Answer:
apple
Explanation:
The volumes of two bodies are measured to be
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³. Calculate sum and difference in
volumes with error limits.
Answer:
sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
Explanation:
Here,
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.
Now,
∆V = ± (∆V₁ + ∆V₂)
= ± (0.02 + 0.01) cm³
= ± 0.03 cm³
V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and
V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³
Thus, sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
-TheUnknownScientist
Answer:
I hope it's helpful .............
At room temperature, most metals are
A. Solids
B. Liquids
C. Gases
D. Plasma
Answer:
A. Solids
Explanation:
only Mercury is liquid soo .... solid
Horsepower is defined as ______.
A. power applied over the distance of an English horserace track
B. the mechanical advantage gained by using a typical horse
C. the mass of a horse divided by the time it takes the horse to run 100 meters
D. a specific amount of power (550 ft-lb/s)
The definition of horsepower is . A. the amount of force used to cover the length of an English associated activities track B. the practical benefit of utilizing a standard horse
Who developed the horsepower?
James Watt, an engineer, is credited with creating the term horsepower. According to legend, Watt wanted to find a method to describe the power that one of those animals could produce while he was dealing with ponies in a coal mine. An engine is connected to a dynamometer in order to determine its horsepower.
What is the power of a horse?
The most prevalent unit of power is horsepower , which measures how quickly work is completed. According to the British Imperial Units, a horsepower is equivalent to 33,000 walking of work per minute, or the force required to elevate a mass of 3 million pounds one foot in a minute.
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You are driving home from school St at 97 km/h for 190 km and then it begins to rain and you slow to 61 km/h instantly you arrive home after five hours how far is your hometown from school
The distance of your hometown from school is 318.64 km.
Given data
Distance S = 190 km
Speed v = 97 km / h
Now, the time taken to travel S distance is calculated as,
t = S / v
t = 180 / 95
t = 1.958 hrs
Now, the total time is given as
Total time T = 4.0 h
So, remaining time t ' = T - t = 4 hrs - 1.958 hrs = 2.042 hrs
Now, the velocity after travel 190 km is v ' = 63 km/ h
Distance travel in this velocity S ' = v ' t '
= 128.6 km
Now, the distance of your hometown from school , S " = S + S '
= 190 km + 128.6 km = 318.64 km
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I have multiple voltage sources of different rating like 5V,6V,1V and 20V draw schematic diagram using these sources to power a light of rating 11 volt
Answer:
add molecules
Force (N)
896760 50 3NTO
10
2
I
0 0.04 0.08 0.12 0.16 0.20
Extension (m)
13. Using the graph above, (a) determine the spring constant, (b) write the Hooke's law equation for this
spring.
a) The spring constant is 896760 N/m.
b) F = -896760x
How do we arrive at the values?(a) To determine the spring constant, we need to find the slope of the linear portion of the graph. The slope can be found by dividing the change in force by the change in extension.
(b) Hooke's law states that the force applied to a spring is proportional to the spring's extension, with the constant of proportionality being the spring constant. So the equation for this spring would be:
F = kx
where F is the force, x is the extension, and k is the spring constant.
Therefore, the spring constant is 896760 N/m. It could then be concluded that the spring constant is as given above.
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A researcher tries to determine the effects of lack of exercise on cholesterol levels. The participants are divided into two groups; one group of participants is put on a low-exercise regime, another group is put on a high-exercise regime. After several months of following their regimes, participants' cholesterol levels are measured. In this study, cholesterol level is the _______ variable.
The cholesterol levels of the patients are assessed after many months of adherence to their regimens. In this research, cholesterol level is the Dependent variable.
Which fitness program works the best?Us Department of Human services Services advises that most healthy adults engage in at least 150 hours of moderate cardiovascular exercise or 75 minutes of strenuous aerobic activity per week, or a mix of both.You should spread out this workout over the period of a week, according to the instructions.
What applications exist for the 80/20 rule?The 80/20 rule states that 20% of your training time (effort) results in 80% of your workout benefits (such as weight loss or muscle growth).
