I don’t know how to do this I need help plzzz

The inequality of (2x1)2x5x4x can be solved by determining that x>0.

In mathematics, a statement of the order connection between two integers equivalent algebraic expressions that is greater than, equal to or greater to, less than, or lower than or equal to is referred to as an inequality.

(2x−1)2x−5x<4x +2−x

To multiply 2x-1 by 2, use the distributive property.

(4x−2)x−5x<4x + 2 −x

multiplying 4x-2 to x using the distributive property.

4x + 2 −2x−5x<4x + 2 −x

-2x and -5x together provide 7x.

4x + 2 −7x<4x + 2 −x

Subtract 4x + 2 by both sides.

4x + 2 −7x−4x + 2 <−x

Combine 4x + 2 and −4x + 2 to obtain 0.

−7x<−x To both sides, add x.

−7x+x<0

7x and x together yield 6x.

−6x<0

The product is 0 if any of the two numbers in it is greater than 0 and the other is 0 as well. 6 > 0, indicating that x would have to be greater than 0.

x>0

The Inequality of (2x−1)2x−5x<4x is x>0

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Step-by-step explanation:

\(196\pi\)

is the answer

plz mark as brainliest

This indicates that the Australian dollar appreciated by 5.80%. the correct answer is (a) appreciated; 5.80.

To determine whether the Australian dollar appreciated or depreciated and by what percentage, we can calculate the percentage change in value between today and yesterday.

The formula for calculating the percentage change is:

Percentage Change = (New Value - Old Value) / Old Value * 100

Using this formula, we can calculate the percentage change:

Percentage Change = (0.73 - 0.69) / 0.69 * 100

Percentage Change = 0.04 / 0.69 * 100

Percentage Change ≈ 5.80

The percentage change is approximately 5.80%. This indicates that the Australian dollar appreciated by 5.80%.

Therefore, the correct answer is (a) appreciated; 5.80.

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Chord [a straight line segment that joins two points on the circumference of a circle]

Tangent [a straight line that touches a circle or sphere at a single point]

Secant [a straight line that intersects a circle at two points]

Diameter [a straight line passing through the center of a circle and connecting two points on the circumference]

In geometry, there are several terms related to circles, such as chord, tangent, secant, and diameter. Here are their definitions:

Chord: A chord is a line segment connecting any two points on the circumference of a circle. It is the longest segment that can be drawn inside a circle.

Tangent: A tangent is a line that touches the circumference of a circle at only one point, called the point of tangency. It is perpendicular to the radius at the point of tangency.

Secant: A secant is a line that intersects a circle at two points. It can be a line that passes through the center of the circle, in which case it is the diameter of the circle.

Diameter: The diameter is the longest chord of a circle, and it passes through the center of the circle. It is twice the length of the radius.

Understanding these terms is important in solving problems related to circles and their properties. For example, in finding the length of an arc or the area of a sector, we need to know the chord or diameter of the circle, and the angle or central angle subtended by the arc or sector. In constructing tangents to circles, we need to know the point of tangency and the radius or diameter of the circle.

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Answer:

97.75

Step-by-step explanation:

15% of 85 is  12.75

12.75 + 85 = 97.75

Hope this helps have a nice day

Answer:

Step-by-step explanation:

Solving systems of equations gives the points of intersection when the equations are graphed.

The answer is 3.

Therefore, in either partial derivatives, we have u = 0 or v = 0.

The given information implies that two vectors u and v satisfy:

u * v = 0, where * denotes the dot product between vectors.

u X v = 0, where X denotes the cross product between vectors.

From the first equation, we know that the angle between u and v is either 90 degrees or 270 degrees. That is, u and v are orthogonal (perpendicular) to each other.

From the second equation, we know that the magnitude of the cross product u X v is equal to the product of the magnitudes of u and v multiplied by the sine of the angle between them. Since u and v are orthogonal, the angle between them is either 90 degrees or 270 degrees, which means that the sine of the angle is either 1 or -1. Therefore, we have:

|u X v| = |u| * |v| * sin(θ)

= 0

Since the magnitudes of u and v are non-negative, it follows that sin(θ) must be zero. This can only happen if the angle between u and v is either 0 degrees (i.e., u and v are parallel) or 180 degrees (i.e., u and v are anti-parallel).

In the case where u and v are parallel, we have:

u * v = |u| * |v| * cos(θ)

= |u|²

= 0

This implies that |u| = 0, which means that u = 0.

In the case where u and v are anti-parallel, we have:

u * v = |u| * |v| * cos(θ)

= -|u|²

= 0

This again implies that |u| = 0, which means that u = 0.

