I need help and its due Friday! If somone help me if will help so much and ty!!!

Answer:

h = 3V/πr^2

Step-by-step explanation:

\(IF ;\\V = \frac{1}{3} \pi r^2 h\\Make ; h , subject-of-the-formula\\3V = \pi r^2 h\\Divide-both-sides-of-the-equation -by \pi r^2\\\frac{3V}{ \pi r^2} = \frac{ \pi r^2 h}{ \pi r^2 } \\\frac{3V}{ \pi r^2} = h\)

Answer:

Step-by-step explanation:

the answer is

Answer:

She subtracted the GCF from the second term in the expression instead of dividing.

Step-by-step explanation:

Given the expression 32ab-8b, to find the common greatest factor, we will bring out a function that us common to both terms 32ab and 8b. To do that, we need to first find their individual factors as shown:

32ab = (2×2×2)×2×2×a×(b)

8b = (2×2×2×b)

From both factors, the common terms are the values in parenthesis i.e 2×2×2×b = 8b

Hence the GCF of the expression 32ab - 8b is 8b. On factoring out 8b from the expression we will have;

= 32ab - 8b

= 8b(32ab/8b - 8b/8b)

= 8b(4a-1)

Comparing the gotten equation with Venita's own, 8b(4a-0), we can say that she correctly factored out the GCF but her error was that she subtracted 8b from the second term of the expression instead of dividing by 8b. 8b-8b is what gives her 0 making her expression wrong. She should have divided her second term also by 8b to have 8b/8b which results in 1 instead of 0 that venita got.

Answer:b

Step-by-step explanation:

a) By strong induction, any amount of postage worth 8 cents or more can be made from 3-cent or 5-cent stamps.

b) By strong induction, any amount of postage worth 24 cents or more can be made from 7-cent or 5-cent stamps.

c) By strong induction, any amount of postage worth 12 cents or more can be made from 3-cent or 7-cent stamps.

a. Prove that any amount of postage worth 8 cents or more can be made from 3-cent or 5-cent stamps.

Base case: For postage worth 8 cents, we can use two 4-cent stamps, which can be made using a combination of one 3-cent stamp and one 5-cent stamp.

Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 8, can be made from 3-cent or 5-cent stamps.

Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 8, we can use the induction hypothesis to make k cents using 3-cent or 5-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 3-cent stamp, we can replace it with a 5-cent stamp to get the same value. If the last stamp we added was a 5-cent stamp, we can replace it with two 3-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 3-cent or 5-cent stamps.

b. Prove that any amount of postage worth 24 cents or more can be made from 7-cent or 5-cent stamps.

Base case: For postage worth 24 cents, we can use three 8-cent stamps, which can be made using a combination of one 7-cent stamp and one 5-cent stamp.

Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 24, can be made from 7-cent or 5-cent stamps.

Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 24, we can use the induction hypothesis to make k cents using 7-cent or 5-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 5-cent stamp, we can replace it with two 7-cent stamps to get the same value. If the last stamp we added was a 7-cent stamp, we can replace it with three 5-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 7-cent or 5-cent stamps.

c. Prove that any amount of postage worth 12 cents or more can be made from 3-cent or 7-cent stamps.

Base case: For postage worth 12 cents, we can use one 3-cent stamp and three 3-cent stamps, which can be made using a combination of two 7-cent stamps.

Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 12, can be made from 3-cent or 7-cent stamps.

Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 12, we can use the induction hypothesis to make k cents using 3-cent or 7-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 3-cent stamp, we can replace it with two 7-cent stamps to get the same value. If the last stamp we added was a 7-cent stamp, we can replace it with one 3-cent stamp and two 7-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 3

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Answer:

I am getting no solution. Are there any answers that go with the problem?

Answer:

Green paint is made by mixing blue, yellow and white paints in the ratio 2 : 7 : 1. How much blue paint is needed to make 64 litres of green paint? Therefore, the required blue paint = 12.8 litres

Step-by-step explanation:

Answer:

part c is the correct answer to this question

Answer:

p = -10 and p = -5

Step-by-step explanation:

p must be less than -2.5So, the possible value of p from the given options are,p = -10 and p = -5.

The expression that represents the number of football cards that Frankie has is given as follows:

F = J + 65.

