Identify which statement accurately describes the role of a debt collector.

a.) A debt collector has the same role and rights as the original creditor.
b.) A debt collector is hired by the original creditor to collect a debt.
c.) A debt collector works for the Consumer Protection Bureau.
d.) A debt collector can shame and harass people to force them to repay debts.

I think the answer is B or C, I'm not sure.

Answers

Answer 1

Answer:

B

Step-by-step explanation:

I think its B dont quote me


Related Questions

What factors affect band gap?

Answers

The factors that affect band gap are material, temperature, pressure and strain.

Band gap refers to the energy difference between the highest occupied energy level and the lowest unoccupied energy level in a material. This energy difference plays a crucial role in determining the electrical and optical properties of a material. The band gap is a critical factor in the design of electronic devices and solar cells.

There are several factors that can affect the band gap of a material. The most important factor is the composition of the material. The band gap is dependent on the electronic structure of the atoms in the material. Another factor that can affect the band gap is the crystal structure of the material. The band gap is influenced by the arrangement of atoms in the crystal lattice.

Temperature is also a significant factor that affects the band gap of a material. As the temperature increases, the energy of the electrons in the material increases, causing the band gap to decrease.

Additionally, external factors such as pressure and strain can also affect the band gap of a material. When a material is subjected to high pressure or strain, its crystal structure can change, altering its electronic properties and causing a change in the band gap.

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Which of the following expressions has a simplified value of 3a - 2?



Group of answer choices

-8 + 3a + 10 - a

-10 - 5a + 12 + 8a

-a + 4 + 5a - a - 6

-6a + 9a + 4 - 2

Answers

Given:

Simplified value is 3a-2.

To find:

The expression which has a simplified value of 3a - 2.

Solution:

In option A,

\(-8+3a+10-a=(-8+10)+(3a-a)\)

\(-8+3a+10-a=2+2a\neq 3a-2\)

In option B,

\(-10-5a+12+8a=(-10+12)+(-5a+8a)\)

\(-10-5a+12+8a=2+3a\neq 3a-2\)

In option C,

\(-a+4+5a-a-6=(-a+5a-a)+(4-6)\)

\(-a+4+5a-a-6=3a-2\)

In option D,

\(-6a+9a+4-2=3a+2\neq 3a-2\)

Therefore, the correct option is C.

What is the slope of the line that
passes through these two points?
(-2, 4)
(3, 4)
Remember, given two points,
(Xi yu)
Slope
(x2.72
rise (y2-yı)
run (x2-x1)
Simplify your answer completely.

What is the slope of the line thatpasses through these two points?(-2, 4)(3, 4)Remember, given two points,(Xi

Answers

Answer:

when u said (Xi yu) be more spefic

Step-by-step explanation:

when u said (Xi yu) be more spefic

Can anyone write a proof for this problem? Thanks

Can anyone write a proof for this problem? Thanks

Answers

The two column proof procedure below has shown that  ΔABE ≅ ΔACD by SAS Congruency Postulate

How to prove congruent triangles?

To prove that ΔABE ≅ ΔACD, we will use a two column proof procedure for congruency.

Statement 1; AD ≅ AE

Reason 1; Given

Statement 2; ∠ABC ≅ ∠ACB

Reason 2; Given

Statement 3; AC ≅ AB

Reason 3; Definition of Isosceles Triangles

Statement 4; ΔABE ≅ ΔACD

Reason 4; SAS Congruency Postulate

Both triangles share the included angle A.

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Which system of linear equations has the ordered pair (15, – 25) as its solution?
x - 2y = 35 and 2x + y = 55
x-2y = -35 and 2x - y = 55
2x+y=5 and 2x + y = 55
2x+y=5 and 2x – y=55

Answers

Answer:

The solution to the system of equations be:

(x, y) = (15, -25)

Therefore, the fourth system of equations i.e. 2x+y=5 and 2x – y=55 has the ordered pair (15, – 25) as its solution.

