If the current skatepark is 25 m by 25 m, the area is 625 \(m^2\).
Since the sides are equal in magnitude, we can say we have a square skatepark. Squares are 2-Dimensional shapes. It is quadrilateral with 4 equal sides and 4 equal angles of the magnitude of 90°
Area refers to a space occupied by a 2-Dimensional shape. The area of a square is expressed as
A = \(s^2\)
s is the side of a square
side of the square = 25 m
Area = 25 * 25
= 625 square meters.
Thus, the area of the skatepark comes out to be 625 square meters.
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Please help it’s timed
Answer: I THINK ITS D
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Write 3/15 3/7 3/21 3/8 3/11 in ascending order
Answer:
The sorted inputs in order from least to greatest is:
3/21 < 3/15 < 3/11 < 3/8 < 3/7
Step-by-step explanation:
Using the given inputs:
3/15 3/7 3/21 3/8 3/11
As the least common denominator (LCD) is: 9240
Rewriting as equivalent fractions with the LCD:
3/15 3/7 3/21 3/8 3/11
1848/9240 3960/9240 1320/9240 3465/9240 2520/9240
Sorting this table by the numerators of the equivalent fractions in order from least to greatest:
3/21 3/15 3/11 3/8 3/7
1320/9240 < 1848/9240 < 2520/9240 < 3465/9240 < 3960/9240
Therefore, the sorted inputs in order from least to greatest is:
3/21 < 3/15 < 3/11 < 3/8 < 3/7
T/F: a frequency polygon is a very useful graphic technique when comparing two or more distributions.
The statement ''A frequency polygon is a very useful graphic technique when comparing two or more distributions'' is true because a frequency polygon is a very useful graphic technique for comparing two or more distributions.
A frequency polygon is a line graph that shows the distribution of a dataset.
It is created by plotting the frequency of each data value or interval on the y-axis and the corresponding values or intervals on the x-axis, and then connecting the points with line segments.
By using frequency polygons, it becomes easy to compare the shapes and spread of two or more distributions. We can overlay different frequency polygons on the same graph and compare them.
This helps to identify similarities and differences between the data sets.
For instance, frequency polygons can help identify which data set has a higher mean or median, and which distribution has a greater variance.
In summary, frequency polygons are a useful visual tool for comparing distributions and identifying patterns in data.
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Write each number as a
power of 10.
100 = 10
Answer:
100 = 10²
Step-by-step explanation:
100 equals 10² because 10×10=100. Likewise, 10³ would be 1000 because 10×10×10=1000. I hope this makes sense.
2. Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft, what will the total area of the walkway be? Hint: Draw a picture!
can anybody help me
The area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.
What is the area of the rectangle?It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
The dimensions of the garden = 10 ft by 12 ft
Area = 10×12 = 120 square feet
The width of the walkway = 3 feet
If we create a walkway around the garden, it will be a rectangle around the garden.
So the dimensions for the bigger rectangle = (3+10+3) ft by (3+12+3) ft
Area of the bigger rectangle = 16×18 = 288 square feet
So the area of the walkway = 288 - 120 = 168 square feet
Thus, the area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.
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Helpppppp MEEEEE PLSSSS
Which is the approximate measure of angle yzx? 34.8° 39.4° 50.6° 55.2°
The measure of <YZX is 55.2 degree.
What is Trigonometry?The area of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms (csc).
Given:
XY= 12.4 cm, YZ= 15.1 cm
In right ΔXYZ with hypotenuse XZ and opposite side XY to ∠YZX then
Using the sine ratio
sin <YZX= 12.4/ 15.1
sin <YZX = 0.8211
<YZX= 55.2
Hence, the measure of <YZX is 55.2 degree
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Answer: 55.2
Step-by-step explanation: just took it
The temperature one night in Ulundi was measured at -1 °C. The temperature increased to 8 °C the next day. By how many degrees did the temperature rise?
The amount of degrees by which the temperature rose is; 9 °C
How to find the rise in temperature?A change in temperature simply tells us by how much a temperature increased or decreased as the case may be.
