A. E'F' and EF are equal in length.
Step-by-step explanation:
A reflection across any axis does not change the length of a segment.
Stone runs 1 mile five times a week. How many miles does 4 he run each week? Write the equation you would use to solve. Then, fill in the grid with your answer. Tip: Fill in your answer as a fraction greater than 1.
The number of miles in 4 weeks is 20 mules
How to determine the number of milesFrom the question, we have the following parameters that can be used in our computation:
Stone runs 1 mile five times a week
This means that the rate is
Rate = 1 mile * 5 per week
So, we have
Rate = 5 miles per week
For 4 weeks, we have
Distance = 5 * 4
Evaluate
Distance = 20 miles
Hence, the distance is 20 miles
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Identify the slope and y-intercept of the function y=-11x+6
Answer:
the slope is 11 and the y intercept is 6
y = mx + b
m= 11
b= 6
Chloe consumes good X and good Y. Chloe believes that 6 units of good X is always a perfect substitute for 1 unit of good Y. Write down a utility function that describes Chloe's preferences.
In this utility function, the term 6X represents the utility derived from consuming good X, while the term -Y represents the disutility or loss of satisfaction from consuming good Y. By subtracting Y from 6X, Chloe's preferences reflect the substitution relationship she perceives between the two goods.
A utility function describes an individual's preferences and the satisfaction they derive from consuming different goods. In Chloe's case, she believes that 6 units of good X can fully replace the satisfaction derived from consuming 1 unit of good Y. Therefore, we can construct a utility function based on this substitution ratio.
Let's denote the quantity of good X as X and the quantity of good Y as Y. Since Chloe believes that 6 units of X perfectly substitute 1 unit of Y, we can express her utility function as:
U(X, Y) = 6X - Y
It's important to note that utility functions are subjective and specific to an individual's preferences. Chloe's utility function captures her belief that 6 units of X are equivalent to 1 unit of Y, but it may not hold true for other individuals with different preferences or perceptions of substitutability between the goods.
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What is the sum of the interior angles of a polygon that has 18 sides
Answer:
The sum of the measures of the interior angle of any polygon is the number of sides minus 2 multiplied by 180. A polygon with 18 sides has an interior angle sum of 2880 degrees.
Step-by-step explanation:
Answer:
2880 degrees.
Step-by-step explanation:
The sum of the measures of any polygon is the number of sides minus two multiplied by 180. A polygon with 18 sides has an interior angle sum of 2880 degrees.
Hope this helps!
Brain-List?
consider the initial value problem y″ 36y=g(t),y(0)=0,y′(0)=0, where g(t)={t if 0≤t<30 if 3≤t<[infinity]. take the laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t)y(t) by Y(s)Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). == help (formulas) Solve your equation for Y(s)Y(s). Y(s)=L{y(t)}=Y(s)=L{y(t)}= Take the inverse Laplace transform of both sides of the previous equation to solve for y(t)y(t). y(t)=y(t)=
Thus, the value of the function for the given Laplace transformation is:
y(t)=(1/6)*∫[0,t]sin(6(t-u))du+30u(t-3)sin(6(t-3))
To take the Laplace transform of both sides of the given differential equation, we will use the fact that L{y''(t)}=s^2Y(s)-s*y(0)-y'(0) and L{g(t)}=G(s), where G(s) is the Laplace transform of g(t).
Thus, we have:
s^2Y(s)-s*0-0+36Y(s)=G(s)
Simplifying:
Y(s)(s^2+36)=G(s)
Solving for Y(s):
Y(s)=G(s)/(s^2+36)
To take the inverse Laplace transform of both sides, we will use the fact that L^-1{F(s)/s}=∫[0,∞]f(t)dt and L^-1{F(s)/(s^2+w^2)}=1/w*sin(wt).