Step-by-step explanation:

Let us solve and check the 4th system of equations

2x+y=5

2x – y=55

solving the system of equations

\(\begin{bmatrix}2x+y=5\\ 2x-y=55\end{bmatrix}\)

subtracting

\(2x-y=55\)

\(-\)

\(\underline{2x+y=5}\)

\(-2y=50\)

so the system of equations becomes

\(\begin{bmatrix}2x+y=5\\ -2y=50\end{bmatrix}\)

solve -2y = 50

\(-2y=50\)

Divide both sides by -2

\(\frac{-2y}{-2}=\frac{50}{-2}\)

\(y=-25\)

\(\mathrm{For\:}2x+y=5\mathrm{\:plug\:in\:}y=-25\)

\(2x-25=5\)

Add 25 to both sides

\(2x-25+25=5+25\)

Simplify

\(2x=30\)

Divide both sides by 2

\(\frac{2x}{2}=\frac{30}{2}\)

simplify

\(x=15\)

Thus, the solution to the system of equations be:

(x, y) = (15, -25)

Therefore, the fourth system of equations i.e. 2x+y=5 and 2x – y=55 has the ordered pair (15, – 25) as its solution.

I need help with geometry

I need help with geometry

Answers

Isn’t that (-1,-1)
Point V shows -1,-1
The bottom left corner of a graph is always negative. So if there’s a point, both points will be negative

The elongation α
of a planet is the angle formed by the planet, earth, and sun. it is known that the distance from the sun to venus is 0.723au
(see exercise 65 in section 6.2 ). at a certain time the elongation of venus is found to be 39.4∘.
find the possible distances from the earth to venus at that time in astronomical units (au).

Answers

The distance from the earth to venus is an illustration of the sine ratio

The distance from the earth to venus at that time is 1.12 au

How to determine the possibe distance?

See attachment for the diagram that illustrates the complete question.

Start by calculating the angle V using the following sine ratio

SE/sin(V) = VS/sin(E)

This gives

1/sin(V) = 0.723/sin(39.4)

Take the inverse of both sides

sin(V)/1 = sin(39.4)/0.723

Evaluate the quotient

sin(V) = 0.8779

Take the arcsin of both sides

V = 61.4

Calculate the measure of angle S

<S + <V + <E = 180

This gives

<S  = - <V - <E + 180

Substitute known values

<S  = -61.4 - 39.4 + 180

<S  = 79.2

The distance (VE) is then calculated using the following sine ratio

VE/sin(S) = VS/sin(E)

This gives

VE/sin(79.2) = 0.723/sin(39.4)

Multiply bot sides by sin(79.2)

VE = sin(79.2) * 0.723/sin(39.4)

Evaluate the product

VE = 1.12

Hence, the distance from the earth to venus at that time is 1.12 au

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The elongation of a planet is the angle formed by the planet, earth, and sun. it is known that the distance

kozol observes the strain on fremont's students at lunchtime, when all of the 3,300 students in attendance are served in one 30-minute meal period. one teacher calculates that the extended walk to the cafeteria and long food lines create a 10-minute window for students to eat. what often results is that many students go all day without a meal (176).

Answers

Kozol notices the stress on the 3,300 kids at Fremont during lunch, when the entire meal is provided in a single 30-minute period. One teacher estimates that the lengthy distance to the cafeteria and the lengthy queues for food provide children a 10-minute window during which to eat. As a result, many students frequently skip meals entirely (176).

Given,

Lunch was served to the pupils in this school in a single sitting, unlike the staggered luncheon sessions I saw at Walton High. 3,300 children cannot be fed at once due to physical limitations, the teacher explained. "The session lasts barely 30 minutes, and there is a very large line for children to obtain their food. They must wait in line for fifteen minutes before they can even walk there from their classes. They most likely have 10 minutes to eat their food. Many of them don't even try.

You've worked as a teacher, so you know what it's like for students to go a whole day without eating. Here at Fremont, the school day lasts eight hours.

Here,

Kozol notices the stress on the 3,300 kids at fremont during lunch, when the entire meal is provided in a single 30-minute period. One teacher estimates that the lengthy distance to the cafeteria and the lengthy queues for food provide children a 10-minute window during which to eat. As a result, many students frequently skip meals entirely .

