I) 1 mg =
a
g

ii)
b
mg = 1 g

iii) 1 kg =
c
g

iv)
d
kg = 1 g

v) 1 tonne =
e
kg

vi)
f
tonnes = 1 kg

Check B

(-3,0) and (0,-3)

Find slope

It has y intercept (0,-3)

Check A

(3,0) and (0,3)

Option A is correct

Answer:

A

Step-by-step explanation:

Positive slope:  as the x-value increases, the y-value increases.

Negative slope:  as the x-value increases, the y-value decreases.

The slope of the graph is -1

As it has a negative sign, the graph has a negative slope.  

As the slope is -1, this means that for every 1 unit increase of the x-value, the y-value decreases by 1 unit.

The line passes through (0, 3)

When the x-value is zero, the line intercepts the y-axis.  

Therefore, the line will intercept the y-axis when y = 3.

Therefore, the graph of the line that passes through (0, 3) and has a slope of -1 is option A.

\(\begin{array}{|l|c|c|c|c|}\cline{1-5} & \sf Graph\:A & \sf Graph\:B & \sf Graph\:C & \sf Graph\:D \\\cline{1-5} \sf slope & \sf negative & \sf negative & \sf positive & \sf positive\\\cline{2-5} \sf & -1 & -1 & 1 & 1\\\cline{1-5} \sf y-intercept & (0,3) & (0,-3) & (0,-3) & (0,3)\\\cline{1-5}\end{array}\)

The value of the line integral is 108π.

To use Green's theorem to evaluate the line integral ∫c (y − x) dx (2x − y) dy, we first need to find a vector field F whose components are the integrands:

F(x, y) = (2x − y, y − x)

We can then apply Green's theorem, which states that for a simply connected region R with boundary C that is piecewise smooth and oriented counterclockwise,

∫C F ⋅ dr = ∬R (∂Q/∂x − ∂P/∂y) dA

where P and Q are the components of F and dr is the line element of C.

To apply this formula, we need to find the region R that is bounded by the given curves y = √81 −\(x^2\) and y = √9 − \(x^2.\) Note that these are semicircles, so we can use the fact that they are both symmetric about the y-axis to find the bounds for x and y:

-9 ≤ x ≤ 9

0 ≤ y ≤ √81 − \(x^2\)

√9 − \(x^2\) ≤ y ≤ √81 − \(x^2\)

The first inequality comes from the fact that the semicircles are centered at the origin and have radii of 9 and 3, respectively. The other two inequalities come from the equations of the semicircles.

We can now apply Green's theorem:

∫C F ⋅ dr = ∬R (∂Q/∂x − ∂P/∂y) dA

= ∬R (1 + 2) dA

= 3 ∬R dA

Note that we used the fact that ∂Q/∂x − ∂P/∂y = 1 + 2x + 1 = 2x + 2.

To evaluate the double integral, we can use polar coordinates with x = r cos θ and y = r sin θ. The region R is then described by

-π/2 ≤ θ ≤ π/2

3 ≤ r ≤ 9

and the integral becomes

∫C F ⋅ dr = 3 ∫_{-π/2\(}^{{\pi /2} }\int _3^9\) r dr dθ

= 3\(\int_{-\pi /2}^{{\pi /2}} [(9^2 - 3^2)/2]\)dθ

= 3 (72π/2)

= 108π

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Answer:

guru gossip and you can you invite me to the heading

The inequality for the possible values of w are;  w >  2l.

We know that the sum of length of the sides used to made the given figure.

We are given that perimeter of the rectangle > perimeter of the triangle

Let the dimension of the rectangle be w as width and L as length

Then perimeter of the rectangle = 2(L + w)

Now let the side of triangle be w then;

The perimeter of the triangle = 3w

The inequality becomes as;

2(L + w) > 3w

2w + 2L > 3w

w + 2l> 0

w >  2l

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Question 1 below on day 1 city A

on day 3 city B

Question 3 city A has more crimes

for question 2 i need to know the options

Parametric estimating is a valuable technique in project management that can save time and resources by using historical data to establish a statistical relationship and estimate the scope, cost, and duration of a project. (option d).

