I really just need help with part C, Also this is 50 points!

Answer: $13.75

Step-by-step explanation:

Since Mrs. Chin paid a 20 percent tip on the bill for lunch and the tip amount was $2.75, then the bill for lunch before the tip was added to it will be calculated thus:

Let the bill for lunch be represented by x. Therefore,

20% of x = $2.75

20/100 × x = $2.75

0.2 × x = $2.75

0.2x = $2.75

x = $2.75/0.2

x = $13.75

Therefore, the bill is $13.75 before the too was added.

The percentage change in the quantity οf οil in the cοntainer is 75%.

First: Find οut the difference between the twο numbers yοu are cοmparing.

Then: Divide the change by the οriginal number and multiply the answer by 100.

Tο find the percentage change, we first need tο find the difference between the initial and final quantities οf οil:

Change in quantity = Final quantity - Initial quantity

Change in quantity = 14 - 8

Change in quantity = 6

Then, we can use the fοrmula fοr percentage change:

Percentage change = (Change in quantity / Initial quantity) x 100%

Plugging in the values we get:

Percentage change = (6 / 8) x 100%

Percentage change = 0.75 x 100%

Percentage change = 75%

Therefοre, the percentage change in the quantity οf οil in the cοntainer is 75%.

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The speed of the faster car is 40 miles/hr.

both cars travel for same time , so let that time be 't'

car 1 :

distance travelled = 75 miles

let the speed of the car be = x miles/hr

∴ time (t)  = distance / speed

              t  =   75 / x               .............(1)

car 2 :

distance travelled = 100 miles

speed of the car is = x + 10 miles/hr  ( already provided )

∴  time ( t) = distance / speed

            t  = 100/ (x+10)        ..............(2)

    now as the time for both the cases is same  , so we equate eqn (1) and eqn (2) .

∴ 75/x  =  100/ (x+10)

3x + 30 = 4x

x = 30

so the speed of the 1st car will be 30 miles / hr

and the speed of the 2nd car ( faster car ) will  be x + 10 = 40 miles/hr

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Answer:

Slope = -2.5

Step-by-step explanation:

use the formula:

y2-y1/x2-x1

I a case whereby a shop earns a profit of 1300 on every heater sold and incurs a loss of 1800 on every fan sold, its total profit at the end of the day in which 25 heaters and 7 fans were sold.  is 26900 rupee.

Given that  profit on every heater sold=  1300

loss on every fan sold = 1800

Profit on every heater =  [1300x25]

=32500 rupee

Loss on every fan =[800x7]

=5600 ruppee

Therefore the profit = [32500-5600]

=26900

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Answer:

B. 4.09 cm²

Step-by-step explanation:

Let point O be the center of the circle.

As the center of the circle is the midpoint of the diameter, place point O midway between P and R.

Therefore, line segments OP and OQ are the radii of the circle.

As the radius (r) of a circle is half its diameter, r = OP = OQ = 5 cm.

As OP = OQ, triangle POQ is an isosceles triangle, where its apex angle is the central angle θ.

To calculate the shaded area, we need to subtract the area of the isosceles triangle POQ from the area of the sector of the circle POQ.

To do this, we first need to find the measure of angle θ by using the chord length formula:

\(\boxed{\begin{minipage}{5.8 cm}\underline{Chord length formula}\\\\Chord length $=2r\sin\left(\dfrac{\theta}{2}\right)$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the central angle.\\\end{minipage}}\)

Given the radius is 5 cm and the chord length PQ is 6 cm.

\(\begin{aligned}\textsf{Chord length}&=2r\sin\left(\dfrac{\theta}{2}\right)\\\\\implies 6&=2(5)\sin \left(\dfrac{\theta}{2}\right)\\\\6&=10\sin \left(\dfrac{\theta}{2}\right)\\\\\dfrac{3}{5}&=\sin \left(\dfrac{\theta}{2}\right)\\\\\dfrac{\theta}{2}&=\sin^{-1} \left(\dfrac{3}{5}\right)\\\\\theta&=2\sin^{-1} \left(\dfrac{3}{5}\right)\\\\\theta&=73.73979529...^{\circ}\end{aligned}\)

Therefore, the measure of angle θ is 73.73979529...°.

