If a PA chest was performed with the center detector selected, the resulting image is likely to be_______.

i don't know.

Explanation:

because i don't want responde

Answer:

I think it's a because it goes thru it and reflects

Answer:

Andrew's dog's speed was 1.89 m/s

Explanation:

Motion at Constant Speed

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

This can be written as the formula below:

\(\displaystyle v=\frac{d}{t}\)

Where  

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

Andrew's dog run a distance of d=17 meters in a time of t=9 seconds, thus its speed was;

\(\displaystyle v=\frac{17}{9}\)

v = 1.89 m/s

Andrew's dog's speed was 1.89 m/s

Answer:

The time it takes the ball to fall 3.8 meters to friend below is approximately 0.88 seconds

Explanation:

The height from which the student tosses the ball to a friend, h = 3.8 meters above the friend

The direction in which the student tosses the ball = The horizontal direction

Given that the ball is tossed in the horizontal direction, and not the vertical direction, the initial vertical component of the velocity of the ball = 0

The equation of the vertical motion of the ball can therefore, be represented by the free fall equation as follows;

h = 1/2 × g × t²

Where;

g = The acceleration due gravity of the ball = 9.81 m/s²

t = The time of motion to cover height, h

Then height is already given as h = 3.8 m

Substituting gives;

3.8 = 1/2 × 9.81 × t²

t² = 3.8/(1/2 × 9.81) ≈ 0.775 s²

∴ t = √0.775 ≈ 0.88 seconds

The time it takes the ball to fall 3.8 meters to friend below is t ≈ 0.88 seconds.

Answer: 2 m/s to the right

Explanation:

This is a conservation of momentum question:

p before = p after → m1v1 + m2v2 = m3v3 + m4v4

**Note- if the speed is to the left, plug in a negative v!

5(2) + 3(-3) = 5(-1) + 3(v4) → 1 = -5 + 3v4 → v4 = +2 m/s :)

Answer:

ikr same.....lol......

Answer:

Answer choice B!

Explanation:

Study Island work

Answer:A

I DID THIS ON STUDYILSLAND

Answer:

Ted is correct

Explanation:

The equation for gravitational potential energy is PE = m·g·h

The equation for gravitational kinetic energy is KE = 1/2·m·v²

Where:

m = Mass of the object (The racing car)

g = Acceleration due to gravity

h = The height to which the object is raised

v = Velocity of motion of the object

From the principle of conservation of energy, energy can neither be created nor destroyed but changes from one form to another, we have;

Potential energy gained from location at height h = Kinetic energy gained as the object moves down the level ground

m·g·h = 1/2·m·v² canceling like terms gives

g·h = 1/2·v²

v = (√2·g·h)

If the speed is doubled, we have

2·v = 2× (√2·g·h) =  (√2·g·4·h)

Therefore, if 2·v = v₂ then v₂ =  (√2·g·4·h)

Since g, the acceleration due to gravity, is constant, it means that the initial  height must be multiplied or increased 4 times to get the new height, that is we have;

v₂ =  (√2·g·4·h) = (√2·g·h₂)

Where:

4·h = h₂

Which gives;

v₂² = 2·g·h₂

1/2·v₂² = g·h₂

1/2·m·v₂² = m·g·h₂ Just like in the first relation

Therefore, Ted is correct s they need to go up four times the initial height to double the speed.

The refractive index is  1.620.

To find the refractive index of the material, we will use Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the materials. The equation for Snell's Law is:

n1 * sin(θ1) = n2 * sin(θ2)

Here, n1 and n2 are the refractive indices of the material and air respectively, and θ1 and θ2 are the angles of incidence ( angle made with normal)and refraction.

Given the information in the question:
- Angle of incidence (θ1) = 16°
- Angle of refraction (θ2) = 26°
- Refractive index of air (n2) = 1 (since air has a refractive index very close to 1)

Now, we can plug these values into Snell's Law to find the refractive index of the material (n1):

n1 * sin(16°) = 1 * sin(26°)

To solve for n1, divide both sides by sin(16°):

n1 = sin(26°) / sin(16°)

Now, calculate the values:

n1 ≈ 1.620

Therefore, the refractive index of the material is approximately 1.620.

To learn more about "refractive index", visit: https://brainly.com/question/83184

#SPJ11

Answer:

186 N

ExplanatioN

Weight is essentially just a measurement of the force of gravity, so you can use this equation.

F = mg

Force = Mass × Acceleration due to Gravity

F = 19kg × 9.8m/s^2. (Acceleration due to Gravity on Earth.)

F = 186.02N

Answer:

13.6 cm

Explanation:

From Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.