Now, we are told that the temperature one night in Ulundi was measured at -1 °C. Thus;
Initial temperature = -1 °C
Temperature on next day = 8 °C
Thus;
Increase in temperature = 8 - (-1) = 9 °C
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I'm been doing this question about an hour still can't solve so I really need your help! Really appreciate if u do :D
Explanation:
1 hat = 45 dollars
6 hats = 6*45 = 270 dollars
1 phone = 40 dollars
4 phones = 4*40 = 160 dollars
total = $270 + $160 = $430
Felicia spent a total of $430. Since this amount of money leaves her account, this means we write a negative sign out front to end up with the final answer of -430
In other words, her account balance went down by $430 which is why we use a negative. If someone gave her $430, then the answer would be positive.
Derek decides that he needs $184,036.00 per year in retirement to cover his living expenses. Therefore, he wants to withdraw $184036.0 on each birthday from his 66th to his 90.00th. How much will he need in his retirement account on his 65th birthday? Assume a interest rate of 5.00%.
Derek plans to retire on his 65th birthday. However, he plans to work part-time until he turns 71.00. During these years of part-time work, he will neither make deposits to nor take withdrawals from his retirement account. Exactly one year after the day he turns 71.0 when he fully retires, he will wants to have $2,742,310.00 in his retirement account. He he will make contributions to his retirement account from his 26th birthday to his 65th birthday. To reach his goal, what must the contributions be? Assume a 5.00% interest rate.
Derek needs to make contributions of approximately $21,038.34 per year from his 26th birthday to his 65th birthday in order to accumulate $2,742,310.00 in his retirement account by the time he fully retires.
To determine the amount Derek needs in his retirement account on his 65th birthday, we can use the concept of present value. Since he plans to withdraw $184,036.00 per year, starting from his 66th birthday until his 90th, the cash flows can be treated as an annuity. The interest rate is 5.00%, and the time period is 25 years (from 66 to 90). Using the formula for the present value of an annuity, we can calculate the required amount. The formula is:
PV = PMT * (1 - \((1 + r)^(-n)\)) / r
where PV is the present value, PMT is the annual withdrawal amount, r is the interest rate per period, and n is the number of periods.
Plugging in the values, we get:
PV = $184,036.00 * (1 - \((1 + 0.05)^(-25)\)) / 0.05 ≈ $2,744,607.73
Therefore, Derek needs approximately $2,744,607.73 in his retirement account on his 65th birthday to cover his desired annual withdrawals.
Moving on to the second part, Derek plans to make contributions to his retirement account from his 26th birthday to his 65th birthday. To reach his goal of having $2,742,310.00 in his retirement account after fully retiring, we can calculate the necessary contributions using the formula for the future value of an ordinary annuity:
FV = PMT * \(((1 + r)^n\) - 1) / r
Rearranging the formula, we can solve for the required contributions (PMT):
PMT = FV * (r / (\(((1 + r)^n\) - 1))
Plugging in the values, we get:
PMT = $2,742,310.00 * (\(\frac{0.05} {((1+0.05)^{39}-1 )}\))≈ $21,038.34
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product of x and y divided by the difference of a and b
Answer:
x*y/a-b
Step-by-step explanation:
How do you convert millimeters to centimeters?
Millimeters can be converted into centimeters by dividing the value by 10. The solution has been obtained by using the unit conversion.
What is unit conversion?
A unit conversion is used to express the same property in a different unit of measurement. For instance, you could use minutes instead of hours to represent time or feet instead of miles to indicate distance. It commonly occurs when measurements are provided in one system of units, such as feet, but are required in a different system, such as chains.
We are required to convert millimeters to centimeters.
We know that 1 centimeter = 10 millimeters
So, for converting millimeters to centimeters, we need to divide the value by 10.
Hence, millimeters can be converted into centimeters by dividing the value by 10.
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One kilogram is 2.2 pounds. Complete the tables. What is the
interpretation of the constant of proportionality in each case?
