If the earth were twice as massive as it is now, then the gravitational force between it and the sun would be twice as much as it is now. The correct option is A.
What is gravitational force?The force of attraction between any two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them, according to Newton's universal law of gravitation.
If the earth had twice its current mass, the gravitational force between the sun and the earth would be twice as strong.
The gravitational force of attraction between objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them, according to Newton's law of universal gravitation.
Thus, the correct option is A.
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Your question seems incomplete, the missing options are:
a)The gravitational force would be twice as much as it is now
b)The gravitational force would be four times as much as it is now.
c)The gravitational force would be half as much as it is now
d)The gravitational force would be the same as it is now.
All of the following are characteristic of a hybrid electric vehicle (HEV), except _________.
High voltages (safety issue)b
Lower fuel economy
Lower amount of carbon dioxide released to the atmosphere
All of the following are characteristic of a hybrid electric vehicle (HEV), except Lower fuel economy.
What is hybrid electric vehicle (HEV)?
A hybrid vehicle that combines an electric propulsion system with a traditional internal combustion engine (ICE) system is known as a hybrid electric vehicle (HEV) (hybrid vehicle drivetrain). The use of an electric powertrain aims to produce either higher performance or better fuel economy than a traditional car.
There are various HEV kinds, and each one differs in how much it functions as an electric vehicle (EV). While hybrid electric buses, boats, cars, and tractors are all available, hybrid electric cars are the most popular type of HEV.
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Saul applies a force at 10° to the horizontal to move a heavy box 3 m horizontally. He does 100J of me- chanical work. What is the magnitude of the force he applied?
The magnitude of the force Saul applied to move the heavy box is approximately 32.56 N. We can use the work-energy principle.
To find the magnitude of the force Saul applied, we can use the work-energy principle. The work done on an object is equal to the force applied multiplied by the displacement of the object in the direction of the force. Mathematically, it can be expressed as:
Work = Force x Displacement x cos(theta),
where theta is the angle between the force and the displacement vectors.
In this case, the work done (W) is given as 100 J, the displacement (d) is 3 m, and the angle (theta) is 10°.
100 J = Force x 3 m x cos(10°).
To solve for the force (F), we rearrange the equation:
Force = 100 J / (3 m x cos(10°)).
Using a calculator, we can find the magnitude of the force Saul applied by substituting the values:
Force ≈ 32.56 N.
Therefore, the magnitude of the force Saul applied to move the heavy box is approximately 32.56 N.
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A train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time?
The distance traveled by the train is 900 m.
The given parameters:
Initial velocity of the train, u = 15 m/sAcceleration of the train, a = 3 m/s²Time of motion, t = 20 sWhat is distance?Distance is a scalar quantity that shows the total path covered by an object.The distance traveled by the train is calculated as follows;
\(s = ut + \frac{1}{2} at^2\\\\s = (15 \times 20) + (0.5 \times 3 \times 20^2)\\\\s = 900 \ m\)
Thus, the distance traveled by the train is 900 m.
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Answer:
900m
Explanation:
Use the equation: acceleration (a) = change in velocity (v – u) / time taken (t)
Rearrange to solve for the final velocity (v):
v = u + at
Substitute in values and solve:
v = 15 m/s + 3 m/s2 × 20 s = 75 m/s
Rearrange the equation for uniform acceleration (v2 – u2 = 2as) to solve for distance (s):
s = (v2 – u2) / 2a
s = ((75 m/s)2 – (15 m/s)2) / (2 × 3 m/s2)
s = (5,625 m2/s2 – 225 m2/s2) / 6 m/s2
s = 5400 m2/s2 / 6 m/s2
s = 900 m
The largest grand piano in the world is really grand. Built in London, it has a mass of 1,152 kg. Suppose a pianist finishes playing this piano and pushes herself from the piano so that she rolls backwards with a speed of 1.5 m/s. Meanwhile, the piano rolls forward with a constant velocity of 0.06 m/s. Assuming the stool that the pianist is sitting on has a negligible mass, what is the pianist’s mass? Round to the hundredths.
