I need urgent help please people ​

There are 8,519,680 hexadecimal numbers. The result is obtained by using the multiplication principle.

Hexadecimal number system is a numbering system with the base of 16. The 16-digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. They are usually denoted by the subscript 16. For example, 429AD₍₁₆₎.

How many combination of hexadecimal numbers that can be made if:

Let's broke the problem into 3 cases.

Using the multiplication principle, we can multiply them all.

The combination of hexadecimal numbers is

= 10 × 13 × 16³

= 8,519,680

Hence, the combination that can be made is 8,519,680 hexadecimal numbers.

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Given Rational Inequality: \(\frac{x}{x^2 - x - 6x} &< -\frac{1}{x^2 - x - 6} \\\) For this inequality, the denominator cannot be 0, which means, x² − x − 6 ≠ 0 (1) It is a factorable quadratic expression.

So, we can write the above inequality as follows:

\(\frac{x}{x^2 - x - 6x} &< -\frac{1}{x^2 - x - 6x} \cdot \frac{(x + 2)(x - 3)}{(x + 2)(x - 3)} \\\)

Now, multiply both sides by (x+2)(x-3), and then simplify as follows: x < −1(x+2)(x-3) This can be written as follows:

\(x(x+2)(x-3) + (x+2)(x-3) < 0(x+2)(x-3)(x+1) < 0\)

The critical points of this inequality are given as x = −2, −1, 3.We can now plot the critical points on a number line as follows: On the interval (−∞, −2), the factor (x+2) is negative.On the interval (−2, −1), the factors (x+2) and (x+1) are positive.On the interval (−1, 3), the factor (x+1) is positive. On the interval (3, ∞), all three factors are positive. For (−∞, −2), we have:\((x+2)(x-3)(x+1) < 0\)

That is, we need 2 negatives and 1 positive.So, the solution set on this interval is: x < −2 For (−2, −1), we have:

\((x+2)(x-3)(x+1) > 0\)

That is, we need all three factors to be positive.So, the solution set on this interval is: −2 < x < −1 For (−1, 3), we have:

\((x+2)(x-3)(x+1) < 0\)

That is, we need 1 negative and 2 positives.So, the solution set on this interval is: −1 < x < 3 For (3, ∞), we have:

\((x+2)(x-3)(x+1) > 0\)

That is, we need all three factors to be positive. So, the solution set on this interval is: x > 3

Therefore, the solution set of the given inequality is: (−∞, −2) ∪ [−1, 3) ∪ (3, ∞) Answer:

The solution set of the given inequality is: (−∞, −2) ∪ [−1, 3) ∪ (3, ∞).

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The causes of variation that can be identified and eliminated are called; Assignable Causes.

There are two primary causes of variation in the quality of a product or process. These two primary causes are called;

Now, Common causes of variation are defined as random causes that we cannot identify. However, Assignable causes of variation are those that can be identified and eliminated.

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Answer:$40

Step-by-step explanation:

Find the price of the item after the discount was applied.

Find the discount percentage that was applied to the price.

Divide the discount percentage by 100.

Subtract that number from 1.

Divide the after-discount price by that number.

This number is the original price of the item, pre-discount.

When computing the given expressions for f(x) = 3x - 1, we find that f(3 + 1) = 15, f(3) + f(1) = 8, f(3-1) = 5, f(3) = 8, f(1) = 2, and f(3-1) = 5.

To find f(3 + 1), we substitute the value of 3 + 1 into the expression for f(x): f(3 + 1) = 3(3 + 1) - 1 = 12 - 1 = 11.

Next, to calculate f(3) + f(1), we substitute the values of 3 and 1 into the expression for f(x) separately and add them together: f(3) + f(1) = (3 * 3 - 1) + (3 * 1 - 1) = 8.

For f(3-1), we substitute the value of 3 - 1 into the expression for f(x): f(3-1) = 3(3-1) - 1 = 5.

Since f(3) and f(1) are both defined as 3x - 1, they have the same value: f(3) = f(1) = 8.

Finally, to compute f(3) f(1), we multiply the values of f(3) and f(1) together: f(3) f(1) = (3 * 3 - 1)(3 * 1 - 1) = 5.

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\(~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ (4)^{\frac{-4}{2}} \implies (4)^{-2}\implies 4^{-2}\implies \cfrac{1}{4^2}\implies \cfrac{1}{16}\)

9514 1404 393

Answer:

  62°

Step-by-step explanation:

The measure of the external angle where the secants meet is half the difference of the arcs they subtend.

  ∠A = (DE - BC)/2

  2×∠A = DE -BC

  DE = BC + 2×∠A

  DE = 38° +2(12°)

  arc DE = 62°

Lorraine can fill 8 jars with the tomatoes from the 2.5-gallon pot.

