If the standard solutions had unknowingly been made up to be 0. 0024 m agno3 and 0. 0040 m k2cro4, would this have affected your calculated ksp?

A series of nuclear events that transform four protons into the helium nucleus, two positrons, and two neutrinos result in the fusion of hydrogen into helium.

Transformation of one element into another, typically with the emission of additional particles and energy.

There are four types decay as follows;

Beta Decay 2 neutrons and 2 protons were lost. Atomic mass decreases by 4, atomic number decreases by 2.

Alpha Decay A proton is created from one neutron. Atomic number increased by 1.

Particle Emission One proton transforms into a neutron.

Beta Decay A nucleus with a high energy output emits energy and stabilizes.

When two nuclei join together to form one atom, fusion processes take place. Two hydrogen atoms are fused together to create helium in the sun's reaction.

Thus, a series of nuclear events that transform four protons into the helium nucleus, two positrons, and two neutrinos result in the fusion of hydrogen into helium.

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Answer:

When the concentration is higher, more hydrogen ions are near the Zn atoms at any given time. This allows for more Zn atoms to be ionized and dissolved into the solution per second.

Explanation:

Answer:

It will produce 44 grams of carbon dioxide

Explanation:

Step 1: Data given

MAss of CaCO3 = 100 grams

Molar mass of CaCO3 = 100.09 g/mol

Mass of CaO produced = 56 grams

Molar mass of CaO = 56.08 g/mol

Step 2: The balanced equation

CaCO3 → CaO + CO2

Step 3: Calculate moles CaCO3

Moles CaCO3 = mass CaCO3 / molar mass CaCO3

Moles CaCO3 = 100 grams / 100.09 g/mol

Moles CaCO3 = 1.00 moles

Step 4: Calculate moles CaO

Moles CaO = 56 grams / 56.08 g/mol

Moles CaO = 1.00 moles

Step 5: Calculate moles CO2

For 1 mol CaCO3 we'll have 1 mol 1 mol CaO and 1 mol CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 1.00 moles * 44.0 g/mol

Mass CO2 = 44 grams

It will produce 44 grams of carbon dioxide

Answer:

The answer to your question is given below.

Explanation:

The equation for the reaction is given below:

2H2O —> 2H2 + O2... ΔH = –572KJ

A. The reaction is exothermic since the enthalphy change, ΔH has a negative sign.

B. Since the enthalphy change, ΔH has a negative sign for the reaction, It means heat has be released to the surroundings. Therfore, 86.4g will also release heat.

C. We'll begin by calculating the mass of H2O that reacted from the balanced equation.

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g.

From the balanced equation above:

When 36g of H2O reacted, –572KJ of heat were released.

Therefore, 86.4g of H2O will react to release = (86.4 × –572)/36 = –1372.8KJ of heat.

Therefore, –1372.8KJ of heat is released.

Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

\(P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ \)

actual density = 11.4g/cm³

error = 11.4 - 10.8 = 0.6

We have

\(p(\%) = \frac{0.6}{11.4} \times 100 \\ = 5.263157894...\)

We have the final answer as

Hope this helps you

Answer:

Non-metals

Explanation:

Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom.

Answer:A balanced chemical equation provides a great deal of information in a very succinct format. Chemical formulas

provide the identities of the reactants and products involved in the chemical change, allowing classification of the

reaction. Coefficients provide the relative numbers of these chemical species, allowing a quantitative assessment

of the relationships between the amounts of substances consumed and produced by the reaction. These quantitative

relationships are known as the reaction’s stoichiometry, a term derived from the Greek words stoicheion (meaning

“element”) and metron (meaning “measure”). In this module, the use of balanced chemical equations for various

stoichiometric applications is explored.

The general approach to using stoichiometric relationships is similar in concept to the way people go about many

common activities. Food preparation, for example, offers an appropriate comparison. A recipe for making eight

pancakes calls for 1 cup pancake mix, 3

4

cup milk, and one egg. The “equation” representing the preparation of

pancakes per this recipe is

1 cup mix + 3

4

cup milk + 1 egg ⟶ 8 pancakes

If two dozen pancakes are needed for a big family breakfast, the ingredient amounts must be increased proportionally

according to the amounts given in the recipe. For example, the number of eggs required to make 24 pancakes is

24 pancakes ×

1 egg

8 pancakes = 3 eggs

Balanced chemical equations are used in much the same fashion to determine the amount of one reactant required to

react with a given amount of another reactant, or to yield a given amount of product, and so forth. The coefficients in

the balanced equation are used to derive stoichiometric factors that permit computation of the desired quantity. To

illustrate this idea, consider the production of ammonia by reaction of hydrogen and nitrogen:

