I don't need any explanation only the answers

Answer:

C. NH₄Cl

Explanation:

The compound with the element ratio 1 : 4 : 1 from the given choices is NH₄Cl.

An element is a pure substance made up of distinct number of atoms. Elements are unique and are different from other elements because of the nature of their atoms.

We often delineate an element using chemical symbols.

   In the compound NH₄Cl;

There are 3 elements:

           Number of atoms

N                      1

H                      4

Cl                     1

We need to add 837.5 mL of water to the original 1.25 M potassium chloride solution to make a 0.50 M potassium chloride solution.

To solve this problem, we can use the formula for dilution:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given:
Initial concentration (C1) = 1.25 M
Initial volume (V1) = 337 mL
Final concentration (C2) = 0.50 M

We need to find the final volume (V2) by adding water to the original solution.

Rearranging the formula, we have:

V2 = (C1V1) / C2

Plugging in the values:

V2 = (1.25 M * 337 mL) / 0.50 M

Simplifying the equation:

V2 = 837.5 mL

Therefore, you need to add 837.5 mL of water to the original 1.25 M potassium chloride solution to make a 0.50 M potassium chloride solution.

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Answer:

Density = 0.27 decagrams/cm³

Explanation:

From conversion tables, we know that;

1 g/cm³ = 0.1 decagrams/cm³

We are given;

Density of aluminium = 2.7 g/cm³

Thus;

Density = 2.7 * 0.1

Density = 0.27 decagrams/cm³

Answer:

270000 decagrams/m³

Explanation:

1.

Density=mass/Volume

=2.7g/1cm3

=(2.7/1000)/(1/1000000)

=2.7x1000

Density=2700kg/ m3

= 270000 decagrams/m³

2.

1000g=1kg

1g=1/1000kg

1cm3= ? m3

100cm=1m

1cm=1/100 m

1cm3=1/1000000 m3

a) iron + oxygen ----> iron oxide

b) silver + oxygen -----> silver oxide

c) tin + chlorine -----> Tin chloride

We know that a word equation is the kind of equation that does not show us the symbols of the compounds or the elements that are taking part in the reaction.

In this case we have a number of reactions that have taken place here and we have been asked to show the reactants and the products as word equations. The word equations must show the reactants and the products of the reaction here.

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The magnetic force experienced by a proton moving with a speed of 3 ×\(10^{5}\) m/s in the magnetic field B of magnitude 6 ×\(10^{-5}\) T will be 2.88×\(10^{-18}\) N.

Magnetic force can be defined as the attraction or repulsion force that arises between electrically charged particles due to the motion of the charged particles.

Given,

Speed = 3×\(10^{5}\) m/s

Magnetic Field, B= 6 ×\(10^{-5}\) T

Magnetic force is the product of velocity, the charge of a proton, and the magnetic field present there.

The magnetic force can be represented as:

F=qvB

F=1.6×\(10^{-19}\)×3×\(10^{5}\) ×6 ×\(10^{-5}\)

F=2.88×\(10^{-18}\) N

Hence, the magnetic force experienced by the proton will be 2.88×\(10^{-18}\) N.

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Answer:

1.3 x 10^-15J

Explanation:

Answer:

moist air is less dense than dry air because water has a lower molecular weight than nitrogen and oxygen

Answer:

Water vapor is a relatively light gas when compared to diatomic Oxygen and diatomic Nitrogen. Thus, when water vapor increases, the amount of Oxygen and Nitrogen decrease per unit volume and thus density decreases because mass is decreasing.

Answer:

What question?

Explanation:

Answer:

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"the number of ions produced by one formula unit of the electrolyte," refers to the van't Hoff factor (i) in an ideal solution of a strong electrolyte. It represents the extent of dissociation of the electrolyte into ions.

In an ideal solution of a strong electrolyte, the van't Hoff factor (i) represents the number of ions that are produced when one formula unit of the electrolyte dissociates completely in the solution. It is a measure of the extent of dissociation of the electrolyte.

For example, for a strong electrolyte such as sodium chloride (NaCl), when it dissolves in water, it completely dissociates into sodium ions (Na+) and chloride ions (Cl-). In this case, the van't Hoff factor (i) would be 2 because one formula unit of NaCl produces two ions (Na+ and Cl-).

Similarly, for other strong electrolytes, the van't Hoff factor (i) can be determined based on the number of ions produced per formula unit. It is important to note that for non-electrolytes or weak electrolytes, the van't Hoff factor (i) is typically less than 1, indicating partial dissociation or no dissociation in the solution.

