If this decay has a half life of 2.60 years, what mass of 72.5 g of sodium 22 will remain after 15.6 years

Answer:

if an object weighs more than an equal volume of water, it is more dense and will sink, and if it weighs less than an equal volume of water, it is less dense and will float.

Explanation:

Hope that helps

Answer:

proton

A proton is composed of two up quarks, one down quark, and the gluons that mediate the forces "binding" them together.

Answer:

A.)physical B.)physical C.)physical D.)chemical

The efficiency of chemical sanitizers depends on a number of variables. Volume, temperature, contact time, total alkalinity, and pH are among the most important.

The substances, such as copper, nitrogen, and oxygen, as well as compounds comprised of components like alcohol, carbon dioxide, and salt, as well as more complicated materials, such as a computers, the air you breathe, precipitation, a chicken, a car, etc., are examples of chemicals.

Chemicals are another name for matter, which is everything composed of atoms. Chemicals are the buildings you can create using atoms as the building pieces in a LEGO set. They could be solid, liquid, or gas in any form. Chemical can be a combination or a pure substance.

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A molecule is a chemical compound that is created when two or more atoms are combined .Water serves as an example of a molecule (H2O H 2 O ).

A structure made up of two or more atoms that are chemically connected to one another is called a molecule .The structure could be an elemental molecule or a complex.. An elemental molecule, like ozone (O3) or chlorine, only contains one type of atom (Cl2). One or more distinct components combine to form a composite molecule.

Any substance made up of similar molecules with atoms from two or more different chemical elements is referred to as a chemical compound.

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Answer:

i can see you down the +-

Explanation:

The pH of the 0.2 M solution of the amine with a pKa of 9.5 is approximately 8.8.

To calculate the pH of a 0.2 M solution of an amine with a pKa of 9.5, we can use the Henderson-Hasselbalch equation:

pH = pKa + log ([A-]/[HA])

Given:

pKa = 9.5

[A-]/[HA] = 0.2 M

Substituting the values into the equation:

pH = 9.5 + log (0.2/1)

Since log (0.2/1) is equal to log (0.2), we can calculate the pH as follows:

pH = 9.5 + log (0.2)

Using logarithm properties, we can convert log (0.2) to its decimal equivalent:

log (0.2) ≈ -0.69897

Now we can calculate the pH:

pH ≈ 9.5 - 0.69897

pH ≈ 8.80103

Therefore, the pH of the 0.2 M solution of the amine with a pKa of 9.5 is approximately 8.8.

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When the organic phase is less dense than water: The organic phase will float on top of the water phase.

The organic phase will sink to the bottom of the separation funnel.

Regarding the difference between anhydrous magnesium sulfate and anhydrous sodium sulfate as drying agents:

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The exponential decay rate for healthy human body is 0.1155 and the time taken  by 94% of the chemical consumed by the body to leave is 11.5 hours.

a) The exponential decay rate, often denoted as λ (lambda), can be calculated using the formula:

\(\lambda = \dfrac{ ln(2)} {t^{\frac{1}{2}}}\)

where ln represents the natural logarithm and \(t^\frac{1}{2}\) is the half-life of the chemical.

Substituting the given half-life value:

λ = ln(2) / 6

Using a calculator, we find:

λ ≈ 0.1155

So, the exponential decay rate is approximately 0.1155.

b) To calculate the time it takes for 94% of the chemical to leave the body, we can use the formula for exponential decay:

\(N(t) = N_{o} \times e^{-\lambda t}\)

where N(t) is the amount of chemical remaining at time t, N₀ is the initial amount of chemical, λ is the decay rate, and t is the time elapsed.

We want to find the time at which N(t) is 94% of N₀, which means:

0.94N₀ = N₀ \(\times e^{-\lambda t}\)

Cancelling out N₀:

0.94 = \(e^{-\lambda t}\)

Taking the natural logarithm of both sides:

ln(0.94) = -λt

Substituting the value of λ we found earlier:

ln(0.94) = -0.1155t

Now, solving for t:

t = ln(0.94) / -0.1155

solving the above equation, we get:

t ≈ 11.46

Therefore, the exponential decay rate for healthy human body is 0.1155 and it will take approximately 11.5 hours for 94% of the chemical consumed to leave the body.