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\( = \frac{ - 3}{4} (p) - \frac{3}{4} ( - 12) + 2(8) + 2( - \frac{1}{4} p) \\ = - \frac{3}{4} p + 9 + 16 - \frac{2}{4} p \\ \\ = - \frac{3}{4} p - \frac{2}{4}p + 9 + 16 \\ = - \frac{5}{4} p + 25\)

ATTACHED IS THE SOLUTION

Answer:

\(-1\frac{1}{4}+25\)

Step-by-step explanation:

first distribute

(-3/4)(p) -(-3/4)(12)

-3/4p+36/4

-3/4p+9

2(8) - 2(1/4p)

16-2/4p

-3/4p+9+16-2/4p

Combines like terms

-5/4p+25

\(-1\frac{1}{4}+25\)

Hopes this helps please mark brainliest

The given points are

These are complex numbers. They work as two-coordinates points because complex numbers have a real part and a complex part. The real part is the horizontal coordinate, and the complex part is the vertical coordinate.

To find the midpoint, we use the following formula

The probability that a randomly selected call time will be less than 30 seconds is approximately 0.7445.

The problem involves exponential distribution which is a standard continuous distribution. The probability density function of this distribution is given by -

f(x) = θe^(-θx) ; where θ is a parameter and characteristic of the distribution, x is the random variable.

Also, the mean for an exponential distribution is given by u = 1/θ .

In the question it is 22 seconds.

So, the value of θ is 1/22.

Now, we have to find P(X<30) where X is the random variable denoting the calling time in seconds.

P(X<30) is nothing but F(x) at x = 30 seconds, i.e. cumulative distribution function. For an exponential distribution , F(X) is given by -

P(X<x)= F(X) = 1- e^(-θ x) , where x>0.

Putting θ = 1/22 and x= 30 in F(X) , we get -

F(X) = 1-e[(-1/22)30] = 1- 0.2555 = 0.7445 which is P(X<x) = P(X<30) = 0.7445.

So, the probability that a randomly selected call time will be less than 30 seconds is approximately 0.7445.

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The probability that a randomly selected call time will be less than 30 seconds is approximately 0.7445.

The problem involves exponential distribution which is a standard continuous distribution. The probability density function of this distribution is given by -

f(x) = θe^(-θx) ; where θ is a parameter and characteristic of the distribution, x is the random variable.

Also, the mean for an exponential distribution is given by u = 1/θ.

In the question, it is 22 seconds.

So, the value of θ is 1/22.

Now, we have to find P(X<30) where X is the random variable denoting the calling time in seconds.

P(X<30) is nothing but F(x) at x = 30 seconds, i.e. cumulative distribution function. For an exponential distribution , F(X) is given by -

P(X<x)= F(X) = 1- e^(-θ x) , where x>0.

Putting θ = 1/22 and x= 30 in F(X) , we get -

F(X) = 1-e[(-1/22)30] = 1- 0.2555 = 0.7445 which is P(X<x) = P(X<30) = 0.7445.

So, the probability that a randomly selected call time will be less than 30 seconds is approximately 0.7445.

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Answer:

1.4 (rounded to the nearest tenth)

1.43 (rounded to the nearest hundredths)

1.432 (rounded to the nearest thousandths)

Step-by-step explanation:

C=2 π r

C/2 π = 9/2 * π = (depends what is is rounded to really)

Answer:

1^13 and 1^15

Step-by-step explanation:

1 raised to anything is still just 1

so, 1^13 = 1 and 1^15 =1

Answer:

13=3/4x

3/4 of fabric=$6

Step-by-step explanation:

Answer:

n=10/k - x/k

Step-by-step explanation:

Hope this helps

Answer:

n = (10 - x) / k

Step-by-step explanation:

nk + x = 10

nk = 10 - x

n = (10 - x) / k

The time-series model that assumes that demand in the next period will be equal to the most recent period's demand is A) Naive approach.

This model is based on the simplest assumption of all, that the next period's demand will be equal to the current period's demand. It is called the naive approach because it assumes no underlying pattern in the data and provides a baseline prediction. The formula for the naive approach is as follows:

y(t) = y(t-1) where y(t) represents the demand in period t and y(t-1) represents the demand in the previous period.

Although this model is simple, it is often used as a benchmark for comparison with more complex models and can provide reasonable results for stable demand patterns.

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The probability that if you choose 2 people randomly, exactly one will need an x-ray is 0.4.