Next, we need to find the area of the sector POQ.

To do this, use the formula for the area of a sector.

\(\boxed{\begin{minipage}{6.4 cm}\underline{Area of a sector}\\\\$A=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}\)

Substitute θ = 73.73979529...° and r = 5 into the formula:

\(\begin{aligned}\textsf{Area of section $POQ$}&=\left(\dfrac{73.73979529...^{\circ}}{360^{\circ}}\right) \pi (5)^2\\\\&=0.20483... \cdot 25\pi\\\\&=16.0875277...\; \sf cm^2\end{aligned}\)

Therefore, the area of sector POQ is 16.0875277... cm².

Now we need to find the area of the isosceles triangle POQ.

To do this, we can use the area of an isosceles triangle formula.

\(\boxed{\begin{minipage}{6.7 cm}\underline{Area of an isosceles triangle}\\\\$A=\dfrac{1}{2}b\sqrt{a^2-\dfrac{b^2}{4}}$\\\\where:\\ \phantom{ww}$\bullet$ $a$ is the leg (congruent sides). \\ \phantom{ww}$\bullet$ $b$ is the base (side opposite the apex).\\\end{minipage}}\)

The base of triangle POQ is the chord, so b = 6 cm.

The legs are the radii of the circle, so a = 5 cm.

Substitute these values into the formula:

\(\begin{aligned}\textsf{Area of $\triangle POQ$}&=\dfrac{1}{2}(6)\sqrt{5^2-\dfrac{6^2}{4}}\\\\ &=3\sqrt{25-9}\\\\&=3\sqrt{16}\\\\&=3\cdot 4\\\\&=12\; \sf cm^2\end{aligned}\)

So the area of the isosceles triangle POQ is 12 cm².

Finally, to calculate the shaded area, subtract the area of the isosceles triangle from the area of the sector:

\(\begin{aligned}\textsf{Shaded area}&=\textsf{Area of sector $POQ$}-\textsf{Area of $\triangle POQ$}\\\\&=16.0875277...-12\\\\&=4.0875277...\\\\&=4.09\; \sf cm^2\end{aligned}\)

Therefore, the area of the shaded region is 4.09 cm².

The maximum height of the rocket, in meters, is 245 meters.

A plane curve produced by a moving point such that its separation from a fixed point equals that of a fixed line is a parabola.

Given:

The height of a rocket, in meters, launched from a platform after t seconds can be modeled by the function:

h(t) = -5t² + 50t + 120

In order to find the maximum height:

First, we find the vertex (\(t_{max}\), \(h_{max}\))

\(t_{max}\) = -b/2a = -50/-10 = 5 seconds.

So, \(h_{max}\) =  -5(5)² + 50(5) + 120

= -125 + 250 + 120

= 245.

Therefore, the height is 245 meters.

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Answer:

A. 4a + 3b + 5

B. 24

C. 8x - 12

Step-by-step explanation:

a + 2b + 5 + 3a + b

To simplify this, we'll want to group the similar terms together. In other words, put all of the a's first, then all of the b's, then just the numbers.

a + 2b + 5 + 3a + b

a + 3a + 2b + b + 5

Now, we want to add those similar terms, according to this:

a + a = 2a

So in our expression, we first have

a + 3a = 4a

then

2b + b = 3b

and finally 5, which is just... 5.

Thus, our expression simplified is:

4a + 3b + 5

Now let's do the same for the other expressions.

12 - a + a + 12

First, group them.

12 + 12 - a + a

Then, add them. Let's see, first 12 + 12:

12 + 12 = 24

Then -a + a:

- a + a = 0

24 + 0 = 24

Our 2nd expression, simplified, is just 24.

Finally,

4x - 12 + 4x

First group the x's:

4x + 4x - 12

And then add them, first 4x + 4x:

4x + 4x = 8x

And of course, -12 is just -12.

Thus, our third expression simplified is:

8x - 12

A. 4a + 3b + 5

B. 24

C. 8x - 12

The earth is 40000 kilometers around. There is no need to round off because the circumference already contains significant figures.

