if a subject is moving from right to left in shot one, what is an acceptable camera placement for shot two if the subject is in the same space and moment in time?

Answers

Answer 1

An acceptable camera placement for shot two would be from the left side of the subject.

If a subject is moving from right to left in shot one and the subject is supposed to be in the same space and moment in time in shot two, an acceptable camera placement for shot two would be from the left side of the subject.

This follows the 180-degree rule of continuity editing, which states that the camera should stay on one side of an imaginary line drawn between two characters or subjects so that they always appear in the same orientation as each other. If the camera were to be placed on the right side of the subject in shot two, the subject's orientation would appear to have changed, and this could be disorienting to the viewer.

By maintaining a consistent camera placement relative to the subject's movement, the viewer can more easily follow the action and maintain a sense of spatial continuity.

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Related Questions

Different Betweens in Current Source And Voltage Source.
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Thanks:')​

Answers

Answer:

Voltage and current sources are two different sorts of sources that may be found in an electrical network. A voltage source has an emf forcing function, whereas a current source has a current forcing function.

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A new planet is discovered orbiting a single star. the planet has one moon. according to kepler’s first law, what do scientists know about the orbit of the planet around the star?

Answers

A fresh planet is found to be revolving around a solitary star. The world has a single moon. The star is located at one of the elliptical orbit's foci.

The "giant impact theory" is the accepted explanation for how the moon arose. According to this theory, the moon was created when the earth and another huge object crashed. Along with scientific motivations, political motivations also led to the start of the Moon exploration program. According to this theory, the Moon was created after the Earth collided with a smaller planet that was around Mars' size. The Moon was created when the impact's leftover debris gathered in an orbit around Earth.

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two resistors can be either connected to a battery in series or in parallel. in which case, if either, is the equivalent resistance the smallest?

Answers

In a circuit with two resistors, the equivalent resistance is smallest when the resistors are connected in parallel.

In a parallel circuit, the total resistance is smaller than the smallest individual resistor because the current is divided among the resistors. Each resistor in the circuit has its own current, and the total current is equal to the sum of the individual currents. This means that the total resistance in a parallel circuit is less than the smallest individual resistor, since the current flowing through each resistor adds up to the total current.

In a series circuit, the total resistance is equal to the sum of the individual resistors, so the total resistance is greater than the smallest individual resistor. This is because in a series circuit, the current flows through each resistor one after the other, so the total resistance is the sum of the resistances of each resistor.

Therefore, the equivalent resistance is smallest in a parallel circuit.

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Part A
Determine the bending stress developed at corner A. Take M = 55kN?m .
Part B
Determine the bending stress developed at corner B. Take M = 55kN?m .
Part C
What is the orientation of the neutral axis?

Answers

(a) The bending stress at corner A is 6.67 kPa.

(b) The bending stress at corner B is 2.22 kPa.

(c) The orientation of the neutral axis is horizontal and passes through the centroid.

How to find the bending stress at corner A?

(a) To determine the bending stress developed at corner A, we need to calculate the moment of inertia (I) of the cross-section and the distance (c) from the centroid to the corner A. Then, we can use the formula:

σ = Mc/Ic

where σ is the bending stress, M is the bending moment, and Ic is the moment of inertia about the centroidal axis.

Assuming the cross-section is rectangular, we have:

I = \(bh^3\)/12, where b is the base and h is the height

c = h/2

Substituting these values and M = 55 kN/m, we get:

σ = (55 kN/m)(h/2)/(\(bh^3\)/12) = 6.67 kPa

Therefore, the bending stress developed at corner A is 6.67 kPa.

How to find the bending stress at corner B?

(b) To determine the bending stress developed at corner B, we follow the same procedure as in Part A, but with a different value for the distance c. Assuming the cross-section is rectangular and symmetric, we have:

c = b/2

Substituting this value and M = 55 kN/m, we get:

σ = (55 kN/m)(b/2)/(\(bh^3\)/12) = 2.22 kPa

Therefore, the bending stress developed at corner B is 2.22 kPa.

