This is not possible since \(b^2\) cannot be negative. Therefore, the hyperbola with foci (0,3) and (0,-3) and difference of foci radii 3 does not exist.
We know that the distance between the foci of a hyperbola is 2c, where c is a constant. We also know that the difference between the distances from any point on the hyperbola to the two foci is a constant, which we will call 2a. Therefore, we have:
2c = 6 (since the difference of foci radii is 3, and each radius is c)
c = 3
Now, we need to find the value of a. We know that the distance between the center of the hyperbola and each focus is c, so the center of the hyperbola is at the origin (0,0). Therefore, the distance from the center to each focus is 3, and the value of a can be found using the Pythagorean theorem:
\(a^2 + b^2 = c^2\\a^2 + b^2 = 9\)
We don't know the value of b yet, but we can find it using the fact that the distance between any point on the hyperbola and the center is a constant, which we will call r. For the hyperbola, we have:
\(r^2 = x^2 + y^2\)
We know that the difference between the distances from any point on the hyperbola to the two foci is 2a, so we can write:
\(|(x-0)^2 + (y-3)^2 - (x-0)^2 - (y+3)^2| = 2a\)
Simplifying this expression, we get:
|36 - 6y| = 2a
Now, we can substitute the value of a and solve for b:
\(9 + b^2 = 9/4\)
\(b^2 = -63/4\)
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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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2. A 70.0-kg man and a 55.0-kg woman holding a 2.50-kg purse on ice skates stand facing eac other. (a) If the woman pushes the man backwards so that his final speed is 1.50 m/s, with what average force did she push him, assuming they were in contact for 0.500 s? (b) What i the woman's recoil speed? (c) If she now throws her 2.50-kg purse at him at a 20.0° angle ac
a) The average force with which the woman pushed the man is 210 N.
b. the woman's recoil speed is still 3.68 m/s
c. If she now throws her 2.50-kg purse at him at a 20.0° angle, the speed is 0.
How do we calculate?We first calculate the Momentum = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)
0 = (70.0 kg)(0 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s) - (70.0 kg)(-1.50 m/s)
v = 3.68 m/s
Δp = (70.0 kg)(1.50 m/s) - (70.0 kg)(0 m/s) = 105 kg·m/s
The average force exerted on the man by the woman is:
Average force = Δp / Δt
Average force = 105 kg·m/s / 0.500 s
Average force = 210 N
b) The woman's recoil speed is :
0 = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)
v = 3.68 m/s
c) If the woman throws her 2.50-kg purse at the man at a 20.0° angle, we apply the conservation of momentum equation in two dimensions and get the speed as 0.
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What is erosion and what are some famous things it has made?
Answer:
Erosion is the wearing away if land by forces such as water and wind. It has created things such as mountain peaks, valleys and coastlines.
Two straight wires located one-fifth of a meter from each other carry current in different directions. Current I1 = 13 A is into the page and I2 = 18 A is out of the page. Determine the magnitude and direction of the magnetic field for each of the wire and determine the magnitude of the magnetic field between the two wires.
The given situation can be illustrated as follow:
The red circles repersent the magnetic field produced by the currents on the wire.
As you can notice, between the wires the direction of the magnetic field is the same.
Consider that the magnetic field produced by a current I in a wire, at a distance r, is given by the following formula:
\(B=\frac{\mu_0I}{2\pi r}\)where,
r: distance at the center betwen the wires = 0.20m/2 = 0.10m
μ0: permeability of free space = 4π*10^-7 Tm/A
Then, the total magnetic field between the wire is the sum of the magnetic fields generated by each wire:
\(B=\frac{\mu_0}{2\pi(0.10m)^2}(I_1+I_2)=\frac{4\pi\cdot10^{-7}Tm\text{ /A}}{2\pi(0.10m)^2}(13A+18A)=6.2\cdot10^{-4}T\)Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with in a one-dimensional box 34.0 pm in length.
