if a gate valve resists turning after fewer than the indicated number of turns required to close the valve, the:

Since P[X=n] is the same for every n, we can use the formula for the expected value of a discrete random variable, which is E[X] = Σ (n * P[X=n]). Since P[X=n] is the same for every n, we can simplify this formula to E[X] = Σ (n * p), where p is the probability of any given value.

We know that there are 7 consecutive integers from 0 to 6, so p = 1/7.
Therefore, E[X] = Σ (n * 1/7) = (0/7 + 1/7 + 2/7 + 3/7 + 4/7 + 5/7 + 6/7) / 7 = 21/2 * 1/7 = 3.
So the expected value of X is 3.
To calculate the expected value E[X] of a discrete random variable X with a uniform distribution over the set {0,1,...,6}, follow these steps:

1. Determine the probability of each outcome: Since P[X=n] is the same for every n, and there are 7 possible outcomes (0 to 6), the probability for each outcome is 1/7.
2. Multiply each outcome by its probability: Calculate the product of each integer in the set and its probability (1/7). For example, for the integer 0, the product is 0*(1/7), for 1, it's 1*(1/7), and so on.
3. Sum the products: Add up the products calculated in step 2: 0*(1/7) + 1*(1/7) + 2*(1/7) + 3*(1/7) + 4*(1/7) + 5*(1/7) + 6*(1/7).
4. Calculate E[X]: E[X] = 0*(1/7) + 1*(1/7) + 2*(1/7) + 3*(1/7) + 4*(1/7) + 5*(1/7) + 6*(1/7) = (1/7)(0 + 1 + 2 + 3 + 4 + 5 + 6) = (1/7)(21) = 3.
So, the expected value E[X] for the discrete random variable X over the set {0,1,...,6} is 3.

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The Clark and Diliberto Search Team Clark and Diliberto refer to the investigators dispatched to the computer crime scene as the "Computer Search Warrant .

what is  recommended composition?

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The "Computer Search Warrant" is the name given by Clark and Diliberto to the team of investigators who were sent to the computer crime scene.

A good composition has just the right amount of detail. A work of art that has too few elements is bad because it lacks the necessary detail for correct interpretation. Additionally, it throws off an image's balance. Additionally, having too many elements can be very distracting. Good balance is necessary for good composition.

Every visual element in a good composition plays a specific role and contributes to the story. Photography requires a balance between the elements in the frame for a good composition. It means that you need to strike a balance between space and detail, highlights and shadows, etc.

The act of writing or the piece of writing that results is referred to as composition. Additionally, it refers to the material of something. The word "composition" comes from the Latin word "componere," which means "to put together," and its meaning is still very similar to that.

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In a channel where a modem transmits a +2 voltage signal, the PMF of the output Y includes probabilities of 4/10 for +2, 3/10 for +1, 2/10 for 0, and 1/10 for -1. The probability of the output being equal to the input is 4/10, and the probability of the output being positive is 7/10.

To solve this problem, we'll use the given probabilities to determine the probability mass function (PMF) of the output Y of the channel.

(a) PMF of the output Y:

Let's define Y as the output of the channel after adding noise. The possible values of Y are determined by adding the noise terms to the input signal.

Y = +2 + 0 = +2 (with probability 4/10)

Y = +2 + (-1) = +1 (with probability 3/10)

Y = +2 + (-2) = 0 (with probability 2/10)

Y = +2 + (-3) = -1 (with probability 1/10)

Therefore, the PMF of Y is:

P(Y = +2) = 4/10

P(Y = +1) = 3/10

P(Y = 0) = 2/10

P(Y = -1) = 1/10

(b) Probability that the output is equal to the input:

We can see from the PMF that Y = +2 occurs with a probability of 4/10. Therefore, the probability that the output of the channel is equal to the input is 4/10.

(c) Probability that the output is positive:

The values of Y that are positive are +2 and +1. From the PMF, we can calculate the probability as follows:

P(Y > 0) = P(Y = +2) + P(Y = +1) = (4/10) + (3/10) = 7/10

Therefore, the probability that the output of the channel is positive is 7/10.

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The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole.

Let suppose that the gas sample behaves ideally. The Graham's law establishes a connection between the ideal gas model and the kinetic theory of gases.

