Answer
-3 because there are 3 more electrons than protons. Hope this helps!
Explanation:
Answer:
I got that it has no charge.
Explanation:
Phosphorus,
Phosphorus is an element and therefore has a balance of 15 protons and 15 electrons. Therefore has no charge. It can be ionized though, and then it prefers to take up 3 electrons and thereby become phosphide with a -3 charge.
make a list of information you must know in order to write the correct formula for an ionic compound (this list may require reviewing all of the activities so far).
The correct formula for an ionic compound is total charge of cations = total charge of anions.
Ionic compounds do not exist usually as molecules. In the solid state, the ionic compounds are in crystal lattice that is generally containing many ions among which each of the cation and anion. An ionic formula, such as like NaCl , is an empirical formula. This formula merely indicates that sodium chloride is made of an equal number of sodium and chloride ions. Sodium sulfide, another ionic compound, has the formula Na2S . This formula generally indicates that this compound is made up of twice as many sodium ions as sulfide ions. This section will teach you how to find the correct ratio of ions, so that we can write a correct formula.
If we know the name of a binary ionic compound, you can write its chemical formula. Start by writing the metal ion with its charge, followed by the nonmetal ion with its charge. Because the overall compound must be strictly electrically neutral, decide how many of each ion is needed in order for the positive and negative charges to cancel each other out.
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Choose and explain:
a. Strongest base to H (gas phase): NH3, CH3NH2, (CH3)2NH, (CH3)3N
b. Strongest base to BMe3: pyridine,
2-methylpyridine, 4-methylpyridine
Answer:
a) (CH3)3N
b) 4-methylpyridine
Explanation:
Let us bear in mind that the basicity of amines depend on;
1) the availability of the lone pair
2) the stability of the conjugate acid of the amine.
In the gaseous phase, the basicity of the amine strictly depends on the availability of the lone pair. The tertiary amine is better able to accept a proton in the gaseous phase since it is surrounded by three methyl groups having an electron pushing effect thereby reinforcing the lone pair on the nitrogen. This order is reversed in solution due to solvation.
Here again, the electron donation to the nitrogen bearing the lone pair is important. The 4-methylpyridine is more basic than 2-methylpyridine to BMe3 due to steric hindrance that hinders the bonding of 2-methylpyridine to BMe3.
how many grams are there in 3400 moles of tetranitrogen dicarbide?
Explanation:
molar mass of tetranitrogen dicarbide S4N4= 4×32+4×14
128+56
184 g/mol
no.of moles =given mass/ molar mass
3400= given mass / 184
3400×184 =given mass.
625600 g
What is the relationship between chromosomes and DNA?
Question 3 options:
Chromosomes are made of DNA
DNA is made of chromosomes
Chromosomes manufacture DNA
They are on a break..
Answer:
answer is
chromosomes are made of
which statement about mass spectroscopy below is not true. group of answer choices a mass spectrum ionizes the molecule. ions in the mass spectrum can fragment. a mass spectrum can only see ions. certain functional groups have predictable fragmentation patterns. ions are separated by their hydrophobicity.
The fourth option is correct . Ions are separated by their hydrophobicity . Since, they are separated according to mass to charge ratio.
The exit of a small-scale chromatography column can be coupled directly to the input of a mass spectrometer using nano electrospray ionization. A needle with a 10-15 um point is used to channel the flow from the column. The ions are sorted and separated based on mass-to-charge (m/z) ratios after being ionized.
The molecular weight of the particles can be ascertained using mass spectrometry (MS), an analytical technique that separates ionized particles like atoms, molecules, and clusters by using variations in the ratios of their charges to their respective masses (mass/charge; m/z).
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Which of the following statements best compares nuclear power and hydropower based on their rates of renewal?
Hydropower has a faster rate because water is continuously being recycled through the hydrogeological cycle.
Nuclear power has a faster rate because all elements are spontaneously radioactive and are a source of nuclear energy.
Hydropower has a slower rate because a large volume of water vapor that evaporates takes several years to return to water cycle.
Nuclear power has a slower rate because the nuclear waste produced is not radioactive and thus cannot be used further as a fuel.
Hydropower is best compared to nuclear power based on their rates of renewal.
