Answer:
Yeah you are right. None of the other options make much sense and this is a function.
Step-by-step explanation:
the life of light bulbs is distributed normally. the variance of the lifetime is 625 and the mean lifetime of a bulb is 520 hours. find the probability of a bulb lasting for at most 549 hours. round your answer to four decimal places.
Light bulbs is normally distributed with a variance of 625 and a mean lifetime of 520 hours, we need to calculate the cumulative probability up to 549 hours. The answer will be rounded to four decimal places.
Given a normally distributed lifetime with a mean of 520 hours and a variance of 625, we can determine the standard deviation (σ) by taking the square root of the variance, which gives us σ = √625 = 25.
To find the probability of a bulb lasting for at most 549 hours, we need to calculate the area under the normal distribution curve up to 549 hours. This can be done by evaluating the cumulative distribution function (CDF) of the normal distribution at the value 549, using the mean (520) and standard deviation (25).
The CDF will give us the probability that a bulb lasts up to a certain point. Rounding the result to four decimal places will provide the desired precision.
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The problem involves using normal distribution to find the probability of a given outcome. Using the Z-score, we can determine that the probability of a light bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%
Explanation:Given the mean (µ) of the lifetime of a bulb is 520 hours. Also, the variance (σ²) is given as 625. Thus, the standard deviation (σ) is the square root of the variance, which is 25.
To find the probability of a bulb lasting for at most 549 hours, we first calculate the Z score. The Z-score formula is given as follows: Z = (X - µ) / σ, where X is the number of hours, which is 549. So substitute the given values into the formula. Z = (549 - 520) / 25, the Z value is 1.16.
We then look up the Z-table to find the probability associated with this Z-score (1.16), which is approximately 0.8770. Therefore, the probability of a bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%.
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b. use the overhead rate in (a) to determine the amount of total and per-unit overhead allocated to each of the three products, rounded to the nearest dollar.
The amount of total and per-unit overhead allocated to each of the three products using overhead rate is equal to,
Total Per Unit Factory Overhead , Cost Factory Overhead Cost
Flutes $530 $1,060,000
Clarinets $795 $1,192,500
Oboes $397.5 $695,625
Total $1,722.5 $2,948,125
Budgeted factory overhead cost = $2,948,125
The single plantwide overhead rate
= Dividing the budgeted factory overhead cost by the total budgeted direct labor hours.
For this,
Flutes= 2,000×2
= 4,000 hours
Clarinets= 1,500×3
= 4,500 hours
Oboes= 1,750×1.5
= 2,625 hours
Total direct labor hours = 11,125
Substitute the value we have,
⇒ Single plantwide overhead rate = $2,948,125 / (2,000 x 2.0 + 1,500 x 3.0 + 1,750 x 1.5)
= $2,948,125 / 11,125
= $265 per direct labor hour
To allocate overhead to each product
=Multiply the overhead rate by the budgeted direct labor hours per unit for each product.
Substitute the value we have,
Flutes,
$265 x 2.0 = $530 total overhead cost, $265 per unit
Clarinets,
$265 x 3.0 = $795 total overhead cost, $265 per unit
Oboes,
$265 x 1.5 = $397.5 total overhead cost, $265 per unit
And
Total factory overhead cost allocated = Estimated manufacturing overhead rate× Actual amount of allocation base
For,
Flutes
= 4,000× 265
= $1,060,000
Clarinets
= 4,500×265
= $1,192,500
Oboes
= 2,625×265
= $695,625
This implies,
The total and per-unit overhead allocated to each product, rounded to the nearest dollar is,
Total Per Unit Factory Overhead , Cost Factory Overhead Cost
Flutes $530 $1,060,000
Clarinets $795 $1,192,500
Oboes $397.5 $695,625
Total $1,722.5 $2,948,125
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The above question is incomplete, the complete question is:
Bach Instruments Inc. makes three musical instruments: flutes, clarinets, and oboes. The budgeted factory overhead cost is $2,948,125. Overhead is allocated to the three products on the basis of direct labor hours. The products have the following budgeted production volume and direct labor hours per unit:
Budgeted Production Volume Direct Labor Hours Per Unit
Flutes 2,000 units 2.0
Clarinets 1,500 3.0
Oboes 1,750 1.5
a. Determine the single plantwide overhead rate.
$ per direct labor hour
b. Use the overhead rate in (a) to determine the amount of total and per-unit overhead allocated to each of the three products, rounded to the nearest dollar.