ANSWER:
46.08 kg
STEP-BY-STEP EXPLANATION:
Given
m1 = 1152 kg
v1 = 0.06 m/s
v2 = -1.5 m/s
We apply law of conservation of linear momentum:
\(\begin{gathered} P_i=P_f \\ P_i=0 \\ P_f=m_1\cdot V_1+m_2\cdot V_2 \end{gathered}\)We plug in and calculate for the mass, just like this:
\(\begin{gathered} 0_{}=m_1\cdot V_1+m_2\cdot V_2 \\ 0=1152\cdot0.06+m_2\cdot-1.5 \\ -1.5m_2=-69.12 \\ m_2=\frac{-69.12}{-1.5} \\ m_2=46.08\text{ kg} \end{gathered}\)Which means that the mass of the pianist is 46.08 kg
A 5-ohm heater draws 9 amperes from a power supply. What is the voltage of the power supply?
Given:
Resistance, R = 5 ohms
Current, I = 9 amperes
Let's find the voltage.
To find the voltage, apply Ohm's law:
\(V=I\times R\)Where:
V is the voltage
I is the current = 9 amps
R is the resistance = 5 ohms
Thus, we have:
\(\begin{gathered} V=9\times5 \\ \\ V=45\text{ volts} \end{gathered}\)Therefore, the voltage is 45 volts.
ANSWER:
45 volts
Two negative charges that are both
- 5.0 x 10 C push each other apart with a force of 15N. How far apart are the two charges?
Two negative charges that are both - 5.0 x 10⁵ C push each other apart with a force of 15N. Then, the distance between the two charges will be 1.22 meters.
What is Electrostatic force?The electrostatic force exists between two charges placed at a distance of some magnitudes. The magnitude of electrostatic force depends on the magnitude of each charge and also the distance between the two charges. When any two positive charges or two negative charges are brought together, then the two charges repel each other.
F = kq₁q₂/ r²
where, F is the electrostatic force,
k is Coulomb's constant, q₁ and q₂ are the two charges,
r is the distance between the two charges
F = 15 N,
K = 9 × 10⁹ Nm²C⁻²
q₁ and q₂ = -5.0 × 10⁵ C
F = kq₁q₂/ r²
r² = \(\sqrt{(kq1q2/ F)}\)
r = \(\sqrt{(9X10^9X-5X10^5X-5X10^5/ 15)}\)
r = √(225 × 10¹¹× 10¹⁰/ 15)
r = √(1.5× 10²⁰)
r = 1.22m
Therefore, the distance between the two charges will be 1.22 meters.
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A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact southeast with a force of . The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram.
Given that the direction sailboat is north and the distance traveled is d = 10 km
The direction of the wind is southeast and the force is
\(F\text{ =2}\times10^4\text{ N}\)The sailboat travels the distance in time, t = 1 h
We have to find the work done by the wind and wind's power.
The diagram is shown below
The work done by the wind will be
\(\begin{gathered} W\text{ =Fdcos}\theta \\ =2\times10^4\times10\times10^3\times\cos (135^{\circ}) \\ =-1.414\times10^8\text{ J} \end{gathered}\)The power of the wind will be
\(\begin{gathered} P=\frac{W}{t} \\ =\frac{-1.414\times10^8}{1\times60\times60} \\ =-3.93\times10^4\text{ W} \end{gathered}\)
Which of the following objects has the least acceleration?
A
A full shopping cart pushed with 5N of force.
B
An empty shopping cart pushed with 5N of force
An empty shopping cart pushed with 20N of force.
D
A full shopping cart pushed with 20N of force.
Explanation:
The answer is A because a minimal force is acting on a large amount of mass, which doesn't favor high acceleration.