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At 25ºC, the substances can be ranked in order of increasing ka as follows: HBrO < HClO3 < HBrO3. This is because the acidity of a substance is directly proportional to its Ka value, which is the acid dissociation constant.

A higher Ka value indicates a stronger acid, and a lower Ka value indicates a weaker acid. HBrO has the lowest Ka value of the three substances because it is a weaker acid than HClO3 and HBrO3, this is because it has a larger atomic radius than the other two, which means its hydrogen atom is less likely to dissociate from the molecule. HClO3 has a higher Ka value than HBrO because it is a stronger acid, this is due to its electronegativity, which means it can more easily donate its hydrogen ion to a base.

HBrO3 has the highest Ka value of the three substances because it is the strongest acid. This is because it has the highest electronegativity and the smallest atomic radius, making it the most likely to donate its hydrogen ion to a base. In summary, the order of increasing Ka value at 25ºC for HBrO, HClO3, and HBrO3 is HBrO < HClO3 < HBrO3. This is because the acidity of a substance is directly proportional to its Ka value, which is the acid dissociation constant.

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The enantiomer of trans-1,2-diamino cyclohexane that would form a solid complex with d-tartaric acid is the (1R,2R)-trans-1,2-diamino cyclohexane. This is because d-tartaric acid has a (2R,3R) configuration, and it can form a diastereomeric salt with the (1R,2R)-trans-1,2-diamino cyclohexane through hydrogen bonding and other non-covalent interactions.

The formation of this diastereomeric salt leads to a solid complex with enhanced stability and decreased solubility, allowing for easy separation of the enantiomers. The enantiomer of trans-1,2-diamino cyclohexane that would form a solid complex with d-tartaric acid is the (1R,2R)-trans-1,2-diamino cyclohexane. This is because d-tartaric acid, which has a (2R,3R) configuration, can form a diastereomeric salt with the (1R,2R)-trans-1,2-diamino cyclohexane through hydrogen bonding and other non-covalent interactions. Diastereomers are stereoisomers that are not mirror images of each other and can have different physical properties, such as solubility and melting points. In this case, the (1R,2R)-trans-1,2-diamino cyclohexane would form a solid complex with d-tartaric acid due to the specific arrangement of functional groups and their interactions, leading to the formation of a stable diastereomeric salt.

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Winston and Julia incorrectly believe that they will be able to overthrow the Party and establish a better society through their work for the Brotherhood.

Throughout the novel "1984" by George Orwell, Winston and Julia are disillusioned with the oppressive Party and the society it has created. They both believe that they can make a difference and change things for the better. As they promise to work for the Brotherhood, a secret organization dedicated to overthrowing the Party and establish , they are convinced that they will be able to achieve their goals and create a free and equal society.

However, their beliefs are based on a misunderstanding of the Party's power and the extent of its control over society. They underestimate the Party's ability to manipulate and suppress dissent, and they fail to recognize the true nature of the Brotherhood and its leader, Emmanuel Goldstein. In the end, their efforts are in vain, and they are captured and subjected to the Party's brutal methods of torture and brainwashing.

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P tot = 0.1065 atm

The mole fraction of oxygen in the mixture : 0.709

Given

10 L flask

1.013 g O₂

572 g CO₂

T = 18 °C = 291 K

Required

P O₂ and P CO₂

Solution

Dalton Law's of partila pressure

P tot = P₁ + P₂ + ..Pₙ

From ideal gas Law :

\(\tt P_{O_2}=\dfrac{\dfrac{1.013}{32}\times 0.082\times 291 }{10}\\\\P_{O_2}=0.0755~atm\)

\(\tt P_{CO_2}=\dfrac{\dfrac{0.572}{44}\times 0.082\times 291}{10}\\\\P_{CO_2}=0.031~atm\)

P tot = P O₂ + P CO₂

P tot = 0.0755 + 0.031

P tot = 0.1065 atm

The mole fraction of  O₂ :

\(\tt P_{O_2}=X_{O_2}\times P_{tot}\\\\X_{O_2}=\dfrac{P_{O_2}}{P_{tot}}\\\\X_{O_2}=\dfrac{0.0755~atm}{0.1065~atm}\\\\X_{O_2}=0.709\)

Answer:

The difference between an atom and an ion has to do with net electrical charge. An ion is a particle or collection of particles with a net positive or negative charge. ... A stable atom contains the same number of electrons as protons and no net charge. When electrons are added or removed, the stable atom becomes an ion.Apr 12, 2015