Total Per Unit
Factory Overhead Cost Factory Overhead Cost
Flutes $ $
Clarinets
Oboes
Total $
Will mark brainly :)
Which interval contains all the x-values where f(x)=log0.75x is positive?
x>0.75
0 1
0
Given the function f(x) = log 0.75x
The interval that contains all the x-values must be greater than 1.333
For the function to be positive, the expression 0.75x must be greater than and equal to 1 as shown:
0.75x ≥ 1Divide both sides by 0.75
0.75x/0.75 ≥ 1/0.75
x ≥ 1/0.75
x ≥ 1.333
Hence the interval that contains all the x-values must be greater than 1.333
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Cost of a radio: $43.95
Markup: 80%
Discount: 55%
Tax: 1%
Some of the values that can be obtained from the given parameters are as
follows;
Profit is $35.16Selling price is $79.11Discount amount is $96.69Marked price is $175.8Amount paid is $79.9011Reasons:
The cost is the amount by which the radio is obtained.
\(Markup = \dfrac{Profit}{Cost}\)
\(Discount \ percentage = \dfrac{Discount }{Marked \ price} \times 100\)
Discount = Listed price - Selling price
Tax amount = Total price × Tax rate
Therefore, we have;
Profit = Cost × Markup = 43.95 × 80% = 35.16
Selling price = Cost + Profit
Therefore;
Selling price = 43.95 + 35.16 = 79.11
Selling price = $79.11\(Marked \ Price = \dfrac{Selling \ price}{1 - \dfrac{Percentage \ discount}{100} }\)
\(Marked \ Price = \dfrac{79.11}{1 - \dfrac{55}{100} } = 175.8\)
Marked price = $175.8The discount = 175.8 - 79.11 = 96.69
Discount amount = $96.69Total amount paid = Selling price + Tax
Therefore;
Total amount paid = 79.11 + 0.01 × 79.11 = 79.9011
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hi! I hope you're doing good. Can you please help!
Answer:
I have made it in above picture
Lincoln has 16 pins in one box and 17 pins in another box. He is hanging posters with the pins. Lincoln uses 4 pins to hang each posted. What is the total number of posters Abe can hang with the pins?
Answer: 8 posters
Step-by-step explanation:
From the question, we are informed that Lincoln has 16 pins in one box and 17 pins in another box and that he uses 4 pins to hang each posters posted. The total number of posters he can hang with the pins goes thus:
We should first calculate the total number of pins he has.
= 16 + 17 = 33 pins
Since he uses 4 pins to hang a poster, we then divide 33 pins by 4.
= 33 ÷ 4
= 8.25
This means that he can hang 8 posters with the pin
What is an advantage of using a stem-and-leaf plot instead of a histogram? What is a disadvantage? O A. Stem-and-leaf plots show data clusters where histograms do not O B. Stem-and-leaf plots contain original data values where histograms do not. O C. Stem-and-leaf plots.easily organize data of all sizes where histograms do not O D. Stem-and-leaf plots graph qualitative data where histograms do not.
Stem-and-leaf plots contain original data values where histograms do not. Therefore, option B is the correct answer.
What is stem and leaf?The "stem" values are listed down, and the "leaf" values go right (or left) from the stem values.
The "stem" is used to group the scores and each "leaf" shows the individual scores within each group.
The advantage of a stem leaf diagram is it gives a concise representation of data. The advantage of a frequency histogram is, that it is visually strong. Histograms are usually preferable to stem and leaf diagrams in large data sets. The disadvantage of a stem leaf diagram is not visual.
Therefore, option B is the correct answer.
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a_1 = 8 and a_n = 3a_n-1 then find the value of a_4
In the series of a value of a(4)=216
What do the terms sequence and series mean?
Mathematical sequence and series formulas pertain to several kinds of sequences and series. A series is the accumulation of the elements in a sequence, which is a group of arranged elements that follow a pattern. The formulas for the nth term and the sum are typically included in the sequence and series formulas.
Given that:
a(1) = 8
a(n)= 3a(n-1)
so a(4) = 3a(3) = 72*3 = 216
a(3)= 3a(2) = 24*3 = 72
a(2)= 3a(1) = 3*8 = 24
Hence a(4) = 216
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help
? i will give brainliest if ur right!
Answer:
r ≤ 13
Step-by-step explanation:
Okay, if admission is $4, then we have to take away 4 from 25 at the beginning, this leaves us with $21. Then, we divide 21 by 1.5 to get the amount of rides he can go on with all of his money. This is 14, but, he can't spend all his money, this means the maximum rides he can go on is 13. For the inequality, I think it is r ≤ 13. I hope this helps!