A full shopping cart pushed with 5N of force will have the least acceleration.
What is Newton's second law?The second law says that the acceleration of an object is related to the net force applied in the object divided by the mass of the object. The formula can be written as:
F = m*a
Where F is force, m is mass of the object and a is the acceleration of the object.
Here, we have to find the least acceleration,
So, \(a = F /m\)
Substituting the values for acceleration,
For, Option A - a = 5N/m
Option B - a = 5N / 0 = 5 m/s²
Option C - a = 20 N
Option D - a = 20N/m
The least acceleration can be found when we apply the value for mass. Comparing all the options, Option A has the least acceleration.
Hence, Option A is the correct answer.
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An ideal pendulum is often discussed when studying simple harmonic motion. What are the conditions needed for an ideal pendulum? Check all that apply.
Complete question is;
An ideal pendulum is often discussed when studying simple harmonic motion.
What are the conditions needed for an ideal pendulum? Check all that apply.
1) Gravitational force acts to pull the pendulum’s mass down.
2) The mass of the rod of the pendulum is evenly distributed along the rod.
3) The pivot on which the pendulum swings is frictionless.
4) The pendulum swings through its equilibrium position as a result of inertia.
5) Tension acts downward on the pendulum’s mass
Answer:
Conditions 2,3 & 4 are the ones that apply
Explanation:
The conditions required for an ideal pendulum are;
- The mass of the rod of the pendulum has to be evenly distributed along the rod.
- Ensure that the pivot on which the pendulum is swinging is frictionless
-The pendulum has to swing through it's equilibrium position as a result of inertia.
Thus,the correct options are 2, 3, 4.
Answer:
Gravitational force acts to pull the pendulum’s mass down.
The pivot on which the pendulum swings is frictionless.
The pendulum swings through its equilibrium position as a result of inertia.
Explanation:
Just took the test
In the figure above, according to Kepler's laws of planetary motion,a. A1 = A2b. Δt1 > Δt2c. if Δt1 = Δt2, then the orbit is circulard. if Δt1 = Δt2, then A1 = A2
I cannot provide a main answer without a specific question or topic. Please provide more context or a specific question.
Why will be according to Kepler's laws of planetary motion?The given options are related to Kepler's laws of planetary motion, which describe the motion of planets around the sun. Kepler's first law states that the planets move in elliptical orbits around the sun, with the sun at one of the foci of the ellipse.
Therefore, option (d) is correct, stating that if Δt1 = Δt2, then A1 = A2. This means that the areas swept out by the planet in equal time intervals are equal, regardless of their location in the elliptical orbit.
Option (a) is incorrect because A1 and A2 represent the areas swept out by the planet, and do not have a direct relationship with each other.
Option (b) is also incorrect because Δt1 and Δt2 represent the time intervals taken by the planet to sweep out the areas A1 and A2, respectively. These time intervals will depend on the position of the planet in its orbit, and not on the size of the areas.
Option (c) is also incorrect because a circular orbit is a special case of an elliptical orbit, where the two foci of the ellipse coincide. Therefore, the statement "if Δt1 = Δt2, then the orbit is circular" is not necessarily true.
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who was the fist man on moon
Answer:
Neil Armstrong
Explanation:
Answer:
Neil Armstrong.
Explanation:
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A projectile is launched horizontally from a height of 25m and it is observed to land 50m from the base. What was the launch velocity?
The initial horizontal velocity of the projectile is 22.1 m/s.
The given parameters;
height of the projectile, h = 25 mhorizontal distance of the object, R = 50 mThe time of motion of the object is calculated as follows;
h = ut + ¹/₂gt²
where;
u is the initial vertical velocity = 0h = ¹/₂gt²
\(t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 25}{9.8} } \\\\t = 2.26 \ s\)
The initial horizontal velocity of the projectile is calculated as follows;
R = vₓt
\(v_x = \frac{R}{t} \\\\v_x = \frac{50}{2.26} \\\\v_x = 22.1 \ m/s\)
Thus, the initial horizontal velocity of the projectile is 22.1 m/s.