How to find orientation of the neutral axis?

(c) The neutral axis is the line on which the stress is zero during bending. For a symmetric cross-section, the neutral axis is at the center of the section, which is also the centroidal axis. Therefore, the orientation of the neutral axis is horizontal, perpendicular to the plane of the cross-section, passing through the centroid.

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PLEASE HELP

While moving at a constant speed on a level, snowy surface, a snowmobile rider throws a snowball vertically up-
wards. If the snowmobile continues moving at a constant velocity, the ball returns to the driver. Explain, using one of Newton's Laws of Motion why the ball lands ahead of the driver if the snowmobile stops.

Answers

The ball lands ahead of the driver if the snowmobile stops in obedience to the law of inertia.

According to Newton's first law of motion, an object continues in its state of rest or uniform motion unless it is acted upon by an unbalanced external force. This is also known as the law of inertia.

The law of inertia explains the reluctance of an object to stop when it has started moving and also the reluctance of objects to start moving. The ball lands ahead of the driver if the snowmobile stops in obedience to the law of inertia.

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A boy pulls a sweater off over his head. What force is responsible for his hair being attracted to the sweater?
A. an applied force
B. a friction force
C. an electric force
D. a magnetic force

Answers

Answer:

B. a friction force

Explanation:

(i think)

Answer:

C. an electric force

the sweater and Explanation:

Electrons are rubbing against it and are atrractted

Balancing Chemical Equations:
CaCl2 +
H2O
HCl +
CaO

Answers

water and calcium add and then H2O cancels out HCI+

Please I need help with this ❤️ ?

Please I need help with this ?

Answers

Answer:

Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The

a. l1 =20 A and l2 =24 A
B. l1 = 20A and l2 = 12 A
C. l1 = 26 A and l2 = 12 A
D. l1 = 24 A and l2 = 8 A

a. l1 =20 A and l2 =24 AB. l1 = 20A and l2 = 12 AC. l1 = 26 A and l2 = 12 AD. l1 = 24 A and l2 = 8 A

Answers

Answer:

when u find out pls lmk! i have the same question and I've been stuck for a while lol

the laser in an audio compact disc player uses light with a wavelength of 7.80 x 102 nm. calculate the frequency of this light.

Answers

The required  frequency of this light is 3.8 x 10^16 Hertz.

What is frequency of light?

The wavelength is the distance between two wave peaks, and it will be no different for box. The frequency is the quantity of vibrations that ignore a given spot in one moment, and it is estimated in cycles each second (Hz) (Hertz).

Explain audio compact disc player.

A Cd player is an electronic gadget that plays sound conservative plates, which are a computerized optical circle information capacity design. Cd players were first offered to buyers in 1982. Discs commonly contain accounts of sound material like music or book recordings.

According to question:

We have,

λ = 7.80 x 10^2 nm = 7.8  x 10^-7 m, c = 3 x 10^8 m/s

So, v = f λ

f = v /λ

f = 3 x 10^8 m/s/7.8  x 10^-7 m

7.8  x 10^-7 m = 3.8 x 10^16 Hertz

Thus, required frequency of the light is 3.8 x 10^16 Hertz.

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Low-energy lightbulbs currently cost $3.60, have a life of 9 years, and currently use $2.00 of electricity per year. Conventional lightbulbs are cheaper to buy; they currently cost only $0.60. On the other hand, they last only 1 year and currently use $7.00 of electricity per year. If the real discount rate is 4%, what are the EACs for each lightbulb? Which lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb? a. EAC( Low-energy lightbulb )=2.48 EAC( Conventional lightbulb )=7.62 Low-energy lightbulb is cheaper to operate b. EAC( Low-energy lightbulb )=3.60 EAC( Conventional lightbulb )=0.60 Conventional lightbulb is cheaper to operate c. EAC( Low-energy lightbulb) =2.00 EAC( Conventional lightbulb )=7.33 Low-energy lightbulb is cheaper to operate d. EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate

Answers

EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D

Energy cost calculation

To calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.

