Answer:
Th ball
Explanation:
the thumb is what to the phalanges?
Answer:
A thumb only has one joint and two phalanges. The thumb is referred to as “the big finger".
Brainlist pls!
Write 3 things you want to learn about the ocean.
Answer: How it was created, The frequency of the waves, and is the water salty enough to kill someone.
Explanation:
Just from my brain.
Answer: the ecosystem , differnt species of fish, and ship wrecks
Explanation:
:)
A runner weighing 70 kg, moving at a speed of 8.8 m/s, rounds
a bend with a radius of 25 m. What is the centripetal force
needed to keep this runner on the curve?
a 250 N
b 100 N
C 217 N
d 158 N
Answer:
217 N
Explanation:
Answer:217N
Explanation:
URGENT HELP
The electric motor in the car is powered by a battery.
To charge the battery, the car is plugged into the mains supply at 230 V
The power used to charge the battery is 6.9 kW
Calculate the current used to charge the battery.
Current = ?
Answer:
0.03 A
Explanation:
Answer:
30A
Explanation:
I (current)= p (power) / V (voltage)
I= 6.9*10^3 / 230
I= 30A
-2 4/5 = -3 1/2n help pls
Answer:
4/5=n
Explanation:
hah I have the same homework :0
an electric dipole consists of a pair of equal but opposite point charges of magnitude 4.0 nc separated by a distance of 2.0 cm. what is the electric field strength at the point midway between the charges?
The electric field strength at the point midway between the charges of an electric dipole is 0 N/C.
An electric dipole consists of two equal but opposite point charges, in this case, each having a magnitude of 4.0 nC and separated by a distance of 2.0 cm.
When we want to determine the electric field strength at the midpoint between these charges, we need to consider the individual electric fields created by each charge and their directions.
At the midpoint, the electric fields due to each charge are equal in magnitude but opposite in direction. This is because the distance from each charge to the midpoint is the same, and the charges have the same magnitude but opposite signs. Therefore, the electric fields will cancel each other out.
In an electric dipole with charges of equal magnitude but opposite signs, the electric field strength at the point midway between the charges is 0 N/C, as the electric fields created by each charge cancel each other out.
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after he gets the block to move, what does dr. hewitt do to drag the block across the table at a steady rate?
Inertia has an impact on both moving and stationary objects, according to Newton's first law of motion. Unless an unbalanced force is acting on an object, Newton's first law states that it will stay at rest or move in a straight line at a constant speed.
What is inertia?
Iners, which means idle or slow in Latin, is where the word inertia originates. Any physical object's resistance to a change in velocity can also be referred to as having inertia. Changes in the object's motion's speed or direction fall under this category. This trait includes the propensity for objects to continue going straight ahead at a constant pace in the absence of external pressures. Mass, a quantitative characteristic of physical systems, manifests itself primarily in inertia. One of the pillars of traditional physics is the concept of inertia.
It is still utilized today to describe how objects move and are impacted by external forces.
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If an object experienced an impulse when a large force was applied what does that indicate about the length of time the force was applied
proof the equation of motion third
The proof of third equation of motion is determined as v² = 2as + u².
What is the proof of third equation of motion?
The proof of third equation of motion is determined as follows;
The first equation is given as;
v = u + at
t = ( v - u ) /a
where;
u is the initial velocitya is the accelerationt is the time of motionThe formula for the average distance traveled by an object is;
s = (v + u)/2 x t
Expand the equation above as;
s = (v + u)/2 x (v - u)/a
s = (v² - u²) / 2a
2as = v² - u²
v² = 2as + u², proved
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Determine the orbits period of the moon when the distance between the earth and the moon is 3.82 x 10 to the power of 8
Answer:
3820000000
Explanation:
Which type of extinguisher is intended to be used on a Class B fire?
Select one:
- Pump-type water extinguisher
- Stored-pressure water-mist extinguisher
- Stored-pressure wet chemical extinguisher
- Aqueous film forming foam extinguisher
The type of extinguisher that is intended to be used on a Class B fire is the Aqueous film forming foam (AFFF) extinguisher. The AFFF extinguisher is the main answer to the question.
