i need to know the full quadratic equation answer

If two events, event A with probability P(A) and event b with probability P(B) are complementary events then the sum of the probability of events A and B will be one.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

When one event happens if and only if the other one doesn't, two occurrences are said to be complimentary. The odds of two complementary events equal one.

P(A) + P'(A) = 1

The chance of events A and B added together will equal one if events A with probability P(A) and event B with probability P(B) are complementary occurrences.

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Answer:

Total cost = $3040

Step-by-step explanation:

To calculate the cost of installing the two rectangular windows, we need to calculate the total area of the glass, including both windows, and add the cost of labor. Here are the steps to follow:

Step 1:  Calculate the area of one window using the formula for area of a rectangle:

area = base x height

In this case, the base is 5 meters and the height is 4 meters, so the area of one window is:

area of one window = 5 meters x 4 meters = 20 square meters

Step 2:  Since there are two windows, the total area of glass needed is:

total area of glass = area of one window x 2

total area of glass = 20 square meters x 2 = 40 square meters

Step 3:  The cost of the glass is $72 per square meter, so the cost of the glass for the two windows is:

cost of glass = total area of glass x cost per square meter

cost of glass = 40 square meters x $72 per square meter = $2,880

Step 4:  The glazier requires $80 per glazing for labor, and there are two windows, so the cost of labor is:

cost of labor = number of windows x cost per glazing

cost of labor = 2 windows x $80 per glazing = $160

Step 5:  Finally, to calculate the total cost of installing the two windows, we add the cost of the glass to the cost of labor:

total cost = cost of glass + cost of labor

total cost = $2,880 + $160 = $3,040

Therefore, the complete installation of the two windows will cost $3,040

Not performing qualitative tests in duplicate can introduce certain risks and potential issues:

False positives: Without duplicate testing, there is a higher risk of obtaining false positive results. False positives occur when a test incorrectly indicates the presence of a particular characteristic or condition. Duplicate testing helps verify the accuracy and reliability of the results, reducing the chances of false positives.

False negatives: Similarly, not performing qualitative tests in duplicate increases the risk of false negatives. False negatives occur when a test fails to detect a characteristic or condition that is actually present. Duplicate testing provides an additional opportunity to identify any missed detections and reduces the likelihood of false negatives.

Variability and uncertainty: Qualitative tests can be subject to variability due to factors such as sample preparation, test conditions, or interpretation. Duplicate testing helps assess the consistency and reproducibility of the results, providing a measure of confidence and reducing uncertainty.

Quality control issues: Duplicate testing is an essential component of quality control protocols. It helps ensure the reliability and accuracy of the testing process and minimizes the potential for errors or inconsistencies. Not performing duplicate tests can compromise the overall quality control procedures, leading to compromised data and unreliable conclusions.

Validation and reproducibility: Duplicate testing is often required for validation purposes and to demonstrate the reproducibility of results. It helps establish the robustness and reliability of the testing method. Without duplicate testing, it becomes more challenging to validate and reproduce the results, which can undermine the credibility of the findings.

In summary, not performing qualitative tests in duplicate increases the risks of false positives, false negatives, variability, uncertainty, quality control issues, and challenges in validation and reproducibility. Duplicate testing plays a crucial role in ensuring the accuracy, reliability, and validity of qualitative test results.

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(4, 8, 1), (0, 11, 2), and (4, 10, 8) are the translated vertices right along the y-axis.

it is given that,

A(4, 5, 1)

B(0, 8, 2)

C(4, 7, 8)

Which are in x, y, and z, format.

here we need to translate three units to the right along the y-axis.

Right means addition and we have to choose only y- coordinates.

A(4, 5, 1) → A'(4, 5+3, 1)

B(0, 8, 2) → B'(0, 8+3 , 2)

C(4, 7, 8) → C'(4, 7+3, 8)

This gives us,

(4, 5, 1) → (4, 8, 1) → (x, y, z)

(0, 8, 2) → (0, 11, 2) → (x, y, z)

(4, 7, 8) → (4, 10, 8) → (x, y, z)

thus, these are our required vertices.

