The energy difference between the staggered and eclipsed populations of ethane depends on various factors such as bond length, bond angle, and bond energy.
In general, the energy difference between these two populations is proportional to the difference in their molecular structure.]
If the difference in molecular structure between the staggered and eclipsed populations of ethane had only been 30-fold instead of the almost three orders of magnitude, it would result in a proportionally smaller energy difference between them. However, without more specific information about the specific molecular structure and bond energies involved, it is not possible to determine the exact energy difference.
In general, it's important to note that the magnitude of the energy difference between the staggered and eclipsed populations of ethane can be influenced by various factors such as temperature, pressure, and the presence of other molecules. These factors can affect the magnitude of the energy difference and make it difficult to determine an exact value.
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State Newton's three laws of motion.
Answer:
Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.
Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.
Explanation:
HURRY!!! How does a sound wave travel through air?
a. absorption of sound waves
b. traveling by light waves
c. air currents move away from the sound
d. repeating compressions of air particles
Vanillin, a compound in vanilla bean, is used for flavoring ice cream. The chemical formula for this compound is C8H8O3.
What elements make up this compound? Select three options.
carbon
chlorine
helium
hydrogen
osmium
oxygen
A bullet from a gun at 30° to the horizontal remains in flight for 25s before touching the ground.Calculate the velocity of the projection.
Answer: The velocity of the bullet will be more than half of its earlier velocity
Explanation: I did it on a test and it was right because i calculated 30 degrees within 25 seconds and it was half times the velocity
i hope this helps sorry if i got it wrong
If the mass of the cart was increased but the hanging mass remained the same, how would the acceleration be affected? Explain how you know in terms of net force and system mass.
Answer:
It is always said that mass is same everywhere.
7. From the choices below, select ALL that are results of radioactive decay.
-the nuclear ejection of electrons
-nuclear fission
-radiation emission
-the nuclear capture of electrons
-nuclear fusion
A particular engine takes in 10,000 J of heat, does 2,000 J of work, and as it runs discharges heat. Its own energy is the same when it
has finished as when it started. How much heat did it discharge if this is a closed system?
10,000 J
12,000 J
2,000 J
8,000 J
Answer:
8000 J
Explanation:
There is a Quizlet made by a teacher with this answer.
Can a soccer goalkeeper score a goal in his own goal.
A. Yes
B.No
Plis answer correctly
Answer:
No
Explanation:
A goal can be scored directly from a goal kick against the opposing team. An own goal cannot be scored from a goal kick; in the highly unlikely circumstance that the ball enters the kicker's own goal before being touched by another player, a corner kick is awarded.
An impulse of 20,000 N*s is applied to a car, bringing it to a stop in 0.17 seconds. What force was applied to the car?
F =
t = 0.17 s
Impulse (J) = 20,000 N
J = F x t
F = J / t = 20,000 Ns / 0.17 s = 117,647.0588 N
2 pts
The energy and penetrating power of nuclear radiation in decreasing order is:
Alpha > beta > gamma
Beta > alpha > gamma
Gamma > beta > alpha
Answer:
I think the answer 1
Explanation:
im probably wrong too i dont know
What would happen if the earth did not spin on its axis.
A 8.73-g bullet is moving horizontally with a velocity of 345 m/s, where the sign indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1201 g, and its velocity is 0.714 m/s after the bullet passes through it. The mass of the second block is 1606 g. (a) What is the velocity of the second block after the bullet imbeds itself
Answer:
v₃ = 1.334 m/s
Explanation:
This problem can be solved using the law of conservation of momentum:
\(m_{1}u_{1} + m_{2}u_{2} + m_{3}u_{3} = m_{1}v_{1} + m_{2}v_{2} + m_{3}v_{3}\\\)
m₁ = mass of bullet = 8.73 g = 0.00873 kg
m₂ = mass of first block = 1201 g = 1.201 kg
m₃ = mass of second block = 1606 g = 1.606 kg
u₁ = initial speed of bullet = 345 m/s
u₂ = initial speed of first block = 0 m/s
u₃ = initial speed of second block = 0 m/s
v₁ = final speed of bullet = v₃ (since the bullet is embedded in second block)
v₂ = final speed of first block = 0.714 m/s
v₃ = final speed of second block = ?