An Aqueous film forming foam extinguisher is designed to extinguish fires that are fueled by flammable liquids like oil, gasoline, or kerosene. This extinguisher works by covering the fuel source with a layer of foam that deprives the flames of oxygen. The foam also helps to cool the fuel, further limiting the spread of the fire.
There are different types of fires, and each requires a specific type of extinguisher. A Class B fire is fueled by flammable liquids, including gasoline, oil, and kerosene, among others. These fires can be extremely dangerous and difficult to extinguish, which is why it's important to use the right type of fire extinguisher.
The Aqueous film forming foam extinguisher (AFFF) is the most effective type of extinguisher for Class B fires. This type of extinguisher works by smothering the flames with a layer of foam that contains water and a special chemical agent. The foam creates a barrier that cuts off the fire's oxygen supply and prevents it from spreading. AFFF extinguishers are stored-pressure extinguishers, which means that the foam is already mixed with water and ready to use.
In conclusion, the Aqueous film forming foam extinguisher (AFFF) is the type of extinguisher intended to be used on a Class B fire. This type of extinguisher is highly effective in smothering flames and preventing the fire from spreading. It is essential to use the right type of extinguisher for the type of fire to prevent the fire from growing.
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experimental study on the frosting characteristics of round tube in confined circular flow path at low temperature
In a round tube, frost accumulation increases with an increase in tube temperature.
On cold surfaces, frosting takes place in the case of confined structures. A study was conducted to study frosting characteristics on a round tube. At the temperature of 60°, the frosting was observed. Factors such as temperature, air velocity, and cold surface temperature were independent. All these factors' relationships were assumed. It was concluded that the reason for period frosting and frost-melting is thermal resistance.
Along with frosting reached the mature stage by heat transfer. It was also observed that average density and frost accumulation increases with an increase in tube temperature, relative humidity, and heat transfer rate. In the lowest air inlet, the frost layer thickness is the lowest while in the middle is position layer range is the highest.
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A sample of a low-density gas is initially at room temperature and has pressure p. The gas is warmed at constant volume until the pressure is 2p. Compared to the initial Celsius temperature of the gas, the final Celsius temperature is
Answer:
Compared to the initial Celsius temperature of the gas, the final Celsius temperature is greater by a factor of more than 2.
Explanation:
Gay-Lussac's law states that the pressure of a fixed volume of a gas is directly proportional to its temperature. In other words, if the temperature increases, the pressure will increase and if the temperature decreases, the pressure will decrease.
In summary, Gay-Lussac's law is a law that says that when the amount of gas and volume are kept constant, the quotient that exists between the pressure and the temperature will always have the same value:
\(\frac{P}{T}=k\)
Being an initial state 1 and a final state 2, it is true:
\(\frac{P1}{T1} =\frac{P2}{T2}\)
In this case:
P1= pT1= tP2= 2pT2= ?Replacing:
\(\frac{p}{t} =\frac{2p}{T2}\)
Solving:
\(T2=2p*\frac{t}{p}\)
T2= 2*t
Compared to the initial Celsius temperature of the gas, the final Celsius temperature is greater by a factor of more than 2.
A 40. 0-kilogram child exerts a 100. -newton force on a 50. 0-kilogram object. The magnitude of the force that the object exerts on the child is.
The magnitude of the force that the object exerts on the child is 100 N.
Calculation:-
mass of object = 50 kg
Force exerted by child = 100 N
From newton's third law of motion, equal and opposite force is applied.
Hence, force the object exert is same 100 N.
Force is a push or pulls upon an item because of the object's interaction with some other object. pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e, to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.
The phrase 'Force' has a unique meaning. At this degree, it is absolutely appropriate to describe a force as a push or a pull. A force is not something that an object consists of or 'has in it. A force is exerted on one object through another. The concept of a force isn't always restricted to living matters or non-living matters.
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What is the most likely outcome? it will become a permanent magnet because the domains will remain aligned. it will become a temporary magnet because the domains will remain aligned. it will become a permanent magnet because the domains will easily realign. it will become a temporary magnet because the domains will easily realign.
The likely outcome when a magnetically soft material is placed in a strong magnetic field is that it will become a temporary magnet because the domains will easily realign.
