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Explanation:

To calculate the concentration of the resulting solution, we can use the formula C₁V₁ = C₂V₂, where C₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume.

Given:

C₁ = 0.2 mg/mL

V₁ = 3.5 mL

V₂ = V₁ + 0.5 mL = 3.5 mL + 0.5 mL = 4 mL (assuming no significant change in volume upon mixing)

Using the formula, we can solve for C₂:

C₁V₁ = C₂V₂

0.2 mg/mL * 3.5 mL = C₂ * 4 mL

0.7 mg = C₂ * 4

C₂ = 0.7 mg / 4 mL

C₂ ≈ 0.175 mg/mL

Therefore, the concentration of the resulting solution is approximately 0.175 mg/mL.

Answer:

The answer is 412

Explanation:

Because we distracted c1 from h2o due to the chemical combination of the two

Answer:

4C2H5NH2(g) + 15O2(g) →  8CO2(g) + 14H2O(g) + 2N2(g)

Explanation:

The balanced chemical equation  for the given chemical reaction is 4 C₂H₅NH₂(g) + 15 O₂(g) →  8 CO₂(g) + 14 H₂O(g) + 2 N₂(g).

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Answer:

None of these statements are true

Answer:

B.K2(OH)2 i think that is the answer

Answer:

Xylitol

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Answer:

\(M=1.1M\)

Explanation:

Hello,

In this case, since we are mixing two NaOH solutions, the first step is to compute the total moles once the mixing is done, by using the volumes and concentrations of each solutions and subsequently adding them:

\(n_T=2.0L*0.60\frac{mol}{L}+495mL*\frac{1L}{1000mL}*3.0\frac{mol}{L}= 2.7molNaOH\)

Next, we compute the total volume by adding the volume of each solution:

\(V_T=2.0L+495mL*\frac{1L}{1000mL}= 2.495L\)

Finally, we compute the molarity of the resulting solution by the division between the total moles and the total volume:

\(M=\frac{2.7mol}{2.495L}\\ \\M=1.1M\)

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If the 13.5 mol of the Zn and 3.5 mol of S are mixed together and the heated, the mass of the ZnS will be produced is 93.97 g.

The chemical equation is as :

Zn + S -->  ZnS

The moles of the zinc, Zn the = 13.5 mol

The moles of the sulfur, S = 3.5 mol

1 mole of the Zn produces the 1 mole of the ZnS

1 mole of the S produces the 1 mole of the ZnS

The S is the limiting reactant. The production of the ZnS is depends on the the sulfur.

1 mole of the S produces the 1 mole of the ZnS

The moles of the ZnS = 3.5 mol

The mass of the ZnS = moles × molar mass

The mass of the ZnS = 3.5 × 97.47

The mass of the ZnS = 93.97 g

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Answer:

Na, K

Explanation:

From the given choices, the two elements that will react similarly are Na and K.

This is because, Na and K are in the same group on the periodic table.

Na and K are both called Alkali metals and they have just one electron in their outermost shell.

The number of electrons in the outermost of an atom determines their chemical properties.

Since Na and K are in the same group, they chemically combine with other atoms in similar fashion.

LiAlH4 reagent can reduce aldehydes to primary alcohols, ketones to secondary alcohols, carboxylic acids and esters to primary alcohols, amides and nitriles to amines, epoxides to alcohols and lactones to diols.

LiAlH4 is a powerful reducing agent compared to sodium borohydride, NaBH4, since the Al-H bond is weaker and thus less stable than B-H bond.

Reduction of aldehydes or ketone to primary  and secondary alcohols:

Initially, a hydride ion is transferred onto the carbonyl carbon and the oxygen atom coordinates to the remaining aluminum hydride species to furnish an alkoxy tri hydro aluminate ion, which can reduce the next carbonyl molecule. Thus three of the hydride ions are used up in reduction. The reaction will be as follows :

    AlH4 + ROR   →  RHROH

Reduction of amides to amine:

Amides are converted to amines. The LAH reduction mechanism is slightly different from that depicted for esters. In iminium ion is formed during the reaction since nitrogen atom is relatively a good donor than oxygen atom. The reaction will be as follows:

RONR2 + AlH4 → RNR2

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Answer:

The molar mass and molecular weight of Al(CH3CO2)3 is 204.1136.

Explanation:

Answer:

168.1 g/mol

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

Al(CH₃O₂)₃

Step 2: Find molar masses

Molar Mass of Al - 26.98 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al(CH₃O₂)₃ - 26.98 + 3(12.01) + 9(1.01) + 6(16.00) = 168.1 g/mol

Answer:

Determination of kcat:

Enzyme kinetics refers to the quantitative investigation of enzyme-catalyzed reactions, such as the determination of Michaelis-Menten kinetics parameters, including Vmax, Km, and kcat.

Michaelis-Menten kinetics is a critical aspect of enzyme kinetics that aids in the characterization of enzymes based on their activities. Vmax refers to the maximum initial rate of an enzyme-catalyzed reaction, and Km is the substrate concentration that leads to half the maximum initial velocity.

There are various strategies for determining kcat, which is the enzyme catalytic constant.

It is described as the number of substrate molecules that are converted into product molecules by an enzyme molecule per unit of time when the enzyme is completely saturated with the substrate.

The most direct way of measuring kcat is to use a single turnover method, where the enzyme is initially saturated with the substrate and then mixed with excess enzyme inhibitor or by removing the reaction products as soon as they are formed.

As a result, during the reaction, the enzyme is prevented from engaging in further catalysis.

Enzyme kinetics is an essential topic for life science research as it aids in the characterization of enzymes based on their activities.

Answer:

3.31x10^24 atoms

Explanation:

1 mole of S atom = 6.023^23 atoms

5.5 moles            = 5.5 x 6.023^23

                           = 3.31x10^24 atoms

The measure of the length of events and the duration of intervals between events is time.