What is the dot product of vectors u = <-5, 4> and v=<-8, -6>?
Answer:
16
Step-by-step explanation:
dot product = x1x2 + y1y2
= (-5)(-8 + (4)(-6)
= 40 - 24
= 16
A student graphed f(x) = x and g(x) = f(x) + 3 on the same coordinate grid. Which statement describes how the graphs of f and g are related?
The graph of f(x) = x is a straight line that passes through the origin and has a slope of 1. When g(x) = f(x) + 3, the entire graph of f(x) is shifted vertically upward by 3 units. This means that every point on the graph of f(x) is now 3 units higher on the y-axis.
Therefore, the graph of g(x) is also a straight line with the same slope as f(x) but with a y-intercept of 3. In other words, g(x) is f(x) shifted up by 3 units. Thus, the graphs of f(x) and g(x) are related by a vertical shift of 3 units on the coordinate grid.
The graphs of f(x) = x and g(x) = f(x) + 3 on the same coordinate grid are related as follows: The graph of g(x) is a vertical translation of the graph of f(x) by 3 units upwards. This means that each point on the graph of f(x) is shifted 3 units up to form the graph of g(x). The student plotted both graphs on the grid and noticed that the slope and the shape of the graphs are the same, indicating a direct relationship between the two functions. The key difference is the vertical position of the graphs due to the added constant in g(x).
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find the value of 8x+8 given that -3x+1=4. simplify as much as you can
after performing polynomial long division, the answer may be checked by multiplying the divisor, quotient, remainder, and then adding the quotient. dividend. remainder. divisor. this should give the remainder. quotient. divisor. dividend.
The answer can be checked by multiplying the divisor, quotient, and remainder, and then adding the quotient to the result.
After performing polynomial long division, the answer may be checked by following these steps:
1. Multiply the divisor by the quotient obtained from the division.
2. Add the obtained product to the remainder.
3. The result should be equal to the dividend.
In other words, you can check the answer by multiplying the divisor, quotient, and remainder, and then adding the quotient to the result.
This should give you the dividend.
To explain this step-by-step:
1. Perform the polynomial long division to obtain the quotient and remainder.
2. Multiply the divisor by the quotient obtained in the division.
3. Add the obtained product to the remainder.
4. The result should be equal to the dividend.
Remember to follow the correct order: multiply the divisor by the quotient first, and then add the remainder.
This method allows you to verify the correctness of the division.
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i need help solving the first problem
Answer:
f(x), g(x)10, 0, UNDEFINEDStep-by-step explanation:
You want to know which functions have 5 in their domain, and what the function value is at x=5.
f(x) = x² -3xg(x) = (x -5)/xh(x) = √(x -10)ValuesIt is more convenient to do the second part first, as that tells you the answer to the first part:
f(5) = 5² -3·5 = 25 -15 = 10 . . . . 5 is in the domain
g(5) = (5 -5)/5 = 0/5 = 0 . . . . 5 is in the domain
h(5) = √(5 -10) = √(-5) . . . . UNDEFINED; 5 is not in the domain
Describe and correct the error in solving the equation. 40. -m/-3 = −4 ⋅ ( − m — 3 ) = 3 ⋅ (−4) m = −12
Answer:
m = -36/11
Step-by-step explanation:
Start with the equation: -m/-3 = −4 ⋅ ( − m — 3 )
2. Simplify the left side of the equation by canceling out the negatives: -m/-3 becomes m/3.
3. Simplify the right side of the equation by distributing the negative sign: −4 ⋅ ( − m — 3 ) becomes 4m + 12.
after simplification, we have: m/3 = 4m + 12.
