if the car rolls down the hill ( with engine off) with negligible friction and air resistance what will its kinetic energy be

Answer:

Hello, Yes i believe it would be a positive charge considering electrons have a negative charge while protons have a positive charge.

Explanation:

The irms at the resonance of the RLC series circuit is 0.494 A.

For the given RLC series circuit, the resonant frequency can be calculated using the formula:
fr = 1 / [2π √(LC)]
Where L is the inductance in henries, C is the capacitance in farads, and π is a mathematical constant approximately equal to 3.14.

Substituting the given values, we get:
fr = 1 / [2π √(3.00 mH x 5.00 μF)]
fr = 1 / [2π √(0.015 H x 0.000005 F)]
fr = 1 / [2π x 0.003]
fr = 53.05 Hz
Therefore, the resonant frequency of the RLC series circuit is 53.05 Hz.

To calculate the irms at resonance, we need to first find the impedance of the circuit at resonance, which is given by:
Z = √[R^2 + (ωL - 1/ωC)^2]
Where R is the resistance in ohms, L is the inductance in henries, C is the capacitance in farads, and ω is the angular frequency in radians per second, which is equal to 2π times the frequency in hertz.
Substituting the given values and using the resonant frequency found earlier, we get:
Z = √[(40.0 Ω)^2 + ((2π x 53.05 Hz) x 3.00 mH - 1/(2π x 53.05 Hz x 5.00 μF))^2]
Z = √[1600 + (318.39 - 597.89)^2]
Z = √[1600 + 58817.46]
Z = 242.43 Ω

Now, we can calculate the irms using the formula:
irms = vrms / Z
Substituting the given value of vrms and the calculated value of Z, we get:
irms = 120 V / 242.43 Ω
irms = 0.494 A

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Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to decrease in strength

The strength of the magnetic field produced by an electromagnet decreases as the distance from the electromagnet increases. This means that if the distance between the electromagnet and the compass increases, the magnetic field that the compass is experiencing will weaken.

As a result, the observed effect of the compass will decrease in strength as the distance between the electromagnet and the compass increases.

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The life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

The life expectancy of a star is determined by its mass and luminosity. The more massive and luminous the star is, the shorter its life expectancy is. Hence, using this information, we can estimate the life expectancy of the following stars:a) 0.2-solar mass, 0.01-solar luminosity red dwarfRed dwarfs are known to have the longest life expectancies among all types of stars. They can live for trillions of years.

Hence, a 0.2-solar mass, 0.01-solar luminosity red dwarf is expected to have a much longer life expectancy than the Sun. It could live for up to 10 trillion years or more.b) 3-solar mass, 30-solar luminosity starA 3-solar mass, 30-solar luminosity star is much more massive and luminous than the Sun. As a result, it will have a much shorter life expectancy than the Sun.

Based on its mass and luminosity, it is estimated to have a lifetime of around 10 million years.c) 10-solar mass, 1000-solar luminosity starA 10-solar mass, 1000-solar luminosity star is extremely massive and luminous. It will burn through its fuel much faster than the Sun, resulting in a much shorter life expectancy. Based on its mass and luminosity, it is estimated to have a lifetime of only around 10 million years as well.

Therefore, the life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

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One filter box will be required for the plant expansion, but an alternative design needs to be proposed if the design loading rate is exceeded with one filter box out of service.

To determine the number of filter boxes required, we need to calculate the total surface area required and divide it by the maximum surface area per filter box.

Calculate the total surface area required:

Total surface area = Design flow rate / Design loading rate

Total surface area = 1.2 m³/s × 24 × 3600 s / (575 m³/d × 1 d/24h)

Total surface area = 18.67 m²

Determine the number of filter boxes required:

Number of filter boxes = Total surface area / Maximum surface area per filter box

Number of filter boxes = 18.67 m² / 50 m²

Number of filter boxes = 0.37 (round up to the nearest whole number)

Number of filter boxes = 1 (since we cannot have a fraction of a filter box)

Therefore, one filter box will be required to meet the design loading rate.

To check the design loading with one filter box out of service, we need to recalculate the loading rate:

Calculate the new design loading rate:

New design loading rate = Design flow rate / (Number of filter boxes - 1)

New design loading rate = 1.2 m³/s / (1 - 1)

New design loading rate = Undefined

Since the new design loading rate is undefined when one filter box is out of service, an alternative design should be proposed to ensure that the design loading rate is not exceeded. This could involve increasing the number of filter boxes or redesigning the filtration system to accommodate the required flow rate.

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Answer:

You need the attachment, sorry I can't answer :(

Answer:

It is short thats what the awnser is

Answer:

I believe its C

Explanation:

Yes, there is a Gizmos lab available for students to explore the concept of nuclear decay. The Gizmos lab titled "Nuclear Decay" is part of the Physics curriculum and is designed to help students understand the process of radioactive decay and the concept of half-life.