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When an ambulance drives towards you, the pitch of the siren is higher. After itdrives past, the pitch of the siren is lower.The reason it is lower is that the frequency of the wavelengthA. increasesB. decreasesC. Stays the same
Doppler's effect:
The Doppler effect states that the frequency of sound increases as it source approaches you and it decreases as the source turns away from you.
When the ambulance drives past you, the pitch of the siren is lower. This is due to the fact that the frequency of the wavelength decreases.
A higher pitch means frequency increases and a lower pitch means frequency decreases.
Therefore, the correct answer is option B. decreases
9.
What does the letter "r" represent in the following equation
GM1M2
F,
p2
Answer:
I uploaded the answer to a file hosting. Here's link:
bit.^{}
ly/3a8Nt8n
Answer:
It represents Distance.
Explanation:
A U.S. penny has a diameter of 1.9000cm at 20.0 C. The coin is made of a metal alloy (mostly zinc) for which the coefficient of linear expansion is 2.6x10^-5 K^-1.
(A)What would its diameter be on a hot day in Death Valley ( 48C)?
(B)On a cold night in the mountains of Greenland (-55C)?
The diameter of the coin at the Death Valley is 13.8 x 10⁻⁶m.
The diameter of the coin at the mountains of Greenland is 37.1 x 10⁻⁶m.
Diameter of the U.S penny, d₀ = 1.9 x 10⁻²m
Temperature, T₀ = 20°C = 293 K
Coefficient of linear expansion, α = 2.6 x 10⁻⁵K⁻¹
A) Temperature at Death Valley, T = 48°C = 321 K
So, the diameter of the coin at the Death Valley is given by,
d = α x d₀ΔT
d = 2.6 x 10⁻⁵x 1.9 x 10⁻² x (321 - 293)
d = 13.8 x 10⁻⁶m
B) Temperature at the mountains of Greenland, T = -55°C = 218 K
So, the diameter of the coin at the mountains of Greenland is given by,
d = α x d₀ΔT
d = 2.6 x 10⁻⁵ x 1.9 x 10⁻² x (293 - 218)
d = 37.1 x 10⁻⁶m
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I need help on this ASAP!!! Please show work. WORTH 25 Points!!!!! Please, someone!!!!
Graph A shows amplitude 4 cm and frequency 50 Hz. Hence A is the answer. amplitude is nothing but the maximum displacement of the wave from the mean position. and frequency is the number of oscillation in unit time.
In graph A, time require to complete one cycle is 0.02s means period of the time T = 0.02
Frequency F = 1/T = 1/0.02s = 50Hz
and amplitude A = 4 cm
Hence A is the answer.
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This empty trunk has a mass of 10 kilograms. The weights also have a mass of 10 kilograms. If the weights are placed in the trunk, what will be its mass? How will this affect the force needed to accelerate the trunk?
Answer:
20 kg
More force required after placing weight in trunk to accelerate the trunk than before when the trunk is empty.
Explanation:
We are given that
Mass of empty trunk, m=10 kg
Mass of a weight, m'=10 kg
We have to find the total mass after placing weight in trunk and how will this affect the force needed to accelerate the trunk.
Total mass =m+m'
Total mass=10+10=20 kg
We know that
Force, F=ma
Force is directly proportional to mass.
When we placed weight in trunk then the mass of trunk increases .Therefore, now more force required to accelerate the trunk than before when the trunk is empty.
pleaseeee helpp quickkkk
A skateboarder starts at the top of a halfpipe ramp, skates through the middle, and up the other side.
Match the following to describe what is happening at each of the three points in the skater's movement.
Question 1 options:
Middle
End
Beginning
1.
Maximum kinetic energy
2.
Potential and kinetic energy equal
3.
