Answer:
1kgStep-by-step explanation:
According to Newton's second law
Force = mass * acceleration
Given
Force = 2N
acceleration = 2m/s^2
Mass =Force/Acceleration
Mass = 2/2
Mass =1kg
Hence the mass of the ball is 1kg
A side of the triangle below has been extended to form an exterior angle of 132°. Find the value of X
Answer:
x = 114°
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, thus
x + 18° = 132° ( subtract 18° from both sides )
x = 114°
The value of angle x in the triangle will be equal to 114°.
What is an exterior angle?When one side of a triangle is extended, an external angle of the triangle is created. The external angle of the triangle is the non-straight angle (the one that is not simply the extension of the side) that is outside the triangle but close to an interior angle.
Given that a side of the triangle below has been extended to form an exterior angle of 132°
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, thus
x + 18° = 132° ( subtract 18° from both sides )
x = 114°
Therefore, the value of angle x in the triangle will be equal to 114°.
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in an experiment, a ball is drawn from an urn containing 9 green balls and 11 orange balls. if the ball is green, three coins are tossed. otherwise two coins are tossed. how many elements of the sample space will have a green ball?
There are 13 elements of the sample space that will have a green ball.
The various ways in which objects from a set may be selected, generally without replacement, to form subsets.
Since, when a green ball is drawn, three coins are tossed. So, sample points are OHHH, OHHT, OHTH, and OHTT. OTHH, 0THT, OTTH, OTTT
So, clearly, 9 sample points will have an orange ball.
When a blue ball is drawn, two coins are tossed. So, sample points are BHH, BHT, BTH, and BTT.
So, clearly, 4 sample points will be when a blue ball is drawn.
Total samples points=4+9=13
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CC has the following beginning balances in its stockholders' equity accounts on January 1, 2012: Common Stock, $100,000; Additional Paid-in Capital, $4,100,000; and Retained Earnings, $3,000,000. Net income for the year ended December 31, 2012, is $800,000. Court Casuals has the following transactions affecting stockholders' equity in 2012:
May 18 Issues 25,000 additional shares of $1 par value common stock for $40 per share.
May 31 Repurchases 5,000 shares of treasury stock for $45 per share.
July 1 Declares a cash dividend of $1 per share to all stockholders of record on July 15. Hint: Dividends are not paid on treasury stock.
July 31 Pays the cash dividend declared on July 1.
August 10 Reissues 2,500 shares of treasury stock purchased on May 31 for $48 per share.
Taking into consideration all the entries described above, prepare the statement of stockholders' equity for the year ended December 31, 2012.
Total stockholders’ equity 7,800,000
Statement of stockholders’ equity for CC for the year ended December 31, 2012:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000
Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
Total stockholders’ equity 7,800,000
Explanation:The given information is as follows:Common Stock on January 1, 2012 = $100,000Additional Paid-in Capital on January 1, 2012 = $4,100,000
Retained Earnings on January 1, 2012 = $3,000,000Net Income for the year ended December 31, 2012 = $800,000Cash Dividend Declared on July 1 and paid on July 31 = $200,000
To prepare the statement of stockholders’ equity for the year ended December 31, 2012, we will begin by preparing the opening balances of each of the equity accounts. We will then add the net income to the retained earnings account.
The closing balance for retained earnings is then computed by subtracting the cash dividend declared and paid from the total retained earnings. Finally, the total stockholders' equity is calculated by adding the balances of all the equity accounts.
Calculations:Opening balance of common stock = $100,000
Opening balance of additional paid-in capital = $4,100,000
Opening balance of retained earnings = $3,000,000
Net Income for the year ended December 31, 2012 = $800,000
Retained earnings (Opening Balance) = $3,000,000
Add: Net Income for the year ended December 31, 2012 = $800,000
Total retained earnings = $3,800,000Less: Cash Dividend Declared on July 1 and paid on July 31 = $200,000Retained earnings (Closing balance) = $3,600,000
Total stockholders’ equity = Common Stock + Additional Paid-in Capital + Retained Earnings (Closing balance) = $100,000 + $4,100,000 + $3,600,000 = $7,800,000
Therefore, the statement of stockholders’ equity for CC for the year ended December 31, 2012, is as follows:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000
Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
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John has a swimming pool filled with 400 gallons of water. the water is draining at a rate of 0.35 gallons per minute. the function f(x)=400-0.35x can be used to determine the amount of water remaining from 0 to 5 minutes. what is the range of the function for this situation?
