I USED ALL MY POINTS! PLEASE HELP ME ASAP!!!
Mrs. Jackson wants to tile a wall to serve as a splash guard above a basin in the basement. She plans to use equal-sized tiles to cover an area that measures 48 inches by 36 inches. She does not want to cut any of the tiles. What is the least number of tiles she could use?

Answer:

bro/sis through this solution u can solve ur values

Step-by-step explanation:

To calculate the variance, you first subtract the mean from each number and then square the results to find the squared differences. You then find the average of those squared differences. The result is the variance. The standard deviation is a measure of how spread out the numbers in a distribution are.

I hope this will help you

Answer:

The area is always placed in square so the correct answer is square yards.

Answer:

The angle is usually the same and they I believe it would be 24.18 if it's not then sorry for wasting your time.

Answer:

x = 107

Step-by-step explanation:

44+29+107=180

a triangle equals 180 with all the degrees added together :)

polygon -- a closed figure made up of line segments

regular polygon -- a polygon whose sides are all the same length & whose angles are all the same measure

octagon -- a polygon with eight side

pentagon -- a polygon with five sides

quadrilateral -- a polygon with four sides

The probability that a randomly selected consumer is female, given that the person prefers Brand A 0.68

Preference of Brand A =30% ⇒ P(A) = 0.3

Preference of Brand B =70% ⇒ P(B)= 0.7

Prefer Brand A and are Female = 20% ⇒ P(A/F) = 0.2

Prefer Brand B and are Female = 40% ⇒ P(B/F) = 0.4

To find : Selected consumer is female, given that the person prefers Brand A  P(F/A)

Using Bayes' theorem, which state that

P(A/B) = P(B/A)P(A)/P(B)

where, P(A) and P(B) are probabilities of observing A and B.

P(B/A)= is a conditional probability where event B occur and A is true

P(A/B)= also a conditional probability where event A occur and B is true.

Now, applying Bayes' theorem,

P(F/A) = P(A/F)P(A)/P(B)P(B/F) + P(A)P(A/F)

Substituting all the above values,

P(F/A) = 0.68

Therefore, the probability that a randomly selected consumer is female, given that the person prefers Brand A 0.68

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Answer: x=45

Step-by-step explanation:

To solve for x, we first need to understand the figure. We know TV and RS are parallel lines. If we extend TV to the left, we get a straight line parallel to RS. By Alternate Interior Angles, We know ∠R is equivalent to ∠T on the very left. Therefore, we can set it equal to 180° and solve.

x+2x+x=180          [combine like terms]

4x=180                  [divide both sides by 4]

x=45

Now, we know x=45.

Step-by-step explanation:

Given - The distance between point (2, 2) and point (8, 2) is 6 units on

             a coordinate plane.

To find - Which other pairs of points are also 6 units apart?

Proof -

The distance between two points (x₁, y₁), (x₂, y₂) are 6 if and only if either

( x₂ - x₁ = 6 and y₂ = y₁ )or ( x₂ = x₁ and y₂ - y₁ = 6 ).

If either of the conditions is satisfied , then only we can say that the two points has ha distance of 6 units between them.

Now, As given

Let (x₁, y₁) = ( 2, 2) , (x₂, y₂) = (8, 2)

Check whether the conditions are satisfied or not .

Here x₁ = 2 , x₂ = 8, y₁ = 2, y₂ = 2

Now,

x₂ - x₁ = 8 - 2 = 6 , y₂ - y₁ = 2 - 2 = 0

∴ we get

1st condition is satisfied, So the points have a distance of 6 units between them.

Now,

Let us suppose another point (x₁, y₁) = ( 4, 3) , (x₂, y₂) = (3, 3)

Here x₁ = 4 , x₂ = 3, y₁ = 3, y₂ = 3

Now,

x₂ - x₁ = 4 - 3 = 1 , y₂ - y₁ = 3 - 3 = 0

Here neither of the conditions are satisfied.

So the points are not at a distance of 6 units from each other.

Let A(t) denote the amount of salt (in ounces, oz) in the tank at time t (in minutes, min).

