If a true bearing of a ship at sea is 227°, what is its direction angle?

A. 43°
B.313°
C. 223°

In order to calculate vox and voy, let's use the velocity vo = 15 m/s and the angle theta = 60°.

Then, using the formulas, we have:

Answer:

Explanation:

ME initial = ME final

PE initial + KE initial = PE final + KE final

There's no kinetic energy the moment Jorge is at the top of the ramp therefore KE initial = 0

PE initial = PE final + KE final

Assuming the bottom of the ramp is h = 0 we can then say PE final = 0

PE initial = KE final

Write the equations out.

mgh = (.5)mv^2

They tell us potential energy is 6000J therefore that portion of the equation is already "solved"

6000 = (.5)mv^2

Plugin the values

6000 = (.5) 70 v^2

Solve for v

6000 = 35v^2

171.43 = v^2

13.1 = v at the bottom of the slope

Solving for KE we get

(.5) m v^2

Plugin the value from the previous problem and solvee!

It is in charge of the variances in sound quality that individuals can detect.

The frequency of a sound wave that determines the pitch of the sound. High-frequency sound waves are thought to have a higher pitch than low-frequency sound waves.

The wavelength, amplitude, frequency, time period, and velocity of sound waves are their five primary characteristics. How far a sound wave will travel before repeating depends on its wavelength. The wavelength itself is a longitudinal wave that demonstrates how the sound wave is compressed and rarefied.

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The correct answer is (A & D).

In the case of total internal reflection: Total internal reflection occurs when the light travels from a denser medium to a rarer medium. And refraction does not occur at the critical angle

Thus the need for total internal reflection when the ray travels from medium B to medium A.

nB > nA

Thus the need for total internal reflection when the ray travels from medium A to medium

B.

nA > nB

Both the conditions can not be satisfied simultaneously so, the initial light travels from medium A to medium B therefore options C and B are incorrect in the given options.

Hence, the correct option is A and D respectively.

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Answer:

Planks?

Explanation:

It's kinda resting

Answer:

weights

walking

stretching

etc.

The time that takes for a small bag of sand to reach the ground after it is released from an ascending hot-air balloon whose upward velocity is 2.25 m/s is 2.94 s.  

We can find the time that takes for the bag to reach the ground with the following equation:

\( y_{f} = y_{i} + v_{i_{y}}t + \frac{1}{2}gt^{2} \)   (1)

Where:            

\( y_{f} \): is the final height = 35.8 m

\( y_{i} \): is the initial height = 0

\( v_{i_{y}} \): is the initial velocity = 2.25 m/s

t: is the time =?

g: is the acceleration due to gravity = 9.81 m/s²

When the bag is released, it will move upward until it reaches a maximum height and then begins to fall. We can find the time that takes for the bag to reach the maximum height as follows:      

\( v_{f} = v_{i} - gt \)  (2)

Where:

\( v_{f} \): is the final velocity = 0 (at the maximum height)

\( v_{i} \): is the initial velocity = 2.25 m/s

The time is:        

\( t = -\frac{v_{f} - v_{i}}{g} = \frac{2.25 m/s}{9.81 m/s^{2}} = 0.23 s \)

This is the rise time it takes for the bag to reach the maximum height, which is equal to the fall time it takes for the bag to reach the same starting point (35.8 m above the ground), so:

\( t = 0.23 s*2 = 0.46 s \)

Now, from equation (1) we have:

\( 35.8 m = 0 + 2.25 m/s*t + \frac{1}{2}9.81 m/s^{2}*t^{2} \)    

By solving the above quadratic equation for t we have:

\( t = 2.48 s \)    

Hence, the total time is:

\( t = 2.48 s + 0.46 s = 2.94 s \)

Therefore, the time that it takes for the bag to reach the ground is 2.94 s.

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Answer:

2Kg

first you find the total mass of both the person und skateboard

f = m*a

30 = m* 0.5

m= 30/ 0.5

m= 60 kg

then you subtract the mass of the person from the total mass

m1 - m2

60 - 58

= 2 kg

Taking into account the Newton's second law, the mass of the skateboard is 2 kg.

Newton's Second Law establishes the relationship between the forces acting on an object and the acceleration it experiences. This law says that the acceleration that an object experiences when subjected to a net force (force applied to the body) is proportional to that force.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

In this case, you know:

Replacing:

30 N= m× 0.5 m/s²

Solving:

m= 30 N÷0.5 m/s²

m= 60 kg

The mass of the sistem is the sum of the mass of the skateboard and the mass of the mass of your body:

Mass= mass of the skateboard + mass of your body

In this case:

60 kg= mass of the skateboard + 58 kg

Solving:

mass of the skateboard= 60 kg - 58 kg

mass of the skateboard= 2 kg

Finally, the mass of the skateboard is 2 kg.

