Identify the proportional relationships: y = kx or y =
k
x
x y
1 5
3 15
5 25
7 35

A
Directly proportional


B
Inversely proportional


C
Neither


D

The addition property and division properties are used to solve the expression.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

The expression is,

⇒ 3x - 4 = 1

Now, We can solve as;

⇒ 3x - 4 = 1

Add 4 both side,

⇒ 3x - 4 + 4 = 1 + 4

⇒ 3x = 5

Divide by 3;

⇒ x = 5/3

Thus, The addition property and division properties are used to solve the expression.

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a) d/dt [√(289 - 8²)] = d/dt [√(255)] = d/dt [√(5²*17)] = 5/2√17 m/s.

b) The required value is the rate of change of x when the top of the ladder is 8 feet from the ground, then y = 15 feet.

a) Determine how fast the bottom of the ladder is sliding away when the top of the ladder is 8 feet from the ground. As the ladder leans against the side of the house, it makes a right angle with the ground. Using Pythagorean Theorem, the length of the ladder is given by.

Ladder length = √(hypotenuse)² - (height)²= √(17² - height²) meters. Taking the derivative of both sides of this equation, we get: dL/dt = [d/dt √(289 - h²)] meters/sec. Let h = 8 feet, dL/dt = -5 feet/sec.

Thus, the rate of change of the bottom of the ladder is d/dt [√(289 - h²)] meters/sec when the top of the ladder is 8 feet from the ground, and the bottom of the ladder is sliding away at a rate of 5 feet/sec.

b) At what rate is the angle o between the ladder and the ground changing then. Let y be the height of the ladder and the angle it makes with the ground be x. From the given values, y = 17 cos x.

Taking the derivative of both sides with respect to time: dy/dt = -17 sin x (dx/dt)In the given problem, dx/dt = -5/17sin x. Then, dy/dt = 5 sin x cos x= (5/2) sin 2x.

Solving this value of sin x by Pythagorean Theorem, sin x = 8/17. Substituting the value in the equation for the derivative, we get: dy/dt = (5/2) * sin 2x= (5/2) * sin 2(arc sin(8/17))= (5/2) * (2*8/17 * 15/17)= (600/289) ft/sec.

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Contributing $2,000 to an RRSP does not change the Tax Free Savings Account (TFSA) contribution. Option (c)

TSA (Tax-Free Savings Account) is a saving plan that allows you to accumulate money throughout your lifetime without incurring taxes on any interest or investment income earned within the account. The question asks us about the effect of contributing $2,000 to an RRSP on the Tax-Free Savings Account (TFSA) contribution. There is no direct effect on the TFSA contribution. If a person contributes $2,000 to an RRSP, the person will get tax relief based on his/her tax rate. However, the contribution to the RRSP may indirectly affect the contribution room available for the Tax-Free Savings Account (TFSA). It is because the contribution limit for the TFSA is based on the income of the person in the previous year, and the contribution to RRSP is subtracted from the total income. Therefore, the less income you have, the less TFSA contribution room you will have for the year.

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Answer:

It is multiplication

Step-by-step explanation:

It is multiplication because when you divide 9,460,730,472,580.8 by 299,792,458 you will get 31557.6 so that means,

9,460,730,472,580.8/299,792,458 = 31557.6

so, 299,792,458 * 31557.6 = 9,460,730,472,580.8

So the answer is Multiplication by 31557.6

Let me know if it was Helpfull.

Answer: "add by>" ; "65>" ; "go" im pretty sure

Step-by-step explanation:

my brain

The Laplace transform can be used to solve the given initial-value problem, where y'' − 4y' + 4y = t, with initial conditions y(0) = 0 and y'(0) = 1.