Next Londell needs a total of $400 to buy a new bicycle. He has $40 saved. He earns $15 each week delivering newspapers. How many weeks will Londell have to deliver papers to have enough money to buy the bicycle?
Londell needs to deliver newspapers for 24 weeks to have enough money to buy the bicycle.
Londell currently has $40 saved, and he needs a total of $400 to buy the bicycle. Each week, he earns $15 delivering newspapers.
To calculate the number of weeks Londell needs to work, we can set up an equation:
$40 (current savings) + $15 (weekly earnings) × (number of weeks) = $400 (total cost of the bicycle)
Simplifying the equation:
$40 + $15 = $400
Subtracting $40 from both sides of the equation:
$15 = $400 - $40
$15 = $360
Dividing both sides of the equation by $15:
= $360 / $15
≈ 24
Therefore, Londell will have to deliver newspapers for approximately 24 weeks to have enough money to buy the bicycle.
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Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer. A used Car salesperson can be paid using two methods of commission. METHOD X uses straight commission 3.5% of the selling price of all vehicles sold. METHOD Y uses a fixed amount of £250 per week plus commission of 1.5% of the selling price of all vehicles sold. If the total selling price of the Cars sold in each week is on average £20,000, calculate which of the two methods of commission the salesperson would prefer.
The cost of one computer is £600 and the cost of one printer is £800.
Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, and the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer.
Let the cost of a computer be x and the cost of a printer be y.
Then, the two simultaneous equations are:5x + 4y = 6600 ---------------------- (1)
4x + 5y = 6000 ---------------------- (2)
Solving equations (1) and (2) simultaneously:x = 600y = 800
Therefore, the cost of a computer is £600 and the cost of a printer is £800..
:Therefore, the cost of one computer is £600 and the cost of one printer is £800.
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true or false? aₙ₊₁ = 2aₙ₋₁ is a one-step recurrence relation.
The statement "aₙ₊₁ = 2aₙ₋₁ is a one-step recurrence relation." is true.
The recurrence relation "aₙ₊₁ = 2aₙ₋₁" states that the next term, aₙ₊₁, is equal to two times the previous term, aₙ₋₁. This means that to find aₙ₊₁, we only need to look at a single previous term, aₙ₋₁. Hence, the given recurrence relation is indeed a one-step recurrence relation.
To illustrate this further, let's consider an example. Suppose we have a sequence where the first term, a₁, is given as 1. Using the recurrence relation "aₙ₊₁ = 2aₙ₋₁," we can calculate the subsequent terms of the sequence as follows:
a₂ = 2a₁ = 2(1) = 2
a₃ = 2a₂ = 2(2) = 4
a₄ = 2a₃ = 2(4) = 8
a₅ = 2a₄ = 2(8) = 16
and so on.
As we can observe, each term in the sequence is determined by doubling the previous term, requiring only one step of calculation. Therefore, the given recurrence relation "aₙ₊₁ = 2aₙ₋₁" is a one-step recurrence relation.
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Please help!!! Angles!
Answer:
m∠JKM = 63°
m∠MKL = 27°
Step-by-step explanation:
Since ∠JKL is a right angle. This means that by summing up both m∠JKM and m∠MKL will result in the same as ∠JKL figure. Thus, m∠JKM + m∠MKL = m∠JKL which is 90° by a right angle definition.
\(\displaystyle{\left(12x+3\right)+\left(6x-3\right) = 90}\)
Solve the equation for x:
\(\displaystyle{12x+3+6x-3 = 90}\\\\\displaystyle{18x=90}\\\\\displaystyle{x=5}\)
We know that x = 5. Next, we are going to substitute x = 5 in m∠JKM and m∠MKL. Thus,
m∠JKM = 12(5) + 3 = 60 - 3 = 63°
m∠MKL = 6(5) - 3 = 30 - 3 = 27°
a random sample of 46 salespersons was asked how long on average they were able to talk to a potential customer. their answers revealed a mean of 8.90 with a variance of 6 minutes. construct a 95% confidence interval for the time it takes a salesperson to talk to a potential customer.
With 95% of confidence interval for the time it takes salesperson to talk to a potential customer is (12.42 , 5.38).
A Random sample is a randomly selected subset of a population. In this sampling method, each member of the population has an exactly equal chance of being selected, minimizing the risk of selection bias.