The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.

For the low-energy lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)

≈ $18.47

For the conventional lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)

≈ $7.33

Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.

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Can someone please help me. I think it D but I wanna make sure kk and thank you What is the main purpose of an scientific investigation A) to persuade with bias B) to teach an lesson C) to form an opinion D) to test a hypothesis

Answers

Answer: I believe it to be D.

what did edison mean with the claim that there is no similar institution in existence?

Answers

Edison means with the claim that "there is no similar institution in existence" was that he had created the first ever laboratory dedicated to research and invention.

After the successful installation of his first power plants in the starting of 1880s, Edison lived up to his reputation as the "Inventor of the Age." For many years Edison had no single, central laboratory. He researched at his electrical manufacturing shops in Harrison, New Jersey and New York.

When his wife Mary died in 1884 he withdrew somewhat from electric light work. In 1887 he had decided to build a new facility near his house in West Orange, New Jersey, several times bigger than the Menlo Park laboratory had been. The new laboratory equipped with everything Edison had learned about the process of invention.

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a violent, whirling wind that moves across the ground in a narrow path it is a tornado

True of false?

Answers

True! This is true because it’s violent (it can damage buildings, the area it’s around, etc.) it’s wind that whirls in a circle, and it goes around on a path!

Using the graph, describe what is happening between 4 and 6 seconds. The object is moving away from the origin at a constant velocity. The object is not moving. The object is moving toward the origin at a constant velocity. The object is changing velocity.

Answers

The position in the graph between 4 - 6 seconds is the region of constant velocity.

What is constant velocity?

The term constant velocity refers to the period in the graph when the velocity is not changing with time. As such, the graph is shown to be a flat portion at such a point.

Hence, it follows that the position in the graph between 4 - 6 seconds is the region of constant velocity.

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Using the graph, describe what is happening between 4 and 6 seconds. The object is moving away from the

An oil drop (m = 1.6 x 10-16 kg) is suspended between plates separated by 1.8 cm. The voltage
across the plates is 125 V. Is this possible?

Answers

Answer:

E = V / d       125 V / .018 m = 6940 V/m     electric field

F = E Q       force on Q due to E

F = E n e     where n is the number of electrons in Q

m g = E n e

n = m g / E e     where n is the number of electrons e needed to support drop

n = 1.6 * 10E-16 * 9.8 / (6940 * 1.6 * 10E-19)

n = 1.41

Since n needs to be an integral number of charges, the drop would

not be suspended (motionless under these conditions).

5) A merry-go-round is rotating with a constant angular velocity of o = 1.5 rad/s. There is a red line painted across the diameter of the merry-go-round. A beetle is traveling towards the center of the merry- go-round along the red line with a constant speed of 2 m/s relative to the merry-go-round. 10 points total a) Find the velocity of the beetle as measured by someone standing on the ground when the beetle is 0.5 m away from the center of the merry-go-round. 5 points b) Find the acceleration of the beetle as measured by someone standing on the ground when the beetle is 0.5 m away from the center of the merry-go-round. 5 points

Answers

a) Velocity of the beetle as measured by someone standing on the ground when the beetle is 0.5 m away from the center of the merry-go-round is 2.5 m/s.

Using the principle of Galilean transformation to transform the velocity of the beetle from the rotating frame of the merry-go-round to the stationary frame of the ground,

we have

v' = v + rv'

= velocity of beetle as measured by someone standing on the ground v

= velocity of beetle relative to the merry-go-round r

= radius of the merry-go-round

= 0.5 mω = angular velocity of the merry-go-round

= 1.5 rad/sAt

the instant when the beetle is 0.5 m away from the center of the merry-go-round, the velocity of the beetle relative to the merry-go-round is given by v = 2 m/s

Then the velocity of the beetle as measured by someone standing on the ground is v' = v + rω= 2 m/s + (0.5 m) (1.5 rad/s)

= 2 m/s + 0.75 m/s= 2.75 m/s

the velocity of the beetle as measured by someone standing on the ground when the beetle is 0.5 m away from the center of the merry-go-round is 2.75 m/s.

b) Acceleration of the beetle as measured by someone standing on the ground when the beetle is 0.5 m away from the center of the merry-go-round is 4.5 m/s2.

