if the chi-squared goodness-of-fit test is used with a significance of 0.05 to test whether random values have been appropriately generated by the device, what is the p-value of the test rounded to two places after the decimal, and what is the appropriate decision?

Answer:

The answer is 113.3

Step-by-step explanation:

We get this because he formula for the volume of a sphere is V = 4/3 πr³. 

The radius is 7.

7^3 = 243

243*4  = 972.

So, the asnwer is 972 ft^3

Given the sequence:

Let's find the third term of the sequence.

To find the third term, a3, we have:

First find the second term, a2:

The second term is -5.

To find the third term, we have:

Therefore, the third term of the

Answer:

it should be y=4x-14

Step-by-step explanation:

since the line is parallel to y=4x+1 than the slope should be the same but the y intercept is different. and so u put the coordinate on a graph and use the slope and coordinate to fine the equation.

If probability of winning a teddy bear at a carnival is 0.89 and 40 turns are taken, then he should have won about 35 teddy bears.

The probability of winning a teddy bear at a carnival is = 0.89, then

The probability of not winning a teddy bear is = 1 - 0.89 = 0.11,

We use binomial-distribution to calculate the probability of winning "k" teddy bears in "n" turns,

Where probability of winning (p) = 0.89,

The formula for the binomial distribution is,

⇒ P(k) = C(n,k) × p^k × (1-p)^(n-k),

The probability of winning "k" teddy bears in 40 turns is :

⇒ P(k) = C(40,k) × 0.89^k × 0.11^(40-k),

To find "expected-number" of teddy bears won, we multiply the probability of winning k teddy bears by k, and sum over all possible values of k,

⇒ E(number of teddy bears won) = \(\[ \sum_{k=0}^{40} \]\) k × P(k),

⇒ \(\[ \sum_{k=1}^{40} \]\) k × C(40,k) × 0.89^k × 0.11^(40-k),

On further solving ,

We get,

⇒ E(number of teddy bears won) ≈ 35.6,

Therefore, we expect to win about 35 teddy bears if we take 40 turns .

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Answer:

slope =m = -1/5

c = -6

y = mx+c

The cardinality of set F, which represents all functions from set A to set B is one-to-one and 25%.

In this case, set A has three elements, and for each element, there are two choices in set B. Therefore, the cardinality of F is given by \(|F| = |B|^{|A|} = 2^3 = 8\). To calculate the cardinality of the set G, which represents all one-to-one (injective) functions from set A to set B, we need to consider the number of possible injections. The first element in A can be mapped to any of the two elements in B, the second element can be mapped to one of the remaining elements, and the last element can be mapped to the remaining element. Thus, the cardinality of G is given by |G| = |B|P|A| = 2P3 = 2 × 1 × 1 = 2.

The probability of choosing a random function from A to B that is one-to-one can be calculated by dividing the cardinality of the set G by the cardinality of the set F. In this case, the probability is given by |G| / |F| = 2/8 = 1/4 = 0.25.

Therefore, the probability that a randomly chosen function from A to B is one-to-one is 0.25 or 25%.

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Answer:

A = 30°

x = 9·√3

Step-by-step explanation:

Part A

In the drawing, we are given;

The radius of the circle with center at point S = SA = 18

ΔAHA is a right triangle

One of the leg length of ΔASH = 9

The length of the hypotenuse side of ΔASH, AS = 18 The radius of the circle with center at the point 'S'

By Pythagoras's theorem, the length of the (radius) side, AS  = √(SH² + AH²)

∴ AH = √(AS² - SH²)

AH = √(18² - 9²) = √(243) = 9·√3

AH = 9·√3

By circle theorem, SH bisects the line AH extended to the circumference of the circle

SH bisects the line with length AH + x

∴ AH = x

x = AH = 9·√3

x = 9·√3

Part B

By trigonometric ratios, we have;

\(sin\angle A = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}\)

\(\therefore sin\angle A = \dfrac{9}{18} = \dfrac{1}{2}\)

