I don’t even understand anyone help please.

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Answer:25N/

Explanation:

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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The gravitational potential energy of the two climbers would be 26,460 J.

The gravitational potential energy (PE) of an object is given by the formula:

PE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.

In this case, the combined mass of the two climbers is 150 kg, and they are 18 m above the ground. Using g = 9.8 m/s², we can calculate their gravitational potential energy as:

PE = (150 kg) x (9.8 m/s²) x (18 m) = 26,460 J

Rounded to the nearest thousand, the gravitational potential energy of the two climbers is 26,000 J.

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The spontaneous drying of leaves occurs due to the loss of moisture through evaporation, primarily facilitated by transpiration and environmental factors such as temperature, humidity, and airflow. Aging and senescence also contribute to the process.

The spontaneous process of drying leaves, also known as desiccation, is a natural occurrence that takes place as a result of various factors. Primarily, it involves the loss of moisture from the leaf tissues through evaporation. Leaves have specialized structures called stomata, small openings on their surfaces, which facilitate the exchange of gases, including water vapor.

When environmental conditions such as high temperature, low humidity, and increased airflow prevail, water molecules escape through the stomata into the surrounding air. This process, called transpiration, plays a significant role in leaf drying. Additionally, sunlight accelerates the rate of evaporation by providing energy to convert water into vapor.

As moisture content decreases, the cell walls of the leaf tissues contract, causing the leaf to become dehydrated and eventually dry. The process is also influenced by the plant's natural aging and senescence, where the leaf undergoes programmed cell death.

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Answer:

which items are matter?

battery , mobile phone

The intrepid hero has done 2.332 x\(10^6\) Joules of work in pushing the crate.

To ascertain the work done by the traveler, we first need to find the power he applied on the case. As per Newton's subsequent regulation, force is equivalent to mass times speed increase, so the power applied by the traveler on the container is:

Force = mass x speed increase

Force = 220 kg x 2 \(m/s^2\) = 440 N

Then, we really want to work out the distance the case was moved. The pilgrim pushed the box a distance of 5.3 km, or 5,300 m.

At long last, we can compute the work done by the pioneer utilizing the equation:

Work = force x distance

Work = 440 N x 5,300 m

Work = \(2.332 x 10^6\) Joules

Thusly, the valiant legend has done 2.332 x \(10^6\) Joules of work in pushing the case.

The space pilgrim takes care of business on the case by applying a power that makes it speed up. The work done is equivalent to the power duplicated by the distance over which the power is applied. Involving the recipe for force, F=ma, and the given qualities for mass and speed increase, we can ascertain the power applied. Then, at that point, involving the recipe for work, W=Fd, and the given distance, we can ascertain the work done. The work done by the adventurer is 2.332 x \(10^6\) J.

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Answer:

2.4 m/s". 1

Explanation:

A jet with mass m = 8 x 10* kg jet accelerates down the runway for takeoff at 2.4 m/s". 1

Answer:

Resistance = 2.2 Ohms.

Explanation:

Given the following data;

Resistivity, P = 0.25

Length, L = 11.2

Area, A = 1.26

To find the resistance.

Resistance is given by the formula below;

Resistance = PL/A

Substituting into the equation, we have;

Resistance = (0.25*11.2)1.26

Resistance = 2.8/1.26

Resistance = 2.2 Ohms.

Therefore, the resistance of the wire is 2.2 Ohms.

The final velocities of the car and truck just after the collision will be as per the conservation of momentum.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].

According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.

if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.

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The gravitational field strength at Pluto's surface is 5.827 x 10⁹ N/kg.

The force of gravity between the object and Pluto's surface is 5.827 x 10¹³ N.

The gravitational field strength at Pluto's surface is calculated as follows;

G_E = GM/r²

where;

G_E = (6.67 x 10⁻¹¹ x 1.2 x 10²²) / (1.172 x10)²

G_E = 5.827 x 10⁹ N/kg

The force of gravity between the object and Pluto's surface is calculated as follows;

F = GMm/r²

F = (6.67 x 10⁻¹¹ x 1.2 x 10²² x 100) /(1.172 x 10)²

F = 5.827 x 10¹³ N

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Answer:

5866.9 kg

Explanation:

We can use the conservation of momentum to solve this problem. The momentum of the rocket and fuel system is conserved, so:

Initial momentum = Final momentum

The initial momentum of the system is zero since the rocket is at rest initially. The final momentum is the momentum of the rocket after burning the fuel. We can find the final momentum using the rocket equation:

Δv = ve * ln(m0 / mf)

where Δv is the change in velocity (100 m/s), ve is the exhaust speed (1500 m/s), m0 is the initial mass of the rocket and fuel system (what we want to find), and mf is the final mass of the rocket and fuel system (m0 - 100 kg).

Solving for m0, we get:

m0 = mf * exp(Δv / ve) = (m0 - 100 kg) * exp(100 / 1500)

Simplifying this equation, we get:

m0 = 100 kg / (1 - exp(100 / 1500))

m0 = 5866.9 kg (rounded to four significant figures)

Therefore, the initial mass of the rocket and fuel system was approximately 5866.9 kg.