Salt flows in at a rate of

\(\dfrac{dA}{dt}_{\rm in} = \left(17 (1 + 15 \sin(t)) \dfrac{\rm oz}{\rm gal}\right) \left(8\dfrac{\rm gal}{\rm min}\right) = 136 (1 + 15 \sin(t)) \dfrac{\rm oz}{\min}\)

and flows out at a rate of

\(\dfrac{dA}{dt}_{\rm out} = \left(\dfrac{A(t) \, \mathrm{oz}}{180 \,\mathrm{gal} + \left(8\frac{\rm gal}{\rm min} - 8\frac{\rm gal}{\rm min}\right) (t \, \mathrm{min})}\right) \left(8 \dfrac{\rm gal}{\rm min}\right) = \dfrac{A(t)}{180} \dfrac{\rm oz}{\rm min}\)

so that the net rate of change in the amount of salt in the tank is given by the linear differential equation

\(\dfrac{dA}{dt} = \dfrac{dA}{dt}_{\rm in} - \dfrac{dA}{dt}_{\rm out} \iff \dfrac{dA}{dt} + \dfrac{A(t)}{180} = 136 (1 + 15 \sin(t))\)

Multiply both sides by the integrating factor, \(e^{t/180}\), and rewrite the left side as the derivative of a product.

\(e^{t/180} \dfrac{dA}{dt} + e^{t/180} \dfrac{A(t)}{180} = 136 e^{t/180} (1 + 15 \sin(t))\)

\(\dfrac d{dt}\left[e^{t/180} A(t)\right] = 136 e^{t/180} (1 + 15 \sin(t))\)

Integrate both sides with respect to t (integrate the right side by parts):

\(\displaystyle \int \frac d{dt}\left[e^{t/180} A(t)\right] \, dt = 136 \int e^{t/180} (1 + 15 \sin(t)) \, dt\)

\(\displaystyle e^{t/180} A(t) = \left(24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t)\right) e^{t/180} + C\)

Solve for A(t) :

\(\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) + C e^{-t/180}\)

The tank starts with A(0) = 15 oz of salt; use this to solve for the constant C.

\(\displaystyle 15 = 24,480 - \frac{66,096,000}{32,401} + C \implies C = -\dfrac{726,594,465}{32,401}\)

So,

\(\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) - \frac{726,594,465}{32,401} e^{-t/180}\)

Recall the angle-sum identity for cosine:

\(R \cos(x-\theta) = R \cos(\theta) \cos(x) + R \sin(\theta) \sin(x)\)

so that we can condense the trigonometric terms in A(t). Solve for R and θ :

\(R \cos(\theta) = -\dfrac{66,096,000}{32,401}\)

\(R \sin(\theta) = \dfrac{367,200}{32,401}\)

Recall the Pythagorean identity and definition of tangent,

\(\cos^2(x) + \sin^2(x) = 1\)

\(\tan(x) = \dfrac{\sin(x)}{\cos(x)}\)

Then

\(R^2 \cos^2(\theta) + R^2 \sin^2(\theta) = R^2 = \dfrac{134,835,840,000}{32,401} \implies R = \dfrac{367,200}{\sqrt{32,401}}\)

and

\(\dfrac{R \sin(\theta)}{R \cos(\theta)} = \tan(\theta) = -\dfrac{367,200}{66,096,000} = -\dfrac1{180} \\\\ \implies \theta = -\tan^{-1}\left(\dfrac1{180}\right) = -\cot^{-1}(180)\)

so we can rewrite A(t) as

\(\displaystyle A(t) = 24,480 + \frac{367,200}{\sqrt{32,401}} \cos\left(t + \cot^{-1}(180)\right) - \frac{726,594,465}{32,401} e^{-t/180}\)

As t goes to infinity, the exponential term will converge to zero. Meanwhile the cosine term will oscillate between -1 and 1, so that A(t) will oscillate about the constant level of 24,480 oz between the extreme values of

\(24,480 - \dfrac{267,200}{\sqrt{32,401}} \approx 22,995.6 \,\mathrm{oz}\)

and

\(24,480 + \dfrac{267,200}{\sqrt{32,401}} \approx 25,964.4 \,\mathrm{oz}\)

which is to say, with amplitude

\(2 \times \dfrac{267,200}{\sqrt{32,401}} \approx \mathbf{2,968.84 \,oz}\)

The constant term is 8, which means that the y-intercept of the graph of g is (0, 8).