To solve the initial-value problem using the Laplace transform, we first apply the transform to both sides of the differential equation. Taking the Laplace transform of the given equation yields:

s^2Y(s) - sy(0) - y'(0) - 4(sY(s) - y(0)) + 4Y(s) = 1/s^2,

where Y(s) represents the Laplace transform of y(t) and s represents the Laplace variable. Substituting the initial conditions y(0) = 0 and y'(0) = 1 into the equation, we have:

s^2Y(s) - 1 - 4sY(s) + 4Y(s) = 1/s^2.

Simplifying the equation, we can solve for Y(s):

Y(s) = 1/(s^2 - 4s + 4) + 1/(s^3).

Using partial fraction decomposition and inverse Laplace transform techniques, we can obtain the solution y(t) in the time domain.

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(a) Example question: "How often do you look at social media while doing schoolwork?

(b) Sofie can select a simple random sample of students by using a random number generator to assign a unique identification number to each student in the online high school.

(c) The sample for Sofie's research is the 32 completed surveys she received. These surveys represent the responses of a subset of the population. The population, in this case, refers to all the students at the online high school.

(d) If Sofie uses only the completed surveys, she can conclude that approximately 50% (16 out of 32) of the students who completed the survey reported using social media while doing schoolwork.

(a) Please select one of the following options: never, rarely, occasionally, frequently, or always."

(b) She can then use the random number generator again to select a specific number of students from the entire population of students, ensuring that each student has an equal chance of being selected. For example, if there are 500 students in total and Sofie wants a sample size of 50, she can generate 50 random numbers and select the corresponding students based on their identification numbers.

(d) However, it is important to note that this conclusion is specific to the sample of completed surveys and cannot be generalized to the entire population of high school students.

To make an inference about the percent of all high school students who use social media while doing schoolwork, Sofie would need a larger and more representative sample that covers a wider range of students in the online high school.

Additionally, she should consider potential biases in the sample, such as non-response bias if the students who chose not to complete the survey have different social media usage patterns compared to those who did respond.

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Answer:

It’s 6

Step-by-step explanation:

The correct identification is that Graph B shows residuals with a distribution that more closely approximates a Normal distribution than Graph A.

Graph B shows residuals with a distribution that more closely approximates a Normal distribution than Graph A.

In the given description, Graph B is described as having blue dots that are a much closer fit to the red line throughout the graph, except for slight deviations at the top-right of the graph. This indicates that the points in Graph B align more closely with the theoretical line, suggesting a closer approximation to a Normal distribution.

On the other hand, Graph A is described as having blue dots that start around the coordinate negative three, negative two, and approach the line around the coordinate negative one, negative one. Additionally, the description mentions that the blue dots waver a little above and below the line as the x-value increases. This implies that the points in Graph A do not align as closely with the theoretical line as in Graph B, indicating a lesser approximation to a Normal distribution.

The correct identification is that Graph B shows residuals with a distribution that more closely approximates a Normal distribution than Graph A.

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Calculation as discuss below.

The largest power of the variable in a quadratic equation, which is a second-degree mathematical expression, is 2.

Given Equations: (x₁²−1)x₂ = x₃² − 1, (x₂² − 1)x₃ = x₄² − 1, ... (xₙ² − 1)x₁ = x₂² − 1

We can start by multiplying the first equation by xₙ²-1, the second equation by x₁²-1, and so on up to the n-1-th equation. This gives us:

(x₁² - 1)(x₂² - 1)x₃ = (xₙ² - 1)(x₂² - 1)x₁

(x₂² - 1)(x₃² - 1)x₄ = (x₁² - 1)(x₃² - 1)x₂...