In this lab, students are provided with a virtual simulation where they can observe the decay of radioactive isotopes over time. They can manipulate the initial quantity of the isotopes and observe how the decay occurs, leading to the formation of stable isotopes.

Students can also measure the half-life of different isotopes and analyze how the rate of decay changes over time.

The lab provides a hands-on and interactive learning experience, allowing students to visualize and explore the principles of nuclear decay.

It helps them develop a deeper understanding of concepts such as half-life, decay rates, and the role of isotopes in radioactive decay.

By engaging with this Gizmos lab, students can gain valuable insights into nuclear physics and its applications in various fields. They can analyze real-world scenarios, make predictions, and draw conclusions based on their observations.

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Answer:

Explanation:

No external force is acting on uranium nucleus so we can apply law of conservation of momentum . If M and m be the mass of bigger and smaller fragments respectively and V and  v be their velocity after fission , Total momentum after fission  = total momentum before fission

MV - mv = 0 , since the nucleus was at rest , its momentum before fission is zero . negative sign of mv is taken because smaller fragment  will move in opposite direction to that of bigger fragment .

MV = mv

M / m = v / V

M > m

Hence,

v > V

So velocity of smaller fragment will be higher .

Answer:

sorry I cannot give the answer I know only little bit about it

To calculate the kinetic energy of the car at point B, we first need to determine its velocity at that point. We can use the work-energy principle to relate the work done by the driving force to the change in kinetic energy of the car:

Work done by driving force = Change in kinetic energy

The work done by the driving force is equal to the product of the force and the displacement:

Work done = Force x Displacement = 66 MN x 150 m = 9.9 GJ

The change in kinetic energy is equal to the final kinetic energy minus the initial kinetic energy. Assuming the car starts from rest at point A, its initial kinetic energy is zero. Therefore, the final kinetic energy at point B is equal to the work done by the driving force:

Final kinetic energy = Work done = 9.9 GJ

Note that we converted the force to MN (meganewtons) and the energy to GJ (gigajoules) to match the SI unit system commonly used in physics calculations.

a. No, all of the heat that is added to the water while the water is boiling is converting the liquid state to the gas state.

When water reaches its boiling point, it undergoes a phase transition from the liquid state to the gaseous state. During this transition, the temperature of the water remains constant even though heat is continuously added to the system. This is because the heat energy is primarily used to overcome the intermolecular forces holding the water molecules together rather than increasing the average kinetic energy of the molecules.

In the liquid state, water molecules are held together by cohesive forces, such as hydrogen bonding. When heat is applied to the water, it increases the kinetic energy of the molecules, causing them to move faster. As the temperature of the water rises, the kinetic energy of the molecules increases, but the average potential energy due to intermolecular forces remains relatively constant.

Once the water reaches its boiling point, the added heat energy is used to break the intermolecular forces completely. As water molecules escape from the liquid surface and enter the gas phase, they take away energy in the form of latent heat of vaporization. This latent heat is used solely for the phase transition, and it does not contribute to an increase in temperature.

As a result, the temperature of the boiling water remains constant until all the liquid water has been converted into water vapor. Only after the phase transition is complete and all the water has evaporated will further heat addition lead to an increase in temperature.

Therefore, during the process of boiling, the water temperature does not change as the heat energy is primarily utilized for the conversion of the liquid state to the gas state.

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Answer:

Average velocity = 0.375 m/s

Explanation:

Average velocity = net displacement/total time

The penguin swims leftward 9m then dodges rightward another 12m. Let left side is negative and right side is positive.

Average velocity,

\(v=\dfrac{-9+12}{8}\\\\v=\dfrac{3\ m}{8\ s}\\\\v=0.375\ m/s\)

So, the penguin's average velocity during the chase is 0.375 m/s.

Answer:

Velocity=0.38

Speed=2.6

Explanation:

A slit separation of approximately 963 nm will produce first-order maxima at angles of ±45∘ from the incident direction when illuminated by laser light with a wavelength of 680 nm.

To determine the slit separation that will produce first-order maxima at angles of ±45∘ from the incident direction, we can use the equation for the position of the maxima:

d sinθ = mλ

where d is the slit separation, θ is the angle from the incident direction, m is the order of the maxima (in this case, m = 1), and λ is the wavelength of the laser light.

At first order, we have m = 1, θ = ±45∘, and λ = 680 nm. Substituting these values into the equation, we get:
d sin(45∘) = 1(680 nm)

Solving for d, we get:
d = λ / sin(θ)
d = 680 nm / sin(45∘)
d ≈ 963 nm

Therefore, a slit separation of approximately 963 nm will produce first-order maxima at angles of ±45∘ from the incident direction when illuminated by laser light with a wavelength of 680 nm.