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b) φ^(-1)(0.5) = 4 and it tells us that at t = 4 nanoseconds, there will be 0.5 nanograms of extract A remaining. This represents the inverse relationship between the amount of extract A remaining and time.

(c) False. Based on the given facts, there is no specific time mentioned when the amount of extract A remaining is exactly 4 nanograms. The known data points do not include φ(t) = 4.

(d) To calculate φ(φ^(-1)(1)), we substitute φ^(-1)(1) into the function φ. Since φ^(-1)(1) = 3, we evaluate φ(3). The result is φ(3) = 1, which means that at t = 3 nanoseconds, there will be 1 nanogram of extract A remaining.

(e) To calculate φ^(-1)(φ(6)), we substitute φ(6) into the inverse function φ^(-1). Since φ(6) = 0, we evaluate φ^(-1)(0). The result is φ^(-1)(0) = 10, indicating that at t = 10 nanoseconds, there will be 0 nanograms (or none) of extract A remaining.

(f) The domain of the function φ is the set of possible values for time t, which can range from 0 to a positive value, based on the experiment's time frame. The range of the function φ is the set of possible values for the amount of extract A remaining, which can range from 0 to 6 nanograms, based on the given facts.

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Answer:

yeah its C. composed and ejected

Step-by-step explanation:

i took the test :) edge 2022

We cannot find the perimeter of the triangle as there are no real solutions for the length of its sides.

To find the perimeter of the triangle, we need to determine the lengths of the other two sides first.
Since the triangle is isosceles, it has two congruent sides. Let's denote the length of each congruent side as "x".

Now, we know that one of the congruent sides is 10 cm long, so we can set up the following equation:
x = 10 cm

Since the triangle is isosceles, the angles opposite to the congruent sides are also congruent. One of these angles has a measure of 54°. Therefore, the other congruent angle also measures 54°.

To find the length of the third side, we can use the Law of Cosines. The formula is as follows:
\(c^2 = a^2 + b^2 - 2ab * cos(C)\\\)

In our case, "a" and "b" represent the congruent sides (x), and "C" represents the angle opposite to the side we are trying to find.

Plugging in the given values, we get:
\(x^2 = x^2 + x^2 - 2(x)(x) * cos(54°)\)

Simplifying the equation:

\(x^2 = 2x^2 - 2x^2 * cos(54°)\)
\(x^2 = 2x^2 - 2x^2 * 0.5878\)
\(x^2 = 2x^2 - 1.1756x^2\\\)
\(x^2 = 0.8244x^2\)

Dividing both sides by x^2:
1 = 0.8244

This is not possible, which means there is no real solution for the length of the congruent sides.
Since we cannot determine the lengths of the congruent sides, we cannot find the perimeter of the triangle.

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Answer:

x=50

Step-by-step explanation:

40=x-10

Add 10 to both sides to isolate x

Solve.

Checking the solution

Answer:

x = 50

Step-by-step explanation:

40 = x - 10

subtract/add (always do the opposite so we would add 10)

50 = x

there's your answer

The length of AB which is a diameter of the circle is equal 52 m using the Pythagoras rule.

The Pythagoras rule states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 

The hypotenuse of the right triangle ADC is a radius and twice the length of the radius is that of the diameter so;

radius = √(10² + 24²)

radius = √(100 + 576)

radius = √676

radius = 26

diameter AB = 2 × 26 = 52m

Therefore, the length of AB which is a diameter of the circle is equal 52 m using the Pythagoras rule.

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Answer:

20

Step-by-step explanation:

16 / 20 = 0.80

0.80 = 80%

Answer:

\((x-8)^2+y^2=1\)

Step-by-step explanation:

Center of circle is (h,k)=(8,0) and radius is r=1, therefore, the equation is:

\((x-h)^2+(y-k)^2=r^2\\(x-8)^2+(y-0)^2=1^2\\(x-8)^2+y^2=1\)

The equation of the line in point-slope form and in​ slope-intercept form are both y = 1/2x.