The situation can be modeled by a system of equations, in which the variables are given as follows:

Frankie has sixty-five more football cards than his friend John, hence the expression that represents the number of football cards that Frankie has is given as follows:

F = J + 65.

As the term sixty-five more means that the number 65 is added to the amount of cards that John has, which is symbolized by J, to obtain the amount F, which is the number of football cards that Frankie has.

The problem asks for the expression of the number of cards that Frankie has.

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The probability is 3/28, or approximately 0.107.  The probability is (3 * 3) / 28, which simplifies to 9/28, or approximately 0.321.

a) The probability that the two fastest swimmers are from Grade 6 can be calculated by considering the total number of possible outcomes and the number of favorable outcomes. There are a total of 8 swimmers, and we need to select 2 from the 3 swimmers in Grade 6. The number of ways to choose 2 swimmers from a group of 3 is given by the binomial coefficient "3 choose 2" which is equal to 3. The total number of possible outcomes is the number of ways to choose any 2 swimmers from the 8, which is given by the binomial coefficient "8 choose 2" which is equal to 28. Therefore, the probability is 3/28, or approximately 0.107.

b) The probability that the fastest swimmer is from Grade 4 and the second fastest is from Grade 6 can be calculated by considering the total number of possible outcome and the number of favorable outcomes. There are 3 swimmers in Grade 4 and 3 swimmers in Grade 6. We need to select 1 swimmer from Grade 4 and 1 swimmer from Grade 6. The number of ways to choose 1 swimmer from a group of 3 is given by the binomial coefficient "3 choose 1" which is equal to 3. Similarly, the number of ways to choose 1 swimmer from a group of 3 is also 3. The total number of possible outcomes is the number of ways to choose any 2 swimmers from the 8, which is given by the binomial coefficient "8 choose 2" which is equal to 28. Therefore, the probability is (3 * 3) / 28, which simplifies to 9/28, or approximately 0.321.

c) To calculate the probability that Timothy, a student in grade 5, will either come first or second, we need to consider two cases: Timothy coming first and Timothy coming second.

Case 1: Timothy comes first. In this case, there are 8 possible swimmers to choose from, and Timothy is one of them. Therefore, the probability of Timothy coming first is 1/8.

Case 2: Timothy comes second. If Timothy doesn't come first, then there are 7 remaining swimmers to choose from for the first position, and Timothy is one of them. The probability of Timothy coming second is 1/7.

The probability of Timothy coming either first or second is the sum of the probabilities from the two cases, which is (1/8) + (1/7) = 15/56, or approximately 0.268.

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Answer:

15.66

Step-by-step explanation:

2.7 x 11.6/2 is your answer

Answer:

6

Step-by-step explanation:

A = π. r²

36π = π. r²

eliminate π, we get:

36=r²

r=√36

r = 6

Answer:

r = 6

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius )

Given A = 36π , then

πr² = 36π ( divide both sides by π )

r² = 36 ( take the square root of both sides )

r = \(\sqrt{36}\) = 6

λn = (nπ)^2 - 1, and the corresponding eigenfunction is y_n(x) = B sin(nπ x).

The general solution of the differential equation is of the form

y(x) = A sin(√(λ+1) x) + B cos(√(λ+1) x).

Applying the boundary condition y'(0) = 0, we have:

y'(x) = A√(λ+1) cos(√(λ+1) x) - B√(λ+1) sin(√(λ+1) x)

y'(0) = A√(λ+1) cos(0) - B√(λ+1) sin(0) = 0

Here  A = 0.

Applying  the boundary condition y'(1) = 0, we have:

y'(x) = - B√(λ+1) sin(√(λ+1) x)

y'(1) = - B√(λ+1) sin(√(λ+1)) = 0

Which means that √(λ+1) = nπ for n = 1, 2, 3, ...

In conclusiuon,  λn = (nπ)^2 - 1, and the corresponding eigenfunction is y_n(x) = B sin(nπ x).

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The answer is (1) x = 22.5; (2) x = 16.7; (3) x = 13.5; (4) x = 16.8; (5) x = 24.5; (6) x = 16.15; (7.a) height of the image on film is 11.2mm; (7.b) distance between camera and her friend is 1,875mm.