How do I calculate a circle's circumference?

A circle's diameter is multiplied by to determine its circumference (pi). You can also determine the circumference by multiplying 2radius by pi (=3.14).

Given: theta angle (central) = 7.2°; arc length S = 800 km

This indicates that an 800 km long arc is extending a circle with a 7.2° center angle ( earth in this case).

By definition, "An arc's length is a portion of a circle's diameter."

Therefore, we must first establish what percentage of the circle the specified arc length represents.

360° is a complete circle.

Thus, the fraction equals 7.2°/360°, or 1/50.

As a result, the stated arc length (800km) with a 7.2° central angle is 1/50th of the entire circle.

Thus, the whole circumference is 800 x 50, or 40000 km.

Alternately, you can calculate circumference using the formula below:

360° center angle x arc length as the circumference (theta)

Values substituted: circumference 800 = 360° 7.2°

circumference = 360°, 800°, and 7.2°, or 40000 kilometers

Therefore, the earth is 40000 kilometers around. There is no need to round off because the circumference already contains significant figures.

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Which of the following is an accurate definition for the power of a statistical test is C. The power of a statistical test refers to the probability of rejecting a false null hypothesis. This means that the test is able to correctly identify when there is a significant difference between two groups or conditions.

statistical tests are used to determine whether the results of an experiment are likely due to chance or whether there is a real effect. The null hypothesis states that there is no significant difference, while the alternative hypothesis states that there is. The power of a statistical test refers to the ability of the test to correctly reject the null hypothesis when it is false, and thus support the alternative hypothesis.

, the power of a statistical test is the probability of correctly rejecting a false null hypothesis, which indicates that there is a significant difference between two groups or conditions.

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Answer:

8

Step-by-step explanation:

\(x^2-2x \\x=4\\(4)^2-2(4)\\16-8\\8\)

This statement is true

A probability is a numerical value that indicates the chance, or likelihood, of a specific event occurring. Probability is the measure of the likelihood of a random event happening, and it is expressed as a number between 0 and 1, with 0 implying that the event would never occur and 1 implying that it is certain to happen.

The probability of an event happening is referred to as its likelihood. Probability can be expressed as a fraction, percentage, or decimal, and it is a vital tool in statistics. It is frequently utilized in mathematics to estimate real-world situations that involve random variables such as coin flips, weather patterns, stock market trends, and even sporting events.

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However, with just these two components, we can get a sense of the general direction and magnitude of the fluid's movement.

A flow field can be defined as the way in which fluid moves through a given space. In this particular example, the flow field is defined by two components, u and v. The u component is given as (2x^2+1) m/s, where x is in meters. The v component is given as (xy) m/s, where both x and y are in meters. These components tell us how the fluid is moving in both the x and y directions. The u component increases as x increases, while the v component increases as both x and y increase. To fully understand the flow field, we would need to visualize how the fluid is moving in three-dimensional space.

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0>1,If a function f is constructed recursively, at least one of its values, f(x), must be defined in terms of f(y), where x>y.

Explanation:

0>1.

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Answer:

130°

Step-by-step explanation:

1. 59 + 71 (We do this because we want to find out their total to help us find out what the angle next to x is)

2. This should have given you 130°. Then, we will subtract 130 from 180 (180-130) (We do this because angles in a triangle add up to 180, so we want to find out what the single angle is).

3. This should have given you 50°. Since we know that angles on a straight line add up to 180°, we subtract 50 from 180 (180-50), and will eventually end up with 130°, so x=130°.

Let's look at the image and think about it for a second. We are given an exterior angle, and two opposite interior angles.

The sum of all angles in a triangle are equal to 180˚. If we look at angle ∠x , we notice something: it is a supplementary angle! ∠x + its supplementary angle is equivalent to 180. Conveniently enough, this supplementary angle is also an interior angle of the triangle.