In mathematics, a function is a rule that assigns a unique output value for every input value in a set. It is a relation between a set of inputs and a set of possible outputs, with the property that each input is related to exactly one output. Functions are widely used in various fields of mathematics, science, engineering, and technology to model and analyze real-world situations, to describe how quantities depend on one another, and to solve problems.

Here,

If we set k=4, the function g(x) becomes:

g(x) = k(x+2) = 4(x+2)

The value of k affects the slope of the graph of g compared to the graph of f. In this case, since k=4, the slope of the graph of g is 4 times the slope of the graph of f.

The slope of the graph of f is 1, since the coefficient of x is 1. Therefore, the slope of the graph of g is:

4 * 1 = 4

This means that the graph of g is steeper than the graph of f.

The y-intercept of the graph of f is 2, since the constant term is 2. Setting k=4 does not affect the y-intercept of the graph of g, since the constant term remains the same:

g(x) = 4(x+2) = 4x + 8

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Answer:

5.364

Step-by-step explanation:

5.3635 is the given number, and because the number next to the thousandths is a five, the number in the thousandths place can be rounded to 4.

The effective interest method is used to amortize the bond premium. The carrying value of the bond increases by the effective interest each period, and the premium is amortized over the life of the bond. The journal entry for bond issuance is as follows: Dr. Cash 205,000, Dr. Premium on Bonds Payable 5,000, Cr. Bonds Payable 210,000

The effective interest method is a method of amortizing bond premium or discount that takes into account the time value of money. The effective interest is the interest that would be earned if the bond were purchased at its market value and held to maturity. The carrying value of the bond increases by the effective interest each period, and the premium is amortized over the life of the bond.

The journal entry for bond issuance records the proceeds from the sale of the bonds, the premium on bonds payable, and the bonds payable. The proceeds from the sale of the bonds are equal to the face value of the bonds plus the premium.

The premium on bonds payable is a liability that represents the excess of the issue price of the bonds over their face value. The bonds payable account is a long-term liability that represents the amount that the company owes to the bondholders.

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Answer:

192,000 grams

Step-by-step explanation:

turn 1,344 kilograms to grams, which gives u 1344000 grams

divide 1344000 by 7 and you get 192,000 grams. Hope this helped :)

Crane Co. journalized the transactions by recording debits and credits to the appropriate accounts, such as Notes Receivable, Cash, Sales Revenue, and Accounts Receivable. Interest revenue on the notes receivable was accrued at the end of the year.

Here are the journal entries for the transactions of Crane Co. related to notes receivable:

Nov. 1:

Cash 52,800

Notes Receivable 52,800

Dec. 11:

Notes Receivable 3,600

Sales Revenue 3,600

Dec. 16:

Notes Receivable 7,200

Accounts Receivable 7,200

Dec. 31:

Interest Receivable [Calculate interest for each note]

Interest Revenue [Calculate interest for each note]

Note: Since the problem does not provide specific dates for the last transaction (Dec. 31) and interest accrual, it's not possible to provide the exact amounts for the Interest Receivable and Interest Revenue accounts.

You'll need to calculate the interest for each note based on the given information (principal, interest rate, and time) and record the appropriate amounts in the journal entries.

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The distributive property can be applied to which expression \(\rm 12x^{3}-9x^{2} +4x-3\)  the given factors are \(\rm = (3x^{2}+1)(4x-3)\)

To factorise a cubic equation we will be finding one factor we will solve by factor theorem to check that the guess is the root. Then we will divide the cubic equation by factor to obtain a quadratic equation. on getting  the quadratic equation we will be applying the various standard methods to factorise further the quadratic equation.

