i am concerned about having my child play in the neighborhood park near my house because of the possible presence of highly aggressive children. i have drawn one random sample of 100 children from the neighborhood (n

Answers

Answer 1

This analysis is based on a sample of 100 number of children from the neighborhood, so the findings may not be representative of the entire population. It's important to interpret the results cautiously and consider conducting further research if needed.

To analyze the presence of highly aggressive children in the neighborhood, you can follow these steps:
1. Define aggression: It's important to have a clear understanding of what qualifies as highly aggressive behavior in children. Aggression can include physical aggression (e.g., hitting, pushing) or verbal aggression (e.g., name-calling, teasing).
2. Observe and document behavior: Use a behavior checklist to systematically observe the children in your sample. Note any instances of aggressive behavior and document them.
3. Analyze the data: Once you have observed and documented the behavior, you can analyze the data to determine the prevalence of highly aggressive children in the neighborhood. Calculate the percentage of children in your sample who exhibit highly aggressive behavior. For example, if 10 children in your sample exhibit highly aggressive behavior, the prevalence would be 10%.
4. Compare to norms: To put your findings into context, it can be helpful to compare the prevalence of highly aggressive children in your neighborhood to established norms. Look for research or studies that provide data on aggression rates in children. This can give you a sense of whether the prevalence in your neighborhood is higher or lower than average.
5. Communicate and take action: Once you have analyzed the data, it's important to communicate your findings with relevant stakeholders, such as other parents, community organizations, or local authorities. If the prevalence of highly aggressive children is a concern, you can discuss potential actions to address the issue, such as implementing programs to promote positive behavior or increasing adult supervision in the park.
Remember, this analysis is based on a sample of 100 children from the neighborhood, so the findings may not be representative of the entire this analysis is based on a sample of 100 children from the neighborhood, so the findings may not be representative of the entire population. It's important to interpret the results cautiously and consider conducting further research if needed.. It's important to interpret the results cautiously and consider conducting further research if needed.

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Related Questions

The Corner Store has a special today. You can either buy three small 6” Hawaiian pizzas for $10 or one large 18” Hawaiian pizza for $18.50. Which option is a better value?

Answers

Answer:B is correct

Step-by-step explanation:

i did the lesson

Show that if G s a group, then (g−1)^(−1) = g and (gh)^(−1)=
h^(-1) * g^(-1)

Answers

In a group G, it can be shown that the inverse of the inverse of an element g is equal to g itself, and the inverse of the product of two elements gh is equal to the product of the inverses of h and g. These properties highlight the algebraic structure of groups and their operation.

To show the given statements, let's consider an arbitrary group G and two arbitrary elements g and h from G.

1.To prove that\((g^{(-1)})^{(-1)}\) = g:

By definition, the inverse of an element g in a group G is denoted as \(g^{(-1)}\)and satisfies the property g * \(g^{(-1)}\) = \(g^{(-1)}\) * g = e, where e is the identity element of the group.

Now, consider the element \(g^{(-1)}\) in G. We want to show that \((g^{(-1)})^{(-1)}\) = g.

Using the definition of inverses, we have:

(\(g^{(-1)}\)) * \((g^{(-1)})^{(-1)}\)= \((g^{(-1)})^{(-1)}\) * (\(g^{(-1)}\)) = e

Now, let's multiply both sides of the equation on the left by g:

g * [(\(g^{(-1)}\)) * \((g^{(-1)})^{(-1)}\)] = g * e

(g * \(g^{(-1)}\)) * \((g^{(-1)})^{(-1)}\) = g

Since g * \(g^{(-1)}\) = e, we can substitute it in the equation:

e * \((g^{(-1)})^{(-1)}\) = g

\((g^{(-1)})^{(-1)}\) = g

Therefore, we have shown that\((g^{(-1)})^{(-1)}\) = g for any element g in the group G.

2.To prove that\((gh)^{(-1)}\) = \(h^{(-1)}\)* \(g^{(-1)}\):

Again, let's use the definition of the inverse in a group. For elements g and h, their inverses are denoted as \(g^{(-1)}\) and \(h^{(-1)}\), respectively, and satisfy the property g * \(g^{(-1)}\) =\(g^{(-1)}\) * g = e and h * \(h^{(-1)}\) = \(h^{(-1)}\) * h = e.

Now, we want to show that \((gh)^{(-1)}\) =\(h^{(-1)}\) * \(g^{(-1)}\).