You might be thinking, "Okay, so ∠x is a supplementary angle. Cool, so what?" Allow me to explain. Let's represent the unknown interior angle inside the triangle as 'n' (this isn't necessary to solve for x, but I'm just trying to prove how the solution works so you'll understand how to do these)

∠x + ∠n = 180˚ (These angles are supplementary)

∠n + 59˚ + 71˚ = 180˚ (The sum of interior angles of a triangle is 180˚)

If we isolate ∠n in both equations, then:

∠n = 180˚ - ∠x

∠n = 180˚ - 59˚ - 71˚

Since the right sides of both equations are equal, we can turn it into a single equation:

∠n = ∠n

180˚ - ∠x = 180˚ - 59˚ - 71˚

Isolate ∠x:

∠x = 59˚ + 71˚

So, what does this mean? This proof, essentially, establishes the fact that an exterior angle is equivalent to the sum of the two opposite interior angles. As you can see with the proof we made, ∠x is equal to the two opposite angles in the triangle, 59˚ and 71˚.

Now, let's get ourselves a definitive answer:

∠x = (59˚ + 71˚)

∠x = 130˚

If you have any further questions on how I got to the answer, just ask in the comments! Good luck!

- breezyツ

Answer:

-43

Step-by-step explanation:

-1-7(6)

-1-42

-43

The surface area and volume of the triangular prism are 312 m², and its volume is 264 m³.

The triangular prism has a right triangle base with legs measuring 8 m and 6 m, a hypotenuse of 10 m, and a height (prism) of 11 m. To find the surface area, we need to determine the areas of all the faces and add them together. The prism has three rectangular faces and two triangular bases.

First, let's find the area of the triangular base:
A = (1/2) × base × height = (1/2) × 8 m × 6 m = 24 m²

Now let's find the areas of the rectangular faces. Their dimensions are 11 m (height of prism) and the sides of the triangle (6 m, 8 m, and 10 m).

Face 1 (with side 6 m): A = 6 m × 11 m = 66 m²
Face 2 (with side 8 m): A = 8 m × 11 m = 88 m²
Face 3 (with side 10 m): A = 10 m × 11 m = 110 m²

Add the areas of all the faces to find the surface area:
Surface area = 24 m² (base) + 24 m² (base) + 66 m² + 88 m² + 110 m² = 312 m²

Next, let's find the volume of the triangular prism:
Volume = base area × height (prism) = 24 m² × 11 m = 264 m³

So, the surface area of the triangular prism is 312 m², and its volume is 264 m³.

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Answer:

6

Step-by-step explanation:

3(1)=3       3(2)=6          3(3)=9      3(4)=12     3(5)=15

3(6)=18     3(7)=21         3(8)=24

----------------------------------------------------

3(6)=18 is closest to 20

so the greatest number of batches Xiaoming can make is 6.

The following which represents the measure of ∠WXS is given by angle 60° which is option B.

When two lines meet at a point, they form angles. An "angle" is the measurement of the "opening" between these two rays. The symbol for it is. Angles are typically measured in degrees and radians, which are units of rotation or circularity. Points are a piece of our everyday life. Roads, buildings, and sporting facilities are all designed with angles by engineers and architects. Allow us to more deeply study the meaning of points in Maths, the importance of points, the various properties of points alongside some point models.

At the point when two harmonies of a circle cross one another, the proportion of the upward point framed rises to half of the amount of the captured circular segments, in light of the meeting harmonies hypothesis.

Given the following measures:

m(SW) = 38°

m(WR) = 98°

m(RT) = 180 - m(WR) (semicircle = 180°)

m(RT) = 180 - 98

m(RT) = 82°

m∠WXS = 1/2[m(RT) + m(SW)] (intersecting chords theorem)

m∠WXS = 1/2(82 + 38)

m∠WXS = 60°

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Complete question:

In circle K, diameter TW intersects chord RS at X such that mSW = 38° and mWR 98° . Which of the

following represents the measure of ∠WXS ?

Answer:

y = 4/3x + 1

Step-by-step explanation:

slope = rise over run

slope = 4 rise 3 run

slope = 4/3

Answer:

1st Option

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Slope Formula: \(m=\frac{y_2-y_1}{x_2-x_1}\)

Step 1: Find slope m

\(m=\frac{5-1}{3-0}\)

\(m=\frac{4}{3}\)

y = 4/3x + b

Step 2: Find y-intercept b

(0, 1)

Step 3: Write linear equation

y = 4/3x + 1

The changes in weights (b) did not affect the decision as Worldwide Delivery remained the most suitable provider. However, the increase in ratings for Overnight Shipping (c) resulted in it becoming the most suitable outsourcing provider according to the given criteria.