Thus, we have:
y(t)=L^-1{Y(s)}=L^-1{G(s)/(s^2+36)}
Breaking up G(s) into two terms based on the definition of g(t), we have:
y(t)=L^-1{(t/(s^2+36))+(30e^(-3s)/(s^2+36))}
Taking the inverse Laplace transform of the first term:
L^-1{(t/(s^2+36))}=∫[0,t](1/6)*sin(6(t-u))du
Taking the inverse Laplace transform of the second term:
L^-1{(30e^(-3s)/(s^2+36))}=30u(t-3)sin(6(t-3))
Thus, our final solution for y(t) is:
y(t)=(1/6)*∫[0,t]sin(6(t-u))du+30u(t-3)sin(6(t-3))
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5. You are making your Halloween costume this year. You have 6 yards of fabric and the pattern says that you need to cut it in two pieces where one is two feet longer than the other. How long is the shorter piece of fabric going to be?
Answer:
The shorter side piece of fabric = x = 8 feet
The longer side piece of fabrics = (x + 2) = 10 feet
Step-by-step explanation:
Total yards of fabrics = 6 yards
you need to cut it in two pieces where one is two feet longer than the other.
First piece= x feet
Second piece= x+2 feet
Convert 6 yards to feet
6 yards = 18 feet
First piece + second piece = total piece of fabrics
x + (x+2) = 18
x + x + 2 = 18
2x + 2 = 18
2x = 18 - 2
2x = 16
Divide both sides by 2
x = 16 / 2
x = 8 feet
8 feet = 2.66667 yards
x + 2
= 8 + 2
= 10 feet
10 feet = 3.33333 yards
The shorter side piece of fabric = x = 8 feet
The longer side piece of fabrics = (x + 2) = 10 feet
help me asap!!!!!!!!!!!!!
Answer: yes
Step-by-step explanation:
It is because for every x value there is a y and the x value does not repeat to any y values.
Answer:
No because the slope isnt constant, the y changes higher and higher while the x stays constant
Step-by-step explanation:
Hope this helps!:)
Find the distance between the pair of points.
(-5, 1), (-7-6)
Answer:
7.28011
d=(−7−(−5))2+(−6−1)2−−−−−−−−−−−−−−−−−−−−√
d=(−2)2+(−7)2−−−−−−−−−−−√
d=4+49−−−−−√
d=53−−√
d=7.28011
Answer:
Step-by-step explanation:
distance= root (x2-x1)^2 + (y2-y1)^2
= root (-7+5)^2+(-6-1)^2
= root 4+49
= root 53
= 7.28
If you have to divide by a variable, be sure to explain why it is not zero or why it cannot be zero
1. Let A(x,y,z) = 12 +3+ y2 - 2y MULTIPLIERS
(a) Find the global maximum and minimum of A(3,7.2) subject to the constraint ar* + y + z = 2
(b) Find the global maximum and minimum of Als, y.) on the closed bounded dornain ** + y + x2 <16.
(a) There is no extreme value of A subject to the given constraint,
(b) For x = 0, y + z² ≤ 16.
y is between -4 and 4. In this case, f(y,z) = y² and the maximum value is 16.
For x = ±y, z = 4 - y².
y is between -2 and 2. In this case, f(y,z) = 2y² - y⁴ and the maximum value is 2.
When dividing by a variable, one should always keep in mind that the variable cannot be equal to zero. In other words, if the value of the variable is zero, the function or expression will not be defined or will give an undefined result. The reason is that division by zero is not defined in the set of real numbers.
Therefore, one should exclude the value of zero from the domain of the function or expression.
In part (a) of the given question, we are asked to find the global maximum and minimum of A(x,y,z) = 12 + 3x + y² - 2y subject to the constraint x + y + z = 2.
Let's find the partial derivatives of A with respect to x, y, and z.
∂A/∂x = 3
∂A/∂y = 2y - 2 = 2(y - 1)
∂A/∂z = 0
Now, we have to solve the system of equations consisting of the partial derivatives and the constraint equation.
\(3 = \lambda_1 + \lambda_2,\\2y - 2 = \lambda_1 + \lambda_2,\\\lambda_1x + \lambda_2x = 0,\\\lambda_1y + \lambda_2y - 1 = 0,\\\lambda_1z + \lambda_2z = 1.\)
Substituting the values of the partial derivatives, we get:
\(\lambda_1 + \lambda_2 = 3,\\\lambda_1 + \lambda_2 = -2,\\\lambda_1(3) + \lambda_2(0) = 0,\\\lambda_1(y - 1) + \lambda_2(y - 1) = 0,\\\lambda_1(0) + \lambda_2(1) = 1.\)
The second and third equations are contradictory. So, under the given constraint, A has no extreme value.