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Why does the transition of light waves from water to air make it seem as if fish and other things in a pond are shallower than they actually are?
Answer:
When light gets in contact with water, it emerges into the air, and then it speeds up, which makes it look shallower than it actually is.
Explanation:
Answer:
Refraction
Explanation:
Light rays reflected from the fish are refracted at the surface of the water, but the eyes and brain trace the light rays back into the water as thought they had not refracted, but traveled away from the fish in a straight line. This effect creates a "virtual" image of the fish that appears at a shallower depth.
A ball has a velocity of 11 m/s and a momentum of 47 kgm/s, what is its mass? Show
your given, required, and solutions.
Explanation:
p=m x v
to find the mass:
m= p/v
=47/11
=4.27 kg
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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The highway distance from Indianapolis to Denver is 1712 km. If the driving time is 29.25 hr, what is the average speed of the trip?
Answer:
54 miles speed
Explanation:
The asteroid 234 Ida has a mass of about 4 × 1016 kg and an average radius of about 16 km. What is the acceleration due to gravity on 234 Ida? Assume that the asteroid is spherical; use G = 6.67 × 10–11 Nm2/kg2.
A. 1 cm/s2
B. 2 cm/s2
C. 5 cm/s2
D. 6 cm/s2
Answer:
1 cm/s²
Explanation:
I just took the quiz
The asteroid 234 Ida has a mass of about 4×1016 kg and an average radius of about 16 km. The acceleration due to gravity will be 1.04 cm/s². Hence, option A is correct.
What is the acceleration due to gravity?The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/s² is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on the earth's surface is 9.8 m/s².
The formula for the acceleration due to gravity is g=GM/r².
According to the question, the given values are :
Mass, M = 4 × 1016 kg or
M = 4 × 10¹⁶.
Radius, r = 16 km or,
r = 16000 meter.
G = 6.67 × 10⁻¹¹ Nm²/kg²
g = (6.67 × 10⁻¹¹ ) (4 × 10¹⁶) / 16000²
g = 0.0104 m/s² or,
g = 1.04 cm/s².
Hence, the acceleration due to gravity will be 1.04 m/s²
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A small mass m is tied to a string of length L and is whirled in vertical circular motion. The speed of the mass v is such that the ratio of the string tension at the top of the circle to that at the bottom of the circle is FtopT/FbotT = 0.5. Derive an expression for the speed v.
Answer:
(mv^2/R)/(mg)=1/2
v^2=R/2g
The expression for the speed of the mass is \(v = \sqrt{\frac{gL}{3} }\)
The given parameters;
mass of the string, = m
length of the string, = L
speed of the string, = v
The tension of the string at the top of the circle;
\(T_{top} = \frac{mv_t^2}{r} - mg\)
The tension of the string at the bottom of the string;
\(T_{bottom} = \frac{mv_b^2}{r} + mg\)
The ratio of the two force is given as;
\(\frac{T_{top}}{T_{bottom}} = \frac{mg - \frac{mv_t^2}{r} }{mg + \frac{mv_b^2}{r}} = 0.5\\\\0.5(mg + \frac{mv_b^2}{r}) = mg - \frac{mv_t^2}{r}\\\\mg + \frac{mv_b^2}{r} = 2(mg - \frac{mv_t^2}{r})\\\\mg + \frac{mv_b^2}{r} = 2mg - 2\frac{mv_t^2}{r}\\\\2\frac{mv_t^2}{r} + \frac{mv_b^2}{r} = 2mg - mg\\\\2\frac{mv_t^2}{r} + \frac{mv_b^2}{r} = mg\\\\assuming \ v_t = v_b\\\\3\frac{mv^2}{r}= mg\\\\\frac{v^2}{r} = \frac{g}{3} \\\\v^2 = \frac{rg}{3} \\\\v = \sqrt{\frac{rg}{3}}\)
\(v = \sqrt{\frac{gL}{3} }\)
Thus, the expression for the speed of the mass is \(v = \sqrt{\frac{gL}{3} }\)
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calculate the density of 1mole of oxygen ata pressure of 4×10^-4Nm^-2 and a temprature of 273.2°K
The density of 1 mole of oxygen at a pressure of 4×10⁻⁴ Nm⁻² and a temprature of 273.2 K is 2.82×10⁻⁶ g/m³
How to determine the density of oxygenWe'll begin by obtaining the volume of the oxygen. This can be obtained as follow:
