If a negatively charged plastic rod is brought near one end of a neutral copper rod, what happens to that near end?.

An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. Power is the measure of how fast work can be done. The unit of power is watts (W), which can be defined as the amount of work done in one second.

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The barge floats 0.088 meters deeper.

To solve this problem, we need to use Archimedes' principle, which states that the buoyant force on an object in a fluid is equal to the weight of the fluid displaced by the object.

First, let's calculate the volume of the barge:

Volume = length x width x height
Height of the barge is not given, but we know that it floats in fresh water, which has a density of 1000 kg/m³. Therefore, the weight of the water displaced by the barge is equal to its weight (excluding the crate) and we can calculate the height using the formula:

Weight of barge (excluding crate) = weight of water displaced
density of water x volume of water displaced = density of barge x volume of barge

We know that the density of the barge is less than the density of water, otherwise it would sink. Let's assume that the barge is made of wood, which has a density of about 500 kg/m³. Then we can calculate the volume of water displaced by the barge:

Volume of water displaced = weight of barge (excluding crate) / density of water
Volume of water displaced = (4.8 m x 2.4 m x h) x 500 kg/m³ / 1000 kg/m³
Volume of water displaced = 5.76 h m³

where h is the height of the barge in meters.

Now let's add the weight of the crate to the barge. The total weight of the barge and the crate is:

Weight of barge and crate = weight of barge (excluding crate) + weight of crate
Weight of barge and crate = density of barge x volume of barge + 450 kg
Weight of barge and crate = 500 kg/m³ x (4.8 m x 2.4 m x h) + 450 kg
Weight of barge and crate = 5760 h + 450 kg

The weight of the water displaced by the barge and the crate is:

Weight of water displaced = density of water x volume of water displaced
Weight of water displaced = 1000 kg/m³ x (4.8 m x 2.4 m x h + V)

where V is the volume of the crate in cubic meters. We don't know the volume of the crate, but we can calculate it using its weight and the density of steel, which is about 7850 kg/m³:

Volume of crate = weight of crate / density of steel
Volume of crate = 450 kg / 7850 kg/m³
Volume of crate = 0.057 m³

Now we can set the buoyant force equal to the weight of the barge and the crate:

Weight of water displaced = Weight of barge and crate
1000 kg/m³ x (4.8 m x 2.4 m x h + 0.057 m³) = 5760 h + 450 kg
11.52 h + 0.057 = 5.76 h + 0.45
5.76 h = 0.507
h = 0.088 m

Therefore, the barge floats 0.088 meters deeper with the crate loaded onto it.

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Answer:

about 4 km

Explanation:

15 minutes is a quarter of an hour, so you divide 16km by 4 to get your answer

The correct order in which the objects reach the bottom of the inclined plane is:

d. Sphere, hoop, disk

When objects roll without slipping, their motion is determined by their rotational inertia, which depends on their mass distribution. The objects' rotational inertia is related to their shape and mass distribution. The solid sphere has the highest rotational inertia among the three objects. It takes more time for the sphere to rotate and roll down the inclined plane, so it reaches the bottom first. The hoop has a lower rotational inertia compared to the sphere but higher than the disk. Therefore, it reaches the bottom after the sphere. The disk has the lowest rotational inertia among the three objects due to its mass distribution. It reaches the bottom last, following the sphere and the hoop. In summary, the correct order is sphere, hoop, and then disk.

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The astronaut's final speed with respect to the shuttle after the tank is thrown would be 2.67 m/s.

Let's first find the initial momentum of the system, which is zero because the astronaut is at rest with respect to the shuttle and the tank is thrown in the opposite direction with a speed of 12 m/s:

p_initial = m_astronaut * v_astronaut_initial + m_tank * v_tank_initial

where m_astronaut = 63 kg is the mass of the astronaut, v_astronaut_initial = 0 m/s is the initial velocity of the astronaut, m_tank = 10 kg is the mass of the oxygen tank, and v_tank_initial = -12 m/s is the initial velocity of the tank (negative because it is thrown in the opposite direction).

p_initial = 63 kg * 0 m/s + 10 kg * (-12 m/s) = -120 kg m/s

After the tank is thrown, the system experiences no external forces, so its total momentum remains constant:

p_final = m_astronaut * v_astronaut_final + m_tank * v_tank_final

Since the tank is thrown away from the astronaut with a certain momentum, the astronaut gains an equal and opposite momentum, so we can write:

p_final = -p_initial

Substituting the values of p_final and p_initial, we get:

m_astronaut * v_astronaut_final + m_tank * v_tank_final = -120 kg m/s

We also know that the tank is thrown away at a certain speed, so we can write:

v_tank_final = -12 m/s

Thus:

m_astronaut * v_astronaut_final + 10 kg * (-12 m/s) = -120 kg m/s

v_astronaut_final = (120 kg m/s - 10 kg * (-12 m/s)) / 63 kg

v_astronaut_final = 2.67 m/s

Therefore, the astronaut's final speed with respect to the shuttle after the tank is thrown is 2.67 m/s.