The question is incomplete. The complete question is :
Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with n = 6 in a one-dimensional box 34.0 pm in length.
Solution :
In an one dimensional box, energy of a particle is given by :
\($E=\frac{n^2h^2}{8ma^2}$\)
Here, h = Planck's constant
n = level of energy
= 6
m = mass of particle
a = box length
For n = 6, the energy associated is :
\($\Delta E = E_6 - E_1 $\)
\($\Delta E = \left( \frac{n_6^2h_2}{8ma^2}\right) - \left( \frac{n_1^2h_2}{8ma^2}\right) $\)
\($=\frac{h^2(n_6^2 - n_1^2)}{8ma^2}$\)
We know that,
\($E = \frac{hc}{\lambda} $\)
Here, λ = wavelength
h = Plank's constant
c = velocity of light
So the wavelength,
\($= \frac{hc}{E}$\)
\($=\frac{hc}{\frac{h^2(n_6^2 - n_1^2)}{8ma^2}}$\)
\($=\frac{8ma^2c}{h(n_6^2 - n_1^2)}$\)
\($=\frac{8 \times 9.109 \times 10^{-31}(0.34 \times 10^{-10})^2 (3 \times 10^8)}{6.626 \times 10^{-34} \times (36-1)}$\)
\($= \frac{ 8 \times 9.109 \times 0.34 \times 0.34 \times 3 \times 10^{-43}}{6.626 \times 35 \times 10^{-34}}$\)
\($=\frac{25.27 \times 10^{-43}}{231.91 \times 10^{-34}}$\)
\($= 0.108 \times 10^{-9}$\) m
= 108 pm
A block and tackle of 6 pulleys is used to raise a load of 300 newton steadily through a height of 30 meters. If the work done against friction is 2000j calculate the work done by effort?
Answer:
W = F * S = 300 N * 30 m = 9000 Joules
This is the work out of the system regardless of how the pulleys are arranged
Conservation of energy tells that
Work Out = Work In - Work done by friction
So Work In = 9000 J + 2000 J = 11000 J The work input to the system
a Toyota Celica, travelling initially at 26.9 m/s [S], comes to a stop in 2.61 s. The mass of the car with the driver is 1.18 × 103 kg. Calculate the car’s acceleration.
The initial velocity of the car is 26.9 m/s [S], and the final velocity is 0 m/s [S]. The time taken for the car to come to a stop is 2.61 s. Using the formula:
acceleration = (final velocity - initial velocity) / time
we can find the car's acceleration:
acceleration = (0 m/s - 26.9 m/s) / 2.61 s
acceleration = -10.305 m/s^2
The negative sign indicates that the car is decelerating, or slowing down.
To calculate the force acting on the car during the deceleration, we can use Newton's second law:
force = mass x acceleration
force = (1.18 × 10^3 kg) x (-10.305 m/s^2)
force = -12,166.1 N
The force acting on the car during deceleration is -12,166.1 N, or approximately 12.2 kN.
An insect crawls 4 m east along a hiking path in
20 seconds, and then a bird swoops down and eats it. What was the insect's velocity?
The insect's velocity is 0.2 meter/second along east.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given parameters:
An insect crawls 4 m east along a hiking path.
Time taken by it: t = 20 seconds.
We have to fine: the insect's velocity, v =?
So, the magnitude of velocity: v= 4/20 meter/second = 0.2 meter/second.
And the direction velocity is along east.
Hence, the insect's velocity is 0.2 meter/second along east.
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This week we discuss injuries to the head, neck and spine. There are so many long term affects of so many different head injuries. One of the biggest changes to head injuries that we have seen in the last decade is the implementation of concussion protocol. No matter the age or activity, the medical world has a recommended protocol for possible concussions and any head injury.
This weeks assignment. Research concussion protocol and submit the following in a written paper format.
-What is a concussion?
-Why do we need to have a concussion protocol?
