i need help with this please​

The buyer should purchase 87913 bales to ensure that he has at least 2000 bales that weigh 420 kilograms each.

For having a bale of 420 and above,

we calculate standard deviation using below information

(420 - 376 /22) = 0.02275 = 2.275% chance of having a bale of 420+ kg

To find out the number of bales to pe precise,

2000/0.02275 = 87912.1 so you'll need at the very least 87913 bales to be reasonably certain.

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the established mean.

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Answer:

7

Step-by-step explanation:

The solution to the equation is x = -2, -1.46, -1, x = 5.46

From the question, we have the following parameters that can be used in our computation:

0 = x^{5}+x^{4}-20x^{3}-68x^{2}-80x-32

Express properly

So, we have

x^5 + x^4 - 20x^3 -68x^2 -80x - 32 = 0

Next, we plot the graph of x^5 + x^4 - 20x^3 -68x^2 -80x - 32 = 0 to determine the solution graphically

See attachment for graph

From the graph, we have

x = -2, -1.46, -1, x = 5.46

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49.2 calories are in  would that contribute per serving .

What does a calorie mean ?

Carbohydrates provide 4 calories per gram.

              1 gm Carbohydrates = 4 calories

 then 12.3 gm Carbohydrates  = 12.3 * 4

                                             = 49.2 calories

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(i) The first fundamental form of x(u,v)=(u−v,u+v,u²+v²) is given by E = 4, F = 0, and G = 2.
(ii) The first fundamental form of x(u,v)=(coshu,sinhu,v) is given by E = 1, F = 0, and G = 1.


To calculate the first fundamental forms of the given surfaces, we need to find the coefficients E, F, and G. These coefficients are defined as follows:

E = x_u · x_u
F = x_u · x_v
G = x_v · x_v

For the first surface x(u,v)=(u−v,u+v,u²+v²):
- Differentiating x(u,v) with respect to u and v, we get x_u=(1,-1,2u) and x_v=(1,1,2v).
- Calculating the dot products, we find that E = x_u · x_u = 4, F = x_u · x_v = 0, and G = x_v · x_v = 2.

For the second surface x(u,v)=(coshu,sinhu,v):
- Differentiating x(u,v) with respect to u and v, we get x_u=(sinhu,coshu,0) and x_v=(0,0,1).
- Calculating the dot products, we find that E = x_u · x_u = 1, F = x_u · x_v = 0, and G = x_v · x_v = 1.

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Answer:

Yes, your answers are correct.

Example of 3 below:

Step-by-step explanation:

5x + 2 = 27

use inverse operations and the properties of equalities. First, subtract 2 from both sides of the equation to isolate the term with x:

5x + 2 - 2 = 27 - 2

5x = 25

Next, use the inverse operation of multiplication to isolate x. divide both sides of the equation by 5 to undo the multiplication:

5x ÷ 5 = 25 ÷ 5

x = 5

You used the inverse operations of subtraction and division, as well as the property of equality that states that we can perform the same operation on both sides of an equation and still have an equivalent equation.

Answer:

around 52 or 51

Step-by-step explanation:

6/24=.25

.25 * 206=51.5

Answer: 1 ticket = 70 cents.

Step-by-step explanation:

If you get 20 tickets for 14.00, then we have to divide 14 by 20.

14 ÷ 20 = 0.7, or 70 cents. Because of this, each ticket will cost 70 cents.

\(\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}\)

\(:\implies\sf{ \frac{36}{x} = - 9} \\ \\ :\implies\sf{ \frac{36}{ 9} = -x} \\ \\ :\implies\sf{4 = -x} \\ \\ :\implies\sf{x = -4}\)

ANSWER

Start with the graph of f(x) = x². Shift it left 1 unit and then shift it up 4 units:

EXPLANATION

The graph of f(x) = x² is

If we shift it 1 unit left:

Then 4 units up:

Since we have that the sale price is $511, then this represents the 100-27%=73% of the total price. Then, using a rule of three we have:

therefore, the original price of the sofa was $700

Answer:

50/77

Step-by-step explanation:

(1÷2 3/4)+(1÷3 1/2)

2 3/4 is same as 11/44

1/2 is same as 7/2

so to divide fraction you have to flip the second number and multiply

so 1 times 4/11=4/11

and 1 times 2/7=2/7

4/11 +2/7=28/77+22/77=50/77

The given system of linear equations has a unique solution or only one solution.

