2) × 10/\)

Pool Simplifying the above equation:

1 = (10/14 + 10S2)/Pool Multiplying both sides by Pool:

\(Pool \\= 10/4 + 10S2\\Pool = 2.5 + 10S2\)

Multiplying both sides by 4:4

\(Pool = 10 + 40S24Pool\\ = 10Pool + 40S24Pool - 10Pool \\= 40S214Pool = 40S2S2 \\= 14/4S2 \\= 3.5\)

The second pump working by itself can fill the pool in 3.5 hours.

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  Among the given options (A, B, C, D), the correct population regression model when k = 2 is option D: Y = β0 + β1X1 + β2X2 + e.

In a population regression model, we are interested in modeling the relationship between a dependent variable (Y) and one or more independent variables (X1, X2, etc.). The model equation consists of the regression coefficients (β0, β1, β2, etc.) that represent the effect of each independent variable on the dependent variable, and the error term (e) that captures the unexplained variation in the data.
Among the given options, only option D includes all the necessary components of a population regression model with two independent variables (k = 2). It includes the dependent variable Y, the regression coefficients β0, β1, and β2 for the independent variables X1 and X2, respectively, and the error term e.
Options A, B, and C are incorrect because they either omit the error term or have an incomplete equation. The error term is crucial in accounting for the unobserved factors and random variation in the relationship between the variables.
Therefore, the correct population regression model when k = 2 is option D: Y = β0 + β1X1 + β2X2 + e.

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The amount Erica owed for 6 years if $5300 is loaned to her at the rate of 8% is  $8,551.56.

The amount Erica owes for 6 years if 5300 dollars is loaned to her at the rate of 8% compounded monthly can be computed as follow:

Therefore, it is compounded 12 times.

\(A = p(1 +\frac{r}{n} )^{nt}\)

where

Therefore,

p = 5300 dollars

t = 6 years

n = 12

r = 8%

Therefore,

\(A = p(1 +\frac{r}{n} )^{nt}\)

\(A = 5300(1+ \frac{0.08}{12} )^{(12)(6)}\)

A = 5300(1 + 0.0067)⁷²

Therefore,

A = $8,551.56

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Answer:

1.

\(C.\\sin(N)=\frac{\sqrt{3} }{2}\)

2.

\(x=82.1\)

3.

x = 18°

Step-by-step explanation:

1. The sine ratio is sin(θ) = opposite/hypotenuse, where θ is the reference angle.  When N is the reference angle, we see that side OP with a measure of 5√3 units is the opposite side and side NP with a measure of 10 units is the hypotenuse.

Thus, we can find plug everything into the sine ratio and simplify:

\(sin(N)=\frac{5\sqrt{3} }{10} \\\\sin(N)=\frac{\sqrt{3} }{2}\)

2. We can use the tangent ratio to solve for x, which is tan (θ) = opposite/adjacent.  If we allow the 75° to be our reference angle, we see that the side measuring x units is the opposite side and the side measuring 22 units is the adjacent side.  Thus, we can plug everything into the ratio and solve for x or the measure of the opposite side:

\(tan(75)=\frac{x}{22}\\ \\22*tan(75)=x\\\\82.10511777=x\\\\82.1=x\)

3. Since we're now solving for an angle, we must using inverse trigonometry.  We can use the inverse of the tangent ratio, whose equation is tan^-1 (opposite/adjacent) = θ.  We see that when the x° is the reference angle, the side measuring 11 units is the opposite and the side measuring 33 units is the adjacent side.  Now we can do the inverse trig to find the measure of x:

\(tan^-^1(\frac{11}{33})=x\\ 18.43494882=x\\18=x\)

Answer:

the ans is 6 it was a easy one

If Sandra has a bunch of grapes that weighs 48.64 g and a bag of mangoes that weighs 937.2 g. The amount that the fruit weight in total is: $985.84.

Using this formula to determine the fruit weight in total

Total fruit weight = Weight of bunch of grapes + Weight of bag of mangoes

Where:

Weight of bunch of grapes = 48.64g

Weight of bag of mangoes = 937.2g

Let plug in the formula

Total fruit weight = 48.64g +  937.2g

Total fruit weight = 985.84g

Therefore $985.84 is the total weight of the fruits.

