if the atmospheric pressure is 87.3 kPa what is th3 pressure in atm​

Answer:

4.21

Explanation:

use Avogadro's number

6.023 x 10^23

multiply this by 7 because you want to find 7 moles :

6.023 x 10^23 x 7 = 4.21

Answer:

Explanation:

i notice that theri is no image so i wont be able to help you sorry

Answer:

the molecules stop sliding and tumbling all over each other

Explanation:

Answer:

A. the box accelerated to at 1.0 m/s² to the right because the net force is 17N to the right.

Explanation:

To solve this problem, we need to find the net force acting on the body;

   Net force  = Forward force  - Backward force

  Forward force  = 35N

  Backward force  = 18N

 Net force  = 35N  - 18N = 17N

 So;

   Net force  = mass x acceleration

        17  = 17 x acceleration

        Acceleration  = 1m/s²

Therefore, the body moves in the forward direction with an acceleration of  1m/s²

A 60 kg man would need a 8000 meters of total foot edge to be supported by surface tension.

Many insects can walk on the water, because of the surface tension at the water surface.

Surface water molecules attract more strongly to the water molecules around them and create a high surface tension with smaller surface area of a water.

The water molecules at the surface do not have other water molecules to form hydrogen bonds, only below and to either sides, like other water molecules that hydrogen bond with other water molecules on all sides.

The surface tension at the water surface is not strong enough to support man on the water.

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I would say C.) It has been updated and modified based on the new data

Answer: D

Explanation:

took test

Answer:

D

Explanation:

got it right  

For a zero-order reaction, the reaction rate is equal to the rate constant (k) multiplied by the concentration of the reactant raised to the power of zero, which simplifies to just the rate constant (k).

The dissociation rate constant (abbreviated as "k_off") gauges how rapidly a complex formed between two molecules separates or dissociates. The complex is stable for a longer time when k_off is low because it takes longer for the molecules to separate.

The phrase "off rate" describes how quickly molecules separate from a complex in a similar way. A low off rate indicates a gradual separation. High affinity in the context of molecular interactions often denotes a strong binding between molecules, producing a stable complex with a low k_off value and a slow dissociation rate. Therefore, the reaction rate is equal to the rate constant for a zero-order reaction.

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Answer:

I'm not completely sure but possibly (HCO³)

Answer:

Wind is caused by differences in the atmospheric pressure. When a difference in atmospheric pressure exists, air moves from the higher to the lower pressure area, resulting in winds of various speeds. On a rotating planet, air will also be deflected by the Coriolis effect, except exactly on the equator. might be a bit extra but i hope it helps!

Explanation:

pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.

When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.

In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.

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Answer: The enthalpy of neutralization is the energy change associated with the reaction of an acid and a base to form a neutral solution of a salt and water. This energy change is typically exothermic, meaning it releases heat.

The acid strength can have an effect on the enthalpy of neutralization. Generally, stronger acids have a more negative enthalpy of neutralization because they release more heat when they react with a base. This is because stronger acids donate their protons more readily to the base, resulting in a stronger electrostatic attraction between the resulting ions, and therefore a more exothermic reaction.

However, it is important to note that the effect of acid strength on enthalpy of neutralization is not the only factor affecting this energy change. Other factors that can influence the enthalpy of neutralization include the strength of the base, the concentration of the acid and base, and the specific reaction conditions, such as temperature and pressure.

Explanation: The enthalpy of neutralization is the energy change associated with the reaction of an acid and a base to form a neutral solution of a salt and water. This energy change is typically exothermic, meaning it releases heat.

The acid strength can have an effect on the enthalpy of neutralization. Generally, stronger acids have a more negative enthalpy of neutralization because they release more heat when they react with a base. This is because stronger acids donate their protons more readily to the base, resulting in a stronger electrostatic attraction between the resulting ions, and therefore a more exothermic reaction.

However, it is important to note that the effect of acid strength on enthalpy of neutralization is not the only factor affecting this energy change. Other factors that can influence the enthalpy of neutralization include the strength of the base, the concentration of the acid and base, and the specific reaction conditions, such as temperature and pressure.

(a) The minimum energy released for  electron and positron = 1.02 MeV

(b) The minimum energy released for muon and anti-muon = 106.1 MeV

(c) The minimum energy released for tau and anti-tau = 1775 MeV

(d) The minimum energy released for proton and anti-proton = 1876 MeV

(a) electron and positron

Rest  mass of electron and positron = 9.1×\(10^{-31}\)kg.