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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Any object under free fall accelerates at a constant rate given by the gravitational acceleration:

On the other hand, the speed v of an object under free fall after t seconds, if it starts from rest, is given by the formula:

Replace g=9.81m/s^2 and t=5s to find the speed of the object 5 seconds after the object is dropped:

Therefore, the speed of the object after 5 seconds is approximately 49 meters per second. Its acceleration is always the same and it is equal to 9.81 meters per second squared.

The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².

What is the moment of inertia?

This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².

From the question:

Mass,M =4.2kg

Radius, R=32Cm

The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:

moment of inertia, I =1/2MR²

I =\(\frac{1}{2}\) * 4.2 * 32²

  =2,150.4 kgm²

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Answer:

The correct answer is 0.022

Divide the volume value by 1000

22 divided by 1,000 = 0.022

Explanation:

Hope this helps!! :))

Answer:

true

Explanation:

Answer:

The correct answer is T (True).

Explanation:

Answer: 25230800 Joules

Explanation: We can treat the copper tank and the water inside as two different objects since they have different specific heats. We will utilize Q=Mcdelta(t) in this problem where M is mass, c is specific heat, and delta t is the change in temperature.

Since we are treating the copper and water separately we can make a Mcdelta(t) for each one of them. This gives us Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t)). The delta t will be the same because both the copper and water are at 15 celsius. Now we just do some calculations.

Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t))

Q=(20)(385)(55-15)+(150)(4200)(55-15)

Q=30800+25200000

Q=25230800 J

This number may seem absurdly high but there is 150 kg of water being heated up which is 150 liters(A LOT!).

Hope this helps!

it increases and gets louder

and it amplifies the noise

Answer:

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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Answer:

a) the velocity increases then decreases.

Answer:

In parts 1 and 3 the energy

In part 2  moment.  inelastic

conserved

Explanation:

In this exercise, we are asked to describe the conservation processes for each part of the exercise.

In parts 1 and 3 the energy is conserved since the bodies do not change

In part 2 the bodies change since they are united therefore the moment is conserved and part of the kinetic energy is converted into potential energy.

Energy

moment   .inelastic

conserved

The two balls swing up together just after the collision to their highest point. energy is conserved.

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

According to the law of conservation of momentum

Momentum before collision =Momentum after collision

When the first ball is released and just before it hits the stationary ball, The two balls collide, The two balls swing up together just after the collision to their highest point. energy is conserved.

The balls swing like pendulums. During the collision in part (2) energy is conserved as the collision is inelastic.

We are requested to describe the conservation methods for each element of the activity in this exercise.

Because the bodies do not change in sections 1 and 3, energy is conserved.

Because the bodies change in part 2 is joined, the moment is conserved and some of the kinetic energy is transformed into potential energy.

Hence the two balls swing up together just after the collision to their highest point. energy is conserved.

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The density of the liquid in the drum is 459.184 kg/m³.

To find the density of a liquid, we must know its pressure, the depth to which it is filled, and the gravitational acceleration acting on it. Using the equation for pressure at a depth h below the surface of a liquid in a container of height H, P = ρgh, where P is the pressure, ρ is the density, g is the gravitational acceleration, h is the height of the liquid, and H is the height of the container.Let's substitute the given values in the above formula:P = 9000800 Pa; h = 2m; g = 9.8m/s²Therefore, ρ = P/gh = 9000800/(9.8 × 2) ≈ 459184.

This means that the density of the liquid in the drum is 459.184 kg/m³ (kilograms per cubic meter).

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Answer:

A 1000 kg truck moving at 2.0 m/s runs into a concrete wall. It takes 0.5 s for the truck to completely stop. What is the magnitude of force exerted on the truck during the collision?

Since [1 + 2] = [1] + [2], the Velocity of the constant 1 and 2 must be the same. Therefore, both constants have the same SI units.

V is the velocity, d is the distance, and t is the duration in the equation V = d/t. Calculate the object's acceleration by dividing its mass by its force, then multiplying the result by the acceleration's duration.

(b) The units of the constants 1 and 2 must be the same because [12 / 12] = 1. As a result, the SI units for both variables are the same.

(c) The units of the constant 2 must be the same as the units of the constant 1 squared because [2] = [2] / [1]. As a result, the SI units for the constants 1 and 2 differ.

(d) The constant 2 must have radians as its units because the cosine function's input must be dimensionless. It is necessary for the constant 1 to have units that enable the cosine function's units to cancel out. This can be done by assigning the constant 1 units that are reciprocal radians, or radians to the power of -1. As a result, the SI units for the constants 1 and 2 are rad-1 and radians, respectively.

Due to the fact that [(2 / 1) - (2)2] equals [(2 / 1)], The units of the constant 2 must match those of the constant 1 cubed, or [22]. As a result, the SI units for the constants 1 and 2 differ.

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