Hydroxyapatite, Ca5(PO4)3(OH), is the main mineral component of dental enamel, dentin, and bone, and thus it has many medical uses. Coating it on metallic implants (such as titanium alloys and stainless steels) helps the body accept the implant. In the form of powder and beads, it is used to fill bone voids, which encourages natural bone to grow into the void. Hydroxyapatite is prepared by adding aqueous phosphoric acid to a dilute slurry of calcium hydroxide.
(a) Write a balanced equation for this preparation. Be sure to include the state of each reactant and product in the equation. Hint: Liquid water is one of the products of this reaction.
(b) What mass of hydroxyapatite could form from 128 g of 95.0% phosphoric acid and 113 g of calcium hydroxide?
g Ca5(PO4)3(OH)

Answers

Answer 1

The equation of the reaction is 5Ca(OH)₂ + 3H₃PO₄ ---> Ca₅(PO₄)₃(OH) + 9H₂O. The mass of hydroxyapatite that could form is 159.7 g

What is the equation of the reaction?

We know that it is not possible to obtain the solutions to a problem of this sort unless we are able to obtain the balanced reaction equation. This is the only way that we are able to apply the stoichiometry solve the problem.

We have the balanced reaction equation as;

5Ca(OH)₂ + 3H₃PO₄ ---> Ca₅(PO₄)₃(OH) + 9H₂O.

Number of moles acid =  128 g /98.00 g/mol = 1.31 moles

Number of moles of calcium hydroxide = 113 g/ 74 g/mol = 1.59 moles

If 5 moles of calcium hydroxide reacts with 3 moles of acid

1.59 moles of calcium hydroxide reacts with 1.59 moles *  3 moles / 5 moles

= 0.954 moles

Hence  calcium hydroxide is the limiting reactant.

Now;

5 moles of  calcium hydroxide yields 1 mole of hydroxyapatite

1.59 moles  of  calcium hydroxide yields   1.59 moles  * 1 mole /5 moles

= 0.318 moles of hydroxyapatite

Mass of hydroxyapatite  = 0.318 moles  * 502.3 g/mol

= 159.7 g

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Related Questions

Which of the following increases as you move from left to right across a row of the
periodic table?
A atomic number
B atomic radius
C reactivity
D tendency to form ions

Answers

As you move from left to right across a row of the periodic table, the atomic number increases, meaning there are more protons in the nucleus of the atom.

Atomic number is the number of protons in the nucleus of an atom, which determines its chemical properties and place in the periodic table of elements. The atomic number is represented by the symbol Z and is the whole number located above an element's symbol in the periodic table.

Elements are arranged in order of increasing atomic number, and elements with the same atomic number belong to the same element, regardless of their mass number or number of neutrons.

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explain the statement potash alum is a double salt using the chemical formula of alum

Answers

Potash alum, represented by the chemical formula KAl(SO4)2·12H2O, is a double salt because it consists of two different salts, potassium sulfate (K2SO4) and aluminum sulfate (Al2(SO4)3), combined together. It forms a unique crystalline structure with 12 water molecules incorporated in its composition.

Potash alum is a type of alum that is commonly used in dyeing and water purification applications. The chemical formula for alum is KAl(SO4)2·12H2O.

The term "double salt" refers to the fact that the compound is made up of two different types of ions that are combined together.
In the case of potash alum, the two different types of ions are potassium ions (K+) and aluminum ions (Al3+). These two ions are combined together in a 1:1 ratio to form a complex ion, KAl(SO4)2, which is then combined with 12 water molecules to form the final compound, KAl(SO4)2·12H2O.
The term "double salt" is used to describe this type of compound because it contains two different types of cations (positive ions) that are combined together to form a single crystal lattice structure.

The two different cations are held together by ionic bonds, which are relatively strong and help to give the compound its characteristic properties.
Potash alum is a particularly useful compound because it has a number of important properties that make it useful in a variety of applications.

For example, it is highly soluble in water, which makes it a good choice for use in water purification applications.

It is also relatively stable and non-toxic, which makes it safe to use in a variety of different settings.

Finally, it has a number of useful physical properties, such as its ability to form crystals that are highly reflective and have a characteristic octahedral shape.

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how many atoms does 6H2O contain

Answers

Answer:

two atoms of oxygen. For H2O, there is one atom of oxygen and two atoms of hydrogen.

C3H8O2
empirical Or molecular
formula formula

Answers

Answer: i think its empirical

Explanation:

Hydrogen gas was cooled from 150 K to 50 K. Its new volume (V2) is 75 mL. What was its original volume (V1)?