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Answer:

11900 meters

Explanation:

Use the Potential energy = mgh formula, substituting these in to get 11.1x10^6 = 95 x 9.81 x h.

Rearrange to make h the subject and the answer given is 11900 (3sig.fig.)

The maximum height to which he can climb will be 1.168 x 10⁴ meters.

The potential energy of a body is the energy of the body due it position. The potential energy always exist for two bodies which are in mutual interaction with each other for example by a force. For body a on earth, the potential energy of the body - earth system is -

E[P] = mgh

Given is a mountain climber that has a mass of 95 kg.

We can write -

Mass of climber = [M] = 95 kg

Energy gained by eating the chocolate = [E] = 11.1 MJ = 1.11 x 10⁷ joules

Assume that the height achieved achieve by the climber is [h] meters

Therefore, the potential energy gained at that height will be equal to 11 MJ

Therefore -

mgh = 1.11 x 10⁷

95 x 10 x h = 1.11 x 10⁷

95 x 10 x h = 1110 x 10⁴

h = (1110 x 10⁴)/950

h = 1.168 x 10⁴ meters

Therefore, the maximum height to which he can climb will be 1.168 x 10⁴ meters.

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The collision frequency is k = Ae^(-Ea/RT) in terms of Arrhenius equation. It stands for how frequently reactant molecules successfully collide. It varies in direct proportion to both the frequency and concentration of molecular collisions in the reaction.

The minimal amount of energy that the reactants require to generate a product during a chemical reaction is known as the activation energy and was first used by Arrhenius. All molecules with energies greater than or equal to the activation energy will collide and produce products, according to the Arrhenius Equation.

The rate at which two atomic or molecular species collide in a given volume during a given period of time is known as the collision frequency.

Specifically for gases, the collision hypothesis is used to forecast the rates of chemical methods. The collision theory is predicated on the idea that in order for a reaction to happen, the reactive components (atoms or molecules) must come into contact with one another or collide.

k = Ae^(-Ea/RT)

Where:

k = rate constant of the reaction,

A = pre-exponential factor

e = base of the natural logarithm,

Ea = activation energy of the reaction,

R = gas constant, and

T = temperature in Kelvin

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Answer:

true

Explanation:

A fluid's specific gravity is determined by comparing its density to the density of a standard reference fluid, often water.

13,580,1000 ≈ 13.6

Mercury is a highly heavy, dense metal that is silver-white and liquid at normal temperature. Because water has a density of 1.0 g/mL, and mercury has a density of 13.5 g/mL, it feels quite weighty for such a small amount of mercury.

Mercury also has a very high surface tension, which causes tiny mercury droplets to condense on glass to create virtually spherical beads. Liquid mercury can be used in thermometers like the lab thermometer below because it expands and shrinks predictably with temperature. However, due to the element's health risks, the usage of mercury thermometers has generally been discontinued.

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While the element Krypton was indeed named after the Greek word "kryptos," meaning "hidden" or "secret," the reason for its name is not related to its properties as a secret element.

Krypton was discovered in 1898 by British chemists Sir William Ramsay and Morris Travers. They had been studying the gas that was produced when they evaporated liquid air, and they found that this gas contained a previously unknown element. Ramsay named the element Krypton because of its ability to hide within the other gases in the air, making it difficult to detect.

So, while the name Krypton does have a connection to the idea of secrecy, it is not because the element itself has any particular properties that relate to secrecy. Rather, it was named for its elusive nature and the difficulty in detecting it.

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One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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Answer:

Explanation:

given :-

force applied = 117.6N

Area = 20 m^2

Pressure =?

solution:-

Pressure = Force / Area

= 117.6 N / 20 m^2

= 5.88 Pascals

Hope it helps :D!

Explanation:

1. Five major external forces that affect organizations are economic, social, cultural, demographic, and technological. Economic factors such as inflation and interest rates can impact a company's profitability and purchasing power. Social factors like changing consumer preferences and lifestyles can influence demand for products and services.

Cultural factors like values and beliefs can shape consumer behavior and market trends. Demographic factors such as population size and age distribution can affect target markets.

Technological factors like advancements in automation or digitalization can disrupt industries and create new opportunities. These external forces shape the business environment and organizations must monitor and adapt to them to stay competitive.