In probability theory and statistics, variance is the expectation of the squared deviation of a random variable from its population mean or sample mean. Variance is a measure of dispersion, meaning it is a measure of how far a set of numbers is spread out from their average value. Variance is an important tool in the sciences, where statistical analysis of data is common. The variance is the square of the standard deviation, the second central moment of a distribution, and the covariance of the random variable with itself, and it is often represented by σ ² ,s² ,Var(X) , or V(X).
A confidence interval (CI) is a range of estimates for an unknown parameter. A confidence interval is computed at a designated confidence level; the 95% confidence level is most common, but other levels, such as 90% or 99%, are sometimes used. The confidence level represents the long-run proportion of corresponding CIs that contain the true value of the parameter. For example, out of all intervals computed at the 95% level, 95% of them should contain the parameter's true value.
Given in the question:
n = 46
x = 8.90
σ = 6
α = 0.95
As we know that:
\(X\) ±\(Z_{\alpha /2} * \frac{\beta }{\sqrt{n} }\)
putting the values we get,
8.90 ± Z (0.95/2) ×6/√46
Now, considering the positive sign, we get,
= 8.90 + 3.52
= 12.42
Now considering the negative sign,
8.90 ± Z (0.95/2) ×6/√46
= 8.90 - 3.52
= 5.38
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88.8 % as a decimal and 0.2 as a percentage
88.8%=0.888
0.2=20%
Your welcome
Explain how you can write a quadratic function in a factored form that would have a vertex with an x-coordinate of 3 and two distant roots
Answer:
Step-by-step explanation:
(x-3)²-4=0
(x-3)²=4=2²
x-3=±2
x=3±2
x=3-2,3+2
x=1,5
it has two distinct roots and a vertex at x=3
YOU HAVE A SWELLING INJURY. DO YOU USE….
Heat or ice?
Answer:
Ice would be the correct answer.
Answer:
if u want go to the doctor but use ice but if its to cold use a little heat not too much tho
Step-by-step explanation:
If you have injured your neck and are experiencing swelling, you should ice the area for at least 72 hours. After icing, you can use heat to help any lingering pain. Tight neck muscles and old injuries can benefit from heat only, as long as there isn’t any swelling.
Solve these for points I got a one in algebra so this would be helpful to my grade
The solution for each system of equations is given as follows:
1) x = -4, y = -8.
2) x = 5, y = -1.
3) x = -7, y = 2.
4) No solution.
5) x = 2, y = -6.
6) x = -3, y = 4.
How to solve the system of equations?The system of equations are solved using the elimination method, writing one variable as a function of another, replacing in the other equation, and then obtaining each variable.
For item 1, we eliminate x, as follows:
x = 12 + 2y.
Hence the solution for y is obtained as follows:
5(12 + 2y) + 3y = -44
60 + 10y + 3y = -44
13y = -104
y = -104/13
y = -8.
Then the solution for x is given as follows:
x = 12 + 2y = 12 + 2(-8) = -4.
For item 2, we have that:
y = 19 - 4x.
Hence:
7x - 2(19 - 4x) = 37
7x - 38 + 8x = 37
15x = 75
x = 5.
Hence the solution for y is of:
y = 19 - 4(5) = -1.
For item 3, we can simplify the second equation by two, hence:
-x + y = 9.
y = 9 + x.
Hence:
3x + 8(9 + x) = -5
3x + 72 + 8x = -5
11x = -77
x = -7.
Hence the solution for y is of:
y = 9 - 7 = 2.
For item 4, we have that:
x = 7 + 3y.
Hence:
2(7 + 3y) - 6y = 12
14 + 6y - 6y = 12
0y = -2. (no solution, division by zero).
For item 5, we have that:
y = -2 - 2x.
Hence:
5x + 3(-2 - 2x) = -8
5x - 6 - 6x = -8
-x = -2
x = 2.
Hence the solution for y is of:
y = -2 - 2(2)
y = -6.
For item 6, we simplify the second equation by two, hence:
2x + y = -2
y = -2 - 2x.
Replacing on the first equation, we have that:
2x + 5(-2 - 2x) = 14.
2x - 10 - 10x = 14
-8x = 24
8x = -24
x = -3.
Hence the solution for y is obtained as follows:
y = -2 - 2(-3)
y = -2 + 6
y = 4.
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A group of students in college of engineering studied the following subjects: 25% studied mathematics subject 20% studied electronics subject 55% studied Communications subject 10% studied both electronics and communications subjects 1- Draw Venn diagram 2- If a student is randomly selected what is the probability that he studied Communications or electronics or both subjects? 3- If a student is randomly selected what is the probability that he studied mathematics and Communications subjects?
