If the wavelength of a wave is quadrupied then what happens to the frequency of the wqve(Assume speed is constant) ​

Answer:

It obeys Newton's third law of motion.

Explanation:

The experiment obeys Newton's third law of motion because when the air in the balloon is released, the air moves in the downward direction which is an action of the balloon so in the reaction, the balloon moves in upward direction   so both action and reaction forces are equal in magnitude but moves in opposite direction which obeys Newton's third law of motion.

Answer:

When electric current weakens then the magnetic field around the wire also weaken

Explanation:

The magnetic field produced by electrical wire is directly proportional to the electricity flowing through it.

Thus, in case when electric current weakens then the magnetic field around the wire also weaken.

Answer:

The field gets weaker

Explanation:

took the quiz!

The power provided by the crane is 12,342,857.1 j/s.

Given here work done by crane is (W)= 432,000,000J and time taken (t) is 35second.

Power can be calculated by the formula, Power = Work done /time

Power = 432,000,000/35

Power = 12,342,857.1 joules per second.

Power is the rate at which work is done or energy is delivered. It can be expressed as the ratio of work done (W) or energy transferred  to time (t), or W/t. The watt, or one joule per second, is the unit of power. Power is a scalar quantity.

The work done by a force is defined to be the product of component of the force in the direction of the displacement and the magnitude of this displacement. Work can be calculated by multiplying Force and Distance. (W= F×s) . Work is also a scalar quantity.

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The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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We can use the formula for gravitational acceleration:

a = G * M / r^2

where G is the gravitational constant, M is the mass of the sun, and r is the radius of the sun. Plugging in the values, we get:

a = (6.67 x 10^-11 N m^2/kg^2) * (2.0 x 10^30 kg) / (7.0 x 10^8 m)^2

a = 274 m/s^2

So the acceleration due to gravity on the surface of the sun is about 274 m/s^2.

The strength of the electric field 5.6 cm from the plastic bead is -2.44 × 10^6 N/C. It can be calculated using Coulomb's law.

Coulomb's law states that the electric field created by a point charge is directly proportional to the charge and inversely proportional to the square of the distance from the charge. Mathematically, it can be expressed as:

E = k * (Q / r^2)

Where E is the electric field strength, k is the electrostatic constant (approximately 9 × 10^9 Nm^2/C^2), Q is the charge of the bead (-7.0 nC or -7.0 × 10^-9 C), and r is the distance from the bead (5.6 cm or 0.056 m).

Plugging the values into the formula, we can calculate the electric field strength:

E = (9 × 10^9 Nm^2/C^2) × (-7.0 × 10^-9 C) / (0.056 m)^2

Simplifying the expression:

E = -2.44 × 10^6 N/C

Therefore, the strength of the electric field 5.6 cm from the charged plastic bead is approximately -2.44 × 10^6 N/C. The negative sign indicates that the electric field is directed towards the bead, as expected for a negative charge.

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Answer:

I Believe the Correct Answer is respiratory system; obtains oxygen so the energy in nutrients can be extracted.

Explanation:

Respiratory System is made for oxygen and involves the Lungs Diaphragm etc.

Please give me Brainliest!

Initial velocity of 2.4 m/s and an angle of 60°.

The x component is 2.4 m/s cos(60°) = 2.4 m/s (0.5) = 1.2 m/s

The y component is 2.4 m/s sin(60°) = 2.4 m/s (0.866) = 2.08 m/s

Initial velocity is the speed an object has when it starts moving in a certain direction. It is the speed that an object has before any external forces act upon it. Initial velocity is a vector quantity, meaning it has both a magnitude, or size, and a direction. Initial velocity is usually measured in meters per second (m/s). It is important to note that the initial velocity of an object can be different depending on the reference frame from which it is measured.

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The complete question is-

A paper airplane is thrown with an initial vclocity of 2,4 m and angle of 60" Find the Voz: 012m/s 0.62 mn/& 0 1.70 m/8 208 m/$

(a) The efficiency of the PV panel can be calculated using the formula:Efficiency = (Power output / Power input) × 100Where,Power output = The power generated by the PV panel (300 W in this case)Power input = The solar insolation (1000 W/m2 in this case) × Area of the panel (2.0 m2 in this case)Efficiency = (300 / (1000 × 2)) × 100= 15%