2. Gathering competitive intelligence is crucial for businesses because it provides valuable insights about their competitors' strategies, strengths, weaknesses, and market position.

By understanding the competitive landscape, businesses can identify opportunities and threats, make informed decisions, and develop effective strategies.

Competitive intelligence helps businesses stay ahead of their competitors, anticipate market trends, identify emerging technologies, and improve their own products or services. It allows businesses to benchmark their performance, evaluate their competitive advantage, and identify areas for improvement.

Ultimately, gathering competitive intelligence empowers businesses to make proactive and strategic decisions that can lead to sustainable growth and competitive advantage.

3. In business, various economic variables need to be monitored as they have significant impacts on strategy applications. Some important economic variables include GDP (Gross Domestic Product), inflation rate, exchange rates, interest rates, consumer spending, unemployment rate, and industry-specific factors like raw material prices or energy costs.

Monitoring these variables helps businesses understand the overall economic conditions, identify market opportunities, and assess potential risks. For example, a high inflation rate may impact pricing strategies, while a favorable exchange rate can benefit export-oriented businesses.

By monitoring economic variables, businesses can adapt their strategies accordingly and make informed decisions to navigate the dynamic business environment.

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Answer:

30 m

Explanation:

Potential energy = kinetic energy + rotational energy

PE = KE + RE

mgh = ½ mv² + ½ Iω²

For a disk, I = ½ mr².  For rolling without slipping, ω = v/r.

mgh = ½ mv² + ½ (½ mr²) (v/r)²

mgh = ½ mv² + ¼ m v²

mgh = ¾ m v²

gh = ¾ v²

h = 3v² / (4g)

h = 3 (20 m/s)² / (4 × 10 m/s²)

h = 30 m

(c) Total internal reflection occurs

when the incident angle is greater than the critical angle.

The mass of the second box car from the calculation is  22317 Kg.

We have to note that we can be able to obtain the momentum as the product of the mass and the velocity of the object that is to be studied. In the case of the cars that we have here;

The momentum before Collison = Momentum after collision

We would then have from the question;

(10300 * 19) + (M * 0) = (10300 + M) * 6

Let the mass of the second box car be M

Then;

195700 = 61800 + 6M

M = 22317 Kg

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Object distance = 26.86 cm

Given:

Image distance, v = -47.0 cm

Magnification, M = 1.75

Object distance, u = ?

Object distance = 26.86 cm

Answer:

Eastward, at 11 m/s^2

Explanation:

64N-31N=unbalanced force of 33N

F=ma

33N=(3kg)a

a=11m/s^2 to the East

Answer:

i think it is B

Explanation:

If you measure the average brightness and pulsation period of a cepheid variable star, you can also determine its distance.

Cepheid variable stars belong to a class of stars that have a distinct relationship between variation period and luminosity.

Their period of cycle and luminosity are closely related to each other and they differ in temperature and diameter.

As their brightness increases and decreases, therefore, it helps out in the measurement of intergalactic and interstellar distances.

The changes in amplitude of their motion and cycle period have a definite impact on their brightness which enables us to determine their distance.

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Answer:

El equilibrio térmico se alcanzará a los 152ºC.

Explanation:

Dado que un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º, para determinar a qué temperatura se alcanza el equilibrio térmico se debe realizar el siguiente cálculo:

2+5 = 7

(200 x 5 + 32 x 2) / 7 = X

1064 / 7 = X

152 = X

Por lo tanto, el equilibrio térmico se alcanzará a los 152ºC.

Answer:

Elements are arranged in the table by increasing atomic number.

Explanation:

In the modern periodic table, each element is represented by its chemical symbol. The number above each symbol is its atomic number.

Answer: the scientist measure the eagle's instantaneous speed

Explanation:

80 km/hr was the eagle's instantaneous speed, measured in an instant by the scientist.  50 km/hr is the eagle's average speed, measured over a certain period of time.  The eagle's speed was less than 50 km/hr at times and greater than 50 km/hr at times, during the elapsed time period of measurement

(a) At perigee relative to the perifocal reference frame, the spacecraft's position vector r is approximately 3,421.32 km and its velocity vector v is approximately 10,946.04 m/s. (b) At perigee relative to the geocentric equatorial frame is 7,405.01 km and its velocity vector v is approximately 10,332.70 m/s.

A-To calculate the position vector r and velocity vector v at perigee, we need to convert the given orbital parameters to Cartesian coordinates in both the perifocal and geocentric equatorial frames.