The acceleration of the beetle relative to the merry-go-round is given by a = rω2 = (0.5 m) (1.5 rad/s)2= 1.125 m/s2

Using the principle of Galilean transformation to transform the acceleration of the beetle from the rotating frame of the merry-go-round to the stationary frame of the ground,

we have

a' = a

Then the acceleration of the beetle as measured by someone standing on the ground when the beetle is 0.5 m away from the center of the merry-go-round is a' = 1.125 m/s2

the acceleration of the beetle as measured by someone standing on the ground when the beetle is 0.5 m away from the center of the merry-go-round is 1.125 m/s2.

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the answer will b bc grass hopppers cant swin

Answers

Answer:

ya thats right they cant swim

Explanation:

Luis is nearsighted. To correct his vision, he wears a diverging eyeglass lens with a focal length of -0.50 m. When wearing glasses, Luis looks not at an object but at the virtual Image of the object because that is the point from which diverging rays enter his eye. Suppose Luis, while wearing his glasses, looks at a vertical 14-cm-tall pencil that is 2.0 m in front of his glasses Review | Constants Part B What is the height of the image? Express your answer with the appropriate units.

Answers

Luis is near sighted. To correct his vision, he wears a diverging eyeglass lens with a focal length of -0.50 m. When wearing glasses, Luis looks not at an object but at the virtual Image of the object because that is the point from which diverging rays enter his eye. Suppose Luis, while wearing his glasses, looks at a vertical 14 cm tall pencil that is 2.0 m in front of his glasses. The height of the image is 2.8 cm.

To find the height of the image, we can use the lens formula:

1/f = 1/\(d_o\) + 1/\(d_i\)

where:

f is the focal length of the lens,

\(d_o\) is the object distance (distance between the object and the lens),

and \(d_i\) is the image distance (distance between the image and the lens).

In this case, the focal length of the lens is -0.50 m (negative sign indicates a diverging lens), and the object distance is 2.0 m.

Using the lens formula, we can rearrange it to solve for di:

1/\(d_i\) = 1/f - 1/\(d_o\)

1/\(d_i\) = 1/(-0.50 m) - 1/(2.0 m)

1/\(d_i\) = -2.0 m⁻¹ - 0.50 m⁻¹

1/\(d_i\) = -2.50 m⁻¹

\(d_i\) = 1/(-2.50 m⁻¹)

\(d_i\) = -0.40 m

The image distance is -0.40 m. Since Luis is looking at a virtual image, the height of the image will be negative. To find the height of the image, we can use the magnification formula:

magnification = -\(d_i\)/\(d_o\)

Given that the object height is 14 cm (0.14 m) and the object distance is 2.0 m, we have:

magnification = -(-0.40 m) / (2.0 m)

magnification = 0.40 m / 2.0 m

magnification = 0.20

The magnification is 0.20. The height of the image can be calculated by multiplying the magnification by the object height:

height of the image = magnification * object height

height of the image = 0.20 * 0.14 m

height of the image = 0.028 m

Therefore, the height of the image is 0.028 meters (or 2.8 cm).

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The speed an
object travels in a
specific
DIRECTION
Is this speed velocity or acceleration

Answers

When you know both the speed and direction of an object’s motion, you know the velocity of an object. speed in a given direction is called velocity
hope this helps :)

16. Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10^24 kg, the mass of Jupiter is 1898.6 x 10^24 kg and the closest distance is abou

Answers

The gravitational force of attraction between the Earth and Jupiter is approximately 1.32 x 10²⁸ N.