Given system of linear equations:

y = 34x + 12 ...(1)

y = 43x ...(2)

We need to find how many solutions does the system of linear equations have

For this, there are  three possibilities:

Case 1: The given system of equations has a unique solution, that is only one solution.

Case 2: The given system of equations has no solution, that is the lines are parallel.

Case 3: The given system of equations has infinitely many solutions, that is both the lines coincide with each other.

Let's find the solutions of the given system of equations by comparing equation (1) and equation (2):

Comparing equation (1) and equation (2), we get:34x + 12 = 43x

Solving the above equation for x, we get:

9x = 12x = 12/9x = 4/3

Putting the value of x = 4/3 in equation (2), we get:

y = 43 × 4/3y = 172/3y = 57.33

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The options have not been given but three correct alternatives have been presented as the solution.

We have given,

\(\frac{c^2-4}{c+3} /\frac{c+2}{3(c^2-9)}\)

Applying the rule a^2-b^2 to the numerator of the first term and the denominator of the second term,

\((a^2-b^2)=(a-b)(a+b)\)

By applying the above formula we have:

\(=\frac{c^2-2^2}{c+3} /\frac{c+2}{3((c+3)(c-3)}\)

\(=\frac{(c-2)(c+2)}{c+3} /\frac{c+2}{3((c+3)(c-3)}\)

Therefore the solution is,

\(=(c-2) \times 3(c-3)\\\\=3(c^2-5c+6)\\\\=3c^2-15c+18\)

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Answer:

C.) StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction 3 (c squared minus 9) Over c + 2 EndFraction"/>

Step-by-step explanation:

Which expression is equivalent to StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction c + 2 Over 3 (c squared minus 9) EndFraction?

StartFraction c + 3 Over c squared minus 4 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction 3 (c squared minus 9) Over c + 2 EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction 3 (c squared minus 9) Over c + 2 EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction

Answer:

40

Step-by-step explanation:

Mode represents the highest number/ highest number of quality

In this case 40 Is both

Answer:

\(-\frac{3}{5}\)

Step-by-step explanation:

so I like to think of slope as rise/run

the "rise" is the difference between the two y's and the run is the difference between the two x's. there isn't a particular order, but make sure that if you use the first coordinate's y first and then the second y, that you do the same for finding the difference between the x's because signs are important.

so, to solve this one:

\(\frac{10-13}{6-1} =\frac{-3}{5}\)

Answer:

166.07

Step-by-step explanation:

since the domain is [0,89] means the maximum amount is when x=89

vertex is where it reached the maximum amount:(44.512,166.07)

Step-by-step explanation:

3. First, let's find the length of AB:

22²+14² = AB²

680 = AB²

AB = √680

AB ≈ 26.08

The sin of x° is equal to 14/2608

14/26.08 ≈ 0.54

Now you do the asin of 0.54:

asin(0.54) = 32.68°

4. The cos(41°) = x/34, and also the value of cos(41°) ≈ 0.75, so:

0.75 = x/34

x = 34•0.75

x = 25.5°

Latasha needs to run 0.23 minutes more minutes to complete the mile.

What is the speed of a runner?

The speed of a runner is the ratio of the distance covered in a specific time.

Given,

Latasha ran a mile in 7.03 minutes and Erik ran a mile in 6.8 minutes.

Therefore, difference in time = (7.03 - 6.8) minutes = 0.23 minutes.

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The output value of g( -5 ) in the function g( x ) = −23( x - 4 )2 + 3 is 417.

A function is simply a relationship that maps one input to one output, that is, each x-value can only have one y-value.