Venn diagram:
The percentage of students that studied mathematics = 25%
The percentage of students that studied electronics = 20%
The percentage of students that studied Communications = 55%
The percentage of students that studied both electronics and Communications subjects = 10%
P(studied Communications or electronics or both subjects)
= P(studied Communications) + P(studied electronics) - P(studied both electronics and Communications subjects)
= 55% + 20% - 10%
= 65%
Therefore, the probability that a student studied Communications or electronics or both subjects is 65%.
P(studied mathematics and Communications subjects)
= P(studied mathematics) × P(studied Communications)
= 25% × 55%
= 13.75%
Therefore, the probability that a student studied mathematics and Communications subjects is 13.75%.
Drawing a Venn diagram, we have 25% studying Mathematics (M), 20% studying Electronics (E), and 55% studying Communications (C).10% studied both Electronics and Communications.
Therefore, the percentages become as follows: M = 25% - 10% = 15% E = 20% - 10% = 10% C = 55%.
Part 2 - To obtain the probability that a student studied Communications or Electronics or both subjects
P(Communication or Electronics) = P(Communication) + P(Electronics) - P(Communication and Electronics) = 55% + 20% - 10% = 65%.
The probability that a student studied Communications or Electronics or both subjects is 65%.
Part 3 -To obtain the probability that a student studied Mathematics and Communications subjects,
P(Mathematics and Communications) = P(Mathematics) * P(Communications) = 25% * 55% = 13.75%.
The probability that a student studied Mathematics and Communications subjects is 13.75%.
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If f(x) = 2x^2 - 3 and g(x) = x + 1, find g(f(x)).
Group of answer choices
2x^2 - 2
2(x+1)^2 - 3
2x^2 + 2
2x^3 + 2x^2 - 3x - 3
Answer:
g(
x
2
−
3
)
=
2
x
2
−
7
Step-by-step explanation:
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What is an equation of the line that passes through the point (6,1)(6,1) and is parallel to the line x+3y=15x+3y=15?
The equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15 is 3y+x=9.
What is an equation of a line?The general equation of a straight line is given by the expression
y = mx + c, where m is the gradient and y = c is the point at which the line intersects the y-axis.
Given,
The line is parallel to the line x + 3y = 15 and passes through the point (6,1).
The procedures listed below can be used to find the equation of the line that runs parallel to the line x + 3y = 15 and passes through the point (6,1).
Step 1 - Keep in mind that two parallel lines have equal slopes.
Step 2: As a result, the line's slope across point (6,1) is -1/3.
Step 3: Accordingly, the equation of a line passing through the point (6,1) and being parallel to the line (x + 3y = 15) may be found using the one-point slope form of a line.
The one-point slope form is shown below in Step 4:
y-y₁=m(x-x₁)
Step 5: In the equation above, substitute the values of the known terms.
y-1=-(1/3)(x-6)
3y - 3 = -x + 6
3y +x = 9
Therefore, the equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15 is 3y+x=9.
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Help please. picture below, not hard to others I'm just lazy.
I need help with this
Answer:
X will equal 30 degrees
Step-by-step explanation:
X will equal 30 degrees due to the rule of corresponding angles and that l1 and l2 are parallel with a transversal intersecting the parallel lines.
The angle of X and the angle of 30 degrees are corresponding angles.
Corresponding angles are equal to each other.
So X will also be 30 degrees.
I hope this answer helped and have a great day!
Let A(x)=∫x0f(t)dt, with f(x) as in figure.a7c62fed-2c14-3a08-b9ef-3e28dcbdf5da___3A(x) has a local minimum on (0,6) at x=A(x) has a local maximum on (0,6) at x=
We can use the first derivative test to determine the local minimum and maximum of A(x) on the interval (0,6).
Taking the derivative of A(x) with respect to x, we get:
A'(x) = f(x)
Note that A(x) is the integral of f(x), so A'(x) is just f(x) by the fundamental theorem of calculus.
To find the critical points of A(x) on (0,6), we set A'(x) = 0 and solve for x:
f(x) = 0
From the given figure, we can see that f(x) is positive on the interval (0,2) and negative on the interval (2,6). Therefore, there must be a local maximum of A(x) at some point in (2,6) where f(x) = 0.