-Who needs a concussion protocol? This is in regards to caring for injuries, not the injured person itself,
-Is there a standard concussion protocol should you follow? What is it?
-At a minimum, concussion protocol steps should include the what people in the process?
-Have you or anyone you know had to follow concussion protocol for a head injury? Tell me about it.
This is due Sunday I want to get started on it please someone help me ?
Answer:
Concussion is the most common type of mild traumatic brain injury and can have serious consequences
Explanation:
If you are running at 6m/s and decide at 2m/s². How long will take you to stop and how far will You go respectively while declaration
You will take 3 second to stop and you will go 9 meters far.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
Initial velocity: u = 6 m/s.
deceleration: a = 2 m/s^2.
Final velocity = 0 m/s.
We have to find: time: t = ? and distance travelled: s = ?
So, time taken to stop = v/a = 6/2 second = 3 second.
Distance travelled in this process: s = v^2/2a = (6×6)/(2×2) meter = 9 meter.
Hence, you will take 3 second to stop and you will go 9 meters far.
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what is average acceleration during time interval 0seconds to 1.1 seconds with 100km/h
Answer:
Therefore, the average acceleration during the time interval of 0 seconds to 1.1 seconds, with the initial velocity of 0 km/h and the final velocity of 100 km/h, is approximately 25.3 m/s².
Explanation:
To calculate average acceleration, we need to know the change in velocity and the time interval over which the change occurs. In this case, we are given the initial velocity (v1) as 0 km/h and the final velocity (v2) as 100 km/h during a time interval of 1.1 seconds.
First, we need to convert the velocities to m/s:
v1 = 0 km/h = 0 m/s
v2 = 100 km/h = 27.8 m/s (rounded to one decimal place)
The change in velocity (Δv) is:
Δv = v2 - v1
= 27.8 m/s - 0 m/s
= 27.8 m/s
The time interval (Δt) is given as 1.1 seconds.
Now, we can calculate the average acceleration (a) using the formula:
a = Δv / Δt
Substituting the values:
a = 27.8 m/s / 1.1 s
= 25.3 m/s² (rounded to one decimal place)
If a heat engine is operating between two temperatures (QH>QC), what is the maximum efficiency attainable?
When a heat engine is operating between two temperatures (QH>QC), the maximum efficiency attainable is Carnot efficiency .
What is Carnot Efficiency?
Carnot efficiency is the maximum theoretical efficiency of a heat engine, defined as the ratio of the work done by the engine to the heat absorbed from a high temperature source, as described by the Carnot cycle.
It is considered as the most efficient possible cycle for converting heat into useful work, and serves as an upper bound for the efficiency of all heat engines.
The Carnot efficiency is expressed as a function of the temperature difference between the hot and cold sources, and is independent of the working fluid or materials used in the engine.
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In what direction will each of the wires below move?
Answer:
Explanation: ckeck this imageTwo slides at a water park are shown below.
Calculate the length of the gentle slide.
Give your answer in metres to 2 d. p.
62%
2.48 m
35°
Key
Gentle slide
Extreme slide
Tp calculate the length of the gentle slide, first need to calculate the of water slide.
\(tan (62^{0})= \frac{h}{2.48}\)
\(h= 2.48*1.88\)
\(h=4,664m\)
Then, the length of gentle side:
\(sin(35^{0} )=\frac{4.664}{y}\)
\(0.57=\frac{4.664}{y}\)
\(y=8.182m\)
The length of gentle slide is 8.182m
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1) In hydrogen, the transition from level 2 to level 1 has a rest wavelength of 121.6 nm.
Find the speed for a star in which this line appears at wavelength 120.8 nm .
3) Find the speed for a star in which this line appears at wavelength 121.1 nm ..
5) Find the speed for a star in which this line appears at wavelength 121.8 nm .
7)Find the speed for a star in which this line appears at wavelength 122.4 nm .