Explanation:

hope this helps ✌️

Answer:

If the mass of a sample of aluminum foil is known, then it is possible to calculate the volume of the foil. In general volume is the product of length times width times height of an object. If we know the length and width of a piece of foil, we can then determine its height, or thickness.

sorry if wrong

Answer:

b

Explanation:

Answer:

Must contain 6.022-1023 atoms of Al

Answer:

True

Explanation:

The correct statements of an electrophilic aromatic substitution reaction are; A strong electrophile is required to bring the aromatic ring into the reaction, and Post electrophile addition to the benzene, a carbocation forms which possesses a sp³ hybridized carbon. Option B and C is correct.

Option A is incorrect.  A strong nucleophile is not required in an electrophilic aromatic substitution reaction. Instead, a strong electrophile is needed to attack the aromatic ring and replace a hydrogen atom.

Option B is correct. Electrophilic aromatic substitution reactions involve the attack of a strong electrophile on an aromatic ring, which leads to the substitution of a hydrogen atom with the electrophile. The electrophile is responsible for initiating the reaction.

Option C is correct. After the electrophile attacks the aromatic ring, a carbocation intermediate is formed. This carbocation possesses a sp3 hybridized carbon atom because the substitution occurs at the carbon atom originally bonded to the hydrogen atom.

Option D is incorrect. The carbocation formed in an electrophilic aromatic substitution reaction possesses a sp³ hybridized carbon atom, not sp². The sp² hybridization occurs in the original aromatic ring structure.

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Answer:

It is the smallest planet found in the habitable zone.

Explanation:

Food  low in sodium and high in potassium among soy sauce, dill pickles, orange juice, and canned soup, the correct answer is orange juice.

Eating a varied diet helps to ensure that you receive all the nutrients necessary for a healthy diet

Variety involves eating different foods from all the food groups. Eating a varied diet helps to ensure that you receive all the nutrients necessary for a healthy diet. One of the major drawbacks of a monotonous diet is the risk of consuming too much of some nutrients and not enough of others.

Orange juice is food which is low in sodium and high in potassium, making it a suitable choice for those seeking such nutritional values.

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Answer:

No.

Explanation:

No, convection does not occur if Earth's mantle were a box 30 km on a side because convection needs medium for the movement of heat energy from one place to another. Convection and conduction are two processes which needs medium for its movement while radiation does not need any medium for its movement. If there is a empty space present between two substances so convection does not occur.

The sludge generation process refers to the production of sewage treatment residue during wastewater treatment. Sludge contains solid and semi-solid materials that must be handled and disposed of properly to protect human health and the environment.

The following are some methods for sewage disposal:

Wastewater Treatment: Initial treatment involves the physical removal of large solids, whereas secondary treatment uses biological processes to break down organic matter and remove dissolved pollutants.

Sludge Treatment: The separated sludge is under further treatment, which may include stabilization, dewatering, and, in some cases, additional processes to reduce contaminants.

Land Application: Treated sludge can be applied to agricultural land as a fertilizer or soil conditioner if it meets regulatory guidelines and has been properly treated.

Landfills: If sludge cannot be reused or recycled, it can be disposed of in a designated landfill that meets regulatory requirements, ensuring proper containment and preventing soil and water contamination.

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Answer:

a) clockwise

b) clockwise and

c) anticlockwise

Extremophiles does Thermus aquaticus belong to thermophiles.

What is thermophile?
A thermophile is an organism that thrives in extremely hot temperatures. They are found in a variety of environments, from deep sea hydrothermal vents to the hot springs of Yellowstone National Park. Thermophiles are important to the study of biology, as they can offer insight into how life began and evolved on Earth. Thermophiles also have a variety of applications, including in biotechnology, as they can be used to create enzymes that can withstand high temperatures and in food production, as they can help break down proteins. Thermophiles can also be used in wastewater treatment, as they can help break down and digest organic materials.

Thermus aquaticus are heat-resistant microorganisms because they can endure harsh environmental circumstances, such as high temperatures.
These bacteria are thermophiles, a class of extremophiles that enjoy heat the most. There are thermophiles in volcanic soil, surrounding geysers, and at deep-sea vents where the temperature is very high.
Taq DNA polymerase, a heat-resistant enzyme that is crucial for molecular biology, is produced by the Thermus aquaticus bacteria.

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Answer:

Thermophiles

Explanation:

Edge