Given n₂ = 4/3:

1 = 4/3 sin θ

sin θ = 3/4

If x is the radius of the circle, then sin θ is:

sin θ = x / √(x² + 12²)

sin θ = x / √(x² + 144)

Substituting:

3/4 = x / √(x² + 144)

9/16 = x² / (x² + 144)

9/16 x² + 81 = x²

81 = 7/16 x²

x ≈ 13.6

Answer:

a

Yes it clears

b

 \(b= 0.19 \ m\)

c

 No it does not clear

d

\(z= 0.86 \ m\)

Explanation:

From the question we are told that

  The speed at which the player serves the ball is \(v = 23.6 \ m/s\)

  The height of the ball above the ground is  \(h = 2.3 7 \ m\)

  The distance of the net is  \(d = 12 \ m\)

   The height of the net is \(H = 0.9 \ m\)

Generally the time taken for the ball to reach the net is mathematically represented as

     \(t = \frac{d}{v}\)

=>  \(t = \frac{12}{23.6}\)

=>  \(t = 0.508 \ s\)

Generally the change in height of the ball after t is mathematically represented as

     \(\Delta h = ut + \frac{1}{2} gt^2\)

Here u is the initial velocity which is zero given that the ball was at rest initially

So

     \(\Delta h = 0* t + \frac{1}{2} * 9.8 * 0.50 8^2\)

=>  \(\Delta h =1.28 \ m\)

Generally the new height of the ball is mathematically evaluated as

      \(s= h-\Delta h\)

=>   \(s = 2.37 - 1.28\)

=>   \(s = 1.09 \ m\)

From the value obtained we see that \(s > H\) hence the ball clears the net

Generally the distance between the center of the ball and the top of the net is mathematically represented as

      \(b = s - H\)

=>   \(b = 1.09 - 0.90\)

=>   \(b= 0.19 \ m\)

Given that the ball makes an angle of \(5^o\) with the horizontal  , the velocity along the x-axis is  

      \(v_x = v cos(5)\)

=>   \(v_x = 23.6 cos(5)\)

=>   \(v_x = 23.5 \ m/s\)

The velocity along the y-axis is  

      \(v_y = v sin(5)\)

=>   \(v_y = 23.6 sin(5)\)

=>   \(v_y = 2.06 \ m/s\)      

Generally the time taken for the ball to reach the net is

      \(t = \frac{d}{v_x}\)

=>   \(t = \frac{12}{23.5}\)

=>   \(t =0.508 \ s\)

Generally the change in height of the ball after t seconds is  

     \(c = v_yt + \frac{1}{2}gt^2\)

=>  \(c = 2.06 * 0.508 + \frac{1}{2}* 9.8 * 0.508 ^2\)

=>  \(c = 2.33\)

Generally the new height of the ball after time t seconds is  

     \(e = h - c\)

=>   \(e = 2.37 - 2.33\)

=>   \(e = 0.04 \ m\)

From the value obtained we see that \(e < H\) hence the ball does not clear the net

Generally the distance between the center of the ball and the top of the net is mathematically represented as

      \(z = H-e\)

=>   \(z = 0.90 - 0.04\)

=>   \(z= 0.86 \ m\)

(a) Yes, the ball clears the net.

(b) The distance between the center of the ball and the top of the net is 0.203 m.

(c) No, the ball does not clear the net.

(d) Now, the distance between the center of the ball and the top of the net is -0.85 m.

When any object or body is launched with some initial velocity and making some angle with the horizontal, the body travels in a parabolic path. It is known as the projectile motion.

Given,

The horizontal distance traveled by the ball is 12 m.

The height of the top of the net is 0.90 m.

The height of the horizontal launch of the ball is 2.37 m.

The time for the horizontal motion of the projectile that is the ball is,

\(\begin{aligned} {{v}_{0x}}&={{S}_{x}}t \\ t&=\dfrac{{{S}_{x}}}{{{v}_{0x}}} \\ &=\dfrac{{{S}_{x}}}{{{v}_{0}}\cos 0{}^\circ } \\ &=\dfrac{{{S}_{x}}}{{{v}_{0}}} \end{aligned}\)

The equation for the vertical motion of the projectile can be solved by substituting the above result.