Now, let's analyze the error in this step. The mistake occurs when distributing the negative sign to both terms inside the parentheses. The correct distribution should be:
−4 ⋅ ( − m — 3 ) = 4m + (-4)⋅(-3)
By multiplying -4 with -3, we get a positive value of 12. Therefore, the correct simplification should be:
−4 ⋅ ( − m — 3 ) = 4m + 12
solving the equation correctly:
Start with the corrected equation: m/3 = 4m + 12
To eliminate fractions, multiply both sides of the equation by 3: (m/3) * 3 = (4m + 12) * 3
This simplifies to: m = 12m + 36
Next, isolate the variable terms on one side of the equation. Subtract 12m from both sides: m - 12m = 12m + 36 - 12m
Simplifying further, we get: -11m = 36
Finally, solve for m by dividing both sides of the equation by -11: (-11m)/(-11) = 36/(-11)
This yields: m = -36/11
What is the value of n in the equation -1/2 (2n + 4) + 6 = -9 + 4(2n + 1)?
n =
Answer:
n=1
Step-by-step explanation:
Answer:
n=1
Step-by-step explanation:
Joan has q quarters, d dimes,and n nickels in her pocket. Howmany coins does she have?Enter a, b, c, d, or e.a. q + d + nb. 5q + 2d+nc. .25q+.10d + .05nd. (25+10+5)(q + d + n)e. 25g + 10d + 5n
Given that Joan has "q" quarters, "d" dimes, and "n" nickels in her pockets, you can determine that the total number of coins she has in her pockets is the sum (the result of an Addition) of all the quarters, dimes, and nickels she has in it.
Therefore, knowing that the given variables represent the number of each type of coin, you can write the following Addition of variables, in order to represent the total number of them:
\(q+d+n\)Hence, the answer is: Option a.
1. If f(x) = (3x-2)/(2x+3), then f'(x) =
Answer:
\(f'(x)= \frac{13}{(2x+3)^2}\\\)
Step-by-step explanation:
\(f(x)= \frac{3x-2}{2x+3} \\\)
\(f'(x)=\frac{dy}{dx} = \frac{d}{dx}(\frac{3x-2}{2x+3})\\ f'(x)= \frac{(2x+3)\frac{d}{dx}(3x-2)-(3x-2)\frac{d}{dx}(2x+3) }{(2x+3)^{2} } \\f'(x)= \frac{(2x+3)(3)-(3x-2)(2)}{(2x+3)^{2} } \\\)
\(f'(x)= \frac{6x+9-6x+4}{(2x+3)^{2} }\\ f'(x)= \frac{13}{(2x+3)^2}\\\)
Difference between trigonal planar and trigonal pyramidal.
The main difference between trigonal planar and trigonal pyramidal is in their molecular geometry and the arrangement of atoms or groups around a central atom.
In trigonal planar geometry, the central atom is surrounded by three bonding pairs of electrons, resulting in a flat, triangular arrangement. All the bond angles in a trigonal planar molecule are 120 degrees. Examples of molecules with trigonal planar geometry include boron trifluoride (BF3) and formaldehyde (CH2O).
On the other hand, in trigonal pyramidal geometry, the central atom is surrounded by three bonding pairs of electrons and one non-bonding pair (lone pair) of electrons. This arrangement leads to a three-dimensional shape resembling a pyramid, with the lone pair occupying more space than the bonding pairs. The bond angle between the three bonding pairs in a trigonal pyramidal molecule is less than 109.5 degrees due to the repulsion from the lone pair. Ammonia (NH3) and phosphine (PH3) are examples of molecules with trigonal pyramidal geometry.
In summary, the key distinction between trigonal planar and trigonal pyramidal is the presence of a lone pair of electrons on the central atom in trigonal pyramidal geometry, which gives rise to a three-dimensional pyramidal shape. Trigonal planar molecules, in contrast, lack a lone pair and exhibit a flat, triangular arrangement.
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Find the exact value of the quantity in the interval (0,π).
arccos (1/2) ......rad
The exact value of the expression arccos(1/2) in the interval (0, π) is π/3 radians. The expression arccos(1/2) represents the angle whose cosine is equal to 1/2. In the interval (0, π), this corresponds to the first quadrant where the cosine function is positive.