Given the data in the question;

To find the g( - 5 ), replace all the occurrence of x with -5 in the function and simplify.

g( x ) = −23( x - 4 )2 + 3

g( -5 ) = −23( -5 - 4 )2 + 3

g( -5 ) = −23( -9 )2 + 3

g( -5 ) = −23( -9 × 2) + 3

g( -5 ) = −23( -18) + 3

g( -5 ) = ( -23 × -18) + 3

g( -5 ) = ( 414 ) + 3

g( -5 ) = 414 + 3

g( -5 ) = 417

Therefore, the output value of g( -5 ) is 417.

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The best estimate for the total number of winter moths in the patch of woodland is 12,000 moths.

We have,

Calculate the average number of moths per square meter in the sampled quadrats:

Quadrat A has 10 moths in 1 square meter, so it has 10 moths per square meter.

Quadrat B has 20 moths in 1 square meter, so it has 20 moths per square meter.

Quadrat C has 35 moths in 1 square meter, so it has 35 moths per square meter.

Quadrat D has 15 moths in 1 square meter, so it has 15 moths per square meter.

Calculate the total number of moths per square meter in all the quadrats:

Total moths per square meter

= (10 + 20 + 35 + 15) moths

= 80 moths per square meter.

Calculate the estimated total number of moths in the 150-square-meter patch of woodland by multiplying the average moths per square meter by the total area:

Estimated total moths = (80 moths per square meter) * (150 square meters)

= 12,000 moths.

Thus,

The best estimate for the total number of winter moths in the patch of woodland is 12,000 moths.

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Answer:

\(y=3\cos(\frac{8}{7}x)+2\)

Step-by-step explanation:

Recall

We are given that the amplitude is \(a=3\) and that the equation of the midline is \(d=2\). Since we know the period to be \(\frac{7\pi}{4}\), we need to solve for \(b\) by setting up the equation \(\frac{7\pi}{4}=\frac{2\pi}{|b|}\):

\(\frac{7\pi}{4}=\frac{2\pi}{|b|}\\\\7\pi b=8\pi\\\\b=\frac{8}{7}\)

Hence, our cosine function will be \(y=3\cos(\frac{8}{7}x)+2\). See the attached graph for a visual.

The probability that the weight limit will be exceeded when there are exactly 40 passengers and 3 crew members on board is 0.031.

Mean = 196 × 43

Mean = 8428

Std. Dev. = 63 × √(43)

Std. Dev. = 63 × 6.56

Std. Dev. = 413.28

Here, μ = 8428, σ = 413.1186 and x = 9200. We must calculate P(X ≥ 9200).

he central limit theorem states that, for a sufficiently large sample size, the sample mean of all observations will be approximately normally distributed, regardless of the distribution of the population from which it was sampled.

The Central Limit Theorem is used to get the associated z-value.

z = (x - μ)/σ

z = (9200 - 8428)/413.28

z = 772/413.28

z = 1.87

Therefore,

P(X ≥ 9200) = P(z ≤ (9200 - 8428)/413.1186)

P(X ≥ 9200) = P(z ≤ 772/413.1186)

P(X ≥ 9200) = P(z ≥ 1.87)

P(X ≥ 9200) = 1 - 0.9693

P(X ≥ 9200) = 0.031

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The complete question is:

A small jet can carry up to 40 passengers and 3 crew members. There is a weight restriction of 9200 pounds on board. The combined weight of each passenger (or crew member) and his luggage has a mean of 196 pounds, with a standard deviation of 63 pounds. What is the probability that the weight limit will be exceeded when there are exactly 40 passengers and 3 crew members on board? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places.

Answer:

False

Step-by-step explanation:

If you were to divide a negative number by a negative number, or multiply a negative number by a negative number, you would change the sign to positive as two negatives make a positive.

Answer:

False

Step-by-step explanation:

if you multiply two negative integers, you will get a positive result

For example

(-1) x (-2) = 2   (the sign of the answer is different from the sign of the two negative integers that we multiplied)

Answer:

p=q

Step-by-step explanation:

the second statement must be true.

Answer:

3\(x^{2}\) -2x - 6

Step-by-step explanation:

Subtract the 2 functions so 3\(x^{2}\) - 2 - (2x + 4) so you get

3\(x^{2}\) - 2 -2x - 4 so add like terms you get 3\(x^{2}\) -2x - 6

the value of f(-2) is approximately 0.540.