(b) The total power generated by 10 pieces of 300 W PV panels is given as:Total power = Power of 1 panel × Number of panels= 300 × 10= 3000 WPeak sun hours in Wyoming = 3.2 hours Therefore, the total energy produced daily is given as:Energy produced = Total power × Peak sun hours= 3000 × 3.2= 9600 Wh or 9.6 kWh(c) The energy produced by the PV panel is given as:Energy produced = Power output × Time= 300 × 3.2 × 50/100= 48 kWh= 48,000 Wh= 48,000 / 3.6 × 106 kWh= 0.013 kWh or 13 Wh Weight of 1 gallon of water = 4.546 × 1 = 4.546 kg Mass of water = Volume × Density= 4.546 × 15 = 68.19 kg= 68.19 / 1 = 68.19 liters

Heat required to increase the temperature of 1 liter of water from 15°C to 55°C is given as:Heat = mass × specific heat capacity × temperature rise= 1 × 4.18 × (55 - 15)= 209.2 JHeat required to increase the temperature of 68.19 liters of water from 15°C to 55°C is given as:Heat = 68.19 × 209.2 J= 14,250 J or 0.01425 kWh Energy produced by the PV panel is 0.013 kWh Therefore, the number of gallons of water that can be heated up is given as:Number of gallons = Energy produced / Heat required= 0.013 / 0.01425= 0.91 gallons Therefore, the PV panel can supply to heat up 0.91 gallons of water from 15°C to 55°C.

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To calculate the kinetic energy of the sled and rider at the bottom of the hill, we can use the principle of conservation of energy, which states that the total energy of a system is conserved, assuming no work is done by non-conservative forces such as friction.

At the top of the hill, the sled and rider have only potential energy, which is given by:

PE = mgh

where m is the total mass of the sled and rider, g is the acceleration due to gravity, and h is the height of the hill.

At the bottom of the hill, all of the potential energy has been converted to kinetic energy, which is given by:

KE = (1/2)mv^2

where v is the speed of the sled and rider at the bottom of the hill.

Since energy is conserved, we can set the potential energy at the top of the hill equal to the kinetic energy at the bottom of the hill:

mgh = (1/2)mv^2

Simplifying this equation, we can solve for v:

v = sqrt(2gh)

where sqrt means "square root of".

Plugging in the given values, we get:

v = sqrt(2 * 9.81 m/s^2 * 60 m) ≈ 34.6 m/s

Finally, we can use the kinetic energy formula to calculate the kinetic energy at the bottom of the hill:

KE = (1/2)mv^2 = (1/2) * 90 kg * (34.6 m/s)^2 ≈ 54,800 J

Therefore, the kinetic energy of the sled and rider at the bottom of the hill, neglecting friction, is approximately 54,800 J.

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The amount of heat that is gained by water is equal to the amount of heat loss by the ice. Therefore, we have the following relationship:

Where "Qw" is the heat of water and "Qi" is the heat of ice. The heat of water is given by:

The amount of heat of ice must be calculated for the two states, solid and liquid. For the solid-state the temperature will be from -30 degrees to 0 degrees, therefore, we have:

Where Ci is the specific heat of ice in solid-state and is equal to:

Replacing the values:

Solving the operations we get:

Now we need to determine the amount of heat that needs the ice to convert into liquid. This is given by:

Lf is the latent heat of ice and is equal to:

Replacing the values we get:

Solving the operations:

Now we need the amount of heat of liquid ice to its final temperature, this is given by:

Applying the relationship:

Cw is the specific heat of water and is equal to:

And the specific heat of ice is:

Replacing the values. The first two terms on the right side we already calculated and the final temperature is the same for both:

Solving operations:

Now we solve for the final temperature:

Subtracting 19835 to both sideS:

Now we add 1673Tf to both sides:

Now we divide both sides by 1882.2

Therefore, the final temperature is 20.57 °C. This value can be converted into Kelvin using the following relationship:

Replacing the temperature:

Therefore, the final temperature is 293.72 K.

Answer:

I think B but I could be wrong

Explanation:

Answer:0.61

Explanation:

the answer is 0.61 because i just typed it into acellus abs it was right

(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) The total length of the track is approximately 5.28 kilometers.

(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:

Linear Speed = Angular Speed * Radius

Solving for angular speed:

Angular Speed = Linear Speed / Radius

Plugging in the given values:

Angular Speed = 1.30 m/s / 0.023 m

Angular Speed ≈ 56.52 radians/second

Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):

Angular Speed = 1.30 m/s / 0.058 m

Angular Speed ≈ 22.41 radians/second

Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) To find the average angular acceleration, we can use the formula:

Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time

The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds

Average Angular Acceleration ≈ -0.000286 radians/second squared

Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:

Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2

The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2

Angular Displacement ≈ -0.343 radians

Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.