E = Δ\(mc^{2}\)

E = 2\(m_{0} c^{2}\)

  = 2 × 9.1×\(10^{-31}\) × (3×\(10^{8}\)) × (3×\(10^{8}\))

1 MeV = 1.602×\(10^{-13}\) J

So, E = 2 × 9.1×\(10^{-31}\) × (3×\(10^{8}\)) × (3×\(10^{8}\)) / 1.602×\(10^{-13}\)

E = 1.02 MeV

The minimum energy released for  electron and positron = 1.02 MeV

(b) muon and anti-muon

Rest  mass of muon and anti-muon = 1.89×\(10^{28}\)kg

E = Δ\(mc^{2}\)

E = 2\(m_{0} c^{2}\)

  = 2 × 1.89×\(10^{-28}\) × (3×\(10^{8}\)) × (3×\(10^{8}\))

1 MeV = 1.602×\(10^{-13}\) J

So, E = 2 × 1.89×\(10^{-28}\) × (3×\(10^{8}\)) × (3×\(10^{8}\)) / 1.602×\(10^{-13}\)

         = 17.01 × \(10^{-12}\)  / 1.602×\(10^{-13}\)  = 10.61 × 10

E = 106.1 MeV

The minimum energy released for muon and anti-muon = 106.1 MeV

(c)tau and anti-tau

Rest  mass of tau and anti-tau = 3.16×\(10^{-27}\)kg

E = Δ\(mc^{2}\)

E = 2\(m_{0} c^{2}\)

  = 2 × 3.16×\(10^{-27}\) × (3×\(10^{8}\)) × (3×\(10^{8}\))

1 MeV = 1.602×\(10^{-13}\) J

So, E = 2 ×3.16×\(10^{-27}\) × (3×\(10^{8}\)) × (3×\(10^{8}\)) / 1.602×\(10^{-13}\)

         = 28.44 × \(10^{-11}\)  / 1.602×\(10^{-13}\)  = 17.75 × \(10^{2}\)

E = 1775 MeV

The minimum energy released for tau and anti-tau = 1775 MeV

(d)  proton and anti-proton

E = Δ\(mc^{2}\)

E = 2\(m_{0} c^{2}\)

  = 2 × 1.67×\(10^{-27}\) × (3×\(10^{8}\)) × (3×\(10^{8}\))

1 MeV = 1.602×\(10^{-13}\) J

So, E = 2 ×1.67×\(10^{-27}\) × (3×\(10^{8}\)) × (3×\(10^{8}\)) / 1.602×\(10^{-13}\)

         = 30.06 × \(10^{-11}\)  / 1.602×\(10^{-13}\)  = 18.76 × \(10^{2}\)

E = 1876 MeV

The minimum energy released for proton and anti-proton = 1876 MeV

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Answer:

Physical changes

Explanation:

Changes in the state of matter are physical changes.

First, the material is made up of the same components that is was before it changed states.

The physical properties of the material changed, but its chemical composition did not, meaning that is is a physical change.

Answer:

Physical change

Explanation:

Matter can change between phases, so they are reversible physical changes that do not change matter’s chemical composition.

Changes of state are physical changes in matter. They are reversible changes that do not change matter’s chemical makeup or chemical properties. Water, for example, can be a solid (ice), a liquid (drinking water), or a gas (steam). Those are physical changes that don't change the fact that water is always chemically made up of H2O (two hydrogens and one oxygen).

Option (c) is correct. 3.80 x 10^24 atoms of oxygen are contained in 160 grams of N2O3. This is calculated by using the Avogadro's constant.

mass of N2O3 = 76.01 g/ mole

Moles of N2O3 = 160 grams / 76. 01 g/ mole

                          = 2.104

Mole can be defined as the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12.

moles of Oxygen = moles of N2O3 x number of oxygen atoms in N2O3

                             = 3 x 2.104  =6.315 moles

the atoms of oxygen = (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole

                                    =3.80 x 10^24 atoms

here used Avogadro's constant. Avogadro's constant is the proportionality factor that relates the number of constituent particles in a sample with the amount of substance in that sample. It is an SI defining constant with an exact value of 6.02214076×10²³ reciprocal moles.

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Answer:

this is your answer hope it helps you

Answer:

Explanation:

35.453 u

a. The Potential Energy (PE) of reactants is 250 KJ/mole. When the reactants are reacting, the Potential Energy is transformed into Kinetic Energy, which is also referred to as the Activation Energy (AE), and the PE of the products.

b. The potential energy diagram of the reaction is shown below. In this diagram, all axes, i.e. Y-axis (Potential Energy) and X-axis (reaction coordinates) have been labeled.

c. One may lower the activation energy (AE) of the reaction by using the following methods:

Temperature: The activation energy of an exothermic reaction decreases with increasing temperature.