Therefore,
\((0.00873\ kg)(345\ m/s)+(1.201\ kg)(0\ m/s)+(1.606\ kg)(0\ m/s)=(0.00873\ kg)(v_{3})+(1.201\ kg)(0.714\ m/s)+(1.606\ kg)(v_{3})\)
\(3.0118\ kg.m/s - 0.8575\ kg.m/s = (1.6147\ kg)(v_{3})\\\\v_{3} = \frac{2.1543\ kg.m/s}{1.6147\ kg} \\\)
v₃ = 1.334 m/s
how do i solve this?
Answer:
hmmm i dont know....
Explanation:
i just wanted free point. TANKS YOU SIR!!
assume all temperatures to be exact. assume a goose has a 2.1-cm -thick layer of feather down (on average) and a body surface area of 0.15 m2 .
The 2.1 cm-thick layer of feather down on a goose provides thermal insulation to reduce the rate of heat loss from the body.
How does the 2.1 cm-thick layer of feather down on a goose provide thermal insulation?Assuming a goose has a 2.1 cm-thick layer of feather down and a body surface area of 0.15 m², we can use the concept of thermal insulation to calculate how effectively the feather down layer protects the goose from heat loss.
The rate of heat loss from a body is given by the equation:
Q/t = hA(Tbody - Tsurroundings)
where Q/t is the rate of heat loss, h is the heat transfer coefficient, A is the surface area of the body, Tbody is the body temperature, and Tsurroundings is the temperature of the surroundings.
The rate of heat transfer is inversely proportional to the thickness of the insulation layer, so we can assume that the thicker the feather down layer, the lower the heat loss rate. Therefore, a thicker layer of feather down would provide better insulation and help the goose to retain its body heat.
Assuming the temperature of the surroundings is lower than the body temperature of the goose, we can use the above equation to calculate the rate of heat loss from the goose's body, given its surface area and feather down thickness. From this, we can infer how well the feather down layer insulates the goose's body from heat loss.
However, it is worth noting that the rate of heat loss also depends on other factors, such as wind speed, humidity, and the temperature gradient between the body and the surroundings. These factors can affect the effectiveness of the feather down layer as an insulator and can lead to variations in heat loss rates.
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To those against whom war is made, permission is given (to fight), because they are wronged;- and verily, Allah is most powerful for their aid.
Answer:
allah is pog
Explanation:
What is an inclined plane that is wrapped in spiral
Answer:
A screw
Explanation:
The threads of a screw act like an inclined plane to increase the distance over which you exert the input force.
the image formed by a convex mirror of focal length 30 cm is a quarter of the length of the object the distance of the object from the mirror is
Answer:
The answer to the question is 90 cm i.e the object distance is 90 cm from the mirror.
CALCULATION:
As per the question, the focal length of the convex mirror f = 30 cm.
The magnification is: 1/4
We are asked to calculate the object distance [u].
As per the sign convention for reflection, the measurements taken along the direction of light is taken as positive and its reverse is taken as negative.
The transverse measurement above the principal axis is taken as positive and below the principal axis is taken as negative.
Hence, the focal length of the convex mirror f = +30 cm.
The image formed by a convex mirror is virtual and erect.
Hence, the magnification will be positive.
Hence, magnification m = +1/4=+0.25
The relation between focal length, magnification and object distance is given as -
m= f/f=u
u= m=1/m multiplyed by f
= 0.25=1/0.25 multiplyed by -(30)
= -90 cm [ans]
Here, the negative sign is due to the fact that object distance is measured opposite to the direction of light.