Maximum potential energy
Answer:
Explanation:
1=3
What are the theoretical properties of a gas at a temperature at 0 kelvin?
Answer:
The theoretical properties of a gas at a temperature of 0 Kelvin would be solid and hard. It will go from gas to liquid and finally to a solid state. All the particles will be mushed together. If a gas at zero degrees Celsius were cooled to -273 degrees Celsius, its volume would be reduced by 273/273 and become zero.
PLS PLS HURRY!!!! 50 points!!
Fred and Ted are racing cars down a frictionless track with a jump at the bottom
when suddenly an argument breaks out. Fred says, “If we release the cars from a
point twice as high as we are currently doing so, the cars will have twice the
gravitational potential energy, and therefore be travelling twice fast when they hit
the jump." Ted says, “In order to double the speed of the cars when they hit the
ramp, I think we will have to more than double the height!" Who is right? Prove it!
Answer: I think Fred is right.
Explanation:
Only question 1 pleasee!!
Answer:
can you take a picture of the whole paper so I can see exactly what else it says so I can figure out the solution the only thing I see is wave speeds and speed of the sounds and distance and frequency
find the angle between the vectors. u = (2, 3, 0), v = (3, −2, 1)
Therefore, the angle between vectors `u` and `v` is 90°.
To find the angle between two vectors, we can use the formula:
`cos(θ) = (u . v) / (||u|| ||v||)`
Where u and v are vectors, `.` is the dot product of vectors and || || is the magnitude of a vector.θ is the angle between the two vectors.
In this problem, we need to find the angle between vectors `u` and `v`.
We have the following vector
s:u = (2, 3, 0) and v = (3, −2, 1)
Let's find the dot product of vectors `u` and `v`.u .
v = 2 × 3 + 3 × (−2) + 0 × 1
= 6 − 6 + 0
= 0
Let's now find the magnitudes of vectors `u` and `v`.||u|| = √(2² + 3² + 0²) = √(13) and
||v|| = √(3² + (−2)² + 1²)
= √(14)
Now, we can use the formula to find the angle between vectors `u` and `v`.cos(θ) = (u . v) / (||u|| ||v||)cos(θ)
= 0 / (√(13) × √(14))cos(θ)
= 0θ
= cos⁻¹(0)θ
= 90°
The angle between the vectors u = (2, 3, 0) and v = (3, −2, 1) is 90 degrees.
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Lengths of time it takes for new light bulbs to burn out are an example of which type of data?
Lengths of time it takes for new light bulbs to burn out are an example of quantitative data. Quantitative data refers to any information that can be expressed numerically or measured.
In this case, the lengths of time are numerical values that can be measured in hours, days, or any other unit of time. This data provides information about the lifespan or durability of the light bulbs. Quantitative data is often used in statistical analysis and can be used to draw conclusions, make predictions, or identify trends.
It is important to collect accurate and reliable data to ensure meaningful analysis. Quantitative data is often used in statistical analysis and can be used to draw conclusions, make predictions, or identify trends. In summary, the lengths of time it takes for new light bulbs to burn out represent quantitative data.
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Assuming the height of the hill is 50m calculate
(i) The velocity of the car at the bottom of the hill
(ii) The height at which it will have half this speed. Assume the car starts from west from the top of the hill
(i)The time can be calculated using the equation:
\(d=v0t+1/2\)\(gt^{2}\)
\(v = 0 + 9.8 * 3.19 = 31.3 m/s\)\(t = sqrt(2d/g) = sqrt(2 * 50 / 9.8) = sqrt(10.2) = 3.19s\)
So the velocity of the car at the bottom of the hill is 31.3 m/s.