On factorizing we get,

                      \(=\rm 12x^{3}-9x^{2} +4x-3\\\\=\rm 3x^{2} (4x - 3) + 1(4x- 3)\\\\= (3x^{2}+1)(4x-3)\)

Therefore, The distributive property can be applied to which expression \(\rm 12x^{3}-9x^{2} +4x-3\)  the given factors are \(\rm = (3x^{2}+1)(4x-3)\)

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To classify the given random variables as discrete or continuous, whether they have a finite or countable number of possible outcomes (discrete) or an infinite number of possible outcomes within a range (continuous).

a. The time it takes to fly from City A to City B: This random variable is continuous. It can take any positive value within a range, including fractions of seconds, seconds, minutes, hours, etc. b. The number of hits to a website in a day: This random variable is discrete. The number of hits is typically a whole number (0, 1, 2, 3, etc.) and cannot be a fraction or continuous value. c. The number of statistics students now reading a book: This random variable is discrete. The number of students reading the book can only take whole number values (0, 1, 2, 3, etc.) and cannot be a fraction or continuous value.

d. The time required to download a file from the Internet: This random variable is continuous. The time can take any positive value within a range, including fractions of seconds, seconds, minutes, etc. e. The exact time it takes to evaluate 27 + 72: This random variable is discrete. The time required to evaluate this arithmetic expression is typically instantaneous and can be considered as a fixed value rather than a range of possible outcomes. Therefore, it is not a continuous random variable.

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True , Network analysts should be concerned with these specific properties and patterns that arise in real-world networks since they have important implications for the network's behavior and performance.

Random graphs are mathematical structures that do not have any inherent structure or patterns. They are created by connecting nodes randomly without any specific rules or constraints. Real-world networks, on the other hand, have a certain structure and properties that arise from the way nodes are connected based on specific rules and constraints.

Network analysts use various mathematical models and algorithms to analyze and understand real-world networks. These networks can range from social networks, transportation networks, communication networks, and many others. The goal of network analysis is to uncover the underlying structure and properties of these networks, which can then be used to make predictions, identify vulnerabilities, and optimize their design. Random graphs are often used as a baseline or reference point for network analysis since they represent the simplest form of a network. However, they are not an accurate representation of real-world networks, which are often characterized by specific patterns and properties. For example, many real-world networks exhibit a small-world property, meaning that most nodes are not directly connected to each other but can be reached through a small number of intermediate nodes. This property is not present in random graphs.

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Answer

\(168in^{2}\)

Step-by-step explanation:

SA=2(wl+hl+hw)

2·(6·2+9·2+9·6)

=168

The probability of line from F to B = 25% and the probability of the second line from A to F = 75%

The probability of an event occurring is the fraction of the number of required outcome divided by the total number of possible outcomes.

The total possible outcome = 20

event of the first line = 5

event of the second line = 15

probability of line from F to B = 5/20

(5 × 100)/20 = 25%

probability of the second line from A to F = 15/20

(15 × 100)/20 = 75%

Therefore, the probability of line from F to B is 25 percent (25%) while the probability of the second line from A to F is 75 percent (75%)

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The probability of line from F to B = 25% and the probability of the second line from A to F = 75%

What is probability

The probability of an event occurring is the fraction of the number of required outcome divided by the total number of possible outcomes.

The total possible outcome = 20

event of the first line = 5

event of the second line = 15

probability of line from F to B = 5/20

(5 × 100)/20 = 25%

probability of the second line from A to F = 15/20

(15 × 100)/20 = 75%

Therefore, the probability of line from F to B is 25 percent (25%) while the probability of the second line from A to F is 75 percent (75%)

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Answer:

y = -3x + 17

Step-by-step explanation:

first, change the equation into slope-intercept form

add 'x' to each side to get:

3y + x = 12

divide each side by 3 to get:

y = 1/3x + 4

now we need to use a slope that is the opposite reciprocal of 1/3 which would be -3, in conjunction with the point (5,2), by entering these values into the slope-intercept form so we can find the y-intercept ('b') of the new line:

2 = -3(5) + b

2 = -15 + b

17 = b

put slope and y-intercept together to get:

y = -3x + 17

Answer: True

Use the vertical line test to determine whether or not a graph represents a function. If a vertical line is moved across the graph and, at any time, touches the graph at only one point, then the graph is a function. If the vertical line touches the graph at more than one point, then the graph is not a function.