(1) We can see that in the given figure all three corresponding angles are congruent and all three corresponding sides are in equal proportion so, these are similar triangles.

As per properties of similar triangle:

Three pairs of corresponding sides are proportional i.e. Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

                        Therefore, \(\frac{32}{24} =\frac{30}{x}\),

then by cross multiplying them, we get,

                                        32x = 720

                                            x = 720/32

                                           x = 22.5

(2) As, this is already given that these are similar triangle and by applying the properties of similar triangle we get,

                                           \(\frac{39}{26} =\frac{25}{x}\)

                                         39x = 650

                                             x = \(16\frac{2}{3}\)

                                            x = 16.7

(3) As these are similar triangle again we can say that,

                                        \(\frac{2x+1}{x+4} =\frac{40}{25}\)

                                 40(x + 4) = 25(2x + 1)

                                40x + 160 = 50x + 25

                                          40x = 50x - 135

                                          -10x = -135

                 (by cancelling (-) sign from both sides we get,

                                              x = 135/10

                                             x = 13.5

(4) By applying similar triangle's property, we can get

                                           \(\frac{20}{30} =\frac{28-x}{x}\)

                                         20x = 840 - 30x

                                         50x = 840

                                             x = 840/50

                                             x = 16.8

(5) As ΔJKL \(\sim\) ΔNPR,

                                           \(\frac{KM}{PT} =\frac{KL}{PR}\)

                                          \(\frac{18}{15.75} =\frac{28}{x}\)

                                            18x = 441

                                                x = 441/18

                                               x = 24.5

(6) As ΔSTU \(\sim\) ΔXYZ,

                                         \(\frac{UA}{ZB} =\frac{UT}{ZY}\)

                                        \(\frac{6}{11.4} =\frac{8.5}{x}\)

                                          6x = 96.6

                                            x = 96.6/6

                                            x = 16.15

(7.a) First we have to change 3 m and 140 cm into mm(millimeters).

So, 1m = 1000 mm

     3m = 3000mm.

And 1cm = 10 mm

   140cm = 1400 mm.

Then to find the height of the image on the film, we have to solve:

                                          \(\frac{24}{3000} =\frac{x}{1400}\)

             by cross multiplication we get,

                                      3000x = 33,600

                                               x = 33,600/3000

                                              x = 11.2 mm

the height of the image on the film is 11.2millimeters.

(7.b) For this also, we have to find x by solving the equation:

                                            \(\frac{24}{3000} =\frac{15}{x}\)

                                            24x = 45,000

                                                x = 45,000/24

                                              x = 1,875 mm

The distance between camera and her friend is 1,875 millimeters.

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Full question is given below in the image.

Answer:

Graph the line starting at the y intercept (-5), count up 1 and left 3 (because \(\frac{1}{3}\) is negative). Once you have a few points draw the line to connect them.

Step-by-step explanation:

the slope is negative and the y-intercept is at -5

Answer:

Answer

a Geometry :- shapes Are composed of regular lines and curves

b Organic shapes:- Unpredictable, irregular lines that suggest the natural world. Chaotic and unrestrained.

c Texture :-The surface quality of a work of art , for example coarse/fine detailed/lacking details

right answer organic..

i hope this helps you (⁠ ⁠◜⁠‿⁠◝⁠ ⁠)⁠♡

Therefore, An unpredictable and irregular shape is called an organic shape.

These shapes often mimic the forms found in nature, such as the shape of a leaf or a tree branch. Organic shapes lack the symmetry and geometric precision of their counterpart, the geometric shape. In art, organic shapes are commonly used to create a sense of movement, flow, and naturalism in a composition. In design, organic shapes can add visual interest and break up the monotony of straight lines and sharp angles. To sum up, the type of shape composed of unpredictable, irregular lines is an organic shape.

Therefore, An unpredictable and irregular shape is called an organic shape.