Answers

Explanation:

57.3ml

we use Charles's law

to solve the question

Hydrogen gas was cooled from 150 K to 50 K. Its new volume (V2) is 75 mL. What was its original volume
Hydrogen gas was cooled from 150 K to 50 K. Its new volume (V2) is 75 mL. What was its original volume

Answer:

\(\boxed {\boxed {\sf 225 \ mL}}\)

Explanation:

The temperature and volume of the gas are changing, so we use Charles's Law. This states the temperature of a gas is directly proportional to the volume of a gas. The formula is:

\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)

The original volume is unknown. The new volume is 75 milliliters.

The gas is cooled from 150 Kelvin to 50 Kelvin, so the original temperature is 150 K and the new temperature is 50 K.

We know that:

T₁= 150 K V₂= 75 mL T₂= 50 K

Substitute the values into the formula.

\(\frac {V_1}{150 \ K}=\frac{ 75 \ mL}{50 \ K}\)

Since we are solving for the original volume, we must isolate the variable V₁.

It is being divided by 150 K. The inverse of division is multiplication, so we multiply both sides by 150 K.

\(150 \ K *\frac {V_1}{150 \ K}=\frac{ 75 \ mL}{50 \ K}* 150 \ K\)

\(V_1=\frac{ 75 \ mL}{50 \ K}* 150 \ K\)

The units of Kelvin (K) cancel.

\(V_1= \frac{ 75 \ mL}{50 }* 150\)

\(V_1=1.5 * 150 \ mL\)

\(V_1= 225 \ mL\)

The original volume is 225 milliliters.

What is the generic name of this molecule? (Ph stands for phenyl)

What is the generic name of this molecule? (Ph stands for phenyl)

Answers

The proper name of the compound is now 1,1 - dihydroxy-3-phenyl propene.

What is the name of the compound?

Firstly we know that the parent chain is based on propane. Now we have three substituents on that parent chain. Two hydroxy moieties and one phenyl moiety.

The proper name of the compound is now 1,1 - dihydroxy-3-phenyl propene.

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What is the mass of 6.02 x 1024 molecules of the compound HCl?

Answers

Answer:

First, we need to determine the molar mass of HCl.

The molar mass of HCl = the mass of hydrogen (1.008 g/mol) + the mass of chlorine (35.45 g/mol) = 36.45 g/mol.

Next, we can use Avogadro's number (6.02 x 10^23 molecules/mol) to convert the number of molecules to moles:

6.02 x 10^24 molecules / 6.02 x 10^23 molecules/mol = 10 moles

Finally, we can use the molar mass to convert moles to grams:

10 moles x 36.45 g/mol = 364.5 grams

Therefore, the mass of 6.02 x 10^24 molecules of HCl is 364.5 grams.

6.02* 10^24 means 1 molecule of any substance
:. It means 1 mole of Hcl
:. To find the mass of HcL
no of moles = mass/ molar mass
To get the molar mass of HCL {H=1 CL=35.5}
:. H+CL = 1+ 35.5 =36.5
So we have our molar mass and number of moles now
Then we input it in the eqn
1=x/36.5
X= 36.5g of HCl

If I start with 0.0350 L of a 12.0 M hydrochloric acid solution, and dilute it with water to a new volume of 1.20 L, what is the new concentration?

Answers

Answer:

0.35 M

Explanation:

Using the formula; C1V1 = C2V2

Where;

C1 = concentration of initial solution

C2 = concentration of final solution

V1 = volume of initial solution

V2 = volume of final solution

Based on this question, I start with 0.0350 L of a 12.0 M hydrochloric acid solution, and dilute it with water to a new volume of 1.20 L. This means that:

C1 = 12.0 M, V1 = 0.0350 L, V2 = 1.20 L, C2 = ?

Hence, C1V1 = C2V2

12 × 0.0350 = C2 × 1.20

0.42 = 1.2C2

C2 = 0.42/1.2

C2 = 0.35 M

During a day that is 39°F outside, it is also mid-fall. There is a nearby pond, what assumptions can you make about the temperature within that pond on that day?

During a day that is 39F outside, it is also mid-fall. There is a nearby pond, what assumptions can you

Answers

The temperature should be between 30 °F and 60 °F because the temperature outside is 39 °F, so the water in the pond should have a temperature range that includes this temperature.

Therefore, the answer is B.

summarize the processes by which glucagon, epinephrine and insulin affect the breakdown or synthesis of glycogen

Answers

Similar to glucagon, epinephrine increases glycogenolysis in the liver, which raises blood glucose levels.