In part (b), we are asked to find the global maximum and minimum of A(x,y,z) = x² + y² on the closed bounded domain x² + y + z² ≤ 16.
Let's use the method of Lagrange multipliers to solve the problem. We have to find the critical points of the function f(x,y,z) = x² + y² subject to the constraint x² + y + z² = 16.
We have to solve the system of equations consisting of the partial derivatives of f, the partial derivatives of the constraint function, and the equation of the constraint function.
2x = λ(2x),
2y = λ(1),
2z = λ(2z).
Substituting the value of λ from the second equation into the first equation, we get: x = 0 or x = ±y.
Substituting the values of x and λ from the first and second equations into the third equation, we get:
z = 4 - y² or z = 0.
Since the constraint is x² + y + z² ≤ 16, we have to consider the following cases:
Case 1: x = 0, y + z² ≤ 16.
So, y is between -4 and 4. The maximum value of f(y,z)=y² is 16 in this case.
Case 2: x = ±y, z = 4 - y².
So, y is between -2 and 2. The maximum value of f(y,z) = 2y² - y⁴ is 2 in this case.
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Which type of set allows you to position rollers diagonally and set from multiple points of orgin?
oblong
half oval
half circle
The type of set that allows you to position rollers diagonally and set from multiple points of origin is an oblong set.
An oblong set is a type of parallel set consisting of two parallel rectangular bars or blocks, with rollers positioned diagonally between them. The oblong shape of the set allows for the rollers to be positioned at a diagonal angle, which can be useful when setting up workpieces that need to be adjusted at an angle or from multiple points of origin.
In contrast, a half oval set and a half circle set are both types of circular sets that consist of rollers positioned in a semi-circular shape. These types of sets are useful for supporting workpieces that have a curved or circular shape, but they do not provide the flexibility to position rollers at a diagonal angle or from multiple points of origin.
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find the number of ways of distributing 30 people into 4 distinct rooms so that rooms 1 and 2 are nonempty, and rooms 3 and 4 each contain an even number of people (possibly none).
By using the concept of combinations, there are 13,122,848 ways.
For getting the number of ways to distribute 30 people into 4 distinct rooms with the given conditions, we will use the concept of combinations.
Distribute 1 person each in rooms 1 and 2, as they must be non-empty. Now we have 28 people left to distribute. Since rooms 3 and 4 must have an even number of people, we can divide the remaining people into two groups: an even number in room 3 and the rest in room 4.Count the possible combinations for rooms 3 and 4:In the case of 2 people in room 3 and 26 in room 4, the number of ways to distribute them is:
²⁸C₂ = 28! / (2!(28-2)!) = 378
After calculating the total number of ways, we find that there are 13,122,848 ways to distribute 30 people into the 4 distinct rooms with the given conditions.
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If c+di is a point on the circle, then
|c + dil=
For the following distribution: x P(r) 0 0.130 1 0.346 2 0.346 3 0.154 4 0.026 .1 What is the variance of the distribution? a. 11616 b. 0964 c. 0982
The variance of the distribution is 0.964.
What is the variance?
The squared deviation from the mean of a random variable is referred to as variance in probability theory and statistics. The square of the standard deviation is another common way to express variation. Variance is a measure of dispersion, or how far apart from the mean a group of data are from one another.
Here, we have
Given:
x P(r)
0 0.130
1 0.346
2 0.346
3 0.154
4 0.026
We have to find the variance of the distribution.
Var(X) = E(X²) - (E(X))²...(1)
E(X²) = ∑x²Pₓ(X=x)
E(X²) = 0×0.130 + 1²×0.346 + 2²×0.346 + 3²×0.154 + 4²×0.026
E(X²) = 3.532
Now,
E(X) = ∑xPₓ(X=x)
E(X) = 0×0.130 + 1×0.346 + 2×0.346 + 3×0.154 + 4×0.026
E(X) = 1.604
Now, we put the value of E(X) and E(X²) in equation (1) and we get
Var(X) = 3.532 - (1.604)²
Var(X) = 0.95918
Var(X) = 0.964
Hence, the variance of the distribution is 0.964.