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Step-by-step explanation:

\( \underline{ \text{Let \: the \: required \: number \: be \: x}} : \)

\( \text{According \: to \: question \: (ATQ)} : \)

⟼ \( \tt{ \frac{1}{3} \times x = 7}\)

⟼ \( \tt{ \frac{1 \times x}{3} = 7}\)

⟼ \( \tt{ \frac{x}{3} = 7}\)

Apply cross product property :

⟼ \( \boxed{ \sf{x = 27}}\)

\( \pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \underline{ \tt{x = 27}}}}}}\)

Hope I helped ! ♡

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joke 1. 2 hunters were out in the woods right while they were following fresh tracks from a big elk one of the hunters drop to the ground and his eyes roll backwards so the other hunter whips out his phone and calls the hospital "I THINK MY FRIEND IS DEAD!" he told the doctor the doctor told him " Calm down let's make sure he's dead. so there is a moment of silence the you here a big pop the hunter says "NOW WHAT!"     (he shot his friend)

joke 2. I wanted to be a democrat for halloween but i could not stick my head far enough up my a/s/s to be one.

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x=2/3

6(2/3) + 4 9/10 =4 + 4 9/10 = 8 9/10

Answer:

2x-1=y,2y+3=x

Step-by-step explanation:

no explanation

The area of the smaller sector or minor sector is  125.66 yd².

The area of the larger sector or major sector is  326.73 yd².

The areas of the minor and major sectors is calculated by applying the following formulas follow;

Area of sector is given as;

A = (θ/360) x πr²

where;

The area of the smaller sector or minor sector is calculated as follows;

A = ( 100 / 360 ) x π ( 12 yd)²

A = 125.66 yd²

The area of the larger sector or major sector is calculated as follows;

θ = 360 - 100

θ = 260⁰

A =  ( 260 / 360 ) x π ( 12 yd)²

A = 326.73 yd²

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Answer:

text me I will show you how to solve it

(7) The volume of the square base pyramid is 122.5 in³.

(8) The volume of the equilateral base pyramid is 311.8 cm².

(9)  The volume of the square base pyramid is 2,880 ft³.

The volume of the pyramids is calculated by applying the following formula as follows;

(7) The volume of the square base pyramid is calculated as;

V = ¹/₃Bh

where;

V = ¹/₃ x (7 in x 7 in ) x 7.5 in

V = 122.5 in³

(8) The volume of the equilateral base pyramid is calculated as;

V = ¹/₃Bh

V = ¹/₃ x (a²√3/4) x h

V =  ¹/₃ x (12²√3/4) x 15

V = 311.8 cm²

(9)  The volume of the square base pyramid is calculated as;

V = ¹/₃Bh

where;

V = ¹/₃ x (24 ft x 24 ft ) x 15 ft

V = 2,880 ft³

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The acceleration vector of the particle at time t=1/2 is {12, 4y''(1)}. To get the acceleration vector of the particle at time t=1/2, we need to first find the velocity and acceleration vectors in terms of position and acceleration.

Here, position vector is {4t^3, y(2t)}. We need to find the derivatives with respect to time t to find the velocity and acceleration vectors.
Step 1: Find the velocity vector by taking the first derivative of the position vector.
Velocity vector = {d(4t^3)/dt, dy(2t)/dt}
Velocity vector = {12t^2, y'(2t) * 2}
Step 2: Find the acceleration vector by taking the second derivative of the position vector or the first derivative of the velocity vector.
Acceleration vector = {d(12t^2)/dt, d(y'(2t) * 2)/dt}
Acceleration vector = {24t, 4y''(2t)}
Step 3: Plug in t=1/2 into the acceleration vector equation to find the acceleration vector at that time.
Acceleration vector at t=1/2 = {24(1/2), 4y''(2(1/2))}
Acceleration vector at t=1/2 = {12, 4y''(1)}
The acceleration vector of the particle at time t=1/2 is {12, 4y''(1)}.

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The classroom had 24 glue bottles.

We have,

If the ratio of glue sticks to glue bottles is 7 : 4, we can express this as 7/4.

We can set up a proportion to solve for the number of glue bottles:

7/4 = 42/x

where x is the number of glue bottles. To solve for x, we can cross-multiply:

7x = 4 x 42

7x = 168

x = 24

Therefore,

The classroom had 24 glue bottles.

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Answer:

Step-by-step explanation:

The missing reasons are Cofunction identity, Cosine difference identity, Cofunction identity, Cosine function is even and sine function is odd respectively.