(xₙ² - 1)(x₁² - 1)x₂ = (xₙ₋₁² - 1)(x₂² - 1)xₙ

We can simplify each equation by expanding the products:

x₁²x₂²x₃ - x₁²x₃ - x₂²x₃ + x₃ = xₙ²x₁x₂ - x₁x₂ - xₙ²x₂ + xₙ²x₁

x₂²x₃²x₄ - x₂²x₄ - x₃²x₄ + x₄ = x₁²x₂x₃ - x₁²x₃ - x₁x₃² + x₁x₄...

xₙ²x₁²x₂ - x₁²x₂ - xₙ²x₁ + x₂ = xₙ₋₁²x₂xₙ - xₙ₋₁²xₙ - x₂²xₙ + x₂x₁

We can then add all n equations together to get:

x₁²x₂²x₃ + x₂²x₃²x₄ + ... + xₙ²x₁²x₂ = x₁²x₂x₃ - x₁x₂ - x₁²x₃ + x₃ + x₂²x₃ - x₂x₃ - x₂²x₄ + x₄ + ... + xₙ²x₁²x₂ - x₁x₂ - xₙ²x₁ + x₂x₁

We can simplify this equation by grouping the terms with x₁, x₂, ..., xₙ, respectively:

(x₁²x₂² - 1)x₃ + (x₂²x₃² - 1)x₄ + ... + (xₙ²x₁² - 1)x₂ = (x₁² - 1)x₂ + (x₂² - 1)x₃ + ... + (xₙ² - 1)x₁

We can then use the fact that x₁² - 1 = (x₁ - 1)(x₁ + 1), x₂² - 1 = (x₂ - 1)(x₂ + 1), ..., xₙ² - 1 = (xₙ - 1)(xₙ + 1), and substitute these expressions into the equation above. This gives us:

(x₁ - 1)(x₁ + 1)x₂² + (x₂ - 1)(x₂ + 1)x₃² + ... + (xₙ - 1)(xₙ + 1)x₁² = (x₁ - 1)(x₂ + 1) + (x₂ - 1)(x₃ + 1) + ... + (xₙ - 1)(x₁ + 1)

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The solutions to the system are: (x₁, x₂, x₃, ..., xₙ) = (1, 0, √2, 1, 0, √2, ..., 1, 0, √2) or (-1, 0, -√2, -1, 0, -√2, ..., -1, 0, -√2).

The largest power of the variable in a quadratic equation, which is a second-degree mathematical expression, is 2.

Given Equations: (x₁²−1)x₂ = x₃² − 1, (x₂² − 1)x₃ = x₄² − 1, ... (xₙ² − 1)x₁ = x₂² − 1

We can see that the system is cyclic, in the sense that each equation depends only on the variables that appear in the next equation in the cycle. Therefore, we can solve the system by finding a solution for the first equation and then using it to obtain a solution for the second equation, and so on.

Let's start with the first equation. We can rearrange it to get:

x₃² = (x₁² - 1)x₂ + 1

Substituting this expression for x₃² into the second equation, we get:

(x₂² - 1)(x₁² - 1)x₂ + x₂² - 1 = x₄² - 1

Simplifying this equation, we get:

(x₁²x₂² - x₁² - x₂² + 1)x₂ = x₄² - x₂²

Again, we can use the expression for x₃² to simplify this equation further:

(x₁²x₂² - x₁² - x₂² + 1)x₂ = (x₁² - 1)x₃²

Substituting this expression for x₃² into the first equation in the cycle, we get:

(x₁² - 1)x₂ = (x₁²x₂² - x₁² - x₂² + 1)x₂/(x₁² - 1) + 1

Simplifying this equation, we get:

x₂² = (x₁²x₂² - x₂²)/(x₁² - 1)

Multiplying both sides by (x₁² - 1), we get:

x₁²x₂² - x₂² = -x₁² + x₁²x₂² - x₂²

Simplifying this equation, we get:

x₁² = 1

Therefore, x₁ = ±1. If we substitute this value into the first equation, we get:

x₂ = 0

Substituting these values into the second equation, we get:

-1 = x₄² - 1

Therefore, x₄ = ±√2.

Using these values, we can obtain the rest of the solutions by cyclically permuting the variables. Therefore, the solutions to the system are:

(x₁, x₂, x₃, ..., xₙ) = (1, 0, √2, 1, 0, √2, ..., 1, 0, √2) or (-1, 0, -√2, -1, 0, -√2, ..., -1, 0, -√2).

