Answer:
A E
Explanation:
The voltage goes up by a factor of 100/10 = 10
the current goes DOWN by the same factor
Power in = power out no change
The experimenter keeps the potential applied by the laser constant and measures the absorption frequency for both lithium and rubidium. suppose that fLA is the first absorption line when lithium is in the trap, and fRu is the first absorption line when rubidium is in the trap.
a. fLA > FRu
b. fLA = FRu
c. fLA < FRu
This is because the absorption frequency is determined by the energy difference between the ground state and the excited state of the atom. The Correct Option is a. fLA > FRu.
The researcher monitors the absorption frequency for both lithium and rubidium while maintaining a steady laser potential.
Assume that when lithium is in the trap, fLA is the first absorption line, and when rubidium is in the trap, fRu is the first absorption line.
Lithium has a smaller atomic number than rubidium, meaning that it has fewer electrons and a smaller energy difference between the ground state and the excited state.
This means that the absorption frequency for lithium will be greater than that for rubidium.
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If a true bearing of a ship at sea is 227°, what is its direction angle?
A. 43°
B.313°
C. 223°
Use the scale on the man and determine the distance in meters along N 11th Street to Church Street and down Church Street to the YMCA..
The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?
4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.
The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.
To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.
Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.
ΔE = 4×10^26 W
c = 3×10^8 m/s (speed of light)
Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².
Substituting the values, we have:
Δm = (4×10^26 W) / (3×10^8 m/s)²
Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.
This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.
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A 200 N resultant force acts on 350 kg object. Calculate how long it takes this force to change the objects velocity from 3 m/s to the right to 8m/s to the right.
Help pls I will mark brainliest ❤️
Answer:
Explanation:
simple, just use F = ma
assume that the acceleration is any positive value a
The force F must accelerate both sleds
F = (2m + m)a
The force T must accelerate the rear sled
T = ma
T/F = ma/3ma = 1/3
A phone with a mass of 0.2 kg is dropped from a height of 30 m what is it’s speed when it hits the ground?the acceleration of gravity is 9.8ms
Answer:
24.2 m/s
Explanation:
Mass is irrelevant in this situation....
Displacement: ( to find time)
x = xo + vo t - 1/2 at^2
30= 0 + 0 - 1/2 (9.8)t^2
t = 2.47 seconds
Velocity:
vf = a t = 9.8 (2.473) = 24.2 m/s
Expository essay "Climate change in Fiji"
Answer: Climate change poses to the tourism development in Fiji islands. It shows the adverse effects of the changing climate and the dangers pose by the tourism activities and also pose a major hazard for the local people in the region. It also deals with the dangerous carbon emissions and CO2 effect on the landscape, food, water, energy.
The pacific is the world`s largest ocean with a surface area of 175 million sq km and constitutes for 40% of the planet`s waters. Located in the tropical latitudes, it covers more than half the globe`s circumference. Temperature of the surface water in the western tropical regions is always more than 28 ÌŠC over a depth of several hundred meters. This makes up the world`s storage of thermal energy for exchange with atmosphere. Here the interaction between atmosphere and ocean is most extreme and influences the climate not only regionally but planet-wide. The nations of the pacific are obscured human settlements absorbed in this vast fluid universe. The ocean is the most important factor controlling the environment and life.
He’s riding his skateboard down a ramp. Assume that his acceleration is 0.8 m/s2. How much force does it take for him to accelerate at this rate? Zeke has a mass of 50 kg.
A. 40 N
B. 62.5 N
C. 40 kg
D. 50 N
Answer:
A. 40 N
Explanation:
To find force with acceleration and mass we use the equation f=ma
f stands for force
m stands for mass
a stands for acceleration
Now we substitute
f=50*0.8
f= 40
Remember that force is measured in newtons. So A. 40 N is the correct answer.
Use the formula a = v / t to determine acceleration, where v stands for the change in velocity and t for the time it took for the change to take place. Use SI units for force (newtons), mass (kg), and acceleration when utilizing this formula (meters per second squared). Thus, option A is correct.
What force does it take for to accelerate?The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion. When the mass of an item and the net force acting on it are known, the acceleration of that object can be determined using this equation for acceleration.
Therefore, An object's force is equal to its mass times its acceleration, or F = m a. To apply this formula, you must use SI units for force (newtons), mass (kilograms), and acceleration (meters per second squared).