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Given question is incomplete. Completed question is here;-

Unlike the staggered luncheon sessions I observed at Walton High, lunch was served in a single sitting to the students in this school. "It's physically impossible to feed 3,300 kids at once," the teacher said. "The line for kids to get their food is very long and the entire period lasts only 30 minutes. It takes them 15 minutes just to walk there from their classes and get through the line. They get 10 minutes probably to eat their meals. A lot of them don't try. You've been a teacher, so you can imagine what it does to students when they have no food to eat for an entire day. The schoolday here at Fremont is eight hours long."

From Kozol, Jonathan. The Shame of the Nation: The Restoration of Apartheid Schooling in America. New York: Crown, 2005. Print. The passage appears on page 176.

can somewone help me to calculate ca the perimter of a round that is 3,16m diameter?

Answers

Step-by-step explanation:

Perimeter is

r × 2 × pi

r is the radius

pi is about 3.1415

you have a diameter at 3.16

radius is half the diameter

so

3.16÷2 = 1.58

put it into equation

1.58 × 2 × 3.1415

= Answer

3. The Alvarez family bought a car for $2,000. They made a down
payment of $500. If they want to pay the balance in 5 equal
payments, how much will each of these payments be?

Answers

The first step is to subtract $500 from $2000 and then you end up with $1500 which you then divide by 5.

Each payment will have to be $300

in a new version of the wason four-card task, participants are given the rule, "if you read the textbook, then you will get an a on the exam." each card has a yes or no on one side, indicating whether or not the student has read the textbook, and an exam grade on the other side. compared with the original version of the task with just numbers and letters, participants should make

Answers

According to the information we can infer that participants are likely to make more accurate decisions about which cards to flip over in the new version, likely because the new content makes the problem more concrete and relatable to everyday life (option B).

What is the difference between old and new version of the wason four-card task?

In the new version of the Wason four-card task, the content involves a familiar scenario of reading a textbook and receiving an exam grade. This scenario is more relatable to everyday life compared to the original version with abstract numbers and letters.

When a problem is relatable and has real-life context, participants tend to have a better understanding of the situation and are more likely to make accurate decisions. The content of the new version provides participants with a clearer mental model, allowing them to relate the "if-then" conditional statement to their own experiences.

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Which statement below is true about TB incidence in 2019? The Texas TB incident rate is above the national target The Texas TB incident rate is below the national average The Texas TB incident rate is roughly equal to the 2025 national target TB incidence was not collected for the year 2019

Answers

According to TB incidence data from 2019, the true statement about TB incidence in that year is that "The Texas TB incident rate is above the national target."

TB incidence in 2019 refers to the statistical measure of the occurrence of tuberculosis disease within a specific region or population during that year. It provides valuable insights into the number of individuals infected by TB bacteria and the reported cases of the disease within the same timeframe. In this context, the available data indicates that the TB incident rate in Texas surpasses the national target. This suggests that the incidence of tuberculosis cases in Texas exceeded the desired level set as a goal at the national level.

It's important to note that without further details, such as the specific national target or the actual incidence rates, we cannot provide precise figures or make comparisons to other options. However, based on the given statement, we can conclude that the TB incident rate in Texas in 2019 was higher than the intended national target.

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Find the perimeter of the shape below:

A four sided figure EFGH is shown. E is located at negative 1, 6. F is located at 2, 4. G is located at negative 1, 3. H is located at -3, 3
options:
1)
12.4 units
2)
13.4 units
3)
15.1 units
4)
16.8 units

Answers

Answer:

12.4

Step-by-step explanation:

i took the test!!

Answer:12.4

i took the test........

Find the perimeter of the shape below:A four sided figure EFGH is shown. E is located at negative 1,

Solve and graph 11x+6<9x+10

Answers

We solved the given inequality and found the values of x lie in the interval   ( -∞ , 4). This is graphed and shown on the number line as below.

What is meant by inequality?

A relationship that compares two numbers or other mathematical expressions in an unequal way is known as an inequality. It is most frequently used to compare the sizes of two numbers on the number line.