Estimating techniques are used in project management to calculate an estimate for the scope, cost, and duration of a project.

The keyword to note here is "statistical relationship". In parametric estimating, this relationship is established by analyzing historical data and identifying patterns and trends. Once a relationship has been established, it can be used to estimate the scope, cost, and duration of a similar project in the future.

Similarly, in software development, the lines of code can be used as a variable to establish a statistical relationship. By analyzing the historical data of similar projects, a relationship can be established between the lines of code and the duration of the project.

Hence the correct option is (d).

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Answer:

Step-by-step explanation:

Trick quesition you asked

Answer:

it can be taken like this

5 y^2/2= 2.5 y^2

The equation Ax = b does not have a solution for all possible b. The set of all b for which Ax = b does have a solution is the set of all b such that 6b3 - 3b2 + 2b1 = 0.

The equation Ax = b is equivalent to the system of equations:
x1 - 4x2 - 3x3 = b1
-4x1 + 4x2 + 0x3 = b2
2x1 + 0x2 + 6x3 = b3

we add the first two equations, we get:
-3x3 = b1 + b2

This means that 6b3 - 3b2 + 2b1 = 0. So, the set of all b for which Ax = b has a solution is the set of all b such that 6b3 - 3b2 + 2b1 = 0.
Step-by-step solution:
1.We can write the equation Ax = b as a system of equations:
x1 - 4x2 - 3x3 = b1
-4x1 + 4x2 + 0x3 = b2
2x1 + 0x2 + 6x3 = b3

2.Add the first two equations:

-3x3 = b1 + b2

3.This means that 6b3 - 3b2 + 2b1 = 0.

4.Therefore, the set of all b for which Ax = b has a solution is the set of all b such that 6b3 - 3b2 + 2b1 = 0.

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The set of all b for which Ax = b does have a solution can be described as: b = b1*[1, -4, -3] + b2*[-4, 4, 0] = [b1 - 4b2, -4b1 + 4b2, -3b1].

To show that the equation Ax = b does not have a solution for all possible b, we can row reduce the matrix A to determine if it has a pivot position in every row. If there is a row without a pivot position, it means that the corresponding equation in the system is inconsistent, and thus the system does not have a solution for all possible b.

Let's row reduce the matrix A:

1 -4 -3

-4  4  0

2   4  6

Performing row operations:

R2 + 4R1 -> R2

R3 - 2R1 -> R3

1 -4 -3

0   0  12

0   12 12

Now, we can see that the second row consists of all zeros, which means there is no pivot position in that row. Therefore, the system Ax = b does not have a solution for all possible b.

To describe the set of all b for which Ax = b does have a solution, we need to consider the column space of matrix A. The column space is the span of the columns of A, and any vector b that can be written as a linear combination of the columns of A will have a solution.

The columns of A are:

[1, -4, 2]

[-4, 4, 4]

[-3, 0, 6]

We can see that the third column is a multiple of the second column, so the column space of A is actually spanned by the first two columns. Therefore, any vector b that can be expressed as a linear combination of the first two columns will have a solution to Ax = b.

Thus, the set of all b for which Ax = b does have a solution can be described as:

b = b1*[1, -4, -3] + b2*[-4, 4, 0] = [b1 - 4b2, -4b1 + 4b2, -3b1]

Here, b1 and b2 are scalar coefficients that can vary, and bz is set to 1 as indicated in the question.

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Let A = 1-4 -3 -4 4 0 2 4 6 and b = b2 . Show that the equation Ax=b does not have a solution for all possible b, and describe the set of all b for which Ax=b does have a solution. How can it be shown that the equation Ax = b does not have a solution for all possible b? Describe the set of all b for which Ax=b does have a solution. 0= (Type an expression using b1,b2, and bz as the variables and 1 as the coefficient of bz.)

Answer:

a=(2p-3n)/12

Step-by-step explanation:

-12a=-2p+3n

Or, a= -{(-2p+3n)/12}

a=(2p-3n)/12

Option 2 is correct that is 1.79

When presented in ascending order, the value that 75% of data points fall within is known as the higher quartile, or third quartile (Q3).