1) Factor rating
2) Outsourcing provider
3) Logistics services
4) Weights
5) Ratings

a) Factor rating is a method used to evaluate and select an outsourcing provider based on predetermined criteria. In this case, Fernando Garza's firm wants to select a logistics services provider using factor rating. The table provided includes the weights assigned to different criteria (quality, delivery, and cost) and the ratings of three potential providers (Overnight Shipping, Worldwide Delivery, and United Freight).

To make his decision, Garza needs to multiply the weight of each criterion by the rating of each logistics provider and sum up the results. The highest sum indicates the most suitable outsourcing provider. Let's calculate the results:

Overnight Shipping:
Quality: 5 (weight) x 90 (rating) = 450
Delivery: 3 (weight) x 70 (rating) = 210
Cost: 2 (weight) x 70 (rating) = 140
Total: 450 + 210 + 140 = 800

Worldwide Delivery:
Quality: 5 (weight) x 80 (rating) = 400
Delivery: 3 (weight) x 85 (rating) = 255
Cost: 2 (weight) x 80 (rating) = 160
Total: 400 + 255 + 160 = 815

United Freight:
Quality: 5 (weight) x 75 (rating) = 375
Delivery: 3 (weight) x 70 (rating) = 210
Cost: 2 (weight) x 95 (rating) = 190
Total: 375 + 210 + 190 = 775

Based on these calculations, Worldwide Delivery has the highest total score of 815, making it the most suitable outsourcing provider according to the given criteria.

b) Garza decides to increase the weights for quality, delivery, and cost to 10, 6, and 4, respectively. This change means that Garza now considers quality to be twice as important as before, delivery to be 1.5 times as important, and cost to be twice as important.

Let's recalculate the results with the updated weights:

Overnight Shipping:
Quality: 10 (weight) x 90 (rating) = 900
Delivery: 6 (weight) x 70 (rating) = 420
Cost: 4 (weight) x 70 (rating) = 280
Total: 900 + 420 + 280 = 1600

Worldwide Delivery:
Quality: 10 (weight) x 80 (rating) = 800
Delivery: 6 (weight) x 85 (rating) = 510
Cost: 4 (weight) x 80 (rating) = 320
Total: 800 + 510 + 320 = 1630

United Freight:
Quality: 10 (weight) x 75 (rating) = 750
Delivery: 6 (weight) x 70 (rating) = 420
Cost: 4 (weight) x 95 (rating) = 380
Total: 750 + 420 + 380 = 1550

With the updated weights, the new results show that Worldwide Delivery still has the highest total score of 1630, making it the most suitable outsourcing provider.

c) If Overnight Shipping's ratings for each of the factors increase by 10%, we need to recalculate the results while considering these changes.

Overnight Shipping:
Quality: 10 (weight) x (90 + 10% of 90) = 990
Delivery: 6 (weight) x (70 + 10% of 70) = 462
Cost: 4 (weight) x (70 + 10% of 70) = 308
Total: 990 + 462 + 308 = 1760

With the increased ratings, Overnight Shipping now has the highest total score of 1760, making it the most suitable outsourcing provider.

In summary, the changes in weights (b) did not affect the decision as Worldwide Delivery remained the most suitable provider. However, the increase in ratings for Overnight Shipping (c) resulted in it becoming the most suitable outsourcing provider according to the given criteria.