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The probability of both John and Jill winning is 0.000134 or approximately 0.0001

The probability of John winning is 4/300, or 0.01333. The probability of Jill winning is 3/299, since there are only 299 employees left and one winner has already been chosen. The probability of both John and Jill winning is the product of these probabilities:

0.01333 x 3/299 = 0.000134

So the probability of both John and Jill winning is 0.000134 or approximately 0.0001 (rounded to six decimal places).

To calculate this probability, we first find the probability of John winning, which is the number of ways he can be chosen (1) out of the total number of employees (300). This is 1/300. Then, we find the probability of Jill winning, which is the number of ways she can be chosen (1) out of the remaining employees (299) after John has already been chosen. This is 1/299. Finally, we multiply these two probabilities to find the probability of both John and Jill winning.

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Answer:

Yes, it does.

Step-by-step explanation:

When you plug the point into the inequality: 6(5)+14(7)>14, you receive 128>14.

To calculate the price of a common stock that pays regular dividends, we could begin with the general formula for the valuation of a dividend-paying stock.

The formula is known as the Dividend Discount Model (DDM) or the Gordon Growth Model. It calculates the present value of all future dividends and the stock's expected growth rate. The general formula is:

Price of Stock = Dividend / (Required Rate of Return - Dividend Growth Rate)

In this formula:

- Dividend refers to the expected dividend payment for a specific period.

- Required Rate of Return is the minimum rate of return an investor expects to receive from the stock. It represents the opportunity cost of investing in that stock.

- Dividend Growth Rate is the estimated rate at which the company's dividends are expected to grow over time.

By plugging in the appropriate values for the dividend, required rate of return, and dividend growth rate, you can calculate the price of a common stock using this formula. It's important to note that this formula assumes a constant growth rate in dividends, which might not be applicable for all stocks.

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Answer:

y = - 3x + 5

Step-by-step explanation:

Given

6x + 2y = 10 ( subtract 6x from both sides )

2y = - 6x + 10 ( divide all terms by 2 )

y = - 3x + 5

The correct equation for y in terms of x would be, y = - 3x + 5

Hence, option 2 is true.

Used the concept of an equation that states that,

An equation is a group of numerical variables and functions that have been combined using operations like addition, subtraction, multiplication, and division.

Given that the expression is,

6x + 2y = 10

Now, simplify the equation for y in terms of x as,

6x + 2y = 10

Subtract both sides by 6x,

2y = - 6x + 10

Divide both sides by 2,

y = - 3x + 5

So, The correct equation would be, y = - 3x + 5

Thus, option 2 is true.

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(-4)^{2/7} in radical form is 7√16

A radical expression is an expression containing a square root. Radicand - A number or expression inside the radical symbol.

In fractional Indices, when the power or exponent of a number is in fraction, the denominator is the root while the numerator is the power.

For example, 2^{2/3} is an example of expression with fractional exponents. Here 2 is the power and 3 is the root.

2² = 4

2^{2/3} = 3√4

Similarly the expression (-4)^{2/7}

(-4)² = 16

(-4)^{2/7} = 7√16

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The tires and the traction control system work in tandem to ensure maximum traction and stability, minimizing the risk of traction loss and improving overall vehicle control and safety.

The two most important parts of a vehicle in preventing traction loss are the tires and the traction control system.

Tires: Tires are the primary point of contact between the vehicle and the road surface. The quality and condition of the tires greatly influence traction. Tires with good tread depth and appropriate tread pattern are essential for maintaining grip on the road. Tread depth helps to channel water, snow, or debris away from the tire, preventing hydroplaning or loss of traction. Additionally, tire pressure should be properly maintained to ensure even contact with the road. Choosing tires suitable for the specific driving conditions, such as all-season, winter, or performance tires, is crucial for optimal traction and handling.