Consider the product gh in G. We want to find an element x such that (gh) * x = x * (gh) = e, where e is the identity element of the group.

Let x = \(h^{(-1)}\) * \(g^{(-1)}\). Now, we have:

(gh) * (\(h^{(-1)}\) * \(g^{(-1)}\)) = h * (g * (\(h^{(-1)}\)* \(g^{(-1)}\))) [Associativity of group operation]

= h * ((g * \(h^{(-1)}\)) * \(g^{(-1)}\)) [Associativity of group operation]

= h * (e * \(g^{(-1)}\)) [Since g * \(h^{(-1)}\) = e]

= h * \(g^{(-1)}\) [Since e * \(g^{(-1)}\)= \(g^{(-1)}\)]

= e [Since h * \(g^{(-1)}\) = e]

Similarly, we can show that (\(h^{(-1)}\)* \(g^{(-1)}\)) * (gh) = e.

Therefore, we have shown that \((gh)^{(-1)}\) = \(h^{(-1)}\) * \(g^{(-1)}\) for any elements g and h in the group G.

Hence, both statements are proven.

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Calculate the range, variance, and standard deviation for the following samples a. 43, 41, 48, 47, 49 b. 100, 1, 3, 95, 70, 4, 6, 10, 5 c. 100, 1, 3, 30, 70, 30, 43, 5 a. The range is 8 Type an integer or a decimal. Do not round.) The variance is 11.80 (Round to two decimal places as needed.) The standard deviation is 3.4 (Round to one decimal place as needed.) b. The range is 99 (Type an integer or a decimal. Do not round.) The variance is 1813.50 (Round to two decimal places as needed.) The standard deviation is 42.6 (Round to one decimal place as needed.) c. The range is 99 (Type an integer or a decimal. Do not round.) The variance is 1234.79 (Round to two decimal places as needed.) he standard deviation is (Round to one decimal place as needed.)

Answers

The range, variance, and standard deviation are 8, 21.10, 445.21.

The range, variance, and standard deviation are 99, 40.14,1612

What is data?

Data is a collection of measurements or observations used as a source of information. There are numerous types of data and numerous ways to represent data.

Given data is

43, 41, 48, 47, 49

Arrange them in ascending order:

41, 43, 47, 48,49

The range is (49 - 41) =8

The mean is (41+43+47+48+49)/5 =45.6

Data      deviation from mean    square  deviation

41                         4.6                         21.16

43                         2.6                        6.76

47                         -1.4                        1.96

48                         -2.4                        5.76

49                         -3.4                        11.56

Total                                                  47.2

The standard deviation is s = √[(x-μ)²/N] = 21.10

The variance is s² = 445.21

Given data is

100, 1, 3, 95, 70, 4, 6, 10, 5

Arrange them in ascending order:

1, 3, 4, 5, 6, 10, 70, 95, 100

The range is (100 - 1) = 99

The mean is (1+3+4+6+5+10+70+95+100)/9 =32.67

Data      deviation from mean    square  deviation

1                         31.67                         1002.99

3                         29.67                       880.31

4                         28.67                        821.97

5                        27.67                         756.63

6                         26.67                        711.29

10                         22.67                      513.93

70                        -37.33                       1393.52

95                        -62.33                      3885.03

100                         -3.33                        4533.33

Total                                                     14508.0001

The standard deviation is s = √[(x-μ)²/N] = 40.14

The variance is s² = 1612

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Given f(x) = 3x - 1 and g(x) = 2x + 1, find (f +g)(3)

Answers

Answer:

(f + g)(3) = 15

Step-by-step explanation:

f(x) = 3x - 1

g(x) = 2x + 1

To find (f +g)(3) , first find (f + g)(x)

To find (f + g)(x) add g(x) to f(x)

That's

(f + g)(x) = 3x - 1 + 2x + 1

= 3x + 2x + 1 - 1

(f + g)(x) = 5x

Now to find (f + g)(3) substitute 3 into

(f + g)(x)

That's

(f +g)(3) = 5(3)

(f + g)(3) = 15

Hope this helps you

Would be grateful if I get help

Would be grateful if I get help

Answers

\(\\ \sf\longmapsto 72^{\frac{3}{4}}\)

\(\\ \sf\longmapsto 72^{\frac{1}{4}+\frac{1}{4}+\frac{1}{4}}\)

\(\\ \sf\longmapsto 2.91+2.91+2.91\)

\(\\ \sf\longmapsto 3.73\)

I am thinking of a number. When I divide my number by $7$ and subtract $\dfrac{3}{5},$ I get back my original number. What is my number?