Given inequality is:

11x + 6 < 9x + 10

Solving,

11x - 9x < 10 - 6

2x < 4

x < 4

The values of x is in the interval : ( -∞ , 4)

The above inequality is shown below on the number line as well as on the graph.

We can see that all the values to the left of 4 but not including 4 can be taken as the value of x.

Therefore we solved the given inequality which is graphed and shown on the number line.

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Solve and graph 11x+6&lt;9x+10
Solve and graph 11x+6&lt;9x+10

Can someone tell me what side b is? Thank youuu

Can someone tell me what side b is? Thank youuu

Answers

Answer:

Hey there!

We can use sine B= b/c.

Plugging in the values, we have sine 69= b/60

b=56.01

Hope this helps :)

Answer:

The answer is

56.01m

Step-by-step explanation:

To find side b we use sine

sin ∅ = opposite / hypotenuse

From the question

side c is the hypotenuse and

side b is the opposite

side c = 60m

B is 69°

So we have

sin 69 = b/c

sin 69 = b / 60

b = 60 sin 69

b = 56.0148

b = 56. 01m to 2 decimal places

Hope this helps you

Find the midpoint M of the line segment joining the points A = (-2, 8) and B = (-8, -4).

Answers

Answer:

M (- 5, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \(\frac{x_{1}+x_{2} }{2}\) , \(\frac{y_{1}+y_{2} }{2}\) )

Here (x₁, y₁ ) = A (- 2, 8 ) and (x₂, y₂ ) = B (- 8, - 4 ) , then

midpoint = ( \(\frac{-2-8}{2}\) , \(\frac{8-4}{2}\) ) = ( \(\frac{-10}{2}\) , \(\frac{4}{2}\) ) = (- 5, 2 )

An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiveness of the new method was evaluated in a simulation study. In 50 simulations, the mean improvement in traffic flow in a particular intersection was 653.5 vehicles per hour, with a standard deviation of 311.7 vehicles per hour.1. Find a 95% confidence interval for the improvement in traffic flow due to the new system. Round the answers to three decimal places.2. Find a 98% confidence interval for the improvement in traffic flow due to the new system. Round the answers to three decimal places.3. Approximately what sample size is needed so that a 95% confidence interval will specify the mean to within ±55 vehicles per hour? Round the answer to the next integer.4. Approximately what sample size is needed so that a 98% confidence interval will specify the mean to within ±55 vehicles per hour? Round the answer to the next integer.

Answers

1. The 95% confidence interval is between 567.07 and 739.93 vehicles per hour
2. The 98% confidence interval is between 547.47 and 759.53 vehicles per hour
3. The sample size needed for a 95% confidence interval to specify the mean to within ±55 vehicles per hour is 121
4. The sample size needed for a 98% confidence interval to specify the mean to within ±55 vehicles per hour is 187

1. To find the 95% confidence interval, we use the formula:

Mean improvement +/- (t-value * standard error)

where t-value for 49 degrees of freedom at 95% confidence level is 2.009.

The standard error can be found by dividing the standard deviation by the square root of the sample size:

Standard error = 311.7 / sqrt(50) = 44.06

So the 95% confidence interval is:

653.5 +/- (2.009 * 44.06) = (567.07, 739.93)

Therefore, we can say with 95% confidence that the true mean improvement in traffic flow is between 567.07 and 739.93 vehicles per hour.

2. To find the 98% confidence interval, we use the same formula but with a different t-value. For 49 degrees of freedom at 98% confidence level, the t-value is 2.678.

The 98% confidence interval is:

653.5 +/- (2.678 * 44.06) = (547.47, 759.53)

Therefore, we can say with 98% confidence that the true mean improvement in traffic flow is between 547.47 and 759.53 vehicles per hour.

3. To find the sample size needed for a 95% confidence interval to specify the mean to within ±55 vehicles per hour, we use the formula:

n = \((z * s / E)^2\)

where z is the z-value for 95% confidence level (1.96), s is the standard deviation (311.7), and E is the margin of error (55).