Traction Control System: The traction control system is a vehicle safety feature that helps prevent the wheels from slipping or spinning on low-traction surfaces. It uses various sensors to monitor the speed and rotation of the wheels. If the system detects a loss of traction, it will automatically reduce engine power and apply braking force to the wheels that are slipping. By modulating power delivery and braking, the traction control system helps maintain traction and prevent wheel spin, especially in challenging conditions like slippery roads or during quick acceleration.

The tires and the traction control system work in tandem to ensure maximum traction and stability, minimizing the risk of traction loss and improving overall vehicle control and safety.

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Answer:

Volume = 280 yd³

Step-by-step explanation:

Volume = 1/2bhl

Volume = 1/2(7)(8)(10) = 280 yd³

The problem involves the binomial probability distribution, which is used to calculate probabilities related to the number of successes in a fixed number of independent Bernoulli trials. In this case, the retailer is inspecting a shipment of electronic devices with a known defective rate of 3%. The problem asks for the probabilities of finding certain numbers of defective items in a random sample of 20 items.

i) To find the probability of at least one defective item, we can calculate the complement of the probability of finding no defective items, which is equal to (1 - probability of finding no defect).

ii) To find the probability of exactly two defective items, we use the formula for the binomial probability distribution to calculate the probability of two successes (defective items) in 20 trials.

iii) To find the probability of more than three defective items, we calculate the cumulative probability of finding three or fewer defects and subtract it from 1.

iv) To find the probability of at most two defective items, we calculate the cumulative probability of finding two or fewer defects.

v) To find the probability of no defective items, we calculate the probability of 20 successful trials (no defects).

In each case, the binomial probability formula is used, which considers the number of trials, the probability of success (defect), and the desired number of successes. The calculations yield the probabilities for the specific scenarios requested in the problem.

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Answer:

Step-by-step explanation:

1. When two chords intersect each other inside a circle, the products of their segments are equal. ... One chord is cut into two line segments A and B. The other into the segments C and D. This theorem states that A×B is always equal to C×D no matter where the chords are.

2. If two chords intersect inside a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle . In the figure, m∠1=12(m⌢QR+m⌢PS) .

3. The intersecting chords theorem or just the chord theorem is a statement in elementary geometry that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal.

Answer:

I got 8/3...............

The measures of the angles in the triangle AABC are mZSAU = 1°, m2SBV = 32°, and SV = 0.

1. Find mZSAU:

Using the Triangle Angle Bisector Theorem, we know that the angle bisector divides the opposite side into two segments of equal length, so we can use the following equation to find mZSAU:

mZSAU = mZTCU/2 = 22/2 = 1°

2. Find m2SBV:

Since both angles SAU and SBV are on the same side of the angle bisector AV, they must be equal in measure. Therefore, m2SBV = m2SAV = 32°

3. Find SV:

Since the angle bisectors AV, BV, and CV all meet at the same point V, we know that the lengths of the segments AV, BV, and CV must all be equal. Since TV = 18, CV = 27, and mZSAU = 1°, the length of the angle bisector AV must also be 18. Therefore, SV = 0.

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Answer:

205,891,132,094,649

Step-by-step explanation:

9^5 = 59049

(59040)^3 = 205,891,132,094,649

Answer:

9^15

Step-by-step explanation:

(9^5)^3 is a specific example of the rule of exponents (a^b)^c = a^(bc).

Following this rule, we get:  (9^5)^3 = 9^15

Answer:

Step-by-step explanation:

When the problem is asking which lines have a slope of -2, this is referring to the steepness or rate of change. To determine which lines have a slope of -2, the line must have a rise of -2 and a run of 1. This means that the line will go down 2 units every 1 unit to the right.

Also, if a line is parallel (lines which never cross), it will have the same slope.

You can also eliminate lines c, and d because they increase while lines a, and b decrease. A and B have the same slope because they are parallel and decrease which means that this must be the answer.

