I need an A so I don’t get yelled at

The probability that a given class period runs between 50.5 and 51 minutes is 0.05

Understanding that a uniform probability distribution is essentially a rectangle with a surface area of one will help you to find the simplest solution to this problem.

Find a section of this rectangle's area now.

Her classes are uniformly distributed between 48.0 and 58.0 minutes so,

We have to find the probability that a given class period runs between 50.5 and 51 minutes

51−50.5-/58-48

=0.5/10

=0.05

1 X0.05=0.05

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The full question:

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 58.0 minutes. Find the probability that a given class period runs between 50.5 and 51 minutes.

Answer:

The answer would be 5.

Step-by-step explanation:

If you take away 18 from 90 would be 72.

72 - 18 =54

54 - 18 =36

36 - 18 =18

18 - 18 =0

If you count that would equal 5 .

Hope this helps .

If the mean monthly electric bill for 71 residents of the local apartment is $62 , then the best point estimate is $62 .

In the question ,

it is given that ,

the number of residents in the local apartment complex is = 71

the mean electric bill for the 71 residents = $62 ;

we know that the sample mean is itself called as the best point estimate ;

So , best point estimate for mean monthly electric bill for all residents of local apartment complex will be = mean monthly bill for 71 residents of  local apartment complex which is given as $62 .

Therefore , the best point estimate is $62 .

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In summary, a dilation with a scale factor not equal to 1 preserves the angles of the preimage while altering the side lengths in a proportional manner.

In a dilation with a scale factor not equal to 1, the angles and side lengths of the preimage and the image are related in the following ways:

Angles: The angles in the preimage and the image remain the same. They have the same measures, and their relative positions to each other are preserved. The dilation does not affect the angles; they are unchanged.

Side Lengths: The side lengths in the image are proportional to the corresponding side lengths in the preimage. The scale factor of the dilation determines the ratio between the side lengths. If the scale factor is greater than 1, the side lengths in the image will be longer than the corresponding side lengths in the preimage. If the scale factor is between 0 and 1, the side lengths in the image will be shorter than the corresponding side lengths in the preimage. The ratio of the side lengths remains the same throughout the dilation.

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Answer:

Collect like terms 5 p 2 − p 2

Step-by-step explanation:

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The robotics industry (a) involves designing and developing androids, integrating their degrees of freedom, and testing them out. These activities are essential for creating advanced humanoid robots.

The robotics industry is a rapidly growing field that encompasses a wide range of applications and technologies. One aspect of this industry is designing simple androids, which involves creating humanoid robots that resemble humans in appearance and behavior. These androids often mimic human movements and interactions, making them suitable for various tasks and roles. Another aspect is integrating the degrees of freedom of these androids. Degrees of freedom refer to the number of independent movements or actions a robot can perform. By carefully designing and integrating the degrees of freedom, engineers can enable androids to perform complex and precise tasks. This involves considering factors such as joint mechanisms, range of motion, and coordination between different parts of the robot's body.

Testing is also a crucial aspect of the robotics industry. Before deploying androids in real-world scenarios, rigorous testing is conducted to ensure their functionality, safety, and performance. Testing involves evaluating the robot's ability to perform tasks, its response to different environments and stimuli, and its overall reliability. Through testing, engineers can identify and address any issues or limitations, refining the design and improving the android's capabilities.

Overall, the robotics industry encompasses designing, integrating, and testing androids, enabling the development of advanced machines that can assist humans in various domains and contribute to technological advancements.

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The results of the expressions involving logarithms are listed below:

Case 1: 1 / 2

Case 2:

Subcase a: 0

Subcase b: 11 / 2

Subcase c: - 11 / 2

In this problem we have a case of an expression involving logarithms that must be simplified and three cases of expressions involving logarithms that must be evaluated. Each case can be solved by means of the following logarithm properties:

㏒ₐ (b · c) = ㏒ₐ b + ㏒ₐ c

㏒ₐ (b / c) = ㏒ₐ b - ㏒ₐ c

㏒ₐ cᵇ = b · ㏒ₐ c

Now we proceed to determine the result of each case:

Case 1

㏒ ∛8 / ㏒ 4

(1 / 3) · ㏒ 8 / ㏒ 2²

(1 / 3) · ㏒ 2³ / (2 · ㏒ 2)

㏒ 2 / (2 · ㏒ 2)

1 / 2

Case 2:

Subcase a

㏒ [b / (100 · a · c)]

㏒ b - ㏒ (100 · a · c)

㏒ b - ㏒ 100 - ㏒ a - ㏒ c

3 - 2 - 2 + 1

0

Subcase b

㏒√[(a³ · b) / c²]

(1 / 2) · ㏒ [(a³ · b) / c²]