How does breakdown of glycogen take place and how glucagon, epinephrine and insulin affect the process?

Glycogenolysis is the biological process through which glucose and glucose-1-phosphate are produced from glycogen. Both myocytes and hepatocytes contribute to the reaction. The process is affected by glycogen, epinephrine and insulin in such a way that-

The pancreas produces the hormone insulin, which enables glucose to enter body cells. Insulin's anabolic action on glycogen metabolism results in a decline in glycogen synthase phosphorylation. Other enzymes involved in the creation of glycogen are also affected. As a result, when the blood glucose level rises, insulin drives the creation of glycogen.Glucagon is a type of hormone that interacts with other hormones to help regulate blood glucose levels. It prevents the drop in blood glucose levels. Glycogen is released into the bloodstream and the breakdown of glycogen into a usable form is triggered. Additionally, it stops the production of glycogen.Epinephrine signals the liver and skeletal muscle to convert stored glycogen to glucose and release it primarily by starting gluconeogenesis when the level of blood glucose drops too low. This helps to increase blood sugar levels.

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A liquid has a mass of 3.35 g and volume of 5 mL. What is its density?*
D =
mass
volume

Answers

Explanation:

density= mass × volume

3.35×5

=. 16 .75

Suppose that 0.95 g of water condenses on a 75.0 g block of iron that is initially at 22 °C. If the heat released during condensation goes only to warming the iron block, what is the final tempera- ture (in Celsius) of the iron block? (Assume a constant enthalpy ofvaporizationforwaterof44.0kJmol-1.)

Answers

Answer:

The temperature of the iron block is 68.5°C.

Explanation:

The heat released during condensation of water is used to warm the iron block:

q = m_H2O * ΔH_vap = m_fe * c_fe * ΔT

where q is the heat released, m_H2O is the mass of water condensed, ΔH_vap is the enthalpy of vaporization for water, m_fe is the mass of iron, c_fe is the specific heat capacity of iron, and ΔT is the change in temperature of the iron block.

Rearranging the equation gives:

ΔT = (m_H2O * ΔH_vap) / (m_fe * c_fe)

Substituting the given values gives:

ΔT = (0.95 g * 44.0 kJ/mol) / (75.0 g * 0.449 J/(g°C))

ΔT = 46.5°C

Therefore, the final temperature of the iron block is:

T_f = T_i + ΔT = 22°C + 46.5°C = 68.5°C.

The final temperature of the iron block is 68.5°C.


scientist observes a 5-mL sample of
an unknown substance. It is a blue liquid with a
density of 1.2 g/cm3. The substance reacts with
carbon dioxide. List each of the properties of
matter the scientist observed and whether it is a
characteristic property of matter

Answers

Given what we know about the characteristics of matter and the observations given by the question, we can confirm that the characteristic properties observed by the scientists are the color, density, and the reaction of the liquid with carbon dioxide.

When we mention the properties of matter, we are speaking in general terms. Anything we can observe can be a property of the matter, such as:

Color Shape MassDensity

and etc. However, not all properties are characteristic properties of matter. These properties are reserved for those that do not change. Therefore, they are properties that can be used to identify matter.

Of the options listed, the properties that can be considered characteristic of this type of matter are the density, the color, and the reaction it has in the presence of carbon dioxide. This is because these properties will be the same anytime we have a sample of this matter, regardless of its mass, shape, or quantity.

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When liquids of a ph 5 and ph 2 mixed together, gives what ph value

Answers

Answer:

By mixing two solutions of differing pH values, the final pH of the mixed solution is going to be a function of the pH-, or the hydrogen ion (H+), of the lower pH solution, and the final volume. The hydrogen ion(H+) of the higher pH solution has little to no effect in the final pH value.

Please help I only need this one to finish!

Please help I only need this one to finish!

Answers

Answer:

                                                                2CO(g) + O2(g) ⇌ 2CO2(g)

Increasing the concentration of CO -         ↓         ↓                 ↑

Increasing the concentration of CO2 -       ↑         ↑                 ↓

Explanation:

The given reaction is

2CO(g) + O2(g) ⇌ 2CO2(g)

a) When the concentration of CO is increased, the stress is relieved as the reaction that consumes the added CO occurs more rapidly than its reverse reaction, for example., the forward reaction rate increases. The equilibrium will shift in favor of the product. However, the concentration of reactants (CO and O2) decreases and product concentration (CO2) increases.

b) When the concentration of CO2 is increased, the stress is relieved as the reaction that consumes the added CO2 occurs more rapidly than its reverse reaction, for example., the rate of backward reaction increases. The equilibrium will shift in favor of the reactant. Therefore, the concentration of reactants (CO and O2) increases, and the product concentration (CO2) decreases.