The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.

Circumference = 2π * (2.30 cm + 5.80 cm) / 2

Circumference ≈ 27.77 cm

Converting the circumference to meters:

Circumference = 27.77 cm * 0.01 m/cm

Circumference ≈ 0.2777 m

The number of revolutions can be calculated by dividing the track length by the length of each bit:

Number of Revolutions = Track Length / Length of Each Bit

Number of Revolutions = 0.2777 m / 0.0006 m

Number of Revolutions ≈ 462.83 revolutions

Finally, we can calculate the total length of the track:

Total Length of the Track = Number of Revolutions * Circumference

Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution

Total Length of the Track ≈ 128.53 m

Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).

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Answer:59.3

Explanation:

The force due to gravity or weight is 582 N. The mass of a student  is 59.39 Kg.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Force = mass.acceleration

582 = m*9.8

m = 59.39 Kg.

The force due to gravity or weight is 582 N. The mass of a student  is 59.39 Kg.

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(a)

- The coefficient of log(income) (0.88) suggests that a 1% increase in income is associated with a 0.88% increase in cigarette consumption, holding other variables constant.

- The coefficient of log(price) (-0.75) indicates that a 1% increase in cigarette prices is associated with a 0.75% decrease in cigarette consumption, holding other variables constant.

- The coefficient of educ (-0.50) implies that a one-year increase in education is associated with a 0.50 unit decrease in cigarette consumption, holding other variables constant.

- The coefficient of age (0.77) suggests that a one-year increase in age is associated with a 0.77 unit increase in cigarette consumption, holding other variables constant.

- The coefficient of age squared (-0.008) indicates that the relationship between age and cigarette consumption is not linear, and as age increases further, the rate of increase in cigarette consumption slows down.

- The coefficient of restaurant (2.83) implies that individuals who have access to smoking in restaurants smoke, on average, 2.83 more cigarettes per week compared to those who do not have access.

(b) The R-squared measures the proportion of the total variation in cigarette consumption that is explained by the independent variables. In this case, the R-squared is not provided, so it cannot be calculated or commented upon.

The Adjusted R-squared takes into account the number of variables and the sample size, providing a more reliable measure of model fit. Unfortunately, the Adjusted R-squared is also not provided, so it cannot be calculated or commented upon.

The difference between R-squared and Adjusted R-squared lies in the penalization of the latter for including additional variables that may not significantly contribute to the model.

(c) To perform a 1% individual significance test for each slope coefficient, we need the t-statistics and the corresponding p-values for each coefficient. These values are not provided, so we cannot perform the significance tests or comment on the results.

The null hypothesis (H0) for each significance test would be that the corresponding slope coefficient is equal to zero. The alternative hypothesis (Ha) would be that the slope coefficient is not equal to zero.

(d) The confidence interval for each slope coefficient can be calculated using the provided standard errors and assuming a t-distribution. However, the standard errors are not provided in the given format, so we cannot calculate the confidence intervals.

(e) To perform a 5% test of the overall significance of the regression model, we need the F-statistic and its corresponding p-value. Unfortunately, these values are not provided, so we cannot perform the test or comment on the results.

The null hypothesis (H0) for the overall significance test would be that all slope coefficients are equal to zero, indicating that none of the independent variables have a significant effect on cigarette consumption. The alternative hypothesis (Ha) would be that at least one of the slope coefficients is not equal to zero, indicating that at least one independent variable has a significant effect on cigarette consumption.

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Einstein’s equation means that a small amount of mass can be converted into a large amount of energy.

The Einstein’s equation shows the relationship between the mass and energy of matter. According to his theory, mass and energy are interconvertible. The “c^2” in Einstein’s equation means that a small amount of mass can be converted into a large amount of energy.

In a nuclear reactor, energy is one of the products, the energy produced ina nuclear reactor is vented as small amount of mass can be converted into a large amount of energy.  Nuclear fusion involves the joining of to nuclei, this process occurs naturally  in the Sun and other stars.