(1 / 2) · ㏒ (a³ · b) - (1 / 2) · ㏒ c²

(1 / 2) · ㏒ a³ + (1 / 2) · ㏒ b - ㏒ c

(3 / 2) · ㏒ a + (1 / 2) · ㏒ b - ㏒ c

(3 / 2) · 2 + (1 / 2) · 3 + 1

3 + 3 / 2 + 1

11 / 2

Subcase c

㏒ [(2 · a · √b) / (5 · c)]⁻¹

- ㏒ [(2 · a · √b) / (5 · c)]

- ㏒ (2 · a · √b) + ㏒ (5 · c)

- ㏒ 2 - ㏒ a - ㏒ √b + ㏒ 5 + ㏒ c

- ㏒ (2 · 5) - ㏒ a - (1 / 2) · ㏒ b + ㏒ c

- ㏒ 10 - ㏒ a - (1 / 2) · ㏒ b + ㏒ c

- 1 - 2 - (1 / 2) · 3 - 1

- 4 - 3 / 2

- 11 / 2

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Answer:

Step-by-step explanation:

True

if the number of times you take the test were independent variable of the chance you fail what could that mean the difficulty of the test is consistent and unchanging.

The difficulty of the test is consistent and unchanging, making it so that the chance of failing is solely determined by the individual's performance on the test. Factors such as knowledge of the subject and the ability to focus can play a role in a person's success, but the actual chance of failing is not affected by how many times the test is taken. This means that those who fail the test will have to work harder and prepare better in order to pass it on the next attempt. Taking the test multiple times does not guarantee a higher chance of success, as the difficulty remains the same each time due to independent variable.

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5.) The dimensions of the banner whose perimeter is given is listed below:

length = 134in

width = -59in

To calculate the dimensions of the rectangular banner, the formula for the perimeter of rectangle should be used and it's given below;

Perimeter of rectangle = 2(length+width)

length = 16-2a

width = a

perimeter = 160in

That is;

160 = 2(16-2a+a)

160 = 32-4a+2a

160 = 42-2a

2a = 42-160

2a = -118

a = 118/2

= -59

Length = 16-2(-59)

= 16+118

= 134in

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Answer:

Graph a

Step-by-step explanation:

Answer:

the answer is A

Step-by-step explanation:

to start, I would use the slope intercept, in this case -3 which lets you know the slope meets the y axis at (0,-3) since you have that point, you count with the slope.

now slope is rise over run, therefore, it would be y over x and since the y in this case is 3, you'd go up three from your point. since x is 4, you'd go right four units from where you are. since A is the only graph that follows that, A would be correct.

Answer:

Step-by-step explanation:

maybe c but im not sure

Answer:

The answer is A

Step-by-step explanation: I just took the quiz.

Answer:

0

Step-by-step explanation:

First let's solve for the value in the parentheses.

\(0.35 \cdot 100 = 35\)

We know this is correct because if we multiply a value by 100, the decimal point is moved 2 places to the left.

35 - 35 = 0, so the value of this expression equals out to be 0.

Hope this helped!

Answer:

Step-by-step explanation:

The first three terms of the arithmetic sequence for the number of words written are 10010, 9760, 9510. These have a common difference of 9760-10010 = -250. The first term and common difference can be used to make the explicit equation for the words written on the n-th day.

The explicit formula for the n-th term of an arithmetic sequence with first term a₁ and common difference d is ...

  \(a_n=a_1+d(n-1)\)

For first term a₁ = 10010 and common difference d = -250, the explicit rule is ...

  \(a_n=10010-250(n-1)\)

On day 14, n=14, and the number of words written is ...

  \(a_{14}=10010-250(14-1)\\\\a_{14}=10010-250(13)=10010-3250\\\\a_{14}=6760\)

The writer would write 6760 words on the 14th day.

The number of years is given by the equation T = 10 years

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of years to qualify to receive Social Security benefits when Stacy retires be T

Now , the equation will be

The present age of Stacy = 46 years

The maximum number of credits each year = 4 credits

As to earn the social security benefits, she needs to earn 40 credits

So , the number of years = 40 credits / maximum number of credits each year

Substituting the values in the equation , we get

The number of years to qualify to receive Social Security benefits when Stacy retires T = 40/4

On simplifying the equation , we get

The number of years to qualify to receive Social Security benefits when Stacy retires T = 10 years

Hence , the number of years is 10 years

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1. Closing entry of net income to retained earnings: Net income of $78 million is transferred from the income statement to retained earnings.

2. Payment of the cash dividend: Cash dividend of $22 million is paid out to shareholders, reducing retained earnings.

3. A stock dividend of 1 million shares of $1 par common stock is issued

4. A property dividend of Gary Larson Publishers preferred stock held as a short-term investment is issued

5. Treasury shares with a cost of $50 million are sold, resulting in a decrease in retained earnings and an increase in cash.