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Weylan is at the county fair playing some of the games. At one booth, he throws a 0.75-kg ball forward with a velocity of 21.0 m/s in order to hit a 0.50-kg bottle sitting on a shelf, and when he makes contact the bottle goes flying forward at 20.0 m/s. What is the velocity of the ball after it hits the bottle?
Given that the mass of the ball is m1= 0.75 kg and initial velocity, u1 = 21 m/s.
This ball strikes a bottle of mass, m2= 0.5 kg, and the initial velocity of the bottle, u2 = 0 m/s.
We have to find the final velocity of the ball, v1 after collision with the bottle having final velocity, v2 = 20 m/s
Momentum is conserved during a collision. So, the equation of momentum can be written as
\(m1u1+m2u2=m1v1+m2v2\)Substituting the values, v1 will be
\(\begin{gathered} v1=\frac{m1u1+m2u2-m2v2}{m1} \\ =\frac{0.75\times21+0.5\times0-0.5\times20}{0.75} \\ =7.67\text{ m/s} \end{gathered}\)Thus, the velocity of the ball is 7.67 m/s.
A hiker with a skin surface area of 1.3 m² is protected from hypothermia (the cold) by a close-fitting sleeping bag 30 mm thick. If her skin temperature is 34°C and she can safely lose 85 W of heat by conduction through the sleeping bag, what is the lowest outside temperature for which the sleeping bag provides adequate protection? Ignore heat losses due to convection or radiation. Coefficient of thermal conductivity of the sleeping bag = 0.019 Wm¹¹°C-¹
Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.
Explanation:
To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.
The rate of heat loss through conduction can be calculated using the formula:
Q = (k * A * ΔT) / d
Where:
Q is the rate of heat transfer (in Watts)
k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)
A is the surface area (1.3 m² in this case)
ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)
d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)
Let's plug in the values:
Q = (0.019 * 1.3 * ΔT) / (30 / 1000)
The hiker can safely lose 85 W of heat, so we can set up the equation:
85 = (0.019 * 1.3 * ΔT) / (30 / 1000)
To solve for ΔT, we can rearrange the equation:
ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)
ΔT ≈ 89.61°C
The picture shows two solutions of salt water. Which solution is more concentrated (has a higher concentration)?
Question 15 options:
The first solution is more concentrated
The second solution is more concentrated
The solutions have the same concentration.
In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated
When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.
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Graph. See text version for more detail.
The graph above represents the nuclear decay of a radioactive element, measured using a radiation-detecting device. What is the half-life, in days, of this hypothetical element?
If the half-life of a given substance is 65 days, how long will it take for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining?
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope? Hint: First, determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.
If a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years, what is the half-life of technetium-99?
The half-life of hypothetical element technetium-99 is 210,936 years.
Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.
Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.
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The brain is responsible for storing memories. How is this helpful for helping the body react to stimuli? ANSWER PLEASEEE
Answer:
Memories occur when specific groups of neurons are reactivated. In the brain, any stimulus results in a particular pattern of neuronal activity—certain neurons become active in more or less a particular sequence. ... Memories are stored by changing the connections between neurons. When the memories are stored, the stimuli can be recalled by being remembered. Explanation:
Hope it helps, I'm not 100% sure it's right though.
A body weighs 63N on the surface of the earth . What is the gravitational force on it due to the earth at height of 3200km from the earth surface ?Radius of the earth is6400
Answer:
Weight of the body,W=63 N
Acceleration due to gravity at height h from the Earths surface is given by the relation:
g ′ = (1+ R e h ) 2 g
Substituting h=R e /2, g ′ =4g/9
Weight of body of mass m at height h is given as: W ′ =mg ′
=4/9 mg
=4/9×63=28 N
Which techniques can scientists use to determine the characteristics of Earth's layers? Select the two correct answers.
examine the behavior of minerals at extremely low temperatures
study how seismic waves travel through different layers
drill deep mines to obtain samples from Earth's mantle and core
conduct experiments about how minerals change under high pressure
use X-rays to obtain a view of Earth's interior layers
The techniques that scientists can use to determine the characteristics of Earth's layers include:
study how seismic waves travel through different layersuse X-rays to obtain a view of Earth's interior layersWaves were used by scientists to study the layers of the Earth. This was done through the use of seismic waves. These are the waves that are generated by nuclear test explosions.
Also, another technique to determine the characteristics of Earth's layers is the use X-rays to obtain a view of Earth's interior layers.