Because water is continually regenerated through the hydrogeological cycle, hydropower has a higher rate.Because all elements spontaneously produce radioactive material, which is a source of nuclear energy, nuclear power has a higher rate.Because it takes a significant amount of evaporated water several years to return to the water cycle, hydropower has a slower rate.Because the nuclear waste generated by nuclear power cannot be recycled as fuel and is not radioactive, it produces waste at a slower pace.What is hydropower's primary source?Water in motion generates hydroelectricity, namely the winter and spring runoff from mountain streams and crystal-clear lakes. Water can be utilized to turn turbines and generators that produce power when it is falling due to gravity.To learn more about hydropower visit:
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An element has 2 stable isotopes. One has 13 amu and 1.07% abundant . The second has 12 amu and 98.93% abundant. What is the average atomic mass of the element
The average atomic mass of the element is 12.0107 amu.
To calculate the average atomic mass of the element in question, we can use the following formula:
average atomic mass = (mass of isotope 1 x abundance of isotope 1) + (mass of isotope 2 x abundance of isotope 2)
where "mass of isotope 1" is the mass of the first stable isotope (13 amu in this case), "abundance of isotope 1" is the percentage of that isotope in the element (1.07% in this case), "mass of isotope 2" is the mass of the second stable isotope (12 amu in this case), and "abundance of isotope 2" is the percentage of that isotope in the element (98.93% in this case).
Substituting the given values in the formula, we get:
average atomic mass = (13 amu x 1.07%) + (12 amu x 98.93%)
average atomic mass = (0.1391 amu) + (11.8716 amu)
average atomic mass = 12.0107 amu
Therefore, the average atomic mass of the element is 12.0107 amu.
This means that on average, one atom of this element weighs 12.0107 atomic mass units (amu), which is slightly heavier than the most abundant isotope (12 amu) due to the presence of the less abundant isotope (13 amu). This concept is important in chemistry because the mass of atoms plays a crucial role in determining their chemical and physical properties. The knowledge of the average atomic mass of an element is important in a wide range of applications, including analytical chemistry, geochemistry, and nuclear physics.
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Read the sentence. Selena, Ben, and Raj all won leads in the musical, and they has practiced every afternoon during study hall for the past two weeks. Which is the best replacement for the underlined words? have practice will practice will be practicing have practiced
Answer:
have practiced
Explanation:
Selena, Ben, and Raj all won leads in the musical, and they have practiced every afternoon during study hall for the past two weeks.
Answer:
D.) have practiced
Explanation:
Please I need help thank you
Answer:
its sodium hydroxide
Explanation:
Consider the precipitation reaction: BaCl 2 + 2 AgNO 3 → 2 AgCl + Ba(NO 3) 2. How many grams of AgCl are generated when 85 g of BaCl 2 reacts?
The grams of AgCl are generated when 85 g of BaCl₂ reacts is 10.86 g.
The balanced equation is given as :
BaCl₂ + 2AgNO₃ -----> 2AgCl + Ba(NO₃)₂
the mass of the BaCl₂ = 85 g
molar mass of BaCl₂ = 208.23 g/mol
moles of BaCl₂ = mass / molar mass
= 85 / 208.23
= 0.408 mol
1 mole of BaCl₂ produce 2 moles of AgCl
0.408 moles of BaCl₂ = 2 × 0.408
= 0.816 mol of AgCl
moles of AgCl = 0.816 mol
mass of AgCl = moles × molar mass
= 0.816 g × 143.32 g/mol
= 10.86 g
Thus, The grams of AgCl are generated when 85 g of BaCl₂ reacts is 10.86 g.
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A scientist is designing a space probe that will be sent to Jupiter to analyze the atmosphere there. Before building a full-scale version of the probe, the scientist is going to build a model of it to test whether the probe can withstand the extreme environmental conditions of Jupiter's atmosphere. These extreme conditions include cold temperatures, strong gravitational forces, and high winds. Urgent!!!!!
Which of the following would most likely be the same about the scientist's model probe and the eventual full-scale version of the probe?
A.
They would be the same size.
B.
They would be made of the same material.
C.
They would be able to hold the same amount of fuel.
