I don’t know what to do

The mean total repair cost is $100, and the variance of the total repair cost is $1500.

The total repair cost is a random variable that depends on the number of defective machines selected. This is a hypergeometric distribution problem.

In a hypergeometric distribution, the probability mass function is given by:

P(X = k) = [C(K, k) x C(N-K, n-k)] / C(N, n)

Therefore, the mean and variance of X are:

E[X] = n x (K/N) = 5 x (4/10)

= 2

Var [X] = n x (K/N)(1-K/N)[(N-n)/(N-1)]

= 5x (4/10)(1 - 4/10)[(10 - 5)/(10 - 1)]

= 0.6

Since Y = 50X, we can find the mean and variance of Y by multiplying those of X by 50 and 50^2, respectively, because if Y = aX for some constant a, then:

E[Y] = aE[X] and Var[Y] = a ² x Var[X]

Therefore, the mean and variance of the total repair cost are:

E[Y] = 50E[X]

= 50 x 2

=  $100

Var[Y] = 50 ² Var[X]

= 25000 / 6

= $1500

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The approximate mean of the sampling distribution of sample means is 12 ounces

To find the mean of the sampling distribution of sample means, we need to use the formula

μM = μ

where μM is the mean of the sampling distribution of sample means, and μ is the population mean.

In this case, the population mean is 12 ounces. Since we are sampling 4 cups of coffee, the sample size is n = 4. The standard deviation of the sampling distribution of sample means can be calculated using the formula

σM = σ/√n

where σ is the population standard deviation.

Substituting the given values, we get:

σM = 2/√4 = 1

Therefore, the approximate mean of the sampling distribution of sample means is

μM = μ = 12 ounces

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Step-by-step explanation:

See the attached image.  I numbered angles differently so as not to make an assumption that angles numbered the same are congruent.

\(\overline{AB} \parallel \overline{CD}\\\angle1 \cong \angle3\) (alternate interior angles are congruent)

\(\overline{AD} \parallel \overline{BC}\\\angle 2 \cong \angle 4\) (alternate interior angles are congruent)

\(\overline{AB} \cong \overline{CD}\)  (opposite sides of a parallelogram are congruent)

\(\triangle{ABO \cong \triangle{CDO}\)  (ASA - side/angle/side)

\(\overline{AO} \cong \overline{CO}\\\overline{BO} \cong \overline{DO}\)  (corresponding parts of congruent triangles are congruent)

The diagonals bisect each other!

Answer:

Height is 8cm

Step-by-step explanation:

A= bxh

9.6 = 1.2 x h

÷1.2

8 = h

Check:

8 x 1.2= 9.6cm

Hope this helps!

Answer:

1/4 x 1/4 x 1/4

1/64

hope it helps

~Shoto Todoroki here~

Answer:

hope this helps :))

Molly earns $2 for every cup of coffee sold.

If Molly sells 1 cup of coffee, she earns $2.

If she sells 2 cups of coffee, she earns 2*$2 = $4

If she sells 10 cups of coffee, she earns 10*$2 = $20

Now let's say she sells x cups of coffee.

Following the same rule, the earns $2*x

Putting this as an expression:

E = 2x

Where E is the earnings, and x are the number of cups of coffee Molly sells

Answer:

Callie has 4 months to pay off the bill. The rational number is +4. The sign is positive because it represents a quantity of something, in this case, months

Step-by-step explanation:

trust me :)

Answer:

See attachment.

Step-by-step explanation:

On attachment.

The orthogonal basis for the subspace W is { -1, (0, sqrt(2y^2) + sqrt(6y^6))/(3sqrt(2y^2 + 6y^6)), (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3) }.

To apply the Gram-Schmidt Process to the given vectors, we will first normalize each vector to obtain a unit vector. Then, we will subtract the projection of each subsequent vector onto the previous vectors to obtain orthogonal vectors. Finally, we will normalize the orthogonal vectors to obtain an orthogonal basis for the subspace W.