The probability that if you choose 2 people randomly from the 16 in the hospital, exactly one will need an x-ray is as follows:
Firstly, calculate the probability of choosing one person who needs an X-ray and one person who doesn't.

There are 4 people who need an x-ray and 12 who don't, so the probability for this is (4/16) * (12/15).

Now, calculate the probability of choosing one person who doesn't need an X-ray and one person who does. This is (12/16) * (4/15).

Now, add the probabilities to find the total probability.

The probability that exactly one person will need an x-ray is

(4/16) * (12/15) + (12/16) * (4/15) = 2/5

=0.4.

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The probability that if you choose 2 people randomly, exactly one will need an x-ray is 0.4 or 40%.

If there are 16 people in a hospital and 4 need an xray, the probability that if you choose 2 people randomly, exactly one will need an xray is 0.56.

Total number of people in a hospital = 16

Number of people who need an x-ray = 4

Thus, the probability that if you choose 2 people randomly, exactly one will need an x-ray is given by;

P(one needs an x-ray) = (Number of people who need an x-ray × Number of people who do not need an x-ray) / Total number of people × Total number of people - 1

P(one needs an x-ray) = (4 × 12) / 16 × 15

P(one needs an x-ray) = 0.08

P(one doesn't need an x-ray) = (Number of people who need an x-ray × Number of people who do not need an x-ray) / Total number of people × Total number of people - 1

P(one doesn't need an x-ray) = (12 × 4) / 16 × 15

P(one doesn't need an x-ray) = 0.32

Now, we have to add both the probabilities of exactly one person needing an x-ray and exactly one person not needing an x-ray;

P(exactly one person needs an x-ray) = P(one needs an x-ray) + P(one doesn't need an x-ray)

P(exactly one person needs an x-ray) = 0.08 + 0.32P(exactly one person needs an x-ray) = 0.4

The probability that if you choose 2 people randomly, exactly one will need an x-ray is 0.4 or 40%.

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A convex set is a set in which a line segment connecting any two points in the set is entirely included in the set. This implies that if two consumption bundles are chosen, then all consumption bundles on the line segment between them are also chosen.

We assume that the preference ordering is convex and the representation of utility functions u1 and u2 is given over the consumption bundle space R2+. Therefore, we must investigate whether the function v(x1, x2) = min{u1(x1, x2), u2(x1, x2)} is a convex preference ordering. We must show that for any x, y ∈ R2+, and any 0 ≤ t ≤ 1, the following inequality holds: v(tx + (1 − t)y) ≤ tv(x) + (1 − t)v(y).

We need to prove that v(x1,y1) ≤ tv(x1,x2)+(1−t)v(y1,y2) is satisfied for every x, y ∈ R2+, and any 0 ≤ t ≤ 1.
It is true because, given that u1 and u2 are convex preference orderings, the minimum of the two utility functions is also convex. We use the definition of a convex set to prove this. Given two consumption bundles, if the minimum utility function is selected, all consumption bundles lying on the line segment between them will be selected.

(b) Define the function w: R2+ → R by w(x1,x2)=u1(x1,x2)+u2(x1,x2). We need to prove that the preference ordering represented by the utility function w is convex. We must show that for any x, y ∈ R2+, and any 0 ≤ t ≤ 1, the following inequality holds: w(tx + (1 − t)y) ≤ tw(x) + (1 − t)w(y).

The inequality can be simplified to the following:

u1(tx1 + (1 − t)y1, tx2 + (1 − t)y2) + u2(tx1 + (1 − t)y1, tx2 + (1 − t)y2) ≤ tu1(x1,x2) + (1 − t)u1(y1,y2) + tu2(x1,x2) + (1 − t)u2(y1,y2).

It can be seen that since u1 and u2 are convex, u1(tx1 + (1 − t)y1, tx2 + (1 − t)y2) ≤ tu1(x1,x2) + (1 − t)u1(y1,y2) and u2(tx1 + (1 − t)y1, tx2 + (1 − t)y2) ≤ tu2(x1,x2) + (1 − t)u2(y1,y2).

Therefore, w(tx + (1 − t)y) = u1(tx1 + (1 − t)y1, tx2 + (1 − t)y2) + u2(tx1 + (1 − t)y1, tx2 + (1 − t)y2) ≤ tu1(x1,x2) + (1 − t)u1(y1,y2) + tu2(x1,x2) + (1 − t)u2(y1,y2)

= tw(x) + (1 − t)w(y). Thus, the preference ordering represented by the utility function w is convex.

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Number of boys in Mandy’s science class is 5.