(ii)To find the height at which the car will have half this speed,
\(v = v0 + gt\)
\(t = (v - v0) / g = (15.65 - 0) / 9.8 = 1.59 s\)
\(d = v0t + (1/2)gt^2\)
where d is the distance traveled, v0 is the initial velocity
\(d = 0 * 1.59 + (1/2) * 9.8 * 1.59^2 = 12.1 m\)
So the car will have half the velocity at the bottom of the hill when it is 12.1 m below the top of the hill.
When an object moves under the influence of gravity, it experiences a constant acceleration due to gravity, which is approximately 9.8 m/\(s^{2}\) on the surface of the Earth.
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Em um centro de distribuição uma empilhadeira carrega uma caixa de 1000kg até o caminhão responsável pelo transporte desta carga. Partindo do repouso a empilhadeira precisa percorrer uma certa distância 8,4 m para atingir a sua velocidade máxima de operação 10 k/h. Determine a força média necessária para acelerar essa carga.
Answer:
F = 592238.09 N
Explanation:
To find the mean force you first calculate the acceleration by using the following kinematic equation:
\(v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\\)
you do "a" the subject of the equation and replace the values of the other parameters:
\(a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}\)
next, the force, by using the second Newton law is:
\(F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N\)
hence, the force is 592238.09 N
- - - - - - - - - - - - - - - - - - - - - - - - - - -
TRANSLATION:
Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:
você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:
Em seguida, a força, usando a segunda lei de Newton, é:
portanto, a força é 592238.09 N
Where electrons are held or stored
Answer:
Held
~Hope it Helps!~
Which statements describe the motion of car A and car B? Check all that apply. Car A and car B are both moving toward the origin. Car A and car B are moving in opposite directions. Car A is moving faster than car B. Car A and car B started at the same location. Car A started ahead of car B.
Answer:
✔️Car A and Car B are moving in opposite directions.
✔️Car A is moving faster than Car B.
✔️Car A started ahead of car B.
Explanation:
The position-time graph shows Car A and Car B. The graph reveals that both cars are moving in opposite directions.
Car A shows a positive slope and Car B shows a negative slope.
The graph also shows that Car A started ahead of Car B. It's seen from the graph that Car A started from the origin.
Therefore, we conclude that the correct statements are:
✔️Car A and Car B are moving in opposite directions.
✔️Car A is moving faster than Car B.
✔️Car A started ahead of car B.
Answer:
merry cristmas the other person answered right I checked for you
Explanation:
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PLSSS HELP MEEEE
When copper combines with oxygen to form copper (II) oxide, the charge of the copper ion is
a.
Cu1+.
c.
Cu3+.
b.
Cu2+.
d.
Cu4+.
Answer:
Cu2+
Explanation:
The voltage waveform in the given figure is applied across a 55-μf capacitor
Answer:
Explanation:
A capacitor is an electronic component that stores and releases electrical energy. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied across the plates, charge accumulates on them, creating an electric field between the plates.
The capacitance of a capacitor is a measure of its ability to store charge. It is typically represented by the symbol 'C' and is measured in farads (F). In your case, you mentioned a 55-μF (microfarad) capacitor, indicating its capacitance value.
When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The rate at which the capacitor charges and discharges depends on the capacitance and the resistance in the circuit
Since there is no figure provided in the text, I am unable to reference it for the specific details of the voltage waveform. However, I can explain the general behavior of a capacitor when a voltage waveform is applied.
When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The behavior of the capacitor is determined by its capacitance, which is given as 55 μF in this case.
As the voltage waveform varies, the capacitor stores and releases electrical charge. During the rising portion of the waveform, the capacitor charges and accumulates energy. During the falling portion, the capacitor discharges and releases the stored energy.
The exact behavior and characteristics of the voltage waveform and the charging/discharging process depend on the specific shape and frequency of the waveform. Without the specific details of the voltage waveform provided in the figure, it is challenging to provide a more detailed analysis.
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Walking at a slower pace after realizing you will be early to school.
A. speed
B. velocity
C. acceleration
Answer:
A.speed
Explanation:
I didn't quite get the question but hope this helps