if tine were to pull a skittle from the bag, record the flavor , and then put the skittle back, how many times should she expect to get a a cherry skittle put of 50 attempts?

Using the fundamental theorem of calculas the derivative of function g(x)=\(xt^{3}+t^{5}\) at x=0 is \(t^{3}\).

Given a function g(x)=\(xt^{3}+t^{5}\).

We are required to find the derivative of the function g(x) at x=0.

Function is relationship between two or more variables expressed in equal to form. The values entered in a function are part of domain and the values which we get from the function after entering of values are part of codomain of function. Differentiation is the sensitivity to change of the function value with respect to a change in its variables.

g(x)=\(xt^{3}+t^{5}\)

Differentiating with respect to x.

d g(x)/dx=\(t^{3}\)+0  [Differentiation of x is 1 and differentiation of constant is 0]

=\(t^{3}\)

Hence using the fundamental theorem of calculas the derivative of function g(x)= \(xt^{3}+t^{5}\) at x=0 is \(t^{3}\).

The function given in the question is incomplete. The right function will be g(x)=\(xt^{3}+t^{5}\).

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.

The expected correlation between the supply of a commodity (x) and the price of a commodity (y) depends on the nature of the commodity and market dynamics. However, in general, we would expect a **negative correlation** between the supply of a commodity and its price. Correct option is C.

The law of supply states that as the supply of a commodity increases, assuming demand remains constant, the price tends to decrease. This is because an increase in supply leads to a higher quantity of the commodity available in the market, potentially causing an excess supply or surplus. In such situations, suppliers may lower prices to attract buyers and reduce their inventory.

Conversely, when the supply of a commodity decreases, assuming demand remains constant, the price tends to increase. A decrease in supply results in a lower quantity available in the market, potentially leading to a scarcity or shortage. In such scenarios, suppliers may increase prices to maximize their profits due to the limited availability of the commodity.

It's important to note that real-world markets can be influenced by various factors, including changes in demand, production costs, technological advancements, government policies, and market competition, which can complicate the relationship between supply and price. Nonetheless, the general expectation is that a decrease in supply tends to lead to an increase in price, and an increase in supply tends to lead to a decrease in price, indicating a negative correlation.

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Answer:

D. Acute

Step-by-step explanation:

Acute because both <A and <B are less then 90 degrees

Hope this helps :).

Answer:

Option A

Step-by-step explanation:

Given :-

We need to find the relationship between a and b. Also we know that the measure of angle of straight line is 180 ° .

According to Question :-

\(:\implies\) a + b + 90° = 180°

\(:\implies\) a + b = 180° - 90°

\(:\implies\) a + b = 90°

When Gary mailed 10 to the third power flyers to clients in one week, the number of flowers that he mailed will be 1000 flowers.

It should be noted that from the information, Gary mailed 10 to the third power flyers to clients in one week.

It should be noted noted the power of 20 is simply used when one wants to shorten numbers if they're long or sometimes to inconsistent.

In this case, Gary mailed 10 to the third power flyers to clients in one week. The number that he mailed will be:

= 10³

= 10 × 10 × 10.

= 100

Therefore, when Gary mailed 10 to the third power flyers to clients in one week, the number of flowers that he mailed will be 1000 flowers.

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A Venn diagram is a graphic organizer utilized to show relationships between sets. The Venn diagram uses circles or other shapes to show the commonalities and distinctions between the two or more sets.

It comprises of two overlapping circles, each circle representing a set. The common parts between two sets are illustrated in the overlapping region. The number of elements is shown in each set. The common region is represented by the intersection of two sets. \(n(A)=9, n(B)=13, n(A∩B)=8\); We know the number of elements in set A and set B and their intersection.

Using the formula for the union of two sets, we can find\(n(A∪B).n(A∪B)= n(A) + n(B) - n(A∩B)n(A∪B)= 9 + 13 - 8n(A∪B)= 14\)Therefore, the number of elements in the union of A and B is 14. A diagram is presented below to illustrate the relationship between A and B. \(\text{Venn diagram of set A and set\(B}\)\)

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Answer: She bought 28 daises and 10 Tulips.

Step-by-step explanation:

Let x represent the number of daises bought.

Let y represent the number of tulips bought.