The range of the function for this situation is the interval [398.25, 400] gallons.
To determine the range of the function f(x) = 400 - 0.35x for the given situation, we need to find the possible values of the amount of water remaining in the pool.
The function f(x) represents the amount of water remaining (in gallons) after x minutes, where x ranges from 0 to 5.
To find the range of the function, we evaluate f(x) for the extreme values of x in the given range (0 to 5).
For x = 0, the initial amount of water remaining:
f(0) = 400 - 0.35(0) = 400 gallons
For x = 5, the amount of water remaining after 5 minutes:
f(5) = 400 - 0.35(5) = 400 - 1.75 = 398.25 gallons
Therefore, the range of the function for this situation is the interval [398.25, 400] gallons.
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Pls help me answer this!
Answer:
someoeneenennene willlll heelellelelleep yyouuouou
Step-by-step explanation:
stan kim namjoon
Answer:
27
Step-by-step explanation:
i think this is the correct answer. To work out this question i did 100-64, so that i could find the percentage, which was 36 and then i did 36 percent of 75 which got me to 27.
Need help with geometry pls picture provided
Answer:
y= 30 x=15
set up your proportions for example 9/6 to y/20 and 9/6 to x/10 and then cross multiply
What is the growth factor when something is decreasing by:
15.7%
0.12%
When something decreases by 15.7%, the growth factor is about 1.182 and when something decreases by 0.12%, the growth factor is about 1.00012.
In math, what is the definition of multiplying?
Multiplication is a mathematical process that shows the amount of times a number has been added to itself. It is represented by the multiplication symbols (x) or (*). Division is a mathematical process that shows how many equal amounts add up to a given quantity.
If something decreases by 15.7%, the increase in the factor is 100 / (100 - 15.7) Equals 1.182.
As a result, when something decreases by 15.7%, the growth factor is about 1.182.
When something falls by 0.12%, the expansion factor is 100 / (100 - 0.12) = 1.00012.
As a result, when something decreases by 0.12%, the growth factor is about 1.00012.
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Give an example of a proportion that uses the numbers 2, 3, 4 and 6.
Give an example of a proportion that uses the numbers 2, 3, 4 and 6.
2:3 is the same as 4:6
Proportion says that two ratios (or fractions) are equal.
please graph y≤ 2x-3
Which graph represents the solution to the inequality 11 sy-43?
O
1
50 51 52 53 54 55 56 57 58 59 60
50 51 52 53 54 55 56 57 58 59 60
o
--++
--+++++++
-35 -34 -33 -32 -31 -30 -29 -28 -27 -26 -25
-35 -34 -33 -32 -31-30-29-28 -27 -26 -25
Answer:
the correct answer would be B
Step-by-step explanation:
I jus did the tes
Evaluate the Limit as n approaches infinity of (1+1/n)^n limn→[infinity](1+1/n)^n
The limit as n approaches infinity of (1+1/n)^n is equal to e, the base of the natural logarithm, which is approximately 2.71828.
To evaluate the limit lim(n→∞) (1+1/n)^n, we recognize that it is in the form of a well-known limit expression that defines the mathematical constant e. As n approaches infinity, the expression converges to the value of e.
The limit expression is derived from the definition of the exponential function e^x. The expression (1+1/n)^n is equivalent to (1+(1/n))^n, which closely resembles the form e^x, where x = 1/n. As n becomes larger and approaches infinity, 1/n becomes smaller, and (1+1/n)^n approaches e^x.
Therefore, the limit lim(n→∞) (1+1/n)^n evaluates to e, the base of the natural logarithm, which is approximately 2.71828. This is a fundamental result in calculus and demonstrates the relationship between exponential functions and the constant e.
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Find the equation of a line that passes through the points (1,-3) and (3,-1).
Leave your answer in the form
y=mx+c
Find the value of x in the given
right triangle.