Number of mole (n) = 1 molePressure (P) = 4×10⁻⁴ Nm⁻²Temperature (T) = 273.2 K Gas constant (R) = 8.314 m³Nm⁻²/KmolVolume = ?PV = nRT
Divide both sides by P
V = nRT / P
V = (1 × 8.314 × 273.2) / 4×10⁻⁴
V = 5678462 m³
Finally, we shall determine the density of the oxygen. This can be obtained as follow:
Mass of 1 mole of oxygen = 16 gVolume of 1 mole of oxygen = 5678462 m³Density of oxygen =?Density = mass / volume
Density of oxygen = 16 / 5678462
Density of oxygen = 2.82×10⁻⁶ g/m³
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Pressure is applied from a gas cylinder to one side of a U-tube manometer with constant internal diameter “D", as shown below. The manometer is filled with fresh water (density = 999 kg/m3) and upon application of the pressure, the water column on one side rises by 4.00 cm relative to the other. Draw and label a free-body diagram representing the forces in the manometer. Calculate the pressure above atmospheric pressure applied by the gas.
Answer:
P = 39200.76
Explanation:
formula is:
P = pgh
P = pressure
p = density of fluid
g = acceleration due to gravity ( 9.81 m/s2 for earth)
h = height above the point we are looking for
P = pgh
P = 999x9.81x4
P = 39200.76
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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8. A 12kg bowling ball has a velocity of 8 m/s, and is brought to
a stop gradually over 10s. How much change in momentum
does the bowling ball experience?
Answer:
The change in momentum experienced by the bowling ball is 96 kgm/s.
Explanation:
Given;
mass of the bowling ball, m = 12 kg
velocity of the bowling ball, v = 8 m/s
time of motion, t = 10 s
The change in momentum experienced by the bowling ball is equal to the impulse experienced by the bowling ball.
ΔP = J = F x t
\(J = ft =\frac{mv}{t} \times t = mv\\\\J = 12 \times 8\\\\J = 96 \ kg.m/s\)
Therefore, the change in momentum experienced by the bowling ball is 96 kgm/s.
why big tractor can plough many fields than small tractor
A big tractor is more efficient and productive than a small tractor, allowing it to plow through more fields and cover more ground with less time and effort.
A big tractor can plow many fields than a small tractor due to several reasons:Engine Power: Big tractors have larger and more powerful engines than small tractors, which allow them to generate more torque and power to pull heavy loads and work for longer periods of time without overheating or breaking down. This means they can work more efficiently and cover more ground than small tractors.
Size and Weight: Big tractors are usually larger and heavier than small tractors, which gives them more stability and traction on the ground. This allows them to plow through tough and uneven terrain with less effort and more control, reducing the time and effort needed to complete the task.
Implements: Big tractors can accommodate larger and more advanced implements, such as wider plows, cultivators, and seeders, which allow them to cover more ground with each pass. These implements can also be customized to match the specific needs of the soil and crops, increasing the efficiency and productivity of the tractor.
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The coefficient of linear expansion of steel is 12 × 10-6 K-1. What is the change in length of a 25-m steel bridge span when it undergoes a temperature change of 40 K?
In order to calculate the change in length, we can use the following formula:
\(\delta L=L_0\cdot\alpha\cdot\Delta T\)Where deltaL is the change in length, L0 is the initial length, alpha is the coefficient of linear expansion and DeltaT is the change in temperature.
So we have:
\(\begin{gathered} \delta L=25\cdot12\cdot10^{-6}\cdot40 \\ \delta L=120000\cdot10^{-6} \\ \delta L=12\cdot10^{-2}=0.12 \end{gathered}\)So the change in length is 0.12 meters or 12 centimeters.