N2

(g) + 3H2

(g) ⟶ 2NH3

(g)

This equation shows ammonia molecules are produced from hydrogen molecules in a 2:3 ratio, and stoichiometric

factors may be derived using any amount (number) unit:

2 NH3 molecules

3 H2 molecules or

2 doz NH3 molecules

3 doz H2 molecules or

2 mol NH3 molecules

3 mol H2 molecules

These stoichiometric factors can be used to compute the number of ammonia molecules produced from a given

number of hydrogen molecules, or the number of hydrogen molecules required to produce a given number of

ammonia molecules. Similar factors may be derived for any pair of substances in any chemical equation.

Explanation:

Answer:

2.3 kg.

Explanation:

The balanced equation tells us that 2 moles of sodium (Na) reacts with 1 mole of sulfuric acid (H2SO4) to produce 1 mole of hydrogen gas (H2).

To calculate the mass of sodium needed to produce 100g of hydrogen gas, we need to use the following steps:

Calculate the number of moles of hydrogen gas produced from 100g of hydrogen gas.

Use the mole ratio from the balanced equation to determine the number of moles of sodium required to produce that amount of hydrogen gas.

Convert the moles of sodium to grams using the molar mass of sodium.

Step 1:

The molar mass of hydrogen gas (H2) is 2 g/mol. Therefore, 100g of hydrogen gas is equal to 100/2 = 50 moles of H2.

Step 2:

From the balanced equation, 2 moles of Na reacts with 1 mole of H2. So, the number of moles of Na required to produce 50 moles of H2 is:

2 moles Na / 1 mole H2 = 2 * 50 = 100 moles Na

Step 3:

The molar mass of sodium (Na) is 23 g/mol. Therefore, the mass of sodium required to produce 100g of hydrogen gas is:

100 moles Na * 23 g/mol = 2300g or 2.3 kg of Na

Therefore, the mass of sodium needed to produce 100g of hydrogen gas is 2.3 kg.

The article aims to highlight the most recent improvements in the PCET procedures for electrocatalysis at clearly characterized electrode–electrolyte interfaces.

Aim : Here, we focus on the most recent developments in the PCET methods for electrocatalysis at clearly defined electrode–electrolyte interfaces.

Method: Since the groundbreaking and ongoing studies made by Frumkin and his colleagues initiated in the 1930s, non-covalent interaction, which is controlled by the cation/anion features, is known to play a crucial role in the interfacial water and adsorbate environments correlated to electrode–electrolyte catalytic properties.

The microscopic perspective of this interaction is still a significant scientific mystery, nevertheless. Recent research based on the well-defined surface and solid-liquid interfacial structure of single-crystal model electrodes revealed novel characteristics of the cation effect.

Practical usage: Designing high-performance electrode and electrolyte materials requires an understanding of the roles played by the electrical double layer (EDL) structure in proton-coupled electron transfer (PCET) electrode processes.

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Lightning is categorized as plasma because it has extremely high levels of energy.

When the electrons are freed from their host atoms for a short time, due to high temperatures, it is plasma. An electrical discharge consisting of moving electrons and ions, is lightning. Lightning strikes create plasma via a very strong jolt of electricity.

By the passage of electricity through a gas, the plasma was created. An electrical discharge through air and it ionizes the atoms when this happens. The electrons from the atoms strips and leaves positively charged ions in the gas, is lightning.

Lightning as an example of plasma present at Earth's surface. Plasma temperatures approaches 30000 K and electron densities may exceed 10²⁴ m−³.

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Answer:

So its a theory by Alfred Wegener is that All land was one big piece of land called pangea in the early 20th century people began to think that land masses can move such as many do just from it being there or natural disasters then going in to more research they found that when putting the continents together it fit like a puzzle  and the fact that some fossils were far away from were the same were found

The theory of continental drift, based their theory on several lines of evidence, including the fit of the continents, paleoclimate indicators, truncated geologic features, and fossils.

The continental drift hypothesis states that all the continents were once joined together as one large mass of land, but then the land spread apart and drifted into their current positions.

The hot magma flows in convection currents due to tremendous heat and pressure within the earth. These currents cause the tectonic plates that make up the earth's crust to move.

Thus, The theory of continental drift, based their theory on many lines of evidence, including the fit of the continents, paleoclimate indicators, truncated geologic features, and fossils.

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Answer:

1. It is stoichiometric.

2. O2 is the limiting reactant.

3. 9.0 g of C2H6 remain unreacted.