Given:

The given expression is \(\sin (x-y)\).

To find:

The justification for each step.

Explanation:

Cofunction identities:

\(\sin\left(\dfrac{\pi}{2}-x\right)=\cos x\)

\(\cos\left(\dfrac{\pi}{2}-x\right)=\sin x\)

Cosine difference identity:

\(\cos(x-y)=\cos x\cos y+\sin x\sin y\)

Cosine function is even, so \(\cos(-x)=\cos x\).

Sine function is odd, so \(\sin(-x)=-\sin x\).

We have,

\(\sin (x-y)\)

\(=\cos\left|\dfrac{\pi}{2}-(x-y)\right|\)                                             Step 1: Cofunction identity

\(=\cos\left|\dfrac{\pi}{2}-x+y\right|\)                                                 Step 2: Distributive property

\(=\cos\left|\left(\dfrac{\pi}{2}-x\right)+y\right|\)                                            Step 3: Associative property

\(=\cos\left|\left(\dfrac{\pi}{2}-x\right)-(-y)\right|\)                                        Step 4: Factoring out   

\(=\cos\left(\dfrac{\pi}{2}-x\right)\cos(-y)+\sin\left(\dfrac{\pi}{2}-x\right)\sin(-y)\)       Step 5: Cosine difference identity

\(=\sin(x)\cos(-y)+\cos(x)\sin(-y)\)                           Step 6: Cofunction identity

\(=\sin(x)\cos(y)-\cos(x)\sin(y)\)                                Step 7: Cosine function is even, sine function is odd

Therefore, the missing reasons are Cofunction identity, Cosine difference identity, Cofunction identity, Cosine function is even, sine function is odd respectively.

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The area of the acute triangle can be found by the formula: area of acute triangle = (1/2) × b × h.

According to Pythagoras theorem the triangle is termed as acutely angled if the square of its longest side is less than the sum of the squares of two other smaller sides. Let a, b, and c are the length of sides of a triangle, where side "a" is the longest, then the given triangle is acutely angled if and only if a^2 < b^2 + c^2.

The area of the acute triangle can be calculated by the formula:

         area of acute triangle = (1/2) × b × h

         b = base, and

         h = height

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Answer:  b

Step-by-step explanation:

I think

The conversion of  730 km into miles is 456.70 miles so Maria drives 456.70 miles.

To convert any unit into another is called a unit conversion.

In order to convert units, we need to care about their dimensions their dimension should not be changed.

For example conversion of a kilometer to a meter is to multiply by 1000 but meter and kilometer both unit is for distance only.

Distance = 730 kilometers.

Since given that,

1 mile =1.609 kilometers

So,

1 kilometer = 1/1.609 miles

So,

730 kilometers = 730 × 1/1.609 miles

⇒ 456.70 miles

Hence "The conversion of  730 km into miles is 456.70 miles so Maria drives 456.70 miles".

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To answer this question, we'll use the exponential distribution and the concept of the probability density function (pdf). Let X be the time until failure of a single device, with a mean lifetime of 20 months. The exponential distribution has the following pdf:

f(x) = (1/μ) * e^(-x/μ),

where μ is the mean lifetime (20 months in this case).

Now, let's find the probability that the first failure occurs at w months among the 5 independent devices. For this, we need to calculate the probability that none of the other 4 devices fail before w months and that the first device fails at w months.

The probability that a single device does not fail before w months is given by the complementary cumulative distribution function (ccdf) of the exponential distribution:

P(X > w) = e^(-w/μ).

Since the devices are independent, the probability that all 4 devices do not fail before w months is:

P(All 4 devices survive > w) = (e^(-w/μ))^4.

Now, the probability that the first device fails at w months is given by the pdf of the exponential distribution:

P(X = w) = (1/μ) * e^(-w/μ).

Finally, we multiply the two probabilities to find the chance that the first failure occurs at w months:

P(First failure at w) = P(All 4 devices survive > w) * P(X = w)
= (e^(-w/μ))^4 * (1/μ) * e^(-w/μ)
= (1/20) * e^(-5w/20).

Thus, the chance that the first failure will occur at w months is given by the expression (1/20) * e^(-5w/20).

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