Catalyst: A catalyst is a substance that reduces the activation energy of a reaction and increases the reaction rate. The catalyst's role is to provide a different reaction mechanism that has a lower activation energy.

Increasing the concentration of reactants: The rate of the reaction increases with an increase in the concentration of the reactants. Because an increase in the concentration of the reactants increases the frequency of their collisions, which also increases the chance of successful collisions.

Increasing surface area: The rate of the reaction also increases with an increase in the surface area of the reactants because more particles are exposed to collisions, which increases the frequency of successful collisions.

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Answer:

D

Explanation:

Oxygen is an element.

sugar is a hydrocarbon derivative.

water is a compound made of hydrogen and oxygen. There are no metals in it at all.

So you are left with Halite. The common name for halite is salt. The chemical formula is NaCl

Answer: D

Answer:

84400cg

Explanation:

100000 cg in 1kg

100000(8.44)=84400cg

Answer:

I think that the answer is N20:2(14.01)+1(16.06)=44.02g/mol(c) fluorine Di nitrogen monoxide contains how many mom 6.022 x

1023 mol N20

The mass (in grams) of a 0,500 M solution of sodium acetate, CH₃CO₂Na in water you would use to obtain 0.150 mol of sodium acetate is 12.30 grams.

To determine the mass of a 0.500 M solution of sodium acetate required to get 0.150 moles of sodium acetate, the following equation is used:

Mass = moles × molar mass

First, let's calculate the molar mass of sodium acetate:

Molar mass of Na: 22.99 g/mol

Molar mass of C: 12.01 g/mol

Molar mass of O: 16.00 g/mol

Therefore, the molar mass of sodium acetate: 22.99 + 3(12.01) + 2(16.00) = 82.03 g/mol

Now, using the equation above,

Mass = 0.150 mol × 82.03 g/mol

Mass = 12.30 g

Therefore, 12.30 grams of a 0.500 M solution of sodium acetate are required to get 0.150 moles of sodium acetate.

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To determine the pH of a solution using a pH indicator paper, you need a color chart or a color scale that corresponds to different pH values.

This color chart or scale is used to compare the color of the pH indicator paper after it has been immersed in the solution. The pH indicator paper is impregnated with a universal pH indicator, which is a chemical compound that changes color depending on the acidity or alkalinity of the solution.

The indicator undergoes a chemical reaction with the hydrogen ions (H+) or hydroxide ions (OH-) present in the solution, resulting in a color change.

By comparing the color of the pH indicator paper with the color chart or scale, you can determine the approximate pH of the solution. The color chart usually provides a range of colors corresponding to different pH values, allowing you to match the observed color to the nearest pH value.

In the hypothesis mentioned, the aim is to calibrate a cabbage pH indicator using the pH values obtained from a universal pH indicator. Therefore, in addition to the pH indicator paper and color chart, you would also need a range of solutions with known pH values to establish a calibration curve specific to the cabbage pH indicator.

In summary, to determine the pH of a solution using a pH indicator paper, you need a color chart or scale that correlates the observed color of the pH indicator paper with different pH values. This chart or scale serves as a reference for interpreting the color change and determining the pH of the solution.

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Answer: COLOR KEY

Explanation: CS

The balanced equation for the neutralization reaction between NaOH and H2SO4 can be given as follows: H2SO4 + 2NaOH → Na2SO4 + 2H2OThe stoichiometry of the reaction shows that 1 mole of H2SO4 reacts with 2 moles of NaOH.

We can calculate the moles of NaOH that reacted as follows:0.164 M NaOH = 0.164 moles/Liter

Therefore, the number of moles of NaOH present in 32.63 mL can be calculated as follows:

0.164 moles/L * 0.03263 L

= 0.00535 moles

Now we know that 0.00535 moles of NaOH were present in 25.00 mL of H2SO4. Since the stoichiometry shows that 1 mole of H2SO4 reacts with 2 moles of NaOH, we can calculate the number of moles of H2SO4 that were present in 25.00 mL of H2SO4 as follows:

0.00535 moles of NaOH * 1 mole of H2SO4/2 moles of NaOH

= 0.002675 moles of H2SO4

Now that we know the number of moles of H2SO4 present in 25.00 mL of solution, we can calculate the molarity of the solution as follows:

Molarity = Moles of solute/Volume of solution (in liters)

Molarity = 0.002675 moles/0.02500 Liters

= 0.107 M H2SO4

Therefore, the molarity of the H2SO4 solution is 0.107 M.

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