If 1/8 half-lives elapsed in a rock containing Uranium-238 and Lead-206, what is the ratio of parent to daughter isotopes

HCN is a linear molecule with C in the midle. C has 4 linking bonds, Nitrogen has 3 and Hydorgen 1 the structure threfore is:

Answer:

A

Explanation:

Answer:

\(1190\ \text{mL}\)

Explanation:

\(M_1\) = Initial Concentration of KCl = 2.7 M

\(V_1\) = Volume of KCl = 1 M

\(M_2\) = Final concentration of KCl = 1 M

\(V_2\) = Amount of water

We have the relation

\(M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}\)

The amount of water that is to be added is \(1890-700=1190\ \text{mL}\).

Answer:

The Coulomb Barrier U is 25.91 MeV

Explanation:

Given that:

Atomic Mass of lead nucleus A = 208

atomic mass of an alpha particle A = 4

Radius of an alpha particle \(R_\alpha = R_o A^{^{\dfrac{1}{3}}\)

where;

\(R_\alpha = 1.2 \times 10 ^{-15} \ m\)

\(R_\alpha = R_o A^{^{\dfrac{1}{3}}\)

\(R_\alpha = 1.2 \times 10 ^{-15} \ m \times (4) ^{^{\dfrac{1}{3}}\)

\(R_\alpha = 1.905 \times 10^{-15} \ m\)

Radius of the Gold nucleus

\(R_{Au}= R_o A^{^{\dfrac{1}{3}}\)

\(R_{Au}= 1.2 \times 10 ^{-15} \ m \times (208) ^{^{\dfrac{1}{3}}\)

\(R_{Au} = 7.11 \times 10^{-15} \ m\)

\(R = R_\alpha + R_{Au}\)

\(R = 1.905 \times 10^{-15} \ m + 7.11 \times 10^{-15} \ m\)

\(R = 9.105 \times 10 ^{-15} \ m\)

The electric potential energy of the Coulomb barrier \(U = \dfrac{Ke \ q_{\alpha} q_{Au}}{R}\)

\(U = \dfrac{8.99 \times 10^9 \ N.m \ ^2/C ^2 \ \times 2 ( 82) \times \(1.60 \times 10^{-19} C \ \ e } {9.105 \times 10^{-15} \ m }\)

U = 25908577.7eV

U = 25.908577 × 10⁶ eV

U =  25.91 MeV

The Coulomb Barrier U is 25.91 MeV

In IR spectroscopy, a sample of a molecule is irradiated with light in the IR portion of the electromagnetic spectrum. The energy of the infrared radiation after it has passed through the sample is then measured.

A decrease in the energy of a particular wavelength indicates that the molecule has absorbed this energy by undergoing some type of vibration. This is because when a chemical bond stretches and contracts, it vibrates at a specific frequency, which corresponds to a specific wavelength in the IR region of the electromagnetic spectrum. When the sample absorbs IR light at a specific frequency, it causes the bond to vibrate, consuming energy. An IR spectrum is a plot of the energy of the transmitted radiation as a function of the frequency of the infrared radiation. The plot appears as a series of peaks, each of which corresponds to a specific bond vibration in the molecule. The position and intensity of these peaks can provide information about the types of bonds and functional groups present in the molecule.

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Answer:

B)   n2=V2N1/V1

the second part is 0.080

Explanation:

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The volume and number of moles of a gas are in direct proportion. Hence, as the volume increases from 5 ml to 1 L, number of moles increases from 0.040 to 8 moles.

Avogadro's law, states that, at constant pressure and temperature, the number of moles of a gas is directly proportional to the volume of the gas. Hence,

V1/n1 = V2/n2, for two different volumes.

Given that, v1 = 5 ml

v2 = 1 L = 1000 ml

n1 = 0.040 mol

then n2 = v2 n1/ v2

Number of moles at 1 L = (0.040 mol × 1000 ml)/5 ml = 8 moles.

Hence, the number of moles of the gas added  = 8 - 0.040 = 7.96 moles.

Therefore, the amount of gas added at the increased volume is 7.96 moles.

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Answer:

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

The chemical reaction for the formation of ammonia by nitrogen and hydrogen reaction has been as follows:

For the formation of 2 moles of ammonia, 3 moles of hydrogen, and 1 mole of nitrogen s required.

The utilization of 3 moles of hydrogen requires 1 mole of Nitrogen.

So, the utilization of 6.34 moles of hydrogen requires:

3 moles Hydrogen = 1 -mole Nitrogen

6.34 moles hydrogen =  moles of Nitrogen

6.34 moles of hydrogen requires = 2.11 moles of Nitrogen.

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

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In order to test for ammonia, a moist red litmus paper should be held over the test tube containing the ammonia.  Option 3.

Ammonia is a substance that is alkaline in nature. All alkaline substances are able to turn red litmus paper to blue. This is in opposition to acidic substances that turn blue litmus paper to red.