Your friend want to have 38 of her favorite flowers. This means that

x + y = 38

Her favorite flowers are daisies at 1.50 each and tulips at 2.50 each if the total bill was 67, it means that

1.5x + 2.5y = 67 - - - - - - - - - - - - 1

Substituting x = 38 - y into equation 1, it becomes

1.5(38 - y) + 2.5y = 67

57 - 1.5y + 2.5y = 67

- 1.5y + 2.5y = 67 - 57

y = 10

x = 38 - y = 38 - 10

x = 28

Answer: She bought 28 daises and 10 Tulips.

Step-by-step explanation:

Let x represent the number of daises bought.

Let y represent the number of tulips bought.

Your friend want to have 38 of her favorite flowers. This means that

x + y = 38

Her favorite flowers are daisies at 1.50 each and tulips at 2.50 each if the total bill was 67, it means that

1.5x + 2.5y = 67 - - - - - - - - - - - - 1

Substituting x = 38 - y into equation 1, it becomes

1.5(38 - y) + 2.5y = 67

57 - 1.5y + 2.5y = 67

- 1.5y + 2.5y = 67 - 57

y = 10

x = 38 - y = 38 - 10

x = 28

Answer:

1.1l +0.4+0.3+0.5

answer = 2litres 3milimetres

Answer:

  9/4

Step-by-step explanation:

You want to know the value required to complete the square in the equation 1 = x² -3x.

Your picture shows the required value: (-3/2)² = 9/4.

<95141404393>

ANSWER:

-17/32, -18/32, -19/32, -20/32, -21/32, -22/32

EXPLANATION:

-4/8 and -3/4

-4*4/8*4 and -3*8/4*8

-16/32 and -24/32

There are 8 numbers between -16/32 and -24/32. You can write any six of it.

Answer:

Friction is a force between two surfaces that are sliding, or trying to slide, across each other.

Step-by-step explanation:

For example, when you try to push a book along the floor, friction makes this difficult.

Answer:

Friction is the force that opposes motion between any surfaces that are in contact. There are four types of friction: static, sliding, rolling, and fluid friction. Static, sliding, and rolling friction occur between solid surfaces. Fluid friction occurs in liquids and gases.

Step-by-step explanation:

Answer: 16+d>20

d>4

Step-by-step explanation:

d=digs

16+d>20

16-16+d>20-16

d>4

Answer:

You need a z-score of at least 1.09 to get accepted.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \(\mu\) and standard deviation \(\sigma\), the zscore of a measure X is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\(\mu = 20.9, \sigma = 5.6\)

To get accepted into OSU, you need at least a 27. What is the z-score you need to get accepted?

We need to find Z when X = 27. So

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{27 - 20.9}{5.6}\)

\(Z = 1.09\)

You need a z-score of at least 1.09 to get accepted.

The required steps are as follows:

Multiply both sides of the equation by 3.

Divide both sides of the equation by h.

To rearrange the formula to highlight the base area, we can first multiply both sides of the equation by 3 to get:

V = 3Ah

Then, we can divide both sides of the equation by h to get:

A = V/h

Therefore, the rearranged formula to highlight the base area is A = V/h.

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Answer: ok jeez its false because

Step-by-step explanation: It is false

Answer:

do u have a full screenshot of it???

Step-by-step explanation:

Answer:

√3

Step-by-step explanation:

(2√3)²+x²=(√15)²

(4*3)+x²=15

12+x²=15

x²=15-12

x²=3

x=√3

Answer:

easy

x=4 y=7 or

x=4 y=-1

Step-by-step explanation:

x=4 y=7 or

x=4 y=-1

Answer: $100 Rebate

Step-by-step explanation:

20% of 479.99

20/100=0.2

0.2x479.99=95.998

=96 dollars off

100-96=4

With the 20% off you lose $4 compared to the $100 rebate.

Better deal: $100 Rebate

Answer:

Step-by-step explanation:

The given graph is a parabola and so it a quadratic function.

The y-intercept is the point at which the curve crosses the y-axis.

From inspection of the graph, this is when y = -6.

The x-intercepts are the points at which the curve crosses the x-axis.

From inspection of the graph, the x-intercepts are x = 2 and x = 6.

The vertex is the turning point of the graph, so the minimum point of a parabola that opens upwards, and the maximum point of a parabola that opens downwards.

From inspection of the graph, the vertex is at (4, 2), so the greatest value of y is y = 2, and it occurs when x = 4.

The curve is above the x-axis between the interval x = 2 and x = 6.

Therefore, the function value is equal to zero or positive in this interval.

So the function value in the given interval is y ≥ 0.