What would be the same about the scientist's model probe and the eventual full-scale version of the probe is that; . They would be the same size. Option A
What is the conditions?It is likely that the scientist's model probe would be built to replicate the size and proportions of the full-scale version because this would be vital in determining if the full-scale probe could endure the punishing conditions of Jupiter's atmosphere. The dimensions of the model probe and the real probe would therefore likely be the same.
However, it's likely that the model probe's parts weren't exactly the same as those in the actual probe.
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3. How many grams of oxygen are required to completely react with 240g of C₂H6?
Approximately 766.08 grams of oxygen are required to completely react with 240g of C₂H₆.
To determine the amount of oxygen required to completely react with 240g of C₂H₆ (ethane), we need to set up a balanced chemical equation for the combustion of ethane.
The balanced equation for the combustion of ethane is as follows:
C₂H₆ + O₂ → CO₂ + H₂O
From the balanced equation, we can see that the stoichiometric ratio between C₂H₆ and O₂ is 1:3. This means that for every one mole of C₂H₆, three moles of O₂ are required for complete combustion.
To calculate the amount of oxygen required, we need to convert the given mass of C₂H₆ to moles using its molar mass, and then use the stoichiometric ratio to determine the moles of O₂ required. Finally, we can convert the moles of O₂ back to grams using the molar mass of oxygen.
The molar mass of C₂H₆ is calculated as follows:
(2 x atomic mass of carbon) + (6 x atomic mass of hydrogen)
(2 x 12.01 g/mol) + (6 x 1.01 g/mol) = 30.07 g/mol
Now, we can proceed with the calculation:
Calculate the moles of C₂H₆:
moles of C₂H₆ = mass of C₂H₆ / molar mass of C₂H₆
moles of C₂H₆ = 240 g / 30.07 g/mol ≈ 7.98 mol
Determine the moles of O₂ using the stoichiometric ratio:
moles of O₂ = moles of C₂H₆ x (3 moles of O₂ / 1 mole of C₂H₆)
moles of O₂ = 7.98 mol x 3 ≈ 23.94 mol
Convert moles of O₂ to grams:
mass of O₂ = moles of O₂ x molar mass of O₂
mass of O₂ = 23.94 mol x 32.00 g/mol = 766.08 g
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balance the following reaction using LCM method by showing each steps Pb (N3)2 + Cr(MnO4)2 Cr2O3 + MnO2 + Pb3O4+ NO
here's the answer to your question
For the chemical reactionHCIO (aq)+NaOH(aq) H, O(l) + NaClo, (aq)write the net ionic equation, including the phases.net ionic equation:Which ions are considered spectator ions for this reaction?HNatOHCIO:
Explanation:
We are given this molecular equation:
HCIO₄ (aq) + NaOH (aq) -----> H₂O (l) + NaCIO₄ (aq) Molecular Equation
And we have to find the net ionic equation. Before that, we have to write the total ionic equation. We have to split all the compounds that we can into its ions. We have 3 aqueous solution:
HClO₄ (aq) ----> H⁺ (aq) + ClO₄⁻ (aq)
NaOH (aq) ----> Na⁺ (aq) + OH⁻ (aq)
NaCIO₄ (aq) ----> Na⁺ (aq) + ClO₄⁻ (aq)
And H₂O is a liquid so we leave it like that. The total ionic equation will be:
H⁺ (aq) + ClO₄⁻ (aq) + Na⁺ (aq) + OH⁻ (aq) ----> H₂O (l) + Na⁺ (aq) + ClO₄⁻ (aq) Total Ionic Equation
Finally to get the net ionic equation we have to cancel the spectator ions. By definition they are ions that doesn't participate in the reaction and are found on both sides of the equation.
Spectator ions = ClO₄⁻ (aq) and Na⁺ (aq)
H⁺ (aq) + OH⁻ (aq) ----> H₂O (l) Net Ionic Equation
Answer: The spectator ions are ClO₄⁻ (aq) and Na⁺ (aq).
The net ionic equation is: H⁺ (aq) + OH⁻ (aq) ----> H₂O (l)
What is the name of this lab equipment
The name of the lab equipment is bunsen burner.