Answers

(x/3)-10 = 22
add 10 to both sides
x/3 = 32
multiply 3 on both sides
x = 96

Pls help bro my grade depends on y’all

Pls help bro my grade depends on yall

Answers

Answer:

No solution

Step-by-step explanation:

-2x + 3 + x > -x - 1

-2x + x + x > -1 - 3

0 > -4

There is no solution for this inequality

a polygon that is not regualr does not have any symmetries. true or false.

Answers

Solution

For this case we have a non regular polygon

so then we can conclude that the answer is:

False

Since some polygons can have symmetry lines

The Drama Club sold 900 tickets to the school play. They charged $5.50 for students and $8.00 for non-students.

If they took in $5700, how many non-student tickets were sold?

Answers

Answer:

300 non student tickets were sold

Step-by-step explanation:

Let's solve the equation step by step,

In order to solve for how many non student tickets were sold, let's make an equation

5.50x + 8.00y = 5700 --------(equation 1)

x + y = 900 ---------------(equation 2)

Let's solve for x and y

5.5x+8y=5700;x+y=900

Rewrite equations:

x+y=900;5.5x+8y=5700

Step: Solve x+y=900 for x:

x+y=900

x+y+−y=900+−y(Add -y to both sides)

x=−y+900

Step: Substitute−y+900forxin5.5x+8y=5700:

5.5x+8y=5700

5.5(−y+900)+8y=5700

2.5y+4950=5700(Simplify both sides of the equation)

2.5y+4950+−4950=5700+−4950(Add -4950 to both sides)

2.5y=750

2.5y/2.5 = 750/2.5

(Divide both sides by 2.5)

y=300

Step: Substitute300foryinx=−y+900:

x=−y+900

x=−300+900

x=600(Simplify both sides of the equation)

Since y = 300 then 300 non student tickets were sold

Simplify 5 x times the square root of quantity 3 x end quantity minus 2 x times the square root of quantity 3 x end quantity minus x times the square root of quantity 3 x end quantity period. 3 x times the square root of quantity 6 x cubed 3 x times the square root of quantity 3 x end quantity 2 x times the square root of quantity 9 x end quantity 2 x times the square root of quantity 3 x end quantity

Answers

The given expression 5x√3x  -2x√3x - x√3x can be simplified as 2x √3x.

What is the Simplification of the given expression?

The given expression can be written as follows;

5x√3x  -2x√3x - x√3x

Collect similar terms together;

= 5x√3x  -2x√3x - x√3x

= (5x  -2x - x)√3x

Now, factorize the expression since they common roots

=  (5x  -2x - x)√3x

= 2x √3x

Thus, the given expression 5x√3x  -2x√3x - x√3x can be simplified as 2x √3x.

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Answer:

\(2x\sqrt{3x}\)

Step-by-step explanation:

took the test

Add: ( 2x^2 + 6x + 4) and ( 5x^2 - 5x + 10)

Answers

Answer:

7x² + x + 14

Step-by-step explanation:

(2x² + 6x + 4) + (5x² - 5x + 10)

Remove parentheses

2x² + 6x + 4 + 5x² - 5x + 10

Put like terms together.

2x² + 5x² + 6x - 5x + 4 + 10

Simplify.

7x² + x + 14

\(\frac{4\sqrt{3} - 12\sqrt{5} }{2\sqrt{3}+8\sqrt{5} } * \frac{2\sqrt{3} - 8\sqrt{5} }{2\sqrt{3} - 8\sqrt{5}}\)

Answers

Step-by-step explanation:

-18-2√15/11

Answer:

\((2\sqrt{15}-18)/11\)

Step-by-step explanation:

\((4\sqrt{3}-12\sqrt{5})/(2\sqrt{3}+8\sqrt{5})*(2\sqrt{3}-8\sqrt{5})/(2\sqrt{3}-8\sqrt{5}) =\)\((4\sqrt{3}-12\sqrt{5})(2\sqrt{3}-8\sqrt{5})/(2\sqrt{3}+8\sqrt{5})(2\sqrt{3}-8\sqrt{5})=\)\((8*3- 32\sqrt{15} -24\sqrt{15} +96*5)/(4*3-64*5)=\)\((24+480-56\sqrt{15})/(12-320)=\)\((504 - 56\sqrt{15})/(-308) =\)\((2\sqrt{15}-18)/11\)

What is (4.81 times 10 Superscript 16 Baseline) (1.1 times 10 Superscript negative 4 Baseline) in scientific notation?
5.291 times 10 Superscript negative 64
5.291 times 10 Superscript negative 4
5.291 times 10 Superscript 12
5.291 times 10 Superscript 20

Answers

The scientific notation of the product of the given numbers is \(5.291 \times 10^{12}\).