Let's begin:

1. Normalize the first vector -3:

\(v1 = (-3)/sqrt((-3)^2) = (-3)/3 = -1\)

2. Normalize the second vector (0, sqrt(2y^2), sqrt(6y^6)):

\(v2 = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(0^2 + (sqrt(2y^2))^2 + (sqrt(6y^6))^2)\)

\(v2 = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(2y^2 + 6y^6)\)

3. Subtract the projection of v2 onto v1:

proj_v2_v1 = ((v2 . v1)/(v1 . v1)) * v1

where . represents the dot product

v2_orth = v2 - proj_v2_v1

v2_orth = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(2y^2 + 6y^6) - ((0 + sqrt(2y^2) + sqrt(6y^6))(-1/3))(-1)

v2_orth = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(2y^2 + 6y^6) + (sqrt(2y^2) + sqrt(6y^6))/3

4. Normalize the orthogonal vector v2_orth:

u2 = v2_orth/|v2_orth| = (0, sqrt(2y^2) + sqrt(6y^6))/(3sqrt(2y^2 + 6y^6))

5. Normalize the third vector (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6)):

v3 = (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6))/sqrt((sqrt(2)y^2)^2 + (sqrt(2)sqrt(6)y^6)^2 + (sqrt(2/6))^2)

v3 = (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3)

6. Subtract the projection of v3 onto v1 and v2:

proj_v3_v1 = ((v3 . v1)/(v1 . v1)) * v1

proj_v3_v2 = ((v3 . u2)/(u2 . u2)) * u2

v3_orth = v3 - proj_v3_v1 - proj_v3_v2

v3_orth = (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3) - (sqrt(2)y^2)(-1) - ((sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)))(sqrt(2) + sqrt(6))

v3_orth = (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3)

7. Normalize the orthogonal vector v3_orth:

u3 = v3_orth/|v3_orth| = (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3)

Therefore, the orthogonal basis for the subspace W is { -1, (0, sqrt(2y^2) + sqrt(6y^6))/(3sqrt(2y^2 + 6y^6)), (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3) }.

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Answer:

£ \(36\)

Step-by-step explanation:

In this situation, the price of an item is (£ \(45\)). It is given that there is a (\(\frac{1}{5}\)) off discount on this item. To find the price of this item, one will have to subtract the discount rate from (1), this will yield the fraction of the object price that one has to pay. To find the actual amount one has to pay, one must multiply the fractional price of the object by the original price of the object. Using this line of thought, one can form the following equation:

\((1-(rate\ of\ discount))(original\ price)=sale\ price\)

Substitute the given values into this equation:

\((1-\frac{1}{5})(45)=sale\ price\)

Simplify: remember, a fraction with any number over itself equals (1). Bear in mind that one can only perform operations such as addition and subtraction between fractions with common denominators, that is the number under the fraction bar.

\((1-\frac{1}{5})(45)=sale\ price\)

\((\frac{5}{5}-\frac{1}{5})(45)=sale\ price\)

\((\frac{5-1}{5})(45)=sale\ price\)

\((\frac{4}{5})(45)=sale\ price\)

Now perform the multiplication. Divide the denominator by the number one is multiplying by, then multiply it by the numerator (number over the fraction bar).

\((\frac{4}{5})(45)=sale\ price\)

\((4)(45 / 5)=sale\ price\)

\((4)(9)=sale\ price\)

\(36=sale\ price\)

Answer:

The answer is 36$

Step-by-step explanation:

Basically, the original price is 45 dollars, but with the extra 20% off (This is just the 1/5 off) it will be 36. This is because 45/5 equals 9 and 45-9 is 36.

Answer:

Alex = 19 years

Bart's = 15 years

Carl = 8 years

Step-by-step explanation:

Let us represent their ages as

Alex = x

Bart's = y

Carl = z

the sum of the ages of the three brothers is 42

x + y + z = 42

Alex his age is three more than twice Carl's age

x = 2z + 3

The difference between Barts in Carl's ages is seven years

y - z = 7

y = 7 + z

Hence: we Substitute

x + y + z = 42

2z + 3 + 7 + z + z = 42

Collect like terms

2z + z + z + 10 = 42

4z = 42 - 10

4z = 32

z = 32/4

z = 8 years

Hence, Carl = 8 years old

a) y = 7 + z

y = 7 + 8

y = 15 years.

Hence, Bart's is 15 years old

b)x = 2z + 3

x = 2(8) + 3

= 16 + 3

= 19 years

Therefore, Alex is 19 years old.

Answer:

40

Step-by-step explanation:

Answer:

Undefined

Explanation:

Anything over 0 is undefined

Answer:

I cannot understand your question

but if it's 29/0 then answer will be infinity. because anything divided by 0 is infinity.