The gravitational force of attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force (F) is proportional to the product of their masses (m₁ and m₂) and inversely proportional to the square of the distance (r) between their centers. Mathematically, the formula is expressed as:

F = (G * m₁ * m₂) / r²

where G is the gravitational constant.

m₁ = 6 x 10²⁴ kg (mass of Earth)

m₂ = 1898.6 x 10²⁴ kg (mass of Jupiter)

r = 5.88 x 10¹¹ m (distance between Earth and Jupiter)

Plugging in the values into the formula, we have:

F = (6.67 x 10⁻¹¹ N m²/kg²) * (6 x 10²⁴ kg) * (1898.6 x 10²⁴ kg) / (5.88 x 10¹¹ m)²

Calculating the expression, we find:

F ≈ 1.32 x 10²⁸ N

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THE COMPLETE QUESTION IS:

Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10²⁴ kg the mass of Jupiter is 1898.6 x 10²⁴ kg and the closest distance is about 5.88 x 10¹¹

What would happen if you tried using a road bike to ride across a soft surface. explain your answer?

Answers

If you tried using a road bike to ride across a soft surface, such as sand or mud, it would likely be difficult to maneuver and make forward progress. The tires of a road bike are designed for hard surfaces, such as pavement or concrete, and would not be able to provide enough traction on a soft surface. Additionally, the frame of a road bike is typically made from lightweight materials, which would make it difficult to keep on track and push through any obstacles.
Answer:riding a road bike across a soft surface can be challenging and may result in reduced traction, increased resistance, increased wear and tear, and damage to the terrain. For this reason, it is typically best to avoid using a road bike for off-road adventures and to use a bike specifically designed for rough or soft terrain instead.

Explanation:Using a road bike to ride across a soft surface, such as sand or mud, can present several challenges and can result in various outcomes.
1.Reduced Traction
2.Increased Resistance
3. Increased Wear and Tear
4.Damage to the Terrain
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How much heat (btu’s) will be stored in a 100 sq.ft. concrete wall 1 ft. thick, if it is warmed from 65 deg. f to 85 deg. f by exposure to sunlight?

Answers

The amount of heat stored in the wall is 60,000 btu

The amount of heat stored in a 100 sq.ft. concrete wall 1 ft. thick, when it is warmed from 65 deg. f to 85 deg. f by exposure to sunlight can be calculated using the formula:

Q = mcΔT

where Q is the amount of heat, m is the mass of the wall, c is the specific heat capacity of the wall, and ΔT is the change in temperature.

First, we need to calculate the mass of the wall.

The volume of the wall is 100 sq.ft. x 1 ft. = 100 cu.ft.

The density of concrete is 150 lb/cu.ft., so the mass of the wall is 100 cu.ft. x 150 lb/cu.ft. = 15,000 lb.

Next, we need to find the specific heat capacity of concrete. The specific heat capacity of concrete is 0.2 btu/lb-deg. f.

Finally, we need to calculate the change in temperature. The change in temperature is 85 deg. f - 65 deg. f = 20 deg. f.

Now we can plug these values into the formula to find the amount of heat stored in the wall:
Q = mcΔT
Q = (15,000 lb) x (0.2 btu/lb-deg. f) x (20 deg. f)
Q = 60,000 btu

Therefore, the amount of heat stored in the wall is 60,000 btu.

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A car accelerates uniformly from rest and reaches a speed of 21.4 m/s in 5.1 s. The diameter of a tire is 38.2 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping

Answers

To find the number of revolutions the tire makes during this motion, we need to calculate the distance traveled by the tire and divide it by the diameter of the tire.

First, we need to find the distance traveled. This can be calculated using the formula:

distance = (initial velocity + final velocity)/2 * time = (0 + 21.4 m/s)/2 * 5.1s = 110.7m

Next, we need to convert the diameter of the tire from cm to m.

diameter = 38.2 cm / 100 cm/m = 0.382 m

Now we can calculate the number of revolutions by dividing the distance traveled by the diameter of the tire:

revolutions = distance / diameter = 110.7m / 0.382 m = 290.64

Therefore, the tire makes 290.64 revolutions during this motion

Note that it is assuming that the tire is not slipping. When the tire is slipping, this result can be different.