What is a magnet?A magnet is a material whose magnetic domains are properly aligned. These materials are able to attract other materials that are magnetizable.
Hence, the likely outcome when a magnetically soft material is placed in a strong magnetic field is that it will become a temporary magnet because the domains will easily realign.
Missing parts:
A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?
a. It will become a permanent magnet because the domains will remain aligned.
b. It will become a temporary magnet because the domains will remain aligned.
c. It will become a permanent magnet because the domains will easily realign.
d. It will become a temporary magnet because the domains will easily realign.
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Answer: D or It will become a temporary magnet because the domains will easily realign.
Explanation: Taking the quiz!
A 45 kg mass is dragged 50 m over a surface. If 1.0 kW of power is produced over 10 seconds,
what is the coefficient of friction for the surface?
Answer:
Approximately \(0.45\) (assuming that the surface is level, the mass is moving at constant velocity, and that \(g = 9.81\; {\rm m\cdot s^{-2}}\).)
Explanation:
With a power of \(P = 1.0\; {\rm kW} = 1.0\times 10^{3} \; {\rm W}\), the work that would be done over \(t = 10\; {\rm s}\) would be:
\(\begin{aligned}(\text{work}) &= (\text{power})\, (\text{time}) \\ &= (1.0\times 10^{3}\; {\rm W})\, (10\; {\rm s}) \\ &= 1.0 \times 10^{4}\; {\rm J}\end{aligned}\).
Divide work by distance to find the force that did the work:
\(\begin{aligned} (\text{force}) &= \frac{(\text{work})}{(\text{distance})} \\ &= \frac{1.0\times 10^{4}\; {\rm J}}{50\; {\rm m}} \\ &= 200\; {\rm N}\end{aligned}\).
If this mass is moving at a constant velocity, the magnitude of friction on this mass will be equal to that of the external force, \(200\; {\rm N}\).
If the surface is level, the magnitude of the normal force on this mass will be equal to that of weight:
\(\begin{aligned}(\text{weight}) &= (\text{mass})\, g \\ &= (45\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-2}}) \\ &\approx 4.41 \times 10^{3}\; {\rm N}\end{aligned}\).
Divide the magnitude of friction by normal force to find the coefficient of friction:
\(\begin{aligned}& (\text{coefficient of friction}) \\ =\; & \frac{(\text{friction})}{(\text{normal force})} \\ \approx\; & \frac{200\; {\rm N}}{(45\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}))} \\ \approx \; & 0.45\end{aligned}\).
the cosmic background radiation is group of answer choices the electromagnetic remnants of the explosion in which the universe was born. the faint glow along the elliptic, caused by sunlight scattering from dust particles in the planetary system. the result of the radioactive decay of heavy, unstable elements produced in supernova explosions. the radio noise caused by high energy atomic nuclei known as cosmic rays, moving through magnetic fields in space.
The electromagnetic byproducts of the explosion that gave birth to the cosmos are the cosmic background radiation.
The first light to ever be able to move freely throughout the universe is the Cosmic Microwave Background (CMB), which has since been cooled. The 'Big Bang' was followed by the release of this 'fossil' radiation, which is the farthest that any telescope can observe. It is seen by scientists as a "shockwave" or echo of the Big Bang.
The flimsy great bang light is preserved in the cosmic microwave background radiation. About 2.5 percent of the sky is covered by this false-color image, which depicts variations in the ionized gas that eventually condensed to form superclusters of galaxies.
A form of radiation called cosmic background radiation is one in which photons can move around freely since the universe has been transparent to radiation since the Big Bang.
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Can someone please help me? :(
Answer:something empty depressed
Explanation:
A car starts from rest, then accelerates at 1.20 m/s2 for 7.00 s. It hits the brakes,
slowing to a stop at a rate of -4.25 m/s2.
What is the total distance travelled?
Answer:
the answer is 4.15 m/s2
Explanation:
4.15 m/s2
what is the magnitude of the magnetic field at a point midway between them if the top one carries a current of 18.0 aa and the bottom one carries 11.5 aa ?
The exact magnitude of the magnetic field depends on the distance, r, from the midpoint to each wire.