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Answer:
study how seismic waves travel through different layers
use X-rays to obtain a view of Earth's interior layers
:)
Explanation:
A helicopter blade starts to rotate from rest with a constant angular acceleration of \alpha=\:α = 0.98 radians/second2. How many revolutions will the blade make before it is rotating at 500 revolutions per minute (RPM)?
Answer:
n = 223 revolutions
Explanation:
It is given that,
The angular acceleration of a helicopter blade, \(\alpha =0.98\ rad/s^2\)
Initial speed of the helicopter blade, \(\omega_i=0\)
The final speed of the blade, \(\omega_f=500\ rpm=500\times \dfrac{2\pi}{60}\ rad/s=52.35\ rad/s\)
We need to find the number of revolutions. Firstly we will find the angle turned by the blade. Let the angle is \(\theta\). So,
\(\omega_f^2-\omega_i^2=2\alpha \theta\)
\(\theta=\dfrac{\omega_f^2}{2\alpha}\)
\(\theta=1398.22\ rad \)
Let there are n number of revolutions made by the blade. So,
\(n=\dfrac{\theta}{2\pi}\\\\n=\dfrac{1398.22}{2\pi}\\\\n=222.53\ rev\)
or
n = 223 rev
So, there are 223 revolutions.
a bus with a maximum speed of 20m/s takes 21 sec to travel 270m from stop to stop. Its acceleration is
twice as great as its deceleration.
Find:
A, the acceleration
B, the distance traveled at maximum speed
We can use the following data to get the values of acceleration and the distance covered at top speed:
Maximum speed is 20 m/s (v_max).
Time (t) = 21 seconds
(d) = 270 m is the total distance travelled.
Find the acceleration (A) first:
Applying the equation v = u + at
where an is the acceleration, t is the elapsed time, u is the beginning velocity, and v is the end velocity.
Given: The bus will begin at rest with an initial velocity of 0 metres per second (u).
The formula can be rearranged as follows:
a = (v - u) / t
a = (20 m/s - 0 m/s) / 21 seconds
0.952 m/s2 a = 20 m/s / 21 sec
Therefore, the acceleration of the bus is approximately 0.952 m/s².
Next, let's find the distance traveled at maximum speed (B):
Since the bus starts from rest, it takes time to accelerate to its maximum speed and then decelerate to stop. The distance traveled at maximum speed can be found by subtracting the distances covered during acceleration and deceleration from the total distance.
Distance during acceleration = (1/2) * a * t^2
Distance during deceleration = (1/2) * a * t^2
Distance traveled at maximum speed = Total distance - (Distance during acceleration + Distance during deceleration)
B = d - (0.5 * a * t^2 + 0.5 * a * t^2)
B = 270 m - (0.5 * 0.952 m/s² * (21 sec)^2 + 0.5 * 0.952 m/s² * (21 sec)^2)
B = 270 m - (0.952 m/s² * (21 sec)^2)
B = 270 m - 220.392 m
B ≈ 49.608 m
Therefore, the distance traveled at maximum speed is approximately 49.608 m
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A car driving on level ground at 20.0 m/s slams on its brakes and skids to a halt. If the coefficient of kinetic friction between the car’s tires and the road is 0.750, how far does the car skid before stopping? How far would the car have skidded if it had been moving at 40.0 m/s?
The distance the car has skidded if it had been moving at 40.0 m/s is 27.2m
The linear force acting on the car is opposed by the frictional force. Hence;
\(F=F_f\)
\(ma = -\mu R\\ma =-\mu mg\)
m is the mass of the car
a is the acceleration
\(\mu\) is the coefficient of friction
R is the normal force
Given the following parameters
\(a=-\mu g\)
\(a =-0.75(9.8)\\a=-7.35m/s^2\)
Get the distance the car has skidded if it had been moving at 40.0 m/s
\(v^2=u^2+2as\)
\(0^2=20^2+2(-7.35)s\\0=400-14.7s\\s=\frac{400}{14.7}\\s= 27.2m\)
Hence the distance the car has skidded if it had been moving at 40.0 m/s is 27.2m
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in physics what is moment of couples?
The moment of a couple is significant in various applications, such as analyzing the equilibrium and rotational motion of objects, understanding the behavior of rotating systems, and studying the effects of torques in mechanics and engineering.
In physics, the moment of a couple, also known as torque, refers to the rotational effect produced by two equal and opposite forces acting on an object but not along the same line of action.