1. The closing entry transfers the net income earned during the year from the income statement to retained earnings, reflecting the increase in accumulated profits.

2. The payment of the cash dividend represents the distribution of profits to shareholders, resulting in a decrease in retained earnings and an outflow of cash.

3. The issuance of the stock dividend involves distributing additional shares of common stock to shareholders as a dividend. This reduces retained earnings while increasing common stock and additional paid-in capital.

4. The issuance of the property dividend involves distributing shares of Garfield Company preferred stock held as a short-term investment to shareholders. This reduces retained earnings and creates a property dividend distributable account to track the distribution.

5. The sale of treasury shares involves selling previously repurchased shares back to the market. This decreases retained earnings and increases cash, reflecting the proceeds from the sale.

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Exercise 21-18 (Algo) Spreadsheet entries from statement of retained earnings [LO21-3, 21-4, 21-5, 21-6, 21-7, 21-8]

The statement of retained earnings of Gary Larson Publishers is presented below.

GARY LARSON PUBLISHERS

Statement of Retained Earnings

For the Year Ended December 31, 2021

($ in millions)

Retained earnings, January 1 $ 210

Add: Net income  78

Deduct: Cash dividend  (22 )

Stock dividend (1 million shares of $1 par common stock)  (13 )

Property dividend (Garfield Company preferred stock held

as a short-term investment)  (10 )

Sale of treasury stock (cost $50 million)  (8 )

Retained earnings, December 31 $ 235

Required:

For the transactions that affected Larson’s retained earnings, reconstruct the journal entries that can be used to determine cash flows to be reported in a statement of cash flows. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Enter your answers in millions (i.e., 10,000,000 should be entered as 10).)

1. Record the closing entry of net income to retained earnings.

2. Record the payment of the cash dividend.

3. Record the issuance of the stock dividend.

4. Record the issuance of the property dividend.

5. Record the sale of treasury shares.

The z-statistic and the p-value for each of the sample size are as follows;

A. z = 54.3, p = 0.

B. z = 0.018, p = 0.4928.

C. z = 0.0023, p = 0.4991.

D. z = 0.021, p = 0.4916.

E. z = 186.54, p = 0.

Mathematically, the test statistic for the z-statistic of a population proportion can be calculated by using the following mathematical equation;

\(z=\frac{\hat{p} \;- p}{\sqrt{\frac{p(1\;-p)}{n } } }\)

Where:

Part A.

Population proportion, p = \(\hat{p}\)/n

Population proportion, p = 0.30/100 = 0.003.

For the z-statistic, we have:

\(z=\frac{0.3 \;- \;0.003}{\sqrt{\frac{0.003(1\;-\;0.003)}{100} } }\)

z = 0.297/0.005469

z = 54.3

p-value = 1 - p(x < z)

p-value = 1 - 1 = 0

Part B.

Population proportion, p = \(\hat{p}\)/n

Population proportion, p = 0.78/50 = 0.0156.

For the z-statistic, we have:

\(z=\frac{0.78 \;- \;0.0156}{\sqrt{\frac{0.0156(1\;-\;0.0156)}{50} } }\)

z = 0.7644/0.005469

z = 0.018

p-value = 1 - p(x < z)

p-value = 1 - 0.5072 = 0.4928

Part C.

Population proportion, p = \(\hat{p}\)/n

Population proportion, p = 0.32/248 = 0.00129.

For the z-statistic, we have:

\(z=\frac{0.32 \;- \;0.00129}{\sqrt{\frac{0.00129(1\;-\;0.00129)}{248} } }\)

z = 0.3187/0.005469

z = 0.0023

p-value = 1 - p(x < z)

p-value = 1 - 0.5009 = 0.4991.

Part D.

Population proportion, p = \(\hat{p}\)/n

Population proportion, p = 0.667/39 = 0.0171.

For the z-statistic, we have:

\(z=\frac{0.667 \;- \;0.0171}{\sqrt{\frac{0.0171(1\;-\;0.0171)}{39} } }\)

z = 0.6499/0.005469

z = 0.021

p-value = 1 - p(x < z)

p-value = 1 - 0.5084 = 0.4916.

Part D.

Population proportion, p = \(\hat{p}\)/n

Population proportion, p = 0.56/250 = 0.00224.

For the z-statistic, we have:

\(z=\frac{0.56 \;- \;0.00224}{\sqrt{\frac{0.00224(1\;-\;0.00224)}{250} } }\)

z = 0.55776/0.002990

z = 186.54

p-value = 1 - p(x < z)

p-value = 1 - 1 = 0.

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Answer:

0.28

Step-by-step explanation:

Answer:

285 liters

Step-by-step explanation:

Hello!

Let the number be x.

We multiply it by 5:

5x

Subtract 3:

5x-3

Hope it helps. Ask me if you have any query.