In this question we need to use this law to estimate the average kinetic energy (Kₐ), in joules per mole, of a diatomic gas (N₂), which is defined by the following expression:

\(K_{a} = \frac{3}{2}\cdot R_{u}\cdot T\)   (1)

Where:

If we know that \(R_{u} = 8.314\,\frac{J}{mol\cdot K}\) and \(T = 288.15\,K\), then the average kinetic energy is:

\(K_{a} = \frac{3}{2}\cdot \left(8.314\,\frac{J}{mol\cdot K} \right) \cdot (288.15\,K)\)

\(K_{a} = 3593.519\,\frac{J}{mol}\)

The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole. \(\blacksquare\)

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With regard to the scenario given on the injector, neither technician A nor Technician B is entirely correct. Here's why:

The Detroit ACR (Active Control of the Fuel Injection Rate) injectors are designed to maintain a constant injection pressure, which means they do not amplify the injection pressure under heavy loads. Instead, they vary the timing and duration of the injection events to optimize fuel delivery and reduce emissions.

However, Technician B is partially correct in that the ACR injectors do operate differently at different engine speeds. At engine speeds just above idle, the ACR injectors can provide a more precise fuel delivery and reduce emissions by using multiple injection events during each combustion cycle.

So, in summary, Technician A is incorrect and Technician B is partially correct.

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Answer:

George  Floyd (BLACK  LIFES  MATTER)

C O V I D - 19

Quarantine  

no sports

wearing a mask

and a whole lot of other stuff

Explanation:

Answer:

The answer is "\(\bold {3.3 \ \frac{g}{L}}\)"

Explanation:

If the endogenous metabolic rate wasn’t substantial after, which \(\mu_{net} = \mu_{max} = \frac{0.693}{ \text{ doubling period}}\) .

Throughout the calculating of doubling the time is set at 6.5 hours, consequently \(\mu_{max} = \frac{0.693}{6.5} = \frac{0.1}{hours}.\)

Know we calculate the two-equation,  

Initially, the maximum dilution frequency for \(D_{max}\) that is:  

\(D_{max}= \mu _{max}\times \frac{[S_0]}{{K_s + [S_0]}} .....(a)\)

In secondary the steady concentration of state cells X,  

\(X = \frac{Y_{\frac{x}{s}} (s[S_0]-K_sD)}{(\mu _{max}-D)}...... (b)\)

In this section, we will display the \(Y_{\frac{x}{s}}\) , that is equal to \(0.33\ \frac{g}{g-substrate}\), and the value of the \(K_s = 12 \times 10^{-3} \ \frac{g}{L}\).  

For equation (a):

\(D_{max} = 0.1 \times \frac{10}{ (12 \times 10^{-3} + 10)}\)

         \(= 0.1 \times \frac{10}{ (\frac{12}{10^{3}} + 10)}\\\\= 0.1 \times \frac{10}{ 0.012 + 10)}\\\\= 0.1 \times \frac{10}{ 10.012}\\\\=0.1 \times 0.9988\\\\= 0.09988\\\\= 0.1 \ \ \frac{1}{h}\)

In the Operating value is equal to \(D =\frac{1}{2}\) of \(D_{max}\), so D is =\(\frac{0.05}{h}\) in our case.  

Finally, the amount of protozoa cells in equation (b):

\(X = 0.33 \times (10 - 12 \times 10^{-3} \times \frac{0.05}{(0.1 - 0.05)})\\\\X = 0.33 \times (10 - 12 \times 10^{-3} \times \frac{0.05}{-0.05})\\\\X = 0.33 \times (10 - 12 \times 10^{-3} \times -1 )\\\\X = 0.33 \times (10 + \frac{12}{10^{-3}} )\\\\X = 0.33 \times ( 10.012 )\\\\X= 3.303\\\)

The amount of radiation that the system is radiating into space is 1.164 x 10¹⁷. See the explanation below.

Rockets or space crafts emit heat as they navigate into space. This heat or emissions is what is referred to as radiation.