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Complete question: The half-life of a certain chemical in the human body for a healthy adult is approximately 6 hr. a)What is the exponential decay rate b How long will it take 94% of the chemical consumed to leave the body?

1.  The 4s subshell should be filled before the 3d subshell because the 4s subshell is at lower energy than the 3d subshell.

Electrons fill the subshells in order of increasing energy.

2.  To write the electron configuration for the Na^+ ion, which has ten electrons, follow these steps:
  a. Begin with the lowest energy subshell, which is 1s.
  b. Fill the subshells with electrons in increasing energy order: 1s, 2s, 2p, 3s, and so on.
  c. Stop when you've added ten electrons.
The electron configuration for the Na^+ ion is: 1s^2 2s^2 2p^6

3. To write the electron configuration for the Br^- ion, which has thirty-six electrons, follow the same steps as above, but stop when you've added thirty-six electrons.

The electron configuration for the Br^- ion is: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6

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The percent change in volume is 21 %.

given that :

temperature , T1 = 273 -28 = 245 K

temperature , T2 = 273 + 9 = 282 K

pressure P1 = P

pressure P2 = P - O.O5 P = 0.95 P

Volume V1 = V

volume V2 = ?

using ideal gas equation , we get :

P1 V1 / T1 = P2 V2 / T2

V2 = (P1 V1 T2 ) / P2 T1

V2 = ( P × V × 282 ) / ( 0.95 P × 245 P )

V2 = 1.211 V

change in volume is given as = V2 - V1

                                                 =  1.211 V - V

                                                 = 0.211 V

Percent change in volume is = (0.21 V)) / V ) × 100 %

                                                 = 21 %

Thus, For many purposes we can treat propane C3H8 as an ideal gas at temperatures above its boiling point of −42.°C Suppose the temperature of a sample of propane gas is raised from -28.0°C to 9.0°C, and at the same time the pressure is increased by 5.0% . the percent change in volume in 21 %.

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To determine the amount of fertilizer John needs to use for his potato farm, we need additional information such as the recommended fertilizer application rate in kilograms per hectare (kg/ha). Without this information, we cannot provide an accurate calculation. Fertilizer application rates vary depending on factors such as soil fertility, crop type, and specific fertilizer recommendations.

Once the fertilizer application rate is known, the calculation can be done by multiplying the application rate by the area of the farm. For example, if the recommended application rate is 100 kg/ha:

Fertilizer needed = Application rate (kg/ha) x Farm area (ha)

Fertilizer needed = 100 kg/ha x 34.5 ha

Fertilizer needed = 3450 kg

Therefore, John would need 3450 kilograms of fertilizer for his potato farm. However, this calculation is hypothetical without knowing the specific fertilizer application rate for the farm.

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The time required for the effusion of 1 L of methane is equal to 98 seconds.

Graham’s law can be described as the rate of effusion or diffusion of gas being inversely proportional to the square root of its molecular weight.

According to Graham’s Law, molecules with lower molecular mass will effuse faster than those with higher molecular mass molecules.

\({\displaystyle {\frac{R_1}{R_2} =\sqrt{\frac{M_2}{M_1} }\)

Where M₁ and M₂ are the molar mass of gas 1 and gas 2 respectively.

Given the molar mass of Helium = 4 g/mol

The molar mass of methane, CH₄ = 16 g/mol

The rate of the helium diffusion = 1L/49s

The ratio of the rate of diffusion of given gases can represented as:

\({\displaystyle {\frac{1L/49 s}{R_{CH_4}} =\sqrt{\frac{16}{4} }\)

\(R_{CH_4} = 1L/98 s\)

Therefore, one liter of methane will take 98 seconds to effuse.

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A solution with a concentration higher than the solubility is supersaturated. The correct answer is option is A.

A supersaturated solution is a solution that contains more solute than it can normally dissolve at a given temperature. In other words, it has a concentration higher than its solubility.

Solubility refers to the maximum amount of solute that can dissolve in a solvent under specific conditions, such as temperature and pressure. It is often expressed in terms of grams of solute per 100 grams of solvent.

When a solution is unsaturated, it means that the concentration of the solute is below its solubility limit, and there is still room for more solute to dissolve. In an unsaturated solution, if additional solute is added, it will continue to dissolve until the solubility limit is reached.

On the other hand, a saturated solution is one where the concentration of the solute has reached its solubility limit. At this point, any additional solute added will not dissolve and will settle at the bottom of the container.