Given, \((4.81 \times 10^{16} ) (1.1 \times 10^{-4} )\).

We need to write the scientific notation of the product.

What is scientific notation?

Scientific notation is a way of expressing numbers that are too large or too small to be conveniently written in decimal form.

Now, \((4.81 \times 10^{16} ) (1.1 \times 10^{-4} )=4.81 \times 1.1 \times 10^{16} \times10^{-4}\)

\(=5.291 \times 10^{16-4} =5.291 \times 10^{12}\)

Hence, the scientific notation of the product of the given numbers is \(5.291 \times 10^{12}\).

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Answer:C

Step-by-step explanation:

5.291 times 10 Superscript 12

Find the zeros of the function f(x) = - 1.9x squared- 4.3x + 1

Answers

Answer:

x = sqrt(2609)/38 - 43/38 or x = -43/38 - sqrt(2609)/38

Step-by-step explanation:

Solve for x:

-1.9 x^2 - 4.3 x + 1 = 0

-1.9 x^2 - 4.3 x + 1 = -(19 x^2)/10 - (43 x)/10 + 1:

-(19 x^2)/10 - (43 x)/10 + 1 = 0

Multiply both sides by -10/19:

x^2 + (43 x)/19 - 10/19 = 0

Add 10/19 to both sides:

x^2 + (43 x)/19 = 10/19

Add 1849/1444 to both sides:

x^2 + (43 x)/19 + 1849/1444 = 2609/1444

Write the left hand side as a square:

(x + 43/38)^2 = 2609/1444

Take the square root of both sides:

x + 43/38 = sqrt(2609)/38 or x + 43/38 = -sqrt(2609)/38

Subtract 43/38 from both sides:

x = sqrt(2609)/38 - 43/38 or x + 43/38 = -sqrt(2609)/38

Subtract 43/38 from both sides:

Answer: x = sqrt(2609)/38 - 43/38 or x = -43/38 - sqrt(2609)/38

which of these is a unit rate?​

which of these is a unit rate?

Answers

Answer:

$5 for a case of soda

Step-by-step explanation:

I hope this helps! :)

Please I really need help!
It’s 10th grade Integrated Math ll
Given in the diagram:
ED = 7ft
m?BAE = 30°m?A
CB = 45°
m?ABE =

Please I really need help! Its 10th grade Integrated Math llGiven in the diagram: ED = 7ftm?BAE = 30m?ACB

Answers

Answer:

I AM STUCK ON THAT ONE TO!!!

Step-by-step explanation:

CAN SOMEONE PLZZZ HELP!!

please find the mean,median,mode, and range!!!

will give brainliest

please find the mean,median,mode, and range!!!will give brainliest

Answers

Answer:

Mean = 7

Median = 8

Mode = 3

Range = 9

Step-by-step explanation:

2. Approximate e?. Round your answer to the nearest tenth

2. Approximate e?. Round your answer to the nearest tenth

Answers

Answer:

1096.6

Step-by-step explanation:

The answer would be 1096.63316, but since you are rounding to the nearest tenth, then your answer would be 1096.6.

Answer:

1096.6.

Step-by-step explanation:

e = about 2.7

2.7^7is about 1046

Enter the value that belongs in the
green box.
53
у
34
37°
Х
[?]
cos 53°

Enter the value that belongs in thegreen box.533437[?]cos 53

Answers

Answer:

Sorry, I made a mistake

\(cos53° = \frac{y}{34} \)

cos53°=Adjacent / hypotenuse

Answer:

the answer is 20.46 or 20.5

Step-by-step explanation:

i hope this helps

suppose that the population of all north american domesticated cats have a mean weight of 12 pounds and standard deviation of 2.5 pounds. the frequency distribution of north american domesticated cat weights is approximately normal. about 95% of the mean weights from samples of size 100 cats from this population fall between what two values (note: assume the sampling distribution of sample means is approximately normal)?