A student makes the following claim:
The energy of electromagnetic waves increases with decreasing wavelength.
Which of the following statements support this claim?
O A. Dental patients need to wear lead aprons to protect themselves from X-rays but do not wear
protection from flashlights.
B. Both radio waves and gamma rays are invisible to human eyes.
C. Ultraviolet radiation causes sunburn but radio waves do not.
D. Microwaves are used for communication.
E. Gamma rays are used to kill cancer cells, but microwaves have no known effect on cancer
cells.
Answer:
A, C, E
Explanation:
I put this and got it right.
A ball rolls across a smooth surface at a steady 0.5 m/s. What is its acceleration? m/s^2?
Answer:
0m/s²
Explanation:
The acceleration of the given body whose motion has been described will be zero.
This is because the body moves with a constant velocity.
Acceleration is defined as the rate of change of velocity with time.
Since in this problem, the velocity is not changing per time, then the acceleration would be zero.
A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.
Which ones are correct??
Answer:
blanket:thermal conductivity
as it conduct heat.
aquarium glass:transparency
as light can be transfered from one side to
another.
A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better
Answer and Explanation:
A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.
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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.
Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body
Air is matter which backs best support the statement
Answer: A. Balloons can be filled with air.
C. Air has mass.
Explanation:
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Balloons are able to be filled with air and air has mass.
A rocket takes off from Earth's surface, accelerating straight up at 63.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 84.4 kg, including her space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.)
______N
From the calculation, the normal force is 6161.2 N.
What is the normal force?The normal force is given by the expression;
N - mg = ma
Then;
N = mg + ma
m = 84.4 kg
g = 9.8 m/s^2
a = 63.2 m/s2
Now we have;
N = m(g + a)
N = 84.4 (9.8 + 63.2)
N = 6161.2 N
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What is the magnitude of the momentum of a motorcycle of a mass of 100 kg at rest What is its momentum if this motorcycle when it travels at 40 m s?
The magnitude of a momentum of a motorcycle of a mass of 100kg at rest stage is 0kg-m/sec and momentum of a motorcycle is 4000kg-m/sec when it travels with 40m/sec speed.
We know very well that momentum is defined as the quantity of the motion of the body.
Momentum is represented by the product of mass and velocity, or in other words p=mass × velocity
Momentum is called as a vector quantity. It means it has proper magnitude and proper direction.
From momentum, impulse is also calculated.
At rest stage velocity of motorcycle is 0m/sec
Therefore, momentum=100×0=0Kg-m/sec
Now, when motorcycle is moving with speed 40m/sec, then momentum is
=>p=100kg×40m/sec
=>p=4000kg-m/sec
There are various laws in physics which are derived by the conservation of momentum.
Hence, magnitude of momentum are 0kg-m/sec and 4000kg-m/sec.
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WILL GIVE BRAINLIEST TO THE CORRECT ANSWER
Estimate the net force needed to accelerate a 1000-kg car from rest.
AND
Estimate the weight of a 1000-kg car that is accelerating at 3m/s/s.
Answer:
See the answers below.
Explanation:
We can solve both problems using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F =m*a
where:
F = force [N] (units of newtons)
m = mass = 1000 [kg]
a = acceleration = 3 [m/s²]
\(F = 1000*3\\F=3000[N]\)
And the weight of any body can be calculated by means of the mass product by gravitational acceleration.
\(W=m*g\\W=1000*9.81\\W=9810 [N]\)
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
Cual es la Ecuación de velocidad de una onda en función del índice de la amplitud de una cuerda
Answer:
Well velocity is the varaible with direction
Explanation:
PLEASE HELP SOON! For the circuit below , the battery has 4.2V calculate power giving and power receiving
For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.
Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,
R = 55*30/(55+30)
R = 19.4 Ω
Power given to the circuit is,
P = V²/R = 4.2/19.4 = 0.9 W
Receiving power taken from 55Ω resistor
P = V²/R = 4.2/55 = 0.07 W
Receiving power taken from 30Ω resistor
P = V²/R = 4.2/30 = 0.14 W
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