Plugging in the values, we get:

n = \((1.96 * 311.7 / 55)^2\) = 120.25

Rounding up, we need a sample size of 121 to achieve a 95% confidence interval with a margin of error of ±55 vehicles per hour.

4. To find the sample size needed for a 98% confidence interval to specify the mean to within ±55 vehicles per hour, we use the same formula but with a different z-value. For 98% confidence level, the z-value is 2.33.

Plugging in the values, we get:

n = \((2.33 * 311.7 / 55)^2\) = 186.34

Rounding up, we need a sample size of 187 to achieve a 98% confidence interval with a margin of error of ±55 vehicles per hour.

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Rearranging formulae. Can anyone help me with this question and show how you did it please? Will mark brainliest!

Rearranging formulae. Can anyone help me with this question and show how you did it please? Will mark

Answers

x= 5-21y! hope this helps you

Answer:

\(x=-21y+5\)

Step-by-step explanation:

Hi there!

\(7y=\frac{5-x}{3}\)

We can isolate x by performing inverse operations on both sides of the equation and canceling values out.

First, multiply both sides by 3 to cancel 3 out on the right side and isolate 5-x:

\(7y*3=\frac{5-x}{3}*3\\21y=5-x\)

Now, subtract 5 from both sides to isolate -x:

\(21y-5=5-x-5\\21y-5=-x\)

Finally, multiply both sides by -1 to change -x to x:

\(-21y+5=x\\x=-21y+5\)

I hope this helps!

Can someone help please!!!!!!

Can someone help please!!!!!!

Answers

Answer:

The Answer for 19 is x+y=38.

The Answer for 20 is  2x+5y=100.

Assume that ⋅=8,u⋅v=8, ‖‖=6,‖u‖=6, and ‖‖=4.‖v‖=4.

Calculate the value of (6+)⋅(−10).(6u+v)⋅(u−10v).

Answers

The value of dot product (6+8)⋅(−10) is -140.

The value of (6u+v)⋅(u−10v) can be found using the distributive property and the dot product formula, which is (6u⋅u)+(v⋅u)-(60v⋅v). Substituting the given values, we get (6(6)²)+(8(6))-(60(4)²) = 92.

In the given problem, we are given the values of dot product, norms of two vectors u and v. We need to find the value of (6+8)⋅(−10) and (6u+v)⋅(u−10v). Using the formula for dot product, we get the value of the first expression as -140. For the second expression, we use the distributive property and the formula for dot product.

After substituting the given values, we simplify the expression to get the answer 92. The dot product is a useful tool in linear algebra and can be used to find angles between vectors, projections of vectors, and more.

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QUESTION 84

Amount of $3,000 due to be paid in 3 years, has a Present Value ____________.

A.
equal to the Expected Value of $3,000

B.
that is more than $3,000, assuming an interest rate greater than zero

C.
equal to an amount, that with accumulated desired interest would grow to be $3,000 three years from now

D.
Both A and C above

E.
Can’t tell, need the interest rate

Answers

The present value of an amount of $3,000 due to be paid in 3 years is equal to an amount, that with accumulated desired interest would grow to be $3,000 three years from now. This is because the present value is the value of the future payment today, after taking into account the time value of money and the interest rate. The answer to this question is C.

To calculate the present value of $3,000 due in 3 years, we need to discount the future payment back to its present value using the interest rate. This means that we need to find an amount that, when invested today at the given interest rate, will grow to be $3,000 in 3 years.

For example, if the interest rate is 5%, the present value of $3,000 due in 3 years would be approximately $2,530. This means that if you invest $2,530 today at 5% interest, it will grow to be $3,000 in 3 years.

Therefore, the correct answer is C, and we need to know the interest rate to calculate the present value accurately. Answer A is incorrect because the expected value of $3,000 does not take into account the time value of money and the interest rate. Answer B is incorrect because the present value should always be less than the future value if the interest rate is greater than zero. Answer D is incorrect because the expected value and the present value are not the same.

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One-way anova is a procedure for comparing the means of several populations. it is the generalization of what procedure for comparing the means of two populations?

Answers

One-way ANOVA is a statistical procedure that is used for comparing the means of several populations. Also, it is the generalization of pooled t-procedure for comparing the means of two populations.