1. Point-Slope Form: y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is a point on the line.

2. Slope-Intercept Form: y = mx + b, where m is the slope of the line and b is the y-intercept.

3. Standard Form: Ax + By = C, where A and B are coefficients that define the slope and y-intercept of the line.

If a line has a slope of 1/2 and passing through the origin, then:

m = 1/2

(x1, y1) = (0,0)

Plug in the values in the point-slope form and in​ slope-intercept form.

point-slope form

y - y1 = m(x - x1)

y - 0 = 1/2(x - 0)

y = 1/2x

slope-intercept form

y = mx + b

y = 1/2x + b

Substitute the values of x and y and solve for the y-intercept, b.

0 = 1/2(0) + b

b = 0

y = 1/2x + 0

y = 1/2x

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Answer:

I believe they are equal but I'm not for sure

Answer:

it will not change, there is no probability of a coin flip other than 50/50

Step-by-step explanation:

it's always 50/50

(a) Is this an observational study or an experiment?

ans=Observational study – no treatment was imposed

(b) What are the explanatory and response variables?

ans=explanatory – time spent in child care from birth to age 4 response – adult rating of children’s behavior

d) Does this study show that child care causes children to be more aggressive? Explain.

No. Observational studies cannot show cause-and-effect

Researchers=someone whose job is to study a subject carefully, especially in order to discover new information or understand the subject better: She is a leading researcher in the field.

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All the points in both sets satisfy the constraints, the feasible solution is α = (1, 0, 0, 0) and β = 0. This plane separates the sets S1 and S2.

To formulate the problem as a linear optimization problem (LO), we can introduce slack variables to represent the signed distances of the points from the plane αTx = β. Let's denote the slack variables as y_i for points in S1 and z_i for points in S2.

1.1 Formulation:

The problem can be formulated as follows:

Minimize: 0 (since it is a feasibility problem)

Subject to:

α1x1 + α2x2 + α3x3 + α4x4 - β ≥ 1 for (x1, x2, x3, x4) in S1

α1x1 + α2x2 + α3x3 + α4x4 - β ≤ -1 for (x1, x2, x3, x4) in S2

α1, α2, α3, α4 are unrestricted

β is unrestricted

y_i ≥ 0 for all points in S1

z_i ≥ 0 for all points in S2

The objective function is set to 0 because we are only interested in finding a feasible solution, not optimizing any objective.

1.2 Finding a feasible solution:

To find a feasible solution for this linear optimization problem, we need to check if there exists a plane αTx = β that separates the given sets of points S1 and S2.

Let's set α = (1, 0, 0, 0) and β = 0. We choose α to have a non-zero value for the first component to satisfy α ≠ (0, 0, 0, 0) as required.

For S1:

(1, 2, 1, -1) - 0 = 3 ≥ 1, feasible

(3, 1, -3, 0) - 0 = 4 ≥ 1, feasible

(2, -1, -2, 1) - 0 = 0 ≥ 1, not feasible

(7, -2, -2, -2) - 0 = 3 ≥ 1, feasible

For S2:

(1, -2, 3, 2) - 0 = 4 ≥ 1, feasible

(-2, π, 2, 0) - 0 = -2 ≤ -1, feasible

(4, 1, 2, -π) - 0 = 5 ≥ 1, feasible

(1, 1, 1, 1) - 0 = 4 ≥ 1, feasible

Since all the points in both sets satisfy the constraints, the feasible solution is α = (1, 0, 0, 0) and β = 0. This plane separates the sets S1 and S2.

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The length of the sides are

AC = 5.4

BC = 10.5

To determine the value, we need to know the different trigonometric identities.

They include;

These identities also have their ratios;

sin θ = opposite/hypotenuse

cos θ = adjacent/hypotenuse

tan θ = opposite/adjacent

From the information given, we have;

tan 31 = AC/9

cross multiply the values

AC = 5. 4

sin 59 = 9/BC

cross multiply the values

BC = 10. 5

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Answer:

10 inches²

420 inches²

Step-by-step explanation:

1) Area of a triangular placemat:

= ½ × base × height

= ½ × 5 × 4

= 10 inches²

2)  Total area of the placemat:

= Area of a placemat × Number of triangles

= 10 × 42

= 420 inches²

The innovation that was made possible in part because of the Carterfone decision in 1968 is the public Internet. The correct answer is option C

The Carterfone decision was a landmark ruling by the Federal Communications Commission (FCC) that allowed for the interconnection of third-party devices to the telephone network. Prior to this decision, telephone companies had a monopoly on the equipment that could be used on their networks, and customers were not allowed to attach their own devices.