Hope this helps!

How much did asbestos exposure decrease during the year 1982 and 1983

How much did asbestos exposure decrease during the year 1982 and 1983

Answers

The asbestos exposure during the years 1982 and 1983 was 2.5 fibers per cubic centimeter and 0.8 fibers per cubic centimeter respectively. So asbestos exposure decreased by 1.7 fibers per cubic centimeter during the year 1983.

Breathlessness Persistent, dry cough Chest pain or tightness Lack of a dry, crackling sound in the lungs when you breathe in Wider and rounder fingers and toes are some of the symptoms of asbestos exposure.

The largest group of people exposed to asbestos is those working in the construction industry. Historically, asbestos was also used by pipe fitters and shipyard workers. In addition, asbestos was used by military personnel, auto mechanics, and many other occupations.

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what is the noble gas configuration for zirconium?
A. [Xe] 5s2 4d1
B. [Xe] 4d1
C. [Kr] 4d1
D. [Kr] 5s2 4d1

Answers

Answer:

[Kr] 4d² 5s²

Explanation:

In which of Earth's layers are the convection currents?

crust

mantle

inner core

lithosphere

Answers

Convention currents occurs in mantle of the Earth : )

which of following observations would support the claim that as plants absorb sunlight to make food, they release oxygen into the environment?

Answers

Can you include the observations please?

A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent of CH3OH.3. Calculate the molality of CH3OH.

Answers

Answer:

* \(x_{CH_3OH}=0.0425\)

* \(\%m/m_{CH_3OH}=7.31\%\)

* \(m=2.46m\)

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

\(x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}\)

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

\(n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O\)

Hence, mole fraction is:

\(x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425\)

Next, mass percent is:

\(\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%\)

And the molality, considering the mass of water in kg (0.185 kg):

\(m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m\)

Regards.

matrix composites of this type are noted for improving the resistance to fracture of their dispersive material.

Answers

This kind of matrix composite is renowned for strengthening the dispersive material's resistance to fracture. metals, ceramics, and polymers.

Ceramic matrix composites (CMC) are substances made of both ceramic and composite components.It consists of two parts: a matrix that holds the material together and a reinforcement that gives the material its tensile strength. When ceramic matrix composites have a scattered phase, it is primarily because the material's toughness has increased, which has increased the tensile strength.

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Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution.

H+ + H2O2 ↔ H2O+-OH (rapid equilibrium)

H2O+-OH + Br-→ HOBr + H2O (slow)

HOBr + H+ + Br- → Br2 + H2O (fast)

Which of the following rate laws is consistent with the mechanism?


Select one:
a. Rate = k [H2O+-OH][Br-]
b. Rate = k[Br-]
c. Rate = k[HOBr][H+][Br-][H2O2]
d. Rate = k[H2O2][H+][Br-]
e. Rate = k[H2O2][H+]2[Br-]

Answers

Answer:

a. Rate = k [H2O+-OH][Br-]

Explanation:

For a reaction:

nA+xB→C+D

The rate of the reaction is:

Rate = [A]ⁿ[B]ˣ

Now, in a mechanism, the rate of the reaction depends of the slow step. In the problem:

H2O+-OH + Br-→ HOBr + H2O

And the rate is:

a. Rate = k [H2O+-OH][Br-]


The stream table shows the time needed for water to soak into the playfield soil.

Answers

Answer:

TRUE

Explanation:

plz brian list

Answer:

True

Explanation:

Dynamic equilibrium between liquid and gas is established when __________ . a. the vapor pressure of the liquid equals the external pressureb. the liquid and vapor are at the same temperaturec. a liquid vaporizes and condenses at the same rated. the liquid is entirely evaporated

Answers

Answer:

The correct answer is option c. "a liquid vaporizes and condenses at the same rate"

Explanation:

In chemistry, dynamic equilibrium is defined as a state where the reaction rate of a forward reaction is equal to the reaction rate of the backward reaction. In this case, the reactions that participate in the system are the vaporization of a liquid and the condensation of a gas. Therefore, dynamic equilibrium is established when a liquid vaporizes and condenses at the same rate.

2.
If your favorite radio station has a frequency of 103.5 MHz, what is the wavelength
(in meters) of the radiation emitted by this station?