Recall that we are given the following:

Thus,

Converting the temperature of the Radiator, we have:

30°C = 273 + 30

= 303K

Area of the Panel of the radiator = 0.3 x 0.1

= 0.03

The formula for the heat emitted by the system is given as:

Q = ∈δA (T₁⁴  - T₁⁴)

Where:

δ = Stefan - Bolta Mann constant

→ δ = 5.67 X 10⁻ⁿ

→ The amount of heat is thus given as:

Q = 0.89 x 5.17 x 10⁸ [ (303)⁴ - (3)⁴] x 0.03

Therefore,

Q = 1.1635158780036 × 10¹⁷

Q ≈ 1.164 x 10¹⁷

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The specialized part of the practice that deals with an organization's "number one public" and its "most important asset" is public relations.

Public relations (PR) is the specialized field that focuses on managing communication and relationships between an organization and its various publics, including stakeholders, customers, employees, and the general public.

In PR, there is a recognition that the organization's reputation and public perception are crucial to its success. This is why the organization's "number one public" refers to the target audience or key stakeholders that are prioritized in PR efforts.

Additionally, the "most important asset" refers to the organization's reputation, which is highly valued and carefully managed through strategic communication, media relations, crisis management, and other PR techniques.

PR professionals work to build and maintain positive relationships, enhance brand image, and ensure effective communication with the organization's key publics.

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Always run before the subclass constructor is the superclass constructor.The final modifier must be overridden in a subclass when a method is declared with it. A superclass has access to packages.

A subclass must utilize the public accessor and mutator methods rather than the private instance variables of the superclass in order to access the public methods from the superclass that it extends. Additionally, constructors from the superclass are not inherited by subclasses. We utilize the super() function to directly invoke the superclass constructor from the subclass constructor. It's an exclusive variation of the super keyword. Only within the subclass constructor may super() be used, and it must come first. Only the subclass' instance variables can be initialized by the constructors. As a result, when a subclass object is created, the subclass object must also immediately call one of the superclass' constructors. You will get a compile-time error if the super class does not have a no-argument constructor.

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Answer:

An engineer using a decision matrix to determine which one of his/her solution ideas meets the established criteria and constraints.

The rate of heat transfer represents the amount of heat transferred per unit time. It is crucial to use the correct units when measuring this rate. From the list provided, the acceptable units for the rate of heat transfer are:
a.) Kilowatt (kW)
b.) Watt (W)

Kilowatt and watt are both units of power, which is the rate of energy transfer per unit time. In the context of heat transfer, they indicate how quickly heat is being transferred. A kilowatt is equal to 1,000 watts.

Units c, d, and e are not appropriate for measuring the rate of heat transfer. Kilojoule (kJ) and joule (J) are units of energy, not power, and are used to quantify the amount of heat transferred rather than the rate at which it is transferred. Kilojoule per kilogram (kJ/kg) and joule per kilogram (J/kg) are specific energy units, representing the energy per unit mass, and are also not suitable for measuring the rate of heat transfer.

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Answer:

10 flip -flops are required to build a binary counter circuit to count to from 0 to 1023 .

Explanation:

The essay that discuss any experiences I have had with food-borne illness is given below.

Food-borne illness affects millions every year, including people I know. My friend got food poisoning from sushi at a local restaurant, causing stomach cramps, vomiting, and diarrhea for two days. He had an unpleasant experience. Another family member got sick from old potato salad at a picnic.

She had fever, cramps, and nausea and took days to recover, showing the importance of food safety. Cook, store, and handle food properly to prevent harmful bacteria growth. Wash hands, surfaces, utensils, keep hot and cold foods separate, and reheat leftovers properly.

So, It is vital to know food illness symptoms and seek medical help if needed, such as nausea, vomiting, diarrhea, fever, and abdominal pain. Stay hydrated, rest and practice food safety and hygiene to prevent illness.

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Answer:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

Answer: 162.4

Sorry if you get it wrong :(

Explanation:

Based on the image attached, the reading of micrometer is= 15.20.

You will see a line of numbers running down the barrel of your micrometer, starting with the barrel scale. On the barrel scale, each number corresponds to 0.100. Looking at the barrel, 1 equals 0.100, 2 equals 0.200, 3 equals 300, and so on. The distance between each tick mark and the larger numbers on the barrel is 0.025, or 25 thousandths. 

Note that micrometer is one that is also referred to as a micrometer screw gauge—is a tool with a calibrated screw that is frequently used for precise measurement of components in mechanical engineering, and others.

Looking at the image, you will see the stop ends at 15 and  and 20 so adding them together will be option A. 15.20.