The duration of events or the gaps between them can be measured, compared, or even ordered using time. The lengthy period of time that the Earth's geologic history takes up is known as geologic time. Starting at the beginning of the Archean Eon  formal geologic time runs until the present. Geology is defined as the "Science of the Earth."

Geology is the fundamental Earth science that examines how the earth created, its structure and composition, and the various forces acting on it. It is sometimes known as geoscience or earth science.

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In order to test for ammonia, a moist red litmus paper should be held over the test tube containing the ammonia.  Option 3.

Ammonia is a substance that is alkaline in nature. All alkaline substances are able to turn red litmus paper to blue. This is in opposition to acidic substances that turn blue litmus paper to red.

Thus, the first test that can be used to determine if a substance is ammonia would be to hold a moist red litmus paper over the test tube containing the suspected substance.

Since ammonia is gas at room temperature, the substance suspected to be ammonia will diffuse from the test tube to turn the moist red litmus paper to blue.

Other methods to test for ammonia include passing a test tube containing hydrochloric acid over the test tube containing the substance. A white fume of ammonium chloride will confirm the presence of ammonia.

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Answer:

40,113 years

Explanation:

To find the age of the sample, you need to use the half-life formula:

\(N(t)=N_0(\frac{1}{2})^{t/h\)

In this formula:

------> N(t) = current mass (g)

------> N₀ = initial mass (g)

------> t = time passed (yrs)

------> h = half-life (yrs)

You can plug the given values into the equation and rearrange the formula to find "t".

N(t) = 0.781 g                       t = ? yrs

N₀ = 100 g                           h = 5730 yrs

\(N(t)=N_0(\frac{1}{2})^{t/h\)                                           <----- Half-life formula

\(0.781=100(\frac{1}{2})^{t/5730}\)                                     <----- Insert values

\(0.00781=(\frac{1}{2})^{t/5730}\)                                       <----- Divide both sides by 100

\(log_{1/2}(0.00781)=log_{1/2}((\frac{1}{2})^ {t/5730})\)               <----- Take \(log_{1/2}\) of both sides

\(7.00 = \frac{t}{5730}\)                                                   <----- Solve \(log_{1/2}\)

\(40,113 = t\)                                                   <----- Multiply both sides by 5730

The given sample is 40,113 years .

Half-life, in radioactivity, is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

Half-life formula,

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)   .......(1)

where,

N(t)=current mass

N₀=initial mass

t=time period

h=half -life

Given,

N(t)=0.781g, t=? yrs, N₀=100g, h=5730 years

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)

put the values, in ......(1)

0.781=100(1/2) \(t/5730\\\)

log₁/₂(0.00781)=log₁/₂ ( 1/2)\(t/5730\)

7=t/5730

40,113=t

Hence, the given sample is 40,113 years .

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Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles\)  

\(2K+2H_2O\rightarrow 2KOH+H_2\)  

According to stoichiometry :

2 moles of \(K\) produce = 2 moles of \(KOH\)

Thus 0.57 moles of \(K\) will produce=\(\frac{2}{2}\times 0.57=0.57moles\)  of \(KOH\)

Mass of \(KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g\)

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

Answer: 30.3 g

I had this question..If i hadn't done this I'd be confused.

Answer:

it should be 7.300 sorry if I am wrong

Answer:

The answer is 115

Explanation:

Teacher walked me through it.

A pH of 4 is ten times more acidic than a pH of 5.

Yes, pH can have decimal values. In fact, pH values can range from 0 to 14 and can have any value between them including decimals. pH is a measure of the acidity or alkalinity of a solution, and it is determined by the concentration of hydrogen ions (H+) in the solution.A solution with a pH of 7 is neutral, which means that it has an equal concentration of hydrogen ions (H+) and hydroxide ions (OH-). An acidic solution has a pH below 7 and a high concentration of H+ ions. On the other hand, an alkaline solution has a pH above 7 and a low concentration of H+ ions.A pH that is less than 7.0 indicates acidity. pH less than 7.0 is acidic while pH greater than 7.0 is alkaline. Each number on the pH scale represents a ten-fold change in the acidity/alkalinity of the solution. For example, a pH of 5 is 10 times more acidic than a pH of 6, and 100 times more acidic than a pH of 7.A pH of 0 indicates a very strong acidic solution while a pH of 14 indicates a very strong alkaline solution. It's worth noting that pH is a logarithmic scale, meaning that a change of one pH unit corresponds to a ten-fold change in hydrogen ion concentration.

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Answer:

Tings that effect weather is basically the following:

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

Lead (IV) Iodide

Explanation:

Answer:

The starting position of this object is 3 m.

The object is traveling at a velocity of 3 m/s

Explanation:

the graph begins at 3, and increases by 3 at each second

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Let us start by determining the compound formula.

We have Cu^1+ and S^2- when you use a criss cross method, these give you Cu2S.

The molar masses of:

Cu = 63.55 g/mol

S = 32.07 g/mol

Cu2S = 159.17 g/mol

We will use the molar mass and the masses given to calculate the percentage of S and Cu.

For Cu:

(43.40/159.17) x100 = 27.3%

For S:

(10.95/159.17) x 100 = 6.9%

The equlibrium that exist is:

-We will determine the concentration of sodium acetate:

Now that we have the concentration of the conjugate base we can use Henderson-Hasselbach equation to determine the pH:

Answer: The pH of the solution is 5.22,

Answer:

53.5gram.

Explanation

Explanation: number of moles = number of molecule ÷ avogadro's number. => moles = 6.022 × 10²³ ÷ 6.022 × 10²³ = 1 mole. mass of 1 mole of NH4Cl = 1 × molar mass.