\(\begin{aligned} y&={{y}_{0}}+{{v}_{0y}}t-\frac{1}{2}g{{t}^{2}} \\ y&={{y}_{0}}+\left( {{v}_{0}}\sin 0{}^\circ \right)\left( \frac{{{S}_{x}}}{{{v}_{0x}}} \right)-\frac{1}{2}g{{\left( \frac{{{S}_{x}}}{{{v}_{0x}}} \right)}^{2}} \\ \left( 0.90\text{ m}+h \right)&=\left( 2.37\text{ m} \right)+0-\frac{1}{2}\left( 9.8\text{ m/}{{\text{s}}^{2}} \right){{\left( \frac{12\text{ m}}{23.6\text{ m/s}} \right)}^{2}} \\ h&=2.37\text{ m}-\text{1}\text{.267 m}-0.90\text{ m} \\ &=0.203\text{ m} \end{aligned}\)

Now, consider the case when the ball is thrown with an angle \(\bold{5^{\circ}}\) with the horizontal.

The horizontal component of the initial velocity is \(\bold{v_0 \cos 5{}^\circ.}\)

The vertical component of the initial velocity is \(\bold{v_0 \sin 5{}^\circ.}\)

For the horizontal distance traveled by the ball in this case, the time taken can be calculated as below,

\(\begin{aligned} {t}'&=\frac{{{{{S}'}}_{x}}}{{{{{v}'}}_{0x}}} \\ &=\frac{12\text{ m}}{\left( 23.6\text{ m/s} \right)\cos 5{}^\circ } \\ &=0.51\text{ s} \end{aligned}\)

Now, the vertical distance above the ground, y’, traveled by the projectile till reaching the net can be determined as,

\(\begin{aligned} {y}'&={{{{y}'}}_{0}}+{{{{v}'}}_{0y}}{t}'-\frac{1}{2}g{{{{t}'}}^{2}} \\ &=0\text{ m}-\left( \left( 23.6\text{ m/s} \right)\sin 5{}^\circ \right)\left( 0.51\text{ s} \right)-\frac{1}{2}\left( 9.8\text{ m/}{{\text{s}}^{2}} \right){{\left( 0.51\text{ s} \right)}^{2}} \\ &=-1.05\text{ m}-1.28\text{ m} \\ &=-2.32\text{ m} \end{aligned}\)

The height above the top of the net can be determined by adding the above result with (2.37 m - 0.90 m) which is the height of the net’s top relative to the launch position.

\(\begin{aligned} {h}'&=\left( 2.37\text{ m}-0.90\text{ m} \right)+{y}' \\ &=\left( 2.37\text{ m}-0.90\text{ m} \right)-2.32\text{ m} \\ &=-0.85\text{ m} \end{aligned}\)

Thus, the distance between the center of the ball and the top of the net is -2,32 m.

When the ball leaves the racquet at 5.00° below the horizontal, the distance between the center of the ball and the top of the net is -0.85 m.

Learn more about projectile motion here:

https://brainly.com/question/11049671

Minimum 14 times in a year is the time in which a full moon is observed from earth’s surface.

The Moon is not like Earth. It does not have oceans, lakes, rivers, or streams. It does not have wind-blown ice fields at its poles. Roses and morning glories do not sprout from its charcoal gray, dusty surface. Redwoods do not tower above its cratered ground.

Dinosaur foot prints cannot be found. Paramecium never conjugated, amoeba never split, and dogs never barked. The wind never blew. People never lived there—but they have wondered about it for centuries, and a few lucky ones have even visited it.

The lunar surface is charcoal gray and sandy, with a sizable supply of fine sediment. Meteorite impacts over billions of years have ground up the formerly fresh surfaces into powder. Because the Moon has virtually no atmosphere.

To know more about earth's surface here

https://brainly.com/question/17853655

#SPJ4

An electron in an old-fashioned TV camera tube is moving at 9.10 x 106 m/s in a magnetic field of strength 75.0 mT.the value of the expression is approximately \(1.104 * 10^-11\)Newtons.  the minimum magnitude of the force is zero

To find the maximum and minimum magnitudes of the force acting on the electron due to the magnetic field, we can use the formula for the magnetic force on a moving charge:

F = q * v * B * sin(θ)

Where:

F is the force on the electron,

q is the charge of the electron (\(1.6 * 10^{-19}\)C),

v is the velocity of the electron (9.10 x \(10^6\) m/s),

B is the magnetic field strength (75.0 mT or 75.0 x \(10^-3\) T),

θ is the angle between the velocity and the magnetic field.

(a) To find the maximum magnitude of the force, we assume that the angle between the velocity and the magnetic field is 90 degrees, giving us the maximum value for the sine function. Therefore:

F_max = q * v * B

Substituting the given values, we have:

F_max = \((1.6 * 10^-{19} C) * (9.10 * 10^6 m/s) * (75.0 * 10^-3 T)\)

Therefore, the value of the expression is approximately \(1.104 * 10^-11\)Newtons.