Answer:

3 hours

Step-by-step explanation:

24/7 = 3.42 hours and rounded that will be 3 hours

In the absence of price discrimination, the profit-maximizing conditions would be different, and the resulting prices, quantities, total revenue, total cost, and profit would also be different.

To find the profit-maximizing conditions with third-degree price discrimination, we need to equate the marginal revenue (MR) to the marginal cost (MC) for each market segment.

Given the demand equations and the total cost function:

Market 1: Q1 = 160 - 10P1 or P1 = 16 - 0.1Q1

Market 2: Q2 = 200 - 20P2 or P2 = 10 - 0.05Q2

Total Cost: TC = 120 + 4Q

To find the profit-maximizing prices and quantities, we equate MR to MC for each market segment:

MR1 = MC:

16 - 0.2Q1 = 4

0.2Q1 = 12

Q1 = 60

MR2 = MC:

10 - 0.1Q2 = 4

0.1Q2 = 6

Q2 = 60

Substituting the quantities back into the demand equations, we find:

P1 = 16 - 0.1(60) = 10

P2 = 10 - 0.05(60) = 7

The total revenue (TR) can be calculated by multiplying the price by the quantity for each market segment:

TR = P1 * Q1 + P2 * Q2

TR = (10 * 60) + (7 * 60)

TR = 600 + 420

TR = 1020

The total cost (TC) is given by the total cost function:

TC = 120 + 4Q

TC = 120 + 4(60 + 60)

TC = 120 + 480

TC = 600

Finally, the profit (π) can be calculated by subtracting total cost from total revenue:

π = TR - TC

π = 1020 - 600

π = 420

In the absence of price discrimination, the profit-maximizing conditions would be different, and the resulting prices, quantities, total revenue, total cost, and profit would also be different.

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We can Long Division method to solve quotients step by step

What is long division method and its steps ?

When splitting huge numbers, the task is divided into several sequential parts using the long division approach. The dividend is divided by the divisor, just as in conventional division problems, and the result is known as the quotient; occasionally, it also produces a remainder.

We need to comprehend a few stages in order to divide. A vinculum or right parenthesis separates the dividend from the quotient, while a vertical bar separates the divisor from the dividend. Let's now go through the long division stages listed below to comprehend the procedure.

1. Take the dividend's first digit starting from the left . Verify if this digit exceeds or is equal to the divisor.

2. Next, divide it by the divisor, and write the result as the quotient on top.

3. Subtract the outcome from the digit, and then put the difference below.

Step 4: Decrease the dividend's subsequent digit (if present).

Step 5: Carry out Step 4 again.

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Answer:

the answer is seven

Step-by-step explanation:

seven

Answer:

The correct answer is D

Step-by-step explanation:

I'm pretty sure. Thank you.

Answer:

Step-by-step explanation:

Initial Function:

y=x²

Move the parent function 4 units to the right ( moves horizontally).

y = (x-4)²

Make the function's opening wider

y = 1/2 (x-4)²

The graph moves 4 units to the right and widens.

The given events are mutually exclusive events.

Since we know that,

Two occurrences are said to be mutually exclusive in probability theory if they cannot occur at the same time or concurrently.

In other words, discontinuous events are those that are mutually exclusive. If two occurrences are regarded discontinuous, the likelihood of both happening at the same time is zero.

If A and B are the two occurrences, then the probability of their disjoint is stated as:

P (A and B) = 0 for the probability of a disjoint (or mutually exclusive) event.

The given events are;

Event A: Drawing a face card from a deck of cards.

Event B: Drawing a 5 from a deck of cards

These are mutually exclusive, because a face card is not a 5 and a 5 is not a face card, both occurrences are mutually exclusive.

When you draw a card from a deck, it can only be one card with one value, therefore it can't be a face card and a 5.

As a result, the occurrence of one event precludes the occurrence of the other.

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Angle A in the triangle can be found using the given information and applying the appropriate trigonometric or geometric concepts. To determine its approximate degree measure, we'll need to know the lengths of the triangle's sides or the measures of the other angles.

To find the approximate degree measure of angle A in the triangle, we need to have some information about the triangle, such as the lengths of its sides, or the measures of the other angles. However, the information given in your question is incomplete, as no details about the triangle are provided.

Assuming we have the necessary information, there are different methods to calculate angle A depending on the available data. If we have the side lengths, we can use the Law of Cosines or the Law of Sines, depending on which sides and angles we have. If we have the other two angles, we can use the fact that the sum of angles in a triangle is always 180 degrees.