The value 1/2 is commonly associated with the angle π/3 radians, which is exactly 60 degrees. To understand why π/3 radians is the value for arccos(1/2), we can look at the unit circle. The unit circle is a circle with a radius of 1 centered at the origin (0, 0) on the Cartesian plane. The cosine of an angle in the unit circle is equal to the x-coordinate of the point where the terminal side of the angle intersects the unit circle.
In this case, the cosine of π/3 radians is equal to 1/2 because the x-coordinate of the corresponding point on the unit circle is 1/2. Since the interval specified is (0, π), we only consider the angles in the first quadrant, and π/3 radians is the angle in that range whose cosine is 1/2.
Therefore, the exact value of arccos(1/2) in the interval (0, π) is π/3 radians.
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A machine consists of two components, whose lifetimes have the joint density function f(x, y) = {1/162 x > 0, y > 0, x + y < 18; 0 otherwise The machine operates until both components fail. Calculate the expected operational time of the machine.
The expected operational time of the machine is 6.75
For given x , y > 0 , the lifetime of the machine is max{x , y} because it stops when the two component will fail.
The life expectancy if therefore the expectancy of max{x, y}
t = E [ max{x,y} ]
So, the max{x , y} can be x or y
We have three integral
I₁ = \(\frac{1}{162}\int\limits^9_0 \, dx \int\limits^{18-x}_{x} y \. dy\)
Solving the integration
=> I₁ = 729 / 162
=> 4.5
I₂ = \(\frac{1}{162}\int\limits^9_0 \, dx \int\limits^{x}_{0} y \. dy\)
=> I₂ = 121.5/162
=> 0.75
=> I₃ = \(\frac{1}{162}\int\limits^9_0 \, dx \int\limits^{18-x}_{x} x \. dy\)
=> I₃ = 243 / 162
=> 1.5
So . the total is 4.5 + 0.75 + 1.5
=> 6.75 is expected operational time
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Solve for z and 45+Z, Thank you!
Answer:
first I added all numbers together including 45. and I got 252. then I subtracted 252 from 360 and got 108. then I decided 108 by 2 and got 54. then I checked so I think answer is 54
There are 120 wooden roller coasters in operation.This value represents 15% of all the roller coasters.How many roller coasters are there?HELPPPPPP MEEEEEE also PLEASEE include an explanation
Answer:
800 roller coasters
Step-by-step explanation:
120/x = 15/100
120/x=15 x 8/100 x8
120/x = 120/800
x=800
Solve for x.
2/5 (x - 9/10) =- 2 3/4
Answer:
x = -5.975
Step-by-step explanation:
distribute first by multiplying 2/5 by 'x' and then by 9/10 to get:
2/5x - 18/50 = -2 3/4
next, change -2 3/4 into an improper fraction to get:
2/5x - 18/50 = -11/4
now add 18/50 to -18/50 and to -11/4 using a common denominator of 100
2/5x = -275/100 + 36/100
2/5x = -239/100
multiply each side by 5/2 to isolate 'x':
x = -239/100 · 5/2
x = -1195/200
now simplify:
x = -5.975
Which number gives the exact value of 4 5/6
The number that gives the exact value of 4 5/6 is 29/6
How to determine the number that gives the exact value of 4 5/6?The number is given as:
Number = 4 5/6
Convert the above number to improper numbers
Number = 29/6
Hence, the number that gives the exact value of 4 5/6 is 29/6
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Carlisle Transport had $4,520 cash at the beginning of the period. During the period, the firm collected $1,654 in receivables, paid $1,961 to supplier, had credit sales of $6,916, and incurred cash expenses of $500. What was the cash balance at the end of the period?
To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.
Starting cash balance: $4,520
Cash inflows: $1,654 (receivables collected)
Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)
Total cash inflows: $1,654
Total cash outflows: $1,961 + $500 = $2,461
To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:
Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows
Cash balance at the end of the period = $4,520 + $1,654 - $2,461
Cash balance at the end of the period = $4,520 - $807
Cash balance at the end of the period = $3,713
Therefore, the cash balance at the end of the period is $3,713.
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