Thus, the first test that can be used to determine if a substance is ammonia would be to hold a moist red litmus paper over the test tube containing the suspected substance.

Since ammonia is gas at room temperature, the substance suspected to be ammonia will diffuse from the test tube to turn the moist red litmus paper to blue.

Other methods to test for ammonia include passing a test tube containing hydrochloric acid over the test tube containing the substance. A white fume of ammonium chloride will confirm the presence of ammonia.

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Taking into account the reaction stoichiometry, 112.61 grams of lead(II) iodide, PbI₂, are produced from 81.1 g of potassium iodide, KI.

In first place, the balanced reaction is:

2 KI + Pb(NO₃)₂  → PbI₂+ 2 KNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, the direct rule of three must be applied using the following formula, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: x= (c×b)÷a

The following rule of three can be applied: if by reaction stoichiometry 332 grams of KI form 461 grams of PbI₂, 81.1 grams of KI form how much mass of PbI₂?

mass of PbI₂= (81.1 grams of KI× 461 grams of PbI₂)÷ 332 grams of KI

mass of PbI₂= 112.61 grams

Then, 112.61 grams of lead(II) iodide, PbI₂, are produced from 81.1 g of potassium iodide, KI.

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'Removing a small amount of O2(g)' will increase the amount of BaO2(s) in the vessel.

What do you mean by a vessel?

In chemistry, a vessel is a container, typically made of glass, that is used to hold and heat liquids or solids in a chemical reaction. It is an essential piece of laboratory equipment, and it is used to safely and accurately measure, mix, and store materials. Vessels come in many different forms and sizes, and are used for everything from simple mixing applications to complex, high-temperature reactions.

When oxygen is removed from the vessel, the equilibrium of the reaction will shift in favor of the formation of BaO2(s). This is because the reaction is exothermic and the decrease in O2(g) will reduce the amount of energy available for the reaction to occur, thus favoring the formation of BaO2(s).

Hence, option A is correct.

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Explanation:

Moles=mass/molar mass

moles × molar mass = mass

0.206 x 119= mass

Mass= 24. 51grams

Answer:

24.51 g to the nearest hundredth

Explanation:

1 mole of SOCl2 =  32 + 16 + 2 *35.5 = 119 g

0.206 mol = 0.206 * 119

=  24.51 g.

Answer:

i think iron

Explanation:

i not sure with my ans

The strand 1 of hydrocarbons is used to produce plastic, hence option D is correct.

Raw resources like natural gas, oil, or plants that have been processed into ethane and propane are used to make plastics. The subsequent "cracking" procedure uses heat to transform ethane and propane into ethylene and propylene. To produce various polymers, these components are mixed.

Propylene is a substance found in large quantities in petroleum. In order to speed up chemical processes, refiners combine heated propylene with a catalyst to create plastic. Propylene molecules start to cluster together like beads on a thread as a result.

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When more predators prey on glowing rabbits as a result of the slow-glow gene, the odds of rabbit children inheriting bioluminescence would gradually decline.

A chemical process that results in the production of light energy inside an organism's body causes bioluminescence. A species must include luciferin, a molecule that creates light when it interacts with oxygen, for a reaction to take place.

Only fireflies, a few types of mushrooms, glowworms, & a few other creatures exhibit bioluminescence on land. Bioluminescent marine life, however, produces an underwater light display. A MBARI study found that 75% of deep-sea organisms produce their own light.

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Answer:a

Explanation:

Answer:

115.6 kJ/mol

Explanation:

The ΔG of a reaction can be calculated using the following equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG° is the standard free energy change, which is given as 137.0 kJ/mol in this case

R is the gas constant, which is 8.314 J/(mol·K)

T is the temperature in Kelvin, which is 25°C + 273.15 = 298.15 K

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants, each raised to their stoichiometric coefficients.

From the chemical equation given, the stoichiometric coefficients of Mg2+ and PO43- are 3 and 2 respectively. Therefore, the reaction quotient can be expressed as:

Q = [Mg2+]^3 [PO43-]^2

Substituting the given initial concentrations of Mg2+ and PO43- into the reaction quotient expression, we get:

Q = (0.65 M)^3 (0.43 M)^2 = 0.011 M^5

Now we can calculate the ΔG of the reaction:

ΔG = ΔG° + RT ln(Q)

ΔG = (137.0 kJ/mol) + (8.314 J/(mol·K) × 298.15 K) × ln(0.011 M^5)

ΔG = 137.0 kJ/mol - 21.38 kJ/mol

ΔG = 115.6 kJ/mol

Therefore, the ΔG for the reaction at 25°C and the given initial concentrations of Mg2+ and PO43- is 115.6 kJ/mol.

Answer:

Odour is intensive

Explanation:

intensive properties are Independent of the amount of matter

Explanation:

Hope this somewhat helped:

a. The equation for the reaction of weak acid, C6H5CO2H, with water is: C6H5CO2H + H2O <=> C6H5CO2^- + H3O^+. We can assume that all the C6H5CO2H has reacted with water to form C6H5CO2^- and H3O^+.