Assuming the currents in both wires are flowing in the same direction, the formula to calculate the magnetic field at the midpoint is:
B = (μ₀ / 2π) * (I₁ + I₂) / r
Where:
B is the magnetic field
μ₀ is the permeability of free space (approximately 4π x 10^(-7) T·m/A)
I₁ is the current in the top wire (18.0 A)
I₂ is the current in the bottom wire (11.5 A)
r is the distance from the midpoint to each wire (assuming they are equidistant)
Plugging in the given values:
\(B = (4\pi * 10^{(-7)} T.m/A) * (18.0 A + 11.5 A) / r \\B = (4\pi * 10^{(-7) }T.m/A) * (29.5 A) / r \\B = (1.18\pi * 10^{(-5)} T.m) / r\)
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--The complete Question is, What is the magnitude of the magnetic field at a point midway between two current-carrying wires if the top wire carries a current of 18.0 A and the bottom wire carries a current of 11.5 A?--
Let h : Z → R be the point mass function of some distribution.
a) Let Ω = Z × Z. Show that if we define each ω = (ω1, ω2) ∈ Ω,
pω = hω1 hω2, then (pω)ω∈Ω is the point mass function of some distribution.
b) Consider the random variable X : Ω → Z, X(ω) = ω1 + ω2. Show that X's
the point mass function of the distribution, i.e. PX, is

Hints: the a) point is largely a repetition of the old one, but the latter point may require some thought. In particular, you should think about why it is enough to calculate
probability P({ω ∈ Ω : X(ω) = x}). For this, you should think about
that what this event has to do with the event
x - n}
and why it can be applied to calculate the probability of this event
definition of probability distribution.
We have demonstrated that (pω)ω∈Ω is the point mass function of some distribution, and that the random variable X has a point mass function PX equal to (pω)ω∈Ω.
In order to show that (pω)ω∈Ω is the point mass function of some distribution, we need to demonstrate that it satisfies the properties of a probability distribution.
a) Let's consider the properties of a probability distribution. Firstly, the values of pω must be non-negative for all ω ∈ Ω. This is true since pω is defined as the product of two non-negative values hω1 and hω2.
Secondly, the sum of probabilities over all possible outcomes must be equal to 1. In this case, we need to show that the sum of (pω)ω∈Ω over all possible ω in Ω is equal to 1. To do this, we can consider the sum:
Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω
By the properties of the point mass function h, we know that Σhω1 = 1 and Σhω2 = 1. Therefore, the above expression becomes:
Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω = 1 * 1 = 1
Thus, we have shown that (pω)ω∈Ω satisfies the properties of a probability distribution.
b) Now let's consider the random variable X(ω) = ω1 + ω2 and show that its point mass function PX is equal to (pω)ω∈Ω.
To calculate PX(x) = P({ω ∈ Ω : X(ω) = x}), we need to consider the event where the sum of the components ω1 and ω2 is equal to x. This can be expressed as:
{ω ∈ Ω : X(ω) = x} = {(ω1, ω2) ∈ Ω : ω1 + ω2 = x}
Now, notice that this event is equivalent to the event {ω1 = n, ω2 = x - n} for any fixed n. The probability of this event is given by pω1 pω2 = hω1 hω2, which matches the point mass function (pω)ω∈Ω.
By considering all possible values of n, we can cover all the cases for X(ω) = x, and therefore, we have shown that PX(x) is equal to (pω)ω∈Ω.
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which element has 5 valence electrons and 4 shells
Answer:
Arsenic
Explanation:
Arsenic is in group 5 and period 4. Group numbers tell us the number of valence electron and period number tells us the number of shells in an element.
Saved Select the single case from the following that will result in the shortest tidal range. Multiple Choice - The Earth, Sun and Moon are fully aligned in July - The Earth, Sun and Moon are fully aligned in January - The Earth, Sun and Moon are fully aligned in January, but the Sun and Moon are on opposite sides of the Earth - The Earth-Sun and Earth-Moon lines are at an angle of 45° to each other in July - The Earth Sun and Earth-Moon lines are at an angle of 45° to each other in January
The single case that will result in the shortest tidal range is "The Earth, Sun and Moon are fully aligned in January, but the Sun and Moon are on opposite sides of the Earth."