4. 17.6 g of CO2.

5. 85.2%.

Explanation:

Hello there!

In this case, for the given chemical reaction:

\(2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O\)

We can see that:

1. It is stoichiometric and is balanced because the reactants yields the products according to the law of conservation of mass.

2. In this part, it is possible to calculate the moles of ethane by using its molar mass:

\(n_{C_2H_6}=15g*\frac{1molC_2H_6}{30.08g} =0.50molC_2H_6\)

And the moles of oxygen by knowing that one mole is contained in 22.4 L at STP:

\(n_{O_2}=\frac{1mol}{22.4L} *15.68L=0.7molO_2\)

Thus, by calculating the moles of carbon dioxide product by each reactant, we can identify the limiting one:

\(n_{CO_2}^{by\ C_2H_6}=0.50molC_2H_6*\frac{4molCO_2}{2molC_2H_6} =1.0molCO_2\\\\n_{CO_2}^{by\ O_2}=0.70molO_2*\frac{4molCO_2}{7molO_2} =0.4molCO_2\\\)

Thus, since oxygen yields the fewest moles of CO2 product, we infer it is the limiting reactant.

3. In this part, we calculate the mass of C2H6 that actually react first:

\(m_{C_2H_6}^{reacted}=0.4molCO_2*\frac{2molC_2H_6}{4molCO_2}*\frac{30.08gC_2H_6}{1molC_2H_6} =6.0gC_2H_6\)

Thus, the leftover of ethane (C2H6) as the excess reactant is:

\(m_{C_2H_6 }^{leftover}=15g-6.0g=9.0g6.0C_2H_6\)

4. Since 0.4 moles of carbon dioxide were produced, we use its molar mass to calculate the mass as its theoretical yield:

\(m_{O_2}^{theoretical}=0.4molCO_2*\frac{44gCO_2}{1molCO_2}=17.6gCO_2\)

5. Finally, the percent yield is gotten by dividing the actual yield by the theoretical one:

\(Y=\frac{15g}{17.6}*100\%\\\\Y=85.2\%\)

Best regards!

Answer:

21.16 g

Explanation:

Balance the equation

3 Zn + 2 MoO3 = Mo2O3 + 3 ZnO

And prepare their molar masses

Zn - 65.38

MoO3 - 143.96

Mo2O3 - 239.92

ZnO - 81.38

Since Zn is the limiting reagent; (you can determine this by trial and error but I'm too lazy), basically 29.2 g of MoO3 needs 19.892 g of Zn to react; while 17 g of Zn would need 24.955 g of MoO3 so we have shiet leftover. So we should always use the limiting reagent, in this case,

Zn

as it gets used up completely.

Anyway:
We can now solve using the ratio between Zn and ZnO.
(17 g of Zn /

65.38 g per Zn) x (3 mol of ZnO / 3 mol of Zn) x (81.38 g per ZnO / 1 mol of ZnO) = 21.16 g of ZnO

sooooo you get

21.16 g

(typing this on mobile and kinda hungover so yea)

960 molecules of magnesium oxide will form when excess magnesium reacts with 480 molecules of oxygen.

Wilhelm Ostwald, a German scientist, is widely credited with coining the term. Ultimately, though, the word mole derives from the Latin word moles, which meaning "a mass." The word molecule is connected to the word mole; it is a diminutive that means "a little bulk."

The quantity of matter in a system that equals the number of atoms in 0.012 kilograms of carbon-12; it is denoted by the symbol "mol".

Given that,

480 molecules of oxygen is there.

The equation becomes:

2Mg + O₂ → 2MgO

2 mol  1 mol   2 mol

Now,

1 molecule of oxygen give 2 molecule of MgO

480 molecule of oxygen will give (480 × 2) = 960 molecules of MgO

So, 960 molecules of magnesium oxide will form when excess magnesium reacts with 480 molecules of oxygen.

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The pH of the aqueous solution will decrease when CH3CH2NH3 is added to an equilibrium mixture containing CH3CH2NH2.

When CH3CH2NH3 is added to an aqueous solution of CH3CH2NH2, it acts as an acid. CH3CH2NH3 is the conjugate acid of CH3CH2NH2, and it can donate a proton (H+) to the solution. The addition of an acid will increase the concentration of H+ ions in the solution, leading to a decrease in pH.

The equilibrium between CH3CH2NH2 and its conjugate base, CH3CH2NH3+, is governed by the acidity of the solution. Initially, when only CH3CH2NH2 is present, the pH of the solution will be determined by the concentration of H+ ions from the dissociation of water and the basicity of CH3CH2NH2.