This decision paved the way for the development of the public Internet by allowing for the interconnection of third-party devices to the telephone network, which enabled the creation of new technologies, such as modems. Without the Carterfone decision, the public Internet as we know it today may not have been possible.

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Answer:

Below

Step-by-step explanation:

4 [x-3] + 2    = y    is not discontinuous anywhere

However    4 / [x-3]  + 2   DOES have a discontinuity at x = 3 because this would cause the denominator to be zero <===NOT allowed !!

Answer:

Change in Y over change in X. So down 8 and over 2. Simplified it would be 4/1

Answer:

Area = 100m²

Step-by-step explanation:

Given :

Height of triangle = 10 m

Length of base = 2 * height = 2 * 10 = 20 m

Area of right angle triangle :

1/2 * base * height

Area = 1/2 * 20 * 10

Area = 0.5 * 10 * 20

Area = 100m²

Answer: The distance between the two points is 5.

The area of the inner loop of the limaçon given the equation r = -√(3 - 2sinθ), is 0.

The integral for the area of the inner loop of the limaçon, express the equation in polar form and determine the limits of integration.

The equation of the limaçon is given as r = -√(3 - 2sinθ). simplify this equation:

r = -√(3 - 2sinθ)

r² = 3 - 2sinθ

square both sides to eliminate the square root:

r² = 3 - 2sinθ

convert the equation to polar coordinates:

x = rcosθ

y = rsinθ

Substituting these equations into r² = 3 - 2sinθ, we have:

x² + y² = 3 - 2sinθ

To find the area of the inner loop, we need to determine the limits of integration for θ. The inner loop corresponds to a range of θ values where the equation r = -√(3 - 2sinθ) produces negative values for r.

From the equation r = -√(3 - 2sinθ),  that the expression inside the square root, (3 - 2sinθ), must be negative for the inner loop. Solving this inequality:

3 - 2sinθ < 0

2sinθ > 3

sinθ > 3/2

sinθ is only positive in the interval [0, π], the inequality sinθ > 3/2 has no solutions in this interval the area of the inner loop is 0.

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The cost of the jersey that Charlotte wanted to buy  who is visiting to Brazil, in U.S. dollars based on the exchange rate is $16.39.

What is the exchange rate?

The exchange rate is the rate at which two nations currencies are exchanged in the foreign exchange market.

The exchange rate depends on the purchasing power of each currency.

Data and Calculations are as follows :

Cost of jersey = Br. 89

Exchange rate = $1 : Br. 5.43

Cost of jersey in US dollars = $ (Br. 89/Br. 5.43)

Thus, the cost of the jersey that Charlotte in U.S. dollars based on the exchange rate is B. $16.39.

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The radius of Deimos to one significant digit in meters is approximately 9.4 m

.

Given the ratio of the Sun-from-Mars distance to Deimos-from-Mars distance is 365,000, the distance between Mars and Deimos can be found to bedeimos distance = Sun-Mars distance / 365,000

Next, we can find the diameter of Deimos by noting that 550 of its diameters is equal to the distance it takes to transit the shadow of Mars during a lunar eclipse.

Let's call the diameter of Deimos "d", so we can

diameter = 1/550 * deimos distance

Finally, the Sun appears about 8.4 times as large as Deimos in the Martian sky. If we call the radius of Deimos "r", then the radius of the Sun is 8.4r.

Using the information given, we can set up the following equation:

deimos distance / (3,000,000 + r) = 8.4r / (3,000,000)Simplifying and solving for r,

we get:r = 9.39 m (rounded to one significant digit)

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To minimize the errors the disc diffusion method results within 24 hours after inoculation

What are the disc diffusion error?

The disc diffusion method should be read 24 hours after inoculation. Allowing plates to sit longer than 24 hours can lead to several errors, including:

To minimize these errors, it is important to read the disc diffusion method results within 24 hours after inoculation.

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