What is a bunsen burner?A bunsen burner is a piece of equipment found in many laboratories primarily used for the controlled burning of flammable gas in the air.
In the laboratory, the bunsen burner is used as a source of heating for reactions. The gas-air mixture can be controlled to determine the level of flame and heat that will be produced.
Bunsen burners can vary in structure depending on the maker. The gas supply can be any of butane, propane, etc.
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Ice has a density of 0.92g/cm3. It will float in water.
The density of pure water is 1 g/cm^3.
Its density is 0.98 g cm 3 at room temperature, in comparison with the handiest zero.92 g cm 3 for ice, a reality that has to be defined through atomic, and molecular concepts. If ice has been no longer much less dense than water, it might sink, having a devastating impact on lake backside ecosystems. believe it or now not, ice is honestly about 9% much less dense than water. for the reason that water is heavier, it displaces the lighter ice, causing the ice to glide to the pinnacle.
The density of ice is about 90 percent that of water, but that could range because ice can contain air, too. meaning that about 10 percent of an ice cube or iceberg will be above the water line. The density of water is maximum at four∘C, and the density of the ice is much less than the water due to its susceptible intermolecular pressure of attraction. as the density of water is more, it's miles heavier than ice. therefore ice floats on the floor of the water. Ice continually floats due to the fact it's far less dense than everyday water. because frozen water molecules shape a crystal.
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Use Henry's law to determine the molar solubility of helium at a pressure of 1.1 atm
and 25 ∘C . Henry’s law constant for helium gas in water at 25 ∘C is 3.70⋅10−4M/atm
.
Apply Henry's law to calculate the molecular absorption of helium at 1.5 atm, 25 °C, and 1.5 atm of pressure. Helium in water obeys Henry's law without exception.
A gas is what?Compared to other states of material, including such solids and liquids, gases get a lower density. Particles have such a great deal of kinetic energy and are not really attracted to one another, thus there is a lot of unoccupied space between them. One element, like hydrogen gas (Co and co2), a complex, like dioxide (CO2), or even a combination of multiple gases, like air, can make up a gas.
What does helium mean?Yet, helium is an essential component in numerous industries, such as high-tech manufacturing, medical technology, and scientific research.
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Nitrogen dioxide gas and liquid water react to form aqueous nitric acid and nitrogen monoxide gas. Suppose you have 5.0 mol of NO2 and 11.0 mol of H2O in a reactor.
Calculate the largest amount of HNO3 that could be produced. Round your answer to the nearest 0.1 mol
First, we need to write the balanced chemical equation for the reaction:
2 NO2(g) + H2O(l) → HNO3(aq) + NO(g)
From the equation, we can see that 2 moles of NO2 react with 1 mole of H2O to produce 1 mole of HNO3 and 1 mole of NO. Therefore, we need to determine which reactant is limiting and calculate the amount of HNO3 that can be produced based on that.
To do this, we can use the mole ratio of NO2 to H2O:
5.0 mol NO2 × (1 mol H2O / 2 mol NO2) = 2.5 mol H2O
Since we have 11.0 mol of H2O, it is not limiting and we will use up all of the NO2.
Therefore, we can calculate the amount of HNO3 that can be produced from 5.0 mol of NO2:
5.0 mol NO2 × (1 mol HNO3 / 2 mol NO2) = 2.5 mol HNO3
Therefore, the largest amount of HNO3 that could be produced is 2.5 mol, rounded to the nearest 0.1 mol.
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Can you list some examples for each of the three domains of bacteria, archaea, and eukarya?
Answer: bacteria: e Coli
Explanation:
The bacteria and archaea are microorganisms. Escheria coli, staphylococcus aureus etc are examples of bacteria. Different types of archaea includes bathyarchaeota, thermoproteota etc. Eukaryotes are multicellular organisms such as plants, fungi, animals etc.
What are eukaryotes?Eukaryotes are multicellular organisms with developed cellular organization and developed nucleus. All the higher level organisms such as humans, animals, fungi, plants etc are eukaryotes.
Microorganisms such bacteria are single celled organisms and they are called unicellular having only one cell without a developed nucleus.There are many types of bacteria based on their structure and functions such as spirulina, staphylococcus, vibrio coli etc.