Now, According to the question:

The ratio of boys to girls in Mandy’s mathematics class is 3 to 12.

This ratio is the same in Mandy’s science class,

There are 20 girls.

To find the how many boys are there in Mandy’s science class?

Based on the given condition:

Let the ratio be 3x and 12x

Now, According to the statement:

12x = 20

x = 20/12

x = 5/3

So, Number of boys = 3 × 5/3 = 5

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Answer:

Step-by-step explanation:

The slope formula is used to calculate the slope if you are given two points. Remember that slope is defined as rise/run. Which translates to the rise divided by the run. The slope formula will allow us to take the change in the rise and divide by the change in the run.

Answer:

I know that A is one of the answers.

Answer:

Step-by-step explanation:

As you move from left to right along the graph, each y-value gets larger and larger.  Therefore the y value is always increasing.  The correct answer is D.

Answer:

1.00 * 10^-2

Step-by-step explanation:

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a) Activity that should be crashed first to reduce the project duration by 1 day is B.

b) Activity that should be crashed next to reduce the project duration by one additional day is C.

c) Total cost of crashing the project by 2 days = $10,000.

To determine the activities that should be crashed first and next, we need to consider the critical path method (CPM). The critical path is the longest sequence of activities that determines the total project duration. Crashing activities on the critical path will reduce the project duration.

Let's calculate the project duration and costs for each activity:

Activity A:

Normal Time: 7 days

Crash Time: 6 days

Normal Cost: $5000

Total Cost with Crashing: $5600

Activity B:

Normal Time: 4 days

Crash Time: 2 days

Normal Cost: $1500

Total Cost with Crashing: $3400

Immediate Predecessor(s): A

Activity C:

Normal Time: 11 days

Crash Time: 9 days

Normal Cost: $4200

Total Cost with Crashing: $6600

Immediate Predecessor(s): B

To find the critical path, we add the normal times of each activity:

Critical Path: A -> B -> C

a) Activity that should be crashed first to reduce the project duration by 1 day:

Since the critical path includes activities A, B, and C, we need to identify which activity's crash time can reduce the project duration by 1 day. The activity that can achieve this is B since its crash time is 2 days compared to activity A's crash time of 6 days. Therefore, activity B should be crashed first.

b) Activity that should be crashed next to reduce the project duration by one additional day:

After crashing activity B, the project duration will be reduced by 1 day. To further reduce the duration by an additional day, we need to determine which activity's crash time can achieve this. The activity that can achieve this is C since its crash time is 9 days compared to activity A's crash time of 6 days. Therefore, activity C should be crashed next.

c) Total cost of crashing the project by 2 days:

The total cost of crashing the project by 2 days is the sum of the total costs for the crashed activities:

Total cost of crashing = Total cost of crashing activity B + Total cost of crashing activity C

                   = $3400 + $6600

                   = $10,000

Therefore, the total cost of crashing the project by 2 days is $10,000.

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Complete Question:

Three activities are candidates for crashing on a project network for a large computer installation (all are, of course, critical). Activity details are in the following table.

a) Activity that should be crashed first to reduce the project duration by 1 day is

b) Activity that should be crashed next to reduce the project duration by one additional day is

c) Total cost of crashing the project by 2 days =

To perform saturating arithmetic on unsigned 8-bit integers, we need to ensure that the result remains within the valid range of 0 to 255.

To calculate the sum of 151 and 214 using saturating arithmetic, follow these steps:

Add the two numbers:

151 + 214 = 365

Check if the result exceeds the maximum value of an 8-bit unsigned integer (255).

Since 365 is greater than 255, we need to saturate the result.

Set the result to the maximum value (255) to ensure it remains within the valid range.

Therefore, the result of 151 + 214 using saturating arithmetic is 255.

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The conversion of 22 kg to lbs is 48.50164 lbs.

Kilogram (kg) and pound (lbs) are both units of mass or weight.

Kilogram is the base unit of mass in the International System of Units (SI). It is defined as the mass of the International Prototype of the Kilogram (IPK), a platinum-iridium cylinder kept at the International Bureau of Weights and Measures.

To convert 22 kilograms (kg) to pounds (lbs), we can use the conversion factor of 1 kg = 2.20462 lbs.

So, we can multiply 22 kg by 2.20462 lbs/kg to get the equivalent weight in pounds:

22 kg × 2.20462 lbs/kg = 48.50164 lbs (rounded to five decimal places)

Therefore, 22 kg is approximately equal to 48.50164 lbs.

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Answer:

to show the changes in private school enrollment