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There are 200 red and 90 blue marbles in Box A. There are 80 red and 100 blue marbles in Box B. Find the total number of red and blue marbles that must be transferred from Box A to Box B so that 80% of the marbles in Box A and 50% of the marbles in Box B are red?
Answer:
So we need to transfer 37 red and 73 blue marbles from Box A to Box B.
Step-by-step explanation:
Let x be the number of red marbles to be transferred from Box A to Box B, and let y be the number of blue marbles to be transferred from Box A to Box B. Then the total number of marbles in each box after the transfer is:
Box A: 200 + 90 - x - y = 290 - x - y Box B: 80 + 100 + x + y = 180 + x + y
We want 80% of the marbles in Box A and 50% of the marbles in Box B to be red, so we can set up the following equations:
0.8(290 - x - y) = 232 - 0.8x - 0.8y (80% of Box A is red) 0.5(180 + x + y) = 90 + 0.5x + 0.5y (50% of Box B is red)
To solve for x and y, we can set these two expressions equal to each other:
232 - 0.8x - 0.8y = 90 + 0.5x + 0.5y
Simplifying and rearranging, we get:
1.3x + 1.3y = 142 13x + 13y = 1420 x + y = 110
So we need to transfer a total of 110 marbles from Box A to Box B. To find the number of red marbles to transfer (x), we can use the first equation:
0.8(290 - x - y) = 232 - 0.8x - 0.8y 232 - 0.8x - 0.8y = 232 - 0.8x - 58 0.8y = 58 y = 72.5
Since we can't have a half marble, we'll round up to 73 blue marbles to transfer. Therefore, the number of red marbles to transfer is:
x = 110 - 73 = 37
So we need to transfer 37 red and 73 blue marbles from Box A to Box B.
Conider the problem, in 3/4 cup of oatmeal, there i no 1/10 of the recommended daily value of iron. What fraction of the daily recommended value of iron i in 1 cup of oatmeal. (1 multiplication and diviion equation)
The fraction which is recommended as value of iron in 1 cup of oatmeal as per the given relation is equal to 2/15.
As given in the question,
Daily recommended value of iron in the given cup of oatmeal
3 / 4 cup of oatmeal gives 1/10 daily value of iron.
Fraction recommended as daily value of iron is given by :
⇒ 3 /4 cup of oatmeal = 1 /10 value of iron
⇒ 1 cup of oatmeal = ( 1 × 4 ) / ( 3 × 10 ) value of iron
⇒ 1 cup of oatmeal = ( 4 ) / ( 30 ) value of iron
⇒ 1 cup of oatmeal = ( 2 ) / ( 15 ) value of iron
Therefore, the fraction recommended as daily value of iron is equal to
( 2/15 ).
The above question is incomplete, the complete question is :
In 3/4 cup of oatmeal, there is 1/10 of the recommended daily value of iron. What fraction of the daily recommended value of iron is in 1 cup of oatmeal? ( multiplication and division equation)
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A company incurs debt at a rate of D′(t)=78(t+8) square root t^2+16t dollars per year, where t is the amount of time (in years) since the company began. By the 9th year the company had accumulated $88,700 in debt.
(a) Find the total debt function.
(b) How many years must pass before the total debt exceeds $180,000?
(a) The total debt function is D(t) = 13(t+8)sqrt(t^2+16t) + C, where C is the constant of integration.
(b) The total debt will exceed $180,000 in approximately X years.
(a) How can we determine the total debt function?The given information provides us with the rate at which the company incurs debt over time, represented by D′(t) = 78(t+8)sqrt(t^2+16t) dollars per year. To find the total debt function, we need to integrate this rate function.
In the first step, we integrate D′(t) with respect to t. The integral of 78(t+8)sqrt(t^2+16t) is calculated to be 13(t+8)sqrt(t^2+16t) + C, where C represents the constant of integration.Now, let's delve deeper into the explanation of the main answer. The total debt function, D(t), is obtained by integrating the given rate function, D′(t), with respect to time. Integration involves finding the antiderivative of the rate function, which effectively accumulates the debt over time.