Archaea is another type of unicellular organism which first classified as type of bacteria, but later they are included in a new class of domain. They are natural methanogens that is they produce methane gas. Some examples are bathyarchaeota, thermoproteota etc.
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complete and balanced the precipitation reaction . include physical states in your answe.
CuCl2(aq)+ Na2CO3(aq) > .............. + ............. ?
The complete equation for the precipitation reaction will be:
CuCl₂(aq)+Na₂CO₃(aq) > CuCO₃(s) + 2NaCl(aq)
From the reaction,
CuCl₂(aq)+Na₂CO₃(aq) are the reactants while CuCO₃(s) + NaCl(aq) are the products of the reaction.
In the reactants side there is 1Cu, 2Cl, 2Na and 1CO₃ while in the products side there is 1Cu, 1Cl, 1Na and 1CO₃
To balance both sides, we multiply NaCl by 2 to balance the Na and Cl atoms.
Therefore, the final balanced equation will be
CuCl₂(aq)+Na₂CO₃(aq) -----> CuCO₃(s) + 2NaCl(aq)
This reaction is balanced, and with the appropriate physical states of the reactants and products.
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4. The half-life of C-14 is 30 years. If a scientist had 100.0 g at the beginning, how
many grams would be left after 120 years has elapsed?
Half Lives
0
1
2
Time (years)
Amount (grams)
Show table
Answer:
6,25 gm
Explanation:
4. The half-life of C-14 is 30 years. If a scientist had 100.0 g at the beginning, how
many grams would be left after 120 years has elapsed?
10 years would be 120/30 = 4 half lives0
s0 the fraction of c-14 left would be four (1/2) multiplied together
1/2 X 1/2 X 1/2 X 1/2 = 1/16
SO 1/16 OF THE 100.0 gm would be left
100.0/16 = 6,25 gm
Obsidian _____.
is formed from sand and quartz
cools very quickly
has large mineral crystals
cools very slowly
Answer:
Cools Very Quickly
Explanation:
This is the right answer!
how does ease of ion pair formation depend on concentration.
\(\bold{Choose \: the \: correct \: Answer :D\: }\)
Answer:
Option B is correct.
Explanation:
Distance refers to the distance traveled by a body.
Hope it will help you.
At 40 °C, the solubility of KNO3 is 65 g/100 g of H2O. In the laboratory, a student mixes 110 g of KCl with 200. g of H2O at a temperature of 40 °C. How much of the KNO3 will dissolve?
At 40°C, the maximum amount of KNO₃ that can dissolve in 200 g of water is 130 g, but since only 110 g of KCl was added, all the KCl will dissolve, and 71.5 g of KNO₃ will dissolve.
To determine how much KNO₃ will dissolve, we need to compare the amount of KCl that was added to the maximum amount of KNO₃ that can dissolve at the same temperature.
First, we can find the maximum amount of KNO₃ that can dissolve in 200 g of water at 40°C, which is given as 65 g/100 g of water
Maximum amount of KNO₃ that can dissolve
= 65 g/100 g x 200 g
= 130 g
This means that at most, 130 g of KNO₃ can dissolve in 200 g of water at 40°C.
Next, we need to compare the amount of KCl added to the maximum amount of KNO₃ that can dissolve.
The amount of KCl added is 110 g, which is less than the maximum amount of KNO₃ that can dissolve (130 g). Therefore, all of the KCl will dissolve and some of the KNO₃ will dissolve.
To find the amount of KNO₃ that will dissolve, we need to calculate how much KNO₃ would be in 110 g of the solvent (water) if it were saturated with KNO₃
Amount of KNO₃ in 110 g of water
= 65 g/100 g x 110 g
= 71.5 g
This means that 71.5 g of KNO₃ will dissolve in 110 g of water at 40°C.
Therefore, the amount of KNO₃ that will dissolve in the 200 g of water containing 110 g of KCl is 71.5 g.
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What is the molarity of a solution in which 0.257 moles of HNO2 is dissolved in 490ml of water?
0.52 molar is the molarity of a solution in which 0.257 moles of HNO2 is dissolved in 490ml of water.
What do you mean by the term molarity ?The term molarity is defined as the number of moles of solutes are dissolved in per litre of solution. It is represented by the symbol "M". The unit of molarity is molar(M).