(sorry, brainly didn't allow me to put pictures of the calculation)
hope this helps :)
an inductor used in a dc power supply has an inductance of 13.0 hh and a resistance of 160.0 ωω. it carries a current of 0.350 aa.Part A
What is the energy stored in the magneticfield?
Part B
At what rate is thermal energy developed inthe inductor?
Part C
Does your answer to part (b) mean that themagnetic-field energy is decreasing with time? Yes or No.Explain.
Part A: The energy stored in the magnetic field of the inductor can be calculated using the formula:
\(Energy = (1/2) * L * I^2\)
Substituting the given values, the energy stored in the magnetic field is:
\(Energy = (1/2) * 13.0 H * (0.350 A)^2 = 0.80375 Joules\)
Part B: The rate at which thermal energy is developed in the inductor can be calculated using the formula:
\(Power = I^2 * R\)
Substituting the given values, the rate of thermal energy developed in the inductor is:
\(Power = (0.350 A)^2 * 160.0 Ω = 19.6 Watts\)
Part C: Yes, the answer to part (b) indicates that the magnetic-field energy is decreasing with time. The thermal energy developed in the inductor represents energy loss due to the resistance of the inductor. This energy is dissipated as heat, indicating a conversion from magnetic-field energy to thermal energy. The rate of thermal energy developed represents the rate at which the magnetic-field energy is being lost.
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True or False?
If the cart is moving on the positive x axis, the x-component of velocity must be positive.
The given statement is false, the cart is moving on the positive x axis, the x-component of velocity must be positive. The magnitude and the direction both define it.
What exactly is speed?The definition of velocity is the change in displacement with respect to time. Speed is a vector quantity. This element is time-based. The x and y components of velocity at any angle are determined.
Given both magnitude and direction, velocity is a vector quantity. The relationship between displacement and velocity is known as the velocity dependence.
The cartesian coordinate, however, specifies the displacement direction. In contrast to an object moving along a negative x-axis, the cart moves along a positive x-axis and has a positive velocity.
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what is the conclusion of a ballon car model
Newton's third rule of motion states that whenever air is forced backwards out of a balloon (out the end with the opening), there must be an equal and opposite reaction force pushing the balloon forward (out the end opposite the opening).
A balloon tends to fly around the room randomly when you just let it go on its own, making steering nearly impossible. On the other hand, you can use the balloon's energy to move the automobile forward if you attach it to a vehicle.
What is the ballon powered car model experiment?
Steps to Take
1. Poke a hole through the centre of the pop bottle lid with the hammer and nail.
2. Attach the ballon to the straw using masking tape. By blowing into the straw, check the balloon for any holes.
3. Connect the tongue depressor to the two short straw pieces. These will serve as the wheels' axles.
4. Using the skewers, fasten the four wheels. This could be a little difficult! To prevent the bottle cap from rubbing on the side of the tongue depressor, you might need to adjust it.
5. Use masking tape to secure the balloon and straw to the car's top.In order to have enough space to blow into the straw, make sure it is over the edge.
6. Blow into the balloon, grip the straw, then release. Observe how the automobile moves off!
Students build a car in this exercise that is propelled by the elastic energy of a balloon. In contrast to family automobile, which transforms chemical energy into kinetic energy, this vehicle transforms potential energy into kinetic energy.
When inflated with air, balloons, which are elastic, can store potential energy. The potential energy, sometimes referred to as kinetic energy, is transformed into the energy of motion when the air is released. When the car is moving forward, you can perceive this energy.
When you release the automobile, it will have more kinetic energy the more potential energy it has saved.
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Two spheres are both launched horizontally from a 10-m-high table. Sphere A is launched with an initial speed of 5.0 m/s. Sphere B is launched with an initial speed of 2.5 mis. a. What are the times for each sphere to hit the floor? b. What are the distances that each travels from the edge of the table?
(a) Both spheres are launched with 0 initial velocity in the vertical direction, so they both hit the ground at time t such that
10 m - 1/2 g t ² = 0
where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.