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According to Newton's Third Law of Motion, the forces exerted by the car and the truck on each other when the car hits the large truck are equal. Despite the forces being equal, the truck, due to its larger mass, will experience less acceleration and appear to move less.

The subject you're asking about is a fundamental concept in Physics, specifically Newton's Third Law of Motion. According to Newton's Third Law of Motion, when a car hits a large truck, the forces they exert on each other are equal. This law states that 'For every action, there is an equal and opposite reaction.' Therefore, the correct statement is, 'The car and the truck exert equal forces on each other.' However, because the truck has a much greater mass than the car, it will feel less acceleration and appear to move less, even though the force exerted on it is equal to that exerted by it on the car.

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Answer:

3000g

hope this helps<3

We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec

Therefore

The Cart A wins the Race and by 25.5( 77.7-50)secs

From the question we are told

For Cart A

Generally the equation for the Velocity  is mathematically given as

\(v=\frac{d}{t}\\\\t=\frac{d}{v}\\\\t=\frac{1000}{20}\\\\t=50sec\)

For Cart B

Generally the Newtons equation for the Motion  is mathematically given as

\(S=ut+1/2at^2\\\\Therefore\\\\S=ut+1/2at^2\\\\1000=0+1/2*(0.33)t^2\\\\t=\frac{1000}{1/2*(0.33}}\\\\t=77.5secs\)

Since

Cart A spends t=77.5secs and Cart B spends t=50sec

Therefore

The Cart A wins the Race and by 25.5( 77.7-50)secs

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Answer:

Explanation:Digestive juices secreted by various organs such as salivary glands in the mouth, stomach, liver and pancreas help in the process of digestion of food. Saliva secreted by the salivary glands in the mouth aids in the breakdown of starch present in the food to simple sugar

The speed of sound in air on the day Mateo had a "harana" for Mae which had a temperature in the city of 40 °C is 355 m / s

v = 331 m / s + [ ( 0.6 m / s / C ) * T ]

T = Temperature

T = 40 °C

v = 331 m / s + [ ( 0.6 m / s / C ) * 40 ]

v = 355 m / s

The speed of sound in air formula used above is derived from the equation,

\(c_{air}\) = √ γ R T / M

\(c_{air}\) = Speed of air

γ = Adiabatic index

R = Gas constant

M = Molar mass

T = Temperature ( in K )

Therefore, the speed of sound in air is 355 m / s

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To determine the rate of heat input required to operate a unit, we need to consider the specific heat capacity of water and the desired temperature rise.

The specific heat capacity of water is approximately 4.18 J/g°C, which means it takes 4.18 Joules of heat energy to raise the temperature of 1 gram of water by 1 degree Celsius.

Let's assume we have a certain amount of water and we want to raise its temperature by a certain amount, ΔT. The equation for calculating the heat energy required is Q = m * c * ΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.

If we know the desired rate of heat input, we can express it in terms of power, which is the rate at which energy is transferred. Power is defined as the energy transferred per unit time, so we can calculate it using the equation P = Q / t, where P is the power, Q is the heat energy, and t is the time taken.

Therefore, the rate of heat input required to operate the unit can be calculated by dividing the desired power by the specific heat capacity of water.  

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Answer:

8.5m bcs you subtract 6.0m and 14.5m.

Answer:

Point 2.

Explanation:

Potential energy is simply defined as the energy stored in an object due to its position. It is can be represented mathematically by:

P.E = mgh

Where:

P.E is the potential energy.

m is the mass of the object.

g is acceleration due to gravity.

h is the height to which the object is located.

From the above equation, we can thus say that potential energy depends on the height of the object since the mass of the object is always constant i.e as the height of the object increase, the potential energy also increases and as the height of the object decrease, the potential energy also decreases.

Now, considering the diagram in the question given, we can see that point 2 is the lowest height to which the rider is located. At this point i.e point 2, the rider will have the least potential energy.

Answer: Point 2

Explanation:

To determine the resultant force, angle, and location, we need the magnitudes and directions of the three forces acting on the shaft, as well as their respective points of application. Without this information, it is not possible to provide a specific answer.

However, I can still provide a general explanation of how to find the resultant force, angle, and location. When multiple forces act on an object, the resultant force is the vector sum of all the individual forces. To calculate the magnitude of the resultant force, you would add the magnitudes of the individual forces. The angle between the resultant force and the x-axis can be determined using trigonometry.

The specification of where the force acts, measured from end B, would depend on the specific positions of the forces along the shaft. It would involve considering the distances from end B to the points of application of the forces and determining the resulting moment.