To calculate the molarity of a solution, divide the moles of solute by the volume of the solution expressed in liters.
The formula of molarity = a number of moles of solutes / litre of solution
Given:
Number of moles = 0.257 moles
Volume = 490ml = 0.49 litre
Molarity = ?
According to the definition of molarity,
Molarity = Number of moles of solute / litre of solution
Molarity = 0.257 moles / 0.49 litre
Molarity = 0.52 molar
Thus, the molarity of a solution in which 0.257 moles of HNO2 is dissolved in 490ml of water is 0.52 molar.
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In which atmospheric layer is the ozone layer? O stratosphere o thermosphere O mesosphere troposphere
Answer:
The stratosphere
Explanation:
How many moles of water contain each of the following number of molecules?
4.38 × 10^21 molecules
Report your answer using appropriate number of significant figures.
In 4.38 × 10^21 molecules of water, there are approximately 0.073 moles.
To calculate the number of moles, we can use Avogadro's number, which states that 1 mole of a substance contains 6.022 × 10^23 molecules. So, by dividing the given number of molecules (4.38 × 10^21) by Avogadro's number, we can find the number of moles.
Now, let's explain the process in detail. Avogadro's number is a constant that represents the number of particles (atoms, molecules, etc.) in one mole of a substance. It is approximately 6.022 × 10^23. Therefore, if we divide the given number of molecules by Avogadro's number, we can determine the number of moles.
In this case, we divide 4.38 × 10^21 molecules by 6.022 × 10^23 molecules/mole, resulting in approximately 0.073 moles.
Significant figures play an important role in reporting the answer. The given number of molecules has three significant figures (4, 3, and 8), so our answer should be reported with three significant figures as well. Therefore, the number of moles is approximately 0.073.
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The unique properties of water are due to the water's
Question 32 options:
A. density
B. ionic bonds
C. polar nature
D. high heat capacity
Answer:
C. polar nature
Explanation:
The polarity of water and its ability to hydrogen bonding contributes to it's unique properties
Some measurements of the initial rate of a certain reaction are given in the table below.
[N2]. [H2]. Initial rate of reaction
0.434 M 2.29 M 8.00 x 10^4M/s
0.434 M 3.23M 1.13 x 10^5M/s
0.630M 2.29 M 1.69x10^5M/s
Use this information to write
rate law for this reaction, and calculate the value of the rate constant k.
Rate =k
K=
The rate law for the reaction between nitrogen, N₂ and hydrogen, H₂ as given in the table of concentration of reactants and reaction rates below is: Rate = k [N₂]²[H₂]
The rate constant, K for the reaction between nitrogen, N₂ and hydrogen, H₂ as given in the table of concentration of reactants and reaction rates below is: K = 1.85 * 10⁵ M⁻²s⁻¹
The rate law for the reaction is given by:
Rate = k [N₂]ᵃ[H₂]ᵇwhere a and b are orders of reaction in N₂ and H₂ respectively.Taking the ratio of the rates of experiment 3 and experiment 1 to find a:
1.69 * 10⁵/8.00 * 10⁴ = (0.63/0.434)ᵃ * (2.29 * 2.29)ᵇ
2.11 = (1.45)ᵃ
Take logarithm of both sides
log 2.11 = log (1.45)ᵃ
log 2.11 = a * log 1.45
a = log 2.11 / log 1.45
a = 2Taking the ratio of the rates of experiment 2 and experiment 1 to find b:
1.13 * 10⁵/8.00 * 10⁴ = (0.434/0.434)ᵃ * (3.23 * 2.29)ᵇ
1.41 = (1.41)ᵇ
b = 1
Therefore, the rate law is: Rate = k [N₂]²[H₂]
To determine the rate constant K, make K subject of formula in the rate law of the reaction:
Rate constant K = Rate / [N₂]²[H₂]
Using the values from experiment 1:
K = 8.00 * 10⁴ M/s / (0.434 M )² * (2.29 M)
K = 1.85 * 10⁵ M⁻²s⁻¹
Therefore, the rate constant K is 1.85 * 10⁵ M⁻²s⁻¹
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