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The complete question is:

Sandra has a bunch of grapes that weighs 48.64 g and a bag of mangoes that weighs 937.2 g. How much does the fruit weigh in total?

Answer:

62

Step-by-step explanation:

im pretty sure this is right. sry if its not.

Answer:

62

Step-by-step explanation:

1) 10^3 = 1000

2) 1000 x .062=62

Answer:

48

Step-by-step explanation:

I'm assuming it's just multiplication with given info

m3n = (8)3(2) = 24(2) = 48

Answer:

One solution

Step-by-step explanation:

Answer:

The correct answer is A.) one

Step-by-step explanation:

I just did the test on edge 2021 and got it right!

Answer:

36 beans

Step-by-step explanation:

Trust Me, I know the answer its quite easy you do 8×4=32 8×1/2=4 and add them both together which is 36

Answer: I confirm it is 36 beans

Step-by-step explanation:

Answer:

0.3, 1/3, 2/5, 1/2, 0.6

Hope this helps!!

Answer:

x = -2

Step-by-step explanation:

Step 1: Distribute

-4(x + 7) + 2(2 + x) = -20 ---->  -4x-28 + 4+2x=-20

Step 2: Combine Like Terms

-4x-28+4+2x=-20 ----> -2x-24=-20 ----> -2x=4

Step 3: Divide both sides by -2, solving for x.

-2x=4 ----> -2/-2x = 4/-2 ----> x = -2

Answer:

80%

Step-by-step explanation:

150/100*20=$30

150-30=120

120/150=0.8=80%

The correct value of a or initial amount in exponential growth \(Q = ae^b^x\) is 789.

Quantity rises over time through a process called exponential growth and it happens when the derivative, or instantaneous rate of change, of a quantity with respect to time is proportionate to the original quantity.

Given that, hypothetical energy consumption normalized to the year 1990 we have to estimate a and h

\(Q = ae^b^x\)

\(ln Q= ln a+bx\)

For the year 1990:
\(x = 0\)     \(lnQ =0\)

For the year 1910:

\(x= 10\)    \(lnQ= 0.698\)

For the year 1920:

\(x=20\)    \(lnQ= 1.4012\)

For the year 1930:

\(x=30\)     \(lnQ=2.1\)

For the year 1940:

\(x=40\)     \(lnQ=2.8\)

For the year 1950:

\(x=50\)     \(lnQ=3.5\)

For the year 1960:

\(x=60\)     \(lnQ=4.2\)

For the year 1970:

\(x=70\)     \(lnQ=4.9\)

For the year 1980:

\(x=80\)     \(lnQ=5.6\)

For the year 1990:

\(x=90\)     \(lnQ=6.3\)

For the year 2000:

\(x= 100\)     \(lnQ= 7\)

Here, estimate the parameters of the model graphically, the slope of line is approximated as follows:

a = \(\frac{1096.63-544.57}{7-6.3}\)

a = \(\frac{552.06}{0.7}\)

a = 788.657

a ≈ 789

Hence, a or initial amount in exponential growth \(Q = ae^b^x\) is 789.

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Answer: I think it's 30 degrees. Sorry if I'm wrong.

Step-by-step explanation:

The margin of error if we want a 90% confidence interval for the true population mean age is calculated to be 1.62 years, therefore option (a) is correct.

We can use the formula for the margin of error:

Margin of error = z × (σ / √(n))

where z is the z-score for the desired level of confidence, σ is the population standard deviation, and n is the sample size.

For a 90% confidence interval, the z-score is 1.645. Substituting the given values, we get:

Margin of error = 1.645 × (9.84 / √(100)) = 1.62

Therefore, the margin of error is 1.62 years, which is option (a).

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"If x=1 and increases by h the volume of box changes by 4(1 + h)3 - 61(1 + h)3 + 240(1 + h) - 180

The formula to calculate the volume of a box is V = a3 + 3a2b + 3ab2 + b3.
Substituting in x = 1 and h = the increase, we get:
V(1 + h) - V(1) = 4(1 + h)3 - 61(1 + h)3 + 240(1 + h) - 180

Therefore, the volume of the box changes by 4(1 + h)3 - 61(1 + h)3 + 240(1 + h) - 180 when x=1 and increases by h.

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