Х
10
x = [? ]°
Enter your answer as a decimal rounded to the
nearest tenth.
Answer:
Step-by-step explanation
Answer: 35.0
Step-by-step explanation:
) 7/10 = 0.7
) tam(0.7)
) -> 35.0
In at least 150 words, discuss the changes that occur in John Proctor’s character, from the beginning of the play to the end
John Proctor is one of the most significant and complex characters in Arthur Miller's The Crucible, a drama set in 1692 Salem, Massachusetts, during the witchcraft hysteria.
In at least 150 words, we will examine the changes that occur in John Proctor's character from the beginning of the play to the end. John Proctor is a farmer and the husband of Elizabeth Proctor. He is a respected member of Salem's society, but he has a dark past. His affair with Abigail Williams, a teenage girl, led to his wife firing Abigail from her job and made her angry with the Proctors. John Proctor is a man of pride who cares deeply for his family. However, his own sense of right and wrong, his morals, and his beliefs are put to the test as the witchcraft hysteria takes over Salem.
At the beginning of the play, John Proctor is a man of reputation and standing in Salem. His love for his wife Elizabeth is evident, yet he carries with him the guilt of his affair with Abigail Williams. He is distant from his wife, troubled by his actions in the past, and unwilling to forgive himself. John Proctor has reservations about the witchcraft trials, and he is hesitant to speak out against them, which leads to his eventual downfall. However, as the play progresses, he transforms from a guilty and ashamed man into one who is determined to set things right and stand up for his beliefs.
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Brent is skiing down a mountain. If his altitude
changes by -15 feet per second, what will be his
!
Answer:
-900
Step-by-step explanation:
100 POINTS!!! Given f(x) = \(x^2\) - 6x + 8 and g(x) using a table of values. Show your work.
Answer:
X^2-6x+8 -X+2=0
X^2-7x+10=0
(X-5)(X-2)=0
Answer X= 5 and X=2
Step-by-step explanation:
HELP ME WITH THIS FOR BRAINLIST!
Answer:
In order to do this we need to get a better picture as well as a line plot to do this on.
Step-by-step explanation:
Nicolas Cage is transporting the national treasure from town A to town Z, and in between he has topass towns Q, U and W. Bandits abound along the journey. Suppose the probabilities of losing thenational treasure from A to Q, Q to U, U to W, and W to Z are 0.02, 0.04, 0.05 and 0.03,respectively, and these events are mutually independent, what is the probability that Nicolas Cagewill safely bring the national treasure to Z? Enter your answer as a decimal number rounded toFOUR digits after the decimal point.
we know that
The probability of losing the national treasure from A to Q is 0.02
so
The probability that not losing the national treasure from A to Q is 1-0.02=0.98
The probability that not losing the national treasure from Q to U is 1-0.04=0.96
The probability that not losing the national treasure from U to W is 1-0.05=0.95
The probability that not losing the national treasure from W to Z is 1-0.03=0.97
therefore
The probability that not losing the national treasure from A to Z is equal to
P=0.98*0.96*0.95*0.97
P=0.8669Three people each rented a car with insurance and one more prson rented a car with a car wash. What is the expression for the total cost
Correct Question is:
A car company charges x dollars to rent a car plus extra options as shown in table.
Car seat = 50 $
Insurance = 75 $
Car Wash = 15 $
Three people each rented a car with insurance and one more person rented a car with a car wash. What is the expression for the total cost?
Step-by-step explanation:
3 people rented with insurance = (x + 75) * 3) = 3x +225
one person rented with car wash = (15+x)
Total car rental will be adding both equations = 3x +225 + 15 + x = 4x + 240
Aft
10 ft
3 ft
2 ft
6 ft
Surface Area =
Surfa
I need the surface area
Answer:
Step-by-step explanation:
Front and back
Givens
base = 6 feet
height = 2
Formula
Area = 1/2 B * h
Area = 1/2 * 6 * 2
Area = (2) 1/2 * 12
Area = 12 square feet for both front and back
Base
The base is a rectangle. A rectangle has the formula of Area = L*w
Givens
L = 10 feet
W = 6 feet
Area = 10 * 6 = 60
Left roof
The left roof is also a rectangle. Area = L*w
Givens
L = 10 feet
W = 3 feet
Area = 3 * 10 = 30 feet^2
Right Roof
The right roof is a rectangle. Area = L*w
Givens
L = 10 feet
w = 4 feet
Area = 4 * 10 = 40 ft^2
Total area
Total Area = right roof + left roof + Base + front and back
Total Area = 40 + 30 + 60 + 12
Total Area = 142 feet ^2
what is the proportional relationship between x 2 6 8 10 and y 6 18 24 30
The proportional relationship is y = 3x.