We know that;

E = mc^2

E = 3 * 10^-3 * (3×108 m/s)^2 = 2.7×10^14 J

Again;

E = mc^2

m= E/c^2

m = 1012 J/(3×108 m/s)^2 = 1.1 * 10^-14 Kg

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Answer:

1. A small amount of mass can be converted into a large amount of energy.

2. heat

3. in the Sun and other stars

4. 2.7×1014 J

5. 1.1×10−5 kg

100% correct

Explanation:

guy thy guy thy guy thy guy thy guy thy

Answer:

because they are underaged and prob dont care and also the gov thinks that the youth cant make a reasonable decision for them selves for sum like that and the media influnces them to by saying whats going on and who supports who

Answer:

Boiling a kettle is an example of both thermal and kinetic energy. Thermal energy comes from a substance whose molecules and atoms are vibrating faster due to a rise in temperature. Heat energy is another name for thermal energy. Kinetic energy is the energy of a moving object.

it's kinetic!

Answer:

the last one, It moves away from a mid-ocean ridge.

Answer:

D

Explanation:

BabaBooey

An electron's overall energy in an orbit with a radius of \(3.175 * 10^{-10} m\) is -1.51 eV.

Equation gives the total energy of an electron in a hydrogen atom.

E = -13.6 eV/n^2, where the primary quantum number is n

The radius of the orbit is given, so we can solve for n. The equation for the radius of an orbit is given by

\(r = 0.5 * n^2 * a_0\), where \(a_0\) is the Bohr radius, equal to\(5.2917721067 *10^{-11 }m.\)

Plugging in the given radius, we find that n = 3.

Plugging n = 3 into our equation for the total energy of the electron gives us

\(E = \frac{-13.6 eV}{3^2}\\ =\frac{ -13.6 e}{9}\\ = -1.51 eV.\)

Therefore, the overall energy of an electron in a \(3.175 * 10^{-10} m\) radius orbit is -1.51 eV.

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Answer:What they did not count on is the immense distance to the stars, which made the shift so small it was not able to be detected until the 1830s. The first scientist to do so was Friedrich Bessel in 1838. The method that is used to measure distances to nearby stars is called trigonometric parallax, or sometimes, triangulation.

Explanation:

The number of revolutions the tire makes during the motion, we need to first calculate the distance traveled by the car and then convert it to the number of tire revolutions.

The distance traveled by the car can be calculated using the formula:

Distance = (initial velocity * time) + (0.5 * acceleration * time^2)

The car starts from rest (initial velocity = 0), the formula simplifies to:

Distance = 0.5 * acceleration * time^2

Substituting the values:

Distance = 0.5 * acceleration * (9.05 s)^2

Next, we need to find the circumference of the tire using its diameter. The circumference (C) can be calculated as:

C = π * diameter

Substituting the value:

C = π * 57.2 cm

To convert the distance traveled by the car into tire revolutions, we divide the distance by the circumference:

Number of revolutions = Distance / Circumference

Substituting the values:

Number of revolutions = (0.5 * acceleration * (9.05 s)^2) / (π * 57.2 cm)

Make sure to convert the units to a consistent system, such as meters and seconds, before calculating. The final result will be the number of tire revolutions during the car's motion.

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This question involves the concepts of Newton's Second Law of Motion.

The acceleration of the bowling ball will be "0.67 m/s²".

According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,

\(F=ma\\\\a=\frac{F}{m}\)

where,

Therefore,

\(a=\frac{6\ N}{9\ kg}\)

a = 0.67 m/s²

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Answer:

D?

Explanation:

not a 100 percent sure

Answer:

B

im pretty sure its B but i could be wrong

Explanation:

we can use the formula F = ma

hence,

500 = 75a

a = 6.666 m/s² or 6(2/3) m/s²

hope this helps.

In a two-dimensional elastic collision of a particle with a stationary particle that has the same mass, the trajectories of the two particles after the collision is at right angles to each other because of the law of conservation of momentum.

Momentum is conserved in an elastic collision, which means that the total momentum before and after the collision must remain the same.

Since the stationary particle has zero momentum, the total momentum before the collision is just equal to the momentum of the moving particle.

Therefore, after the collision, the momentum of the moving particle must be equal in magnitude but opposite in direction to the momentum of the stationary particle.

This means that the trajectories of the two particles must form a right angle.

Thus, in the two-dimensional elastic collision of a particle with a stationary particle that has the same mass, the trajectories of the two particles after the collision is at right angles to each other. This is due to the law of conservation of momentum.

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Answer:F. all are equally likely

Explanation:

F. because there is no way to tell if or what the persentage of tails to heads could be.