Answers

Answer. The correct option is (E). 9.5 and 14.5

Explanation for step 1This is because 95% of the mean weights from samples of size 100 cats from this population will fall between 9.5 and 14.5 pounds. The other answers are incorrect because they do not fall within the range of 95% of the mean weights from samples of size 100 cats from this population

About 95% of the mean weights from samples of size 100 cats from this population would fall between approximately 11.51 pounds and 12.49 pounds.

To determine the range within which 95% of the mean weights from samples of size 100 cats would fall, we can use the concept of the confidence interval.

Given:

Population mean weight (μ) = 12 pounds

Population standard deviation (σ) = 2.5 pounds

Sample size (n) = 100 cats

Since the population distribution is assumed to be approximately normal, the sampling distribution of sample means will also be approximately normal. To calculate the range, we can use the formula for the confidence interval:

Confidence Interval = sample mean ± (z * standard error)

The standard error can be calculated using the formula:

Standard Error = σ / √n

Using a 95% confidence level, the corresponding z-value is approximately 1.96 (obtained from standard normal distribution table).

Plugging in the values:

Standard Error = 2.5 / √100 = 0.25

Confidence Interval = 12 ± (1.96 * 0.25)

Calculating the values:

Lower limit = 12 - (1.96 * 0.25) ≈ 11.51 pounds

Upper limit = 12 + (1.96 * 0.25) ≈ 12.49 pounds

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if m=5 and n=3, find the value of 2m-n

Answers

Answer:

7

Step-by-step explanation:

plug in m and n

m = 5

n = 3

so...

2(5) - (3)

10 - 3

7

Answer: 2 * m(10) - n(3) = 17

Step-by-step explanation:

2 times 10 gives you 20 and minus 3 would give you 17.

Hope this Helps! ;)

Given \( x(t)=4 \sin (40 \pi t)+2 \sin (100 \pi t)+\sin (200 \pi t), X(\omega) \) is the Fourier transform of \( x(t) \). Plot \( x(t) \) and the magnitude spectrum of \( X(\omega) \) Question 2 Given

Answers

For the given signal \(x(t) = 4\sin(40\pi t) + 2\sin(100\pi t) + \sin(200\pi t)\), we are asked to plot the time-domain signal \(x(t)\) and the magnitude spectrum of its Fourier transform \(X(\omega)\).

To plot the time-domain signal \(x(t)\), we can calculate the values of the signal for different time instances and plot them on a graph. Since the signal is a sum of sinusoidal components with different frequencies, the plot will show the variations of the signal over time. The amplitude of each sinusoidal component determines the height of the corresponding waveform in the plot.

To plot the magnitude spectrum of the Fourier transform \(X(\omega)\), we need to calculate the Fourier transform of \(x(t)\). The Fourier transform will provide us with the frequency content of the signal. The magnitude spectrum plot will show the amplitude of each frequency component present in the signal. The height of each peak in the plot corresponds to the magnitude of the corresponding frequency component.

By plotting both \(x(t)\) and the magnitude spectrum of \(X(\omega)\), we can visually analyze the signal in both the time domain and the frequency domain. The time-domain plot represents the signal's behavior over time, while the magnitude spectrum plot reveals the frequency components and their amplitudes. This allows us to understand the signal's characteristics and frequency content.

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Please helpppp please I will mark branlyist and 50 point please Question 13 (5 points)
(02.02 MC)
Which of the following rational numbers is equal to 34 ? (5 points)
32
33
34
31
9
9
9
1) 31
9
2) 32
9
3) 33
9
4) 34
9

Please helpppp please I will mark branlyist and 50 point please Question 13 (5 points)(02.02 MC)Which

Answers

Question:

Which of the following rational number is equal to 3,4?

Answer:

31

9

Step-by-step explanation:

That's my opinion and I hope it helps^_^

#CARRYONLEARNING #STUDYWELL

Given that Justin is collecting data on reaction time, what type of data is he working with?
Select the correct answer below:
A. qualitative
B. discrete quantitative
C. continuous quantitative
D. none of the above

Answers

Since reaction time is measured and not constrained to a specific range of numbers, it is continuous quantitative data.

'What is continuous quantitative?'

A continuous data set is a quantitative data set that represents a scale of measurement that includes fractions and decimals in addition to whole integers. Values like height, weight, length, temperature, and other similar metrics would be included in continuous data sets. They are items that can be quantified in decimals and fractions. A continuous data set typically requires the use of a tool, such as a ruler, measuring tape, scale, or thermometer, to create the numbers.