To find the local minimum of A(x) on (0,6), we need to look for a point where A'(x) changes sign from positive to negative. From the given figure, we can see that f(x) is increasing on the interval (0,1) and decreasing on the interval (1,6). Therefore, A'(x) = f(x) is also increasing on (0,1) and decreasing on (1,6). This means that A(x) has a local minimum at the point x where A'(x) = f(x) changes sign from positive to negative. From the figure, we can see that this occurs at x = 2.
Therefore, the local minimum of A(x) on (0,6) is at x = 2, and the local maximum of A(x) on (0,6) is at some point in (2,6) where f(x) = 0.
Help please i’m terrible at maths !!
which of the intervals contains the root of the f(x) = 2x − x3 + 0.5?
The interval that contains the root of f(x) = 2x − x3 + 0.5 is [-2, -1].
To find which interval contains the root of the equation f(x) = 2x − x3 + 0.5, we can use the intermediate value theorem. This theorem states that if a function is continuous on a closed interval [a, b], and takes on values f(a) and f(b) at the endpoints, then for any value y between f(a) and f(b), there exists a value c in [a, b] such that f(c) = y.
In this case, we can evaluate f(x) at the endpoints of the intervals [-2, -1], [-1, 0], [0, 1], and [1, 2], as follows
For [-2, -1]: f(-2) = -11.5 and f(-1) = 1.5
For [-1, 0]: f(-1) = 1.5 and f(0) = 0.5
For [0, 1]: f(0) = 0.5 and f(1) = 1.5
For [1, 2]: f(1) = 1.5 and f(2) = -11.5
From this, we can see that the function changes sign from negative to positive in the interval [-2, -1], which means there must be a root in this interval. We can also see that the function is positive throughout the interval [1, 2], so there cannot be a root in this interval. The intervals [-1, 0] and [0, 1] do not change sign, so we cannot conclude whether or not there is a root in these intervals.
Therefore, the interval that contains the root of f(x) = 2x − x3 + 0.5 is [-2, -1].
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Find the slope of each line. Write your answer in simplest form. Also need the steps!
Answer: For number 6 its -3/1 or -3. For number 7 its 4/2 =2
Step-by-step explanation: Hope this helps :).
One card is drawn at random from a deck of cards. What is the probability that the card will be a red ace?
Answer:
Since a normal deck of cards holds 52 cards, and there are two red aces, ace of diamonds and ace of hearts. So 2/52 probability that you will draw a red ace, to simplify it is a 3.84% chance of drawing a red ace.
what is the maximum of the sinusoidal function? enter your answer in the box.
Answer:
Step-by-step explanation:
B
A piecewise function f (x) is defined by Part A: Graph the piecewise function f (x) and determine the range. (5 points)Part B: Determine the asymptotes of f (x). Show all necessary calculations. (5 points)Part C: Describe the end behavior of f (x). (5 points)
Answer
• a) Range: (-∞, –1)
• b) Horizontal asymptote when x ≤ 2: y = –3. Vertical asymptote when x > 2: x= 2. Horizontal asymptote when x > 2: y = –1.
,• c) When x decreases, it approaches –3, and when x increases, it approaches –1.
Explanation
• Part A: Graph the piecewise function f (x) and determine the range.
Using a graphing tool we can get the following graph:
As the range is all the y-values included in the function, we can see that in this case, the range is:
\((-\infty,-1)\)• Part B: Determine the asymptotes of f (x). Show all necessary calculations.
We have to get the asymptotes from the part where x ≤ 2 and x > 2.
In x ≤ 2 we do not have a vertical asymptote as it is not a rational function, but we do have a horizontal asymptote, which is y = k when we have the function:
\(y=a(b)^{x-h}+k\)Thus, in our case y = –3.
In x > 2, we do have a vertical and horizontal asymptote. We can get the vertical asymptote by setting the denominator of the function to 0:
\(x^2-5x+6=0\)If we solve the expression by factoring we get two solutions:
\((x-2)(x-3)=0\)\(\begin{gathered} x_1-2=0 \\ x_1=2 \end{gathered}\)\(\begin{gathered} x_2-3=0 \\ x_2=3 \end{gathered}\)Based on our function we can see that the vertical asymptote is x = 2 when x > 2. Then, the horizontal asymptote can be calculated with the limit:
\(\lim_{x\to\infty}(\frac{-x^2+2x+3}{x^2-5x+6})=-1\)Thus, our horizontal asymptote is y = –1 when x > 2.
• Part C: Describe the end behavior of f (x).
The end behavior of a function is how the function acts when x increases or decreases. Based on our graph we can see that when x decreases, it approaches –3, and when x increases, it approaches –1.