Learn more about the Newton's second law:

Answer:

The width is \(w_c = 0.00252 \ m\)

Explanation:

From the question we are told that

  The  width of the single slit is  \(a = 1.5 \ mm = 1.5 *10^{-3} \ m\)

   The  wavelength is  \(\lambda = 420 *10^{-9} \ m\)

   The distance of the screen is  \(D = 4.5 \ m\)

Generally the width of the central maximum is  

        \(w_c = 2 * y\)

where y is the width of the first maxima which is mathematically represented as

       \(y = \frac{\lambda * D}{a}\)

=>   \(y = \frac{ 420 *10^{-9} * 4.5}{ 1.5*10^{-3}}\)

=>  \(y = 0.00126 \ m\)

So

    \(w_c = 2 *0.00126\)

    \(w_c = 0.00252 \ m\)

Answer:

loyalty

Explanation:

Answer:

just use the formula λ = v/f

Explanation:

v = velocity

f = frequency

a. We can calculate the amount of work by calculating the area under the graph.

first area (rectangular): 2.5 x 6 = 15

second area(trapezoid): 1/2 x (6+10) x 2.5 =20

total work done: 35 J

b. the force was first applied = 6 N

F = m.a

a = 6 : 3 = 2 m/s²

vf²=vi²+2as

vf²=6²+2.2.5

vf²=56

vf=7.5 m/s

The package strike the ground relative to the point directly below it was released at 213.3m.

Given values,

Velocity of plane 45 m/s

Acceleration due to gravity 9.8 m/s²

horizontal component of plane velocity is

ux = 45 m/s

Vertical component is zero

In the same way

ay = - 9.8  m/s²

ax = .0 m/s^2

Motion in y direction = -110 m

From equation of motion time of flight is

d = u x t + 1/2 at²

where,

d is distance

u is velocity initial

a is acceleration

t is time

So, putting values

-110 = 0 + 1/2 (-9.8)t²

-110 = -4.9t²

t² = 110 / -4.9

t² = 22.45

t = √22.45

t = 4.74

Motion in x direction,

d = u x t + 1/2 at²

d = ( 45 x 4.74) + 1/2 (0) 4.74²

d = 213.3 + 0

d = 213.3m

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Answer:

The maximum kinetic energy is 100 j.    

Explanation:

Answer :100J of KE.

Explanation:

Answer:

Electrical energy.

Explanation:

Electrical energy comes into the blender, which turns into magnetic energy in the electric motor. This magnetism repels permanent magnets. The motor spins as well as the blade. So the magnetism is converted to kinetic energy.

Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

Answer: Repelling is when something will not connect with another object. The force will cause a repel between the two objects. Attracting is when something is attracted or being pulled to another object.

Explanation: Hope this helps!

The possible temperature of the system after the iron has been added to the beaker is 52°C.

option B.

A system is said to be in thermal equilibrium when there is no temperature difference between system and surroundings. Temperature, as you know, measures how hot or cold a body is with respect to a standard object.

When a system ( cold and hot body) reaches thermal equilibrium or equilibrium temperature, the heat lost by the hot body will be equal to the heat gained by the cold body.

heat gained by the water = heat lost by the iron

The equilibrium temperature will be greater than the initial temperature of the cold body but less than the final temperature of the hot.

Thus, the only possible answer for the equilibrium temperature of mixture is 52⁰C.

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Answer:

The acceleration of the object can be calculated using the formula:

a = v^2 / r

where v is the velocity of the object and r is the radius of the circular orbit.

Substituting the given values, we get:

a = (10 m/s)^2 / 10 m

a = 100 m/s^2

Therefore, the acceleration of the object is 100 m/s^2.

Answer:

conjugate points is the object point and image point of a lens system

Answer:

In physical science, an isolated system is either of the following: a physical system so far removed from other systems that it does not interact with them. a thermodynamic system enclosed by rigid immovable walls through which neither mass nor energy can pass

The spring constant of the branch satisfying Hooke's law is 1,658.46 N/m.

The given parameters;

The spring constant of the branch satisfying Hooke's law is calculated as follows;

F = kx

mg = kx

\(k = \frac{mg}{x} \\\\k = \frac{22 \times 9.8}{0.13} \\\\k = 1658.46 \ N/m\)

Thus, the spring constant of the branch is 1,658.46 N/m.

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A boy tosses a 0.5 kg ball straight up into the air.

How high up does the ball go if the ball leaves the boy's hand with a speed of 5 m/s?

Recall from the equations of motion

Where y is the maximum height achieved by the ball, v₀ is the initial velocity and t is the time.

Let us first find the time (t)

Re-arranging the equation for time (t)

Where v is the final velocity of the ball and is zero at the maximum height and g is the gravitational acceleration.

Now we can find the maximum height of the ball

Therefore, the maximum height of the ball 3.83 m

OPTION D is the correct answer.

Refer to the attachment for complete calculation...

The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

 F = m a,  a = 0.3 m / s²

this acceleration points in the direction of the unbalanced force

Explanation:

In this problem we must use Newton's second law. Let's fix a reference system with the x axis parallel to the surface and the y axis perpendicular

Y axis y

         N-W = 0

         N = W = mg

X axis

        ∑ F = m a

        F = m a

we substitute

        150 = m a

To find an acceleration value, the mass of the car must be known, if the mass is m = 500 kg

        a = 150/500

        a = 0.3 m / s²

this acceleration points in the direction of the unbalanced force

Answer:

true

true

false

true

pls follow me and thank you

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

d. Ice

Explanation:

When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.

Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.

Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.

To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²

Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds

Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

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