Solve for t :
10 m = 1/2 g t ²
t ² = (20 m) / g
t ≈ 1.4 s
(b) Sphere A travels a horizontal distance of
(5.0 m/s) (1.4 s) ≈ 7.1 m
while sphere B travels a distance of
(2.5 m/s) (1.4 s) ≈ 3.6 m
what observation has prompted astronomers to ponder the possible existence of dark energy?supernovae appear fainter than expected at large redshiftsGUTs(grand unified theories)MACHOs(Massive compact Halo Objects)
The observation that has prompted astronomers to ponder the possible existence of dark energy is the fact that supernovae appear fainter than expected at large redshifts.
This observation was made in the late 1990s by two independent research teams, led by Saul Perlmutter and Brian Schmidt, who were studying distant Type Ia supernovae. Type Ia supernovae are known as "standard candles" because they have a consistent intrinsic brightness. Astronomers use them to measure distances in the universe. Based on the understanding of the expansion of the universe, it was expected that as the universe expands, the light from distant supernovae would be stretched, or redshifted, making them appear fainter. However, the observed supernovae were significantly fainter than predicted.
This discrepancy led to the realization that some form of additional energy must be responsible for the accelerated expansion of the universe. This mysterious energy, which permeates space and drives the acceleration, came to be known as dark energy.
Alternative explanations, such as modifications to gravity (GUTs - Grand Unified Theories) or the presence of unseen massive objects (MACHOs - Massive Compact Halo Objects), have been proposed but have not provided satisfactory explanations for the observed cosmic acceleration. Therefore, the observation of supernovae appearing fainter at large redshifts is a crucial piece of evidence supporting the existence of dark energy.
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a real power supply can be modeled as an ideal emf of 19 volts in series with internal resistance. the voltage across the terminals is 13.2 volts when the current is 1.47 amps. what is the internal resistance?
The internal resistance is 3.92 Ω.
An ideal emf of 19 volts, voltage across the terminals is 13.2 volts, current is 1.47 amps.
Resistance and voltage:
In terms of power, voltage is defined as the work done per unit charge across two points in an electric circuit. It is measured in volts (V).
Resistance is defined as the opposition to the flow of electric current through a conductor. It is measured in ohms (Ω).
Internal resistance:
Let R be the internal resistance.
The voltage, V = 19 V - IR
The voltage across the terminals, V' = 13.2 V, and the current, I = 1.47 A.
The equation for calculating internal resistance is given asR = (V - V') / I
Substitute the given values.
R = (19 - 13.2) / 1.47R = 3.92 Ω
Therefore, the internal resistance is 3.92 Ω.
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AYUDAAA PORFAVOR
Desarrollar un diagrama de flujo para un programa que solicite la base y la altura y calcule el área de un triangulo
Queremos crear un diagrama general para calcular el área de un triangulo.
Este será algo como:
Definir variablesPedirle al usuario que introduzca los valores deseados (de las variables).Leer los valores deseados y asignarlo a la variable correspondiente.Realizar la operación para calcular el área.Mostrar en pantalla el resultado.Como naturalmente habra algunas variaciones segun el programa que utilicemos, lo voy a escribir de forma bastante general.
Primero definamos nuestras variables:
Por ejemple, en fortran usariamos algo como:
real:: B, H, A
Donde B será la variable que usaremos para la base, H para la altura, y A para el área.
Luego tenemos que escribir en pantalla algo que le diga al usario que debe introducir la base y el area.
Luego el programa debe ser capaz de leer ese input.
con algo de la forma:
B = read*input 1
H = read*input 2
Una vez tenemos definidas las variables, simplemente calculamos el área del triangulo:
A = H*B/2
Finalmente la podemos mostrar en pantalla con algo como:
print(A).
Lo que nos mostraría el valor del área.