Perifocal reference frame:

Given:

e = 1.5

Perigee altitude = 300 km

Position vector r: r = [rp, 0, 0] = [300 km, 0, 0]

Semi-major axis: a = rp / (1 - e) = 300 km / (1 - 1.5) = -600 km

Gravitational parameter of Earth: μ = 3.986 × 10⁵ km³/s²

Velocity vector v: v = (μ * (2/r - 1/a))

v =(3.986 × 10⁵ km³/s² * (2 / 300 km - 1 / -600 km))

v ≈ 10,946.04 m/s

(b) To convert to the geocentric equatorial frame, we need to perform a series of rotations on the position and velocity vectors based on the inclination i, right ascension of the ascending node Ω, and argument of periapsis ω.

First, we rotate the position vector r by Ω around the z-axis. Then, we rotate the resulting vector by i around the x-axis. Finally, we rotate the resulting vector by ω around the z-axis

Geocentric equatorial frame:

Given:

i = 35°

Ω = 130°

ω = 115°

Position vector r: r = [rp, 0, 0] = [300 km, 0, 0]

Rotate by Ω around the z-axis:

r = r * Rz(Ω)

r = r * Rz(130°)

Rotate by i around the x-axis:

r = r * Rx(i)

r = r * Rx(35°)

Rotate by ω around the z-axis:

r = r * Rz(ω)

r = r * Rz(115°)

The resulting position vector r in the geocentric equatorial frame is approximately [7,405.01 km, 0, 0].

Velocity vector v: v = [10,946.04 m/s, 0, 0]

Rotate by Ω around the z-axis:

v = v * Rz(Ω)

v = v * Rz(130°)

Rotate by i around the x-axis:

v = v * Rx(i)

v = v * Rx(35°)

Rotate by ω around the z-axis:

v = v * Rz(ω)

v = v * Rz(115°)

The resulting velocity vector v in the geocentric equatorial frame is approximately [10,332.70 m/s, 0, 0].

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Answer:

V = X i + Y j        expression of vector in terms of unit vectors i andj

V = 12.0 i + 9.00 j

V = (12.0^2 + 9.00^2)^1/2 = 15.0      magnitude of resultant vector

Note this is a multiple of a 3, 4, 5 right triangle

5 is the magnitude of a 3, 4, 5 right triangle the given vector is 3X the 3, 4, 5 triangle or 15

Given three identical metallic spherical objects have individual charges of, q1 = -9.612 nC,

q2 = +3.204 nC,

and q3 = +6.408 nC.

If the three objects are brought into contact with each other at the same time and then separated, the final net charge on q1, q2, and q3 will be calculated as follows;

Initial total charge, Q = q1 + q2 + q3

Q= -9.612 nC + 3.204 nC + 6.408 nC

Q= -0.002 nC

The final net charge on q1, q2, and q3 is same as they are identical:

q1 + q2 + q3 = -0.002 nC

q1 = q2 = q3 = -0.002 nC/3

q1 = -0.0006667 nC

Therefore, the final net charge on q1, q2, and q3 is -0.0006667 nC.The charge on q1 before and after is -9.612 nC and -0.0006667 nC respectively. The difference is the number of electrons that were removed from/added to q1. The number of electrons can be calculated as follows;

Charge on an electron,

e = 1.6 ×\(10^{-19\) C

Total number of electrons removed from

q1 = [(final charge on q1) - (initial charge on q1)] / e

q1 = [-0.0006667 - (-9.612)] / 1.6 × \(10^{-19\)

q1 = 6.0075 × 1013

The number of electrons removed from q1 is 6.0075 × 1013, and electrons were removed from q1. Thus, option d is,

"The number of electrons that were removed from q1 = 6.0075 × 1013 electrons were removed from q1."

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Cold and warm fronts are different because the type of front is determined by which air mass is heavier.

A cold front forms when a cold air mass advances towards a warm air mass. It is characterized by the cooler air mass pushing under the warmer air mass. This creates a steep slope, and the air rises rapidly, creating thunderstorms and strong winds.

Warm fronts, on the other hand, occur when a warm air mass advances towards a cold air mass. In this case, the warm air mass gradually rises over the denser, cooler air mass. This creates a long, gradual slope, and the air is less likely to create severe weather, instead causing a gradual change in weather patterns.

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It take more force for something to slide across a surface then it does to change direction on the same surface

What does the word force mean?

The definition of force in physics is: The push or draw on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a trajectory and a magnitude.

Friction is the energy that opposes motion, slowing or stopping it entirely. When two things rub against one another, friction is created. Sliding friction is the resistance that any two things produce when they slide against one another. This friction, also referred to as kinetic friction, is the force required to maintain one surface moving along another.

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