Graph is parabola

Y inetercept is the point where the curve crosses y axis

X inetercepts are the points crossing x axis

As it's parabola opening downwards vertex is maximum

So max value of y is 2

y≥0

(1) Fv(2) = 1 - sin²(Nx/2) / (2N sin²(x/2)).

(2) FN(0) = N + 1 for any N ≥ 1.

(3) α is a fixed value, the integral ∫[0, α] Fₙ(y)dy will approach 0 as N approaches infinity. we have proved that ∫[0, α] Fₙ(y)dy → 0 as N → ∞.

(1) Prove that Fv(2) = 1 - sin²(Nx/2) / (2N sin²(x/2)), provided sin(2/2) ≠ 0.

To simplify the notation, let's define D₁(x) = cos(x), and FN(x) = D₀(x) + D₁(x) + ⋯ + DN-1(x), where D₀(x) = 1.

We have D₁(x) = sin(N + 1/2) / (2 sin(x/2)).

FN(x) = D₀(x) + D₁(x) + ⋯ + DN-1(x)

= 1 + sin(1 + 1/2) / (2 sin(x/2)) + ⋯ + sin(N + 1/2) / (2 sin(x/2))

= 1 + 1/2 ∑ (sin(k + 1/2) / sin(x/2)), where the summation goes from k = 1 to N.

As Tk(x) = sin(k + 1/2) / sin(x/2).

We need to find Fv(2), which is the value of FN(x) when x = 2.

Fv(2) = 1 + 1/2 ∑ (sin(k + 1/2) / sin(1)), where the summation goes from k = 1 to N.

Using the sum of a geometric series, we can simplify the expression further:

Fv(2) = 1 + 1/2 (sin(1/2) / sin(1)) × (1 - (sin(N + 3/2) / sin(1))) / (1 - (sin(1/2) / sin(1)))

= 1 + sin(1/2) / (2 sin(1)) × (1 - sin(N + 3/2) / sin(1)) / (1 - sin(1/2) / sin(1))

= 1 + sin(1/2) / (2 sin(1)) × (1 - sin(N + 3/2) / sin(1)) / (1 - sin(1/2) / sin(1)) × (sin(1) / sin(1))

= 1 + sin(1/2) / (2 sin(1)) × (sin(1) - sin(N + 3/2)) / (sin(1) - sin(1/2))

Now, we'll use the trigonometric identity sin(a) - sin(b) = 2 cos((a + b) / 2) sin((a - b) / 2) to simplify the expression further.

Fv(2) = 1 + sin(1/2) / (2 sin(1)) × (2 cos((1 + N + 3/2) / 2) sin((1 - (N + 3/2)) / 2) / (sin(1) - sin(1/2))

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) sin((1 - (N + 3/2)) / 2)

Since sin(2/2) ≠ 0, sin(1) - sin(1/2) ≠ 0.

Fv(2) = (sin(1) - sin(1/2)) / (sin(1) - sin(1/2)) + (sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) sin((1 - (N + 3/2)) / 2)

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) sin((1 - (N + 3/2)) / 2)

The trigonometric identity sin(α - β) = sin(α) cos(β) - cos(α) sin(β) to further simplify the expression:

Fv(2) = 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) × (sin(1/2) cos((N + 1/2) / 2) - cos(1/2) sin((N + 1/2) / 2))

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × (sin(1/2) cos((N + 1/2) / 2) cos((1 + N + 3/2) / 2) - cos(1/2) sin((N + 1/2) / 2) cos((1 + N + 3/2) / 2))

Using the double-angle formula cos(2θ) = cos²(θ) - sin²(θ),

Fv(2) = 1 + sin(1/2) / (sin(1) - sin(1/2)) × (sin(1/2) cos(N + 1/2) cos((1 + N + 3/2) / 2) - cos(1/2) sin(N + 1/2) cos((1 + N + 3/2) / 2))

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) × (sin(1/2) cos(N + 1/2) - cos(1/2) sin(N + 1/2))

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) × sin(N + 1/2 - 1/2)

Using the identity sin(a - b) = sin(a) cos(b) - cos(a) sin(b),

Fv(2) = 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) × sin(N)

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos((1 + N + 3/2) / 2) × sin(N)

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos(N + 2)

= 1 + sin(1/2) / (sin(1) - sin(1/2)) × cos(2) [since sin(N + 2) = sin(2)]

= 1 + sin(1/2) / (2 sin(1/2) cos(1/2)) × cos(2) [using the double-angle formula sin(2θ) = 2 sin(θ) cos(θ)]

= 1 + 1/2 × cos(2)

= 1 + 1/2 × (2 cos²(1) - 1) [using the identity cos(2θ) = 2 cos²(θ) - 1]

= 1 + cos²(1) - 1/2

= cos²(1) + 1/2

= (1 - sin²(1)) + 1/2

= 1 - sin²(1) + 1/2

= 1 - sin²(Nx/2) / (2N sin²(x/2))

Therefore, we have proved that Fv(2) = 1 - sin²(Nx/2) / (2N sin²(x/2)).