A supersaturated solution occurs when a solution is prepared at a higher temperature and then cooled down rapidly. This process allows the solute to stay dissolved in a higher concentration than its normal solubility limit. It is a metastable state where the solute remains dissolved even though the conditions are not favorable for its dissolution.

In conclusion, a solution with a concentration higher than the solubility is classified as a supersaturated solution.

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Answer:

The common application of indicators is the detection of end points of titrations. The colour of an indicator alters when the acidity or the oxidizing strength of the solution, or the concentration of a certain chemical species, reaches a critical range of values.

Answer: Its filtration

Explanation:

I took the test and got it right

Answer:

A

Explanation:

it is filtration

The size of micropipette that you would select to deliver 215 microliters would be a micropipette with a volume range of 200-1000 microliters.

What is a micropipette?

A micropipette is a laboratory instrument used to measure and dispense small volumes of liquid, typically in the range of microliters (µL) or nanoliters (nL). They are commonly used in chemistry, biology, and biochemistry experiments, as well as in clinical and industrial settings.

Micropipettes consist of a handle, a digital or manual volume adjustment mechanism, and a tip that is placed into the liquid to be dispensed. They work by creating a vacuum or positive pressure inside the tip, which draws or pushes the liquid out of the tip.

Micropipettes come in different volume ranges and it is important to select the right one to ensure accurate delivery of the desired volume. For example, a micropipette with a volume range of 2-10 microliters would not be suitable for delivering 215 microliters, while a micropipette with a volume range of 200-1000 microliters would be more appropriate.

It's also important to note that, even if the micropipette is able to deliver 215 microliters, you should always check the calibration of the micropipette before use, to make sure that it's delivering the correct volume.

Hence, a micropipette with a volume range of 200-1000 microliters is suitable to deliver 215 microliters.

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Answer: Potassium (K) has the lowest electronegativity among the given elements.

Explanation:

Electronegativity is a measure of an element's ability to attract electrons towards itself when it is involved in a chemical bond with another element. Potassium has the lowest electronegativity because it has only one valence electron that is located far from the nucleus, making it easier to lose that electron and become a positively charged ion. In contrast, nitrogen, lithium, and bromine have higher electronegativities because they have more valence electrons or the valence electrons are closer to the nucleus, making it more difficult to remove or share electrons.

The element with the lowest electronegativity among the given options is potassium (K). Potassium has an electronegativity value of approximately 0.82 on the Pauling scale, which is the lowest value among the four elements listed. In contrast, nitrogen (N) has an electronegativity of approximately 3.04, bromine (Br) has an electronegativity of approximately 2.96, and lithium (Li) has an electronegativity of approximately 0.98. Electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond. The lower the electronegativity value, the less the atom attracts electrons towards itself.

Brainliest?

Answer:

Dependent variable: Amount of NaCI dissolved in water

Explanation:

In an experiment, the DEPENDENT VARIABLE is the variable that the experimenter measures. It is the variable whose response is dependent on the independent variable.

In this experiment, researchers were studying the temperature and the amount of NaCI dissolved in water i.e. how a change in temperature affected the amount of NaCl dissolved. They conducted two tests one changing the temperature (experimental group) and another without changing the temperature (control group) the temperature change. It is clear that the RESPONDING/DEPENDENT VARIABLE IN THIS EXPERIMENT IS THE AMOUNT OF NACL DISSOLVED.

the maximum number of electrons an atom can have with the sublevel designation is 2 electrons.

to calculate the maximum number of electrons an atom can have with the sublevel designation can be calculate as below:

as we know that,

The energy level of each of an atom with the given sublevel designations determines the maximum number of electrons the atom can occupy.

(a) For n = 2, I = 1, ml = 0,

The energy level is calculated as;

Energy level = 2(1) + 1 = 3 sub-orbtials

= -1  0  1  : ( 2 electrons each)

Thus, the maximum number of electrons an atom can have with the sublevel designation is 2 electrons.

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Answer:

The answer is 1/3 of the population.

The calculated molar ratio of iron to oxygen in BIFs is 1.452.

Comparing this ratio to the molar ratios of Hematite (1:0.75) and Magnetite (1:0.67), we can see that the calculated value of 1.452 is closest to the Hematite molar ratio of 1:0.75. Therefore, Hematite is the more dominant iron component in BIFs.