(b) To find the minimum magnitude of the force, we assume that the angle between the velocity and the magnetic field is 0 degrees, resulting in the minimum value for the sine function. Therefore, the force is zero.

F_min = 0

(c) To find the angle between the electron's velocity and the magnetic field when it has an acceleration of magnitude 5.60 x 10^14 m/s^2, we can use the formula for the acceleration of a charged particle moving in a magnetic field:

a = (q * B * v * sin(θ)) / m

Where:

a is the acceleration of the electron,

m is the mass of the electron (9.11 x 10^-31 kg).

Rearranging the formula to solve for sin(θ), we get:

sin(θ) = (a * m) / (q * B * v)

Substituting the given values for acceleration, mass, charge, magnetic field strength, and velocity, we can calculate the sine of the angle:

sin(θ) = \((5.60 * 10^14 m/s^2 * 9.11 * 10^-31 kg) / ((1.6 * 10^-19 C) * (75.0 * 10^-3 T) * (9.10 * 10^6 m/s))\)

Learn more about magnetic field here:

https://brainly.com/question/19542022

#SPJ11

The answers to the given questions are as follows:

a) Transmissivity of the aquifer with a thickness of 20 m and hydraulic conductivity of 20 cm/day is 0.1667 m²/day.

b) i) The total daily flow through a confined aquifer with a thickness of 33 m, width of 7 km, distance between observation wells of 1.2 km, and hydraulic conductivity of 1.2 m/day is 5.25 m³/day.

ii) The transmissivity of the aquifer is 39.6 m²/day.

c) The daily flow of water through a confined aquifer with a thickness of 35 m, width of 5 km, the distance between observation wells of 1.5 km, and hydraulic conductivity of 2.5 m/day is 16.67 m³/day

(a) To calculate the transmissivity of the aquifer, we need to convert the hydraulic conductivity from cm/day to m²/day.

Given:

Thickness of the aquifer (h) = 20 m

Hydraulic conductivity (K) = 20 cm/day

Transmissivity (T) is calculated as:

T = K × h

Converting hydraulic conductivity to m/day:

K = 20 cm/day × (1 m/100 cm) × (1 day/24 hours)

   = 0.008333 m/day

Substituting the values:

T = 0.008333 m/day × 20 m

  = 0.1667 m²/day

Therefore, the transmissivity of the aquifer is 0.1667 m²/day.

(b) Thickness of the confined aquifer (h) = 33 m

Width of the aquifer (L) = 7 km = 7000 m

Distance between the observation wells (d) = 1.2 km = 1200 m

Head in Well 1 (h1) = 97.5 m

Head in Well 2 (h2) = 89.0 m

Hydraulic conductivity (K) = 1.2 m/day

i. To calculate the total daily flow through the aquifer, we can use Darcy's Law:

Q = K × L × (h1 - h2) / d

Substituting the given values:

Q = 1.2 m/day × 7000 m × (97.5 m - 89.0 m) / 1200 m

Q = 5.25 m³/day

ii. The transmissivity (T) of the aquifer is calculated as:

T = K × h

Substituting the given values:

T = 1.2 m/day × 33 m

  = 39.6 m²/day

(c) Thickness of the confined aquifer (h) = 35 m

Width of the aquifer (L) = 5 km = 5000 m

Distance between the observation wells (d) = 1.5 km = 1500 m

Head in Well 1 (h1) = 100 m

Head in Well 2 (h2) = 85 m

Hydraulic conductivity (K) = 2.5 m/day

To calculate the daily flow of water through the aquifer, we can use Darcy's Law:

Q = K × L × (h1 - h2) / d

Substituting the given values:

Q = 2.5 m/day × 5000 m × (100 m - 85 m) / 1500 m

Q = 16.67 m³/day

Therefore, the daily flow of water through the aquifer is 16.67 m³/day.

Learn more about Hydraulic Conductivity from the given link:

https://brainly.com/question/31920573

#SPJ11

Answer:

The space around a charge or a pole in which a force is experienced is called a magnetic field. And a cluster of aligned magnetic atoms is a magnetic domain. When the clustered regions are aligned with one another, they form a magnet

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

The internal resistance of a 12V car battery is around 0.01 ohms. The value of internal resistance depends on the battery's state of charge and temperature. When a battery is fully charged, it has a low internal resistance, which can vary between 0.005 and 0.01 ohms.