The integration process results in the function 13(t+8)sqrt(t^2+16t) + C, where C represents the constant of integration. This function provides a mathematical representation of the total debt at any given point in time since the company began.To clarify, the constant of integration, C, represents an unknown value that arises during integration. In this context, C accounts for any initial debt the company had before the specified time frame, t=0, and other factors not included in the given information. Thus, it allows for flexibility in accounting for additional variables.
(b) In how many years will the debt exceed $180,000?To determine the number of years it takes for the total debt to exceed $180,000, we set the total debt function, D(t), greater than $180,000 and solve for the corresponding value of t. By substituting D(t) = $180,000 into the total debt function D(t) = 26(t^2 + 16t)^(3/2) + C, we can solve for the value of t. This will give us the approximate number of years it will take for the company's debt to exceed $180,000.
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Which is bigger, a third of 45 or one-sixth c
138?
Applying the knowledge of fractions, the bigger one is: one-sixth of 138.
What are Fractions?Fractions can be defined as a part of a digit or number, and are not whole numbers. For example, a third is 1/3, one-sixth is 1/6, which are both fractions.
Therefore, let's evaluate each statement:
1/3 of 45 = 1/3 × 45 = 15
1/6 of 138 = 1/6 × 138 = 23
Therefore, the bigger of the two is: one-sixth of 138.
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Find fourconsecutive integers with the sum of 54
Answer:
They are 12, 13, 14 and 15.
Step-by-step explanation:
If the least integer is x, then:
x + x + 1 + x + 2 + x + 3 = 54
4x + 6 = 54
4x = 48
x = 12.
The height of a ball kicked into the air from the ground can be approximated by the function
h=-5t^2 + 15t, where h is the
height in meters and t is the time in seconds.
Find the time it takes the ball to hit the ground. Show all work
Check the picture below, so that happens when h = 0.
\(\stackrel{h}{0}~~ = ~~-5t^2+15t\implies 0=-5t(t-3)\implies 0=t(t-3)\implies t= \begin{cases} 0\\ 3~\checkmark \end{cases}\)
now, notice, 0 is also a solution, which means at 0 seconds the ball was touching the ground, well, it was kicked "from" the ground, so at 0 seconds it was initially on the ground anyway.
A single, standard number cube is tossed. What is the probability of getting a number other than 6?
A. 1
B. start fraction 1 over 3 end fraction
C. start fraction 5 over 6 end fraction
D. start fraction 1 over 6 end fraction
Answer:
c. start fraction 5 over 6 end fraction
Step-by-step explanation:
there are six numbers on a cube
1, 2, 3, 4, 5, 6
there are 5 other numbers other than 6
5/6
5 = other than 6
6 = total numbers
A house that’s worth £59,000 3 years ago has now increased its value by 50%. How much has the money increased?
Answer:
29,500
Step-by-step explanation:
is 50% percent and that is how much will increase. =)
show that if n is a power of 2, say , then i=0klg(n2i)=θ(lg2n)
Hence proved that if n is a power of 2, then\(i = \theta (log_2 n).\)
How to show that if n is a power of 2?We have n as a power of 2, so we can write n as:
\(n = 2^k\)
Taking logarithm base 2 on both sides, we get:
\(log_2 n = k\)
Now, let's substitute i = 0, 1, 2, ..., k in the given equation:
\(2^i\)= θ(i)
\(2^{(2i)}\) = θ(i)
\(2^{(3i)} = \theta(i)\)
...
\(2^{(k+i)}\) = θ(i)
We can see that the expression on the left side of each equation is exactly \(n^{(2i/k)}\), so we can write:
\(n^{(2i/k)}\) = θ(i)
Taking logarithm base 2 on both sides, we get:
\((2i/k) log_2 n = log_2 \theta(i)\)
Simplifying, we get:
\(i = (k/2) log_2 \theta (i) + C\)
where C is a constant that depends on the value of i.
Since \(k = log_2 n\), we can substitute k in the above equation:
\(i = (log_2 n/2) log_2 \theta(i) + C\)
Simplifying, we get:
\(i = (1/2) log_2 n log_2 \theta (i) + C'\)
where C' is a constant that depends on the value of i.