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Answer:

i) SF = 0.83

ii) 10 psi

iii) 3.16 psi

iv) 0.0083

Explanation:

Constant load = 1000 Psi

mean resistance = 1200 psi

Probability of failure = 1.9 * 10^-3

Determine

i) Safety factor

S.F =  1 / (mean load / load design ) = 1 / ( 1200 / 1000 ) = 0.83

ii) Standard deviation

1.9 X 10^-3 = e  ( -1/2 ( μ / б) ^3  /  (2.5 * 6  )

0.004756 = e^- 20000 / б^3

hence std = 10 psi

iii) Variance

= \(\sqrt{10}\) = 3.16 psi

iv) coefficient of variation

Cv = std / mean resistance

    = 10 / 1200 = 0.0083

A pediatrician would use an ophthalmoscope for viewing the interior of the eyes.

Ophthalmoscope is an instrument used by pediatricians and other physicians to examine the interior of the eye.

The ophthalmoscope, an important diagnostic tool in ophthalmology, enables doctors to view the retina, optic disc, macula, and other parts of the eye in detail.

The ophthalmoscope is designed to allow physicians to view the interior of the eye through the pupil. With the help of an ophthalmoscope, doctors can diagnose and monitor a variety of eye disorders, such as glaucoma, cataracts, and macular degeneration.

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A pediatrician is a doctor who specializes in treating babies, toddlers, and children up to the age of 18. Pediatricians are well-equipped to diagnose, treat, and illnesses. Because they deal with such young patients, pediatricians must have access to a variety of specialized medical instruments,

One such instrument is an ophthalmoscope. An ophthalmoscope is a handheld instrument that is used to view the interior of the eye. It allows doctors to examine the retina, optic disc, and other structures of the eye to identify any signs of damage or disease.
Pediatricians might use an ophthalmoscope to diagnose a variety of eye conditions in children. For example, they might use it to look for signs of strabismus (a misalignment of the eyes), cataracts (cloudy areas on the lens of the eye), or glaucoma (increased pressure in the eye that can damage the optic nerve)
In addition to an ophthalmoscope, they might also use other specialized instruments to examine different parts of the eye.

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Answer:

a) The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

b) The change in diameter of the specimen is  - 0.015 mm

Explanation:

Given the data  in the question;

(a) The amount by which this specimen will elongate in the direction of the applied stress.

First we find the area of the cross section of the specimen

A = \(\frac{\pi }{4}\) d²

our given diameter is 20.5 mm so we substitute

A = \(\frac{\pi }{4}\) ( 20.5 mm )²

A = 330.06 mm²

Next, we find the change in length of the specimen using young's modulus formula

E = σ/∈

E = P/A × L/ΔL

ΔL = PL/AE

P is force ( 46300 N), L is length ( 201 mm ), A is area ( 330.06 mm² ) and E is  elastic modulus (60.5 GPa) = 60.5 × 10⁹ N/m² = 60500 N/mm²

so we substitute

ΔL = (46300 N × 201 mm) / ( 330.06 mm² × 60500 N/mm² )

ΔL =  0.466 mm

Therefore, The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

(b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.

Using the following relation for Poisson ratio

μ = -  Δd/d / ΔL/L

given that Poisson's ratio of the metal is 0.33

so we substitute

0.33 = -  Δd/20.5 / 0.466/201

0.33 = -  Δd201 / 20.5 × 0.466

0.33 = - Δd201  / 9.143

0.33 × 9.143 =  - Δd201

3.01719 = -Δd201

Δd = 3.01719 / - 201

Δd  = - 0.015 mm

Therefore, The change in diameter of the specimen is  - 0.015 mm

Answer:

shrinkae limit = 20.35%

shrinkage ratio = 1.45

Explanation:

1. to get the shrinkage limit we would first calculate the moisture content w.

w = (37-28)/28

= 9/28

= 0.3214

then the formula for shrinkage limit is

\([w-\frac{(V-Vd}{wd} ]*100\)

w = 0.3214

V = 19.3

Vd = 16

Wd = 28

when we put these values into the formula:

\([0.3214-\frac{(19.3-16)}{28} ]*100\\\)

= 20.35%

2. the shrinkage limit = Wd/V

= 28/19.3

= 1.45

Fuel lines are normally made of double wall steel tubing. For fire safety, a fuel line must be able to withstand the constant and severe vibration produced by the engine and road surface. Lines are placed away from exhaust pipes , mufflers, and manifolds, so that excessive heat will not cause vapor lock.