∠A = arcsine (1/2) = 30°

Angle A = 30°

with alpha = .01 the two-tailed critical region for a t test using a sample of n = 16 subjects would have boundaries of -2.769 and 2.769

To calculate the critical region boundaries for a two-tailed t-test with alpha = 0.01 and n = 16 subjects, we need to use the t-distribution table. The table will give us the critical values for the given alpha level and sample size. In the t-distribution table, look up the row that corresponds to alpha = 0.01 and n = 16. This will give us the critical values, which in this case are -2.769 and 2.769. Therefore, the two-tailed critical region for a t-test using a sample of n = 16 subjects would have boundaries of -2.769 and 2.769.

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Answer:

y = 7/10

Step-by-step explanation:

1. Subtract 10 from both sides of the equation

2. Simplify

3. Subtract 5y from both sides of the equation

4. Simplify

5. divide both sides of the equation

6. simplify

7. solution

Your welcome!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

The y-intercept in the situation given represents: C. The amount of protein the feed has if no oats are added.

The y-intercept of a linear function is the initial value or the value of y when x equals 0.

The initial value in this situation is the amount of protein in the feed when the amount of oats added is 0.

Therefore, the y-intercept represents: C. The amount of protein the feed has if no oats are added.

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According to the information we can infer that Dora's conclusion may be incorrect because the information provided only states that the number of people who spent time reading falls within specific ranges (0-2 hours, 2-4 hours, and 2-10 hours), but it does not give a specific count for those who spent at least 4 hours. Therefore, Dora's assumption that "most people spent at least 4 hours a week reading" is not supported by the given data.

The range of the time spent reading cannot be determined from the information provided because the ranges are overlapping. For example, a person who spent exactly 2 hours reading could fall into both the first range (0-2 hours) and the second range (2-4 hours). Without more specific data or non-overlapping ranges, it is not possible to determine the exact range of time spent reading.

To estimate the mean time spent reading by Dora's friends, we can calculate the midpoint of each range and use it as an approximate value. The midpoint for the first range (0-2 hours) is 1 hour, for the second range (2-4 hours) is 3 hours, and for the third range (2-10 hours) is 6 hours. We can then calculate the estimated mean by taking the weighted average of these midpoints using the respective number of people as weights.

Estimated mean = [(4 * 1) + (5 * 3) + (11 * 6)] / (4 + 5 + 11) = 4.53 hours (approximately)

So, an estimate of the mean time spent reading by Dora's friends is approximately 4.53 hours.

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The structure of 12-crown-4 is shown below.

12-Crown-4, also known as lithium ionophore V and 1,4,7,10-tetraoxacyclododecane, is a crown ether with the chemical formula C8H16O4. It is a lithium cation-specific cyclic tetramer of the chemical compound ethylene oxide.

12-crown-4 combines with alkali metal cations, similar to other crown ethers. It has a strong selectivity for the lithium cation due to the cavity diameter of 1.2–1.5.

LiClO4 can be used as a template cation in a modified Williamson ether synthesis to create 12-Crown-4:

(CH2CH2O)4 + 2 NaCl + 2 H2O = (CH2OCH2CH2Cl)2 + (CH2OH)2 + 2 NaOH

In the presence of gaseous boron trifluoride, it can also result from the cyclic oligomerization of ethylene oxide.

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The proportion of rent that the friend with the smaller bedroom has to pay is 125/265. So his share of the rent is $540.35.

Suppose the distance from your house to your school is 2 miles, while the distance from your house to the nearest park is 3 miles.

Then we say that the ratio of the two distances s 2:3. To take another example suppose in today's hw, you have got 10 questions to answer, while in yesterday's hw you had 7 questions to answer. In this case we say that the ratio of the no of hw questions you have today, to the no questions you had yesterday is 10:7.

A ratio is a pair of numbers which gives the relative magnitudes of two similar quantities. A ratio of a:b is also represented by the fraction a/b.