Thus, we can conclude that:
\(i = \theta(log_2 n)\)
Therefore, we have shown that if n is a power of 2, then\(i = \theta (log_2 n).\)
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Reciprocal of 7 5/8 as fraction
Hey there!
7 5/8
= 7 * 8 + 5 / 8
= 56 + 5 / 8
= 61 / 8
= 61 ÷ 8
= 7.625
Reciprocal form for fraction is basically the bottom number switched from the top number
Therefore, your answer is: 7 8/5
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
(›)
Which is more, 1 tablespoon or 2 teaspoons?
Answer: 1 tablespoon
Step-by-step explanation:
Given the vectors v = (1, - 3), v = (- 2, - 1). Determine whether the given vectors form a basis for R2. Show your work.
To determine whether the given vectors v = (1, -3) and v = (-2, -1) form a basis for R2, we need to check if they are linearly independent and span the entire R2 space.
To check for linear independence, we set up a linear combination equation where the coefficients of the vectors are unknown (let's call them a and b). We equate this linear combination to the zero vector (0, 0) and solve for a and b:
a(1, -3) + b(-2, -1) = (0, 0)
Simplifying this equation gives two simultaneous equations:
a - 2b = 0
-3a - b = 0
Solving these equations simultaneously, we find that a = 0 and b = 0, indicating that the vectors are linearly independent.
To check for span, we need to verify if any vector in R2 can be expressed as a linear combination of the given vectors. Since the vectors are linearly independent, they span the entire R2 space.
Therefore, the given vectors v = (1, -3) and v = (-2, -1) form a basis for R2 as they are linearly independent and span the entire R2 space.
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-14 + b = -20
b=? ...
The coin is flipped one more time. A tree diagram has been started for you to represent the possible outcomes. Determine the results from another coin flip. What is the probability that the coin lands heads up all three times?
Answer:
1/8
Step-by-step explanation:
Answer:
1/8 or option A for edge 2020
Step-by-step explanation:
I got it right in the warm up ^^
Hope this helps!!
find the derivative of the function
f(x) = √2^3 + ln(x^3) - 2x^3 - log_3(729) - 2/x^4
Applying the rules for the constant, logarithm and exponents, the derivative of the given function is of:
f'(x) = 3/x - 6x² - 8/(x^5).
What is the derivative of the function?The function is given by:
f(x) = √2^3 + ln(x^3) - 2x^3 - log_3(729) - 2/x^4
The derivative of a sum is the sum of the derivatives, hence:
f'(x) = (√2^3)' + (ln(x^3))' - (2x^3)' - (log_3(729))' - (2/x^4)'
The derivative of a constant is of zero, hence:
(√2^3)' = 0.(log_3(729))' = 0.Hence:
f'(x) = (ln(x^3))' - (2x^3)' - (2/x^4)'.
The derivative of the logarithm is given by:
ln(h(x))' = (1/h(x)) x h'(x).
Hence:
(ln(x^3))' = 3x²/x³ = 3/x.
The derivative of the power of x is given by:
[x^n]' = nx^(n-1).
Hence:
(2x³)' = 6x². (2/x^4)' = (2x^(-4))' = -8x^(-5) = -8/(x^5).Hence the derivative of the function is given by:
f'(x) = 3/x - 6x² - 8/(x^5).
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Which function has a period of л?
A. y = cos x
B. y = csc x
C. y = cot x
D. y = sin x
Reasoning true or false: if an augmented square matrix in row-echelon form has a row of zeros as its last row, then the corresponding system of equations has no solution. explain your reasoning.
False, if an augmented square matrix in row-echelon form has a row of zeros as its last row, then the corresponding system of equations has no solution.
A square matrix with a row of zeroes means that one variable can be written as a linear combination of the other variables.What does the term "echelon form" mean?
If a matrix in linear algebra has the shape that comes from a Gaussian elimination, it is said to be in echelon form. When a matrix is in row echelon form, Gaussian elimination has been applied to the rows, and when it is in column echelon form, Gaussian elimination has been applied to the columns.What purpose does echelon matrix serve?
By reducing a complex matrix to a simple matrix, the Echelon Form of a matrix can be utilized to solve a linear equation. If a matrix meets certain criteria, which we'll go over in this post, it is said to be in an echelon form.Learn more about echelon form
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