Answer:

eoidnfoejsdncodsnc

Explanation:

dfdjsncojnsdjcnsdojnvjsdvkjsdkjvnsdjvnskjnvkjdvkjnsdcjndkjndskjndskjndskjnsdvkjnvsdkjvsdkjnvskdjnvkjdsvkjsdnvkjsdnkjsvnkj

The equilibrium, the pressure of SO₃ is equal to the square root of Kp times 6

You should understand that equilibrium pressure is the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases at a given temperature in a closed system.

It relates to the balance of particles escaping from the liquid or solid in equilibrium with those in a coexisting vapor phase.

A substance with a high vapor pressure at normal temperatures is often referred to as volatile

The gas phase reaction

SO₂(g) + O₂(g) ↔ 2SO₃(g), can be calculated if we know the equilibrium.

⇒Kp = P(SO₃)² / P(SO₂) x P(O₂)

Where P(SO₃), P(SO₂) and P(O₂) are the partial pressures of the respective gases at equilibrium.

Kp = P(SO₃)² / P(SO₂) x P(O₂)

Kp = (P)² / (2P) x (3P)

Kp = P² / 6

P = √(Kp x 6)

In conclusion,  the pressure of SO₃ will be equal to the square root of Kp times 6,  at equilibrium where Kp is the equilibrium constant for the reaction.

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The expression for the equilibrium constant (Kc) of the given reaction is, Kc = SO3²2/([SO2]²[O2])

At equilibrium, let the concentration of SO2 be ‘x.’ Thus, the equilibrium concentration of SO3 is ‘2x’ and that of O2 is also ‘x.’ Hence, substituting these values in the above expression, we get:

Kc = (2x)^2/[(x)^2(x)] = 4x^2/x^3 = 4/x.

We know that Kc = (P(SO3))^2/(P(SO2))^2(P(O2)). Here, the reaction is a gas-phase reaction at equilibrium. Hence, we can assume that the initial pressure of SO2, O2, and SO3 is ‘P atm.’ Thus, the equilibrium pressure of SO2 is ‘(1-x)P’ and that of O2 is also ‘(1-x)P.’ The equilibrium pressure of SO3 is ‘(2x)P.’

Substituting these values in the above expression, we get:

Kc = [(2xP)^2]/[(1-x)^2P^2.(1-x)P] = 4x^2P/(1-x)^2P^3 = 4x^2/(1-x)^2P^2

Given that the free energy of the reaction at 775 K is -2.8626 x 104 J.

ΔG° = - RTln(Kc)

-2.8626 x 10^4 = - (8.314 x 775)ln(4/x^2)/ln(1-x)^2P^2

Solving the above expression, we get the value of ‘x’ as 0.189.

Hence, the equilibrium pressure of SO2 is (1-x)P = (1-0.189)P = 0.811P.

Therefore, the equilibrium pressure required for 90% conversion of SO2

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The pressure needed at point (1) to produce the flow where water "bubbles up above the exit of the vertical pipe attached to three horizontal pipe segments is 0.750 psi.

The Bernoulli's equation for incompressible fluid can be given as,

\(P_1+\dfrac{1}{2}\rho v_1^2+\rho gh_1=P_2+\dfrac{1}{2}\rho v_2^2+\rho gh_2\)

Here, ρ is density of fluid, g is acceleration due to gravity, (P) is the pressure v is velocity, h is height of elevation and subscript (1 and 2) is used for point 1 and 2.

Water "bubbles up" h2 = 9 in.  Above the exit of the vertical pipe attached to three horizontal pipe segments.

The total length of the 1.75-in.- diameter galvanized iron pipe between point (1) and the exit is 21 inches. h3 = 18 in.