Please provide the magnitudes, directions, and points of application for the three forces so that I can assist you further in calculating the resultant force, angle, and location.

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Motor neurons are a type of nerve cell that transmit signals from the central nervous system to muscles or glands, resulting in movement or secretion. Among the neuron types you mentioned, the one often found to be a motor neuron is the multipolar neuron.

Multipolar neurons have multiple dendrites and a single axon, with the cell body located between them. These neurons are commonly found in the brain and spinal cord, where they serve as motor neurons responsible for controlling muscle contractions. By receiving signals from other neurons and sending them to muscles, multipolar motor neurons enable voluntary movements and reflexes.

In contrast, bipolar neurons have two processes extending from the cell body, unipolar neurons have a single elongated process, and anaxonic neurons lack a clearly distinguishable axon. However, these neuron types are typically associated with sensory processing rather than motor control.

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I'm guessing 6.

the coefficient of two turns our hydrogen into 4 and our oxygen into 2 which makes a total of 6 molecules.

Answer:

The distance between the 2 centers of the object.

Explanation:

If it's harder to win a super bowl for the rams than the gravity means the chiefs will win it.

The speed of the water leaving the nozzle can be determined by using the principle of conservation of mass. Since the volume of water flowing through the hose remains constant, the product of the cross-sectional area of the hose and the velocity of water remains the same.

Let's first find the cross-sectional area of the hose. The diameter of the hose is given as 2.74 cm, so the radius is half of that, which is 1.37 cm or 0.0137 m. The area of a circle is calculated using the formula A = πr^2, where π is approximately 3.14. Substituting the values, the cross-sectional area of the hose is A = 3.14 * (0.0137)^2 = 0.000592 m^2.

Next, we need to find the velocity of water when it is flowing through the hose without the nozzle. The volume of water filled in the bucket is given as 25 L, which is equivalent to 0.025 m^3. The time taken is given as 1.50 min, which is equivalent to 90 s. The velocity of water flowing through the hose is calculated using the formula v = Q / A, where Q is the volume of water and A is the cross-sectional area of the hose.

Substituting the values, the velocity is v = 0.025 m^3 / 0.000592 m^2 = 42.23 m/s.

Now, let's find the diameter of the nozzle. It is given as one-third the diameter of the hose. So, the diameter of the nozzle is 2.74 cm / 3 = 0.913 cm or 0.00913 m. The radius of the nozzle is half of that, which is 0.00457 m.

Finally, we can find the speed of the water leaving the nozzle.

Since the volume of water flowing through the hose remains constant, we can use the same formula v = Q / A, but this time A will be the cross-sectional area of the nozzle. The cross-sectional area of the nozzle can be calculated using the formula A = πr^2, where π is approximately 3.14 and r is the radius of the nozzle. Substituting the values, the cross-sectional area of the nozzle is A = 3.14 * (0.00457)^2 = 0.000066 m^2.

Now, we can calculate the speed of the water leaving the nozzle using the formula v = Q / A, where Q is the volume of water and A is the cross-sectional area of the nozzle. Substituting the values, the velocity is v = 0.025 m^3 / 0.000066 m^2 = 378.79 m/s.

Therefore, the speed of the water leaving the nozzle is approximately 378.79 m/s.

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The girl encounters a 9100 N average force to the west.

The interaction between two things or between an object and its surroundings is characterized by force, a physical quantity. It can be explained simply as the push or pull that one item applies to another.

An object's mass (m) multiplied by its velocity (v) will give it momentum (p):

p = mv

The girl's initial momentum is:

To the East, p1 = (35 kg)(4.5 m/s) = 157.5 kg*m/s

The girl strikes the tree and rebounded with a speed of 3.3 m/s to the west. Her final momentum (p2) can be found as follows:

To the West, p2 = (35 kg)(-3.3 m/s) = -115.5 kg*m/s

Thus, the girl's change in momentum (∆p) is: ∆p = p2 - p1 = -115.5 kgm/s - 157.5 kgm/s = -273 kg*m/s to the West.

We are aware that the time spent interacting with the tree was 0.03 seconds. Hence, using the impulse-momentum theorem, the girl's average force (F) can be calculated as follows:

F = Δp / Δt

F = (-273 kg*m/s) / (0.03 s) = -9100 N to the West

The force is acting in the opposite direction to the girl's starting velocity, which is to the east, as indicated by the force's negative sign. As a result, the girl encounters a 9100 N average force to the west.

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Answer:

Given

velocity( v) =3m/s

momentum (p) =9kg.m/s

mass (m) =?

Form

p=mv

m=p/v

(9kg.m/s) /3m/s

p=3kg

mass =3kg