For example, if we know the measures of angles B and C, we can use the following formula to find angle A:

Angle A = 180 - (Angle B + Angle C)

To find the approximate degree measure of angle A, we need to have more information about the triangle. Once we have that information, we can apply the appropriate trigonometric or geometric concept to determine the degree measure of angle A.

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Answer:

8u - 20

Step-by-step explanation:

Step-by-step explanation:

remember, the domain is the interval or set of all valid x values, the range is the interval or set of all valid y values (functional result values).

1.

domain : -infinity < x < +infinity

range : -1 <= y < +infinity

due to the x² term that part can never be negative. the minimum is 0, and then -1 gives us a overall minimum -1. and then up ... the sky is the limit ...

2.

domain : every value of x that does not turn (3x + 5) to 0 and therefore does not cause a 1/0 situation.

the only forbidden value of x is therefore

3x + 5 = 0

3x = -5

x = -5/3

so, (-infinity < x < -5/3) OR (-5/3 < x < +infinity)

range : -infinity < y < +infinity

3.

domain : -infinity < x < +infinity

range : 0 <= y < +infinity

due to the x⁴ term (even exponent) all results will be positive starting with 0. similar to 1.

4.

this is 1/(2x) as I understand it.

similar to 2. we must avoid at 1/0 situation.

so, x must not be 0. everything else is possible

domain : (-infinity < x < 0) OR (0 < x < +infinity)

range : -infinity < y < +infinity

5.

everything is allowed and possible.

domain : -infinity < x < +infinity

range : -infinity < y < +infinity

Answer:

add everything to everything

Step-by-step explanation:

Answer:

I can t see it

Step-by-step explanation:

Answer:

(8) \(x + y = -8\) and \(2x - y = -10\)

(9) \(3x - y = -54\) and \(4x + y = -30\)

(10) \(x + y = 2\) and \(x - y = 2\)

Step-by-step explanation:

Given [Missing from the question]

\((8).\ (-6,-2)\ \\ (9).\ (-12,18)\ \\ (10).\ (2,0)\)

Required

Write a system of linear equations

The solutions to this question is open and have different solutions

Solving (8) (-6,-2)

Let the equations be: x + y and 2x - y

\(x + y = -6 - 2\)

\(x + y = -8\) --- (1)

\(2x - y = 2 * (-6) - (-2)\)

\(2x - y = -10\) -- (2)

So, the equations are:

\(x + y = -8\) and \(2x - y = -10\)

Solving (9) (-12, 18)

Let the equations be: 3x - y and 4x + y

\(3x - y = 3 *(-12) - 18\)

\(3x - y = -54\)

\(4x + y = 4 * (-12) + 18\)

\(4x + y = -30\)

So, the equations are:

\(3x - y = -54\) and \(4x + y = -30\)

Solving (9): (2,0)

Let the equations be: x + y and x - y

\(x + y = 2 + 0\)

\(x + y = 2\)

\(x - y = 2 - 0\)

\(x - y = 2\)

So, the equations are:

\(x + y = 2\) and \(x - y = 2\)

Answer:

cos C

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos C = \(\frac{adjacent}{hypotenuse}\) = \(\frac{BC}{AC}\) = \(\frac{12}{13}\)

Only matrices of the same size can be added or subtracted.

A matrix is a rectangular array of numbers and is composed of rows and columns. In order to add or subtract matrices, the matrices must have the same number of rows and columns. If the matrices do not have the same size, they cannot be added or subtracted.

For example, if one matrix is a 2x3 matrix, the other matrix must also be a 2x3 matrix. Similarly, if one matrix is a 3x2 matrix, the other matrix must also be a 3x2 matrix. The numbers in each matrix may vary, but the size of the matrices must be the same for the operation to be valid.

When adding or subtracting matrices, the numbers in the same position (row and column) are added or subtracted. For example, if one matrix is [[1,2,3], [4,5,6], [7,8,9]] and the other matrix is [[2,4,6], [8,10,12], [14,16,18]], the resulting matrix would be [[3,6,9], [12,15,18], [21,24,27]].

Adding and subtracting matrices is a useful tool in mathematics and is often used to solve equations and simplify complex problems. It is important to remember that only matrices of the same size can be added or subtracted.

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