Let us use the previous example. the ratio of the distances from your home to your school and to the nearest park is say 2:3 . Now consider the ratio of the time it takes to reach your school from your home by car to the time it takes to reach the park by car from your home. suppose this ratio a:b . Then it reasonable to assume that the two fractions a/b and 2/3 are equal, assuming the car moves at the same average speed.

This common ratio is called the proportion. we write it as follows,dist to school : dist to park : : time to school : time to park.

This is read as the distance to school IS TO distance to park AS time to school IS TO time to park.

if we write the ratios as fractions. Then they are proportional or equivalently they are the same proportion if and only if the two fractions are equal.

So The ratio of the bedroom sizes is 125 : 140.

Total rent that is to be divided between them is $1150.

if the share of the rents are a,b. then as fractions a/b = 125/140

So. a/a+b = 125/125+140 = 125/265

but a + b = 1150

So a = 125/265 (1150) = 542.452

The closest option is $540.35. So this is our answer.

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Answer:

⅑

Step-by-step explanation:

Let m represents number of males, and f represents number of females taking the maths course.

Given that number of males (m) taking the maths course is 8 times as much as number of females (f), total number of students taking the maths course (T).

Thus we can represent the information above with the following:

m = no. of males

f = no. of females

T = Total

m = 8f

T = m + f

Thus,

Total = 8f + f = 9f

==>The fraction of the course that are females = No. of females (f) ÷ Total no. of students (T)

= f/9f

Fraction of females in simplified form would be ⅑

The scouts are using quantitative analysis.

The length of the curve for t∈[0,1] is 4/9. To find the length of the curve defined by x(t)=\(2t^3\) and y(t)=\(4t^2\)+2, we need to use the arc length formula:

L = ∫√\((dx/dt)^2 + (dy/dt)^2\) dt from t=0 to t=1.
First, let's find dx/dt and dy/dt:
dx/dt = \(6t^2\)
dy/dt = 8t
Now we can plug these into the arc length formula:
L = ∫√\((6t^2)^2\)+ \((8t)^2\) dt from t=0 to t=1
L = ∫√(\(36t^4 + 64t^2\)) dt from t=0 to t=1
L = ∫√(\(4t^2(9t^2 + 16)\)) dt from t=0 to t=1
L = 2∫√(\(9t^2\) + 16) dt from t=0 to t=1
To integrate this expression, we can use a trig substitution. Let u = (3/4)\(t^2\) and du = (3/2)t dt. Then:
L = 2∫√(9(4/3)u + 16) (2/3) du from u=0 to u=3/4
L = (4/3)∫√(12u + 48) du from u=0 to u=3/4
L = (4/3)∫√(12(u + 4)) du from u=0 to u=3/4
L = (4/3)∫2√(u + 4) du from u=0 to u=3/4
L = (8/3)[(2/3)\((u + 4)^{(3/2)}\)] from u=0 to u=3/4
L = (8/3)[(2/3)\((3/4 + 4)^{(3/2)}\) - \((2/3)(4)^{(3/2)}\)]
L = (8/3)[(2/3)\((25/4)^{(3/2)}\) - (2/3)(8)]
L = (8/3)[(25√25)/6 - 16/3]
L = (8/3)(25/6 - 16/3)
L = (8/3)(1/6)
L = 4/9

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Answer:

25%

Step-by-step explanation:

12 hrs = 100%

=> 3 hrs = 3 : 12 = 25%

Answer: 400%

Step-by-step explanation:

12/3 = 4

Answer:

12 ft^3

Step-by-step explanation:

Given data

Dimension

Lenght= 2ft

Width= 3ft

Height= 2ft

The expression for the volume is

Volume= L*W*H

Substitute

V= 2*3*2

V= 12 ft^3

Hence the volume of the box is 12 ft^3

Answer:

The answer is D

Step-by-step explanation:

Because the whole length is 29.1 so you would subtract the part you have which is 16.8 so 29.1-16.8=12.3

Answer:

Option d) 2.1 + 2x = 7.5

Step-by-step explanation:

An isosceles triangle is a triangle with two equal sides.

Perimeter of a triangle is some of all the 3 sides.