To solve the differential equation dy/dx = e^x - e^y, we can use separation of variables:

dy / (e^y - e^x) = e^x dx

Integrating both sides, we get:

ln|e^y - e^x| = e^x + C

where C is the constant of integration. Since y = f(x) is a particular solution, we can use the initial condition f(1) = 0 to find C:

ln|e^0 - e^1| = 1 + C

ln(1 - e) = 1 + C

C = ln(1 - e) - 1

Substituting this value of C back into the general solution, we get:

ln|e^y - e^x| = e^x + ln(1 - e) - 1

Taking the exponential of both sides, we get:

|e^y - e^x| = e^(e^x) * e^(ln(1 - e) - 1)

Simplifying the right-hand side, we get:

|e^y - e^x| = e^(e^x - 1) * (1 - e)

Since f(1) = 0, we know that e^y - e^1 = 0, or equivalently, e^y = e. Therefore, we have:

|e - e^x| = e^(e^x - 1) * (1 - e)

Solving for y in terms of x, we get:

e - e^x = e^(e^x - 1) * (1 - e) or e^x - e = e^(e^y - 1) * (e - 1)

We can now use the initial condition f(1) = 0 to find the value of f(-2):

f(-2) = y when x = -2

Substituting x = -2 into the equation above, we get:

e^(-2) - e = e^(e^y - 1) * (e - 1)

Solving for e^y, we get:

e^y = ln((e^(-2) - e)/(e - 1)) + 1

e^y = ln(1 - e^(2))/(e - 1) + 1

Substituting this value of e^y into the expression for f(-2), we get:

f(-2) = ln(ln(1 - e^(2))/(e - 1) + 1)

Using a calculator, we get:

f(-2) ≈ 0.540

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A definite integral is said to be improper if one or both of the limits of integration are infinite, or if the integrand function has a vertical asymptote within the interval of integration.

In other words, an improper integral is one that cannot be evaluated using the usual techniques of integration, such as the fundamental theorem of calculus, because it involves infinite limits or a function that is not integrable over the interval.

For example, the definite integral of f(x) = 1/x from 1 to infinity is an improper integral because the upper limit of integration is infinity, which is not a finite number. Similarly, the definite integral of f(x) = ln(x) from 0 to 1 is an improper integral because the lower limit of integration is 0, and the function has a vertical asymptote at x=0.

To evaluate improper integrals, we use limit processes to determine whether the integral converges (has a finite value) or diverges (has an infinite value). If the integral converges, we can find its value by taking the limit of a related integral as one or both of the limits of integration approach infinity or zero.

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Answer:

One real root (multiplicity 2).

Step-by-step explanation:

-3=x^2+4x+1

x^2 + 4x + 4 = 0

Discriminant = 4^2 - 4*1*4 = 0

There is one real root (multiplicity 2).

The equation has 1 real solution.

The quadratic function is given as:

\(-3=x^2+4x+1\)

Add 3 to both sides of the equation

\(3-3=x^2+4x+1 + 3\)

This gives

\(0=x^2+4x+4\)

Rewrite the equation as:

\(x^2+4x+4 = 0\)

A quadratic equation is represented as:

\(ax^2+bx+c = 0\)

By comparison, we have:

\(a =1\)

\(b =4\)

\(c = 4\)

The discriminant (d) is calculated as:

\(d =b^2 - 4ac\)

So, we have:

\(d =4^2 - 4 \times 1 \times 4\)

\(d =16 - 16\)

Evaluate like terms

\(d = 0\)

Given that the discriminant value is 0, it means that the equation has 1 real solution.

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Answer: the true answer is A

Step-by-step explanation:

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Using the normal distribution, it is found that the probability that more than 524 customers will come to the store on a given day is given by:

A. 0.15%.

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

In this problem, the mean and the standard deviation are given, respectively, by:

\(\mu = 428, \sigma = 32\).

The probability that more than 524 customers will come to the store on a given day is one subtracted by the p-value of Z when X = 524, hence:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{524 - 428}{32}\)

Z = 3

Z = 3 has a p-value of 0.9985.

1 - 0.9985 = 0.0015 = 0.15%.

Hence option A is correct.

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