What is the proportional relationship?
If the corresponding elements of two sequences of numbers, frequently experimental data, have a constant ratio, known as the coefficient of proportionality or proportionality constant, then the two sequences of numbers are proportional or directly proportional.
Here, we have
Given:
x: 2, 6, 8, 10
y: 6, 18, 24, 30
We have to find the proportional relationship between x and y.
So, we can see from inspection and visual observation that there is a proportional relationship between x and y.
6 = 3 2, 18 = 3 6, 24 = 3 8, 30 = 3 10.
Hence, The proportional relationship is y = 3x.
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A CONE IS 1/3 OF A CYLINDER, SO THE VOLUME FORMULA IS 1/3 THE CYLINDER. True or false
Answer:
yes that's the answer because the volume of a cylinder= πr²h and the volume of a cone =1/3πr²h
The vertex of the graph of y = (x - 1)2.5 is
Answer:
vertex = (1, - 5 )
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
y = (x - 1)² - 5 ← is in vertex form
with (h, k ) = (1, - 5 ) ← vertex
If there are outliers in a sample, which of the following is always true?a. Mean > Median
b. Standard deviation is smaller than expected (smaller than if there were no outliers)
c. Mean < Median
d. Standard deviation is larger than expected (larger than if there were no outliers)
In the presence of outliers in a sample, the statement that is always true is d. Standard deviation is larger than expected (larger than if there were no outliers).
Outliers are extreme values that are significantly different from the other data points in a sample. These extreme values have a greater impact on the standard deviation compared to the mean or median. As a result, the standard deviation increases when outliers are present. Therefore, option d is the correct answer.
To summarize, when outliers are present in a sample, the standard deviation is typically larger than expected, while the relationship between the mean and median can vary and is not always predictable.
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Please answer it now.
The radius of the curved path of the car such that it is not skidding is 51.2 meters.
What is the coefficient of friction for a car moving on curve?
A car is moving in a curved path at constant speed. By Newton's laws and equation of friction, we find that the square of the car's speed (v), in meters per second, is directly proportional to the radius of the curve path (s) and to the coefficient of friction (μ), no unit:
v² = k · R · μ
Where k is the constant of proportionality.
If we know that R = 40 m, v = 4√10 m / s, μ = 0.4, v' = 10 m / s, μ' = 0.5, then the resulting radius is:
v'² / (μ' · R') = v² / (μ · R)
10² / (0.4 · 40) = (4√10)² / (0.5 · R)
0.5 · R = (4√10)² · (0.4 · 40) / 10²
0.5 · R = 128 / 5
R = 256 / 5
R = 51.2 m
The radius of the curved path is 51.2 meters.
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My cousin borrowed $18,000 for a new car loan for 6 years. He told me that at the end of the loan, he had paid $25,560 for the interest and principal. What was the rate of the loan?
Answer:
6%
Step-by-step explanation:I
I'm going to assume that the interest is compoudning anually and there was only one payment
we know that
FV=PV(1+i)^N
which means taht
25560=18000(1+i)^6
Solve for i and get .06 or 6%
Write the equation in point-slope form of the line that passes through the points (-10,4) and (10,8)
Answer:
10
Step-by-step explanation:
10 and 8 would be in between 10 and 9 hope this can help
you need to compute the probability of 5 or fewer successes for a binomial experiment with 10 trials. the probability of success on a single trial is 0.42. since this probability of success is not in the table, you decide to use the normal approximation to the binomial. is this an appropriate strategy? explain.
The normal approximation to the binomial distribution may not be appropriate since the number of trials is small (10) and the success probability is relatively far from 0.5 (0.42). The conditions for the normal approximation are not met in this scenario.