The quartiles formula is as follows:

Upper Quartile (Q3) = 3/4(N+1)

Lower Quartile (Q1) = (N+1) * 1/3

Middle Quartile (Q2) = (N+1) * 2/3

Interquartile Range = Q3 -Q1,

1.74, 0.24, 1.56, 2.79, 0.89, 1.16, 0.20, and 1.84 are available.

Sort the data as follows: 0.20, 0.24, 0.89, 1.16, 1.56, 1.74, 1.84, 2.79 in ascending order of magnitude.

The data set has 8 values.

hence, n = 8; third quartile: 3/4 (n+1)th term

Q3 =3/4 of a term (9) term

Q3 =27/4 th term

Q3 = 1.74 + 1.84 / 2 (average of the sixth and seventh terms)

equals 1.76

Thus Q3 is 1.76 that is option 2

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Answer:

982.

Step-by-step explanation:

hope you get a good grade

As a result, on a graph of dP/dt vs P, the curve would be concave down for P b/a and concave up for P > b/a. The curve would reach its maximum when P = b/a, with dP/dt equal to zero.

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign.

Here,

The equation dP/dt = aP² - bP represents the rate of change of the population P over time t.

When dP/dt is positive, the population is increasing. When dP/dt is negative, the population is decreasing.

To find when dP/dt is positive and negative, we need to find the critical points where dP/dt = 0.

Solving the equation dP/dt = aP² - bP = 0, we get:

aP² - bP = 0

aP(P - b/a) = 0

This equation has two solutions: P = 0 and P = b/a.

For P < b/a, dP/dt is negative (the population is decreasing). For P > b/a, dP/dt is positive (the population is increasing).

So, on a graph of dP/dt against P, the curve would be concave down for P < b/a and concave up for P > b/a. At P = b/a, the curve would have a maximum and dP/dt = 0.

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If someone wants the product of two line segments to be represented as another line segment, they can make use of similar triangles

The correlation between the lengths of line segments can be established by creating a geometric shape comprising of two triangles that are identical and share one side.

If the legs of the triangles are used to represent the two line segments and their shared side represents the resulting line segment, it is possible for the lengths to be proportional through the similarity of the triangles.

To represent the product of the two original line segments, it is necessary to ensure that they and the resulting line segment are a collection of similar triangles. This is because the length of the resulting line segment can represent the product of the initial segments.

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Factors estimate 5,897 times 67

The estimate product of the factors 5897 times 67 is 383500.

We have to use strategies to estimate the products.

We can round each factor to the greatest place value which is the place value farthest to the left.

we can use compatible numbers.

compatible numbers are friendly numbers they are easy to compute numbers.

Given 5897\(\times\)67=395099

This is the actual factor

But the estimation product is

We use mental math and compatible numbers here.

step1: 5900\(\times\\\)70=413000

step2:5900\(\times\)65=383500

Both the step1 and step2 are reasonable because the factor are close to the actual factor.

But 5900\(\times\)65=383500 is better because it is very close to the actual factor compared to 5900\(\times\\\)70=413000.

Therefore, The estimate product of the factors 5897 times 67 is 383500.

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To choose the addition problems in which you add zeros to align place values in the addends, let's go through each option:

a. 6.23 + 11.01 + 4.99
In this problem, you need to add zeros to align the place values. Let's write it out:

  6.23
+11.01
+ 4.99
_______
 22.23

b. 15.03 + 23.23
In this problem, the place values are already aligned, so you don't need to add any zeros. Let's add the numbers:

  15.03
+ 23.23
_______
  38.26

c. 0.04 + 5 + 3.2
Here, the place values are not aligned. To align them, we need to add a zero to 5 and 3.2. Let's rewrite the problem:

  0.04
+ 5.00
+ 3.20
_______
  8.24

d. 1.2 + 5.75 + 2.8
In this problem, the place values are already aligned, so no need to add any zeros. Let's add the numbers:

  1.20
+ 5.75
+ 2.80
_______
  9.75

e. 18.9 + 0.7
The place values are already aligned, so no need to add any zeros. Let's add the numbers:

  18.90
+  0.70
_______
  19.60

Based on the analysis above, the addition problems in which you add zeros to align place values in the addends are:
a. 6.23 + 11.01 + 4.99
c. 0.04 + 5 + 3.2

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The tires and the traction control system work in tandem to ensure maximum traction and stability, minimizing the risk of traction loss and improving overall vehicle control and safety.