First, we need to convert the volume of the pot from gallons to quarts, since the jars are measured in quarts:

2.5 gallons = 2.5 * 4 quarts = 10 quarts

Next, we can divide the total volume of the pot in quarts by the volume of each jar in quarts to find the number of jars Lorraine can fill:

10 quarts / 1.25 quarts per jar = 8 jars

So Lorraine can fill 8 jars with the tomatoes from the 2.5-gallon pot.

Mensuration is a branch of mathematics that deals with the measurement of various geometric figures and objects, such as lengths, areas, and volumes. It is concerned with finding the size, shape, and measurement of geometric objects, such as points, lines, circles, polyggon, and solids.

Mensuration is used in various areas of mathematics, science, and engineering to solve problems involving measurements, such as finding the area of a rectangle, the volume of a cylinder, the circumference of a circle, or the surface area of a sphere.

Mensuration provides a set of mathematical formulas and methods for measuring geometric objects, and it requires knowledge of basic concepts such as perimeter, area, volume, and surface area. These concepts are used to find the size of objects and to compare different objects to one another based on their measurements.

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Answer:

Arithmetic

Step-by-step explanation:

300: 30: 3

100: 10: 1

Answer:

The first one is not a function, the 2nd one is a function

Step-by-step explanation:

Ok so first you have to like write all the inputs and outputs and like draw lines showing which goes to which.

If one of the inputs, "x" values goes to more than one of the outputs, "y" values than it isn't a function.

Answer:

\(\huge\boxed{\sf x=4,\ y=7}\)

Step-by-step explanation:

Given that:

(4,y) = (x,7) [Both are equal]

Comparing both sides of the equation:

we will get,

4 = x

or

x = 4

and,

y = 7

\(\rule[225]{225}{2}\)

The radius of the spherical part is 3 inches and the length of the tube is 21 cm.

The capacity of a cylinder, which determines how much material it can hold, is determined by the cylinder's volume. There is a formula for the volume of a cylinder that is used in geometry to determine how much of any quantity, whether liquid or solid, can be immersed in it uniformly.

Given that the volume when the water is fully dipped is 4554 / 7 cm³. The volume when the length is 9 cm empty is 396 cm³.

The two equations can be formed as below:-

4554 / 7 = πr²l + (2/3)πr³

396 = πr²( l - 9 ) + (2/3)πr³

Subtract the second equation from the first,

( 4554 / 7 ) - 396 = 9πr²

9πr² = 254.5

r² = 9

r = 3 cm

The length will be calculated as:-

4554 / 7 = πr²l + (2/3)πr³

4554 / 7 = π( 3 )²l + (2/3)π(3)³

l = 21 cm

Therefore, the tube's length is 21 cm, and the spherical part's radius is 3 inches.

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Answer: c 2.18

Step-by-step explanation:

pray to god that its right

Answer:

Part A: yes

Part B: yes

Part C: yes

Step-by-step explanation:

Part A:

77² + 420² = 427²

5,929 + 176,400 = 182,329

182,329 = 182,329

---------------------------------------------------------

Part B:

279² + 440² = 521²

77,841 + 193,600 = 271,441

271,441 = 271,441

----------------------------------------------------------

Part C:

39² + 760² = 761²

1,521 + 577,600 = 579,121

579121 = 579,121

----------------------------------------------------------

There are 16 bit strings of length eight that contain either three consecutive 0s or four consecutive 1s.

To count the number of bit strings of length eight that contain either three consecutive 0s or four consecutive 1s, we can use the principle of inclusion-exclusion.

Step 1: Count the total number of bit strings of length eight.

Each bit in the string can have two possible values (0 or 1), so the total number of bit strings of length eight is 2^8 = 256.

Step 2: Count the number of bit strings with three consecutive 0s.

We can treat the three consecutive 0s as a single block and consider the remaining five bits. The block of three 0s can start from the first position to the sixth position, so we have 6 choices for its starting position. The remaining five bits can have two possible values (0 or 1), so there are 2^5 = 32 choices for the remaining bits. Therefore, the number of bit strings with three consecutive 0s is 6 * 32 = 192.

Step 3: Count the number of bit strings with four consecutive 1s.

Similar to Step 2, we treat the four consecutive 1s as a single block and consider the remaining four bits. The block of four 1s can start from the first position to the fifth position, so we have 5 choices for its starting position. The remaining four bits can have two possible values (0 or 1), so there are 2^4 = 16 choices for the remaining bits. Therefore, the number of bit strings with four consecutive 1s is 5 * 16 = 80.

Step 4: Subtract the overlaps.

In Step 2 and Step 3, we have counted some bit strings twice. Specifically, there are bit strings that contain both three consecutive 0s and four consecutive 1s. To correct for this, we need to subtract the number of bit strings that have both patterns.

To have both patterns, we consider the starting position of the block of three 0s and the block of four 1s. The block of three 0s can start from the first position to the fourth position (leaving three positions for the block of four 1s). So, we have 4 choices for the starting position of the block of three 0s. The remaining three positions can have two possible values (0 or 1), so there are 2^3 = 8 choices for the remaining bits. Therefore, the number of bit strings with both patterns is 4 * 8 = 32.