To find the speed of a star in which the hydrogen transition from level 2 to level 1 appears at wavelength 120.8 nm, we can use the Doppler effect. The Doppler effect states that the observed wavelength of light (λobs) emitted by a moving object will be shifted relative to its rest wavelength (λrest) by an amount proportional to the object's velocity (v) with respect to the observer:
λobs = λrest * (1 + v/c)
where c is the speed of light.
In this case, we can use the known rest wavelength of the transition (121.6 nm) and the observed wavelength (120.8 nm) to solve for the velocity:
120.8 nm = 121.6 nm * (1 + v/c)
Solving for v, we get:
v = c * (120.8 nm - 121.6 nm) / 121.6 nm = -12.5 * 10^5 m/s
This is the velocity of the star away from the observer.
To find the speed for a star in which this line appears at wavelength 121.1 nm, we can use the same formula:
v = c * (121.1 nm - 121.6 nm) / 121.6 nm = -2.5 * 10^5 m/s
To find the speed for a star in which this line appears at wavelength 121.8 nm, we can use the same formula:
v = c * (121.8 nm - 121.6 nm) / 121.6 nm = -0.8 * 10^5 m/s
What is the doppler effect?The doppler effect is a physics phenomenon related to the perceived frequency variation of a moving wave relative to an observer.
This effect was studied by the Austrian physicist Christian Doppler (1803-1853) and the discovery was named after him. Hence, the doppler effect.
The doppler effect can be observed in any and all electromagnetic waves, such as light, or mechanical waves, such as sound.
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Calculations, show formula, substitution, and answer with units for full credit:
1. A train travels 150 kilometers in 5 hours. How fast is it traveling?
Answer:
30 km/h
Explanation:
V=S:t
speed=length:time
150:5=30
A light ray is incident from air into glass (ng = 1.52) then onto water (nw= 1.33). The wavelength of light in air (na= 1) is air = 500 nm and it travels at a speed c = 3 x 108 m/s. The wavelength of light, A, and its frequency, f, in water, are, respectively:
(a) 376 nm, 6 x 10¹4 Hz.
(b) 376 nm, 8 x 10¹¹ Hz
(c) 500 nm, 6 x 10¹4 Hz
(d) 500 nm, 8 x 10¹¹ Hz
What’s the correct answer answer asap for brainlist
Answer:
animals and wildlife (c)
Explanation:
Ecotourism is essentially tourism of nature--which highly incorporates animals/wildlife
> it usually has a goal of conservation of nature
poaching is illegally hunting wild animals, which is focused on an aspect of nature protection (which is why it is ecotourism)
the only option listed here that is about ecotourism is animals and wildlife (c), meaning that this is the correct fill-in
hope this helps! have a lovely day :)
Which wave has a longer wavelength?
Interpreting Graphics The velocity-versus-time graph for a shut-
tle bus moving along a straight path is shown in Figure 13.
a. Identify the time intervals during
which the velocity of the shuttle bus
is constant.
b. Identify the time intervals during
which the acceleration of the shuttle
bus is constant.
c. Find the value for the average veloc-
ity of the shuttle bus during each
time interval identified in b.
d. Find the acceleration of the shuttle
bus during each time interval identi-
fied in b.
e. Identify the times at which the
velocity of the shuttle bus is zero.
f. Identify the times at which the acceleration of the shuttle bus is zero.
g. Explain what the slope of the graph reveals about the acceleration in
each time interval.
Interpreting Graphics The velocity-versus-time graph for a shuttle bus moving along a straight path is shown in Figure 13., all the answer is attached.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
a) The time intervals during which the velocity of the shuttle bus is constant: 50 s to 150 s.
b) The time intervals during which the acceleration of the shuttlebus is constant: 500 s to 600s.
c) The value for the average velocity of the shuttle bus during time interval identified in b is: ( -3 +(-5))/2 =m/s = - 4 m/s.
d) The acceleration of the shuttle bus during time interval identified in b = ( -3 +(-5))/(600 - 500) m/s² = 0.02 m/s²
.e) The times at which the velocity of the shuttle bus is zero is : 200s to 300s.
f) The times at which the acceleration of the shuttle bus is zero is : 50s to 150s.
g) The slope of the graph reveals about the acceleration in each time interval that when it is positive the car is accelerated, when it is negative, the car is decelerated.