To calculate the mass of oxygen contained within BIFs, we'll use the given information:

Total mass of the modern atmosphere = 5.01×10¹⁸ kg

Percentage of oxygen in the modern atmosphere = 21%

Mass of oxygen contained within the modern atmosphere = (5.01×10¹⁸ kg) × (0.21) = 1.051×10¹⁸ kg

Percentage of oxygen contained in BIFs = 6.6% (given)

Mass of oxygen contained within BIFs = (6.6% of 1.051×10¹⁸ kg) = 6.6/100 × 1.051×10¹⁸ kg = 6.9166×10¹⁶ kg

Therefore, the mass of oxygen contained within BIFs is 6.9166 × 10¹⁶ kg.

To calculate the number of moles of oxygen contained within BIFs, we'll use the molecular mass of O₂:

Molecular mass of O₂ = 0.032 kg/mole

Number of moles of oxygen contained within BIFs = (Mass of oxygen in BIFs) / (Molecular mass of O₂)

= (6.9166×10¹⁶ kg) / (0.032 kg/mole) = 2.1614375 × 10¹⁸ moles

Therefore, the number of moles of oxygen contained within BIFs is 2.1614375 × 10¹⁸ moles.

Next, let's calculate the mass of iron in BIFs:

Total mass of BIFs = 5.0×10¹⁷ kg

Percentage of iron in BIFs = 35%

Mass of iron contained within BIFs = (35% of 5.0×10¹⁷ kg) = 35/100 × 5.0×10¹⁷ kg = 1.75×10¹⁷ kg

To calculate the number of moles of iron contained within BIFs, we'll use the atomic mass of iron:

Atomic mass of iron = 0.0558 kg/mole

Number of moles of iron contained within BIFs = (Mass of iron in BIFs) / (Atomic mass of iron)

= (1.75×10¹⁷ kg) / (0.0558 kg/mole) = 3.1367419 × 10¹⁸ moles

Therefore, the number of moles of iron contained within BIFs is 3.1367419 × 10¹⁸ moles.

Finally, let's calculate the molar ratio of iron to oxygen in BIFs:

Molar ratio of iron to oxygen = (Number of moles of iron) / (Number of moles of oxygen)

= (3.1367419 × 10¹⁸ moles) / (2.1614375 × 10¹⁸ moles)

≈ 1.452

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Answer:

Two factors that contribute to the efficiency of a chromatographic separation are the amount of sample being separated and the separation time. A larger sample size or a longer separation time will generally result in a more efficient separation. Other factors that can impact the efficiency of a chromatographic separation include the nature of the sample, the type of chromatographic technique being used, and the characteristics of the separation column.

Question:

Each liter of air has a mass of 1.80 grams. How many liters of air are contained in 2.5 x103) kg of air?

Answer:

11.48106 L

Answer:

Explanation: The best-supported theory of our universe's origin centers on an event known as the big bang. This theory was born of the observation that other galaxies are moving away from our own at great speed in all directions as if they had all been propelled by an ancient explosive force.

Answer:

Following are the solution to the given question.

Explanation:

Answer:

radioisotopes is the answer.

Explanation:

Answer:

The increase in mass is not due to the heating but due to the reaction of the metal with oxygen in air to form an oxide

Explanation:

When a metal is heated in the presence of air, oxygen present in air reacts with the metal to form the oxide of the metal. The mass of this oxide is greater than the original metal by the amount of oxygen added to the metal during the reaction.

The above reaction is known as an oxidation reaction. Generally,

metal M + O2 ---> MO2

Answer:

bR2 since it is nonpolar

The first step of the reaction, we have  reaction between a nucleophile and an electrophile.

We can see that in the first step of the reaction, we have  reaction between a nucleophile and an electrophile. In this case, the electrophile would have to be an alkyl halide which produces a carbocation as show in the image attached. What we have here is quite similar or  like most of the organic reactions, this reaction occurs in a number of detailed or smaller steps and each step of the reaction is going to help to bring us closer to the end product of the entire steps of the reaction which is wat we target as we carry out the particular reaction.The second step involves the reduction of the alkyne with the use of a Lindlar catalyst. As such the reaction is poisoned and it stops at the alkyne stage rather than going on to obtain the alkane.

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