Let the equal sides be x

Let the third side be y

Therefore,

              Perimeter = x + x + y

                         7.5 = 2x + y    

                          7.5 = 2x + 2.1                    [ given shortest side, y = 2.1m ]

There are approximately 11.25 cups of granulated sugar in a 5 pound bag.

To determine the number of cups of granulated sugar in a 5 pound bag, we can use the conversion factor of 2.25 cups per pound.

First, we multiply the number of pounds (5) by the conversion factor:

5 pounds * 2.25 cups/pound = 11.25 cups

Therefore, there are approximately 11.25 cups of granulated sugar in a 5 pound bag.

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Answer:

p is false and q is true

Step-by-step explanation:

bc it's equals to the right answer if u calculate

Answer:

D. P is false and Q is false

In 2001, 150 000 students were expected to enroll at the institution.

For the 2018 academic year, 468000 students are anticipated to enroll at the

The size of a population refers to its total number of members. The average person count per unit of area or volume is referred to as population density.

a. The formula to solve the question is as follows:

y = 123.1(1.069)x.

Hence x is the amount of time that was passed.

2001 - 1998 = 3y = 123.1 (1.069)³y

= 123.1 x  1.2216115y = 150.4

In 2001, the school is expected to have 150000 students enrolled.

b. 2018

The distinction x, or the variation between the years we are to calculate, must be considered:

x = 2018 - 1998

= 20.y = 123.1 x  (1.069)²⁰y

= 123.1 x  3.798y

= 467.5468

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Answer:

25 grams of protein

Step-by-step explanation:

10 grams of protein is in 1 cup of milk.

To understand how many grams of protein are in 0.5 cups of milk, I would need to divide 10 by 2, to get 5.

There are 5 grams of protein in 0.5 cups of milk.

Now if I want to see how many grams of protein are in 2 cups of milk, I would multiply 10 by 2, to get 20.

There are 20 grams of protein in 2 cups of milk.

But, the question is asking for how much protein is in 2.5 cups of milk.

Since we know how much is in 2 cups, and 0.5, we can just add them together, because 2+0.5 is 2.5.

20+5 is 25 grams.

There are 25 grams of protein in 2.5 cups of milk.

In this argument, the conclusion is supported by premises. Hence the statement is true and is an example of deductive argument.

The conclusion that Rick isn't a Raiders fan is supported by the premises that no members of the Edwards Country Club are Raiders fans and that Rick is a member of the Edwards Country Club. This is an example of a deductive argument, where the conclusion logically follows from the premises.

Hence, to say that in this argument conclusion is supported by premises is true. The conclusion "Rick isn't a Raiders fan" is supported by the premises 1) no members of the Edwards Country Club are Raiders fans, and 2) Rick is a member of the Edwards Country Club.

Note: The question is incomplete. The complete question probably is: 1. no members of the Edwards country club are raiders fans. 2. rick is a member of the Edwards country club. 3. so, rick isn't a raiders fan. in this argument, the conclusion is supported by premises. True or false.

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Answer:

A. 34,900

Good Luck!!

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ 

Answer:

A) 34,900

Step-by-step explanation:

When rounding to the nearest hundred, look at the TENS DIGIT of the number.

If that digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.

If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.

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Answer:

d

Step-by-step explanation:

hope this helps

Answer: The answer would be D) x²-12

explanation: Values mentioned in the form of table b are not a function. Option D is correct. Given that, Four functions in the tabulated options are given we have to find the one that is not a function. What are functions? Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable. Here, From observation Function mentioned in Tables A, C and D are proper functions because each of them has a relative and corresponding value of ordinate with respect to the abscissa. While in option B one of the abscissae gives two values of the ordinates but another abscissa relates to a single value. That is why Table in B does not represent the functions. Thus, values mentioned in the form of table b is not a function. Option D is correct.

Answer:

q¹²

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

(q⁶)²

Step 2: Simplify

q¹²

( q⁶)²

( use exponent rule ) multiply the exponents

q⁶ × ²

q¹²