A couple consists of two forces that have the same magnitude, act in parallel lines, and are opposite in direction. These forces create a rotational moment or torque around a particular point, known as the pivot or axis of rotation. The moment of a couple is a measure of the tendency of the couple to rotate an object.
The magnitude of the moment of a couple is given by the product of one of the forces and the perpendicular distance between the lines of action of the two forces. Mathematically, it can be expressed as:
Moment of couple = Force × Perpendicular distance
The SI unit of moment of a couple is the newton-meter (Nm). It is also important to note that the moment of a couple is a vector quantity and follows the right-hand rule for determining its direction.
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The law of Conservation of energy states that energy can be transformed from one form to another, but it cannot be _______ or ________.
A. radiated, conducted
B. created, changed
C. changed, destroyed
D. created, destroyed
Answer:
D
Explanation:
What does it mean for a chemical equation to be balanced?
Answer:
The number of each type of atom is the same for both the reactants and products.I hope this helps
Bending the stick stretches the chemical bonds holding the stick's atoms together, which provides a source of elastic energy.
a. True
b. False
Answer:
true
Explanation:
If you are given values for Δx, v, and Δt, which kinematic equation could be used to find v0?
V = v0 + aΔt
Δx= (v + v0/ 2) Δt
v^2 = v0^2 2aΔx
Δx = v0Δt + 1/2 a (Δt)^2
The kinematics equation to determine v₀ is Δx = (v + v₀/2) Δt; option B
What are kinematic equations?Kinematic equations are equations which describe the motion of moving bodies.
Kinematic equations are also known as equations of motion.
The equations of motion are given below:
v = u + ats = (v + u/2) * tv² = u² + 2ass = ut + ¹/₂at²where;
v is final velocity = vu is initial velocity = v₀s is distance = Δxa is accelerationt is time = ΔtGiven that the values for the following are given; Δx, v, and Δt, the equation to determine v₀ will be Δx = (v + v₀/2) Δt
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The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?
Kinetic energy is the energy of _____.
Speed, Mass, Work, Motion
Answer: Motion
Explanation:
A 500 watt electrical heater operates at 100 V. Find the current in the heater.Group of answer choices2 A3 A5 A10 A
5 A
Explanation
to find the current we need to use the expression
\(\begin{gathered} P=IV \\ \text{where P is the power} \\ I\text{ is the current} \\ \text{V is the voltage} \end{gathered}\)Step 1
a) Let
\(\begin{gathered} I=\text{ I} \\ V=\text{ 100 v} \\ P=500\text{ watts} \end{gathered}\)b) now, replace and solve for I
\(\begin{gathered} P=IV \\ 500(watts)=I\cdot100v \\ \text{divide both sides by 100 v} \\ \frac{500(watts)}{100\text{ v}}=\frac{I\cdot100v}{100\text{ v}} \\ 5Amperes=I\text{ } \end{gathered}\)therefore, the answer is
5 A
I hope this helps you
If a cuboid of weight 100N has sides 5cm by 10cm, calculate the
i. area of the cuboid
ii. pressure exerted by the cuboid when it lies on its side
The area of cuboid is 0.005m². the pressure exerted by the cuboid is 20Kpa.
What is the area of the cuboid?Given; Weight 100N
Sides of cuboid 5cm by 10cm
i) Area of Cuboid = 5cm × 10cm
Area of Cuboid = 50cm²
Area of Cuboid = 50/10000 m²
Area of Cuboid = 0.005 m²
Hence, the area of cuboid is 0.005m².
ii) Pressure exerted by the cuboid when it lies on its side;
Pressure = Force/Area
Pressure = 100/0.005
Pressure = 20000Pa
Pressure = 20Kpa.
Hence, the pressure exerted by the cuboid is 20Kpa.
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During a NASCAR race a car goes 50 m/s around a curved section of the track that has a radius of 250 m. What is the car's
acceleration?
Answer:10
Explanation: Acceleration of car is given by a= v^2/r, v= 50m/s, r= 250m a= 10 m/s^2 2
A foul ball is hit straight up into the air with a speed of 25 m/s.
how long is it in the air?
Answer:
31.25 m
Explanation:
The foul ball experiences upward linear motion thus:
initial velocity(u) - 25m/s
final velocity(v) - 0m/s
velocity due to gravity - -10m/s2 (since the ball moves upwards)
Hence:
v2=u2+2(gs)
0=625+2(-10*s)
0=625-20s
-625=-20s
s=31.25m