Answer:

True

Step-by-step explanation:

Using the vertical line test since it only passes through the graph once it is a function

Answer:d

Step-by-step explanation:

(a) The proposition can be expressed as ∀x(Cliff(x) → ∃y(Adjacent(x, y) ∧ NonNull(y, r3))).

(b) The proposition can be expressed as ∀x(NonNull(x, r2) → (∃y(Adjacent(x, y) ∧ Hill(y)) ∧ ¬∃z(Adjacent(x, z) ∧ Hill(z) ∧ ¬(z = y)))).

(c) The proposition can be expressed as ∀x(Resource(x, r1) → (Corner(x) ∧ ¬∃y(Resource(y, r1) ∧ ¬(x = y) ∧ Adjacent(x, y)))).

(a) In propositional logic, we use quantifiers (∀ for "for every" and ∃ for "there exists") to express the properties. The proposition (a) states that for every location that is a cliff (Cliff(x)), there exists an adjacent location (Adjacent(x, y)) to it that contains some non-null quantity of resource r3 (NonNull(y, r3)).

(b) The proposition (b) states that for every location that contains some non-null quantity of resource r2 (NonNull(x, r2)), there is exactly one adjacent location (y) that is a hill (Hill(y)), and there are no other adjacent locations (z) that are hills (¬(z = y)).

(c) The proposition (c) states that resource r1 (Resource(x, r1)) can only appear in the corners of the grid (Corner(x)), and there are no other adjacent locations (y) that contain resource r1 (Resource(y, r1)).

By using logical connectives (∧ for "and," ∨ for "or," ¬ for "not"), quantifiers (∀ for "for every," ∃ for "there exists"), and predicate symbols (Cliff, NonNull, Resource, Hill, Corner), we can express these properties in propositional logic to represent the given statements accurately.

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The constant of proportionality for x gallons water and y miles is k = 25

The ratio connecting two given numbers in what is known as a proportional relationship is the constant of proportionality.

Constant ratio, constant rate, unit rate, constant of variation, and even rate of change are other names for the constant of proportionality.

A proportionate connection is simple to represent as a straight line on a coordinate plane. It is a straight line because it is directly proportional; the slope serves as the constant of proportionality.

The proportionate change along the x and y axes never varies, hence the slope or increase is constant.

According to the question,

x(gallons)     y(miles)

 1                       25

 2                      50

 3                      75

 4                      100

As we know, If y is proportional to x

=> y ∝ x

=> y = kx , where k is constant of proportionality

Using the table,

when x = 1 => y = 25

=> 25 = k(1)

=> k = 25

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Statistical process control technique that permits only 3.4 defects per million opportunities is Six Sigma.

Six Sigma is a statistical technique that emphasizes the necessity of a standardized approach to enhancing and optimizing the efficiency of the production and management processes by reducing the variation and waste within them. It concentrates on controlling a process to ensure that the results of a process are consistent and reliable by using statistical methods. The objective of the Six Sigma process is to produce 3.4 errors or defects per million opportunities. If the process is better than Six Sigma, it is considered more consistent and predictable.
Six Sigma's statistical approach to process control encompasses a range of tools and methods. Six Sigma's primary objective is to increase revenue and profits by developing and delivering high-quality products and services while eliminating defects and reducing waste.
Six Sigma aims to improve quality by detecting and reducing the reasons for variations in production processes. It accomplishes this by developing quality management practices that enable it to assess quality, establish goals, and implement best practices to achieve those goals.
In conclusion, Six Sigma is a process control approach that emphasizes statistical methods for process control and improvement. Six Sigma is used to reduce variability and eliminate waste, and its goal is to achieve 3.4 defects per million opportunities.

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Answer:

the answer is 10w + 11

Answer:

no idea

Step-by-step explanation:

Jk the answers square