Concluyendo, el diagrama en general sería:
Definir variablesPedirle al usuario que introduzca los valores deseados (de las variables).Leer los valores deseados y asignarlo a la variable correspondiente.Realizar la operación para calcular el área.Mostrar en pantalla el resultado.
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What is the magnitude of the output gear angular velocity (in units of rad/sec)?
The magnitude of the output gear angular velocity is 50 rad/sec. The actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.
The magnitude of the output gear angular velocity is determined by the gear ratio between the input and output gears. The gear ratio is the ratio of the number of teeth on the output gear to the number of teeth on the input gear.
To find the magnitude of the output gear angular velocity in units of rad/sec, you can use the formula:
Output gear angular velocity = Input gear angular velocity * (Number of teeth on input gear / Number of teeth on output gear)
Let's say the input gear has 20 teeth and the output gear has 40 teeth. If the input gear is rotating at 100 rad/sec, we
can calculate the output gear angular velocity as follows:
Output gear angular velocity = 100 rad/sec * (20 / 40) = 50 rad/sec
In this case, the magnitude of the output gear angular velocity is 50 rad/sec.
Remember to check the units and the gear ratio to ensure the correctness of your calculation. Also, note that the actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.
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At the mirror surface, the light rays that you see are on the ______ of/as the light rays that your friend sees.
Given what we know, the light rays that you see on the surface of the mirror are at the same angle as the light rays that your friend sees.
Why does this happen?This has to do with the way in which a mirror affects the light that hits it. A mirror will reflect light, but will do so at the same angle that the light reaches it. This means that if the light reaches the mirror at a 40-degree angle, it will be reflected in the opposite direction at a 40-degree angle.
Therefore, we can confirm that the light rays that you see on the surface of the mirror are at the same angle as the light rays that your friend sees.
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Question 8
If a cheetah can run at a speed of 100 km/h for the initial 500 m of its chase, h
much time would it take to catch its prey that is at a distance of 100 m?
O 1.5 s
O 2.3s
O 3.6s
O 4.8s
Answer:
3.6 s
Explanation:
100 km/hr =27.77 m/s
100/27.77=3.6 sec
Comet tails _____.
A) always point toward the sun
B) are made of carbon and magnesium
C) are only seen when comets are near the sun
D) are caused by intense air friction
Answer:
A always point toward the sun
Answer:
A) Always point towards the sun
help me plz Your starting fitness level is known as__________. (10 points) a starting point b beginning level c baseline d entry level
Answer:
Would it be starting point?
Explanation:
When you start a sport or something, you may not be good or bad at it. However, as time goes on you are going to improve.
Idk if this helps or not buh yeah
A square object of mass {m} is constructed of four identical uniform thin sticks, each of length {L}, attached together. This object is hung on a hook at its upper corner.
If it is rotated slightly to the left and then released, at what frequency will it swing back and forth?
Express your answer in terms of the variables m, L, and appropriate constants.
The frequency at which the square object will swing back and forth is given by √(g / (4\(\pi ^{2}\) * L)), where g is the acceleration due to gravity.
To determine the frequency at which the square object will swing back and forth, we can use the formula for the period of a simple pendulum. The period (T) is the time taken for one complete oscillation.
For a simple pendulum, the period can be given by the formula:
T = 2π * √(L/g)
Where:
T = period
L = length of the pendulum (distance from the pivot to the center of mass)
g = acceleration due to gravity
In this case, the length of the pendulum is the distance from the pivot to the center of mass of the square object. Since the object is hung at its upper corner, the distance from the pivot to the center of mass is (L/2).
Therefore, the period of the square object can be expressed as:
T = 2π * √((L/2)/g)
T = 2π * √(L/2g)
To find the frequency (f), we can take the reciprocal of the period:
f = 1/T
f = 1 / (2π * √(L/2g))
f = √(g / (4\(\pi ^{2}\) * L))
So, the frequency at which the square object will swing back and forth is given by √(g / (4\(\pi ^{2}\) * L)), where g is the acceleration due to gravity.
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