Kirchoff’s laws question
Can someone please explain to me how to do this question. Answer is C. Thank you in advance :)

Kirchoffs laws question Can someone please explain to me how to do this question. Answer is C. Thank

Answers

The current in resistor X is s 2ε/5R.

Option C is correct.

What is Kirchhoff's law?

The Kirchhoff's law states that the amount of current flowing into a node is equal to the sum of currents flowing out of it. It can also be described as  the algebraic sum of all the currents in any given circuit will be equal to zero.

The  four identical resistors of resistance R are connected in a square as shown, the equivalent resistance of the circuit = R/2.

using Ohm's Law, we find the current passing through resistor X

I = V/R

where V =  voltage across the resistor

R = resistance.

Applying the  the voltage divider rule:

V = ε (R/2)/(2R)

V= ε/4

current passing through resistor X  will then be :

I (current )  = ε/4 / R

I (current )= 2ε/5R

The correct answer is  2ε/5R.

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the following figures each show vectors representing the forces exerted on an object that is initially at rest. in which case will the object remain at rest?

Answers

The system of forces that would make the object not to move is shown in  option A.

Why would the object remain at rest?

We know that a force is a vector. A vector is a quantity that does have both magnitude and direction. This implies that we would know the direction in which the vector would move by looking at the direction that is indicated.

A force could have direction because force is a vector quantity. We know that an object is going to remain at rest if the object is acted upon by balanced forces. According to the Newton's first law, the only time that an object would move is if the object has been acted upon by external forces.

We now have to look at the horizontal forces that act on the object. The image that shows horizontal forces of the same magnitude in both directions would not make the object to move.

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the following figures each show vectors representing the forces exerted on an object that is initially

a car can cover distance of n kilometers per day. how many days will it take to cover a route of length m kilometers? the program gets two numbers: n and m.

Answers

If a car can cover n kilometers per day, it will take m/n days to cover a distance of m kilometers. This assumes that the car can cover the distance without any interruptions or delays, and that it maintains a constant speed of n kilometers per day.

The number of days it will take for a car to cover a distance of m kilometers, given that it covers a distance of n kilometers per day, is m/n.

To understand why this is the case, consider that the car covers n kilometers in one day.

Therefore, it will cover 2n kilometers in two days, 3n kilometers in three days, and so on. This means that the car will cover m kilometers in m/n days.

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It is estimated that a driver takes, on average, 1.5 seconds from seeing on obstacle to react by applying the brakes to stop or swerving. How far will a car, moving at 26 miles per hour in a residential neighborhood, travel (in feet) before a driver reacts to an obtacle? (round distance to one decimal place) feet

Answers

Answer
Answer:
The car was 132 feet far before the driver reacts to an obstacle.
Step-by-step explanation:
Given,
The speed of car = 60 miles per hour,
Also, time taken by the car to reacting the
obstacle =1.5 seconds = 3600 = 2100 hours
(1 hour = 3600 seconds )
We know that,
Distance = Speed × Time,
Hence, the distance of car from the obstacle before reacting the obstacle
= 60 × 2100
60
2400
# miles
Since, 1 mile = 5280 feet
= # miles = $280 = 132 feet
Therefore, the car would 132 feet far from the obstacle.

PLEASE HURRY!!!
How much time would it take for the sound of thunder to travel at an average speed of 330 meters per second a distance of 8000

Answers

hi! it’s 24 hours, 14 minutes, 33 seconds.
i hope this is right

NEED HELP ASAP question in picture

NEED HELP ASAP question in picture

Answers

Answer:

B

Explanation:

I don't know how to break it down but I hope this is helpful!

Other Questions
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