Reynolds number is,

\(R_e=\dfrac{V_3D}{v}\\R_e=\dfrac{4.01\dfrac{0.75}{12}}{1.21\times10^{-15}}\\R_e=2.07\times10^4\)

The formula for the ratio of pressure to radius, when pressure and velocity at point 2 is zero can be given as,

\(\dfrac{p_1}{r}=z_2\left(f\dfrac{l}{d}+\sum k_L\right)\dfrac{v^2}{2g}-\dfrac{v_1^2}{2g}\)

Here, f=0.039 and ∑K(L)=4.5. Put the values,

\(\dfrac{p_1}{r}=\dfrac{7}{12}\left(0.03\dfrac{21}{0.75}+4.5-1\right)\dfrac{4.01^2}{2\times32.2}\\\dfrac{p_1}{r}=1.73\rm\; ft\)

Put the value of r we get,

\(p_1=62.4\times1.73\\p_1=108\rm\; ib/ft^2\\p_1=0.750\rm\; psi\)

The pressure needed at point (1) to produce the flow where water "bubbles up above the exit of the vertical pipe attached to three horizontal pipe segments is 0.750 psi.

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Complete Question

Nitrogen (N2) flows through a pipe, entering at at 4 m/sec at 1000 kPa, 2270C. For a pipe inside diameter of 3 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas Then using your ideal gas mass flow rate find the rate at which enthalpy enters the pipe (kJ/sec) NO Cp, Cv, k permitted

Answer:

\(H=9.91kJ/sec\)

Explanation:

From the question we are told that:

Velocity \(v=4 m/sec\)

Pressure \(P=1000kPa\)

Temperature \(T=227 \textdegree C\)

Diameter \(d=3cm=>0.03m\)

Generally the equation for volumetric Flow Rate is mathematically given by

\(V_r=(\frac{\pi*d^2}{4}v)\)

\(V_r=(\frac{\pi*(0.03)^2}{4} *4)\)

\(V_r=0.002827m^3/s\)

Generally the equation for mass Flow Rate is mathematically given by

\(m_r=\frac{PV_r}{RT}\)

\(m_r=\frac{1000*0.002827}{0.297*(227+273)}\)

\(m_r=0.019kg/sec\)

Generally the equation for mass Flow Rate is mathematically given by

Using gas Table for enthalpy Value

\(T=500K=>h=520.75kg\)

Therefore

\(H=mh\)

\(H=0.019*520.75\)

\(H=9.91kJ/sec\)

Answer:

The answer is C

Explanation:

Once you have chosen a topic, the next thing you should do before beginning the research process is: C. discuss your idea with others.

A research topic refers to an event, issue, or subject that a researcher is keenly and deeply motivated or interested in, especially when conducting a study or research.

Based on scientific information and records, it is very important you discuss your idea with others once you have chosen a topic, before beginning the research process.

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Lean production works best with standardized and repeatable processes. Lean production is a manufacturing technique that frequently aims to cut down on wait times for both suppliers' and customers' .

Lean manufacturing seeks to improve processes so that they use less energy, time, and resources overall. For some businesses than others, lean tools may be a better fit. But among the most helpful lean tools are Kaizen, 5S, Kanban, Value Stream Mapping, and Focus PDCA. Value, the value stream, flow, pull, and perfection are the five cornerstones of lean manufacturing, respectively. These are now the cornerstones on which lean is implemented. 1. Value: Value is established from the viewpoint of the customer and relates to the price point at which they are willing to purchase goods or services. Lean production is a manufacturing strategy that frequently aims to cut down on wait times for both suppliers' and customers' responses as well as those inside the manufacturing machine.

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At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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The example of the active reading strategy known as making mental image is said to be option C. Picturing the Earth over a campfire when you read the term global warming.

Global warming is seen as a kind of a long run heating of Earth's surface and it was one that is known to have been observed as at the time of the pre-industrial period (that is said to be between 1850 and 1900).

Note that it is one that was known to have occurred as a result of  the human activities, such as fossil fuel burning, that is said to be increasing  heat-trapping greenhouse gas levels.

Therefore, The example of the active reading strategy known as making mental image is said to be option C. Picturing the Earth over a campfire when you read the term global warming.

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See full question below

Which of the following is an example of the active reading strategy known as

"making mental images"?

A. Restating, in a few brief sentences, the main points of an article

about how hurricanes form

B. When reading about space science, asking yourself how it is

possible for a satellite to orbit Earth

C. Picturing the Earth over a campfire when you read the term global

warming

D. Rereading an article about telescopes after not understanding the

article the first time you read it