This is because the gravitational pull of the Sun and Moon are working against each other, resulting in weaker tides. When the Earth-Sun and Earth-Moon lines are at an angle of 45° to each other, as in the options for July and January, this creates a stronger gravitational pull and therefore a higher tidal range.
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The correct option is E, The case that will result in the shortest tidal range is "The Earth Sun and Earth-Moon lines are at an angle of 45° to each other in January".
Tidal range refers to the vertical difference between the high tide and low tide water levels at a given location over a certain period of time, usually over a 24-hour period. The tidal range is determined by various factors, including the gravitational forces of the sun and moon on the Earth, the shape of the coastline, and the depth and configuration of the ocean floor.
The tidal range can vary significantly depending on the location and the phase of the moon. For example, during a new or full moon, the gravitational forces of the sun and moon align, resulting in higher high tides and lower low tides, which results in a larger tidal range. On the other hand, during a quarter moon, the gravitational forces are less intense, resulting in smaller tidal ranges.
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a plank is balanced in its center. a 100 n bucket is placed 0.66 m from the center of the plank. how far from the center on the opposite side must a 50 n weight must be placed to balance the bucket.
The 50 N weight must be placed 1.32 m from the center on the opposite side to balance the 100 N bucket.
The formula to find the distance, d, from the center that a weight must be placed to balance a weight placed a distance, x, from the center is:
d = x * (m1 / (m1 + m2)),Where:
m1 and m2 are the masses of the weightsIn this case:
m1 = 100 Nm2 = 50 NPlugging these values into the formula, we find:
d = 0.66 m * (100 N / (100 N + 50 N)) d = 0.66 m * (100 N / 150 N) d = 0.66 m * (2 / 3) d = 1.32 mHence, in order to balance the 100 N bucket, the 50 N weight must be positioned 1.32 m from the center on the opposite side.
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If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.
The formula for calculating density is expressed as
Density = mass/volume
From the information given,
mass of empty pycnometer = 10.2
mass of the same pycnometer with an unknown liquid is 21.8.
Mass of unkown liquid = 21.8 - 10.2 = 11.6
volume of unknown liquid = 7
Thus,
Density = 11.6/7
Density = 1.7 g/ml
Which of the following statements are true about gravity?
Check all that apply.
O A. Gravity doesn't exist between the Earth and the sun.
B. Gravity exists in the whole universe.
C. Gravity is a force that pushes two or more objects apart.
D. Gravity exists between two or more objects that have mass.
Answer:
B and D
Explanation:
A is wrong because objects with mass have gravity and the Earth and Sun both have mass. As we know, the Earth orbits around the Sun and the reason si because gravity.
B is corrects because throughout the whole universe there are objects like planets and meteors and more. All these objects have gravity because they have mass.
C Gravity pulls things together that is why we are on Earth and not pushed away into space.
D is correct, using Sun and a meteor. When a meteor comes within the gravity range of the sun, the sun pulls the meteor toward it. Without anything around the sun, nothing happens because there is nothing to pull.
How to Estimate your age in seconds ?
No Spamming ~
Answer:
Explanation:
First, remember your age.
Then, multiply it times 365 x 24 x 60 x 60.
Or basically, multiply it times 315.36 x 10⁵
is driving with a velocity of 5 m/s and speeds up to a velocity of 10 m/s over 5 seconds. What is Mr. DaCosta's acceleration?
two girls drag a bag across the floor. One girl exerts a force of 10 newtons and the other girl a force of 30 Newton's in the same direction. Calculate the resultant force on the bag.
Answer:
Explanation:
The resultant would be a combination of the two forces. We need to add them together since they are exerting a force in the same direction.
10+30= 40 N of force
Which air mass would form over warm water?(1 point)
maritime tropical
continental tropical
continental polar
maritime polar
Answer:
A.) Maritime Tropical (mT)
Explanation:
Continental tropical is the air mass that forms over warm land.
Maritime Polar is the air mass that forms over cold water.
Continental polar is the air mass that forms over cold land.
So therefore A or Maritime Tropical is the correct answer