(2) Prove that for any N ≥ 1, FN(0) = 1.

To find FN(0), we substitute x = 0 into the expression for FN(x):

FN(0) = 1 + sin(1/2) / sin(1/2) + sin(3/2) / sin(1/2) + ⋯ + sin(N + 1/2) / sin(1/2)

= 1 + 1 + 1 + ⋯ + 1

= 1 + N

= N + 1

Therefore, FN(0) = N + 1 for any N ≥ 1.

(3) Prove that for any fixed ε > 0 satisfying 0 < α < 7, we have ∫[0, α] Fₙ(y)dy → 0 as N → ∞.

∫[0, α] Fₙ(y)dy = ∫[0, α] [D₀(y) + D₁(y) + ⋯ + Dₙ₋₁(y)]dy

Since Fₙ(y) is the N-th Cesaro mean of the Dirichlet kernels, the integral above represents the convolution of Fₙ(y) and the constant function 1.

Let g(y) = 1 be the constant function.

The convolution of Fₙ(y) and g(y) is given by:

(Fₙ ×g)(y) = ∫[-∞, ∞] Fₙ(y - t)g(t)dt

Using the linearity of integrals, we can write:

∫[0, α] Fₙ(y)dy = ∫[0, α] [(Fₙ × g)(y)]dy

= ∫[0, α] ∫[-∞, ∞] Fₙ(y - t)g(t)dtdy

By changing the order of integration, we can write:

∫[0, α] Fₙ(y)dy = ∫[-∞, ∞] ∫[0, α] Fₙ(y - t)dydt

Since Fₙ(y - t) is a periodic function with period 2π, for any fixed t, the integral ∫[0, α] Fₙ(y - t)dy is the same as integrating over a period.

Therefore, we have:

∫[0, α] Fₙ(y)dy = ∫[-∞, ∞] ∫[0, α] Fₙ(y - t)dydt

= ∫[-∞, ∞] ∫[0, 2π] Fₙ(y)dydt

= ∫[-∞, ∞] 2π FN(0)dt [Using the periodicity of Fₙ(y)]

= 2π ∫[-∞, ∞] (N + 1)dt [Using the result from part (2)]

= 2π (N + 1) ∫[-∞, ∞] dt

= 2π (N + 1) [t]_{-∞}^{∞}

= 2π (N + 1) [∞ - (-∞)]

= 2π (N + 1) ∞

Since α is a fixed value, the integral ∫[0, α] Fₙ(y)dy will approach 0 as N approaches infinity.

Therefore, we have proved that ∫[0, α] Fₙ(y)dy → 0 as N → ∞.

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None of the statements about quantitative versus qualitative research are true.

This is because the comparison between quantitative and qualitative research is not a matter of one being objectively better or more subjective, richer, or more time-consuming than the other. They are different approaches to research, each with its strengths and limitations, and the choice between them depends on the research question, the nature of the data, and the research design.

Quantitative research is characterized by the collection of numerical data that can be analyzed using statistical methods to identify patterns, relationships, and trends. This approach is used when the research question requires an objective measurement of variables that can be quantified and compared across groups. For example, a quantitative study may examine the relationship between height and weight in a population, using statistical techniques to identify the strength of the relationship and its significance.

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The elasticity for this demand function when p=$220 is 0.14 (rounded to 2 decimal places).

We can start by using the formula for elasticity:

E = (dq/dp)*(p/q)

We need to find dq/dp first:

p = 4400/q + 3

p - 3 = 4400/q

q(p - 3)/4400 = 1/q

dq/dp = -1/q^2 * (-3/4400) = 3/(4400q^2)

Now we can substitute the given values and calculate the elasticity:

E = (3/(4400q^2))*(220/ q)

E = 0.00014q

We need to find q when p=220:

220 = 4400/q + 3

q = (4400/217)

Now we can substitute this value to calculate the elasticity:

E = 0.00014(4400/217)^2

E ≈ 0.1375

Therefore, the elasticity for this demand function when p=$220 is 0.14 (rounded to 2 decimal places).