Step 5: Calculate the final count.

To obtain the number of bit strings that contain either three consecutive 0s or four consecutive 1s, we subtract the overlaps from the total count:

Total count - Overlaps = 256 - 192 - 80 + 32 = 16.

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Data collected over several time periods are called time series data.

Time series data refers to data that is collected over several time periods. It captures a sequence of observations of a variable of interest over time, such as sales figures, stock prices, temperature, and so on. The observations are usually taken at regular intervals, such as daily, weekly, monthly or yearly, and the data reflects the changes in the variable over time.

Time series data is useful for identifying trends, patterns, and seasonality in the data, and for making predictions about future values. It's often used in economic forecasting, weather forecasting, and other fields where understanding how a variable changes over time is important.

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The probability that Austin rolls a 2 or a 7, P is 1/6

From the question, we have the following parameters that can be used in our computation:

Rolling a 12-sided number cube

The sample space of a 12-sided number cube is

S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

From the above, we have

Outcomes of a 2 or 7 = 2

Sample size = 12

Using the above as a guide, we have the following:

The probability that Austin rolls a 2 or a 7, P = 2/12

Simplify

The probability that Austin rolls a 2 or a 7, P = 1/6

Hence, the probability that Austin rolls a 2 or a 7, P is 1/6

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f(n) = ϴ(g(n)) is not true in cases B(sqrt(n)log(n), C(\(3^n 5^n\)), and D(sin(n)+3 cos(n)+1).

A) \(log(n^200) log(n^2)\)

Here, f(n) = \(log(n^200)\) and g(n) = \(log(n^2)\). Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = \([log(n^200) / log(n^2)]\) = 100

This means that as n approaches infinity, the ratio f(n) / g(n) is constant, and so we can say that f(n) = ϴ(g(n)). Therefore, f(n) = ϴ(g(n)) is true in this case.

B) sqrt(n) log(n) Here, f(n) = sqrt(n) and g(n) = log(n). Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = [sqrt(n) / log(n)]

As log(n) grows much slower than sqrt(n) as n approaches infinity, this limit approaches infinity. Therefore, we cannot say that f(n) = ϴ(g(n)) is true in this case.

C) 3^n 5^n

Here, f(n) = \(3^n\) and g(n) = \(5^n\) . Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = \([3^n / 5^n]\)

As \(3^n\) grows much slower than \(5^n\) as n approaches infinity, this limit approaches zero. Therefore, we cannot say that f(n) = ϴ(g(n)) is true in this case.

D) sin(n) + 3 cos(n) + 1

Here, f(n) = sin(n) + 3 and g(n) = cos(n) + 1. Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = [sin(n) + 3] / [cos(n) + 1]

As this limit oscillates between positive and negative infinity as n approaches infinity, we cannot say that f(n) = ϴ(g(n)) is true in this case.

Therefore, f(n) = ϴ(g(n)) is not true in cases B, C, and D.

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The expression that correctly calculates the perimeter of the shape is given as follows:

P = 2(6s + πr).

In which:

The perimeter of a square of side length s is given as follows:

P = 4s.

Hence, for three squares, the perimeter is given as follows:

P = 3 x 4s

P = 12s.

The perimeter, which is the circumference of a semicircle of radius r, is given by the equation presented as follows:

C = πr.

Hence the perimeter of two semicircles is given as follows:

C = 2πr.

The perimeter of the entire shape is given by the sum of the perimeter of each shape, hence:

P = 12s + 2πr.

P = 2(6s + πr).

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Answer:

18y^3 + 24y^5.

Step-by-step explanation:

6y^3(3 + 4y^2)

= 6*3 y^3 + 6*4 y^(3+2)

= 18y^3 + 24y^5.

Answer:

4

Step-by-step explanation:

are you bored? this was funny though

The value of 16.023-5.58 = 10.4430 rounded off to the correct number of significant figures.

To perform the calculation and round the answer to the correct number of significant figures for the expression 16.023-5.58, follow these steps: First, subtract the given values of 16.023 and 5.58.16.023 - 5.58 = 10.443. The difference value is 10.443.

Now, round the answer to the correct number of significant figures by identifying the least significant digit that has been given in the question.

Here, the least significant figure is 2. The next digit after 2 is 3 which is greater than or equal to 5, so round up the digit. Therefore, rounding off 10.443 to the nearest thousandth gives 10.4430.

Thus, the value of 16.023-5.58 = 10.4430 rounded off to the correct number of significant figures.

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Answer:

10

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

10 x 10 is 100

Answer:

prime

Step-by-step explanation:

this equation is not factorable

Answer:

19. 5/6

20. 1 4/8

21.  1

Step-by-step explanation:

Answer:

8 1/6 written as an improper factrion is 49/6

Step-by-step explanation:

Answer:

49/6

Step-by-step explanation:

8*6=48

48+1=49

You can creare an improper fraction by mulitplying the denominator with the whole number then add the numerator