What is a mean?

A mean is also referred to as an arithmetic average and it can be defined as a ratio of the sum of the total number in a data set (population) to the frequency of the data set.

What is an ANOVA?

ANOVA is an abbreviation for analysis of variance which was developed by the notable statistician Ronald Fisher. The analysis of variance (ANOVA) is a collection of statistical models with their respective estimation procedures that are used for the analysis of the difference between the group of means found in a sample.

This ultimately implies that, the analysis of variance (ANOVA) helps to ensure we have a balanced data by splitting the observed variability of a data set into random and systematic factors.

In Statistics, the analysis of variance (ANOVA) procedure is typically used as a statistical tool to determine whether or not the means of two or more populations are equal, especially through the use of the following:

Null hypothesisF-test.Pooled t-procedure

In this context, we can infer and logically deduce that a one-way ANOVA is a statistical procedure that is used for comparing the means of several populations. Also, it is the generalization of pooled t-procedure for comparing the means of two populations.

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Complete Question:

One-way ANOVA is a procedure for comparing the means of several populations. It is the generalization of what procedure for comparing the means of two populations?

A. nonpooled t-procedure

B. paired t-test

C. pooled t-procedure

D. None of the above

x^2-3x+1=0
One solution to the given equation can be written as\(\frac{3-\sqrt{n} }{2}\), where N is the constant WHAT IS THE VALUE OF N

Answers

Answer:

Step-by-step explanation:

Comment

n = the discriminant  of the quadratic equation. That is n = √(b^2 - 4ac)

a = 1

b = -3

c = 1

n = √(9 - 4(1*1)) = √5

Answer n = √5

Mark and John share the sum of $40 in ratio 2:3 how much does John get​

Answers

Answer:

John gets 24 dollars

Step-by-step explanation:

Divide 40 into 5 because 2+3 equals 5.

Each "section" equals 8. Now, multiply that by 3(John's section)

You get 24.

What is the answer to the question below

What is the answer to the question below

Answers

The distance between the two given points coordinates is; Option C: √85

How to find the distance between two coordinates?

Formula for the distance between two coordinates is;

d = √((x₂ - x₁)² + (y₂ - y₁)²)

We are given the coordinates as;

(-2, 3) and (5, -3). Thus;

d = √((-2 - 5)² + (-3 - 3)²)

d = √(49 + 36)

d = √85

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Help plsssssssssssss

Help plsssssssssssss

Answers

Answer:

1/4

Step-by-step explanation:

f(x) = 2 * (1/2) ^x

Let x=3

f(3) = 2 * (1/2) ^3

     = 2 * ( 1/2) * 1/2) * (1/2)

     = 2 * 1/8

    = 2/8

    = 1/4

a variable way to practice variables… variables are basically something that changes in the experiment. follow along in this activity and we will practice identifying variables….both ones that we do know about and ones that we might not see at first… a quick recap… use your notes to quickly define these three terms… hypothesis: independent variable: dependent variable: first, let’s make sure you know how to write a hypothesis: take a look at these questions one might ask and create a hypothesis. remember your formula! i wonder if the number of books i read will help me get smarter? hypothesis: i wonder what will happen to my plant if i leave it in the closet with no light? hypothesis: i wonder if exercising will help me get stronger? hypothesis: now, read the following hypotheses and identify the different variables. if you increase the number of hours of daylight a plant receives, then the plant will grow taller. independent : dependent: if you increase the amount of fish in the water, then you will increase the number of sharks in the area. independent : dependent: if you increase the amount of milk you drink, then you will increase the strength of your bones. independent : dependent: if you increase the number of hours you spend in practice, then you will increase the number of free throw shots you will make. independent : dependent: final practice in this section, you will read about two experiments. please write a hypothesis and identify the different variables. – independent and dependent. i am doing a test to see if there is a connection between how long you run and how fast your heart beats. i will be performing an experiment where a person will run for a 1 minute and i will check their heartbeat. then they will run for 2 minutes and i will check their heart rate. i will do this up to 6 minutes and see if there is a connection. what do you think my hypothesis should be? what are my variables? hypothesis: independent variable: dependent variable: the oc fair is right around the corner and your pig is on the plump side, tipping the scale at almost 300 pounds. you think, mrs. piggy needs to go on a diet to maintain a market ready weight of 280. to have her lose weight, you decide to place her on an all banana diet because you read on the internet it can take off 20 pounds in a week. you want to test this idea and see if it actually works. you plan to feed her a normal diet for the next week and keep track of her weight every morning. then, you plan to feed her nothing but bananas for a week and track her weight each morning. what do you think your hypothesis should be? what will the variables of your experiment be? hypothesis: independent variable: dependent variable:

Answers

In the first experiment, the hypothesis could be: If the duration of running increases, then the heart rate will increase.
The independent variable is the duration of running, and the dependent variable is the heart rate.

In the second experiment, the hypothesis could be: If the pig is fed only bananas for a week, then it will lose 20 pounds.
The independent variable is the diet (normal diet vs. all banana diet), and the dependent variable is the pig's weight.

Hypothesis: If the number of books I read increases, then I will get smarter.
Hypothesis: If I leave my plant in the closet with no light, then something will happen to it.
Hypothesis: If I exercise, then I will get stronger.

In the first hypothesis, the independent variable is the number of books read, and the dependent variable is getting smarter.
In the second hypothesis, the independent variable is leaving the plant in the closet with no light, and the dependent variable is the effect on the plant.
In the third hypothesis, the independent variable is exercising, and the dependent variable is getting stronger.

In the first experiment, the hypothesis could be: If the duration of running increases, then the heart rate will increase.
The independent variable is the duration of running, and the dependent variable is the heart rate.

In the second experiment, the hypothesis could be: If the pig is fed only bananas for a week, then it will lose 20 pounds.
The independent variable is the diet (normal diet vs. all banana diet), and the dependent variable is the pig's weight.

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Some teachers use a weighted mean to calculate grades. Each score is assigned a weight based on its importance. To find a weighted mean, multiply each score by its weight and add the results. For example, a student's final chemistry grade is based on four sources: 30% from lab reports, 10% from quizzes, 25% from the midterm exam, and 35% from the final exam. What is the student's weighted mean given the scores shown?

Answers

The student's weighted mean, based on the given scores and weights, is 81.25.

To calculate the student's weighted mean, we need the scores for each source and their corresponding weights. Since you haven't provided the specific scores, I will demonstrate the calculation using placeholder values.

Let's assume the student's scores are as follows:

Lab Reports: 85

Quizzes: 90

Midterm Exam: 75

Final Exam: 80

The weights for each source are as follows:

Lab Reports: 30%

Quizzes: 10%

Midterm Exam: 25%

Final Exam: 35%

To calculate the weighted mean, we multiply each score by its corresponding weight and then sum the results.

Weighted mean = (Lab Reports × Lab Reports Weight) + (Quizzes × Quizzes Weight) + (Midterm Exam × Midterm Exam Weight) + (Final Exam × Final Exam Weight)

Substituting the values:

Weighted mean = (85 × 0.30) + (90 × 0.10) + (75 × 0.25) + (80 × 0.35)

Weighted mean = 25.5 + 9 + 18.75 + 28

Weighted mean = 81.25

Therefore, the student's weighted mean, based on the given scores and weights, is 81.25.

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1/2x+y = 3
y = 3x + 10
Solve using substitution

Answers

Answer:

(-2,4)

x = -2 y = 4

I hope this helps

Question 1
Does 8! 8 7 • 6? Why or why not?
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Answers

The expanded form of 8! is 8×7×6×5×4×3×2×1.

What is a factorial?

A whole number's factorial is the result of multiplying the integer by each natural number below it.

The sign '!' can be used to indicate a factorial symbolically.

Therefore, 'n factorial' is denoted by the number n and is the product of n up to whole numbers below n except zero.

Given, A factorial number 8!.

Therefore, 8! = 8×7×6×5×4×3×2×1.

The product of all whole numbers below 8 and except zero.

We use factorials in permutation and combination also.

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