The pH is defined as -log(H30^+ concentration), where H30^+ is the hydronium ion, a measure of the acidic strength of the solution. At the equivalence point, all the C6H5CO2H has reacted with the NaOH to form C6H5CO2^- and Na^+. The stoichiometry of the reaction can be determined by balanced the reaction using the information given.

C6H5CO2H + NaOH <=> C6H5CO2^- + Na^+

This reaction tells us that one mole of C6H5CO2H will react with one mole of NaOH to form one mole of C6H5CO2^- and one mole of Na^+.

Answer: 40 + 2x14 + 6x16 = 164g/mole

54.3g x [1mole / 164g] = 0.331moles

355mL x 1L / 1000mL = 0.355L

molarity = 0.331moles / 0.355L =

00

Explanation:

The molarity of a solution prepared by dissolving 54.3 g of Calcium nitrate  into 355 mL of water is 0.9881M

Molarity of solution is the ratio of the number of moles of the substance to the volume.

\(Molarity=\frac{n}{V}\)

\(n=\frac{54.3}{164.088 } \\n=0.331 moles\)

Get the required molarity;

\(Molarity=\frac{0.331}{0.335}\\Molarity= 0.9881 M\)

Hence the molarity of a solution prepared by dissolving 54.3 g of Calcium nitrate  into 355 mL of water is 0.9881M

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125 milliliters of a 6.00 M sulfuric acid solution are required if 0.750 moles of H2SO4 are needed for a reaction.

HOW TO CALCULATE VOLUME:

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The water cycle, also known as the hydrologic cycle, is the continuous movement of water on, above, and below the surface of the Earth.

The water cycle involves a series of physical processes, including evaporation, condensation, precipitation, and runoff, that work together to move water from one location to another and to maintain the balance of water on Earth.

The water cycle begins when water from oceans, lakes, rivers, and other bodies of water evaporates into the atmosphere due to the heat from the sun. As water vapor rises into the atmosphere, it cools and condenses into clouds. When the clouds become saturated with water vapor, precipitation occurs in the form of rain, snow, sleet, or hail.

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The most reactants in the system are the oxygen molecules while the least reactants in the system is carbon sulfide. As such carbon sulfide is the limiting reactant.

We know that when we talk about a chemical reaction, what we are referring to is the interaction that is able to occur between the reactants and the products that are found in the system. We know that when we write down a chemical reaction, the species that are combined are the species that we can find on the left hand side and they are called the reactants. The species that we obtain in the reaction are the species that we can find on the right hand side and they are called the products of the reactions.

If we look at the reaction as it has been shown, we can see that there are ten oxygen molecules and three carbon sulfide molecules that were initially present in the system as we can see here. The entire reaction equation is given as; CS₂(g)+30₂(g) → CO₂(g) +2 SO₂(g).

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Answer:

erosion can be reduced by planting trees and other plants

Answer:

A

Explanation:

Answer:

log = ( - 0.51 z 2) / ( 1 + ( / 305)

Explanation:

Answer:

\(5.64*10^{14}\)m

Explanation:

C = Fλ

C: Speed of light = \(3*10^8\)m/s

f: Frequency (Hz)

λ: Wavelength (m)

Rearrange formula for wavelength:

C/F = λ

\(\frac{3*10^8}{532*10^{-9}} =5.64*10^{14}m\)

Answer:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases equals the original mass of the charcoal and the oxygen when it first reacted.

Explanation:

That is what I think on the subject

Answer:

3600J

Explanation:

Q = mc∆T

= 50 x 0.9 x (100 - 20)

= 3600J

The heat used to change the temperature of 30 grams of water from 45K to 50 K is equal to 627.6 J.

The specific heat capacity of a material can be defined as the heat required to raise the temperature by one degree Celcius in one unit of substance.

Whenever the heat energy is lost or supplied the temperature of the substance will be changed:

Q = mCΔT

Given, the mass of the water, m = 30 g = 0.030 kg

The change in the temperature = 50 - 45 = 5 K

ΔT = 5 K

The specific heat capacity of the water, C = 4184 J/Kg K

The heat required for the given change in temperatures can be calculated as:

Q = 0.03 × (4184) × 5

Q = 627.6 J

Therefore, the heat required is equal to 627.6 J.

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Carbon dioxide gas and solid magnesium oxide are formed by the decomposition of solid magnesium carbonate and the formula is given below:

MgCO₃ → MgO + CO₂

This is referred to as a type of chemical reaction in which one reactant breaks down into two or more products.

An example of this type of reaction is in the case of  solid magnesium oxide which heat energy is applied to it in other to produce two products which are known as Carbon dioxide gas and solid magnesium oxide as shown in the equation above thereby making it the correct choice.

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