When the battery is discharged, its internal resistance increases, which can vary between 0.02 and 0.07 ohms. However, it must be noted that this variation is relative, as a 12V car battery has a relatively low internal resistance compared to other types of batteries. Car batteries are used to power a car's starter motor, lights, and other electrical components. Internal resistance is a critical parameter of a car battery, as it determines the battery's ability to deliver high current. The internal resistance of a car battery can vary with the state of charge and temperature. A fully charged battery has a lower internal resistance than a discharged battery. When a battery is discharged, its internal resistance increases, which can lead to voltage drop and other performance issues. A car battery's internal resistance also plays a role in determining its power output. High internal resistance can lead to power loss, which reduces the battery's efficiency. In contrast, a low internal resistance ensures that the battery can deliver high current without significant power loss.

The internal resistance of a 12V car battery is typically around 0.01 ohms. This value can vary with the state of charge and temperature. A fully charged battery has a lower internal resistance than a discharged battery. The internal resistance of a car battery is an essential parameter that determines the battery's power output and efficiency. A low internal resistance ensures that the battery can deliver high current without significant power loss, while high internal resistance can lead to power loss and other performance issues.

To learn more about internal resistance visit:

brainly.com/question/30902589

#SPJ11

Answer:

velocity

Explanation:

plz mark brainliestʕ•ᴥ•ʔ

Answer:

4a. –2.5 m/s²

4b. 375 m

5. 7.5 s

Explanation:

4. The following data were obtained from the question:

Initial velocity (u) = 50 m/s

Final velocity (v) = 25 m/s

Time (t) = 10 s

Acceleration (a) =?

Displacement (s) =?

4a. Determination of the acceleration of the car.

Initial velocity (u) = 50 m/s

Final velocity (v) = 25 m/s

Time (t) = 10 s

Acceleration (a) =?

a = (v – u) /t

a = (25 – 50)/10

a = –2.5 m/s²

The negative sign indicate that the car is decelerating.

4b. Determination of the displacement of the car.

Initial velocity (u) = 50 m/s

Final velocity (v) = 25 m/s

Time (t) = 10 s

Displacement (s) =?

s = (v + u)t / 2

s = (25 + 50) × 10 / 2

s = (75 × 10) / 2

s = 750 / 2

s = 375 m

Thus, the displacement of the car is 375 m

5. The following data were obtained from the question:

Initial velocity (u) = 30 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = – 4m/s²

Time (t) =?

The time taken for the car to stop can be obtained as follow:

v = u + at

0 = 30 + (–4 × t)

O = 30 – 4t

Collect like terms

0 – 30 = –4t

–30 = –4t

Divide both side by –4

t = –30 / –4

t = 7.5 s

Thus, it will take 7.5 s for the car to completely stop.

Answer:

The gram is the basic unit of measurement

Explanation:

You use it to weigh small items such as sugar, flour, coffee, and other items that are similar.

If you want to measure in grams using a scale is the most accurate solution.

(have a nice day!)

The gravitation force with which the earth is being pulled can be determined by applying Newton's law of universal gravitation.

According Newton's law of universal gravitation, the force exerted between two objects in the universe is directly proportional to the product of masses of the two objects and inversely proportional to the square of the distance between the two objects.

Mathematically, the formula for gravitation force is given as;

F = GmM/R²

where;

If the mass of the object is know and the distance between earth  and the object is also known, the force with which the earth is being pulled can be calculated by applying Newton's law of universal gravitation as shown in the above equation.

Thus, the force with which the earth is being pulled can calculated as well.

Learn more about gravitation force here: https://brainly.com/question/27943482

#SPJ1

An isothermal process is carried out at constant temperature. As a result, the internal energy is constant and there has been no change in it at all.

An isothermal process has a constant temperature. As a result, the internal energy is constant and there has been no change in it at all. Since there are no intermolecular forces or particle interactions in an ideal gas by definition, a change in pressure at constant temperature does not affect on the internal energy.

An isothermal process is one in which the pressure, volume, or contents of a system change without the temperature altering.

The rate of heat transfer would be extremely sluggish because the temperature difference would be so small. As a result, the isothermal process is quite slow from a practical standpoint. Practically speaking, this is practically impossible. As a result, the isothermal method is practically impractical.

To know more about heat visit:

https://brainly.com/question/14257578

#SPJ4

H2O2 H2O

H2 + O2 → H2O. Word equation: Hydrogen gas + Oxygen gas → water. Type of Chemical Reaction: For this reaction we have a Combination reaction. Balancing Strategies: For this reaction it is helpful to start by changing the coefficient in front of H2O and so that you have an even number of oxygen atoms.

Answer:

a=f/m

Explanation:

Answer:

2 meter per second

Explanation:

kinetic energy = 1/2 m v^2

20J = 1/2 × 10 × v^2

v^2 = 4

v= 2 m/s