To compare the 3-month and 12-month moving average forecasts using the mean absolute deviation (MAD) criterion, we need to calculate the MAD for each model and then compare them. The MAD is a measure of the average magnitude of the forecast errors, and a lower MAD indicates a better forecast.

To calculate the MAD for the 3-month moving average model, we need to first calculate the forecasted values for each month by taking the average of the unemployment rates for the previous 3 months. For example, the forecasted value for April 2018 would be the average of the unemployment rates for January, February, and March 2018. We then calculate the absolute deviation between the forecasted value and the actual value for each month, and take the average of those deviations to get the MAD for the 3-month moving average model.

We can repeat this process for the 12-month moving average model, but instead of taking the average of the previous 3 months, we take the average of the previous 12 months.

Once we have calculated the MAD for both models, we can compare them to determine which model yields better results. Generally, a lower MAD indicates a better forecast. However, it is important to note that the MAD criterion only considers the magnitude of the forecast errors and does not take into account the direction of the errors (i.e., overestimation versus underestimation).

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Full Question ;

The accompanying dataset provides data on monthly unemployment rates for a certain region over four years. Compare 3- and 12-month moving average forecasts using the MAD criterion. Which of the two models yields better results? Explain. Click the icon to view the unemployment rate data. Find the MAD for the 3-month moving average forecast. MAD = (Type an integer or decimal rounded to three decimal places as needed.) A1 fx Year D E F G H I 1 2 3 1 с Rate(%) 7.8 8.3 8.5 8.9 9.4 9.6 9.4 9.5 9.7 9.9 9.8 10.1 9.9 9.7 9.8 9.91 9.7 9.4 9.6 9.4 9.3 9.5 9.9 9.5 9.2 9.1 8.9 A B Year Month 2013 Jan 2013 Feb 2013 Mar 2013 Apr 2013 May 2013 Jun 2013 Jul 2013 Aug 2013 Sep 2013 Oct 2013 Nov 2013 Dec 2014 Jan 2014 Feb 2014 Mar 2014 Apr 2014 May 2014 Jun 2014 Jul 2014 Aug 2014 Sep 2014 Oct 2014 Nov 2014 Dec 2015 Jan 2015 Feb 2015 Mar 2015 Apr 2015 May 2015 Jun 2015 Jul 2015 Aug 2015 Sep 2015 Oct 5 7 3 ) 1 2 3 1 5 7 9.1 ) 9. 1 2 3 1 5 7 ) 9.1 8.9 8.9 8.9 8.9 8.7 8.4 8.3 8.3 8.4 8.1 8.1 8.4 8.2 8.3 7.7 7.9 7.9 7.8 1 2 2015 Dec 2016 Jan 2016 Feb 2016 Mar 2016 Apr 2016 May 2016 Jun 2016 Jul 2016 Aug 2016 Sep 2016 Oct 2016 Nov 2016 Dec 3 1 5 3 2 2

Answer:

The x-intercept is the point where the graph crosses the x-axis; it can be found by setting y = 0 and solving for x.

The y-intercept is the point where the graph crosses the y-axis; it can be found by setting x = 0 and solving for y.

1) g(x) = (x + 5)⁴

2) f(x) = 7 - x⁴

3) h(x) = ¼(x - 3)⁴

The graphs are labeled below.

Answer: N

Step-by-step explanation:

Answer:

The answer is D, $50.09

Answer:

-x+3=-2.

we switch the places to change the signs and put x as positive.

so it will be written as 3+2=x.

then we simply solve it and :

5=x

Answer:

x=5

Step-by-step explanation:

1) -x=-3 -2

2) -x=-5

5) x=5 (the minus goes away as it is in both sides)

Answer:

Slope is: 1/2

Y-intercept is: 4

Equation is: y=1/2x+4

*Use Desmos Graphing Calculator to graph and get the answers for #3*

You can use do 37+32.5 and subtract that from 570

Hoped this Helped