The two most important parts of a vehicle in preventing traction loss are the tires and the traction control system.

Tires: Tires are the primary point of contact between the vehicle and the road surface. The quality and condition of the tires greatly influence traction. Tires with good tread depth and appropriate tread pattern are essential for maintaining grip on the road. Tread depth helps to channel water, snow, or debris away from the tire, preventing hydroplaning or loss of traction. Additionally, tire pressure should be properly maintained to ensure even contact with the road. Choosing tires suitable for the specific driving conditions, such as all-season, winter, or performance tires, is crucial for optimal traction and handling.

Traction Control System: The traction control system is a vehicle safety feature that helps prevent the wheels from slipping or spinning on low-traction surfaces. It uses various sensors to monitor the speed and rotation of the wheels. If the system detects a loss of traction, it will automatically reduce engine power and apply braking force to the wheels that are slipping. By modulating power delivery and braking, the traction control system helps maintain traction and prevent wheel spin, especially in challenging conditions like slippery roads or during quick acceleration.

The tires and the traction control system work in tandem to ensure maximum traction and stability, minimizing the risk of traction loss and improving overall vehicle control and safety.

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Answer:

vertex is (6, -11)

Step-by-step explanation:

Given equation
f(x) = x² - 12x + 25

is that of an upward-facing parabola(since the coefficient of x² is positive).

The vertex will be at a minimum and its x-coordinate can be found by finding the first derivative of f(x), setting it equal to zero and solving for x

f'(x) = d/dx(x² - 12x + 25)

= 2x - 12

f'(x) = 0 ==> 2x - 12 = 0

2x = 12

x = 6

Substitute x = 6 in f(x) to get

f(6) = 6² - 12(6) + 25

= 36 - 72 + 25

= -11

So the vertex is at (6, -11)

The probability of the sum of the die rolls being odd is 1.

To find the probability that the sum of the die rolls is odd, let's consider all the possible outcomes step by step.

When two fair coins are tossed, the possible outcomes are: HH, HT, TH, and TT.

For each head that results, we roll a fair die. So, for HH, we roll two dice, and for HT, TH, and TT, we roll one die.

Let's calculate the probability for each outcome:

1. HH: The sum of two dice can be odd if one die shows an even number and the other shows an odd number. The possibilities are: (2, 1), (2, 3), (4, 1), (4, 3), (6, 1), and (6, 3). Therefore, the probability is 6/36 = 1/6.

2. HT: The sum of one die can only be odd if the die shows an odd number. The possibilities are: 1, 3, or 5. Therefore, the probability is 3/6 = 1/2.

3. TH: Same as HT, the probability is also 1/2.

4. TT: Since no dice are rolled, the sum is 00, which is even.

To find the overall probability, we need to consider the probabilities of each outcome occurring:

Probability of HH = 1/6
Probability of HT = 1/2
Probability of TH = 1/2
Probability of TT = 0

The total probability is the sum of these probabilities:

1/6 + 1/2 + 1/2 + 0 = 1/6 + 1 = 7/6

Please note that probabilities cannot exceed 1. Therefore, the probability of the sum of the die rolls being odd is 1.

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We can solve the Inequalities by Isolating the variables that are present in the given Inequality.

In mathematics, an inequality is a connection between two values or mathematical equations that results in an unequal comparison.

The signs that we use in Inequalities are less than( < ), less than or equal to ( ≤ ), greater than ( > ), greater than or equal to ( ≥ ), and not equal to (≠) sign.