However, when CH3CH2NH3 is added, it will react with CH3CH2NH2 to form CH3CH2NH3+ through protonation. This reaction shifts the equilibrium towards the side of the acid, resulting in an increase in H+ ion concentration and a decrease in pH.

In summary, the addition of CH3CH2NH3 to an equilibrium mixture of CH3CH2NH2 will lower the pH of the solution due to the increased concentration of H+ ions resulting from the acid-base reaction.

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Statements A, B, and C are correct. Statement D is incorrect, as the sign of an oxidation number is important and indicates the type of charge on the atom.

A. All elements in a neutral molecule have an oxidation number of zero. This is because the sum of the oxidation numbers of all atoms in a neutral molecule must be zero.

B. The sum of the oxidation numbers for the atoms in a neutral compound is zero. This is because the overall charge of a neutral compound is zero, and the sum of the oxidation numbers of all atoms in a molecule must equal the overall charge of the compound.

C. The oxidation number for a monatomic ion is the same as its charge. This is because a monatomic ion consists of only one atom, and its charge is equal to its oxidation number.

D. The statement that the sign of an oxidation number is unimportant is incorrect. The sign of an oxidation number is important as it indicates the direction of electron flow. Oxidation numbers of different elements can have positive or negative values, depending on their electronegativity and valence electrons.

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"John Adams is a contemporary American composer known for blending elements of minimalism, neo-romanticism, and rock music in his compositions".The statement is true.

John Adams is a prominent American composer who has been active since the 1970s. He is known for his unique style that blends different genres of music, including minimalism, neo-romanticism, and rock music.

Minimalism is a style of music characterized by the use of repetitive patterns and simple harmonic structures. Neo-romanticism, on the other hand, is a style that emerged in the late 19th century as a reaction against the dominance of classical music and the rise of modernism.

It emphasizes emotion, beauty, and expressiveness. Finally, rock music is a popular genre that emerged in the 1950s and is characterized by its use of electric guitars, drums, and bass.

Adams has incorporated these different styles into his compositions to create a unique and innovative sound. He is known for his use of repetitive patterns, driving rhythms, and electronic instruments, which are reminiscent of minimalism and rock music.

At the same time, he also incorporates lush harmonies and expressive melodies, which are characteristic of neo-romanticism. Adams's compositions are often complex and multi-layered, with different elements weaving in and out of each other to create a rich and dynamic musical experience.

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The average atomic mass of the given isotopes of Halfnium is 178.55 amu

The average atomic mass of an element is equal to the sum of its isotope masses multiplied by it's own natural abundance (the decimal associated with the percent of atoms of that element for a given isotope).

In order to determine the weighted average, we must consider the % natural abundances of each isotope. The atomic mass of an element is the weighted average of the atomic masses of the element's naturally occurring isotopes. Determine the average atomic mass by using atomic masses and percentage abundances of each isotope. To convert each percentage abundance to decimal form, divide it by 100. Multiply this figure by the atomic mass of the isotope. To get the average atomic mass, add the atomic masses of each isotope together.

To determine the average atomic mass of Halfnium, the mass fractions of the isotopes multiplied by their respected atomic masses must all be added.

Using 100 atoms as the basis, calculate the mass fractions (m1, m2,...m5):

m1 =   5/100 = 0.05

m2 = 19/100 = 0.19

m3 = 27/100 = 0.27

m4 = 14/100 = 0.14

m5 = 35/100 = 0.35

Multiplying the mass fractions with the atomic masses of the respective isotopes.

Average atomic mass of Halfnium is:

Avg = (m1 x 176) + (m2 x 177) + (m3 x 178) + (m4 x 179) + (m5 x 180)

Avg = (0.05 x 176) + (0.19 x 177) + (0.27 x 178) + (0.14 x 179) + (0.35 x 180)

Avg = 178.55 amu

Therefore, the average atomic mass of Halfnium based on the data for its given isotopes is 178.55 amu.

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the answer is ultraviolet

Answer:

microwave

Explanation:

your gonna have one crispy plant if you put it in the microwave XD

The percent sugar concentration in orange soda is approximately 13.24%.