Answers

The wavelength of lambda is 2.93 m. = (c)/(v) = (3 xx 10(8) ms-(-1), 102.5 xx 10(6)s-(-1), 2.93 m' 2.93 meters is the wave length. 27 Jun 2022.

How can the wavelength of a radio wave be calculated in meters?

In order to get a radio wave's wavelength, divide its frequency by the speed of light (c = 299 792 458 m). The following is the formula for determining a radio wave's wavelength: Wavelength is equal to c/f, where c is the speed in meters per second, and f is the frequency in Hertz.

How is a wavelength calculated?

A wave train's speed (v) in a medium is equal to its frequency (f), hence the formula for wavelength is v/f. Wavelength is typically represented by the Greek symbol lambda ().

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How many single covalent bonds can carbon form?
o A. 1
O B. 2
O C.3
O D. 4

Answers

The answer is D!!!!!

Carbon contains four electrons in its outer shell

A Cycle of Chemical Reactions of Copper PRE-LABORATORY ASSIGNMENT Finish the pre-laboratory assignments before the laboratory experiment. Read the manual of this experiment and complete the following questions. 1. a. Identify oxidation-reduction reactions in the copper cycle experiment. For each oxidation-reduction reaction, write half reactions to show what is oxidized and what is reduced. Identify acid-base reactions and precipitation reactions in the copper cycle experi- ment. Write equations for the corresponding reactions. b. How many mL of 3.0 M NAOH are required to neutralize 4.0 mL of 16.0 M HNO2? 2. 1N Copper. AplL tions and interpreting them in terms of chemical equations. You will also use a simple classification scheme for grouping chemical reactions by type. Finally, you will practice quantitative lab techniques by trying to recover the copper with minimal loss. AN OVERVIEW OF THE COPPER CYCLE One of the most fascinating aspects of laboratory experiments to new chemistry students is the variety of colors, odors, and textures encountered. The present experiment demonstrates that aspect by a sequence of striking changes in color, appearance, and bulk. By going through this experiment, students will develop laboratory techniques by the challenges of shepherding copper through all chemical changes with minimal loss. A schematic outline of the chemical reactions involved in the experiment is shown in Figure 5-1 HNO Cu(NO)2 Cu (1) NaOH (2) Zn (5) Cu(OH), 9VOA CUSO je() A (heat) 1000 Ht H,SO Cuo Figure 5-1. A schematic outline of the series of chemical reactions in the copper cycle. The overall copper cycle is then given as Cu(NO,)2(aq) Cu(s) Cu(OH)2(s) CuO(s) CUSO,(aq) Cu(s) The balanced equations corresponding to these steps are: Nitric acid is not only a strong acid but also a strong oxidizing agent, making it a very effective solvent for most metals. 1. (1) 4HNO,(aq)+ Cu(s) Cu(NOs)2(aq) + 2H20(l) + 2NO2(g) Many heavy metals form insoluble hydroxides which can be precipitated from solutions by sol- uble hydroxides such as NaOH. 2. (2) Cu(OH)2(s) + 2NANO,(aq) Cu(NO,)2laq) + 2NaOH(aq) Many transition metal hydroxides lose water upon heating, thus changing to oxides. For copper, this reaction happens at a relatively lower temperature and is accompanied by a striking color change, from blue to black. 3. (3) Cu(OH)2(s)Cu0(s) + H20(e) 4. Metal oxides, being base an hydrides, form salts with acids just as readily as do the bases themselves. CuO(s) + H,SO(aq) CuSO(aq) + H20(e) (4) 5. Chemically active metals, such as zinc, readily displace less active metals from their salts. CuSO&(aq) + Zn(s) Cu(s) + ZnSO(aq) (5) 6. The reaction used to remove excess Zn(s) left over from eq(5): Zn(s) +2H*(aq) Zn2t(aq) + H(g) (6) The last reaction is not explicitly shown in the cycle, but actually occurs twice. The first reaction is with H from excess HSO, as a side reaction during the reduction of CuSO and the second one is with HCL, as an intentional step for the removal of excess Zn remaining in solution after reduction of Cu2+ to Cu. Each equation, as given above, describes one of the colorful transformations, but it is easy to lose sight of their physical meaning if you merely look upon them as a bunch of symbols written on paper. To become more familiar with the chemical equations it is essential to try the following: Find out what the compounds, represented by the formulas, actually look like and what their chemical properties are. a. What class of compounds they belong to, e.g. acid, salt, etc., and what the generic properties of this class are, ie. what types of reactions they undergo. b. Similarly, try to categorize the equations (actually, the reactions they represent): oxidation- reduction (redox) reaction, acid-base reaction, precipitation reaction, replacement reaction, C. etc CLASSIFICATION OF CHEMICAL REACTIONS Precipitation In a precipitation reaction, two soluble substances react to form an insoluble compound, e.g. (7) CaCl2+ Na COs CaCO,(s) + 2NaCl CACO3 is insoluble in water so this salt will form a precipitate and fall out of the solution. 45 LAB 5: A CYCLE OF CHEMICAL REACTIONS OF COPPER

Answers

1 . a.