Lets us consider we have inequality 3x + 2 + x ≥ 10

We can solve the above inequality as given below

Here we will solve the inequality by Isolating the variable  

Step - 1

Add x term and constant terms

=> 4x + 2 ≥ 10   [ here 3x + x = 4x ]

Step - 2  

Bring out x terms at one side, and constant terms at another side by doing required operations like adding

=> 4x + 2 ≥ 10    [ here we will subtract 2 from both sides ]

=> 4x + 2 - 2  ≥ 10 - 2

=> 4x  ≥ 8  

Step - 3

Now isolate the variable to get the solution

=>  4x/4  ≥ 8/4         [ here divided by 4 ]

=> x  ≥ 2  

Therefore, the required solution is x ≥ 2    

Therefore,

We can solve the Inequalities by Isolating the variables that are present in the given Inequality.

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The equation of the line with slope m and y-intercept b is given by:

In this case the slope is 5 and the y-intercept is -2; then we have that the equation of the line is:

Now that we have the equation of the line we can use it to find points on the line, we do that by given values to x (whichever values we want) and use the equation to determine its corresponding y value.

If x=0, then we have:

Hence, the line passes through the point (0,-2).

If x=1, then we have:

Hence, the line passes through the point (1,3).

Now that we have two points on the line we graph them on the plane:

Finally, we join the points with a straight line. Therefore, the graph of the line is:

Answer:

15

Step-by-step explanation:

the range is the largest number take away the smallest number

56-41=15

Answer:

15

Step-by-step explanation:

you just put 5/6 x 18 in calculator, please rate 5 stars :)

Answer:

15 pencils.

Step-by-step explanation:

Multiply 18 and 5/6 to find the answer.

\((18)(\frac{5}{6})=15\)

Therefore, she will have given away 15 pencils.

The formula for the volume of a cylinder is pi * radius squared * height, or πr^2h.

To find the radius of the cylinder, take the given diameter (60 cm) and divide it by 2. 60 / 2 = 30 cm.

Now we need to either find the height in centimeters or find the radius in meters. Because a centimeter is 1/100 of a meter, we multiply the radius by 100 to get the radius in meters.

We also must square the radius. So 30 cm multiplied by itself equals 900 cm.

Radius: 900 / 100 = 9 m

We have to square the radius before plugging it into the equation because it would mess up the numbers if we didn't (0.3 m squared is 0.09 m, which is very small).

Now we can plug these values into the formula for the volume of a cylinder.

π * r^2 * h = π * 9 m * 1.7 m = ~48.066 cubic meters

Rounded to two decimal places is 48.07 cubic meters.

The volume of the tree trunk is about 48.07 cubic meters.

Therefore, the predicted difference in sales between two women's clothing stores differing by $30,000 is $217,500, which is option E.

Given a regression equation is y = 5000 + 7.25x, where y is the predicted sales value (in dollars) and x is advertising budget (in dollars).To find the predicted difference in sales of two stores which differ by $30,000 in advertising budget. Here, the slope of the line is 7.25. This means that for every dollar increase in advertising budget, sales will increase by $7.25. Therefore, a $30,000 difference in advertising budget will lead to a difference in sales of:7.25 × 30,000 = 217,500Therefore, the predicted difference in sales between two women's clothing stores differing by $30,000 is $217,500, which is option E.

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Answer:

8.41

Step-by-step explanation:

Answer:

it's 8.41

Step-by-step explanation:

SORRY I CANT ADD ANSWER AND SAYS RUDE THEN I HAVE IDEA SCREENSHOT

MAYBE HELP THIS LINK

on picture

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\(\textsl{Answer.}\)

See Below. \(\bigtriangledown\!\!\!\!\bullet\)

\(\leadsto\overline{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}\curvearrowleft\)

\(\textsl{Explanation.}\)

Let's examine our equation first

\(\textmd{y=mx+c}\). In which "m" denotes  "gradient" \(\&\) "c" denotes "y intercept".

\(\mid\odot\odot\odot\odot\odot\odot\odot\odot\odot\odot\odot\odot\odot\odot\mid\)

But now you should notice something.

\(\bullet\) The quantity that denotes the gradient is multiplied times x.

\(\bullet\) The quantity that denotes the y intercept is added to the gradient times x.

\(\textsl{that's how we can find m and c in the equation!}\)

Hope that this helped! Best wishes

\(\star\triangleright\textsl {Reach \: far.\:Aim\: high.\:Dream\:big.}\triangleleft\star\)

\(\boldsymbol{-Greetings!-}\)

______________________