The volume of orange soda is given as 355 mL and its density is given as 1.043 g/mL. According to the nutrition label, there are 49 g of sugar in a 355 mL serving of orange soda.Using the density, we can convert the 355 mL volume into grams as follows:Volume = 355 mL; Density = 1.043 g/mL; Mass = ?To convert mL to g we need to multiply the volume with the density. Thus,Mass = Volume x Density= 355 x 1.043= 369.965 gThus, the mass of a 355 mL serving of orange soda is approximately 369.965 g.Next, we can calculate the percentage of sugar in the beverage as follows:Percent sugar concentration = (Mass of sugar / Total mass of beverage) x 100%Percent sugar concentration = (49 g / 369.965 g) x 100%Percent sugar concentration = 0.1324 x 100%Percent sugar concentration = 13.24%Therefore, the percent sugar concentration in orange soda is approximately 13.24%.

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Answer:

its late but this is the answer

Explanation:

Phases of small stars: Planetary nebula phase, White dwarf phase and Black dwarf phase. Phases of big stars: Red supergiant phase,  Supernova phase and Neutron star phase or Black Holes.

Most galaxies have stars distributed throughout them that are born within dust clouds. The Orion Nebula is a well-known illustration of a dust cloud of this type. Deep within these clouds, turbulence creates knots with enough mass for the gas and dust to start collapsing under its own gravitational pull. The material in the cloud's centre starts to heat up as it breaks up. This heated core at the centre of the collapsing cloud is referred to as a protostar and will eventually turn into a star.

The majority of the stars in the Milky Way are found in pairs or in clusters of several stars, which could be explained by the possibility that the spinning clouds of collapsing gas and dust split into two or three blobs.

The event horizon of a black hole is an area of spacetime where gravity is so intense that nothing, not even light or other electromagnetic waves, has the energy to cross it.  According to general relativity theory, a sufficiently compact mass can cause spacetime to distort and create a black hole.

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Answer:

average star → giant → planetary nebula → white dwarf

massive star → supergiant → supernova → neutron star (or black hole)

Explanation: plato

CH\(_{3}\)OH, also known as methanol, is a polar molecule.

The polarity of a molecule is determined by the distribution of electrons in the molecule.

In CH3OH, the carbon atom is bonded to three hydrogen atoms and one oxygen atom. The oxygen atom is more electronegative than the carbon and hydrogen atoms, so it attracts electrons more strongly, creating a partial negative charge.

This means that the oxygen end of the molecule has a slight negative charge, while the carbon and hydrogen end has a slight positive charge.

the polar nature of the CH3OH molecule is also reflected in its dipole moment, which is a measure of the separation of charge in a molecule. CH3OH has a non-zero dipole moment of 1.69 D, indicating the presence of a dipole.

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Answer:

Neptune to be precise

Explanation:

cause it is the last planet in our solar system

Answer:

the answer is 0.785g/ mL

The gas is Argon.

To identify the gas, we need to compare the number of moles calculated for each gas with the given density.

Let's calculate the number of moles for each gas and compare them:

Given:

Density = 1.17 × 10^(-6) g/cm^3

Pressure = 1.00 × 10^(-3) atm

Temperature = 60.0 °C = 60.0 + 273.15 = 333.15 K

Molar mass of Oxygen (O2) = 32.00 g/mol

Molar mass of Neon (Ne) = 20.18 g/mol

Molar mass of Hydrogen (H2) = 2.02 g/mol

Molar mass of Chlorine (Cl2) = 70.90 g/mol

Molar mass of Argon (Ar) = 39.95 g/mol

Molar mass of Nitrogen (N2) = 28.02 g/mol

For Oxygen (O2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 5.88 × 10^(-12) mol

For Neon (Ne):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 9.26 × 10^(-12) mol

For Hydrogen (H2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 9.26 × 10^(-11) mol

For Chlorine (Cl2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 2.58 × 10^(-12) mol

For Argon (Ar):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 4.64 × 10^(-12) mol

For Nitrogen (N2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 6.45 × 10^(-12) mol

Comparing the number of moles calculated for each gas with the given density, we find that the gas with the closest value is Argon (Ar). Therefore, the gas is Argon.

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Monosaccharides with a carbonyl group at C2 are called ketoses. Option B.

This is because the carbonyl group is a ketone group, as opposed to an aldehyde group which would be located at C1. Monosaccharides with an aldehyde group at C1 are called aldoses. Alditols, on the other hand, are sugar alcohols that have been reduced to a polyol. Anomers refer to the two isomeric forms of a cyclic sugar molecule that differ in the orientation of the anomeric carbon, which is the carbon atom that was formerly part of the carbonyl group in the open-chain form of the sugar. Answer option B.

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Answer:

Home: in cleaning products, pesticides, and paints

Workplace: in industries such as manufacturing, construction, agriculture, healthcare, and labs

Outdoors: polluted air, water sources, and soil

Consumer products: cosmetics, plastics, and electronics

Food and water: can have pesticides and food preservatives