~An excited gal

\(MagicalNature\) here to  help

Answer: 1 is d i think

2 is c i think

Step-by-step explanation:

Answer:

The answer to the first question is C (1,-2)

The answer to the second question is B (-1,3) (4,2) (5,-3) (-5,-2)

If a function f(x) is differentiable on an interval [a, b] and f(a) is less than f(b), it can be shown that there exists at least one point c in the interval (a, b) where the derivative f'(c) is negative.

Since f(x) is differentiable on the closed interval [a, b], it is also continuous on this interval by the differentiability implies continuity theorem. The function values f(a) and f(b) indicate that the function starts at a lower value and ends at a higher value on this interval.

By the Extreme Value Theorem, f(x) must attain its maximum value and minimum value on the interval [a, b]. Let's assume that f(x) achieves its maximum value at some point d in the interval (a, b).

Since f(a) is less than f(d), the function must decrease from a to d to reach its maximum value. This means that the slope of the tangent line at some point c between a and d (exclusive) is negative, indicating a negative derivative f'(c). Therefore, ′ is negative at some point between a and b, as required to be shown.

Similarly, if f(x) achieves its minimum value at some point e in the interval (a, b), the function must increase from a to e. This implies that there exists a point c between a and e (exclusive) where the derivative f'(c) is positive. However, in this case, we are interested in showing that the derivative is negative, so we focus on the case where the maximum value occurs.

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The state that is valid is

"Every diameter of a circle is also a chord because a chord of a circle is any line segment joining two points on the circumference of the circle."

A diameter is a line that divides a circle into two halves, a diameter is also a chord

A chord is a line that connects points on a circle, a chord is not a diameter because it does not divide a circle into two equal halves

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Answer:

A

Step-by-step explanation:

The picture displays an exponential function (a^x)

A is also an exponentional function

B is a rational function

C is an absolute value function

D is a linear function

Therefore, the answer is A

Answer:

A. f(x) = 2x - 3

Step-by-step explanation:

Answer:

linawan mo

Step-by-step explanation:

di ko makita sorry

Answer:

$65.00

Step-by-step explanation:

$60 +$ _ = $125.00

The coefficient of variation is a unit free statistic , the correct option is (B) .

The coefficient of variation (CV) is defined as a statistical measure that expresses the standard deviation as a percentage of the mean.

The coefficient of variation is calculated as ,

⇒ CV = (standard deviation/mean) × 100%

The CV is a unit-free statistic because it doesn't depend on the unit of measurement of the variables being compared. This makes it useful for comparing the variability of variables that are measured in different units.

Therefore , the correct option about the coefficient of variation is (B) .

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Answer: (1,16)

Step-by-step explanation:

The coordinates of a midpoint are given by the midpoint formula:

\((x_m, y_m) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\) where  \((x_m,y_m)\) is the ordered pair for the midpoint,  \((x_1,y_1)\)  is the ordered pair for the first endpoint, and \((x_2,y_2)\) is the ordered pair for the second endpoint.

In this problem, the midpoint is given as \((x_m,y_m) = (-3,7)\)

The known endpoint of XY is X = \((x_1, y_1) = (-7, -2)\)

Y remains unknown so Y =  \((x_2, y_2)\).

If the midpoint is given as (-3,7) we can compare the x value and the y value individually.

-3 = \(\frac{-7+x_2}{2}\)

Solving for \(x_2\), we get \(x_2\) = 1.

7 = \(\frac{-2+y_2}{2}\)

Solving for \(y_2\), we get \(y_2\) = 16.

Thus, the coordinates of Y are (1,16)

Answer:

51.3 degrees

Step-by-step explanation:

Answer:

2, 3, 4, 9, 32, 279, 8928, 2,491,833, 22,236,502,176.

Step-by-step explanation:

To find the first 9 terms of the sequence defined recursively by S_n = S_{n-2} * (S_{n-1} - 1), with S(1) = 2 and S(2) = 3, we can use the recursive formula to calculate each term step by step. Here are the first 9 terms:

S(1) = 2 (given)

S(2) = 3 (given)

S(3) = S(1) * (S(2) - 1) = 2 * (3 - 1) = 2 * 2 = 4

S(4) = S(2) * (S(3) - 1) = 3 * (4 - 1) = 3 * 3 = 9

S(5) = S(3) * (S(4) - 1) = 4 * (9 - 1) = 4 * 8 = 32

S(6) = S(4) * (S(5) - 1) = 9 * (32 - 1) = 9 * 31 = 279

S(7) = S(5) * (S(6) - 1) = 32 * (279 - 1) = 32 * 278 = 8928

S(8) = S(6) * (S(7) - 1) = 279 * (8928 - 1) = 279 * 8927 = 2,491,833

S(9) = S(7) * (S(8) - 1) = 8928 * (2,491,833 - 1) = 8928 * 2,491,832 = 22,236,502,176