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Answer:

The answer would be D.

Step-by-step explanation:

Hey! To determine the mode, you must find the number that appears the most in the data set.

Your data set is unique in a way, as 122, 135, and 195 both appear twice in it, which leads us to our answer!

If you didn't know, the mode is the number that appears the most. We have three in this case.

I hope this helped, best of luck with the rest of your assignment!!

Complete question :

In the evening, the temperature is 2828 degrees. By midnight it has dropped 3131 degrees lower. Between midnight and 4 am, it goes down 66 more degrees. Then, by 9 am, the temperature goes up 3030 degrees. Find the final temperature.

Answer:

-38°

Step-by-step explanation:

Evening temperature = 28°

By midnight = 31° lower

4am = 66° lower

9 a.m = 30° higher

Temperature at midnight :

28° - 31° = - 2°

Temperature at 4 a.m:

-2° - 66° = - 68°

Final temperature at 9a.m :

-68° + 30° = - 38°

The temperature at 9a.m is - 38°

The answer to the equation will be 5, and in the second one the answer to the equation when the value of t is 4 resulted as 14We can evaluate the expression "2 + 3t" for the given values of t:

a. When we consider T as 1 then the substitution can be = 1 as the expression

2 + 3t = 2 + 3(1) = 2 + 3 = 5

Therefore, the value of the expression when t is 1 is 5. to the expression of 2+3t.

b. We substitute t = 4 in the expression and get:

2 + 3t = 2 + 3(4) = 2 + 12 = 14

Therefore, the value of the expression when t is 4 is 14. The value can be 14 when its value is 4.

In the first scenario, the answer to the equation will be 5, and in the second one the answer to the equation when the value of t is 4 resulted as 14. if we give any other number the value changes accordingly.

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The correct question of the answer is

Here is an expression: 2 + 3t

a. Evaluate the expression when t is 1.

b. Evaluate the expression when t is 4.

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the area of a circle with a rectangle will be [π w²2]/4.

What is the area of a circle?

The measurement of the circle's boundaries is called as the circumference or perimeter of the circle. whereas the circumference of a circle determines the space it occupies. The circumference of a circle is its length when it is opened up and drawn as a straight line. Units like cm or unit m are typically used to measure it. The circle's radius is considered while calculating the circumference of the circle using the formula. As a result, in order to calculate the circle's perimeter, we must know the radius or diameter value.

area of the circle will be πr².

The area of a circle inscribed in a rectangle if the length of the rectangle is l and the width is w

= [π w²2]/4.

Hence the area of a circle with a rectangle will be [π w²2]/4.

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Answer:

15

Step-by-step explanation:

2(2) - 18 = -14 |-14| = 14

3(2) -7 = -1 |-1| = 1

14+1=15

The area occupied by the ship is 10 inches².

The area of a parallelogram is -

A{||gm} = base x height

Given is that Ships in a first generation video game were modeled like the one shown in the image.

We can write the area occupied by the ship as -

Area = A{||gm} + A{triangle}

Area = {b x h} + {L x B}

Area = \($(3\frac{2}{5}\times 2)\;+\; (3\frac{2}{5}-1)\times1\frac{1}{3}\)

Area = (17/5 x 2) + (17/5 - 1) x (4/3)

Area = 34/5 + 12/5 x 4/3

Area = 34/5 + 16/5

Area = 50/5

Area = 10 inches²

Therefore, the area occupied by the ship is 10 inches².

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If Aaron is designing a party game in which he needs exactly 24 possible outcomes, then he can use the following sets of actions to have a statistically fair game from the Statistics point  of view,

Toss a coin twice, and then then roll a 6-sided number cube.

How can he play a statistically fair game to get exactly 24 outcomes?

The game has 24 alternative outcomes, as far as we know. The next step is to identify a series of activities that produces 24 distinct outcomes with equal probabilities.

The first of the alternatives is the only one with a sample space of 24 elements.

Flip two coins, then roll a D6.

The results of each coin toss are 2:  (tails and heads).

There are 6 outcomes for the D6: (1, 2, 3, 4, 5, 6)

The combined outcomes of the two throws and rolling the number are then given by the product between the numbers of outcomes for each individual part, as solved below:

C = 2 × 2 × 6

C = 24

Thus, by tossing a coin twice, and then then rolling a 6-sided number cube, Aron can play a statistically fair game if h needs exactly 24 outcomes.

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