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What can light and sound both vary in which one of these ?
Volume
Intensity
Number or prespective?
Answer:
intensity
Explanation:
b. example, The sun is very bright and intense. and sounds can be very loud.
A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision. What is the final velocity of the two combined vehicles?
Answer:
v₃ = 3.33 [m/s]
Explanation:
This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.
In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.
\((m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}\)
where:
m₁ = mass of the car = 1000 [kg]
v₁ = velocity of the car = 10 [m/s]
m₂ = mass of the truck = 2000 [kg]
v₂ = velocity of the truck = 0 (stationary)
v₃ = velocity of the two vehicles after the collision [m/s].
Now replacing:
\((1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s]\)
2. For electric circuit shown in Figure find currents in each resistor.
The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.
What is the current flowing in each resistor?The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;
The total voltage in loop 1 is calculated as;
2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
The current flowing in loop 2 is calculated as;
I = V/R
I₂ = ( 6 V - 4 V ) / (3 + 4)
I₂ = 0.286 A
The value of the current flowing in loop 1 is calculated as;
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0
6 - 3I₁ - 3₁ + 0.858 = 0
-6I₁ = -6.858
I₁ = 6.858 / 6
I₁ = 1.14 A
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How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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Im pretty sure I know which one just makin sure
This is for my sister
______________________ is the body's normal reaction to help the body return to a more stable temperature when a person is really cold.
pacing
walking
shivering
freezing
Answer:
shivering raises your body temperature
The temperature of a body is from 200 to 300C.The change of temp at absolute scale is
Answer:
mark me brainliest
Explanation:
The change of temperature at absolute scale is. A. 3.73 K
Answer:
373K
Explanation:
300°c - 200°c =100°c
Absolute scale means Kelvin scale so
0°c= 273°c
100°c = 100 + 273
=373K
A white blood cell has a diameter of approximately 12 micrometers or 0.012 um a model represents its diameter as 24 um what ratio of model size
Answer:
The ratio of the model size is 1 : 2000
Explanation:
Given
Real Diameter = 0.012 um
Scale Diameter = 24 um
Required
Determine the scale ratio
The scale ratio is calculated as follows;
\(Scale = \frac{Real\ Measurement}{Scale\ Measurement}\)
Substitute values for real and scale measurements
\(Scale = \frac{0.012\ um}{24\ um}\)
Divide the numerator and the denominator by 0012um
\(Scale = \frac{1}{2000}\)
Represent as ratio
\(Scale = 1 : 2000\)
Hence, the ratio of the model size is 1 : 2000
Answer:
Explanation: The Answer Is D Two Thousand & The Number
A metal ball sits motionless on a flat surface. Which of these would make the ball move?
A. The force of gravity becomes less.
B. The force of gravity becomes greater.
C. Two equal horizontal opposing forces act upon the ball.
D. Two unequal horizontal opposing forces act upon the ball.
Answer:
D
Explanation:
Unbalanced forces move stuff. Gravity would only increase/decrease movement if the object was already in motion.
Answer:
b
Explanation:
A toy car on a string is pulled across a table horizontally. The string is at an
angle of 30°. Which is the correct free-body diagram for this situation?
EN
w
w
w
w
А
B
с
D
A. A
ОВ. В
ОО Ο Ο
O C. C
D. D
(C)
...........................
Answer:
Hope this helps!
Explanation:
Organizing and making sense of behavioral observations is central to psychology’s goal of ?
Answer:
Organizing and making sense of behavioral observations is central to psychology’s goal of explanation.