Solution :

a. The oxidation reduction reactio is

1.    HNO₃ + Cu(3) --> Cu(NO₃)₂ + 2H₂O(l) + 2NO₂(g)

    Half reaction

    oxidation --> Cu(s) --> Cu(NO₃)₂(aq)

    reduction --> HNO₃ -->NO₂

   copper is oxidized and nitrogen is reduced

2 ->  CuSO₄(aq) + zn(s) --> Cu(s) + ZnSO₄(aq)

        Half reaction .

        oxidation --> Zn(s) --> ZnSO4(aq)

        Reduction --> CuSO₄ (aq) --> Cu(s)

        zinc is oxidized and copper is reduced.

3 ->   Zn(s) + 2H⁺(aq) --> Zn²⁺(aq) + H₂(g)

        oxidation --> Zn(s) --> Zn²⁺(aq)

         Reduction --> 2H⁺(aq) -->H₂(g)

        Zinc is oxidized and hydrogen is reduced .

b .  Acid - base reaction

       CuO(s) + H₂SO₄(aq) -->CuSO₄(aq) + H₂O(l)

       precipitation reaction

      Cu(NO₃)₂(aq) + 2NAOH(aq) -->Cu(OH)₂ + 2NANO₃

2 .  21.33 mL of 3.0 M NAOH are required to neutralize 4.0 mL of 16.0 M                        HNO2

1 mole of NAOH required to neutralized the

     1 mole of HNO₃

   NAOH + HNO₃ --> H₂O +NANO₃

 (M₁V₁)NAOH  =  (M₂V₂)HNO2

  3 * V₁  = 4 * 16

     V₁ = 64/3

     V₁= 21.33 ml

The term oxidation was originally used to describe the reaction in which an element combines with oxygen.

Example: The reaction of magnesium metal with oxygen to form magnesium oxide involves the oxidation of magnesium.

The term reduction comes from the Latin root and means "to undo". So anything that goes back to magnesium metal is a reduction.

The reaction of magnesium oxide with carbon at 200°C to form magnesium metal and carbon monoxide is an example of the reduction of magnesium oxide to magnesium metal.

electrons were discovered, the chemist became convinced that redox reactions involve the transfer of electrons from one of his atoms to another.

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Which combination of atoms is most likely to produce a compound
with ionic bonds?

Answers

Answer: In an ionic bond, one atom donates an electron to another atom. This stabilizes both atoms. Because one atom essentially gains an electron and the other loses it, an ionic bond is polar. In other words, one atom in the bond has a positive charge, while the other has a negative charge. Often, these atoms dissociate into their ions in water. Atoms that participate in ionic bonding have different electronegativity values from each other. If you look at a table of electronegativity values, it is apparent ionic bonding occurs between metals and nonmetals. Examples of compounds with ionic bonds include salt, such as table salt (NaCl).

What is the temperature (in K) of 16.45
moles of methane gas in a 70.7 L
container at 3,557 torr?

Answers

At 3,557 torr, 16.45 moles of methane gas are at a temperature of T=17.15 K in a 70.7 L container.

According to the ideal gas law: PV=nRT, where R=0.082 and T is temperature in Kelvin (K). P is pressure, V is volume, n is the amount in moles.

(4.68)*(4.95)=(16.45)*(0.0821)*

T=17.15, therefore calculate it.

What's called gas?

An object that is in the gaseous, or vaporous, condition of matter, is referred to as a gas. When referring to material with characteristics of a gaseous substance, the word "gas" can also refer to the condition itself. Along with liquid, solid, and plasma, gases are one of the four natural states of matter. The shape or volume of a gas can change.

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Answer:

245

Explanation:

everyone needs to chill don't answer if you can't get it right it wastes you time and others as well not trying be a hater but its true

Is is chemical or physical change? Sugar dissolving in tea

Answers

Answer:

Chemical

Explanation:

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