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Find the slope of the line through the pair of points. D(3, 5), J(8, 7)


20 POINTS

Answers

Answer:

2/5

Step-by-step explanation:

slope= y2-y1 / x2-x1

in this case:

y2=7                            y1=5                      x2= 8                      x1=3

plug that into the formula above to get the answer

slope= 2/5 or 0.4

If the arithmetic mean of the numbers 7, 14, 6, p, 8 and 14 is 10, find p.​

Answers

Answer:

Step-by-step explanation:

Solution,

Here

Mean=10

N=6

Efx=7+14+6+p+8+14

=49+p

Now

Mean=Efx/N

or,10=49+p/6 ( Therefore,10 is multiplied to 6)

or,60=49+p

or,p=60-49

p=11

Simplify.
-4x² + 7x²

Answers

Answer:

3x^2

Step-by-step explanation:

-4x^2 + 7x^2 = 7x^2 - 4x^2 = x^2 * (7 - 4) = x^2 * 3 = 3x^2

Answer:

3x^2

Step-by-step explanation:

-4x^2 +7x^2

You simply just have to add them because they have the same root and are both cubed as well as the same variable "x".

The distance from Alison's house to the mailbox is 2 5 mile. The distance from the mailbox to the bus stop is 1 3 mile. What is the total distance from Alison's house to the bus stop?.

Answers

The total distance from Alison's house to the bus stop is 3.8 miles.

To find the total distance from Alison's house to the bus stop, we need to add the distance from her house to the mailbox and the distance from the mailbox to the bus stop.

Given:

Distance from Alison's house to the mailbox = 2.5 miles

Distance from the mailbox to the bus stop = 1.3 miles

Total distance = Distance from Alison's house to the mailbox + Distance from the mailbox to the bus stop

Total distance = 2.5 miles + 1.3 miles

Total distance = 3.8 miles

Therefore, the total distance from Alison's house to the bus stop is 3.8 miles.

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The area A of the minor sector OAC shown below is 180pi cm2. The original circle had a center at O and a radius R measuring 30 cm.


Find the value of ANGLE , the measure of the angle /_AOC.


Give your answer in radians in terms of Pi.

Answers

The measure of angle AOC is 2π radians. To answer the question, we need to use the formula for the area of a sector, which is A = (θ/360)πR^2, where A is the area of the sector, θ is the angle of the sector (in degrees), and R is the radius of the circle.



In this case, we know that the area of the minor sector OAC is 180π cm^2 and the radius of the circle is 30 cm. So, we can plug these values into the formula and solve for the angle θ:
180π = (θ/360)π(30)^2
180 = (θ/360)(900)
θ/2 = 180
θ = 360


The value of ANGLE, the measure of the angle /_AOC, is 2π radians (in terms of Pi) and it can be found using the formula A = (θ/360)πR^2, where A is the area of the sector, θ is the angle of the sector (in degrees), and R is the radius of the circle. The area A of the minor sector OAC is 180π cm², and the radius R of the original circle is 30 cm. To find the measure of angle AOC, we can use the formula for the area of a sector: Area = (1/2) × (radius²) × (angle in radians)
We know the area and radius, so we can plug in the values and solve for the angle in radians:
180π = (1/2) × (30²) × (angle in radians)
To find the angle, follow these three steps:
1. Divide both sides of the equation by (1/2) × (30²): (180π) / ((1/2) × (30²)) = angle in radians
2. Simplify the equation: (180π) / (450) = angle in radians
3. Solve for the angle in radians: (2π) = angle in radians

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12
Calculate the area of the given segment. Round your answer to the nearest tenth, if necessary.
60
8 in.

12Calculate the area of the given segment. Round your answer to the nearest tenth, if necessary.608 in.

Answers

Check the picture below.

\(\textit{area of a segment of a circle}\\\\ A=\cfrac{r^2}{2}\left( ~~ \cfrac{\pi \theta }{180}-\sin(\theta ) ~~ \right) \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=8\\ \theta =60 \end{cases} \\\\\\ A=\cfrac{8^2}{2}\left( ~~ \cfrac{\pi (60) }{180}-\sin(60^o ) ~~ \right)\implies A=32\left( ~~ \cfrac{\pi }{3}-\sin(60^o ) ~~ \right) \\\\\\ A=32\left( ~~ \cfrac{\pi }{3}-\cfrac{\sqrt{3}}{2} ~~ \right)\implies A=\cfrac{32\pi }{3}-16\sqrt{3}\implies A\approx 5.8~in^2\)

12Calculate the area of the given segment. Round your answer to the nearest tenth, if necessary.608 in.
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