Using the normal approximation to the binomial distribution may be appropriate in this case. The normal approximation assumes that the binomial distribution is approximately symmetrical and the sample size is sufficiently large. However, certain conditions should be met for the approximation to be valid:
The number of trials, n, should be large enough (usually greater than or equal to 20) to satisfy the Central Limit Theorem.
The probability of success, p, should not be extremely close to 0 or 1. A rule of thumb is that np and n(1-p) should both be greater than or equal to 5.
In this scenario, the number of trials is 10, which is smaller than the recommended threshold for the Central Limit Theorem. Additionally, the success probability is 0.42, which is relatively close to the extremes of 0 or 1. Therefore, using the normal approximation may not be the most appropriate strategy. Instead, it would be better to use the binomial probability formula or consult binomial tables to compute the probability of 5 or fewer successes directly from the binomial distribution.
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in the following, we only consider graphs with 2 or more vertices. a cut in a graph is a subset of edges whose removal leaves a graph with more than one connected component. what is the minimum size of a cut where size is number of edges in the cut, for a graph that has more than one connected component?
The minimum size of a cut where size is number of edges in the cut, for a graph that has more than one connected component is 1.
In graph theory, a bridge, also known as a cut-edge, is a fundamental concept that refers to an edge in a graph that has the property of disconnecting the graph when it is removed. This means that when an edge is considered a bridge, the removal of that edge would result in an increase in the number of connected components in the graph. The importance of bridges in graph theory lies in the fact that they provide a way to break down a complex graph into smaller, simpler components that can be analyzed and understood individually. Bridges can be found in many different types of graphs, including undirected graphs, directed graphs, and weighted graphs. It is also important to note that in a graph with more than one connected component, there must exist at least one bridge, meaning that the minimum size of a cut in a graph is 1. This is because a bridge is the edge that separates the graph into two or more separate components.
The minimum size of a cut in a graph is 1. This occurs in the case of a "bridge", where removing a single edge from the graph would result in two separate connected components. In any graph with more than one connected component, there must exist at least one bridge, meaning that the minimum size of a cut is 1.
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a student has a class that is supposed to end at 9:00am and another that is supposed to begin at 9:15am. suppose the actual ending time of the 9am class is normally distributed random variable (x1) with a mean of 9:02 and a standard deviation of 2.5 minutes and that the starting time of the next class is also a normally distributed random variable (x2) with a mean of 9:15 and a standard deviation of 3 minutes. suppose also that the time necessary to get from one class to another is also a normally distributed random variable (x3) with a mean of 10 minutes and a standard deviation of 2.5 minutes. what is the probability that the student makes it to the second class before the second lecture starts? (hint: assume x1, x2 and x3 are independent also think linear combinations)
The probability that the student makes it to the second class before it starts is very close to 0.
To find the probability that the student makes it to the second class before it starts, we can use the concept of linear combinations of random variables and the properties of normal distributions.
Let's define the random variable X as the total time it takes for the student to transition from the end of the first class to the start of the second class. Since X is a linear combination of independent normally distributed random variables (X1, X2, X3), we can use their means and variances to calculate the mean and variance of X.
The mean of X is the sum of the means of X1, X2, and X3:
μX = μ1 + μ2 + μ3 = 9:02 + 9:15 + 10 = 28:17 minutes.
The variance of X is the sum of the variances of X1, X2, and X3:
σX^2 = σ1^2 + σ2^2 + σ3^2 = (2.5)^2 + (3)^2 + (2.5)^2 = 15.25 minutes^2.
Now, we need to calculate the probability that X is less than or equal to 0, meaning the student arrives before the second lecture starts. Since X follows a normal distribution, we can standardize the variable and calculate the probability using the standard normal distribution table.
Z = (0 - μX) / σX = (0 - 28:17) / √15.25 ≈ -9.43.
Using the standard normal distribution table or a calculator, we can find the probability corresponding to Z = -9.43. The probability is essentially 0, as the value is significantly far in the left tail of the standard normal distribution.
Therefore, the probability that the student makes it to the second class before it starts is very close to 0.
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