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Step-by-step explanation:

18m^3+ 9m^2 + 4m + 7=(9m^2 + 7)

18m^3+9m^2+4m+7=9m^2 + 7

18m^3+9m^2+4m+7-7=9m2+7-7

18m^3+9m^2+4m=9m^2

18m^3+9m^2+4m-9m^2-9m^2

18m^3+4m=0

factor 18m^3+4m:. 2m(9m^2+2)

2m (9m^2+2)=0

using the zero factor principle: if an=0 then a=0 or b=0

m=0 or 9m^2+2=0

solve 9m^2+2=0:. m= i√2 m= -i√2

__, __

3 3

The solutions are:

m=0, m= i√2 m= -i√2

__, __

3 3

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If the surface area of the rectangular box is 4 m² then the dimensions that maximize its volume is  (2/√3 , 2/√3 , 1/√3)  .

In the question ,

let length of rectangular box be = l

let width of rectangular box be = b and

let height of rectangular box be = h .

Since the box has no top ,

So , the surface area is = lb + 2bh + 2hl = 4

we get h = (4-lb)/(2l + 2b) .

The volume of the box is given as  V = l×b×h .

Substituting the value of h from above in the volume formula , we get ,

V = lb(4-lb)/(2l + 2b)

differentiating it with respect to l ,

we get ,

dV/dl = [((2l+2b)(4b-2lb²)-lb(4-lb).2)/(2l+2b)²] = 0

Simplifying further ,

we get ,

2l² + 4lb - 8 = 0       ....equation(1)

Differentiating volume with respect to "b" .

dV/db = [((2l+2b)(4l-2l²b)-lb(4-lb).2)/(2l+2b)²] = 0

simplifying further ,

we get ,

2b² + 4lb - 8 = 0        ...equation(2) .

Simplifying equation(1) and (2) , we get

l = b  ,

Substituting l = b in equation(1) ,

we get ,

2l² + 4l² = 8

l = 2/√

and b = 2/√3 .

Substituting the values in h ,

we get ,

h = (4-lb)/(2l + 2b)

h = 1/√3 .

Therefore , the dimensions of the box is (2/√3 , 2/√3 , 1/√3) .

The given question is incomplete , the complete question is

A rectangular box with no top is to have a surface area of 4 m². find the dimensions (in m) that maximize its volume.

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Answer:

C

Step-by-step explanation:

We want to simplify:

\((3a-2b)^2\)

Recall the perfect square trinomial pattern:

\((a+b)^2=a^2+2ab+b^2\)

Let a = 3a and b = -2b. Thus:

\((3a-2b)^2=(3a)^2+2(3a)(-2b)+(-2b)^2\)

Simplify:

\(=9a^2-12ab+4b^2\)

Our answer is C.

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

\(D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.\)

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

\(D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.\)

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

\(D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.\)

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

\(450 = 2.6 + \dfrac{v^2}{22}\)

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

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ANSWER

D. None of the above

EXPLANATION

We want to determine if x = 3 is the solution to the equation given:

To solve this equation, we have to find the square root of both sides of the equation (the solution will consist of a negative and positive number):

Therefore, Diego is incorrect but none of the reasons stated is correct.

Hence, the answer is None of the above.

The amount of the discount is calculated as 2% of the net amount due ($22,500 - $2,250 - $1,050 = $19,200).

May 3:

Inventory purchase:

Inventory (Dr) $33,000

Cash (Cr) $33,000

May 5:

Sale of inventory to Macy Company:

Accounts Receivable - Macy Company (Dr) $22,500

Sales (Cr) $22,500

Cost of goods sold:

Cost of Goods Sold (Dr) $16,500

Inventory (Cr) $16,500

May 7:

Return of inventory by Macy Company:

Accounts Receivable - Macy Company (Cr) $2,250

Sales Returns and Allowances (Dr) $2,250

Cost of goods sold (restored units):

Inventory (Dr) $1,650

Cost of Goods Sold (Cr) $1,650

May 8:

Allowance given to Macy Company:

Sales Returns and Allowances (Dr) $1,050

Accounts Receivable - Macy Company (Cr) $1,050

May 15:

Receipt of payment from Macy Company:

Cash (Dr) $21,450

Sales Discount (Dr) $450

Accounts Receivable - Macy Company (Cr) $22,500

The Sales Discount account is used to record the amount of the discount given to Macy Company for paying within the discount period (2/10, n/60). The amount of the discount is calculated as 2% of the net amount due ($22,500 - $2,250 - $1,050 = $19,200).

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